The "correct" way to define an exception in Python without PyLint complaining
- by Evgeny
I'm trying to define my own (very simple) exception class in Python 2.6, but no matter how I do it I get some warning.
First, the simplest way:
class MyException(Exception):
pass
This works, but prints out a warning at runtime: DeprecationWarning: BaseException.message has been deprecated as of Python 2.6 OK, so that's not the way. I then tried:
class MyException(Exception):
def __init__(self, message):
self.message = message
This also works, but PyLint reports a warning: W0231: MyException.__init__: __init__ method from base class 'Exception' is not called. So I tried calling it:
class MyException(Exception):
def __init__(self, message):
super(Exception, self).__init__(message)
self.message = message
This works, too! But now PyLint reports an error: E1003: MyException.__init__: Bad first argument 'Exception' given to super class
How the hell do I do such a simple thing without any warnings?
