Search Results

Search found 8267 results on 331 pages for 'insert into'.

Page 68/331 | < Previous Page | 64 65 66 67 68 69 70 71 72 73 74 75  | Next Page >

  • PostgreSQL - fetch the row which has the Max value for a column

    - by Joshua Berry
    I'm dealing with a Postgres table (called "lives") that contains records with columns for time_stamp, usr_id, transaction_id, and lives_remaining. I need a query that will give me the most recent lives_remaining total for each usr_id There are multiple users (distinct usr_id's) time_stamp is not a unique identifier: sometimes user events (one by row in the table) will occur with the same time_stamp. trans_id is unique only for very small time ranges: over time it repeats remaining_lives (for a given user) can both increase and decrease over time example: time_stamp|lives_remaining|usr_id|trans_id ----------------------------------------- 07:00 | 1 | 1 | 1 09:00 | 4 | 2 | 2 10:00 | 2 | 3 | 3 10:00 | 1 | 2 | 4 11:00 | 4 | 1 | 5 11:00 | 3 | 1 | 6 13:00 | 3 | 3 | 1 As I will need to access other columns of the row with the latest data for each given usr_id, I need a query that gives a result like this: time_stamp|lives_remaining|usr_id|trans_id ----------------------------------------- 11:00 | 3 | 1 | 6 10:00 | 1 | 2 | 4 13:00 | 3 | 3 | 1 As mentioned, each usr_id can gain or lose lives, and sometimes these timestamped events occur so close together that they have the same timestamp! Therefore this query won't work: SELECT b.time_stamp,b.lives_remaining,b.usr_id,b.trans_id FROM (SELECT usr_id, max(time_stamp) AS max_timestamp FROM lives GROUP BY usr_id ORDER BY usr_id) a JOIN lives b ON a.max_timestamp = b.time_stamp Instead, I need to use both time_stamp (first) and trans_id (second) to identify the correct row. I also then need to pass that information from the subquery to the main query that will provide the data for the other columns of the appropriate rows. This is the hacked up query that I've gotten to work: SELECT b.time_stamp,b.lives_remaining,b.usr_id,b.trans_id FROM (SELECT usr_id, max(time_stamp || '*' || trans_id) AS max_timestamp_transid FROM lives GROUP BY usr_id ORDER BY usr_id) a JOIN lives b ON a.max_timestamp_transid = b.time_stamp || '*' || b.trans_id ORDER BY b.usr_id Okay, so this works, but I don't like it. It requires a query within a query, a self join, and it seems to me that it could be much simpler by grabbing the row that MAX found to have the largest timestamp and trans_id. The table "lives" has tens of millions of rows to parse, so I'd like this query to be as fast and efficient as possible. I'm new to RDBM and Postgres in particular, so I know that I need to make effective use of the proper indexes. I'm a bit lost on how to optimize. I found a similar discussion here. Can I perform some type of Postgres equivalent to an Oracle analytic function? Any advice on accessing related column information used by an aggregate function (like MAX), creating indexes, and creating better queries would be much appreciated! P.S. You can use the following to create my example case: create TABLE lives (time_stamp timestamp, lives_remaining integer, usr_id integer, trans_id integer); insert into lives values ('2000-01-01 07:00', 1, 1, 1); insert into lives values ('2000-01-01 09:00', 4, 2, 2); insert into lives values ('2000-01-01 10:00', 2, 3, 3); insert into lives values ('2000-01-01 10:00', 1, 2, 4); insert into lives values ('2000-01-01 11:00', 4, 1, 5); insert into lives values ('2000-01-01 11:00', 3, 1, 6); insert into lives values ('2000-01-01 13:00', 3, 3, 1);

    Read the article

  • Inserting newlines into a GtkTextView widget (GTK+ programming)

    - by Mark Roberts
    I've got a button which when clicked copies and appends the text from a GtkEntry widget into a GtkTextView widget. (This code is a modified version of an example found in the "The Text View Widget" chapter of Foundations of GTK+ Development.) I'm looking to insert a newline character before the text which gets copied and appended, such that each line of text will be on its own line in the GtkTextView widget. How would I do this? I'm brand new to GTK+. Here's the code sample: #include <gtk/gtk.h> typedef struct { GtkWidget *entry, *textview; } Widgets; static void insert_text (GtkButton*, Widgets*); int main (int argc, char *argv[]) { GtkWidget *window, *scrolled_win, *hbox, *vbox, *insert; Widgets *w = g_slice_new (Widgets); gtk_init (&argc, &argv); window = gtk_window_new (GTK_WINDOW_TOPLEVEL); gtk_window_set_title (GTK_WINDOW (window), "Text Iterators"); gtk_container_set_border_width (GTK_CONTAINER (window), 10); gtk_widget_set_size_request (window, -1, 200); w->textview = gtk_text_view_new (); w->entry = gtk_entry_new (); insert = gtk_button_new_with_label ("Insert Text"); g_signal_connect (G_OBJECT (insert), "clicked", G_CALLBACK (insert_text), (gpointer) w); scrolled_win = gtk_scrolled_window_new (NULL, NULL); gtk_container_add (GTK_CONTAINER (scrolled_win), w->textview); hbox = gtk_hbox_new (FALSE, 5); gtk_box_pack_start_defaults (GTK_BOX (hbox), w->entry); gtk_box_pack_start_defaults (GTK_BOX (hbox), insert); vbox = gtk_vbox_new (FALSE, 5); gtk_box_pack_start (GTK_BOX (vbox), scrolled_win, TRUE, TRUE, 0); gtk_box_pack_start (GTK_BOX (vbox), hbox, FALSE, TRUE, 0); gtk_container_add (GTK_CONTAINER (window), vbox); gtk_widget_show_all (window); gtk_main(); return 0; } /* Insert the text from the GtkEntry into the GtkTextView. */ static void insert_text (GtkButton *button, Widgets *w) { GtkTextBuffer *buffer; GtkTextMark *mark; GtkTextIter iter; const gchar *text; buffer = gtk_text_view_get_buffer (GTK_TEXT_VIEW (w->textview)); text = gtk_entry_get_text (GTK_ENTRY (w->entry)); mark = gtk_text_buffer_get_insert (buffer); gtk_text_buffer_get_iter_at_mark (buffer, &iter, mark); gtk_text_buffer_insert (buffer, &iter, text, -1); } You can compile this command (assuming the file is named file.c): gcc file.c -o file `pkg-config --cflags --libs gtk+-2.0` Thanks everybody!

    Read the article

  • Connecting form to database errors

    - by Russell Ehrnsberger
    Hello I am trying to connect a page to a MySQL database for newsletter signup. I have the database with 3 fields, id, name, email. The database is named newsletter and the table is named newsletter. Everything seems to be fine but I am getting this error Notice: Undefined index: Name in C:\wamp\www\insert.php on line 12 Notice: Undefined index: Name in C:\wamp\www\insert.php on line 13 Here is my form code. <form action="insert.php" method="post"> <input type="text" value="Name" name="Name" id="Name" class="txtfield" onblur="javascript:if(this.value==''){this.value=this.defaultValue;}" onfocus="javascript:if(this.value==this.defaultValue){this.value='';}" /> <input type="text" value="Enter Email Address" name="Email" id="Email" class="txtfield" onblur="javascript:if(this.value==''){this.value=this.defaultValue;}" onfocus="javascript:if(this.value==this.defaultValue){this.value='';}" /> <input type="submit" value="" class="button" /> </form> Here is my insert.php file. <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="newsletter"; // Database name $tbl_name="newsletter"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // Get values from form $name=$_POST['Name']; $email=$_POST['Email']; // Insert data into mysql $sql="INSERT INTO $tbl_name(name, email)VALUES('$name', '$email')"; $result=mysql_query($sql); // if successfully insert data into database, displays message "Successful". if($result){ echo "Successful"; echo "<BR>"; echo "<a href='index.html'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?>

    Read the article

  • Comments Parent-Child query with indentation

    - by poldoj
    I've been trying to retrieve comments to articles in a pretty common blog fashion way. Here's my sample code: -- ---------------------------- -- Sample Table structure for [dbo].[Comments] -- ---------------------------- CREATE TABLE [dbo].[Comments] ( [CommentID] int NOT NULL , [AddedDate] datetime NOT NULL , [AddedBy] nvarchar(256) NOT NULL , [ArticleID] int NOT NULL , [Body] nvarchar(4000) NOT NULL , [parentCommentID] int NULL ) GO -- ---------------------------- -- Sample Records of Comments -- ---------------------------- INSERT INTO [dbo].[Comments] ([CommentID], [AddedDate], [AddedBy], [ArticleID], [Body], [parentCommentID]) VALUES (N'1', N'2011-11-26 23:18:07.000', N'user', N'1', N'body', null); GO INSERT INTO [dbo].[Comments] ([CommentID], [AddedDate], [AddedBy], [ArticleID], [Body], [parentCommentID]) VALUES (N'2', N'2011-11-26 23:18:50.000', N'user', N'2', N'body', null); GO INSERT INTO [dbo].[Comments] ([CommentID], [AddedDate], [AddedBy], [ArticleID], [Body], [parentCommentID]) VALUES (N'3', N'2011-11-26 23:19:09.000', N'user', N'1', N'body', null); GO INSERT INTO [dbo].[Comments] ([CommentID], [AddedDate], [AddedBy], [ArticleID], [Body], [parentCommentID]) VALUES (N'4', N'2011-11-26 23:19:46.000', N'user', N'3', N'body', null); GO INSERT INTO [dbo].[Comments] ([CommentID], [AddedDate], [AddedBy], [ArticleID], [Body], [parentCommentID]) VALUES (N'5', N'2011-11-26 23:20:16.000', N'user', N'1', N'body', N'1'); GO INSERT INTO [dbo].[Comments] ([CommentID], [AddedDate], [AddedBy], [ArticleID], [Body], [parentCommentID]) VALUES (N'6', N'2011-11-26 23:20:42.000', N'user', N'1', N'body', N'1'); GO INSERT INTO [dbo].[Comments] ([CommentID], [AddedDate], [AddedBy], [ArticleID], [Body], [parentCommentID]) VALUES (N'7', N'2011-11-26 23:21:25.000', N'user', N'1', N'body', N'6'); GO -- ---------------------------- -- Indexes structure for table Comments -- ---------------------------- -- ---------------------------- -- Primary Key structure for table [dbo].[Comments] -- ---------------------------- ALTER TABLE [dbo].[Comments] ADD PRIMARY KEY ([CommentID]) GO -- ---------------------------- -- Foreign Key structure for table [dbo].[Comments] -- ---------------------------- ALTER TABLE [dbo].[Comments] ADD FOREIGN KEY ([parentCommentID]) REFERENCES [dbo]. [Comments] ([CommentID]) ON DELETE NO ACTION ON UPDATE NO ACTION GO I thought I could use a CTE query to do the job like this: WITH CommentsCTE(CommentID, AddedDate, AddedBy, ArticleID, Body, parentCommentID, lvl, sortcol) AS ( SELECT CommentID, AddedDate, AddedBy, ArticleID, Body, parentCommentID, 0, cast(CommentID as varbinary(max)) FROM Comments UNION ALL SELECT P.CommentID, P.AddedDate, P.AddedBy, P.ArticleID, P.Body, P.parentCommentID, PP.lvl+1, CAST(sortcol + CAST(P.CommentID AS BINARY(4)) AS VARBINARY(max)) FROM Comments AS P JOIN CommentsCTE AS PP ON P.parentCommentID = PP.CommentID ) SELECT REPLICATE('--', lvl) + right('>',lvl)+ AddedBy + ' :: ' + Body, CommentID, parentCommentID, lvl FROM CommentsCTE WHERE ArticleID = 1 order by sortcol go but the results have been very disappointing so far, and after days of tweaking I decided to ask for help. I was looking for a method to display hierarchical comments to articles like it happens in blogs. [edit] The problem with this query is that I get duplicates because I couldn't figure out how to properly select the ArticleID which I want comments from to display. I'm also looking for a method that sorts children entries by date within a same level. An example of what I'm trying to accomplish could be something like: (ArticleID[post retrieved]) ------------------------- ------------------------- (Comments[related to the article id above]) first comment[no parent] --[first child to first comment] --[second child to first comment] ----[first child to second child comment to first comment] --[third child to first comment] ----[first child to third child comment to first comment] ------[(recursive child): first child to first child to third child comment to first comment] ------[(recursive child): second child to first child to third child comment to first comment] second comment[no parent] third comment[no parent] --[first child to third comment] I kinda got myself lost in all this mess...I appreciate any help or simpler ways to get this working. Thanks

    Read the article

  • --log-slave-updates is OFF but some updates are still logged to the slave binary log?

    - by quanta
    MySQL version 5.5.14 According to the document, by the default, slave does not log to its binary log any updates that are received from a master server. Here are my config. on the slave: # egrep 'bin|slave' /etc/my.cnf relay-log=mysqld-relay-bin log-bin = /var/log/mysql/mysql-bin binlog-format=MIXED sync_binlog = 1 log-bin-trust-function-creators = 1 mysql> show global variables like 'log_slave%'; +-------------------+-------+ | Variable_name | Value | +-------------------+-------+ | log_slave_updates | OFF | +-------------------+-------+ 1 row in set (0.01 sec) mysql> select @@log_slave_updates; +---------------------+ | @@log_slave_updates | +---------------------+ | 0 | +---------------------+ 1 row in set (0.00 sec) but slave still logs the some changes to its binary logs, let's see the file size: -rw-rw---- 1 mysql mysql 37M Apr 1 01:00 /var/log/mysql/mysql-bin.001256 -rw-rw---- 1 mysql mysql 25M Apr 2 01:00 /var/log/mysql/mysql-bin.001257 -rw-rw---- 1 mysql mysql 46M Apr 3 01:00 /var/log/mysql/mysql-bin.001258 -rw-rw---- 1 mysql mysql 115M Apr 4 01:00 /var/log/mysql/mysql-bin.001259 -rw-rw---- 1 mysql mysql 105M Apr 4 18:54 /var/log/mysql/mysql-bin.001260 and the sample query when reading these binary files with mysqlbinlog utility: #120404 19:08:57 server id 3 end_log_pos 110324763 Query thread_id=382435 exec_time=0 error_code=0 SET TIMESTAMP=1333541337/*!*/; INSERT INTO norep_SplitValues VALUES ( NAME_CONST('cur_string',_utf8'118212' COLLATE 'utf8_general_ci')) /*!*/; # at 110324763 Did I miss something? Reply to @RolandoMySQLDBA: If replication brought this over, then the same query has to be in the relay logs. Please go find the relay log that has the INSERT query with the same TIMESTAMP (1333541337). There is no such query with the same TIMESTAMP in the relay logs. If you cannot find it in the relay logs, then look and see if Infobright is posting the INSERT query. In that instance, the INSERT should be recorded in the binary logs of the Slave. Looking more deeply into the binary logs, I see that almost of the queries are CREATE/INSERT/UPDATE/DROP "temporary" tables, something like this: # at 123873315 #120405 0:42:04 server id 3 end_log_pos 123873618 Query thread_id=395373 exec_time=0 error_code=0 SET TIMESTAMP=1333561324/*!*/; SET @@session.pseudo_thread_id=395373/*!*/; CREATE TEMPORARY TABLE `norep_tmpcampaign` ( `campaignid` INTEGER(11) NOT NULL DEFAULT '0' , `status` INTEGER(11) NOT NULL DEFAULT '0' , `updated` DATETIME, KEY `campaignid` (`campaignid`) )ENGINE=MEMORY /*!*/; # at 123873618 #120405 0:42:04 server id 3 end_log_pos 123873755 Query thread_id=395373 exec_time=0 error_code=0 SET TIMESTAMP=1333561324/*!*/; DROP TABLE IF EXISTS `norep_tmpcampaign1` /* generated by server */ "temporary" here means that they are dropped after calculation is done. I also tells the slave not to replicate any statement matches the norep_ wildcard pattern: replicate-wild-ignore-table=%.norep_% But there is an exception table in the binary logs: # at 123828094 #120405 0:37:21 server id 3 end_log_pos 123828495 Query thread_id=395209 exec_time=0 error_code=0 SET TIMESTAMP=1333561041/*!*/; INSERT INTO sessions (SessionId, ApplicationName, Created, Expires, LockDate, LockId, Timeout, Locked, SessionItems, Fla gs) Values('pgv2exo4y4vo4ccz44vwznu0', '/', '2012-04-05 00:37:21', '2012-04-05 00:57:21', '2012-04-05 00:37:21', 0, 20, 0, 'AwAAAP////8IdXNlcm5hbWUGdXNlcmlkCHBlcm1pdGlkAgAAAAQAAAAGAAAAAQABAAEA', 0) /*!*/; Description: mysql> desc reportingdb.sessions; +-----------------+------------------+------+-----+---------------------+-------+ | Field | Type | Null | Key | Default | Extra | +-----------------+------------------+------+-----+---------------------+-------+ | SessionId | varchar(64) | NO | PRI | | | | ApplicationName | varchar(255) | NO | | | | | Created | timestamp | NO | | 0000-00-00 00:00:00 | | | Expires | timestamp | NO | | 0000-00-00 00:00:00 | | | LockDate | timestamp | NO | | 0000-00-00 00:00:00 | | | LockId | int(11) unsigned | NO | | NULL | | | Timeout | int(11) unsigned | NO | | NULL | | | Locked | bit(1) | NO | | NULL | | | SessionItems | varchar(255) | YES | | NULL | | | Flags | int(11) | NO | | NULL | | +-----------------+------------------+------+-----+---------------------+-------+ I'm sure all these queries are posting by MySQL, not Infobright: $ mysql-ib -u root -p Enter password: Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 48971 Server version: 5.1.40 build number (revision)=IB_4.0.5_r15240_15370(ice) (static) Type 'help;' or '\h' for help. Type '\c' to clear the current input statement. mysql> select * from information_schema.tables where table_name='sessions'; Empty set (0.02 sec) I've been trying some INSERT/UPDATE queries with testing tables on the master, it is copied to the relay logs, not binary logs on slave: # at 311664029 #120405 0:15:23 server id 1 end_log_pos 311664006 Query thread_id=10458250 exec_time=0 error_code=0 use testuser/*!*/; SET TIMESTAMP=1333559723/*!*/; update users set email2='[email protected]' where id=22 /*!*/; Pay attention to the server id, in the relay logs, server id is master's (1) and in the binary log, server id is slave's (3 in this case). Reply to @RolandoMySQLDBA: Thu Apr 5 10:06:00 ICT 2012 Run CREATE DATABASE quantatest; on the Master now, please. Tell me if CREATE DATABASE quantatest; showed up in the Slave's Binary Logs. As I said above: I've been trying some INSERT/UPDATE queries with testing tables on the master, it is copied to the relay logs, not binary logs and you can guess, IO thread copied it to the relay logs, not binary logs. #120405 10:07:25 server id 1 end_log_pos 347573819 Query thread_id=10480775 exec_time=0 error_code=0 SET TIMESTAMP=1333595245/*!*/; /*!\C latin1 *//*!*/; SET @@session.character_set_client=8,@@session.collation_connection=8,@@session.collation_server=8/*!*/; create database quantatest /*!*/; The question must probably change to: why some update queries still logged to the slave binary logs althrough --log-slave-updates is disabled? Where they come from? Here are few last: /*!*/; # at 27492197 #120405 10:12:45 server id 3 end_log_pos 27492370 Query thread_id=410353 exec_time=0 error_code=0 SET TIMESTAMP=1333595565/*!*/; CREATE TEMPORARY TABLE norep_SplitValues ( value VARCHAR(1000) NOT NULL ) ENGINE=MEMORY /*!*/; # at 27492370 #120405 10:12:45 server id 3 end_log_pos 27492445 Query thread_id=410353 exec_time=0 error_code=0 SET TIMESTAMP=1333595565/*!*/; BEGIN /*!*/; # at 27492445 #120405 10:12:45 server id 3 end_log_pos 27492619 Query thread_id=410353 exec_time=0 error_code=0 SET TIMESTAMP=1333595565/*!*/; INSERT INTO norep_SplitValues VALUES ( NAME_CONST('cur_string',_utf8'119577' COLLATE 'utf8_general_ci')) /*!*/; # at 27492619 #120405 10:12:45 server id 3 end_log_pos 27492695 Query thread_id=410353 exec_time=0 error_code=0 SET TIMESTAMP=1333595565/*!*/; COMMIT /*!*/; # at 27492918 #120405 10:12:46 server id 3 end_log_pos 27493115 Query thread_id=410353 exec_time=0 error_code=0 SET TIMESTAMP=1333595566/*!*/; SELECT `reportingdb`.`selfserving_get_locationad`(_utf8'3' COLLATE 'utf8_general_ci',_utf8'' COLLATE 'utf8_general_ci') /*!*/; # at 27493199 #120405 10:12:46 server id 3 end_log_pos 27493353 Query thread_id=410353 exec_time=0 error_code=0 SET TIMESTAMP=1333595566/*!*/; /*!\C utf8 *//*!*/; SET @@session.character_set_client=33,@@session.collation_connection=33,@@session.collation_server=8/*!*/; DROP TEMPORARY TABLE IF EXISTS `norep_SplitValues` /* generated by server */ /*!*/;

    Read the article

  • Export mysql database tables to php code to create same tables in other database?

    - by chefnelone
    How do I Export mysql database tables to php code so that it allows me to create and populate same tables in other database? I have a local database, I exported to sql syntax, then I get something like: CREATE TABLE `boletinSuscritos` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(120) NOT NULL, `email` varchar(120) NOT NULL, `date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=3 ; INSERT INTO `boletinSuscritos` VALUES(1, 'walter', '[email protected]', '2010-03-24 12:53:12'); INSERT INTO `boletinSuscritos` VALUES(2, 'Paco', '[email protected]', '2010-03-24 12:56:56'); but I need it to be: (Is there any way to export the tables in this way) $sql = "CREATE TABLE boletinSuscritos ( id int(11) NOT NULL AUTO_INCREMENT, name varchar(120) NOT NULL, email varchar(120) NOT NULL, date timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( id ) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=3 )"; mysql_query($sql,$conexion); mysql_query("INSERT INTO boletinSuscritos VALUES(1, 'walter', '[email protected]', '2010-03-24 12:53:12')"); mysql_query("INSERT INTO boletinSuscritos VALUES(2, 'Paco', '[email protected]', '2010-03-24 12:56:56')");

    Read the article

  • Issue with resetting auto increment from default to big number

    - by Sai Srikanth
    I have a MySQL table naming Invoice for a Inventory Monitoring site, invoice_number is bigint(19) AUTO_INCREMENT field. Currently AUTO_INCREMENT value is 1. Client want it to start the invoice_number from 50000. With the following script reset the ALTER TABLE INVOICES AUTO_INCREMENT = 50000; When I wrote an Insert Script to insert data in SQLDBX, it is putting the invoice_number from 50000. But when i am trying to do insert a record using the application(web application), the invoice_number value is starting from 1. We are making use of Spring-JDBC template to insert data into mysql database.

    Read the article

  • error exporting data using mysql workbench

    - by Rajneesh Rana
    hi, i have been getting warning of version mismatch when i was trying to export data dump using mysql workbench. So, i copied mysqldump from mysql server folder and placed it in workbench folder. Now when i am trying to export data i am getting error Operation failed with exitcode -1073741819 here is a entry of log 16:31:25 Dumping wordpress (wp_posts) Running: "mysqldump.exe" --defaults-extra-file="c:\docume~1\rajneesh.r\locals~1\temp\1\tmpxau7tz" --no-create-info=FALSE --order-by-primary=FALSE --force=FALSE --no-data=FALSE --tz-utc=TRUE --flush-privileges=FALSE --compress=FALSE --replace=FALSE --host=localhost --insert-ignore=FALSE --extended-insert=TRUE --user=root --quote-names=TRUE --hex-blob=FALSE --complete-insert=FALSE --add-locks=TRUE --port=3306 --disable-keys=TRUE --delayed-insert=FALSE --create-options=TRUE --delete-master-logs=FALSE --comments=TRUE --default-character-set=utf8 --max_allowed_packet=1G --flush-logs=FALSE --dump-date=TRUE --lock-tables=TRUE --allow-keywords=FALSE --events=FALSE "wordpress" "wp_posts" Operation failed with exitcode -1073741819 Please help me with these issues Thank You

    Read the article

  • How to disable text overwrite mode in Netbeans (CentOS)?

    - by Kevin Lee
    Everytime I type some text, it is overwriting what I have typed. I assume that the mode is set to overwriting, I want to insert the text not overwrite it, but I can't disable it because my insert key is mixed up with my delete key so everytime I enter insert to disable the overwrite mode, it just delete what I type. So how to disable this? I'm using centOS.. and it seems that my problem is only related to Netbeans because when I type here, it is set to insert mode.. but in Netbeans, it just overwrites the codes! help!

    Read the article

  • MySQL Privileges required to GRANT EVENT, EXECUTE, LOCK TABLES, and TRIGGER

    - by Brad
    I have an account, user_a, and I would like to grant all available permissions on some_db to user_b. I have tried the following query: GRANT ALTER, ALTER ROUTINE, CREATE, CREATE ROUTINE, CREATE TEMPORARY TABLES, CREATE VIEW, DELETE, DROP, EVENT, EXECUTE, INDEX, INSERT, LOCK TABLES, REFERENCES, SELECT, SHOW VIEW, TRIGGER, UPDATE ON `some_db`.* TO 'user_b'@'%' WITH GRANT OPTION The result: Access denied for user 'user_a'@'%' to database 'some_db' Some experimentation has shown me that the only permissions my account (user_a) is unable to grant are EVENT, EXECUTE, LOCK TABLES, and TRIGGER. What privileges are required for my account to GRANT these privileges to another user? If I run SHOW GRANTS, I get this output: "GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, REFERENCES, INDEX, ALTER, SHOW DATABASES, SUPER, CREATE TEMPORARY TABLES, REPLICATION SLAVE, REPLICATION CLIENT, CREATE VIEW, SHOW VIEW, CREATE ROUTINE, ALTER ROUTINE, CREATE USER ON *.* TO 'user_a'@'%' IDENTIFIED BY PASSWORD '1234567890abcdef' WITH GRANT OPTION" "GRANT SELECT, INSERT, UPDATE, DELETE, EXECUTE ON `some_other_unrelated_db`.* TO 'user_a'@'%'" "GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, REFERENCES, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES, EXECUTE, CREATE ROUTINE, ALTER ROUTINE ON `another_unrelated_db`.* TO 'user_a'@'%' WITH GRANT OPTION"

    Read the article

  • How to disable text overwrite mode in Netbeans (CentOS)?

    - by Kevin Lee
    Everytime I type some text, it is overwriting what I have typed. I assume that the mode is set to overwriting, I want to insert the text not overwrite it, but I can't disable it because my insert key is mixed up with my delete key so everytime I enter insert to disable the overwrite mode, it just delete what I type. So how to disable this? I'm using centOS.. and it seems that my problem is only related to Netbeans because when I type here, it is set to insert mode.. but in Netbeans, it just overwrites the codes! help!

    Read the article

  • Object reference not set to an instance of an object- Linked List Example

    - by Zoro Roronoa
    I am seeing following errors : Object reference not set to an instance of an object! Check to determinate if the object is null before calling the method! I'am new with C#,and I made a program for Sorted Linked Lists. Here is the code where the error comes! public void Insert(double data) { Link newLink = new Link(data); Link current = first; Link previous = null; if (first == null) { first = newLink; } else { while (data > current.DData && current != null) { previous = current; current = current.Next; } previous.Next = newLink; newLink.Next = current; } } It says that the current referenc is null while (data current.DData && current != null), but I assigned it current = first; Please Help ! The rest is the complete code of the Program! class Link { double dData; Link next=null; public Link Next { get { return next; } set { next = value; } } public double DData { get { return dData; } set { dData = value; } } public Link(double dData) { this.dData = dData; } public void DisplayLink() { Console.WriteLine("Link : "+ dData); } } class SortedList { Link first; public SortedList() { first = null; } public bool IsEmpty() { return (this.first == null); } public void Insert(double data) { Link newLink = new Link(data); Link current = first; Link previous = null; if (first == null) { first = newLink; } else { while (data > current.DData && current != null) { previous = current; current = current.Next; } previous.Next = newLink; newLink.Next = current; } } public Link Remove() { Link temp = first; first = first.Next; return temp; } public void DisplayList() { Link current; current = first; Console.WriteLine("Display the List!"); while (current != null) { current.DisplayLink(); current = current.Next; } } } class SortedListApp { public void TestSortedList() { SortedList newList = new SortedList(); newList.Insert(20); newList.Insert(22); newList.Insert(100); newList.Insert(1000); newList.Insert(15); newList.Insert(11); newList.DisplayList(); newList.Remove(); newList.DisplayList(); } }

    Read the article

  • SQL SERVER – Importing CSV File Into Database – SQL in Sixty Seconds #018 – Video

    - by pinaldave
    Importing data into database is one of the most important tasks. I often receive questions regarding what is the quickest way to insert CSV data or how to import CSV Data into SQL Server Table. Honestly the process is very simple and the script is even simpler. In today’s SQL in Sixty Seconds Video we will learn how quickly we can insert CSV data into SQL Server. The steps to import CSV are very simple. Create Table Use Bulk Insert to import the data Verify the data Done! Absolutely it is that simple. More on Importing CSV Data: SQL SERVER – Import CSV File Into SQL Server Using Bulk Insert – Load Comma Delimited File Into SQL Server SQL SERVER – Import CSV File into Database Table Using SSIS SQL SERVER – Create a Comma Delimited List Using SELECT Clause From Table Column SQL SERVER – Comma Separated Values (CSV) from Table Column SQL SERVER – Comma Separated Values (CSV) from Table Column – Part 2 I encourage you to submit your ideas for SQL in Sixty Seconds. We will try to accommodate as many as we can. If we like your idea we promise to share with you educational material. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Database, Pinal Dave, PostADay, SQL, SQL Authority, SQL in Sixty Seconds, SQL Query, SQL Scripts, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL, Technology, Video

    Read the article

  • Using a "white list" for extracting terms for Text Mining, Part 2

    - by [email protected]
    In my last post, we set the groundwork for extracting specific tokens from a white list using a CTXRULE index. In this post, we will populate a table with the extracted tokens and produce a case table suitable for clustering with Oracle Data Mining. Our corpus of documents will be stored in a database table that is defined as create table documents(id NUMBER, text VARCHAR2(4000)); However, any suitable Oracle Text-accepted data type can be used for the text. We then create a table to contain the extracted tokens. The id column contains the unique identifier (or case id) of the document. The token column contains the extracted token. Note that a given document many have many tokens, so there will be one row per token for a given document. create table extracted_tokens (id NUMBER, token VARCHAR2(4000)); The next step is to iterate over the documents and extract the matching tokens using the index and insert them into our token table. We use the MATCHES function for matching the query_string from my_thesaurus_rules with the text. DECLARE     cursor c2 is       select id, text       from documents; BEGIN     for r_c2 in c2 loop        insert into extracted_tokens          select r_c2.id id, main_term token          from my_thesaurus_rules          where matches(query_string,                        r_c2.text)>0;     end loop; END; Now that we have the tokens, we can compute the term frequency - inverse document frequency (TF-IDF) for each token of each document. create table extracted_tokens_tfidf as   with num_docs as (select count(distinct id) doc_cnt                     from extracted_tokens),        tf       as (select a.id, a.token,                            a.token_cnt/b.num_tokens token_freq                     from                        (select id, token, count(*) token_cnt                        from extracted_tokens                        group by id, token) a,                       (select id, count(*) num_tokens                        from extracted_tokens                        group by id) b                     where a.id=b.id),        doc_freq as (select token, count(*) overall_token_cnt                     from extracted_tokens                     group by token)   select tf.id, tf.token,          token_freq * ln(doc_cnt/df.overall_token_cnt) tf_idf   from num_docs,        tf,        doc_freq df   where df.token=tf.token; From the WITH clause, the num_docs query simply counts the number of documents in the corpus. The tf query computes the term (token) frequency by computing the number of times each token appears in a document and divides that by the number of tokens found in the document. The doc_req query counts the number of times the token appears overall in the corpus. In the SELECT clause, we compute the tf_idf. Next, we create the nested table required to produce one record per case, where a case corresponds to an individual document. Here, we COLLECT all the tokens for a given document into the nested column extracted_tokens_tfidf_1. CREATE TABLE extracted_tokens_tfidf_nt              NESTED TABLE extracted_tokens_tfidf_1                  STORE AS extracted_tokens_tfidf_tab AS              select id,                     cast(collect(DM_NESTED_NUMERICAL(token,tf_idf)) as DM_NESTED_NUMERICALS) extracted_tokens_tfidf_1              from extracted_tokens_tfidf              group by id;   To build the clustering model, we create a settings table and then insert the various settings. Most notable are the number of clusters (20), using cosine distance which is better for text, turning off auto data preparation since the values are ready for mining, the number of iterations (20) to get a better model, and the split criterion of size for clusters that are roughly balanced in number of cases assigned. CREATE TABLE km_settings (setting_name  VARCHAR2(30), setting_value VARCHAR2(30)); BEGIN  INSERT INTO km_settings (setting_name, setting_value) VALUES     VALUES (dbms_data_mining.clus_num_clusters, 20);  INSERT INTO km_settings (setting_name, setting_value)     VALUES (dbms_data_mining.kmns_distance, dbms_data_mining.kmns_cosine);   INSERT INTO km_settings (setting_name, setting_value) VALUES     VALUES (dbms_data_mining.prep_auto,dbms_data_mining.prep_auto_off);   INSERT INTO km_settings (setting_name, setting_value) VALUES     VALUES (dbms_data_mining.kmns_iterations,20);   INSERT INTO km_settings (setting_name, setting_value) VALUES     VALUES (dbms_data_mining.kmns_split_criterion,dbms_data_mining.kmns_size);   COMMIT; END; With this in place, we can now build the clustering model. BEGIN     DBMS_DATA_MINING.CREATE_MODEL(     model_name          => 'TEXT_CLUSTERING_MODEL',     mining_function     => dbms_data_mining.clustering,     data_table_name     => 'extracted_tokens_tfidf_nt',     case_id_column_name => 'id',     settings_table_name => 'km_settings'); END;To generate cluster names from this model, check out my earlier post on that topic.

    Read the article

  • Hello Operator, My Switch Is Bored

    - by Paul White
    This is a post for T-SQL Tuesday #43 hosted by my good friend Rob Farley. The topic this month is Plan Operators. I haven’t taken part in T-SQL Tuesday before, but I do like to write about execution plans, so this seemed like a good time to start. This post is in two parts. The first part is primarily an excuse to use a pretty bad play on words in the title of this blog post (if you’re too young to know what a telephone operator or a switchboard is, I hate you). The second part of the post looks at an invisible query plan operator (so to speak). 1. My Switch Is Bored Allow me to present the rare and interesting execution plan operator, Switch: Books Online has this to say about Switch: Following that description, I had a go at producing a Fast Forward Cursor plan that used the TOP operator, but had no luck. That may be due to my lack of skill with cursors, I’m not too sure. The only application of Switch in SQL Server 2012 that I am familiar with requires a local partitioned view: CREATE TABLE dbo.T1 (c1 int NOT NULL CHECK (c1 BETWEEN 00 AND 24)); CREATE TABLE dbo.T2 (c1 int NOT NULL CHECK (c1 BETWEEN 25 AND 49)); CREATE TABLE dbo.T3 (c1 int NOT NULL CHECK (c1 BETWEEN 50 AND 74)); CREATE TABLE dbo.T4 (c1 int NOT NULL CHECK (c1 BETWEEN 75 AND 99)); GO CREATE VIEW V1 AS SELECT c1 FROM dbo.T1 UNION ALL SELECT c1 FROM dbo.T2 UNION ALL SELECT c1 FROM dbo.T3 UNION ALL SELECT c1 FROM dbo.T4; Not only that, but it needs an updatable local partitioned view. We’ll need some primary keys to meet that requirement: ALTER TABLE dbo.T1 ADD CONSTRAINT PK_T1 PRIMARY KEY (c1);   ALTER TABLE dbo.T2 ADD CONSTRAINT PK_T2 PRIMARY KEY (c1);   ALTER TABLE dbo.T3 ADD CONSTRAINT PK_T3 PRIMARY KEY (c1);   ALTER TABLE dbo.T4 ADD CONSTRAINT PK_T4 PRIMARY KEY (c1); We also need an INSERT statement that references the view. Even more specifically, to see a Switch operator, we need to perform a single-row insert (multi-row inserts use a different plan shape): INSERT dbo.V1 (c1) VALUES (1); And now…the execution plan: The Constant Scan manufactures a single row with no columns. The Compute Scalar works out which partition of the view the new value should go in. The Assert checks that the computed partition number is not null (if it is, an error is returned). The Nested Loops Join executes exactly once, with the partition id as an outer reference (correlated parameter). The Switch operator checks the value of the parameter and executes the corresponding input only. If the partition id is 0, the uppermost Clustered Index Insert is executed, adding a row to table T1. If the partition id is 1, the next lower Clustered Index Insert is executed, adding a row to table T2…and so on. In case you were wondering, here’s a query and execution plan for a multi-row insert to the view: INSERT dbo.V1 (c1) VALUES (1), (2); Yuck! An Eager Table Spool and four Filters! I prefer the Switch plan. My guess is that almost all the old strategies that used a Switch operator have been replaced over time, using things like a regular Concatenation Union All combined with Start-Up Filters on its inputs. Other new (relative to the Switch operator) features like table partitioning have specific execution plan support that doesn’t need the Switch operator either. This feels like a bit of a shame, but perhaps it is just nostalgia on my part, it’s hard to know. Please do let me know if you encounter a query that can still use the Switch operator in 2012 – it must be very bored if this is the only possible modern usage! 2. Invisible Plan Operators The second part of this post uses an example based on a question Dave Ballantyne asked using the SQL Sentry Plan Explorer plan upload facility. If you haven’t tried that yet, make sure you’re on the latest version of the (free) Plan Explorer software, and then click the Post to SQLPerformance.com button. That will create a site question with the query plan attached (which can be anonymized if the plan contains sensitive information). Aaron Bertrand and I keep a close eye on questions there, so if you have ever wanted to ask a query plan question of either of us, that’s a good way to do it. The problem The issue I want to talk about revolves around a query issued against a calendar table. The script below creates a simplified version and adds 100 years of per-day information to it: USE tempdb; GO CREATE TABLE dbo.Calendar ( dt date NOT NULL, isWeekday bit NOT NULL, theYear smallint NOT NULL,   CONSTRAINT PK__dbo_Calendar_dt PRIMARY KEY CLUSTERED (dt) ); GO -- Monday is the first day of the week for me SET DATEFIRST 1;   -- Add 100 years of data INSERT dbo.Calendar WITH (TABLOCKX) (dt, isWeekday, theYear) SELECT CA.dt, isWeekday = CASE WHEN DATEPART(WEEKDAY, CA.dt) IN (6, 7) THEN 0 ELSE 1 END, theYear = YEAR(CA.dt) FROM Sandpit.dbo.Numbers AS N CROSS APPLY ( VALUES (DATEADD(DAY, N.n - 1, CONVERT(date, '01 Jan 2000', 113))) ) AS CA (dt) WHERE N.n BETWEEN 1 AND 36525; The following query counts the number of weekend days in 2013: SELECT Days = COUNT_BIG(*) FROM dbo.Calendar AS C WHERE theYear = 2013 AND isWeekday = 0; It returns the correct result (104) using the following execution plan: The query optimizer has managed to estimate the number of rows returned from the table exactly, based purely on the default statistics created separately on the two columns referenced in the query’s WHERE clause. (Well, almost exactly, the unrounded estimate is 104.289 rows.) There is already an invisible operator in this query plan – a Filter operator used to apply the WHERE clause predicates. We can see it by re-running the query with the enormously useful (but undocumented) trace flag 9130 enabled: Now we can see the full picture. The whole table is scanned, returning all 36,525 rows, before the Filter narrows that down to just the 104 we want. Without the trace flag, the Filter is incorporated in the Clustered Index Scan as a residual predicate. It is a little bit more efficient than using a separate operator, but residual predicates are still something you will want to avoid where possible. The estimates are still spot on though: Anyway, looking to improve the performance of this query, Dave added the following filtered index to the Calendar table: CREATE NONCLUSTERED INDEX Weekends ON dbo.Calendar(theYear) WHERE isWeekday = 0; The original query now produces a much more efficient plan: Unfortunately, the estimated number of rows produced by the seek is now wrong (365 instead of 104): What’s going on? The estimate was spot on before we added the index! Explanation You might want to grab a coffee for this bit. Using another trace flag or two (8606 and 8612) we can see that the cardinality estimates were exactly right initially: The highlighted information shows the initial cardinality estimates for the base table (36,525 rows), the result of applying the two relational selects in our WHERE clause (104 rows), and after performing the COUNT_BIG(*) group by aggregate (1 row). All of these are correct, but that was before cost-based optimization got involved :) Cost-based optimization When cost-based optimization starts up, the logical tree above is copied into a structure (the ‘memo’) that has one group per logical operation (roughly speaking). The logical read of the base table (LogOp_Get) ends up in group 7; the two predicates (LogOp_Select) end up in group 8 (with the details of the selections in subgroups 0-6). These two groups still have the correct cardinalities as trace flag 8608 output (initial memo contents) shows: During cost-based optimization, a rule called SelToIdxStrategy runs on group 8. It’s job is to match logical selections to indexable expressions (SARGs). It successfully matches the selections (theYear = 2013, is Weekday = 0) to the filtered index, and writes a new alternative into the memo structure. The new alternative is entered into group 8 as option 1 (option 0 was the original LogOp_Select): The new alternative is to do nothing (PhyOp_NOP = no operation), but to instead follow the new logical instructions listed below the NOP. The LogOp_GetIdx (full read of an index) goes into group 21, and the LogOp_SelectIdx (selection on an index) is placed in group 22, operating on the result of group 21. The definition of the comparison ‘the Year = 2013’ (ScaOp_Comp downwards) was already present in the memo starting at group 2, so no new memo groups are created for that. New Cardinality Estimates The new memo groups require two new cardinality estimates to be derived. First, LogOp_Idx (full read of the index) gets a predicted cardinality of 10,436. This number comes from the filtered index statistics: DBCC SHOW_STATISTICS (Calendar, Weekends) WITH STAT_HEADER; The second new cardinality derivation is for the LogOp_SelectIdx applying the predicate (theYear = 2013). To get a number for this, the cardinality estimator uses statistics for the column ‘theYear’, producing an estimate of 365 rows (there are 365 days in 2013!): DBCC SHOW_STATISTICS (Calendar, theYear) WITH HISTOGRAM; This is where the mistake happens. Cardinality estimation should have used the filtered index statistics here, to get an estimate of 104 rows: DBCC SHOW_STATISTICS (Calendar, Weekends) WITH HISTOGRAM; Unfortunately, the logic has lost sight of the link between the read of the filtered index (LogOp_GetIdx) in group 22, and the selection on that index (LogOp_SelectIdx) that it is deriving a cardinality estimate for, in group 21. The correct cardinality estimate (104 rows) is still present in the memo, attached to group 8, but that group now has a PhyOp_NOP implementation. Skipping over the rest of cost-based optimization (in a belated attempt at brevity) we can see the optimizer’s final output using trace flag 8607: This output shows the (incorrect, but understandable) 365 row estimate for the index range operation, and the correct 104 estimate still attached to its PhyOp_NOP. This tree still has to go through a few post-optimizer rewrites and ‘copy out’ from the memo structure into a tree suitable for the execution engine. One step in this process removes PhyOp_NOP, discarding its 104-row cardinality estimate as it does so. To finish this section on a more positive note, consider what happens if we add an OVER clause to the query aggregate. This isn’t intended to be a ‘fix’ of any sort, I just want to show you that the 104 estimate can survive and be used if later cardinality estimation needs it: SELECT Days = COUNT_BIG(*) OVER () FROM dbo.Calendar AS C WHERE theYear = 2013 AND isWeekday = 0; The estimated execution plan is: Note the 365 estimate at the Index Seek, but the 104 lives again at the Segment! We can imagine the lost predicate ‘isWeekday = 0’ as sitting between the seek and the segment in an invisible Filter operator that drops the estimate from 365 to 104. Even though the NOP group is removed after optimization (so we don’t see it in the execution plan) bear in mind that all cost-based choices were made with the 104-row memo group present, so although things look a bit odd, it shouldn’t affect the optimizer’s plan selection. I should also mention that we can work around the estimation issue by including the index’s filtering columns in the index key: CREATE NONCLUSTERED INDEX Weekends ON dbo.Calendar(theYear, isWeekday) WHERE isWeekday = 0 WITH (DROP_EXISTING = ON); There are some downsides to doing this, including that changes to the isWeekday column may now require Halloween Protection, but that is unlikely to be a big problem for a static calendar table ;)  With the updated index in place, the original query produces an execution plan with the correct cardinality estimation showing at the Index Seek: That’s all for today, remember to let me know about any Switch plans you come across on a modern instance of SQL Server! Finally, here are some other posts of mine that cover other plan operators: Segment and Sequence Project Common Subexpression Spools Why Plan Operators Run Backwards Row Goals and the Top Operator Hash Match Flow Distinct Top N Sort Index Spools and Page Splits Singleton and Range Seeks Bitmaps Hash Join Performance Compute Scalar © 2013 Paul White – All Rights Reserved Twitter: @SQL_Kiwi

    Read the article

  • How to Omit the Page Number From the First Page of a Word 2013 Document Without Using Sections

    - by Lori Kaufman
    Normally, the first page, or cover page, of a document does not have a page number or other header or footer text. You can avoid putting a page number on the first page using sections, but there is an easier way to do this. If you don’t plan to use sections in any other part of your document, you may want to avoid using them completely. We will show you how to easily take the page number off the cover page and start the page numbering at one on the second page of your document by simply using a footer (or a header) and changing one setting. Click the Page Layout tab. In the Page Setup section of the Page Layout tab, click the Page Setup dialog box launcher icon in the lower, right corner of the section. On the Page Setup dialog box, click the Layout tab and select the Different first page check box in the Headers and footers section so there is a check mark in the box. Click OK. You’ll notice there is no page number on the first page of your document now. However, you might want the second page to be page one of your document, only to find it is currently page two. To change the page number on the second page to one, click the Insert tab. In the Header & Footer section of the Insert tab, click Page Number and select Format Page Numbers from the drop-down menu. On the Page Number Format dialog box, select Start at in the Page numbering section. Enter 0 in the edit box and click OK. This allows the second page of your document to be labeled as page one. You can use the drop-down menu on the Format Page Numbers button in the Header & Footer section of the Insert tab to add page numbers to your document as well. Easily insert formatted page numbers at the top or bottom of the page or in the page margins. Use the same menu to remove page numbers from your document.     

    Read the article

  • UTF-8 encoding problem with flash mysql and php

    - by alibhp
    Hi, As you may know, I am programming an on-line game using FLASH. I am connecting my FLASH 8 movie with MySQL database through PHP. I am doing very good in that, and I have everything working fine. The problems come when I am trying to insert (Using the INSERT SQL func) data to the database that are non-english. In other words, UTF-8 data. I red a lot of articls about that stuff and found and apply the fallowing: 1. In PHP4, you need to tell the PHP to use UTF-8 when using the xml_parser_crater() func, however, in PHP5 that is done automatically. Even though I told PHP5 to use the UTF-8 when calling the func. Adding the header to the XML sent to PHP from flash. Force the FLASH to use UTF-8 encoding in the preference options. Set the encoding in MySQL to UTF-8 (utf8_unicode_ci with InnoDB engine). I can read and insert the other language data correctly in the phpadmin as well. I did all that in my coding, and still I can't insert such data. one more strange thing is that, when I use the same link, that the FLASH using, with the XML, that the FLASH creating, on the browser (google chrome), I got the data inserted right in the database!!!!! I am about to get crazy about that stuff, What am I missing? what cause the problem? Thank you in advance.

    Read the article

  • how to troubleshoot sql server issues

    - by joe
    i have an ASP .net application with sql server database, and i am wondering if you can give your ideas on how to troubleshoot the following issue: i can insert / update / delete from any table, but i have one page that uses transactions to insert into different tables. the c# code is correct and very simple, but it fails. i used the sql profiler to see how my app interacts with the DB, especially that the app is using stored procedures, i can catch the exec procedure statement and run it manually from SSMS and it works fine, but the same stored procedure fails from the application!!! which lead me to think that issue is coming from the user account and settings, i am no expert in sql server and wondering if anyone can explain how to verify the required settings for user account. thanks EDIT: in web.config here is how i reference my connection <connectionStrings> <add name="Conn" connectionString="Data Source=localhost;Initial Catalog=myDB;Persist Security Info=True;User ID=DbUser;Password=password1254_3" providerName="System.Data.SqlClient"> </connectionstring> EDIT: i will try to describe the process here: 1- i begin a transaction 2- i call a stored proc to insert (which succeeds) and return the scope identity ( that will be used in the next step) 3- i call another stored procedure to insert some more info + scope identity from step 2, which is a foreign key here 4- i get error, foreign key violation 5- transaction rolled back, now tables empty again... thanks

    Read the article

  • New features in SQL Prompt 6.4

    - by Tom Crossman
    We’re pleased to announce a new beta version of SQL Prompt. We’ve been trying out a few new core technologies, and used them to add features and bug fixes suggested by users on the SQL Prompt forum and suggestions forum. You can download the SQL Prompt 6.4 beta here (zip file). Let us know what you think! New features Execute current statement In a query window, you can now execute the SQL statement under your cursor by pressing Shift + F5. For example, if you have a query containing two statements and your cursor is placed on the second statement: When you press Shift + F5, only the second statement is executed:   Insert semicolons You can now use SQL Prompt to automatically insert missing semicolons after each statement in a query. To insert semicolons, go to the SQL Prompt menu and click Insert Semicolons. Alternatively, hold Ctrl and press B then C. BEGIN…END block highlighting When you place your cursor over a BEGIN or END keyword, SQL Prompt now automatically highlights the matching keyword: Rename variables and aliases You can now use SQL Prompt to rename all occurrences of a variable or alias in a query. To rename a variable or alias, place your cursor over an instance of the variable or alias you want to rename and press F2: Improved loading dialog box The database loading dialog box now shows actual progress, and you can cancel loading databases:   Single suggestion improvement SQL Prompt no longer suggests keywords if the keyword has been typed and no other suggestions exist. Performance improvement SQL Prompt now has less impact on Management Studio start up time. What do you think? We want to hear your feedback about the beta. If you have any suggestions, or bugs to report, tell us on the SQL Prompt forum or our suggestions forum.

    Read the article

  • 12c - Invisible Columns...

    - by noreply(at)blogger.com (Thomas Kyte)
    Remember when 11g first came out and we had "invisible indexes"?  It seemed like a confusing feature - indexes that would be maintained by modifications (hence slowing them down), but would not be used by queries (hence never speeding them up).  But - after you looked at them a while, you could see how they can be useful.  For example - to add an index in a running production system, an index used by the next version of the code to be introduced later that week - but not tested against the queries in version one of the application in place now.  We all know that when you add an index - one of three things can happen - a given query will go much faster, it won't affect a given query at all, or... It will make some untested query go much much slower than it used to.  So - invisible indexes allowed us to modify the schema in a 'safe' manner - hiding the change until we were ready for it.Invisible columns accomplish the same thing - the ability to introduce a change while minimizing any negative side effects of that change.  Normally when you add a column to a table - any program with a SELECT * would start seeing that column, and programs with an INSERT INTO T VALUES (...) would pretty much immediately break (an INSERT without a list of columns in it).  Now we can add a column to a table in an invisible fashion, the column will not show up in a DESCRIBE command in SQL*Plus, it will not be returned with a SELECT *, it will not be considered in an INSERT INTO T VALUES statement.  It can be accessed by any query that asks for it, it can be populated by an INSERT statement that references it, but you won't see it otherwise.For example, let's start with a simple two column table:ops$tkyte%ORA12CR1> create table t  2  ( x int,  3    y int  4  )  5  /Table created.ops$tkyte%ORA12CR1> insert into t values ( 1, 2 );1 row created.Now, we will add an invisible column to it:ops$tkyte%ORA12CR1> alter table t add                     ( z int INVISIBLE );Table altered.Notice that a DESCRIBE will not show us this column:ops$tkyte%ORA12CR1> desc t Name              Null?    Type ----------------- -------- ------------ X                          NUMBER(38) Y                          NUMBER(38)and existing inserts are unaffected by it:ops$tkyte%ORA12CR1> insert into t values ( 3, 4 );1 row created.A SELECT * won't see it either:ops$tkyte%ORA12CR1> select * from t;         X          Y---------- ----------         1          2         3          4But we have full access to it (in well written programs! The ones that use a column list in the insert and select - never relying on "defaults":ops$tkyte%ORA12CR1> insert into t (x,y,z)                         values ( 5,6,7 );1 row created.ops$tkyte%ORA12CR1> select x, y, z from t;         X          Y          Z---------- ---------- ----------         1          2         3          4         5          6          7and when we are sure that we are ready to go with this column, we can just modify it:ops$tkyte%ORA12CR1> alter table t modify z visible;Table altered.ops$tkyte%ORA12CR1> select * from t;         X          Y          Z---------- ---------- ----------         1          2         3          4         5          6          7I will say that a better approach to this - one that is available in 11gR2 and above - would be to use editioning views (part of Edition Based Redefinition - EBR ).  I would rather use EBR over this approach, but in an environment where EBR is not being used, or the editioning views are not in place, this will achieve much the same.Read these for information on EBR:http://www.oracle.com/technetwork/issue-archive/2010/10-jan/o10asktom-172777.htmlhttp://www.oracle.com/technetwork/issue-archive/2010/10-mar/o20asktom-098897.htmlhttp://www.oracle.com/technetwork/issue-archive/2010/10-may/o30asktom-082672.html

    Read the article

  • SQL SERVER – 2008 – Introduction to Snapshot Database – Restore From Snapshot

    - by pinaldave
    Snapshot database is one of the most interesting concepts that I have used at some places recently. Here is a quick definition of the subject from Book On Line: A Database Snapshot is a read-only, static view of a database (the source database). Multiple snapshots can exist on a source database and can always reside on the same server instance as the database. Each database snapshot is consistent, in terms of transactions, with the source database as of the moment of the snapshot’s creation. A snapshot persists until it is explicitly dropped by the database owner. If you do not know how Snapshot database work, here is a quick note on the subject. However, please refer to the official description on Book-on-Line for accuracy. Snapshot database is a read-only database created from an original database called the “source database”. This database operates at page level. When Snapshot database is created, it is produced on sparse files; in fact, it does not occupy any space (or occupies very little space) in the Operating System. When any data page is modified in the source database, that data page is copied to Snapshot database, making the sparse file size increases. When an unmodified data page is read in the Snapshot database, it actually reads the pages of the original database. In other words, the changes that happen in the source database are reflected in the Snapshot database. Let us see a simple example of Snapshot. In the following exercise, we will do a few operations. Please note that this script is for demo purposes only- there are a few considerations of CPU, DISK I/O and memory, which will be discussed in the future posts. Create Snapshot Delete Data from Original DB Restore Data from Snapshot First, let us create the first Snapshot database and observe the sparse file details. USE master GO -- Create Regular Database CREATE DATABASE RegularDB GO USE RegularDB GO -- Populate Regular Database with Sample Table CREATE TABLE FirstTable (ID INT, Value VARCHAR(10)) INSERT INTO FirstTable VALUES(1, 'First'); INSERT INTO FirstTable VALUES(2, 'Second'); INSERT INTO FirstTable VALUES(3, 'Third'); GO -- Create Snapshot Database CREATE DATABASE SnapshotDB ON (Name ='RegularDB', FileName='c:\SSDB.ss1') AS SNAPSHOT OF RegularDB; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO Now let us see the resultset for the same. Now let us do delete something from the Original DB and check the same details we checked before. -- Delete from Regular Database DELETE FROM RegularDB.dbo.FirstTable; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO When we check the details of sparse file created by Snapshot database, we will find some interesting details. The details of Regular DB remain the same. It clearly shows that when we delete data from Regular/Source DB, it copies the data pages to Snapshot database. This is the reason why the size of the snapshot DB is increased. Now let us take this small exercise to  the next level and restore our deleted data from Snapshot DB to Original Source DB. -- Restore Data from Snapshot Database USE master GO RESTORE DATABASE RegularDB FROM DATABASE_SNAPSHOT = 'SnapshotDB'; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO -- Clean up DROP DATABASE [SnapshotDB]; DROP DATABASE [RegularDB]; GO Now let us check the details of the select statement and we can see that we are successful able to restore the database from Snapshot Database. We can clearly see that this is a very useful feature in case you would encounter a good business that needs it. I would like to request the readers to suggest more details if they are using this feature in their business. Also, let me know if you think it can be potentially used to achieve any tasks. Complete Script of the afore- mentioned operation for easy reference is as follows: USE master GO -- Create Regular Database CREATE DATABASE RegularDB GO USE RegularDB GO -- Populate Regular Database with Sample Table CREATE TABLE FirstTable (ID INT, Value VARCHAR(10)) INSERT INTO FirstTable VALUES(1, 'First'); INSERT INTO FirstTable VALUES(2, 'Second'); INSERT INTO FirstTable VALUES(3, 'Third'); GO -- Create Snapshot Database CREATE DATABASE SnapshotDB ON (Name ='RegularDB', FileName='c:\SSDB.ss1') AS SNAPSHOT OF RegularDB; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO -- Delete from Regular Database DELETE FROM RegularDB.dbo.FirstTable; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO -- Restore Data from Snapshot Database USE master GO RESTORE DATABASE RegularDB FROM DATABASE_SNAPSHOT = 'SnapshotDB'; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO -- Clean up DROP DATABASE [SnapshotDB]; DROP DATABASE [RegularDB]; GO Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: SQL, SQL Authority, SQL Backup and Restore, SQL Data Storage, SQL Query, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology

    Read the article

  • SQL SERVER – Enumerations in Relational Database – Best Practice

    - by pinaldave
    Marko Parkkola This article has been submitted by Marko Parkkola, Data systems designer at Saarionen Oy, Finland. Marko is excellent developer and always thinking at next level. You can read his earlier comment which created very interesting discussion here: SQL SERVER- IF EXISTS(Select null from table) vs IF EXISTS(Select 1 from table). I must express my special thanks to Marko for sending this best practice for Enumerations in Relational Database. He has really wrote excellent piece here and welcome comments here. Enumerations in Relational Database This is a subject which is very basic thing in relational databases but often not very well understood and sometimes badly implemented. There are of course many ways to do this but I concentrate only two cases, one which is “the right way” and one which is definitely wrong way. The concept Let’s say we have table Person in our database. Person has properties/fields like Firstname, Lastname, Birthday and so on. Then there’s a field that tells person’s marital status and let’s name it the same way; MaritalStatus. Now MaritalStatus is an enumeration. In C# I would definitely make it an enumeration with values likes Single, InRelationship, Married, Divorced. Now here comes the problem, SQL doesn’t have enumerations. The wrong way This is, in my opinion, absolutely the wrong way to do this. It has one upside though; you’ll see the enumeration’s description instantly when you do simple SELECT query and you don’t have to deal with mysterious values. There’s plenty of downsides too and one would be database fragmentation. Consider this (I’ve left all indexes and constraints out of the query on purpose). CREATE TABLE [dbo].[Person] ( [Firstname] NVARCHAR(100), [Lastname] NVARCHAR(100), [Birthday] datetime, [MaritalStatus] NVARCHAR(10) ) You have nvarchar(20) field in the table that tells the marital status. Obvious problem with this is that what if you create a new value which doesn’t fit into 20 characters? You’ll have to come and alter the table. There are other problems also but I’ll leave those for the reader to think about. The correct way Here’s how I’ve done this in many projects. This model still has one problem but it can be alleviated in the application layer or with CHECK constraints if you like. First I will create a namespace table which tells the name of the enumeration. I will add one row to it too. I’ll write all the indexes and constraints here too. CREATE TABLE [CodeNamespace] ( [Id] INT IDENTITY(1, 1), [Name] NVARCHAR(100) NOT NULL, CONSTRAINT [PK_CodeNamespace] PRIMARY KEY ([Id]), CONSTRAINT [IXQ_CodeNamespace_Name] UNIQUE NONCLUSTERED ([Name]) ) GO INSERT INTO [CodeNamespace] SELECT 'MaritalStatus' GO Then I create a table that holds the actual values and which reference to namespace table in order to group the values under different namespaces. I’ll add couple of rows here too. CREATE TABLE [CodeValue] ( [CodeNamespaceId] INT NOT NULL, [Value] INT NOT NULL, [Description] NVARCHAR(100) NOT NULL, [OrderBy] INT, CONSTRAINT [PK_CodeValue] PRIMARY KEY CLUSTERED ([CodeNamespaceId], [Value]), CONSTRAINT [FK_CodeValue_CodeNamespace] FOREIGN KEY ([CodeNamespaceId]) REFERENCES [CodeNamespace] ([Id]) ) GO -- 1 is the 'MaritalStatus' namespace INSERT INTO [CodeValue] SELECT 1, 1, 'Single', 1 INSERT INTO [CodeValue] SELECT 1, 2, 'In relationship', 2 INSERT INTO [CodeValue] SELECT 1, 3, 'Married', 3 INSERT INTO [CodeValue] SELECT 1, 4, 'Divorced', 4 GO Now there’s four columns in CodeValue table. CodeNamespaceId tells under which namespace values belongs to. Value tells the enumeration value which is used in Person table (I’ll show how this is done below). Description tells what the value means. You can use this, for example, column in UI’s combo box. OrderBy tells if the values needs to be ordered in some way when displayed in the UI. And here’s the Person table again now with correct columns. I’ll add one row here to show how enumerations are to be used. CREATE TABLE [dbo].[Person] ( [Firstname] NVARCHAR(100), [Lastname] NVARCHAR(100), [Birthday] datetime, [MaritalStatus] INT ) GO INSERT INTO [Person] SELECT 'Marko', 'Parkkola', '1977-03-04', 3 GO Now I said earlier that there is one problem with this. MaritalStatus column doesn’t have any database enforced relationship to the CodeValue table so you can enter any value you like into this field. I’ve solved this problem in the application layer by selecting all the values from the CodeValue table and put them into a combobox / dropdownlist (with Value field as value and Description as text) so the end user can’t enter any illegal values; and of course I’ll check the entered value in data access layer also. I said in the “The wrong way” section that there is one benefit to it. In fact, you can have the same benefit here by using a simple view, which I schema bound so you can even index it if you like. CREATE VIEW [dbo].[Person_v] WITH SCHEMABINDING AS SELECT p.[Firstname], p.[Lastname], p.[BirthDay], c.[Description] MaritalStatus FROM [dbo].[Person] p JOIN [dbo].[CodeValue] c ON p.[MaritalStatus] = c.[Value] JOIN [dbo].[CodeNamespace] n ON n.[Id] = c.[CodeNamespaceId] AND n.[Name] = 'MaritalStatus' GO -- Select from View SELECT * FROM [dbo].[Person_v] GO This is excellent write up byMarko Parkkola. Do you have this kind of design setup at your organization? Let us know your opinion. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Best Practices, Database, DBA, Readers Contribution, Software Development, SQL, SQL Authority, SQL Documentation, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • A way for an Upstart event to be sent whenever ecryptfs homedir mounted/unmounted?

    - by David Olivier
    I have an encrypted homedir (ecryptfs) and I'm wanting to run a private mysql daemon with the database files in my homedir. The daemon should be started whenever the homedir is mounted, and stopped before the homedir is unmounted. It seems I have to write an Upstart script, which doesn't seem too hard; the problem is triggering it. Is there already any Upstart event that is sent on these occasions? Or must I insert an "initctl emit" somewhere? Where? It seems the encrypted homedir is mounted whenever I either open my GUI session or ssh to my account. Is there a common place in these two processes where I might insert code? (I don't want to patch and compile any C code, just insert maybe a few lines somewere.) David

    Read the article

< Previous Page | 64 65 66 67 68 69 70 71 72 73 74 75  | Next Page >