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• Most efficient way to store list structure in XML

  - by Mike

  Starting a new project and was planning on storing all of my web content in XML. I do not have access to a database so this seemed like the next best thing. One thing I'm struggling with is how to structure the XML for links (which will later be transformed using XSLT). It needs to be fairly flexible as well. Below is what I started with, but I'm starting to question it. <links> <link> <url>http://google.com</url> <description>Google</description> <link> <link> <url>http://yahoo.com</url> <description>Yahoo</description> <links> <url>http://yahoo.com/search</url> <description>Search</description> </link> <link> </links> That should get transformed into Google Yahoo Search Perhaps something like this might work better. <links> <link href="http://google.com">Google</link> <link href="http://yahoo.com">Yahoo <link href="http://yahoo.com/search">Search</link> </link> </links> Does anyone perhaps have a link that talks about structuring web content properly in XML? Thank you. :)

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• Yet Another crosdomain.xml question or: "How to interpret documentation correctly"

  - by cboese

  Hi! I have read a lot about the new policy-policy of flash player and also know the master policy file. Now image the following situation: There are two servers with services (http) running at custom ports servera.com:2222/websiteA serverb.com:3333/websiteB Now I open a swf from server a (eg. servera.com:2222/websiteA/A.swf) that wants to access the service of serverb. Of course I need a crossdomain.xml at the right place and there are multiple variations possible. I dont want to use a master policy file, as I might not have control over the root of both servers. One solution I found works with the following crossdomain: <?xml version="1.0"?> <cross-domain-policy> <allow-access-from domain="*"/> </cross-domain-policy> served at serverb.com:3333/websiteB/crossdomain.xml So now for my question: Is it possible to get rid of the "*" and use a proper (not as general as *) domainname in the allow-access-from rule? All my attempts failed, and from what I understand it should be possible.

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• Trying to use an Xslt for an xml in asp.net

  - by Josemalive

  Hello, i have the following xslt sheet: <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:variable name="nhits" select="Answer[@nhits]"></xsl:variable> <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <div> <xsl:call-template name="resultsnumbertemplate"/> </div> </xsl:template> <xsl:template name="resultsnumbertemplate"> <xsl:value-of select="$nhits"/> matches found </xsl:template> </xsl:stylesheet> And this is the xml that im trying to mix with the previous xslt: <Answer xmlns="exa:com.exalead.search.v10" context="n%3Dsl-ocu%26q%3Dlavadoras" last="9" estimated="false" nmatches="219" nslices="0" nhits="219" start="0"> <time> <Time interrupted="false" overall="32348" parse="0" spell="0" exec="1241" synthesis="15302" cats="14061" kwds="14061"> <sliceTimes>15272 </sliceTimes> </Time> </time> </Answer> Im using a xslcompiledtransform and that's working fine: XslCompiledTransform transformer = new XslCompiledTransform(); transformer.Load(HttpContext.Current.Server.MapPath("xslt\\" + requestvariables["xslsheet"].ToString())); transformer.Transform(xmlreader, null, writer); My problems comes when im trying to put into a variable the "nhits" attribute value placed on the Answer element, but i'm not rendering anything using my xslt sheet. Do you know what could be the cause? Could be the xmlns attribute in my xml file? Thanks in advance. Best Regards. Jose

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• Problem Displaying XML in Grid View-newbie

  - by Dean

  I am trying to do something in VisualWebDev 2008 Express that I thought would be simple, but it is not working. I want to display data from an XML file so I added the XMLDataSource to my page, pointed it to the XML file, and then added the GridView and connected it to the datasource. I am getting the following error: GridView - GridView1There was an error rendering the control. The data source for GridView with id 'GridView1' did not have any properties or attributes from which to generate columns. Ensure that your data source has content. Could someone please tell me what I might be doing wrong, TIA Dean A smippet from my XML is as follows: 6019 - Renaissance MS - New School Renaissance MS 7155 Hall Road Fairburn, GA 30213 NS-6019200-LA-01 New School Close-out NS-6019200 0.000000000000000e+000 The construction of the new Renaissance MS will be at the intersection of Jones/Hall Road, in the districts 7th & 9F and Land Lots 117, 143 & 146 of Fulton County, GA. The work includes the construction of the 180,500 square foot building that will house 34 standard classrooms, 12 standard science labs, 20 special purpose classrooms, cafeteria and litchen, gymnasium, media center and administrative offices. The site will also have multi-purpose playfields with track, softball field, tennis courts and basketball/volleyball court. Terry O'Brien Parsons Stevens Wilkinson Stang Newdow Barton Malow -84.62242 33.61497

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• How to deploy EJB on server?

  - by shekhar

  Hi, I am learning EJB3 from last few days. I have many questions regarding EJB, application servers and deployment of EJB. To start with, I have created one simple helloworld stateless session bean but I don't know how to deploy it on server. It has single bean class, bean interface and one servlet client. I have used eclipse to develop this project. None of the books that I read gives step by step details about how to put EJB on server and how to access those beans. I have JBoss 6 server and I also have JEE budle downloaded from sun website. Does this JEE bundle contains Glassfish server? or do I need to download it seperately? Can anyone please give me step by step details of how to put my bean and its client on server (JBoss or JEE)? and why do we need to include bean interface class in EJB client code? I mean either we need to keep client and bean in same package or if we keep them in seperate packages we need to import bean interfaces in client code. Am I right? Thanks and Regards, Chandrashekhar

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• External log4j.xml file

  - by javamonkey79

  I am trying to run a jar with the log4j.xml file on the file system outside the jar like so: java -jar MyJarName.jar -cp=/opt/companyName/pathToJar/ log4j.configuration=log4j.xml argToJar1 argToJar2 I have also tried: java -jar MyJarName.jar -cp=/opt/companyName/pathToJar/ log4j.configuration=/opt/companyName/pathToJar/log4j.xml argToJar1 argToJar2 The log4j.xml is file is in the same directory as the jar (/opt/companyName/pathToJar/), yet I still get the standard warning message: log4j:WARN No appenders could be found for logger (org.apache.axis.i18n.ProjectResourceBundle). log4j:WARN Please initialize the log4j system properly. Is it possible to have the config file outside the jar, or do I have to package it with the jar? TIA

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• how to store xml data in array (php)

  - by tommy

  <?xml version="1.0" encoding="UTF-8" ?> - <response xmlns:lf="http://api.lemonfree.com/ns/1.0"> <lf:request_type>listing</lf:request_type> <lf:response_code>0</lf:response_code> - <lf:result type="listing" count="10"> - <lf:item id="56832429"> <lf:attr name="title">Used 2005 Ford Mustang V6 Deluxe</lf:attr> <lf:attr name="year">2005</lf:attr> <lf:attr name="make">FORD</lf:attr> <lf:attr name="model">MUSTANG</lf:attr> <lf:attr name="vin">1ZVFT80N555169501</lf:attr> <lf:attr name="price">12987</lf:attr> <lf:attr name="mileage">42242</lf:attr> <lf:attr name="auction">no</lf:attr> <lf:attr name="city">Grand Rapids</lf:attr> <lf:attr name="state">Michigan</lf:attr> <lf:attr name="image">http://www.lemonfree.com/images/stock_images/thumbnails/2005_38_557_80.jpg</lf:attr> <lf:attr name="link">http://www.lemonfree.com/56832429.html</lf:attr> </lf:item> Above is the xml i am working with - there are more items - this is the first set. How can i get these elements in to an array. I have been trying with php's simple xml etc but i just cant do it. Thanks guys

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• Formatting the parent and child nodes of a Treeview that is populated by a XML file

  - by Marina

  Hello Everyone, I'm very new to xml so I hope I'm not asking any silly question here. I'm currently working on populating a treeview from an XML file that is not hierarchically structured. In the xml file that I was given the child and parent nodes are defined within the attributes of the item element. How would I be able to utilize the attributes in order for the treeview to populate in the right hierarchical order. (Example Mary Jane should be a child node of Peter Smith). At present all names are under one another. root <item parent_id="0" id="1"><content><name>Peter Smith</name></content></item> <item parent_id="1" id="2"><content><name>Mary Jane</name></content></item> <item parent_id="1" id="7"><content><name>Lucy Lu</name></content></item> <item parent_id="2" id="3"><content><name>Informatics Team</name></content></item> <item parent_id="3" id="4"><content><name>Sandy Chu</name></content></item> <item parent_id="4" id="5"><content><name>John Smith</name></content></item> <item parent_id="5" id="6"><content><name>Jane Smith</name></content></item> /root Thank you for all of your help, Marina

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• C# LINQ to XML nissing space character.

  - by Fossaw

  I write an XML file "by hand", (i.e. not with LINQ to XML), which sometimes includes an open/close tag containing a single space character. Upon viewing the resulting file, all appears correct, example below... <Item> <ItemNumber>3</ItemNumber> <English> </English> <Translation>Ignore this one. Do not remove.</Translation> </Item> ... the reasons for doing this are various and irrelevent, it is done. Later, I use a C# program with LINQ to XML to read the file back and extract the record... XElement X_EnglishE = null; // This is CRAZY foreach (XElement i in Records) { X_EnglishE = i.Element("English"); // There is only one damned record! } string X_English = X_EnglishE.ToString(); ... and test to make sure it is unchanged from the database record. I detect a change, when processing Items where the field had the single space character... +E+ Text[3] English source has been altered: Was: >>> <<< Now: >>><<< ... the and <<< parts I added to see what was happening, (hard to see space characters). I have fiddled around with this but can't see why this is so. It is not absolutely critical, as the field is not used, (yet), but I cannot trust C# or LINQ or whatever is doing this, if I do not understand why it is so. So what is doing that and why?

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• Serialize a C# class to xml. Store the XML as a string in SQL Server and then restore the class late

  - by BrianK

  I want to serialize a class to xml and store that in a field in a database. I can serialize with this: StringWriter sw = new StringWriter(); XmlSerializer xmlser = new XmlSerializer(typeof(MyClass)); xmlser.Serialize(sw, myClassVariable); string s = sw.ToString(); sw.Close(); Thats works, but it has the namesapces in it. xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" Will these slow down the deserialization because it will go out to those and verify the XML? I got rid of the namespaces by creating a blank XmlSerializerNamespaces and using that to serialize, but then the xml still had namespaces around integer variables: <anyType xmlns:q1="http://www.w3.org/2001/XMLSchema" d3p1:type="q1:int" xmlns:d3p1="http://www.w3.org/2001/XMLSchema-instance"> 3 </anyType> My question is: Is it necessary to have the namesapces for deserialization and if not, how to get rid of them? How do I tell it fields are ints so it doesnt put in "anytype" Thanks, Brian

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• How to change attribute on Scala XML Element

  - by Dave

  I have an XML file that I would like to map some attributes of in with a script. For example: <a> <b attr1 = "100" attr2 = "50"> </a> might have attributes scaled by a factor of two: <a> <b attr1 = "200" attr2 = "100"> </a> This page has a suggestion for adding attributes but doesn't detail a way to map a current attribute with a function (this way would make that very hard): http://www.scalaclass.com/book/export/html/1 What I've come up with is to manually create the XML (non-scala) linked-list... something like: // a typical match case for running thru XML elements: case Elem(prefix, e, attributes, scope, children @ _*) => { var newAttribs = attributes for(attr <- newAttribs) attr.key match { case "attr1" => newAttribs = attribs.append(new UnprefixedAttribute("attr1", (attr.value.head.text.toFloat * 2.0f).toString, attr.next)) case "attr2" => newAttribs = attribs.append(new UnprefixedAttribute("attr2", (attr.value.head.text.toFloat * 2.0f).toString, attr.next)) case _ => } Elem(prefix, e, newAttribs, scope, updateSubNode(children) : _*) // set new attribs and process the child elements } Its hideous, wordy, and needlessly re-orders the attributes in the output, which is bad for my current project due to some bad client code. Is there a scala-esque way to do this?

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• Deleting an XML tag using C#

  - by gsvirdi

  FIRST EDIT I'm fetching the Child 1 tag into a DropDownList in my C# form, Plz suggest the best practise code (C#) for deleting a Particular Parent tag & all it's child tags in an XML file. Example of my xml file: <Parents> <Parent> <Child 1>Something</Child 1> <Child 2>Something</Child 2> <Child 3>Something</Child 3> <Child 4>Something</Child 4> </Parent> <Parent> <Child 1>Something 1</Child 1> <Child 2>Something 1</Child 2> <Child 3>Something 1</Child 3> <Child 4>Something 1</Child 4> </Parent> </Parents> I mean something like: for (int i=0; i<[Length of xml doc]; i++) { if (Child 1 == ComboBox1.Text && Child 2 == richTextBox1.Text) // Delete <Parent> tag of that Child 1 }

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• xml vs java LinearLayout fills

  - by user293443

  the xml version below properly handles height and width and the java doesn't what is the java missing? xml <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_height="fill_parent" android:layout_width="fill_parent" android:orientation="horizontal"> <include android:id="@+id/cell1" layout="@layout/grid_text_view" /> <include android:id="@+id/cell2" layout="@layout/grid_text_view" /> </LinearLayout> java LinearLayout ll = new LinearLayout(this); ll.setOrientation(LinearLayout.HORIZONTAL); ll.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT)); ll.addView((TextView)this.getLayoutInflater().inflate(R.layout.grid_text_view, null)); ll.addView((TextView)this.getLayoutInflater().inflate(R.layout.grid_text_view, null)); setContentView(ll); grid_text_view <TextView xmlns:android="http://schemas.android.com/apk/res/android" android:layout_height="fill_parent" android:layout_width="0dip" android:text="1" android:textSize="20sp" android:gravity="center" android:layout_weight="1" /> I've tried a ll.invalidate() and it didn't work either? :( screenshots at http://www.flickr.com/photos/48409507@N06/sets/72157623618407586/

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• Serializing a DataType="time" field using XmlSerializer

  - by CraftyFella

  Hi, I'm getting an odd result when serializing a DateTime field using XmlSerializer. I have the following class: public class RecordExample { [XmlElement("TheTime", DataType = "time")] public DateTime TheTime { get; set; } [XmlElement("TheDate", DataType = "date")] public DateTime TheDate { get; set; } public static bool Serialize(Stream stream, object obj, Type objType, Encoding encoding) { try { using (var writer = XmlWriter.Create(stream, new XmlWriterSettings { Encoding = encoding })) { var xmlSerializer = new XmlSerializer(objType); if (writer != null) xmlSerializer.Serialize(writer, obj); } return true; } catch (Exception) { return false; } } } When i call the use the XmlSerializer with the following testing code: var obj = new RecordExample {TheDate = DateTime.Now.Date, TheTime = new DateTime(0001, 1, 1, 12, 00, 00)}; var ms = new MemoryStream(); RecordExample.Serialize(ms, obj, typeof (RecordExample), Encoding.UTF8); txtSource2.Text = Encoding.UTF8.GetString(ms.ToArray()); I get some strange results, here's the xml that is produced: <?xml version="1.0" encoding="utf-8"?> <RecordExample xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <TheTime>12:00:00.0000000+00:00</TheTime> <TheDate>2010-03-08</TheDate> </RecordExample> Any idea's how i can get the "TheTime" element to contain a time which looks more like this: <TheTime>12:00:00.0Z</TheTime> ...as that's what i was expecting? Thanks Dave

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• PHP: Need help with simple XML

  - by Jack

  I am beginner in PHP. I am trying to parse this xml file. <relationship> <target> <following type="boolean">true</following> <followed_by type="boolean">true</followed_by> <screen_name>xxxx</screen_name> <id type="integer">xxxx</id> </target> <source> <notifications_enabled nil="true"/> <following type="boolean">true</following> <blocking nil="true"/> <followed_by type="boolean">true</followed_by> <screen_name>xxxx</screen_name> <id type="integer">xxxxx</id> </source> </relationship> I need to get the value of the field 'following type="boolean" ' for the target and here's my code - $xml = simplexml_load_string($response); foreach($xml->children() as $child) { if ($child->getName() == 'target') { foreach($child->children() as $child_1) if ( $child_1->getName() == 'following') { $is_my_friend = (bool)$child_1; break; } break; } } but I am not getting the correct output. I think the ' type="boolean" ' part of the field is creating problems. Please help.

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• How do I write unescaped XML outside of a CDATA

  - by kazanaki

  Hello I am trying to write XML data using Stax where the content itself is HTML If I try xtw.writeStartElement("contents"); xtw.writeCharacters("<b>here</b>"); xtw.writeEndElement(); I get this <contents>&lt;b&gt;here&lt;/b&gt;</contents> Then I notice the CDATA method and change my code to: xtw.writeStartElement("contents"); xtw.writeCData("<b>here</b>"); xtw.writeEndElement(); and this time the result is <contents><![CDATA[<b>here</b>]]></contents> which is still not good. What I really want is <contents><b>here</b></contents> So is there an XML API/Library that allows me to write raw text without being in a CDATA section? So far I have looked at Stax and JDom and they do not seem to offer this. In the end I might resort to good old StringBuilder but this would not be elegant. Update I agree mostly with the answers so far. However instead of <b>here</b> I could have a 1MB HTML document that I want to embed in a bigger XML document. What you suggest means that I have to parse this HTML document in order to understand its structure. I would like to avoid this if possible.

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• XmlAttribute/XmlText cannot be used to encode complex type

  - by Conrad C

  I want to serialize a class Ticket into xml. I get the error :"XmlAttribute/XmlText cannot be used to encode complex type" because of my customfield class. This is how the xml for customfields should look like ( the attribute array is nesseray but I don't understand how to create it): <custom_fields type="array"> <custom_field name="Standby Reason" id="6"> <value/> </custom_field> <custom_field name="Close Date" id="84"> Class Ticket public class Ticket { [XmlElement("custom_fields")] public CustomFields Custom_fields { get; set; } Class CustomFields [Serializable] public class CustomFields { [XmlAttribute("array")] public List<CustomField> custom_field { get; set; } Class CustomField [Serializable] public class CustomField { [XmlIgnore] public string Name { get; set; } [XmlElement] public int Id { get; set; } [XmlElement] public string Value { get; set; }

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• Creating XML problem using c#

  - by Pankaj

  I am searching a batter solution for creating xml through xml serialization. What i need, i have a given format like this <product Id="1"> <name>2 1/2 X 6 PVC NIPPLE TOE SCH 80</name> <notes> <note>!--note 1---</note> <note>!--note 2--</note> ...... </notes> </product> what i am doing here, i created a 2 classes like this public class product { [XmlElement("name")] public string Name { get; set; } [XmlArray("notes")] public List<notes> ListNotes { get; set; } } public class notes { [XmlIgnore] public string Note { get; set; } } when i am serializing this then i am getting xml in this formate <product Id="1"> <name>2 1/2 X 6 PVC NIPPLE TOE SCH 80</name> <notes> <notes> <note>!--note 1---</note> <note>!--note 2--</note> </notes> </notes> </product> i don't want extra . Any batter solution to solve this problem? Thanks

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• SQL 2008 Querying Soap XML

  - by Vince

  I have been trying to process this SOAP XML return using SQL but all I get is NULL or nothing at all. I have tried different ways and pasted them all below. Declare @xmlMsg xml; Set @xmlMsg = '<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <SendWarrantyEmailResponse xmlns="http://Web.Services.Warranty/"> <SendWarrantyEmailResult xmlns="http://Web.Services.SendWarrantyResult"> <WarrantyNumber>120405000000015</WarrantyNumber> <Result>Cannot Send Email to anonymous account!</Result> <HasError>true</HasError> <MsgUtcTime>2012-06-07T01:11:36.8665126Z</MsgUtcTime> </SendWarrantyEmailResult> </SendWarrantyEmailResponse> </soap:Body> </soap:Envelope>'; declare @table table (data xml); insert into @table values (@xmlMsg); select data from @table; WITH xmlnamespaces ('http://schemas.xmlsoap.org/soap/envelope/' as [soap], 'http://Web.Services.Warranty' as SendWarrantyEmailResponse, 'http://Web.Services.SendWarrantyResult' as SendWarrantyEmailResult) SELECT Data.value('(/soap:Envelope[1]/soap:Body[1]/SendWarrantyEmailResponse[1]/SendWarrantyEmailResult[1]/WarrantyNumber[1])[1]','VARCHAR(500)') AS WarrantyNumber FROM @Table ; ;with xmlnamespaces('http://schemas.xmlsoap.org/soap/envelope/' as [soap],'http://Web.Services.Warranty' as SendWarrantyEmailResponse,'http://Web.Services.SendWarrantyResult' as SendWarrantyEmailResult) --select @xmlMsg.value('(/soap:Envelope/soap:Body/SendWarrantyEmailResponse/SendWarrantyEmailResult/WarrantyNumber)[0]', 'nvarchar(max)') --select T.N.value('.', 'nvarchar(max)') from @xmlMsg.nodes('/soap:Envelope/soap:Body/SendWarrantyEmailResponse/SendWarrantyEmailResult') as T(N) select @xmlMsg.value('(/soap:Envelope/soap:Body/SendWarrantyEmailResponse/SendWarrantyEmailResult/HasError)[1]','bit') as test ;with xmlnamespaces('http://schemas.xmlsoap.org/soap/envelope/' as [soap],'http://Web.Services.Warranty' as [SendWarrantyEmailResponse],'http://Web.Services.SendWarrantyResult' as [SendWarrantyEmailResult]) SELECT SendWarrantyEmailResult.value('WarrantyNumber[1]','varchar(max)') AS WarrantyNumber, SendWarrantyEmailResult.value('Result[1]','varchar(max)') AS Result, SendWarrantyEmailResult.value('HasError[1]','bit') AS HasError, SendWarrantyEmailResult.value('MsgUtcTime[1]','datetime') AS MsgUtcTime FROM @xmlMsg.nodes('/soap:Envelope/soap:Body/SendWarrantyEmailResponse/SendWarrantyEmailResult') SendWarrantyEmailResults(SendWarrantyEmailResult)

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• How to configure Eclipse XML formatting?

  - by tputkonen

  I would like to change the way Eclipse formats XML files. For example, if I have in pom.xml file a section as follows: <dependency> <groupId>junit</groupId> <artifactId>junit</artifactId> <version>3.8.1</version> <scope>test</scope> </dependency> After ctrl+shift+f it will look like: <dependency> <groupId> junit </groupId> <artifactId> junit </artifactId> <version> 3.8.1 </version> <scope> test </scope> </dependency> I prefer the first version, so how to configure Eclipse to format XML files to look like that?

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• How to properly add newlines to an XML string in PHP?

  - by stormist

  I have some xml that I manually construct in a function that is something like: $xml = "<myxml>"; $xml .= "<items>"; $xml .= "<item1>blah</item1>"; $xml .= "</items>"; $xml .= "</myxml>"; When I output the string though I'd like the newlines to be present. How can I add this to the string without affecting a web service accepting the xml? Do newlines in XML even matter?

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• XML-RPC over SSL with Ruby: end of file reached (EOFError)

  - by Michael Conigliaro

  Hello, I have some very simple Ruby code that is attempting to do XML-RPC over SSL: require 'xmlrpc/client' require 'pp' server = XMLRPC::Client.new2("https://%s:%d/" % [ 'api.ultradns.net', 8755 ]) pp server.call2('UDNS_OpenConnection', 'sponsor', 'username', 'password') The problem is that it always results in the following EOFError exception: /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/net/protocol.rb:135:in `sysread': end of file reached (EOFError) So it appears that after doing the POST, I don't get anything back. Interestingly, this is the behavior I would expect if I tried to make an HTTP connection on the HTTPS port (or visa versa), and I actually do get the same exact exception if I change the protocol. Everything I've looked at indicates that using "https://" in the URL is enough to enable SSL, but I'm starting wonder if I've missed something. Note that Even though the credentials I'm using in the RPC are made up, I'm expecting to at least get back an XML error page (similar to if you access https://api.ultradns.net:8755/ with a web browser). I've tried running this code on OSX and Linux with the exact same result, so I have to conclude that I'm just doing something wrong here. Does anyone have any examples of doing XML-RPC over SSL with Ruby?

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• Where does Tomcat cache my taglib .jar files?

  - by NogginTheNog

  I'm deploying a .jar file to a tomcat instance (we're running 6.0.18 on Redhat linux) and according to the log output the old .jar is still being used. I've restarted everthing I can think of, have deleted the work directory etc.etc. but to no avail. I'm no tomcat expert, so here's my question: where should I look for to ascertain if tomcat is using a cached jar and how should I prevent it from doing so?

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• Duplicate elements when adding XElement to XDocument

  - by Andy

  I'm writing a program in C# that will go through a bunch of config.xml files and update certain elements, or add them if they don't exist. I have the portion down that updates an element if it exists with this code: XDocument xdoc = XDocument.Parse(ReadFile(_file)); XElement element = xdoc.Elements("project").Elements("logRotator") .Elements("daysToKeep").Single(); element.Value = _DoRevert; But I'm running into issues when I want to add an element that doesn't exist. Most of the time part of the tree is in place and when I use my code it adds another identical tree, and that causes the program reading the xml to blow up. here is how I am attempting to do it xdoc.Element("project").Add(new XElement("logRotator", new XElement("daysToKeep", _day))); and that results in a structure like this(The numToKeep tag was already there): <project> <logRotator> <daysToKeep>10</daysToKeep> </logRotator> <logRotator> <numToKeep>13</numToKeep> </logRotator> </project> but this is what I want <project> <logRotator> <daysToKeep>10</daysToKeep> <numToKeep>13</numToKeep> </logRotator> </project>

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• Parsing XML in C# from stream

  - by Phillip

  I've tried several methods, from Linq to loading the data to an XML document, but i can't seem to be able to return the result that i need. here's the example XML: <serv:message xmlns:serv="http://www.webex.com/schemas/2002/06/service" xmlns:com="http://www.webex.com/schemas/2002/06/common" xmlns:event="http://www.webex.com/schemas/2002/06/service/event"><serv:header><serv:response><serv:result>SUCCESS</serv:result><serv:gsbStatus>PRIMARY</serv:gsbStatus></serv:response></serv:header><serv:body><serv:bodyContent xsi:type="event:createEventResponse" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><event:sessionKey>11111111</event:sessionKey><event:guestToken>111111111111111111111</event:guestToken></serv:bodyContent></serv:body></serv:message> And, here's what i've tried to do: StreamReader reader = new StreamReader(dataStream); XmlDocument doc = new XmlDocument(); doc.LoadXml(reader.ReadToEnd()); XmlNamespaceManager ns = new XmlNamespaceManager(doc.NameTable); XmlNamespaceManager ns2 = new XmlNamespaceManager(doc.NameTable); XmlNamespaceManager ns3 = new XmlNamespaceManager(doc.NameTable); ns.AddNamespace("serv", "http://www.webex.com/schemas/2002/06/service"); ns2.AddNamespace("com", "http://www.webex.com/schemas/2002/06/common"); ns3.AddNamespace("event", "http://www.webex.com/schemas/2002/06/service/event"); XmlNode node = doc.SelectSingleNode("result",ns); Yet, for some reason i cannot ever seem to return the actual result, which should be either 'SUCCESS' or 'FAILURE' based on the actual xml above. How can i do this?

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