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  • Self updating app, wont overwrite existing app, using Android packagemanager?

    - by LokiSinclair
    I know there are plenty of questions about this on here, but I've tried everything (but the correct 'thing', obviously!) and nothing seems to shine any light on the problem I'm having. I've written an app (for a customer), which is designed to be hosted on their own server. The app references a simple text file with the latest version code in it and checks it against it's own version. If it's out of date it goes off and downloads the update. Everything is working as intended up to this point. I use the: Intent i = new Intent(Intent.ACTION_VIEW); i.setDataAndType(Uri.fromFile(outputFile), "application/vnd.android.package-archive"); i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK); startActivity(i); ...code to start the install process of the newly downloaded .apk file. And that all starts as I would expect. I click on "Install" - when I'm prompted to confirm the overwriting of the current app, with the new. It starts, and then displays: App not installed. And existing package by the same name with a conflicting signature is already installed. Now I'm aware that Android can't have multiple applications sharing the same package name, which is fine, but nothing comes up in LogCat and I can only assume that the OS is annoyed at me attempting to 'update' my app, even though I'm going through all the correct channels and using the inbuilt package manager to do it for me! Can anyone tell me what the OS is moaning about? I'm not attempting to install two apps side by side, I want it to update it, which it starts to do, and then gets really confused. Is it something to do with me using the same keystore for signing the packages? I highly doubt it as I've used the same keystores previously to handle updates to games and the like, but I just can't figure out what it's complaining about. Hopefully someone out there has had this issue and solved it, and can point me in the right direction. I'm flying a bit blind with the limited information it's giving me :( Cheers.

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  • Working with legacy data

    - by John Paul Cook
    We encounter legacy data as a part of life. Colleges and universities have transcript records dating back decades or even centuries. Real estate property records in the United States go as far back as Spanish and British land grants in the 1500s. Very old records are completely paper based and may be completely manually prepared, perhaps typed on a typewriter or written in longhand with a quill pen. How long should transcripts be retained? Nola Ochs graduated from college at age 95 (can you imagine...(read more)

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  • Oracle/c#: How do i use bind variables with select statements to return multiple records?

    - by twiga
    I have a question regarding Oracle bind variables and select statements. What I would like to achieve is do a select on a number different values for the primary key. I would like to pass these values via an array using bind values. select * from tb_customers where cust_id = :1 int[] cust_id = { 11, 23, 31, 44 , 51 }; I then bind a DataReader to get the values into a table. The problem is that the resulting table only contains a single record (for cust_id=51). Thus it seems that each statement is executed independently (as it should), but I would like the results to be available as a collective (single table). A workaround is to create a temporary table, insert all the values of cust_id and then do a join against tb_customers. The problem with this approach is that I would require temporary tables for every different type of primary key, as I would like to use this against a number of tables (some even have combined primary keys). Is there anything I am missing?

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  • How do I do a join in ActiveRecord after records have been returned?

    - by Russ Bradberry
    I am using ActiveRecord in Rails 3 to pull data from two different tables in two different databases. These databases can not join on each other, but I have the need to do a simple join after-the-fact. I would like to preserve the relation so that I can chain it down the line. here is a simplified version of what I am doing browsers = Browser.all # <-- this is fairly small and can reside in memory events = Event.where(:row_date=>Date.today).select(:name, :browser_id) So as you can see, I want to join browsers in on the events relation, where browser_id should equal browsers.name. events is a relation and I can still add clauses to it down the line, so I dont want to run the query on the db just yet. How would I accomplish this?

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  • SQL: without a cursor, how to select records making a unique integer id (identity like) for dups?

    - by Dr. Zim
    If you have the select statement below where the PK is the primary key: select distinct dbo.DateAsInt( dateEntered) * 100 as PK, recordDescription as Data from MyTable and the output is something like this (the first numbers are spaced for clarity): PK Data 2010 01 01 00 New Years Day 2010 01 01 00 Make Resolutions 2010 01 01 00 Return Gifts 2010 02 14 00 Valentines day 2010 02 14 00 Buy flowers and you want to output something like this: PK Data 2010 01 01 01 New Years Day 2010 01 01 02 Make Resolutions 2010 01 01 03 Return Gifts 2010 02 14 01 Valentines day 2010 02 14 02 Buy flowers Is it possible to make the "00" in the PK have an "identity" number effect within a single select? Otherwise, how could you increment the number by 1 for each found activity for that date? I am already thinking as I type to try something like Sum(case when ?? then 1 end) with a group by.

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  • WebCenter Customer Spotlight: Alberta Agriculture and Rural Developmen

    - by me
    Author: Peter Reiser - Social Business Evangelist, Oracle WebCenter  Solution SummaryAlberta Agriculture and Rural Development is a government ministry that works with producers and consumers to create a strong, competitive, and sustainable agriculture and food industry in the province of Alberta, Canada The primary business challenge faced by the Alberta Ministry of Agriculture was that of managing the rapid growth of their information.  They needed to incorporate a system that would work across 22 different divisions within the ministry and deliver an improved and more efficient experience for Desktop, Web and Mobile users, while addressing their regulatory compliance needs as part of the Canadian government. The customer implemented a centralized Enterprise Content Management solution based on Oracle WebCenter Content and developed a strong and repeatable information life cycle management methodology across all their 22 divisions and agencies. With the implemented solution, Alberta Agriculture and Rural Development  centrally manages over 20 million documents for 22 divisions and agencies and they have improved time required to find records,  reliability of information, improved speed and accuracy of reporting and data security. Company OverviewAlberta Agriculture and Rural Development is a government ministry that works with producers and consumers to create a strong, competitive, and sustainable agriculture and food industry in the province of Alberta, Canada.  Business ChallengesThe business users were overwhelmed by growth in documents (over 20 million files across 22 divisions and agencies) and it was difficult to find and manage documents and versions. There was a strong need for a personalized easy-to-use, secure and dependable method of managing and consuming content via desktop, Web, and mobile, while improving efficiency and maintaining regulatory compliance by removing the risk of non-uniform approaches to retention and disposition. Solution DeployedAs a first step Alberta Agriculture and Rural Development developed a business case with clear defined business drivers: Reduce time required to find records Locate “lost” records Capture knowledge lost through attrition Increase the ease of retrieval Reduce personal copies Increase reliability of information Improve speed and accuracy of reporting Improve data security The customer implemented a centralized Enterprise Content Management solution based on Oracle WebCenter Content. They used an incremental implementation approach aligned with their divisional and agency structure which allowed continuous process improvement. This led to a very strong and repeatable information life cycle management methodology across all their 22 divisions and agencies. Business ResultsAlberta Agriculture and Rural Development achieved impressive business results: Centrally managing over 20 million files for 22 divisions and agencies Federated model to manage documents in SharePoint and other applications Doing records management for both paper and electronic records Reduced time required to find records Increased the ease of retrieval Increased reliability of information Improved speed and accuracy of reporting Improved data security Additional Information Oracle Open World 2012 Presentation Oracle WebCenter Content

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  • Why am I returning empty records when querying in mysql with php?

    - by Brian Bolton
    I created the following script to query a table and return the first 30 results. The query returns 30 results, but they do not have any text or information. Why would this be? The table stores Vietnamese characters. The database is mysql4. Here's the page: http://saomaidanang.com/recentposts.php Here's the code: <?php header( 'Content-Type: text/html; charset=utf-8' ); //CONNECTION INFO $dbms = 'mysql'; $dbhost = 'xxxxx'; $dbname = 'xxxxxxx'; $dbuser = 'xxxxxxx'; $dbpasswd = 'xxxxxxxxxxxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpasswd ) or die('Error connecting to mysql'); mysql_select_db($dbname , $conn); //QUERY $result = mysql_query("SET NAMES utf8"); $cmd = 'SELECT * FROM `phpbb_posts_text` ORDER BY `phpbb_posts_text`.`post_subject` DESC LIMIT 0, 30 '; $result = mysql_query($cmd); ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html dir="ltr"> <head> <title>recent posts</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> </head> <body> <p> <?php //DISPLAY while ($myrow = mysql_fetch_row($result)) { echo 'post subject:'; echo(utf8_encode($myrow ['post_subject'])); echo 'post text:'; echo(utf8_encode($myrow ['post_text'])); } ?> </p> </body>

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  • MySQL, Coldfusion, Selecting records that were timestamped in the last 24 hours.

    - by nobosh
    With Coldfuson & MySQL - How to update the query to check for new entries that have a timestamp that occurs in the last 24 hours? Query: <cfquery name="caller.sel_BlogEntries" datasource="#request.db#"> SELECT blogentry.dateAdded, person.personName FROM blogentry INNER JOIN person ON blogentry.personID = person.personID WHERE blogentry.deleted = 'N' ORDER BY blogentry.dateAdded DESC </cfquery> blogentry.dateAdded is a MySql TimeStamp Thanks

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  • Restricting access to records. Is claim-based permissions a good idea.

    - by Vitalik
    in .net Claim-based identity framework If i wanted to restrict users to do an operation (view or edit) on let's say an account, a particular account #123456.(i am talking about business entity, like a bank account.) Is it a good idea to create a claim for each account they can view or edit? Any disadvantages of having a lot of claims in a set? a system admin might have access to all accounts in the system thus creating hundreds of claims (maybe more than one for each account)

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  • Specific ordering of records based on list of IDs? with MySQL & PHP

    - by Mr
    I have a 'user' table in MySQL When users login to my app, they can see a list of all other users and via some javascript-drag-drop can arrange which order the other users appear in. We want to save that order. And it is saved to their record (i.e. 'order_pref' = 4,3,5,23... list of user_ids in the order they specified). So that's fine but when it comes to displaying.. Is there an easy way I can sort based on this comma delimited list of user_ids using just one query?

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  • How to split records per hour in order to display them as a chart?

    - by Axel
    Hi, I have an SQL table like this : sales(product,timestamp) I want to display a chart using Open Flash Chart but i don't know how to get the total sales per hour within the last 12 hours. ( the timestamp column is the sale date ) By example i will end up with an array like this : array(12,5,8,6,10,35,7,23,4,5,2,16) every number is the total sales in each hour. Note: i want to use php or only mysql for this. Thanks

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  • Tricky mod_rewrite challenge

    - by And Finally
    I list about 9,000 records on my little site. At the moment I'm showing them with a dynamic page, like http://domain.com/records.php?id=019031 But I'd like to start using meaningful URLs like this one on Amazon http://www.amazon.co.uk/Library-Mythology-Oxford-Worlds-Classics/dp/0199536325 where the title string on the root level gets ignored and requests are redirected to the records.php page, which accepts the ID as usual. Does anybody know how I could achieve that with mod_rewrite? I'm wondering how I'd deal with requests to my other root-level pages, like http://domain.com/contact.php, that I don't want to redirect to the records page.

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  • If a table has two xml columns, will inserting records be a lot slower?

    - by Lieven Cardoen
    Is it a bad thing to have two xml columns in one table? + How much slower are these xml columns in terms of updating/inserting/reading data? In profiler this kind of insert normally takes 0 ms, but sometimes it goes up to 160ms: declare @p8 xml set @p8=convert(xml,N'<interactions><interaction correct="false" score="0" id="0" gapid="0" x="61" y="225"><feedback/><element id="0" position="0" elementtype="1"><asset/></element></interaction><interaction correct="false" score="0" id="1" gapid="1" x="64" y="250"><feedback/><element id="0" position="0" elementtype="1"><asset/></element></interaction><interaction correct="false" score="0" id="2" gapid="2" x="131" y="250"><feedback/><element id="0" position="0" elementtype="1"><asset/></element></interaction></interactions>') declare @p14 xml set @p14=convert(xml,N'<contentinteractions/>') exec sp_executesql N'INSERT INTO [dbo].[PackageSessionNodes]([dbo].[PackageSessionNodes].[PackageSessionId], [dbo].[PackageSessionNodes].[TreeNodeId],[dbo].[PackageSessionNodes].[Duration], [dbo].[PackageSessionNodes].[Score],[dbo].[PackageSessionNodes].[ScoreMax], [dbo].[PackageSessionNodes].[Interactions],[dbo].[PackageSessionNodes].[BrainTeaser], [dbo].[PackageSessionNodes].[DateCreated], [dbo].[PackageSessionNodes].[CompletionStatus], [dbo].[PackageSessionNodes].[ReducedScore], [dbo].[PackageSessionNodes].[ReducedScoreMax], [dbo].[PackageSessionNodes].[ContentInteractions]) VALUES (@ins_dboPackageSessionNodesPackageSessionId, @ins_dboPackageSessionNodesTreeNodeId, @ins_dboPackageSessionNodesDuration, @ins_dboPackageSessionNodesScore, @ins_dboPackageSessionNodesScoreMax, @ins_dboPackageSessionNodesInteractions, @ins_dboPackageSessionNodesBrainTeaser, @ins_dboPackageSessionNodesDateCreated, @ins_dboPackageSessionNodesCompletionStatus, @ins_dboPackageSessionNodesReducedScore, @ins_dboPackageSessionNodesReducedScoreMax, @ins_dboPackageSessionNodesContentInteractions) ; SELECT SCOPE_IDENTITY() as new_id This is the table: CREATE TABLE [dbo].[PackageSessionNodes]( [PackageSessionNodeId] [int] IDENTITY(1,1) NOT NULL, [PackageSessionId] [int] NOT NULL, [TreeNodeId] [int] NOT NULL, [Duration] [int] NULL, [Score] [float] NOT NULL, [ScoreMax] [float] NOT NULL, [Interactions] [xml] NOT NULL, [BrainTeaser] [bit] NOT NULL, [DateCreated] [datetime] NULL, [CompletionStatus] [int] NOT NULL, [ReducedScore] [float] NOT NULL, [ReducedScoreMax] [float] NOT NULL, [ContentInteractions] [xml] NOT NULL, CONSTRAINT [PK_PackageSessionNodes] PRIMARY KEY CLUSTERED ( [PackageSessionNodeId] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO ALTER TABLE [dbo].[PackageSessionNodes] WITH CHECK ADD CONSTRAINT [FK_PackageSessionNodes_PackageSessions] FOREIGN KEY([PackageSessionId]) REFERENCES [dbo].[PackageSessions] ([PackageSessionId]) ON UPDATE CASCADE ON DELETE CASCADE GO ALTER TABLE [dbo].[PackageSessionNodes] CHECK CONSTRAINT [FK_PackageSessionNodes_PackageSessions] GO ALTER TABLE [dbo].[PackageSessionNodes] WITH CHECK ADD CONSTRAINT [FK_PackageSessionNodes_TreeNodes] FOREIGN KEY([TreeNodeId]) REFERENCES [dbo].[TreeNodes] ([TreeNodeId]) GO ALTER TABLE [dbo].[PackageSessionNodes] CHECK CONSTRAINT [FK_PackageSessionNodes_TreeNodes] GO ALTER TABLE [dbo].[PackageSessionNodes] ADD CONSTRAINT [DF_PackageSessionNodes_Score] DEFAULT ((-1)) FOR [Score] GO ALTER TABLE [dbo].[PackageSessionNodes] ADD CONSTRAINT [DF_PackageSessionNodes_ScoreMax] DEFAULT ((-1)) FOR [ScoreMax] GO ALTER TABLE [dbo].[PackageSessionNodes] ADD CONSTRAINT [DF_PackageSessionNodes_DateCreated] DEFAULT (getdate()) FOR [DateCreated] GO ALTER TABLE [dbo].[PackageSessionNodes] ADD CONSTRAINT [DF_PackageSessionNodes_ReducedScore] DEFAULT ((-1)) FOR [ReducedScore] GO ALTER TABLE [dbo].[PackageSessionNodes] ADD CONSTRAINT [DF_PackageSessionNodes_ReducedScoreMax] DEFAULT ((-1)) FOR [ReducedScoreMax] GO

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  • Using SQL Server's Output Clause

    When you are inserting, updating, or deleting records from a table, SQL Server keeps track of the records that are changed in two different pseudo tables: INSERTED, and DELETED. These tables are normally used in DML triggers. If you use the OUTPUT clause on an INSERT, UPDATE, DELETE or MERGE statement you can expose the records that go to these pseudo tables to your application and/or T-SQL code.

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  • Having trouble comparing a range of dates entered in a form with records in a mySQL database

    - by Andrew Fox
    I have a table called schedule and a column called Date where the column type is date. In that column I have a range of dates, which is currently from 2012-11-01 to 2012-11-30. I have a small form where the user can enter a range of dates (input names from and to) and I want to be able to compare the range of dates with the dates currently in the database. This is what I have: //////////////////////////////////////////////////////// //////First set the date range that we want to use////// //////////////////////////////////////////////////////// if(isset($_POST['from']) && ($_POST['from'] != NULL)) { $startDate = $_POST['from']; } else { //Default date is Today $startDate = date("Y-m-d"); } if(isset($_POST['to']) && ($_POST['to'] != NULL)) { $endDate = $_POST['to']; } else { //Default day is one month from today $endDate = date("Y-m-d", strtotime("+1 month")); } ////////////////////////////////////////////////////////////////////////////////////// //////Next calculate the total amount of days selected above to use as a limiter////// ////////////////////////////////////////////////////////////////////////////////////// $dayStart = strtotime($startDate); $dayEnd = strtotime($endDate); $total_days = abs($dayEnd - $dayStart) / 86400 +1; echo "Start Date: " . $startDate . "<br>End Date: " . $endDate . "<br>"; echo "Day Start: " . $dayStart . "<br>Day End: " . $dayEnd . "<br>"; echo "Total Days: " . $total_days . "<br>"; //////////////////////////////////////////////////////////////////////////////////// //////Then we're going to see if the dates selected are in the schedule table////// //////////////////////////////////////////////////////////////////////////////////// //Select all of the dates currently in the schedule table between the range selected. $sql = ("SELECT Date FROM schedule WHERE Date BETWEEN '$startDate' AND '$endDate' LIMIT $total_days"); //Run a check on the query to make sure it worked. If it failed then print the error. if(!$result_date_query = $mysqli->query($sql)) { die('There was an error getting the dates from the schedule table [' . $mysqli->error . ']'); } //Set the dates to an array for future use. // $current_dates = $result_date_query->fetch_assoc(); //Loop through the results while a result is being returned. while($row = $result_date_query->fetch_assoc()) { echo "Row: " . $row['Date'] . "<br>"; echo "Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Set this loop to add 1 day to the Start Date until it reaches the End Date for($i = $dayStart; $i <= $dayEnd; $i = strtotime('+1 day', $i)) { $date = date('Y-m-d',$i); echo "Loop Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Run a check to see if any of the dates selected are in the schedule table. if($row['Date'] != $date) { echo "Current Date: " . $row['Date'] . "<br>"; echo "Date: " . $date . "<br>"; echo "It appears as though you've selected some dates that are not in the schedule database.<br>Please correct the issue and try again."; return; } } } //Free the result so something else can use it. $result_date_query->free(); As you can see I've added in some echo statements so I can see what is being produced. From what I can see it looks like my $row['Date'] is not incrementing and staying at the same date. I originally had it set to a variable (currently commented out) but I thought that could be causing problems. I have created the table with dates ranging from 2012-11-01 to 2012-11-15 for testing and entered all of this php code onto phpfiddle.org but I can't get the username provided to connect. Here is the link: PHP Fiddle I'll be reading through the documentation to try and figure out the user connection problem in the meantime, I would really appreciate any direction or advice you can give me.

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  • Why would Linux VM in vSphere ESXi 5.5 show dramatically increased disk i/o latency?

    - by mhucka
    I'm stumped and I hope someone else will recognize the symptoms of this problem. Hardware: new Dell T110 II, dual-core Pentium G860 2.9 GHz, onboard SATA controller, one new 500 GB 7200 RPM cabled hard drive inside the box, other drives inside but not mounted yet. No RAID. Software: fresh CentOS 6.5 virtual machine under VMware ESXi 5.5.0 (build 174 + vSphere Client). 2.5 GB RAM allocated. The disk is how CentOS offered to set it up, namely as a volume inside an LVM Volume Group, except that I skipped having a separate /home and simply have / and /boot. CentOS is patched up, ESXi patched up, latest VMware tools installed in the VM. No users on the system, no services running, no files on the disk but the OS installation. I'm interacting with the VM via the VM virtual console in vSphere Client. Before going further, I wanted to check that I configured things more or less reasonably. I ran the following command as root in a shell on the VM: for i in 1 2 3 4 5 6 7 8 9 10; do dd if=/dev/zero of=/test.img bs=8k count=256k conv=fdatasync done I.e., just repeat the dd command 10 times, which results in printing the transfer rate each time. The results are disturbing. It starts off well: 262144+0 records in 262144+0 records out 2147483648 bytes (2.1 GB) copied, 20.451 s, 105 MB/s 262144+0 records in 262144+0 records out 2147483648 bytes (2.1 GB) copied, 20.4202 s, 105 MB/s ... but after 7-8 of these, it then prints 262144+0 records in 262144+0 records out 2147483648 bytes (2.1 GG) copied, 82.9779 s, 25.9 MB/s 262144+0 records in 262144+0 records out 2147483648 bytes (2.1 GB) copied, 84.0396 s, 25.6 MB/s 262144+0 records in 262144+0 records out 2147483648 bytes (2.1 GB) copied, 103.42 s, 20.8 MB/s If I wait a significant amount of time, say 30-45 minutes, and run it again, it again goes back to 105 MB/s, and after several rounds (sometimes a few, sometimes 10+), it drops to ~20-25 MB/s again. Plotting the disk latency in vSphere's interface, it shows periods of high disk latency hitting 1.2-1.5 seconds during the times that dd reports the low throughput. (And yes, things get pretty unresponsive while that's happening.) What could be causing this? I'm comfortable that it is not due to the disk failing, because I also had configured two other disks as an additional volume in the same system. At first I thought I did something wrong with that volume, but after commenting the volume out from /etc/fstab and rebooting, and trying the tests on / as shown above, it became clear that the problem is elsewhere. It is probably an ESXi configuration problem, but I'm not very experienced with ESXi. It's probably something stupid, but after trying to figure this out for many hours over multiple days, I can't find the problem, so I hope someone can point me in the right direction. (P.S.: yes, I know this hardware combo won't win any speed awards as a server, and I have reasons for using this low-end hardware and running a single VM, but I think that's besides the point for this question [unless it's actually a hardware problem].) ADDENDUM #1: Reading other answers such as this one made me try adding oflag=direct to dd. However, it makes no difference in the pattern of results: initially the numbers are higher for many rounds, then they drop to 20-25 MB/s. (The initial absolute numbers are in the 50 MB/s range.) ADDENDUM #2: Adding sync ; echo 3 > /proc/sys/vm/drop_caches into the loop does not make a difference at all. ADDENDUM #3: To take out further variables, I now run dd such that the file it creates is larger than the amount of RAM on the system. The new command is dd if=/dev/zero of=/test.img bs=16k count=256k conv=fdatasync oflag=direct. Initial throughput numbers with this version of the command are ~50 MB/s. They drop to 20-25 MB/s when things go south. ADDENDUM #4: Here is the output of iostat -d -m -x 1 running in another terminal window while performance is "good" and then again when it's "bad". (While this is going on, I'm running dd if=/dev/zero of=/test.img bs=16k count=256k conv=fdatasync oflag=direct.) First, when things are "good", it shows this: When things go "bad", iostat -d -m -x 1 shows this:

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  • In django, how can I include some default records in my models.py?

    - by kdt
    If I have a models.py like class WidgetType(models.Model): name = models.CharField(max_length=200) class Widget(models.Model): typeid = models.ForeignKey(WidgetType) data = models.CharField(max_length=200) How can I build in a set of built in constant values for WidgetType when I know I'm only going to have a certain few types of widget? Clearly I could fire up my admin interface and add them by hand, but I'd like to simplify configuration by having it built into the python.

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  • How do I put data from multiple records into different columns?

    - by Bryan
    My two tables are titled analyzed and analyzedCopy3. I'm trying to put information from analyzedCopy3 into multiple columns in analyzed. Sample data from analyzedCopy3: readings_miu_id OriginalCol ColRSSIz 110001366 Frederick Road -108 110001366 Steel Street 110001366 Fifth Ave. 110001508 Steel Street -104 What I want to do is put the top 3 OriginalCol, ColRSSIz combinations into columns that I have in the table analyzed. In analyzed there is only one record for each unique readings_miu_id. Any ideas? Thanks in advance. Additional Info: By "top 3 OriginalCol, ColRSSIz combinations" I mean the first 3 combinations with the highest value in the ColRSSIz column. For any readings_miu_id there could be anywhere from 1 row of information to 6 rows of information. So at most I'm only wanting the top 3. If there is less than 3 rows for the readings_miu_id then the other columns need to be blank. Query that generates the table "analyzed": strSql4 = " SELECT readings_miu_id, Count(readings_miu_id) as NumberOfReads, First(PercentSuccessz) as PercentSuccess, First(Readingz)as Reading, First(MIUwindowz) as MIUwindow, First(SNz) as SN, First(Noisez) as Noise, First(RSSIz) as RSSI, First(ColRSSIz) as ColRSSI, First(MIURSSIz) as MIURSSI, First(Col1z) as Col1, First(Col1RSSIz) as Col1RSSI, First(Col2z) as Col2, First(Col2RSSIz) as Col2RSSI, First(Col3z) as Col3, First(Col3RSSIz) as Col3RSSI, First(Firmwarez) as Firmware, First(CFGDatez) as CFGDate, First(FreqCorrz) as FreqCorr, First(Activez) as Active, First(MeterTypez) as MeterType, First(OriginColz) as OriginCol, First(ColIDz) as ColID, First(Ownagez) as Ownage, First(SiteIDz) as SiteID, First(PremIDz) as PremID, First(prem_group1z) as prem_group1, First(prem_group2z) as prem_group2, First(ReadIDz) as ReadID, First(prem_addr1z) as prem_addr1 " & _ "INTO analyzed " & _ "FROM analyzedCopy2 " & _ "GROUP BY readings_miu_id, PremIDz; " DoCmd.SetWarnings False DoCmd.RunSQL strSql4 DoCmd.SetWarnings True

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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    I have a form with multiple fields in it along with a image input field, just below the form i have a list to be displayed on every submit of this form... this has to be done without the use of DB.. I think this can be achieved by using session but its not working with me, as evrytime page gets refreshed and session gets recreated/reset.. Please help me in resolving this issue

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