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  • RoR custom routing/Method/View problem all methods come back as undefined

    - by Jeff
    I am playing with custom view and routes. I think that I have everything right but obviously not. Essentially I tried to copy the show method and show.html.erb but for some reason it will not work. My controller class fatherController < ApplicationController def show @father = Father.find(params[:id]) respond_to do |format| format.html # show.html.erb format.xml { render :xml => @father } end end def ofmine @father = Father.find(params[:id]) respond_to do |format| format.html # show.html.erb format.xml { render :xml => @father } end end end My routes.rb Parent::Application.routes.draw do resources :fathers do resources :kids end match 'hospitals/:id/ofmine' => 'father#show2' end when I go to 127.0.0.1:/father/1 it works fine but when I try to go to 127.0.0.1:/father/1/ofmine it gives the following error. It doesn't matter what the variable/method that is called; it occurs at the first one to be displayed. Both show.html.erb and show2.html.erb are the exact same files My Error from webserver commandline > Processing by fathersController#show2 > as HTML Parameters: {"id"=>"1"} > Rendered fathers/show2.html.erb within > layouts/application (31.6ms) Completed > in 37ms > > ActionView::Template::Error (undefined > method `name' for nil:NilClass): > 4: <td>Name</td><td></td> > 5: </tr> > 6: <tr> > 7: <td><%= @father.name %></td><td></td> > 8: </tr> > 9: <tr> > 10: <td>City</td><td>State</td> app/views/fathers/show2.html.erb:7:in > `_app_views_fatherss_show__html_erb___709193087__616989688_0' Error as displayed on actual page NoMethodError in Fathers#show2 Showing /var/ruby/chs/app/views/fathers/show2.html.erb where line #7 raised: undefined method `name' for nil:NilClass Extracted source (around line #7): 4: Name 5: 6: 7: <%= @father.name % 8: 9: 10: CityState If anyone could tell me what in the world I am doing wrong I would appreciate it greatly.

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  • Devise role based routing

    - by teknull
    I have an app with multiple users. Each user as a theoretical role (user, client, etc). I've designed a view/controller for each user type. I want to be able to login each type of user do a different root url and lock them to it. Originally I was going to add a column to Users in Devise called role and so I can differentiate the users. The problem I'm having is how to say in routes.rb if current_user.role == "client" root :to = 'controller#index' Once they are logged in to the page I also want to keep them from being able to visit any of my other paths ie: domain.com/calls domain.com/units I've been looking into cancan to run alongside Devise but I'm not sure if this is the answer.

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  • Cannot see index view of my controller - routing related

    - by olst
    Hi. I have a controller named Content, which has an Index action, which is associated with a view. I would like the simple route "content" to show me the index view of the content controller, so I use the following code (with the addition of the default site home route): routes.MapRoute( "ContentIndex", "content", new { controller = "Content", action = "Index"} ); routes.MapRoute( "Default", "{controller}/{action}", new { controller = "Home", action = "Index" } ); when I type the url : "http://localhost/content/", I get an error 404 saying the resource cannot be found, but when I type "http://localhost/content/index", it shows the content index view. How can I get rid of the index in the url ? Thanks !

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  • How to create multiple inputs in yii + Q&A admin page

    - by user1764357
    In yii, i am developing page for Creating Question with multiple options using forms. So i have two tables Question QuestionId Question optionId Option OptionId Option To create multiple options, option field should be provided with add button so that after clicking add button, it should display new textbox control to get the new option. All these options displayed in a gridview. So can you please help me. I am very new to yii.

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  • how to configure IP cam to stream using right network card?

    - by robin hood
    I have IP cam that supports RTSP streaming. It's connected to router with 2 network cards with IP1 and IP2 addresses. I make 2 connections to IP cam by IP1 and IP2 addresses from the same IP and I need to receive corresponding streams thru correct network card, but both streams (RTP over UDP) go thru IP1. How this can be resolved? I don't know if RTSP server binds UDP sockets to corresponding IP and I don't know what IP stack is in IP cam (weak end system or strong end system). I haven't found anything interesting in router configuration. As I understand, routing table cannot help me cos I'm connected from the same IP, is it right? Also Sorry for incomplete info but it's all I have at the moment. Thanks for your time.

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  • asp.net mvc ignoreRoute with webservice

    - by boz
    Howdy, Im adding the filevistacontrol to my asp.net MVC web application. I have a media.aspx page that is ignored in the routing with routes.IgnoreRoute("media.aspx"); This works successfully and serves a standard webforms page. Upon adding the filevistacontrol, I can't seem to ignore any calls the control makes to it's webservice. Eg the following ignoreRoute still seems to get picked up by the MvcHandler. routes.IgnoreRoute("FileVistaControl/filevista.asmx/GetLanguageFile/"); The exception thrown is: 'The RouteData must contain an item named 'controller' with a non-empty string value' Thanks in advance.

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  • Routing Skype call to another Voip company

    - by Anarchist
    Hello, As my project to do over this summer I would like to create a program that answers a Skype call using the Skype API and allows a user to connect to another VOIP provider (through SIP) and make calls by dialling through the client callers Skype application. I understand that the Skype API allows me to answer and receive keypad input, but I'm stuck on actually sending the sound of the call to a SIP client. Is there an API/library that would allow me to take the Skype receiving audio as input in the SIP client? Is this even possible? I'm not tied to a language but I had planned on using Python. Thanks.

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  • GAE app.yaml appears to be inconsistently routing requests

    - by kamens
    I have the following in app.yaml: - url: /gae_mini_profiler/static static_dir: gae_mini_profiler/static - url: /gae_mini_profiler/.* script: gae_mini_profiler/main.py - url: .* script: main.py and the following in gae_mini_profiler/main.py: def main(): logging.critical("gae_mini_profiler request!") run_wsgi_app(application) However, when I fire requests to, say, /gae_mini_profiler/request?request=ABC, and repeatedly reload the page, sometimes I will get the proper response (as well as a "gae_mini_profiler request!" log entry, and sometimes I get a blank response and nothing in the App Engine logs other than a 200 with an empty response body. This is completely reproducible, only happens in the live environment, and I'd say ~50% of the refreshes work while 50% do not. This only happens in production. Any ideas?

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  • add new records using signal in django admin

    - by ganesh
    I've a model called broadcastinfo, It has fields viz.. info,userid...userid is excluded. when i add an new info, my broadcastinfo table should get the records of all userid from user table and the given message. Im trying this via signal.Any idea is highly appreciated. Thanks

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  • Rails routing aliasing and namespaces

    - by kain
    Given a simple namespaced route map.namespace :api do |api| api.resources :genres end how can I reuse this block but with another namespace? Currently I'm achieving that by writing another routes hacked on the fly map.with_options :name_prefix => 'mobile_', :path_prefix => 'mobile' do |mobile| mobile.resources :genres, :controller => 'api/genres' end But it seems less than ideal.

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  • Default http/admin port in dropwizard project

    - by mithrandir
    I have a dropwizard project and I have maintained a config.yml file at the ROOT of the project (basically at the same level as pom.xml). Here I have specified the HTTP port to be used as follows: http: port:9090 adminPort:9091 I have the following code in my TestService.java file public class TestService extends Service<TestConfiguration> { @Override public void initialize(Bootstrap<TestConfiguration> bootstrap) { bootstrap.setName("test"); } @Override public void run(TestConfiguration config, Environment env) throws Exception { // initialize some resources here.. } public static void main(String[] args) throws Exception { new TestService().run(new String[] { "server" }); } } I expect the config.yml file to be used to determine the HTTP port. However the app always seems to start with the default ports 8080 and 8081. Also note that I am running this from eclipse. Any insights as to what am I doing wrong here ?

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  • Django and ImageField Question

    - by Hellnar
    Hello I have a such model: Foo (models.Model): slug = models.SlugField(unique=True) image = models.ImageField(upload_to='uploads/') I want to do two things with this: First of all, I want my image to be forced to resize to a specific width and height after the upload. I have tried this reading the documentation but seems to getting error: image = models.ImageField(upload_to='uploads/', height_field=258, width_field=425) Secondly, when adding an item via admin panel, I want my image's file name to be renamed as same as slug, if any issue arises (like if such named image already exists, add "_" to the end as it used to do. IE: My slug is i-love-you-guys , uploaded image such have i-love-you-guys.png at the end.

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  • Inline editing of ManyToMany relation in Django

    - by vorpyg
    After working through the Django tutorial I'm now trying to build a very simple invoicing application. I want to add several Products to an Invoice, and to specify the quantity of each product in the Invoice form in the Django admin. Now I've to create a new Product object if I've got different quantites of the same Product. Right now my models look like this (Company and Customer models left out): class Product(models.Model): description = models.TextField() quantity = models.IntegerField() price = models.DecimalField(max_digits=10,decimal_places=2) tax = models.ForeignKey(Tax) class Invoice(models.Model): company = models.ForeignKey(Company) customer = models.ForeignKey(Customer) products = models.ManyToManyField(Product) invoice_no = models.IntegerField() invoice_date = models.DateField(auto_now=True) due_date = models.DateField(default=datetime.date.today() + datetime.timedelta(days=14)) I guess the quantity should be left out of the Product model, but how can I make a field for it in the Invoice model?

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  • Default value for field in Django model

    - by Daniel Garcia
    Suppose I have a model: class SomeModel(models.Model): id = models.AutoField(primary_key=True) a = models.IntegerField(max_length=10) b = models.CharField(max_length=7) Currently I am using the default admin to create/edit objects of this type. How do I set the field 'a' to have the same number as id? (default=???) Other question Suppose I have a model: event_date = models.DateTimeField( null=True) year = models.IntegerField( null=True) month = models.CharField(max_length=50, null=True) day = models.IntegerField( null=True) How can i set the year, month and day fields by default to be the same as event_date field?

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  • Can't set up image upload in Django

    - by culebrón
    I can't understand what's not working here: 1) settings MEDIA_ROOT = '/var/www/satel/media' MEDIA_URL = 'http://media.satel.culebron' ADMIN_MEDIA_PREFIX = '/media/' 2) models class Photo(models.Model): id = models.AutoField(primary_key=True) name = models.CharField(max_length = 200) desc = models.TextField(max_length = 1000) img = models.ImageField(upload_to = 'upload') 3) access rights: drwxr-xrwx 3 culebron culebron 4.0K 2010-04-14 21:13 media drwxr-xrwx 2 culebron culebron 4.0K 2010-04-14 19:04 upload 4) SQL: CREATE TABLE "photos_photo" ( "id" integer NOT NULL PRIMARY KEY, "name" varchar(200) NOT NULL, "desc" text NOT NULL, "img" varchar(100) NOT NULL ); 4) run Django test server as myself. 5) result: SuspiciousOperation at /admin/photos/author/add/ Attempted access to '/var/www/satel/upload/OpenStreetMap.png' denied. Not a PIL & jpeg issue, seems not to be access rights issue. But what's wrong?

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  • Django Caught an exception while rendering: No module named registration

    - by Arno Smit
    I seem to have run into a bit of an issue. I am busy creating an app, and over the last few weeks setup my server to use Git, mod_wsgi to host this app. Since deploying it, everything seems to be running smoothly however, I had to go through all my files and insert the absolute url of the project to make sure it works fine. on my local machine from registration.models import UserRegistration on server from myapp.registration.models import UserRegistration Am I doing something wrong? And this has also caused an issue for me where I cannot access my django admin interface. All i get is this: Caught an exception while rendering: No module named registration Exception Value: Caught an exception while rendering: No module named registration As far as I am concerned my app has all the relevant urls, but it does not seem to work. Thank you in advance

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  • Django make model field name a link

    - by Daniel Garcia
    what Im looking to do is to have a link on the name of a field of a model. So when im filling the form using the admin interface i can access some information. I know this doesn't work but shows what i want to do class A(models.Model): item_type = models.CharField(max_length=100, choices=ITEMTYPE_CHOICES, verbose_name="<a href='http://www.quackit.com/html/codes'>Item Type</a>") Other option would be to put a description next to the field. Im not even sure where to start from.

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  • Alternate datasource for django model?

    - by slypete
    I'm trying to seamlessly integrate some legacy data into a django application. I would like to know if it's possible to use an alternate datasource for a django model. For example, can I contact a server to populate a list of a model? The server would not be SQL based at all. Instead it uses some proprietary tcp based protocol. Copying the data is not an option, as the legacy application will continue to be used for some time. Would a custom manager allow me to do this? This model should behave just like any other django model. It should even pluggable to the admin interface. What do you think? Thanks, Pete

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  • Django loaddata throws ValidationError: [u'Enter a valid date in YYYY-MM-DD format.'] on null=true f

    - by datakid
    When I run: django-admin.py loaddata ../data/library_authors.json the error is: ... ValidationError: [u'Enter a valid date in YYYY-MM-DD format.'] The model: class Writer(models.Model): first = models.CharField(u'First Name', max_length=30) other = models.CharField(u'Other Names', max_length=30, blank=True) last = models.CharField(u'Last Name', max_length=30) dob = models.DateField(u'Date of Birth', blank=True, null=True) class Meta: abstract = True ordering = ['last'] unique_together = ("first", "last") class Author(Writer): language = models.CharField(max_length=20, choices=LANGUAGES, blank=True) class Meta: verbose_name = 'Author' verbose_name_plural = 'Authors' Note that the dob DateField has blank=True, null=True The json file has structure: [ { "pk": 1, "model": "books.author", "fields": { "dob": "", "other": "", "last": "Carey", "language": "", "first": "Peter" } }, { "pk": 3, "model": "books.author", "fields": { "dob": "", "other": "", "last": "Brown", "language": "", "first": "Carter" } } ] The backing mysql database has the relevent date field in the relevant table set to NULL as default and Null? = YES. Any ideas on what I'm doing wrong or how I can get loaddata to accept null date values?

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  • PHP Framework / Library Suggestions for a Backend

    - by frbry
    I am about to start to developing backend site of a php project. Companies and site admins will login to this site and manage their data on the project. My previous admin panel experiences were full of agony and pain. So I want to make sure that I choose correct tools for my purpose. By the way, please note, I'm not looking for scaffolding. There won't be much tables in my database. Instead, there will be complex logic between entities. I want clear seperation of markup and logic code and easy-to-use and standardized user-interface. Thank you.

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  • Passing session data to ModelForm inside of ModelAdmin

    - by theactiveactor
    I'm trying to initialize the form attribute for MyModelAdmin class inside an instance method, as follows: class MyModelAdmin(admin.ModelAdmin): def queryset(self, request): MyModelAdmin.form = MyModelForm(request.user) My goal is to customize the editing form of MyModelForm based on the current session. When I try this however, I keep getting an error (shown below). Is this the proper place to pass session data to ModelForm? If so, then what may be causing this error? TypeError at ... Exception Type: TypeError Exception Value: issubclass() arg 1 must be a class Exception Location: /usr/lib/pymodules/python2.6/django/forms/models.py in new, line 185

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  • Overwrite queryset which builds filter sidebar

    - by cw
    Hi, I'm writing a hockey database/manager. So I have the following models: class Team(models.Model): name = models.CharField(max_length=60) class Game(models.Model): home_team = models.ForeignKey(Team,related_name='home_team') away_team = models.ForeignKey(Team,related_name='away_team') class SeasonStats(models.Model): team = models.ForeignKey(Team) Ok, so my problem is the following. There are a lot of teams, but Stats are just managed for my Club. So if I use "list_display" in the admin backend, I'd like to modify/overwrite the queryset which builds the sidebar for filtering, to just display our home teams as a filter option. Is this somehow possible in Django? I already made a custom form like this class SeasonPlayerStatsAdminForm(forms.ModelForm): team = forms.ModelChoiceField(Team.objects.filter(club__home=True)) So now just the filtering is missing. Any ideas?

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  • Not quite nested inlines?

    - by Lynden Shields
    Not quite sure what to call this, it's not quite nested inlines, but is probably related. I have a 3 level hierarchy of objects, A one-to-many B one-to-many C. Therefore, every C implicitly also belongs to an A. class A(models.Model): stuff = models.CharField("Stuff", max_length=50) class B(models.Model): a = models.ForeignKey(A) class C(models.Model): b = models.ForeignKey(B) I would like all C's that belong to an A to be listed on the admin page for A in an in-line. They do not have to show which B they belong to on the same page. Is this possible or is it the same problem as nested inlines anyway? If it's possible, how do I do it? I'm using django 1.3

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  • MVC Html.ActionLink not passing querystring properly

    - by Dave Hanna
    This seems like it should be pretty straight forward, but I'm apparently confused. I have a List view that displays a paged list. At the bottom I have a set of actionlinks: <%= Html.ActionLink("First Page", "List", new { page = 1} ) %> &nbsp; <%= Html.ActionLink("Prev Page", "List", new { page = Model.PageNumber - 1 }) %> &nbsp; <%= Html.ActionLink("Next Page", "List", new { page = Model.PageNumber + 1 }) %> &nbsp; <%= Html.ActionLink("Last Page", "List", new { page = Model.LastPage } )%> I'm using the basic default routes setup, except with "List" substituted for "Index": routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "List", id = UrlParameter.Optional } // Parameter defaults ); The problem is that the ActionLink helpers are generating links of the form: http://localhost:2083/Retrofit?page=2 rather than http://localhost:2083/Retrofit/?page=2 (with the trailing slash after the controller name & before the query string). When the first URL is routed, it completely loses the query string - if I look at Request.QueryString by the time it gets to the controller, it's null. If I enter the second URL (with the trailing slash), it comes in properly (i.e., QueryString of "page=2"). So how can I either get the ActionLink helper to generate the right URL, or get the Routing to properly parse what ActionLink is generating? Thanks.

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