Search Results

Search found 2818 results on 113 pages for 'nested repeater'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 67/113 | < Previous Page | 63 64 65 66 67 68 69 70 71 72 73 74  | Next Page >

  • How do I compare two complex data structures?

    - by Phil H
    I have some nested datastructures, each something like: [ ('foo', [ {'a':1, 'b':2}, {'a':3.3, 'b':7} ]), ('bar', [ {'a':4, 'd':'efg', 'e':False} ]) ] I need to compare these structures, to see if there are any differences. Short of writing a function to explicitly walk the structure, is there an existing library or method of doing this kind of recursive comparison?

    Read the article

  • Combine Related Resources With TastyPie

    - by Aaron Ng
    How can I combine multiple Resources in TastyPie? I have 3 models I'd like to combine: users, profiles and posts. Ideally I'd like profiles nested within user. I'm not sure where to go from here. class UserResource(ModelResource): class Meta: queryset = User.objects.all() resource_name = 'user' fields = ['username','id','date_joined'] #Improper Auth authorization = Authorization() class UserProfileResource(ModelResource): class Meta: queryset = UserProfile.objects.all() resource_name = 'profile' class UserPostResource(ModelResource): user = fields.ForeignKey(UserResource,'user', full=True) class Meta: queryset = UserPost.objects.all() resource_name = 'userpost' #Improper Auth authorization = Authorization()

    Read the article

  • Problem While Deploying Application in GlassFish

    - by Sarang
    I have to deploy an application named "mrs-ws-server.war" in glassfish. I did it using both : 1) Package File to be uploaded to the server 2) Local package File or Directory at the address : http://localhost:42328/common/index.jsf It generates the following error : Exception while loading the app : java.lang.Exception: java.lang.IllegalStateException: ContainerBase.addChild: start: org.apache.catalina.LifecycleException: org.springframework.transaction.CannotCreateTransactionException: Could not open Hibernate Session for transaction; nested exception is org.hibernate.exception.GenericJDBCException: Cannot open connection What should be the solution for the same ?

    Read the article

  • Perform selector on paren NSOperation

    - by user326943
    I extend NSOperation (call it A) which contains NSOperationQueue for other NSOperations (which is another extended class different from A, call these operations B). When operation A is running (executing B operations) how do i call a specific function/method on operation A when certain event takes place on B operations? For example every operation B that finishes it calls a function on operation A returning itself? *Nested NSOperation and NSOperationQueue(s) Thanks

    Read the article

  • Flex: Bottom-left align components?

    - by David Wolever
    As the title suggests, is there any way to bottom-left align components? An <HBox .../> nested in a <Canvas .../> doesn't work because the elements in the HBox are top-aligned instead of bottom aligned. For example, I'd like my components to be aligned like this: +-------------+ <-- container | components | | | V | | V +--+ | | +-+ | | | | +-+ +--+ | +-------------+

    Read the article

  • Centering of a div, but the normal CSS does not work

    - by Jean
    Hello, I want to center a div, but the general way is #selector{position:relative;margin:0px auto;} What exactly is wrong below #crp{top:40%; position:absolute; margin:auto;} The Div below is not nested but a standalone. The #crp is going to the extreme right. <div id="crp">...something goes here....</div> Thanks Jean

    Read the article

  • MySQL - Calculate the net time difference between two date-times while excluding breaks?

    - by John M
    In a MySQL query I am using the timediff/time_to_sec functions to calculate the total minutes between two date-times. For example: 2010-03-23 10:00:00 - 2010-03-23 08:00:00 = 120 minutes What I would like to do is exclude any breaks that occur during the selected time range. For example: 2010-03-23 10:00:00 - 2010-03-23 08:00:00 - (break 08:55:00 to 09:10:00) = 105 minutes Is there a good method to do this without resorting to a long list of nested IF statements?

    Read the article

  • "ejb not bound" -- What could be the problem?

    - by Bernhard V
    Hi! When I'm running my program, I get the following error: ... nested exception is javax.naming.NameNotFoundException: ejb not bound The error occurs at the start up when Java wants to create a certain bean. The Bean is a SimpleRemoteStatelessSessionProxyFactoryBean. Could it be that I ain't got the rights to access the naming provider URL although I can ping it? When accessing the bean on my local JBoss there are no problems.

    Read the article

  • Multiple column subselect in mysql 5 (5.1.42)

    - by rubber boots
    This one seems to be a simple problem, but I can't make it work in a single select or nested select. Retrieve the authors and (if any) advisers of a paper (article) into one row. I order to explain the problem, here are the two data tables (pseudo) papers (id, title, c_year) persons (id, firstname, lastname) plus a link table w/one extra attribute (pseudo): paper_person_roles( paper_id person_id act_role ENUM ('AUTHOR', 'ADVISER') ) This is basically a list of written papers (table: papers) and a list of staff and/or students (table: persons) An article my have (1,N) authors. An article may have (0,N) advisers. A person can be in 'AUTHOR' or 'ADVISER' role (but not at the same time). The application eventually puts out table rows containing the following entries: TH: || Paper_ID | Author(s) | Title | Adviser(s) | TD: || 21334 |John Doe, Jeff Tucker|Why the moon looks yellow|Brown, Rayleigh| ... My first approach was like: select/extract a full list of articles into the application, eg.SELECT q.id, q.title FROM papers AS q ORDER BY q.c_year and save the results of the query into an array (in the application). After this step, loop over the array of the returned information and retrieve authors and advisers (if any), via prepared statement (? is the paper's id) from the link table like:APPLICATION_LOOP(paper_ids in array) SELECT p.lastname, p.firstname, r.act_role FROM persons AS p, paper_person_roles AS r WHERE p.id=r.person_id AND r.paper_id = ? # The application does further processing from here (pseudo): foreach record from resulting records if record.act_role eq 'AUTHOR' then join to author_column if record.act_role eq 'ADVISER' then join to avdiser_column end print id, author_column, title, adviser_column APPLICATION_LOOP This works so far and gives the desired output. Would it make sense to put the computation back into the DB? I'm not very proficient in nontrivial SQL and can't find a solution with a single (combined or nested) select call. I tried sth. like SELECT q.title (CONCAT_WS(' ', (SELECT p.firstname, p.lastname AS aunames FROM persons AS p, paper_person_roles AS r WHERE q.id=r.paper_id AND r.act_role='AUTHOR') ) ) AS aulist FROM papers AS q, persons AS p, paper_person_roles AS r in several variations, but no luck ... Maybe there is some chance? Thanks in advance r.b.

    Read the article

  • mysql joins - how to find all children that belongs to ALL parents

    - by kimsia
    I have three mysql tables items the columns are id, title items_in_categories the columns are id, item_id, category_id categories the columns are id, title I want to find all the items that belong to ALL the stated categories. Not any one category, but ALL categories Eg, if I want to search all the items that belongs to category id 3 and 5 I would like to use as simple a way as possible. I have tried AND and a nested NOT EXISTS as stated in the mysql manual. Nothing worked.

    Read the article

  • Silverlight 4 Treeview MVVM WCF

    - by Coppermine
    I'm having an issue with the treeview control from the silverlight 4 toolkit. I can't get it to view to display my data correctly, the toplevel items are shown but the childnodes are nowhere to be seen. More info: I have a wcf service that delivers a list of Categories with nested subcategories to my viewmodel (I made sure to explicitly include my subcategory data). My viewmodel has an observable list property (wich is named Categories) with this data from my WCF service. My ViewModel: _http://pastebin.com/0TpMW3mR My XAML: http://pastebin.com/QCwVeyYu

    Read the article

  • javascript accordian menu problem in worpress

    - by Praveen kalal
    hi all i am working on wordpress project there is i used accordion for right sidebar but all the link are over lapping each other in IE8 its working fine mozzila so plz help my code is var parentAccordion=new TINY.accordion.slider("parentAccordion"); parentAccordion.init("acc","h4",1,-1); var nestedAccordion=new TINY.accordion.slider("nestedAccordion"); nestedAccordion.init("nested","h4",1,-1,"acc-selected"); $args = array('parent'=>0,'hide_empty'=>0); $cats = get_categories($args); echo '<ul id="acc" class="acc">'; foreach($cats as $key => $val) { $args1=array( 'showposts' => 10, 'category__in' => array($val->term_id), 'caller_get_posts'=>1 ); $post=get_posts($args1); echo '<li><h4>'.$val->name.'</h4>'; echo '<div class="" style="opacity: 0; height: auto;">'; echo '<ul id="nested" class="acc">'; if(isset($post) && !empty($post)) { foreach($post as $key1 => $val1) { echo '<li class="cat-item"><a title='.$val1->post_title.' href='.$val1->guid.'>'.$val1->post_title.'</a>'; } } $subcats = get_categories(array('parent'=>$val->term_id,'hide_empty'=>0)); if(isset($subcats) && !empty($subcats)) { foreach($subcats as $k => $v) { echo '<li><h4 class="">'.$v->name.'</h4>'; $args2=array( 'showposts' => 10, 'category__in' => array($v->term_id), 'caller_get_posts'=>1 ); $post1=get_posts($args2); if(isset($post1) && !empty($post1)) { echo '<div class="" style="opacity: 1; height: auto;">'; echo '<ul class="children" style="padding-left:15px;">'; foreach($post1 as $key2 => $val2) { echo '<li><a title='.$val2->post_title.' href='.$val2->guid.'>'.$val2->post_title.'</a></li>'; } echo '</ul></div>'; } } } echo "</ul>"; echo "</li>"; } echo '</ul>'; ?> </div> so plz help me

    Read the article

  • XSLT: Transform XML files tree

    - by Myniva
    I have the following file structure (XML files 'index.xml' in nested folders): index.xml foo/index.xml foo/sub/index.xml foo/.../index.xml bar/.../index.xml Now I have to transform each of this XML files with a given XSL stylesheet. The result should be the same folder structure (overwriting would be OK). What would be your approach to achieve this? My system: OS X 10.6, Saxon XSLT processor

    Read the article

  • RoR - Associations into practise - forms (View)

    - by NicoJuicy
    I'm learning Ruby on Rails. I'm using some associations (has_many :through, ...) But i'm having some problems with it when i'm combining my views. How exactly do i combine these nested forms? Can i do this with partial forms and where do i have to write extra code for this? I have seen examples only use the "view" and others also edit the controller.... An example would be very nice :-)

    Read the article

  • PCRE (recursive) pattern that matches a string containing a correctly parenthesized substring. Why d

    - by Anton N. Petrov
    Well, there are other ways (hmmm... or rather working ways) to do it, but the question is why does this one fail? / \A # start of the string ( # group 1 (?: # group 2 [^()]* # something other than parentheses (greedy) | # or \( (?1) \) # parenthesized group 1 ) # -group 2 + # at least once (greedy) ) # -group 1 \Z # end of the string /x Fails to match a string with nested parentheses: "(())"

    Read the article

  • format - Help with printing a table

    - by Michael Kohl
    This question will probably end in a facepalm, but I've tried for a while and am still stuck despite reading through the hyperspec. Basically what I want to do is something like (format t "~{|~{ ~5d~}|~%~}" '((1 23 2 312) (23 456 1 7890))) but instead of hard-coding the 5 it should be calculated from the list (length of longest element from any nested list + 1) to give something like | 1 23 2 312| | 23 456 1 7890| Maybe I'm thinking way too complicated here and there is an easier way to do what I want, but I think I ran myself into a mental corner that I can't get out of.

    Read the article

  • SQL: How to order values inside group by

    - by Denis Yaremov
    Consider the following MS SQL Server table: ID | X | Y ------+-------+------- 1 | 1 | 1 2 | 1 | 2 3 | 1 | 3 4 | 2 | 40 5 | 2 | 500 6 | 3 | 1 7 | 3 | 100 8 | 3 | 10 I need to select the ID of the row that has the maximum value of Y grouped by x, i.e: ID | X | Y ------+-------+------- 3 | 1 | 3 5 | 2 | 500 7 | 3 | 100 The query will be nested several times so an optimal performance solution is required... Thank you!

    Read the article

  • Changing default REST routes in Rails 3

    - by Vincent
    I need to add one parameter to the default REST route for the show action for SEO purposes: resources :neighborhoods, :only => [:index, :show] neighborhood_url(neighborhood) # => /neighborhoods/lower-east-side I want something like the following: neighborhood_url(city, neighborhood) # => /neighborhoods/manhattan/lower-east-side What would be the easiest way to do this without using nested routes and without breaking Rails REST conventions?

    Read the article

  • Maintaining property lists for xCode projects

    - by William Jockusch
    My project currently contains two largish property lists. One is currently 20KB; another is 8KB. So far, I have been maintaining them with xCode's property list editor. This is manageable but also a bit clunky. I am wondering if other people have better ways of doing this? So far, my lists consist of nested arrays of strings. The depth is not uniform.

    Read the article

  • List circular group membership from active directory

    - by KAPes
    We have 40K+ groups in our active directory and we are increasingly facing problem of circular nested groups which are creating problems for some applications. Does anyone know how to list down the full route through which a circular group membership exists ? e.g. G1 --> G2 --> G3 --> G4 --> G1 How do I list it down.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 63 64 65 66 67 68 69 70 71 72 73 74  | Next Page >