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  • How much sense does it make for a veteran .Net developer to move to ROR professionally?

    - by SharePoint Newbie
    Hi, I consider myself a moderately skilled (definitely not stupid) .Net developer. Over the past 5 years I've been working with ASP.Net, ASP.Net MVC, SharePoint, WPF, Silverlight, RDBMS (SQL Server and Oracle). I maintain/contribute a couple of .Net OSS. I've also picked up F# and Haskell over the previous year. I am currently employed at one of the better (best) software firms out there and would surely love to continue working here. However over the past 6 months opportunities in .Net have mostly dried up and all new work is headed towards ROR (and whatever is left towards Java). I have never been apprehensive about learning a new stack/language for fun and have previously picked up Haskell and Python in my free time. I am however apprehensive as to what impact moving to a new entirely different stack would have on my career. What would you do: Change jobs if you don't find anything on .Net soon. Try out the ROR stack for some time. If you find that its not your cup of tea, move back. (How would this impact my career and job opportunities in the longer run?) Also it would be very helpful if there are any ASP.Net MVC folks who have switched over to ROR professionally who can share their experiences. Edit: I have not done any development on a *nix box before. I've however used Ubuntu for fun and games. Sorry if this sounds subjective.

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  • PathTooLongException after migrating from ASP.NET MVC 1 to ASP.NET MVC 2

    - by admax
    I had updated my app from MVC 1 to MVC 2. After that some pages throws PathTooLongException: [PathTooLongException: The specified path, file name, or both are too long. The fully qualified file name must be less than 260 characters, and the directory name must be less than 248 characters.] System.IO.Path.SafeSetStackPointerValue(Char* buffer, Int32 index, Char value) +7493057 System.IO.Path.NormalizePathFast(String path, Boolean fullCheck) +387 System.IO.Path.NormalizePath(String path, Boolean fullCheck) +36 System.IO.Path.GetFullPathInternal(String path) +21 System.Security.Util.StringExpressionSet.CanonicalizePath(String path, Boolean needFullPath) +73 System.Security.Util.StringExpressionSet.CreateListFromExpressions(String[] str, Boolean needFullPath) +278 System.Security.Permissions.FileIOPermission.AddPathList(FileIOPermissionAccess access, AccessControlActions control, String[] pathListOrig, Boolean checkForDuplicates, Boolean needFullPath, Boolean copyPathList) +87 System.Security.Permissions.FileIOPermission..ctor(FileIOPermissionAccess access, String path) +65 System.Web.InternalSecurityPermissions.PathDiscovery(String path) +29 System.Web.HttpRequest.MapPath(VirtualPath virtualPath, VirtualPath baseVirtualDir, Boolean allowCrossAppMapping) +146 System.Web.HttpRequest.MapPath(VirtualPath virtualPath) +37 System.Web.HttpServerUtility.Execute(IHttpHandler handler, TextWriter writer, Boolean preserveForm, Boolean setPreviousPage) +43 System.Web.HttpServerUtility.Execute(IHttpHandler handler, TextWriter writer, Boolean preserveForm) +28 System.Web.HttpServerUtilityWrapper.Execute(IHttpHandler handler, TextWriter writer, Boolean preserveForm) +22 System.Web.Mvc.ViewPage.RenderView(ViewContext viewContext) +284 System.Web.Mvc.WebFormView.RenderViewPage(ViewContext context, ViewPage page) +82 System.Web.Mvc.WebFormView.Render(ViewContext viewContext, TextWriter writer) +85 System.Web.Mvc.ViewResultBase.ExecuteResult(ControllerContext context) +267 System.Web.Mvc.ControllerActionInvoker.InvokeActionResult(ControllerContext controllerContext, ActionResult actionResult) +10 System.Web.Mvc.ControllerActionInvoker.InvokeAction(ControllerContext controllerContext, String actionName) +320 System.Web.Mvc.Controller.ExecuteCore() +104 System.Web.Mvc.ControllerBase.Execute(RequestContext requestContext) +36 System.Web.Mvc.ControllerBase.System.Web.Mvc.IController.Execute(RequestContext requestContext) +7 System.Web.Mvc.<c_DisplayClass8.b_4() +34 System.Web.Mvc.Async.<c_DisplayClass1.b_0() +21 System.Web.Mvc.Async.<c__DisplayClass81.<BeginSynchronous>b__7(IAsyncResult _) +12 System.Web.Mvc.Async.WrappedAsyncResult1.End() +53 System.Web.Mvc.MvcHandler.EndProcessRequest(IAsyncResult asyncResult) +30 System.Web.Mvc.MvcHandler.System.Web.IHttpAsyncHandler.EndProcessRequest(IAsyncResult result) +7 System.Web.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() +8678910 System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) +155 I know the issue with 260-character-url-lenght in ASP.NET, but my app works fine before update to ASP.NET MVC 2.0!

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  • pylucene: install error

    - by Pradeep
    I am trying to install Pylucene (pylucene-3.3-3-src.tar.gz) on my ubuntu linux 11.10. I have python 2.7.2. I was able to compile JCC (I think) because I didnt see any error when I installed it. When I tried to install Pylucene I get the following error. Can someone help? Thanks. ICU not installed /usr/bin/python -m jcc --shared --jar lucene-java-3.3/lucene/build/lucene-core-3.3.jar --jar lucene-java-3.3/lucene/build/contrib/analyzers/common/lucene-analyzers-3.3.jar --jar lucene-java-3.3/lucene/build/contrib/memory/lucene-memory-3.3.jar --jar lucene-java-3.3/lucene/build/contrib/highlighter/lucene-highlighter-3.3.jar --jar build/jar/extensions.jar --jar lucene-java-3.3/lucene/build/contrib/queries/lucene-queries-3.3.jar --jar lucene-java-3.3/lucene/build/contrib/grouping/lucene-grouping-3.3.jar --package java.lang java.lang.System java.lang.Runtime --package java.util java.util.Arrays java.util.HashMap java.util.HashSet java.text.SimpleDateFormat java.text.DecimalFormat java.text.Collator --package java.util.regex --package java.io java.io.StringReader java.io.InputStreamReader java.io.FileInputStream --exclude org.apache.lucene.queryParser.Token --exclude org.apache.lucene.queryParser.TokenMgrError --exclude org.apache.lucene.queryParser.QueryParserTokenManager --exclude org.apache.lucene.queryParser.ParseException --exclude org.apache.lucene.search.regex.JakartaRegexpCapabilities --exclude org.apache.regexp.RegexpTunnel --exclude org.apache.lucene.analysis.cn.smart.AnalyzerProfile --python lucene --mapping org.apache.lucene.document.Document 'get:(Ljava/lang/String;)Ljava/lang/String;' --mapping java.util.Properties 'getProperty:(Ljava/lang/String;)Ljava/lang/String;' --sequence java.util.AbstractList 'size:()I' 'get:(I)Ljava/lang/Object;' --rename org.apache.lucene.search.highlight.SpanScorer=HighlighterSpanScorer --version 3.3 --module python/collections.py --module python/ICUNormalizer2Filter.py --module python/ICUFoldingFilter.py --module python/ICUTransformFilter.py --files 3 --build /usr/bin/python: No module named jcc make: *** [compile] Error 1 Here is my Makefile configuration which I uncommented PREFIX_PYTHON=/usr ANT=ant PYTHON=$(PREFIX_PYTHON)/bin/python JCC=$(PYTHON) -m jcc --shared NUM_FILES=3

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  • XElement.Load("~/App_Data/file.xml") Could not find a part of the path

    - by mahdiahmadirad
    hi everybody, I am new in LINQtoXML. I want to use XElement.Load("") Method. but the compiler can't find my file. can you help me to write correct path for my XML file? Note that: I defined a Class in App_Code and I want to use the XML file data in one of methods and my XML file Located in App_Data. settings = XElement.Load("App_Data/AppSettings.xml"); i cant Use Request.ApplicationPath and Page.MapPath() or Server.MapPath() to get the physical path for my file because i am not in a class Inherited form Page class. Brief error Message: *Could not find a part of the path 'C:\Program Files\Microsoft Visual Studio 9.0\Common7\IDE\App_Data\AppSettings.xml'*. you see the path compiled is fully different from my project path(G:\MyProjects\ASP.net Projects\VistaComputer\Website\App_Data\AppSettings.xml) Full error Message is here: System.IO.DirectoryNotFoundException was unhandled by user code Message="Could not find a part of the path 'C:\\Program Files\\Microsoft Visual Studio 9.0\\Common7\\IDE\\App_Data\\AppSettings.xml'." Source="mscorlib" StackTrace: at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize) at System.Xml.XmlDownloadManager.GetStream(Uri uri, ICredentials credentials) at System.Xml.XmlUrlResolver.GetEntity(Uri absoluteUri, String role, Type ofObjectToReturn) at System.Xml.XmlReader.Create(String inputUri, XmlReaderSettings settings, XmlParserContext inputContext) at System.Xml.XmlReader.Create(String inputUri, XmlReaderSettings settings) at System.Xml.Linq.XElement.Load(String uri, LoadOptions options) at System.Xml.Linq.XElement.Load(String uri) at ProductActions.Add(Int32 catId, String title, String price, String website, String shortDesc, String fullDesc, Boolean active, Boolean editorPick, String fileName, Stream image) in g:\MyProjects\ASP.net Projects\VistaComputer\Website\App_Code\ProductActions.cs:line 67 at CMS_Products_Operations.Button1_Click(Object sender, EventArgs e) in g:\MyProjects\ASP.net Projects\VistaComputer\Website\CMS\Products\Operations.aspx.cs:line 72 at System.Web.UI.WebControls.Button.OnClick(EventArgs e) at System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) at System.Web.UI.WebControls.Button.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) InnerException:

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  • Java: static-non-static-this problem

    - by HH
    $ javac TestFilter.java TestFilter.java:19: non-static variable this cannot be referenced from a static context for(File f : file.listFiles(this.filterFiles)){ ^ 1 error $ sed -i 's@this@TestFilter@g' TestFilter.java $ javac TestFilter.java $ java TestFilter file1 file2 file3 TestFilter.java import java.io.*; import java.util.*; public class TestFilter { private static final FileFilter filterFiles; // STATIC! static{ filterFiles = new FileFilter() { // Not Static below. When static, an error: // "accept(java.io.File) in cannot implement // accept(java.io.File) in java.io.FileFilter; // overriding method is static" // // I tried to solve by the change the problem at the bottom. public boolean accept(File file) { return file.isFile(); } }; } // STATIC! public static void main(String[] args){ HashSet<File> files = new HashSet<File>(); File file = new File("."); // IT DID NOT WORK WITH "This" but with "TestFilter". // Why do I get the error with "This" but not with "TestFilter"? for(File f : file.listFiles(TestFilter.filterFiles)){ System.out.println(f.getName()); files.add(f); } } }

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  • security exception in file handling in j2me

    - by learn
    i am trying to generate a logfile. static String fname="file:///c:/logfile.txt;append=true"; fc = (FileConnection) Connector.open(fname, Connector.WRITE); if (fc.exists()) { // file exists, open at EOF. offset = fc.fileSize(); os = fc.openOutputStream(offset); } else { // file does not exist, create and open. fc.create(); os = fc.openOutputStream(); } getting tthe following exception java.lang.SecurityException: Access denied at com.symbian.midp.io.protocol.file.FileConnectionImpl.open(FileConnectionImpl.java:71) at com.symbian.midp.io.protocol.file.Protocol.openConnection(Protocol.java:40) at com.symbian.gcf.ProtocolBase.openConnection(), bci=159 at com.symbian.gcf.GCFConnector.open(), bci=237 at com.symbian.j2me.midp.legacy.LegacyConnectionFactory.open(LegacyConnectionFactory.java:35) at com.symbian.j2me.midp.runtimeV2.ConnectionService.open(), bci=8 at javax.microedition.io.Connector.open(), bci=6 at javax.microedition.io.Connector.open(Connector.java:48) at Symbian.LogFile.FileOpen(LogFile.java:27) at Symbian.Symbian.startApp(Symbian.java:216) at javax.microedition.midlet.MIDletInvoker.invokeStartApp(MIDletInvoker.java:30) at com.symbian.j2me.midp.runtimeV2.Application.startAction(Application.java:458) at com.symbian.j2me.midp.runtimeV2.Application.startRequest(Application.java:413) at com.symbian.j2me.midp.runtimeV2.Application.event(Application.java:264) at com.symbian.j2me.midp.runtimeV2.ApplicationEvent.dispatch(ApplicationEvent.java:90) at com.symbian.j2me.midp.runtimeV2.ApplicationThread.run(ApplicationThread.java:30) Access denied

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  • Create Zip File In Windows and Extract Zip File In Linux

    - by Yan Cheng CHEOK
    I had created a zip file (together with directory) under Windows as follow : package sandbox; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.util.zip.ZipEntry; import java.util.zip.ZipOutputStream; /** * * @author yan-cheng.cheok */ public class Main { /** * @param args the command line arguments */ public static void main(String[] args) { // These are the files to include in the ZIP file String[] filenames = new String[]{"MyDirectory" + File.separator + "MyFile.txt"}; // Create a buffer for reading the files byte[] buf = new byte[1024]; try { // Create the ZIP file String outFilename = "outfile.zip"; ZipOutputStream out = new ZipOutputStream(new FileOutputStream(outFilename)); // Compress the files for (int i=0; i<filenames.length; i++) { FileInputStream in = new FileInputStream(filenames[i]); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(filenames[i])); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file out.close(); } catch (IOException e) { e.printStackTrace(); } } } The newly created zip file can be extracted without problem under Windows, by using http://www.exampledepot.com/egs/java.util.zip/GetZip.html However, I realize if I extract the newly created zip file under Linux, using http://www.exampledepot.com/egs/java.util.zip/GetZip.html, I will get a file named "MyDirectory\MyFile.txt" instead of MyFile.txt being placed under folder MyDirectory. I try to solve the problem by changing the zip file creation code to String[] filenames = new String[]{"MyDirectory" + "/" + "MyFile.txt"}; But, is this an eligible solution, by hard-coded the seperator? Will it work under Mac OS? (I do not have a Mac to try out)

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  • LWUIT Deadlock (lwuit dialog VS System dialog)

    - by Ramps
    Hi, I have a deadlock problem when I try to make some I/O operations that needs user permission. When user click the button I start a new thread which is responsible for performing IO operations, and I display lwuit "please wait" dialog. Dialog is dismissed by IO thread from callback method. Problem is that, when system dialog appears (asking for user permission ) on top of lwuit dialog - deadlock occurs. I assume that this is because dialog.show() method blocks main thread (EDT), so it's impossible to dismiss system dialog, when lwuit dialog is behind it. Anyone managed to solve this problem? Here is the simplified code, hope it is clear enough: protected void actionPerformed(ActionEvent evt, int id) { switch (id) { case ID_FRIEND: MyRunnableWithIoOperation r = new MyRunnableWithIoOperation(this); new Thread(r).start(); //run the thread performing IO operations Command cmd = mWaitDialog.showDialog(); // show the "please wait" dialog ...//handle cancel }//end switch } /* method called from MyRunnableWithIoOperation, when operation finished*/ public void myCallbackMethod(){ mWaitDialog.dispose(); // } I tried to start my IO thread by calling Display.getInstance().invokeAndBlock( r ), but with no luck. In such case, my "wait dialog" doesn't show up.

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  • Replacing a Namespace with XSLT

    - by er4z0r
    Hi I want to work around a 'bug' in certain RSS-feeds, which use an incorrect namespace for the mediaRSS module. I tried to do it by manipulating the DOM programmatically, but using XSLT seems more flexible to me. Example: <media:thumbnail xmlns:media="http://search.yahoo.com/mrss" url="http://www.suedkurier.de/storage/pic/dpa/infoline/brennpunkte/4311018_0_merkelxI_24280028_original.large-4-3-800-199-0-3131-2202.jpg" /> <media:thumbnail url="http://www.suedkurier.de/storage/pic/dpa/infoline/brennpunkte/4311018_0_merkelxI_24280028_original.large-4-3-800-199-0-3131-2202.jpg" /> Where the namespace must be http://search.yahoo.com/mrss/ (mind the slash). This is my stylesheet: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="//*[namespace-uri()='http://search.yahoo.com/mrss']"> <xsl:element name="{local-name()}" namespace="http://search.yahoo.com/mrss/" > <xsl:apply-templates select="@*|*|text()" /> </xsl:element> </xsl:template> </xsl:stylesheet> Unfortunately the result of the transformation is an invalid XML and my RSS-Parser (ROME Library) does not parse the feed anymore: java.lang.IllegalStateException: Root element not set at org.jdom.Document.getRootElement(Document.java:218) at com.sun.syndication.io.impl.RSS090Parser.isMyType(RSS090Parser.java:58) at com.sun.syndication.io.impl.FeedParsers.getParserFor(FeedParsers.java:72) at com.sun.syndication.io.WireFeedInput.build(WireFeedInput.java:273) at com.sun.syndication.io.WireFeedInput.build(WireFeedInput.java:251) ... 8 more What is wrong with my stylesheet?

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  • FileNotFoundException when reading .xml file to parse

    - by thechiman
    I'm writing a program in Java where I read in data from an XML file and parse it. The file is imported into a folder named "Resources" in the src directory of my project. I'm using Eclipse. When I run the program, I get the following error: java.io.FileNotFoundException: /Users/thechiman/Dropbox/introcs/PSU SOC Crawler/resources/majors_xml_db.xml (No such file or directory) at java.io.FileInputStream.open(Native Method) at java.io.FileInputStream.<init>(FileInputStream.java:106) at java.io.FileInputStream.<init>(FileInputStream.java:66) ... The relevant code is here: private void parseXML() { //Get a factory DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { //Use factory to get a new DocumentBuilder DocumentBuilder db = dbf.newDocumentBuilder(); //Parse the XML file, get DOM representation dom = db.parse("resources/majors_xml_db.xml"); } catch(ParserConfigurationException pce) { pce.printStackTrace(); } catch(SAXException se) { se.printStackTrace(); } catch(IOException ioe) { ioe.printStackTrace(); } } I do not understand why I'm getting the FileNotFoundException when the file is there. Thanks for the help.

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  • bash - how to filter java exception info

    - by Michael Mao
    Hi all: We've got a multi-agent Java environment where different agent would most likely produce all sorts of exceptions thrown to stderr. Here is a sample taken from the huge exception log **java.security.AccessControlException: access denied (java.io.FilePermission ..\tournament\Driver\HotelRoomAnalyser.class read)** at java.security.AccessControlContext.checkPermission(Unknown Source) at java.security.AccessController.checkPermission(Unknown Source) at java.lang.SecurityManager.checkPermission(Unknown Source) at java.lang.SecurityManager.checkRead(Unknown Source) at java.io.File.length(Unknown Source) at emarket.client.EmarketSandbox$SandboxFileLoader.loadClassData(EmarketSandbox.java:218) at emarket.client.EmarketSandbox$SandboxFileLoader.loadClass(EmarketSandbox.java:199) at java.lang.ClassLoader.loadClass(Unknown Source) **java.security.AccessControlException: access denied (java.io.FilePermission ..\tournament\Driver\HotelRoomAnalyser.class read)** at java.security.AccessControlContext.checkPermission(Unknown Source) at java.security.AccessController.checkPermission(Unknown Source) at java.lang.SecurityManager.checkPermission(Unknown Source) at java.lang.SecurityManager.checkRead(Unknown Source) at java.io.File.length(Unknown Source) at emarket.client.EmarketSandbox$SandboxFileLoader.loadClassData(EmarketSandbox.java:218) at emarket.client.EmarketSandbox$SandboxFileLoader.loadClass(EmarketSandbox.java:199) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClassInternal(Unknown Source) at MySmarterAgent.hotelRoomBookings(MySmarterAgent.java:108) fortunately all top-tier exceptions are denoted by no leading spaces, as wrapped by ** above. My concern is to get all of the top-tier exception name (delimited by colon :), together with the first line below which contains something like at emarket.client.EmarketSandbox$SandboxFileLoader.loadClassData(EmarketSandbox.java:218) Basically, something with padded style, starts with "at" and ends with ".java:108" So this info can be forwarded to the owner of that error-prone agent and let him/her fix it. My code in ~/.bashrc is incompleted now : alias startmatch='java -jar "emarket.jar" ../tournament 100'; function geterrors() { startmatch 2>"$1"; a=0; while read line do if true; then a=$(($a+1)); echo $a; fi; done } What it does now is to redirect all stderr to a text file specified by the first argument passed in, and after that, parse that text file line by line, if certain conditions returns true, echo only that line. And I am stuck with what to do inside the loop. Any suggestion is much appreciates, any hint is welcomed.

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  • multiple keys and values with google-collections

    - by flash3000
    Hello, I would like use google-collection in order to save the following file in a Hash with multiple keys and values Key1_1, Key2_1, Key3_1, data1_1, 0, 0 Key1_2, Key2_2, Key3_2, data1_2, 0, 0 Key1_3, Key2_3, Key3_3, data1_3, 0, 0 Key1_4, Key2_4, Key3_4, data1_4, 0, 0 The first three columns are the different keys and the last two integer are the two different values. I have already prepare a code which spilt the lines in chunks. import java.io.BufferedReader; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; public class HashMapKey { public static void main(String[] args) throws FileNotFoundException, IOException { String inputFile = "inputData.txt"; BufferedReader br = new BufferedReader(new FileReader(inputFile)); String strLine; while ((strLine = br.readLine()) != null) { String[] line = strLine.replaceAll(" ", "").trim().split(","); for (int i = 0; i < line.length; i++) { System.out.print("[" + line[i] + "]"); } System.out.println(); } } } Unfortunately, I do not know how to save these information in google-collection? Thank you in advance. Best regards,

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  • C# .net Deserialization I get an exception.

    - by starz26
    namespace N1 { public class InputEntry { //FieldName is a class tht is generated from an XSD which has complex type Name and value private FieldName[] name; public FieldName[] Name { get { return this.Name; } set { this.Name = value; } } } public class B { public void Method1() { InputEntry inputEntry = new InputEntry(); inputEntry.Name = "abc"; } private void Method2(InputEntry inputEntry) { System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(typeof(InputEntry)); System.IO.StringWriter inputStr = new System.IO.StringWriter(CultureInfo.InvariantCulture); serializer.Serialize(inputStr, inputEntry); string ipEntry = inputStr.ToString(); Method3(ipEntry); } private void Method3(string ipEntry) { System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(typeof(InputEntry)); System.IO.StringReader inputStr = new System.IO.StringReader(ipEntry); InputEntry inputEntry = (InputEntry)serializer.Deserialize(inputStr); } } } I get an exception when deserialising the follwing data(when a client configues data as <FieldName>PRINTLINE00</FieldName> <FieldValue>DENIAL STATE</FieldValue> ) Exception is: Message: There is an error in XML document (6, 22). String: <?xml version="1.0" encoding="utf-16"?> <InputEntry xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Fields> <Field> <FieldName>PRINTLINE00</FieldName> <FieldValue>&#x1B;DENIAL STATE 217</FieldValue> </Field> </InputEntry>

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  • ASP.NET - I am generating an .XLS file with a DLL, how do I grant permissions for writing to file? (

    - by hamlin11
    I'm generating an .XLS file with a DLL (Excel Library http://code.google.com/p/excellibrary/) I've added this DLL as a reference to my project. The code to save the .XLS to disk is running, but it's encountering a permissions issue. I've attempted to set full access for IUSRS, Network Service, and Everyone just to see if I could get it working, and none of these seems to make a difference. Here's where I'm trying to write the file: c:/temp/test1.xls Here's the error: [SecurityException: Request for the permission of type 'System.Security.Permissions.FileIOPermission, mscorlib, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' failed.] System.Security.CodeAccessSecurityEngine.Check(Object demand, StackCrawlMark& stackMark, Boolean isPermSet) +0 System.Security.CodeAccessPermission.Demand() +54 System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) +2103 System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize, FileOptions options, String msgPath, Boolean bFromProxy) +138 System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share) +89 System.IO.File.Open(String path, FileMode mode, FileAccess access, FileShare share) +58 ExcelLibrary.Office.CompoundDocumentFormat.CompoundDocument.Create(String file) +88 ExcelLibrary.Office.Excel.Workbook.Save(String file) +73 CHC_Reports.LitAnalysis.CreateSpreadSheet_Click(Object sender, EventArgs e) in C:\Users\brian\Desktop\Enterprise Manager\CHC_Reports\LitAnalysis.aspx.vb:19 System.Web.UI.WebControls.Button.OnClick(EventArgs e) +115 System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) +140 System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) +29 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +11041511 System.Web.UI.Page.ProcessRequest(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +11041050 System.Web.UI.Page.ProcessRequest() +91 System.Web.UI.Page.ProcessRequest(HttpContext context) +240 ASP.litanalysis_aspx.ProcessRequest(HttpContext context) +52 System.Web.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() +599 System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) +171 Any idea what I need to do to diagnose the permissions issue and allow the file creation? Thanks.

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  • Saving and retrieving image in SQL database from C# problem

    - by Mobin
    I used this code for inserting records in a person table in my DB System.IO.MemoryStream ms = new System.IO.MemoryStream(); Image img = Image_Box.Image; img.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp); this.personTableAdapter1.Insert(NIC_Box.Text.Trim(), Application_Box.Text.Trim(), Name_Box.Text.Trim(), Father_Name_Box.Text.Trim(), DOB_TimePicker.Value.Date, Address_Box.Text.Trim(), City_Box.Text.Trim(), Country_Box.Text.Trim(), ms.GetBuffer()); but when i retrieve this with this code byte[] image = (byte[])Person_On_Application.Rows[0][8]; MemoryStream Stream = new MemoryStream(); Stream.Write(image, 0, image.Length); Bitmap Display_Picture = new Bitmap(Stream); Image_Box.Image = Display_Picture; it works perfectly fine but if i update this with my own generated Query like System.IO.MemoryStream ms = new System.IO.MemoryStream(); Image img = Image_Box.Image; img.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp); Query = "UPDATE Person SET Person_Image ='"+ms.GetBuffer()+"' WHERE (Person_NIC = '"+NIC_Box.Text.Trim()+"')"; the next time i use the same code for retrieving the image and displaying it as used above . Program throws an exception

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  • Too many open files in one of my java routine.

    - by Irfan Zulfiqar
    I have a multithreaded code that has to generated a set of objects and write them to a file. When I run it I sometime get "Too many open files" message in Exception. I have checked the code to make sure that all the file streams are being closed properly. Here is the stack trace. When I do ulimit -a, open files allowed is set to 1024. We think increasing this number is not a viable option / solution. [java] java.io.FileNotFoundException: /export/event_1_0.dtd (Too many open files) [java] at java.io.FileInputStream.open(Native Method) [java] at java.io.FileInputStream.<init>(FileInputStream.java:106) [java] at java.io.FileInputStream.<init>(FileInputStream.java:66) [java] at sun.net.www.protocol.file.FileURLConnection.connect(FileURLConnection.java:70) [java] at sun.net.www.protocol.file.FileURLConnection.getInputStream(FileURLConnection.java:161) [java] at java.net.URL.openStream(URL.java:1010) Now what we have identified so far by looking closely at the list of open files is that the VM is opening same class file multiple times. /export/BaseEvent.class 236 /export/EventType1BaseEvent.class 60 /export/EventType2BaseEvent.class 48 /export/EventType2.class 30 /export/EventType1.class 14 Where BaseEvent is partent of all the classes and EventType1 ant EventType2 inherits EventType1BaseEvent and EventType2BaseEvent respectively. Why would a class loader load the same class file 200+ times. It seems it is opening up the base class as many time it create any child instance. Is this normal? Can it be handler any other way apart from increasing the number of open files?

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  • HttpPostedFile.SaveAs() throws UnauthorizedAccessException even though the file is saved?

    - by jrummell
    I have an aspx page with multiple FileUpload controls and one Upload button. In the click handler I save the files like this: string path = "..."; for (int i = 0; i < Request.Files.Count - 1; i++) { HttpPostedFile file = Request.Files[i]; string fileName = Path.GetFileName(file.FileName); string saveAsPath = Path.Combine(path, fileName); file.SaveAs(saveAsPath); } When file.SaveAs() is called, it throws: System.Web.HttpUnhandledException: Exception of type 'System.Web.HttpUnhandledException' was thrown. --- System.UnauthorizedAccessException: Access to the path '...' is denied. at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize, FileOptions options, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode) at System.Web.HttpPostedFile.SaveAs(String filename) at Belden.Web.Intranet.Iso.Complaints.AttachmentUploader.btnUpload_Click(Object sender, EventArgs e) at System.Web.UI.WebControls.Button.OnClick(EventArgs e) at System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) --- End of inner exception stack trace --- at System.Web.UI.Page.HandleError(Exception e) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) at System.Web.UI.Page.ProcessRequest(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) at System.Web.UI.Page.ProcessRequest() at System.Web.UI.Page.ProcessRequest(HttpContext context) at ASP.departments_iso_complaints_uploadfiles_aspx.ProcessRequest(HttpContext context) at System.Web.HttpApplication.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() at System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) Now here's the fun part. The file is saved correctly! So why is it throwing this exception?

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  • Access denied for pdf to read using itextsharp at server level..

    - by apekshabs
    Am facing error after uploadind to server... as access denied .... can anyone help me.... Document myDocument = new Document(PageSize.A5, 26, 72, 180, 180); string strUniqueFn = "onlineinvoice.pdf"; string imgpath = "logo.gif"; string strUser = Thread.CurrentPrincipal.Identity.Name.Substring(Thread.CurrentPrincipal.Identity.Name.IndexOf("\\") + 1).ToUpper(); string strFolder = Server.MapPath("."); System.IO.DirectoryInfo di = new System.IO.DirectoryInfo(strFolder); System.IO.FileInfo[] fi = di.GetFiles(strUser + "*.*"); for (i = 0; i <= fi.Length - 1; i++) { System.IO.File.Delete(strFolder + "\\" + strUniqueFn); } string strPath = strFolder + "\\" + strUniqueFn; PdfWriter pdfw = PdfWriter.GetInstance(myDocument, new FileStream(strPath, FileMode.Create)); string iPath = strFolder + "\\" + imgpath; pdfw.CloseStream = false; myDocument.Open(); ...................... myDocument.Close(); Am facing error at PdfWriter pdfw = PdfWriter.GetInstance(myDocument, new FileStream(strPath, FileMode.Create)); can anyone help me... Thank you

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  • commons-exec: hanging when I call executor.execute(commandLine);

    - by Stefan Kendall
    I have no idea why this is hanging. I'm trying to capture output from a process run through commons-exec, and I continue to hang. I've provided an example program to demonstrate this behavior below. import java.io.DataInputStream; import java.io.IOException; import java.io.PipedInputStream; import java.io.PipedOutputStream; import org.apache.commons.exec.CommandLine; import org.apache.commons.exec.DefaultExecutor; import org.apache.commons.exec.ExecuteException; import org.apache.commons.exec.PumpStreamHandler; public class test { public static void main(String[] args) { String command = "java"; PipedOutputStream output = new PipedOutputStream(); PumpStreamHandler psh = new PumpStreamHandler(output); CommandLine cl = CommandLine.parse(command); DefaultExecutor exec = new DefaultExecutor(); DataInputStream is = null; try { is = new DataInputStream(new PipedInputStream(output)); exec.setStreamHandler(psh); exec.execute(cl); } catch (ExecuteException ex) { } catch (IOException ex) { } System.out.println("huh?"); } }

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  • How to Make my application handle Errors for a few different scenarios?

    - by NightsEVil
    so i have this code to extract a program to the temp directory then run it, the problem is it doesn't work perfectly on every computer (for some reason it hits a error or exception sometimes) string tempFolder = System.IO.Path.Combine(System.IO.Path.GetTempPath(), ""); System.Diagnostics.Process defrag1 = System.Diagnostics.Process.Start(@"Programs\Optimize\AusLogics_Defrag.exe", string.Format(" -o{0} -y", tempFolder)); defrag1.WaitForExit(); string executableDirectoryName = Path.GetDirectoryName(Application.ExecutablePath); System.Diagnostics.Process defrag2 = System.Diagnostics.Process.Start(tempFolder + "\\" + "AusLogics_Defrag" + "\\" + "DiskDefrag.exe", ""); defrag2.WaitForExit(); System.IO.Directory.Delete(tempFolder + "\\" + "AusLogics_Defrag", true); and what i wanna know is there a way that say if it starts to extract but hits a error (no matter what it is) it will automatically change and go to this code, but if it DOESN'T hit a error it continues as it was meant to? string tempFolder = Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData); System.Diagnostics.Process defrag1 = System.Diagnostics.Process.Start(@"Programs\Optimize\AusLogics_Defrag.exe", string.Format(" -o{0} -y", tempFolder)); defrag1.WaitForExit(); string executableDirectoryName = Path.GetDirectoryName(Application.ExecutablePath); System.Diagnostics.Process defrag2 = System.Diagnostics.Process.Start(tempFolder + "\\" + "AusLogics_Defrag" + "\\" + "DiskDefrag.exe", ""); defrag2.WaitForExit(); System.IO.Directory.Delete(tempFolder + "\\" + "AusLogics_Defrag", true); with the path going to the application data folder? and if THAT hits a error it would change that path to this, but if it DOESN'T hit a error it continues as it was meant to? string tempFolder = System.Environment.GetEnvironmentVariable("HomeDrive");

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  • Windows 7 Create Folder in "Program Files" failing in C# code even thought I have admin rights!

    - by Shiva
    Hi, I am unable to create a file under "program files" folder on my Windows 7 64-bit machine in VS 2008 WPF C# code. The error I get on the following code myFile = File.Create(logFile); is the following. (this is the innerException stack trace). at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize, FileOptions options) at System.IO.File.Create(String path) at MyFirm.MyPricingApp.UI.App.InitializeLogging() in C:\Projects\MyPricingApp\App.xaml.cs:line 150 at MyFirm.MyPricingApp.UI.App.Application_Startup(Object sender, StartupEventArgs e) in C:\Projects\MyPricingApp\App.xaml.cs:line 38 at System.Windows.Application.OnStartup(StartupEventArgs e) at System.Windows.Application.<.ctor>b__0(Object unused) at System.Windows.Threading.ExceptionWrapper.InternalRealCall(Delegate callback, Object args, Boolean isSingleParameter) at System.Windows.Threading.ExceptionWrapper.TryCatchWhen(Object source, Delegate callback, Object args, Boolean isSingleParameter, Delegate catchHandler) this seems like it has something to do with UAC in Windows 7, because why else would I get this since my user is already Admin on the machine ?! Also since the WinIOError has SECURITY_ATTRIBUTES, I am thinking this has something to do with a "new way" security is handled in Windows 7. I tried to browse to the "Program Files" folder, under which the log folder and file were to be created. I can create the folder by hand, but when i try to create the file, I get the similar "Access Denied" exception.

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  • Wildcards vs. generic methods

    - by FredOverflow
    Is there any practical difference between the following approaches to print all elements in a range? public static void printA(Iterable<?> range) { for (Object o : range) { System.out.println(o); } } public static <T> void printB(Iterable<T> range) { for (T x : range) { System.out.println(x); } } Apparently, printB involves an additional checked cast to Object (see line 16), which seems rather stupid to me -- isn't everything an Object anyway? public static void printA(java.lang.Iterable); Code: 0: aload_0 1: invokeinterface #18, 1; //InterfaceMethod java/lang/Iterable.iterator:()Ljava/util/Iterator; 6: astore_2 7: goto 24 10: aload_2 11: invokeinterface #24, 1; //InterfaceMethod java/util/Iterator.next:()Ljava/lang/Object; 16: astore_1 17: getstatic #30; //Field java/lang/System.out:Ljava/io/PrintStream; 20: aload_1 21: invokevirtual #36; //Method java/io/PrintStream.println:(Ljava/lang/Object;)V 24: aload_2 25: invokeinterface #42, 1; //InterfaceMethod java/util/Iterator.hasNext:()Z 30: ifne 10 33: return public static void printB(java.lang.Iterable); Code: 0: aload_0 1: invokeinterface #18, 1; //InterfaceMethod java/lang/Iterable.iterator:()Ljava/util/Iterator; 6: astore_2 7: goto 27 10: aload_2 11: invokeinterface #24, 1; //InterfaceMethod java/util/Iterator.next:()Ljava/lang/Object; 16: checkcast #3; //class java/lang/Object 19: astore_1 20: getstatic #30; //Field java/lang/System.out:Ljava/io/PrintStream; 23: aload_1 24: invokevirtual #36; //Method java/io/PrintStream.println:(Ljava/lang/Object;)V 27: aload_2 28: invokeinterface #42, 1; //InterfaceMethod java/util/Iterator.hasNext:()Z 33: ifne 10 36: return

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  • Generating a canonical path

    - by Joel
    Does any one know of any Java libraries I could use to generate canonical paths (basically remove back-references). I need something that will do the following: Raw Path - Canonical Path /../foo/ -> /foo /foo/ -> /foo /../../../ -> / /./foo/./ -> /foo //foo//bar -> /foo/bar //foo/../bar -> /bar etc... At the moment I lazily rely on using: new File("/", path).getCanonicalPath(); But this resolves the path against the actual file system, and is synchronised. java.lang.Thread.State: BLOCKED (on object monitor) at java.io.ExpiringCache.get(ExpiringCache.java:55) - waiting to lock <0x93a0d180> (a java.io.ExpiringCache) at java.io.UnixFileSystem.canonicalize(UnixFileSystem.java:137) at java.io.File.getCanonicalPath(File.java:559) The paths that I am canonicalising do not exist on my file system, so just the logic of the method will do me fine, thus not requiring any synchronisation. I'm hoping for a well tested library rather than having to write my own.

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  • When Creating a Reference for an Object Where from where that class is Loaded?

    - by asela38
    When doing some sample codings with Java I came crosss ClassCast Exception, from where I cast the object to StaticClass. Can any explaing the what has happened here. public void test5() throws Exception { System.out.println(StaticClass.obj); Object newInstance = ClassLoader.getSystemClassLoader().loadClass("com.StaticClass").newInstance(); System.out.println(newInstance.getClass().getDeclaredField("obj").get(newInstance)); Object newInstance2 = new ILoader().loadClass("com//StaticClass.class").newInstance(); System.out.println(newInstance2.getClass().getDeclaredField("obj").get(newInstance2)); StaticClass s = (StaticClass)newInstance2; System.out.println(s.obj); System.out.println(newInstance.getClass().getClassLoader()); System.out.println(newInstance2.getClass().getClassLoader()); } package com; public class StaticClass { public static final Object obj = new Object(); } package com; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; public class ILoader extends ClassLoader { public ILoader() { super(null); } @Override protected Class<?> findClass(String name) throws ClassNotFoundException { File file = new File(name); byte[] bytes = new byte[(int)file.length()]; try { new FileInputStream(file).read(bytes); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return super.defineClass("com.StaticClass",bytes, 0, bytes.length); } } output which was given by last sysout's when the casting part of the code not existed is as belows. sun.misc.Launcher$AppClassLoader@133056f com.ILoader@1ac3c08

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  • Can someone answer this for me?

    - by Dcurvez
    okay I am totally stuck. I have been getting some help off and on throughout this project and am anxious to get this problem solved so I can continue on with the rest of this project. I have a gridview that is set to save to a file, and has the option to import into excel. I keep getting an error of this: Invalid cast exception was unhandled. At least one element in the source array could not be cast down to the destination array type. Can anyone tell me in layman easy to understand what this error is speaking of? This is the code I am trying to use: Dim fileName As String = "" Dim dlgSave As New SaveFileDialog dlgSave.Filter = "Text files (*.txt)|*.txt|CSV Files (*.csv)|*.csv" dlgSave.AddExtension = True dlgSave.DefaultExt = "txt" If dlgSave.ShowDialog = Windows.Forms.DialogResult.OK Then fileName = dlgSave.FileName SaveToFile(fileName) End If End Sub Private Sub SaveToFile(ByVal fileName As String) If DataGridView1.RowCount > 0 AndAlso DataGridView1.Rows(0).Cells(0) IsNot Nothing Then Dim stream As New System.IO.FileStream(fileName, IO.FileMode.Append, IO.FileAccess.Write) Dim sw As New System.IO.StreamWriter(stream) For Each row As DataGridViewRow In DataGridView1.Rows Dim arrLine(9) As String Dim line As String **row.Cells.CopyTo(arrLine, 0)** line = arrLine(0) line &= ";" & arrLine(1) line &= ";" & arrLine(2) line &= ";" & arrLine(3) line &= ";" & arrLine(4) line &= ";" & arrLine(5) line &= ";" & arrLine(6) line &= ";" & arrLine(7) line &= ";" & arrLine(8) sw.WriteLine(line) Next sw.Flush() sw.Close() End If I bolded the line where it shows in debug, and I really dont see what all the fuss is about LOL

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