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  • Google maps API V3 code to V2 help.

    - by abemonkey
    I've started working on a project to inject markers into a map with jQuery by looping through rows on a table in the page. After getting it working I realized that I was accessing the V3 API and using V3 syntax. I've been beating my head against a wall trying to get this working in google maps API V2. If someone could please take a look at my code and help that would be great! Thanks! You can see my little test in action at www.axtsweapons.com/maptest.html. Here is the JS code: <script type="text/javascript"> $(function() { var latlng = new google.maps.LatLng(45.440000,-122.630000); var settings = { zoom: 12, center: latlng, disableDefaultUI: false, mapTypeControl:false, mapTypeId: google.maps.MapTypeId.ROADMAP }; var map = new google.maps.Map(document.getElementById("map_canvas"), settings); $('tr').each(function(i) { var the_marker = new google.maps.Marker({ title: $(this).find('.views-field-title').text(), map: map, clickable: true, position: new google.maps.LatLng( parseFloat($(this).find('.views-field-latitude').text()), parseFloat($(this).find('.views-field-longitude').text()) ) }); var bounds = new google.maps.LatLngBounds(); var infowindow = new google.maps.InfoWindow({ content: $(this).find('.views-field-title').text() + $(this).find('.adr').text() }); new google.maps.event.addListener(the_marker, 'click', function() { infowindow.close(); infowindow.open(map, the_marker); }); }); }); </script>

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  • Asp.net mvc 2 .net 4.0 error when View model type is Tuple with more than 4 items

    - by Bojan
    When I create strongly typed View in Asp.net mvc 2, .net 4.0 with model type Tuple I get error when Tuple have more than 4 items example 1: type of view is Tuple<string, string, string, string> (4-tuple) and everything works fine view: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/WebUI.Master" Inherits="System.Web.Mvc.ViewPage<Tuple<string, string, string, string>>" %> controller: var tuple = Tuple.Create("a", "b", "c", "d"); return View(tuple); example 2: type of view is Tuple<string, string, string, string, string> (5-tuple) and I have this error: Compiler Error Message: CS1003: Syntax error, '>' expected view: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/WebUI.Master" Inherits="System.Web.Mvc.ViewPage<Tuple<string, string, string, string, string>>" %> controller: var tuple = Tuple.Create("a", "b", "c", "d", "e"); return View(tuple); example 3 if my view model is of type dynamic I can use both 4-tuple and 5-tuple and there is no error on page view: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/WebUI.Master" Inherits="System.Web.Mvc.ViewPage<dynamic>" %> controller: dynamic model = new ExpandoObject(); model.tuple = Tuple.Create("a", "b", "c", "d"); return View(model); or view: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/WebUI.Master" Inherits="System.Web.Mvc.ViewPage<dynamic>" %> controller: dynamic model = new ExpandoObject(); model.tuple = Tuple.Create("a", "b", "c", "d", "e"); return View(model); Even if I have something like Tuple<string, Tuple<string, string, string>, string> 3-tuple and one of the items is also a tuple and sum of items in all tuples is more than 4 I get the same error, Tuple<string, Tuple<string, string>, string> works fine

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  • File Uploading In Google Application Engine Using Django

    - by Ayush
    I am using gae with django. I have an project named MusicSite with following url mapping- urls.py from django.conf.urls.defaults import * from MusicSite.views import MainHandler from MusicSite.views import UploadHandler from MusicSite.views import ServeHandler urlpatterns = patterns('',(r'^start/', MainHandler), (r'^upload/', UploadHandler), (r'^/serve/([^/]+)?', ServeHandler), ) There is an application MusicSite inside MusicFun with the following codes- views.py import os import urllib from google.appengine.ext import blobstore from google.appengine.ext import webapp from google.appengine.ext.webapp import blobstore_handlers from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app def MainHandler(request): response=HttpResponse() upload_url = blobstore.create_upload_url('http://localhost: 8000/upload/') response.write('') response.write('' % upload_url) response.write("""Upload File: """) return HttpResponse(response) def UploadHandler(request): upload_files=request.FILES['file'] blob_info = upload_files[0] response.redirect('http://localhost:8000/serve/%s' % blob_info.key()) class ServeHandler(blobstore_handlers.BlobstoreDownloadHandler): def get(self, resource): resource = str(urllib.unquote(resource)) blob_info = blobstore.BlobInfo.get(resource) self.send_blob(blob_info) now whenever a upload a file using /start and click Submit i am taken to a blank page with the following url- localhost:8000/_ah/upload/ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgHDA These random alphabets keep varying but the result is same. A blank page after every upload. Somebody please help. The server responses are as below- INFO:root:"GET /start/ HTTP/1.1" 200 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 - INFO:root:Internal redirection to http://localhost:8000/upload/ INFO:root:Upload handler returned 500 ERROR:root:Invalid upload handler response. Only 301, 302 and 303 statuses are permitted and it may not have a content body. INFO:root:"POST /_ah/upload/ ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgCDA HTTP/1.1" 500 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 -

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  • Product Catalog Schema design

    - by FlySwat
    I'm building a proof of concept schema for a product catalog to possibly replace a very aging and crufty one we use. In our business, we sell both physical materials and services (one time and reoccurring charges). The current catalog schema has each distinct category broken out into individual tables, while this is nicely normalized and performs well, it is fairly difficult to extend. Adding a new attribute to a particular product involves changing the table schema and backpopulating old data. An idea I've been toying with has been something along the line of a base set of entity tables in 3rd normal form, these will contain the facts that are common among ALL products. Then, I'd like to build an Attribute-Entity-Value schema that allows each entity type to be extended in a flexible way using just data and no schema changes. Finally, I'd like to denormalize this data model into materialized views for each individual entity type. This views are what the application would access. We also have many tables that contain business rules and compatibility rules. These would join against the base entity tables instead of the views. My big concerns here are: Performance - Attribute-Entity-Value schemas are flexible, but typically perform poorly, should I be concerned? More Performance - Denormalizing using materialized views may have some risks, I'm not positive on this yet. Complexity - While this schema is flexible and maintainable using just data, I worry that the complexity of the design might make future schema changes difficult. For those who have designed product catalogs for large scale enterprises, am I going down the totally wrong path? Is there any good best practice schema design reading available for product catalogs?

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  • iPhone: TableView inside UIScrollview, show vaccillating scrollbars around

    - by karim
    Hi, I have added some table and other vies in a scrollview. scrolling in tables are working fine. But in the parent scrollview, when scrolling, a vacillating vertical scrollbars are shown, sometimes it even come to the middle of the screen. sometime show at the left side of the screen. and not limited to the vertical scrollbar region. When I set tje showsVerticalScrollIndicator = NO, it is not shown. But do you know why the scrollbar is moving around. DashboardView is a subclass of UIScrollView. dashboard=[[DashboardView alloc] initWithFrame:fullScreenRect]; dashboard.contentSize = CGSizeMake(320,700); // must do! dashboard.showsVerticalScrollIndicator = YES; dashboard.bounces = YES; self.view = dashboard; @implementation DashboardView (id)initWithFrame:(CGRect)frame { if (self = [super initWithFrame:frame]) { // Initialization code } return self; } (void)drawRect:(CGRect)rect { // Drawing code } (void) layoutSubviews{ NSArray *views = self.subviews; [UIView beginAnimations:@"CollapseExpand" context:nil]; [UIView setAnimationDuration:0.5]; [UIView setAnimationBeginsFromCurrentState:YES]; [UIView setAnimationCurve:UIViewAnimationCurveEaseIn]; UIView *view = [views objectAtIndex: 0]; CGRect rect = view.frame; for (int i = 1; i < [views count]; i++ ) { view = [views objectAtIndex:i]; view.frame = CGRectMake(rect.origin.x, rect.origin.y + rect.size.height, view.frame.size.width, view.frame.size.height); rect = view.frame; } [UIView commitAnimations]; }

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  • On Ruby on Rails, <%= or <% should only matter whether it is show or no show, but why will it give

    - by Jian Lin
    The following code: <div id="vote_form"> <%= form_remote_tag :url => story_votes_path(@story) do %> <%= submit_tag 'shove it' %> <% end %> </div> gives compilation error while if the first <%= is replaced with <%, then everything works. I thought they only differ by "show" or "not show", but why will it actually cause a compile error? The error is: > SyntaxError in Stories#show > > Showing > app/views/stories/show.html.erb where > line #17 raised: > > compile error C:/Software > Projects/ror/shov12/app/views/stories/show.html.erb:17: > syntax error, unexpected ')' ... > story_votes_path(@story) do ).to_s); > @output_buffer.concat ... > ^ C:/Software > Projects/ror/shov12/app/views/stories/show.html.erb:23: > syntax error, unexpected kENSURE, > expecting ')' C:/Software > Projects/ror/shov12/app/views/stories/show.html.erb:25: > syntax error, unexpected kEND, > expecting ')'

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  • has_many, belongs_to and comment forms

    - by Koning Baard XIV
    I'm having two models: Snippet and SnippetComment. These also have their own controllers, as well as views. In /app/views/snippets/show.html.erb I have a form that starts like this: <% form_for(@new_snippet_comment) do |form| %> SnippetComment belongs to one Snippet, and a Snippet belongs to one User. This means that I have this routing: map.resources :users do |user| user.resources :snippets do |snippet| snippet.resources :snippet_comments, :as => "comments" end end So when I submit the SnippetComment form in the SnippetController#show view, this request should be made: POST /users/x/snippets/x/comments HTTP/1.1 (where x is the User's or Snippet's id). The problem is that I don't even get the comment submission form, but rahter this: NoMethodError in Snippets#show Showing app/views/snippets/show.html.erb where line #29 raised: undefined method `snippet_comments_path' for Extracted source (around line #29): 26: <% if current_user %> 27: <h2>Schrijf een nieuwe reactie</h2> 28: 29: <% form_for(@new_snippet_comment) do |form| %> 30: 31: <p> 32: <%= form.text_area :body %> RAILS_ROOT: /Users/jeffatwood/Dev/youjustdontneedmyrealname Application Trace | Framework Trace | Full Trace /Users/jeffatwood/.gem/ruby/1.8/gems/actionpack-2.3.5/lib/action_controller/polymorphic_routes.rb:107:in `__send__' /Users/jeffatwood/.gem/ruby/1.8/gems/actionpack-2.3.5/lib/action_controller/polymorphic_routes.rb:107:in `polymorphic_url' /Users/jeffatwood/.gem/ruby/1.8/gems/actionpack-2.3.5/lib/action_controller/polymorphic_routes.rb:114:in `polymorphic_path' /Users/jeffatwood/.gem/ruby/1.8/gems/actionpack-2.3.5/lib/action_view/helpers/form_helper.rb:298:in `apply_form_for_options!' /Users/jeffatwood/.gem/ruby/1.8/gems/actionpack-2.3.5/lib/action_view/helpers/form_helper.rb:277:in `form_for' /Users/jeffatwood/Dev/youjustdontneedmyrealname/app/views/snippets/show.html.erb:29:in `_run_erb_app47views47snippets47show46html46erb' /Users/jeffatwood/Dev/youjustdontneedmyrealname/app/controllers/snippets_controller.rb:19:in `show' Request Parameters: {"id"=>"1", "user_id"=>"2"} Show session dump Response Headers: {"Content-Type"=>"text/html", "Cache-Control"=>"no-cache"} Can anyone help me with this problem? Thanks

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  • How to display a subview loaded from a separate NIB file

    - by Marcus Netter
    I'm developing a Cocoa desktop application that uses a source list in the style of iTunes: different elements in the source list cause the main content area to display different views. The content area is entirely filled with a (vertical) NSSplitView; on the left is an NSOutlineView source list. When the user selects an item on the left, the relevant view appears on the right side of the splitter. I can make it work well enough by putting everything in one NIB file and putting a borderless NSTabView to the right of the splitter; to switch views, I just have to change the selected tab. But putting all the views in one NIB is bad practice, so I'm trying to move each of the subviews into their own NIB files. I have a pretty good idea of most of this process — I've created an NSViewController subclass for each of these views (EntityDetailViewController, GroupDetailViewController, and so on), set the File's Owner of each new NIB to the relevant controller class, set the view connection in each NIB, and reworked the bindings. What I don't know is how to actually change which subview is being shown on screen. I've tried using the default generic NSView on the right side and sending it addSubview: messages; I've tried connecting to it as the first subview and calling NSView *newSubview = /* get subview from the new subview controller */ [[subview superview] replaceSubview:subview with:newSubview]; [self setSubview:newSubview]; But everything just leaves the space blank. How do I display a subview loaded from a separate NIB?

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  • How to troubleshoot PHP session file empty issue?

    - by Morgan Cheng
    I have a very simple test page for PHP session. <?php session_start(); if (isset($_SESSIONS['views'])) { $_SESSIONS['views'] = $_SESSIONS['pv'] + 1; } else { $_SESSIONS['views'] = 0; } var_dump($_SESSIONS); ?> After refreshing the page, it always show array 'views' => int 0 The environment is XAMPP 1.7.3. I checked phpInfo(). The session is enabled. Session Support enabled Registered save handlers files user sqlite Registered serializer handlers php php_binary wddx Directive Local Value Master Value session.auto_start Off Off session.bug_compat_42 On On When the page is accessed, there is session file sess_lnrk7ttpai8187v9q6iok74p20 created in my "D:\xampp\tmp" folder. But the content is empty. With Firebug, I can see cookies about the session. Cookie PHPSESSID=lnrk7ttpai8187v9q6iok74p20 It seems session data is not flushed to files. Is there any way or direction to trouble shoot this issue? Thanks.

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  • TeamCity output artifacts not published to IIS7 folder

    - by clausas
    I am trying to set up TeamCity to build and deploy an ASP.NET MVC application. I have the setup running successfully on other servers using TeamCity 4.5, but the new server is running TeamCity 6, and I am having trouble getting it to work as expected. TeamCity manages to get the files from source control, and the project (Visual Studio Solution 2008 set to "Build") builds and outputs the necessary files as expected. The problem seems to be with my artifact paths, as the output files are not copied to the website folder. My solution consists of dozen projects, of which the "Web" project is the interesting one in this case. The build checkout directory is C:\TeamCity\buildAgent\work\7da320cebf0ee541, and the "Web"-project is found in C:\TeamCity\buildAgent\work\7da320cebf0ee541\Web I have set up my build configuration with the following artifact paths (relative from checkout directory to the folder containing the website): Web/bin=>../../../../inetpub/wwwroot/staging/bin Web/Content=>../../../../inetpub/wwwroot/staging/Content Web/Views=>../../../../inetpub/wwwroot/staging/Views Web/Media=>../../../../inetpub/wwwroot/staging/Media Web/*.aspx=>../../../../inetpub/wwwroot/staging Web/*.asax=>../../../../inetpub/wwwroot/staging (I've tried with more ../ just in case, but it didn't make a difference). This is the output I get from the log [19:35:29]: Publishing artifacts (1s) [19:35:29]: [Publishing artifacts] Paths to publish: [Web/bin=../../../../inetpub/wwwroot/staging/bin, Web/Content=../../../../inetpub/wwwroot/staging/Content, Web/obj=../../../../inetpub/wwwroot/staging/obj, Web/Views=../../../../inetpub/wwwroot/staging/Views, Web/Media=../../../../inetpub/wwwroot/staging/Media, Web/.aspx=../../../../inetpub/wwwroot/staging, Web/.asax=../../../../inetpub/wwwroot/staging, teamcity-info.xml] [19:35:30]: [Publishing artifacts] Sending files [19:35:32]: Build finished Logs from some of the other servers running TeamCity 4.5 uses a different format, with a line for each of the artifacts being published, I'm not sure if this is relevant or only due to a different logging format. Everything seems to be working, but no files are put in my website folder after a build, am I missing something here? Any help will be much appreciated :)

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  • Core Data: Overkill for simple, static UITableView-based iPhone App?

    - by David Foster
    Hello! I have a rather simple iPhone app consisting of numerous views containing a single, grouped table view. These views are held together in navigation controllers which are grouped in a tab bar. Simple stuff. My table views do little more than list text (like "Dog", "Cat" and "Weasel") and this data is being served from a collection of plists. It's perhaps worth mentioning too that these tables are 'static' in the sense that their data is pre-determined and will only ever be amended—and if so, very rarely indeed—by the developer (in this case, moi). This rudimentary approach has reached its limits though, and I think I'm going to need something a bit more relational. I have worked a tad with Core Data in the past, but only with apps whose data is determined by user input. I have four closely related questions: Is Core Data overkill for an app consisting mainly of a selection of simple table views? Do you recommend using Core Data to manage data which is predetermine and extremely unlikely to ever change? Can one lock Core Data down so that its data can't change, thereby relinquishing my responsibility as the developer to handle the editing and saving of the managed object context? How do I go about giving Core Data my predetermined data, and in a format I know that it can work with? Thanks a bunch guys.

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  • django: How to make one form from multiple models containing foreignkeys

    - by Tim
    I am trying to make a form on one page that uses multiple models. The models reference each other. I am having trouble getting the form to validate because I cant figure out how to get the id of two of the models used in the form into the form to validate it. I used a hidden key in the template but I cant figure out how to make it work in the views My code is below: views: def the_view(request, a_id,): if request.method == 'POST': b_form= BForm(request.POST) c_form =CForm(request.POST) print "post" if b_form.is_valid() and c_form.is_valid(): print "valid" b_form.save() c_form.save() return HttpResponseRedirect(reverse('myproj.pro.views.this_page')) else: b_form= BForm() c_form = CForm() b_ide = B.objects.get(pk=request.b_id) id_of_a = A.objects.get(pk=a_id) return render_to_response('myproj/a/c.html', {'b_form':b_form, 'c_form':c_form, 'id_of_a':id_of_a, 'b_id':b_ide }) models class A(models.Model): name = models.CharField(max_length=256, null=True, blank=True) classe = models.CharField(max_length=256, null=True, blank=True) def __str__(self): return self.name class B(models.Model): aid = models.ForeignKey(A, null=True, blank=True) number = models.IntegerField(max_length=1000) other_number = models.IntegerField(max_length=1000) class C(models.Model): bid = models.ForeignKey(B, null=False, blank=False) field_name = models.CharField(max_length=15) field_value = models.CharField(max_length=256, null=True, blank=True) forms from mappamundi.mappa.models import A, B, C class BForm(forms.ModelForm): class Meta: model = B exclude = ('aid',) class CForm(forms.ModelForm): class Meta: model = C exclude = ('bid',) B has a foreign key reference to A, C has a foreign key reference to B. Since the models are related, I want to have the forms for them on one page, 1 submit button. Since I need to fill out fields for the forms for B and C & I dont want to select the id of B from a drop down list, I need to somehow get the id of the B form into the form so it will validate. I have a hidden field in the template, I just need to figure how to do it in the views

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  • Webfaction apache + mod_wsgi + django configuration issue

    - by Dmitry Guyvoronsky
    A problem that I stumbled upon recently, and, even though I solved it, I would like to hear your opinion of what correct/simple/adopted solution would be. I'm developing website using Django + python. When I run it on local machine with "python manage.py runserver", local address is http://127.0.0.1:8000/ by default. However, on production server my app has other url, with path - like "http://server.name/myproj/" I need to generate and use permanent urls. If I'm using {% url view params %}, I'm getting paths that are relative to / , since my urls.py contains this urlpatterns = patterns('', (r'^(\d+)?$', 'myproj.myapp.views.index'), (r'^img/(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT + '/img' }), (r'^css/(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT + '/css' }), ) So far, I see 2 solutions: modify urls.py, include '/myproj/' in case of production run use request.build_absolute_uri() for creating link in views.py or pass some variable with 'hostname:port/path' in templates Are there prettier ways to deal with this problem? Thank you. Update: Well, the problem seems to be not in django, but in webfaction way to configure wsgi. Apache configuration for application with URL "hostname.com/myapp" contains the following line WSGIScriptAlias / /home/dreamiurg/webapps/pinfont/myproject.wsgi So, SCRIPT_NAME is empty, and the only solution I see is to get to mod_python or serve my application from root. Any ideas?

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  • How can I shared controller logic in ASP.NET MVC for 2 controllers, where they are overriden

    - by AbeP
    Hello, I am trying to implement user-friendly URLS, while keeping the existing routes, and was able to do so using the ActionName tag on top of my controller (http://stackoverflow.com/questions/436866/can-you-overload-controller-methods-in-asp-net-mvc) I have 2 controllers: ActionName("UserFriendlyProjectIndex")] public ActionResult Index(string projectName) { ... } public ActionResult Index(long id) { ... } Basically, what I am trying to do is I store the user-friendly URL in the database for each project. If the user enters the URL /Project/TopSecretProject/, the action UserFriendlyProjectIndex gets called. I do a database lookup and if everything checks out, I want to apply the exact same logic that is used in the Index action. I am basically trying to avoid writing duplicate code. I know I can separate the common logic into another method, but I wanted to see if there is a built-in way of doing this in ASP.NET MVC. Any suggestions? I tried the following and I go the View could not be found error message: [ActionName("UserFriendlyProjectIndex")] public ActionResult Index(string projectName) { var filteredProjectName = projectName.EscapeString().Trim(); if (string.IsNullOrEmpty(filteredProjectName)) return RedirectToAction("PageNotFound", "Error"); using (var db = new PIMPEntities()) { var project = db.Project.Where(p => p.UserFriendlyUrl == filteredProjectName).FirstOrDefault(); if (project == null) return RedirectToAction("PageNotFound", "Error"); return View(Index(project.ProjectId)); } } Here's the error message: The view 'UserFriendlyProjectIndex' or its master could not be found. The following locations were searched: ~/Views/Project/UserFriendlyProjectIndex.aspx ~/Views/Project/UserFriendlyProjectIndex.ascx ~/Views/Shared/UserFriendlyProjectIndex.aspx ~/Views/Shared/UserFriendlyProjectIndex.ascx Project\UserFriendlyProjectIndex.spark Shared\UserFriendlyProjectIndex.spark I am using the SparkViewEngine as the view engine and LINQ-to-Entities, if that helps. thank you!

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  • help in selecting a row in a tableview and pushing that row into anotherview? sturgling on this sinc

    - by Madhu
    Hi, I have a list of about 5 items in a tableview which I bought them from a database and now when i am trying to push each of them into different views in DidSelectRow() what I am seeing is it is showing me all the views in all the categories.... here is the code I have written.... Here is the code written in cell for row at indexpath: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } BeautyQuotes *bQuote = (BeautyQuotes*)[mBeautyQ objectAtIndex:indexPath.row]; cell.textLabel.text = bQuote.qBeauty; [cell setAccessoryType:UITableViewCellAccessoryDisclosureIndicator] ; return cell; and in didselectrow() i have written this code: id count1 = [mBeautyQ count]; while (count1--) { object = [mBeautyQ objectAtIndex:count1]; } [mBeautyQ release]; if([[object objectAtIndex:indexPath.row] isEqual : @"Beauty Quotes"]){ [tableView deselectRowAtIndexPath:indexPath animated:NO]; BeautysubViewController *subBeauty = [[BeautysubViewController alloc] initWithNibName:@"BeautysubViewController" bundle:nil]; //subBeauty.selected =[regions objectAtIndex:indexPath.row];(this is not working) [subBeauty setTitle:@"Beauty Quotes"]; NSLog(@"it is about push beauty subview controller"); [self.navigationController pushViewController:subBeauty animated:YES]; [subBeauty release]; } in this way i am pusing all the rows in to different views....but when I am pushing this into beautyquotes it is showing me all other views along with this.... struggling on this a lot please help me in dealing with this....

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  • Correct way to switch between UIView with ARC. My way leads to memory leaks :( (iOS)

    - by Andrei Golubev
    i use xcode 4.4 with ARC on.. I have dynamically created UIViews in the ViewController.m: UIView*myviews[10]; Then in the - (void)viewDidLoad function i fill each of it with pictures i need myviews[viewIndex] = [[UIView alloc]initWithFrame:myrec]; UIImage *testImg; UIImageView * testImgView; testImg = [UIImage imageNamed:[NSString stringWithFormat:@"imgarray%d.png", viewIndex]; testImgView.image = testImg; viewindex++; So all seems to be fine, when i want to jump from one view to another i do with two buttons next: [self.view addSubview:views[viewIndex]]; CATransition *animation = [CATransition animation]; [animation setDelegate:self]; [animation setDuration:1.0f]; [animation setType:@"rippleEffect"]; [animation setSubtype:kCATransitionFromTop]; //[animation setTimingFunction:[CAMediaTimingFunction functionWithName:kCAMediaTimingFunctionEaseInEaseOut]]; [self.view.layer addAnimation:animation forKey:@"transitionViewAnimation"]; Nothing seems to be bad, but the memory consumption grows with huge speed when i switch between views.. and then i get low memory warning or sometimes application will just crash. I have tried to use UIViewController array and was switching between the controllers: nothing changes, the memory low warning is what i end up with.. Maybe i need to clean the memory somehow? But how? ARC does not allow to use release and so on.. last what i have tried (sorry, maybe not very professional) before to add new subview is this NSArray *viewsToRemove = [self.view subviews]; for (UIView *views in viewsToRemove) { [views removeFromSuperview]; } But this does not help either.. Please don't judge too strong, i am still new to iOS and Objective-c..

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  • django multiprocess problem

    - by iKiR
    I have django application, running under lighttpd via fastcgi. FCGI running script looks like: python manage.py runfcgi socket=<path>/main.socket method=prefork \ pidfile=<path>/server.pid \ minspare=5 maxspare=10 maxchildren=10 maxrequests=500 \ I use SQLite. So I have 10 proccess, which all work with the same DB. Next I have 2 views: def view1(request) ... obj = MyModel.objects.get_or_create(id=1) obj.param1 = <some value> obj.save () def view2(request) ... obj = MyModel.objects.get_or_create(id=1) obj.param2 = <some value> obj.save () And If this views are executed in two different threads sometimes I get MyModel instance in DB with id=1 and updated either param1 or param2 (BUT not both) - it depends on which process was the first. (of course in real life id changes, but sometimes 2 processes execute these two views with same id) The question is: What should I do to get instance with updated param1 and param2? I need something for merging changes in different processes. One decision is create interprocess lock object but in this case I will get sequence executing views and they will not be able to be executed simultaneously, so I ask help

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  • Qt: QStackedWidget solution

    - by Martin
    I'm building a Qt application that have about 30 different views (QWidgets). My idea is to use a QStackedWidget to make it easy to switch between the different views in the application. I have two different solutions of how to implement this and use as little memory as possible when the user navigates through the application. Solution 1: Everytime I need to show a view I check if it is already in the stack. (The user might open the same view many times, maybe a view showing an item from a database). If the view is in the stack already it doesn't need to be created again and I can just show the view. The good thing with this solution is that I reuse the views (widgets) so they only need to be created once. This is good as the UI and other stuff should look the same everytime the user show a view, so why not reuse it? The problem with this solution is that every view has childrens. Maybe an object, a QList with objects or other things. A good thing with Qt is that you can use the parent-children mechanism so that the children will be deleted when the parent is deleted. As I never delete the parent (view) I need to handle this myself as the children might need to be deleted from different times when the view is shown. (Maybe the view show a list with objects and the list should be updated from a database each time the view is shown.) Solution 2: Everytime I need to show a QWidget I create a new one and show it. When it is not shown anymore, I delete it from memory. This is a quite easy solution. And as I delete the views when they are not shown both the view and it's children should be deleted from memory so it shouldn't increase memory, am I right? Which one of the solutions do you recommend?

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  • Iteratively creating multiple file input fields in Rails

    - by David
    I have a column of product views in a database (e.g. top, bottom, front, back). I'm trying to generate a series of file inputs to allow the user to upload an image for each view. This is the result I'm after: ... <label>Top</label> <input type="file" name="image[Top]"><br> <label>Bottom</label> <input type="file" name="image[Bottom]"><br> <label>Front</label> <input type="file" name="image[Front']"><br> ... This is what I'm trying: <%= views = View.order('name ASC').all.map { |view| [view.name, view.id] } %> <%= views.each { |view| label(view); file_field('image', view) } %> However, all this does is print out the views array a couple of times. Hopefully you Rails experts can point me in the right direction. (I apologize in advance if I'm butchering Ruby.)

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  • Set bounds for markers generated by jQuery table loop?

    - by abemonkey
    I have some jQuery code that goes through a table of location results and puts corresponding pins on a map. I am having trouble figuring out how to set the bounds so that when it goes through the loop and generates the markers on the map that it zooms and pans to fit the markers in the view. I've tried implementing code from some similar questions on this site but nothing seems to be working. Please let me know what code I should be using and where the heck I should put it in my script: $(function() { var latlng = new google.maps.LatLng(44, 44); var settings = { zoom: 15, center: latlng, disableDefaultUI: false, mapTypeId: google.maps.MapTypeId.ROADMAP }; var map = new google.maps.Map(document.getElementById("map_canvas"), settings); $('tr').each(function(i) { var the_marker = new google.maps.Marker({ title: $(this).find('.views-field-title').text(), map: map, clickable: true, position: new google.maps.LatLng( parseFloat($(this).find('.views-field-latitude').text()), parseFloat($(this).find('.views-field-longitude').text()) ) }); var infowindow = new google.maps.InfoWindow({ content: $(this).find('.views-field-title').text() + $(this).find('.adr').text() }); new google.maps.event.addListener(the_marker, 'click', function() { infowindow.open(map, the_marker); }); }); }); `

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  • How do I use Haml in a view in my new plugin?

    - by Eric
    I'm creating a new plugin for a jruby on rails application that will eventually be turned into a gem. Inside my plugin I have controllers, helpers and views. For my views I'd like to use Haml. The problem is that I can't seem to get it to recognize that they are haml templates. Is it even possible to do this? Is there a way for a plugin to have Haml as a dependency for its view? And by that I mean, I intend for the plugin that I'm creating to have a view created by the plugin, that can be used by the application developer. for example: vendor/ plugins/ my_plugin/ lib/ app/ views/ my_plugin_demo/ index.haml.html controllers/ my_plugin_demo_controller.rb helpers/ In my plugin's init.rb, I tried: require 'my_plugin' require 'haml' #doesn't seem to make a difference :( but that didn't seem to make any difference. Has anybody had any experience with this? I can't seem to find any documentation on how to make this work. Are plugin views restricted to .erb templates?

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  • Android - update widget text

    - by david
    Hi, i have 2 questions about widgets update I have 2 buttons and i need to change one button text when i press the other one, how can i do this? The first time i open the widget it calls the onUpdate method, but it never calls it again. I need to update the widget every 2 seconds and i have this line in the xml. android:updatePeriodMillis="2000" Do i need a service or should it works just with the updatePeriodMillis tag? onUpdate method RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.newswidget); Intent intent = new Intent(context, DetalleConsulta.class); intent.putExtra(DetalleConsulta.CONSULTA_ID_NAME, "3"); PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, intent, 0); views.setOnClickPendingIntent(R.id.btNews, pendingIntent); /* Inicializa variables para llamar el controlador */ this.imei = ((TelephonyManager)context.getSystemService(Context.TELEPHONY_SERVICE)).getDeviceId(); this.controlador = new Controlador(this.imei); try { this.respuestas = this.controlador.recuperarNuevasRespuestas(); if(this.respuestas != null &amp;&amp; this.respuestas.size() &gt; 0){ Iterator&lt;Consulta&gt; iterRespuestas = this.respuestas.iterator(); views.setTextViewText(R.id.btNews, ((Consulta)iterRespuestas.next()).getRespuesta()); } } catch (PersistenciaException e) { //TODO manejar error } appWidgetManager.updateAppWidget(appWidgetIds, views); thx a lot!!!

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  • Refetching a previously visited page

    - by user613665
    All, I am having a field day with page refetching. Any help or pointer will be greatly appreciated!! The behavior is a bit specific to mobile browser. Problem: I have two pages and created a shortcut link to pg#1 in the home page. Through a form submit button, user is taken from pg#1 to pg#2. All that is working fine. Now once I am on pg#2. I will leave the browser and click the shortcut later. The browser will stay on pg#2 and won't go to pg#1 even though the path in URLS is different between the two views. It is almost like Django decides that since I have already visited view#1, it doesn't need to fetch it again. This problem or behavior doesn't happen if I move the same code that handle the two views and the templates to a bare bone test project. Setup: I am using django-registration, context session. I am not using any HTML caching tag. I already have DEBUG turned on in my settings.py. Are there other ways that I can tell what the server is doing. Thanks in advance. pdxMobile Update: Here is the code snippets. def sendmsg(request): if request.method =='POST': messages.add_message(request, messages.INFO, "Hello world") return redirect ('rcvmsg') return render_to_response('sendMsg.html',RequestContext(request)) def rcvmsg(request): '''view that receives the msg.''' printMsg ='Didnt get a message' if messages: thisMsg = messages.get_messages(request) for rcvMsg in thisMsg: printMsg = rcvMsg return render_to_response('rcvMsg.html',{'print_msg':printMsg},RequestContext(request)) URL: url(r'^rcvMsg/','mydomain.mainApp.views.rcvmsg',name='rcvmsg'), (r'^sendMsg/code','mydomain.mainApp.views.sendmsg'),

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  • Dynamically adding custom view to RemoteViews

    - by Naidu
    Could any help me to do this?My code is like: public CustomClass extends View { //uses ondraw() to do something } For displaying my custom view on HomeScreen i created a class to extend Broadcast Receiver public class customAppWidgetProvider extends BroadcastReceiver { public void onReceive(Context context, Intent intent) { String action = intent.getAction(); if (AppWidgetManager.ACTION_APPWIDGET_UPDATE.equals(action)) { RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.main); //Here i want to create my custom view class object and i want to add this view to linear layout in main.xml CustomClass object = new CustomClass(context) ; LinearLayout layout = new LinearLayout(context) ; layout.setLayoutParameters(new LayoutParameters(LayoutParams.WRAP_CONTENT,LayoutParams.WRAP_CONTENT)); layout.addView(object); views.addview(R.id.linearlayout, (ViewGroup) layout) ; views.setOnClickPendingIntent(R.id.analog_appwidget, PendingIntent.getActivity(context, 0, new Intent(context, AlarmClock.class), PendingIntent.FLAG_CANCEL_CURRENT)); int[] appWidgetIds = intent.getIntArrayExtra( AppWidgetManager.EXTRA_APPWIDGET_IDS); AppWidgetManager gm = AppWidgetManager.getInstance(context); gm.updateAppWidget(appWidgetIds, views); } } } But adding viewgroup to RemoteView reference is not working... above main.xml contains only LinearLayout.I want to add custom view object to it.But after running this not showing anything on screen.. please help me to do this.Thanks in Advance.

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  • How To - Guide to Importing Data from a MySQL Database to Excel using MySQL for Excel

    - by Javier Treviño
    Fetching data from a database to then get it into an Excel spreadsheet to do analysis, reporting, transforming, sharing, etc. is a very common task among users. There are several ways to extract data from a MySQL database to then import it to Excel; for example you can use the MySQL Connector/ODBC to configure an ODBC connection to a MySQL database, then in Excel use the Data Connection Wizard to select the database and table from which you want to extract data from, then specify what worksheet you want to put the data into.  Another way is to somehow dump a comma delimited text file with the data from a MySQL table (using the MySQL Command Line Client, MySQL Workbench, etc.) to then in Excel open the file using the Text Import Wizard to attempt to correctly split the data in columns. These methods are fine, but involve some degree of technical knowledge to make the magic happen and involve repeating several steps each time data needs to be imported from a MySQL table to an Excel spreadsheet. So, can this be done in an easier and faster way? With MySQL for Excel you can. MySQL for Excel features an Import MySQL Data action where you can import data from a MySQL Table, View or Stored Procedure literally with a few clicks within Excel.  Following is a quick guide describing how to import data using MySQL for Excel. This guide assumes you already have a working MySQL Server instance, Microsoft Office Excel 2007 or 2010 and MySQL for Excel installed. 1. Opening MySQL for Excel Being an Excel Add-In, MySQL for Excel is opened from within Excel, so to use it open Excel, go to the Data tab located in the Ribbon and click MySQL for Excel at the far right of the Ribbon. 2. Creating a MySQL Connection (may be optional) If you have MySQL Workbench installed you will automatically see the same connections that you can see in MySQL Workbench, so you can use any of those and there may be no need to create a new connection. If you want to create a new connection (which normally you will do only once), in the Welcome Panel click New Connection, which opens the Setup New Connection dialog. Here you only need to give your new connection a distinctive Connection Name, specify the Hostname (or IP address) where the MySQL Server instance is running on (if different than localhost), the Port to connect to and the Username for the login. If you wish to test if your setup is good to go, click Test Connection and an information dialog will pop-up stating if the connection is successful or errors were found. 3.Opening a connection to a MySQL Server To open a pre-configured connection to a MySQL Server you just need to double-click it, so the Connection Password dialog is displayed where you enter the password for the login. 4. Selecting a MySQL Schema After opening a connection to a MySQL Server, the Schema Selection Panel is shown, where you can select the Schema that contains the Tables, Views and Stored Procedures you want to work with. To do so, you just need to either double-click the desired Schema or select it and click Next >. 5. Importing data… All previous steps were really the basic minimum needed to drill-down to the DB Object Selection Panel  where you can see the Database Objects (grouped by type: Tables, Views and Procedures in that order) that you want to perform actions against; in the case of this guide, the action of importing data from them. a. From a MySQL Table To import from a Table you just need to select it from the list of Database Objects’ Tables group, after selecting it you will note actions below the list become available; then click Import MySQL Data. The Import Data dialog is displayed; you can see some basic information here like the name of the Excel worksheet the data will be imported to (in the window title), the Table Name, the total Row Count and a 10 row preview of the data meant for the user to see the columns that the table contains and to provide a way to select which columns to import. The Import Data dialog is designed with defaults in place so all data is imported (all rows and all columns) by just clicking Import; this is important to minimize the number of clicks needed to get the job done. After the import is performed you will have the data in the Excel worksheet formatted automatically. If you need to override the defaults in the Import Data dialog to change the columns selected for import or to change the number of imported rows you can easily do so before clicking Import. In the screenshot below the defaults are overridden to import only the first 3 columns and rows 10 – 60 (Limit to 50 Rows and Start with Row 10). If the number of rows to be imported exceeds the maximum number of rows Excel can hold in its worksheet, a warning will be displayed in the dialog, meaning the imported number of rows will be limited by that maximum number (65,535 rows if the worksheet is in Compatibility Mode).  In the screenshot below you can see the Table contains 80,559 rows, but only 65,534 rows will be imported since the first row is used for the column names if the Include Column Names as Headers checkbox is checked. b. From a MySQL View Similar to the way of importing from a Table, to import from a View you just need to select it from the list of Database Objects’ Views group, then click Import MySQL Data. The Import Data dialog is displayed; identically to the way everything looks when importing from a table, the dialog displays the View Name, the total Row Count and the data preview grid. Since Views are really a filtered way to display data from Tables, it is actually as if we are extracting data from a Table; so the Import Data dialog is actually identical for those 2 Database Objects. After the import is performed, the data in the Excel spreadsheet looks like the following screenshot. Note that you can override the defaults in the Import Data dialog in the same way described above for importing data from Tables. Also the Compatibility Mode warning will be displayed if data exceeds the maximum number of rows explained before. c. From a MySQL Procedure Too import from a Procedure you just need to select it from the list of Database Objects’ Procedures group (note you can see Procedures here but not Functions since these return a single value, so by design they are filtered out). After the selection is made, click Import MySQL Data. The Import Data dialog is displayed, but this time you can see it looks different to the one used for Tables and Views.  Given the nature of Store Procedures, they require first that values are supplied for its Parameters and also Procedures can return multiple Result Sets; so the Import Data dialog shows the Procedure Name and the Procedure Parameters in a grid where their values are input. After you supply the Parameter Values click Call. After calling the Procedure, the Result Sets returned by it are displayed at the bottom of the dialog; output parameters and the return value of the Procedure are appended as the last Result Set of the group. You can see each Result Set is displayed as a tab so you can see a preview of the returned data.  You can specify if you want to import the Selected Result Set (default), All Result Sets – Arranged Horizontally or All Result Sets – Arranged Vertically using the Import drop-down list; then click Import. After the import is performed, the data in the Excel spreadsheet looks like the following screenshot.  Note in this example all Result Sets were imported and arranged vertically. As you can see using MySQL for Excel importing data from a MySQL database becomes an easy task that requires very little technical knowledge, so it can be done by any type of user. Hope you enjoyed this guide! Remember that your feedback is very important for us, so drop us a message: MySQL on Windows (this) Blog - https://blogs.oracle.com/MySqlOnWindows/ Forum - http://forums.mysql.com/list.php?172 Facebook - http://www.facebook.com/mysql Cheers!

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