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  • Tracking SVN changes through multiple merges

    - by Paul D.
    At work we use a branching strategy where all changes start off in a development branch, then subsequently make their way through one or more integration branches, and finally end up in a release branch. Occasionally (more often than I'd like) I find myself needing to figure out where a particular change originated (which development branch). In this case I have to spend a considerable amount of time playing detective to trace a change backwards through 2-3 merges. Am I missing an easy way to do this?

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  • How to get multiple counts with one SQL query?

    - by Crobzilla
    I am wondering how to write this query. I know this actual syntax is bogus, but it will help you understand what I am wanting. I need it in this format, because it is part of a much bigger query. SELECT distributor_id, COUNT(*) AS TOTAL, COUNT(*) WHERE level = 'exec', COUNT(*) WHERE level = 'personal' I need this all returned in one query. Also, it need to be in one row, so the following won't work: 'SELECT distributor_id, COUNT(*) GROUP BY distributor_id'

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  • Inner join 2 tables one to many 2 where clauses

    - by user2892350
    I'm a relative rookie at this,so please bear with me... I have 2 tables: OrderDetail and OrderMaster...both have a column named SalesOrder. OrderDetail table has multiple rows per unique SalesOrder. OrderMaster table has one row per unique SalesOrder. OrderDetail has a column named LineType. OrderMaster has a column named OrderStatus. I want to select all records from OrderDetail that have a LineType of "1" AND whose matching SalesOrder line in the OrderMaster table has a OrderStatus column value of "4". In plain English, orders with a Status 4 are open and ready to ship, LineType value of 1 means the Detail Line is a product code. How should this query be structured? It's going into VS 2008 (VB). Many thanks in advance!!! Mike

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  • Best way to do one-to-many "JOIN" in CouchDB

    - by mit
    There are CouchDB documents that are list elements: { "type" : "el", "id" : "1", "content" : "first" } { "type" : "el", "id" : "2", "content" : "second" } { "type" : "el", "id" : "3", "content" : "third" } There is one document that defines the list: { "type" : "list", "elements" : ["2","1"] , "id" : "abc123" } As you can see the third element was deleted, it is no longer part of the list. So it must not be part of the result. Now I want a view that returns the content elements including the right order. The result could be: { "content" : ["second", "first"] } In this case the order of the elements is already as it should be. Another possible result: { "content" : [{"content" : "first", "order" : 2},{"content" : "second", "order" : 1}] } I started writing the map function: map = function (doc) { if (doc.type === 'el') { emit(doc.id, {"content" : doc.content}); //emit the id and the content exit; } if (doc.type === 'list') { for ( var i=0, l=doc.elements.length; i<l; ++i ){ emit(doc.elements[i], { "order" : i }); //emit the id and the order } } } This is as far as I can get. Can you correct my mistakes and write a reduce function? Remember that the third document must not be part of the result. Of course you can write a different map function also. But the structure of the documents (one definig element document and an entry document for each entry) cannot be changed.

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  • Filtering with joined tables

    - by viraptor
    I'm trying to get some query performance improved, but the generated query does not look the way I expect it to. The results are retrieved using: query = session.query(SomeModel). options(joinedload_all('foo.bar')). options(joinedload_all('foo.baz')). options(joinedload('quux.other')) What I want to do is filter on the table joined via 'first', but this way doesn't work: query = query.filter(FooModel.address == '1.2.3.4') It results in a clause like this attached to the query: WHERE foos.address = '1.2.3.4' Which doesn't do the filtering in a proper way, since the generated joins attach tables foos_1 and foos_2. If I try that query manually but change the filtering clause to: WHERE foos_1.address = '1.2.3.4' AND foos_2.address = '1.2.3.4' It works fine. The question is of course - how can I achieve this with sqlalchemy itself?

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  • select row from table and substitute a field with one from another column if not null

    - by EarthMind
    I'm trying construct a PostgreSQL query that does the following but so far my efforts have been in vain. Problem: There are two tables: A and B. I'd like to select all columns from table A (having columns: id, name, description) and substitute the "A.name" column with the value of the column "B.title" from table B (having columns: id, table_A_id title, langcode) where B.table_A_id is 5 and B.langcode is "nl" (if there are any rows). I've tried using a CASE and COALESCE() but failed due to my inexperience with both concepts. Thanks in advance.

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  • select row from table and substitute a field with one from another column if it exists

    - by EarthMind
    I'm trying construct a PostgreSQL query that does the following but so far my efforts have been in vain. Problem: There are two tables: A and B. I'd like to select all columns from table A (having columns: id, name, description) and substitute the "A.name" column with the value of the column "B.title" from table B (having columns: id, table_A_id title, langcode) where B.table_A_id is 5 and B.langcode is "nl" (if there are any rows). My attempts: SELECT A.name, case when exists(select title from B where table_A_id = 5 and langcode= 'nl') then B.title else A.name END FROM A, B WHERE A.id = 5 and B.table_A_id = 5 and B.langcode = 'nl' -- second try: SELECT COALESCE(B.title, A.name) as name from A, B where A.id = 5 and B.table_A_id = 5 and exists(select title from B where table_A_id = 5 and langcode= 'nl') I've tried using a CASE and COALESCE() but failed due to my inexperience with both concepts. Thanks in advance.

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  • Oracle join issue

    - by acadia
    Hello, I have 3 tables and I am joining these 2 tables as follows: SELECT EMP.FNAME,EMP.LNAME,EMP.AGE,EMPD.TQ,EMPD.TA,CTY.CITY_NAME FROM EMPLOYEE EMP,EMPLOYEE_DETAIL EMPD, CITY CTY WHERE EMP.EMP_ID=EMPD.EMP_ID AND EMPD_CITY_ID=CTY.CITY_ID I want to display records even if City record is not in CITY table. For eg. if City_ID record for say 10 is not in City table but there is an employee detail record with City_id 10 it should display City_name as null instead of not displaying the record at all. Appreciate your help

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  • SQL OUTER JOIN with NEWID to generate random data for each row

    - by CL4NCY
    Hi, I want to generate some test data so for each row in a table I want to insert 10 random rows in another, see below: INSERT INTO CarFeatures (carID, featureID) SELECT C.ID, F.ID FROM dbo.Cars AS C OUTER APPLY ( SELECT TOP 10 ID FROM dbo.Features ORDER BY NEWID() ) AS F Only trouble is this returns the same values for each row. How do I order them randomly?

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  • Grails many to many using a third 'join' class

    - by andy mccullough
    I read that a m:m relationship often means there is a third class that isn't yet required. So I have m:m on User and Project, and I created a third domain class, ProjectMembership The three domains are as follows (minimized for illustration purposes): User class User { String name static hasMany = [projectMemberships : ProjectMembership] } Project Membership class ProjectMembership { static constraints = { } static belongsTo = [user:User, project:Project] } Project: class Project { String name static hasMany = [projectMemberships : ProjectMembership] static constraints = { } } If I have the ID of the user, how can I get a list of Project objects that they are assigned to?

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  • Ruby On Rails: Ask for Confirmation When Table Entry Associated With Another Is Destroyed

    - by Train Main
    Hi all, I would like some assistance with the following problem: I have a table of groups that is self-associated with itself, so each group is (optionally) linked to another in a hierarchical fashion. I want to write some code that will somehow check before the destruction of a group entry, if it has any children, and ask the user for confirmation, or whether they wish to delete the child groups as well. I've looked at callbacks, but I don't know how to get the confirmation request to the end user in the view, and then get the response back to the model's callback. Thanks

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  • How to coerce type of ActiveRecord attribute returned by :select phrase on joined table?

    - by tribalvibes
    Having trouble with AR 2.3.5, e.g.: users = User.all( :select => "u.id, c.user_id", :from => "users u, connections c", :conditions => ... ) Returns, e.g.: => [#<User id: 1000>] >> users.first.attributes => {"id"=>1000, "user_id"=>"1000"} Note that AR returns the id of the model searched as numeric but the selected user_id of the joined model as a String, although both are int(11) in the database schema. How could I better form this type of query to select columns of tables backing multiple models and retrieving their natural type rather than String ? Seems like AR is punting on this somewhere. How could I coerce the returned types at AR load time and not have to tack .to_i (etc.) onto every post-hoc access?

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  • CakePHP 3-level-deep model associatons

    - by user357452
    Hi, I am relatively new to CakePHP, I am doing fine with the documentation, but I've been trying to find a way out to this problem for weeks and I don't seem to find the solution, I am sure it is easy and maybe even automagicaly doable, but I just don't know how to find it (maybe I don't know the jargon for these kind of things) My model structure is like this: <?php class Trip extends AppModel { var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id' ), 'Start' => array( 'className' => 'Place', 'foreignKey' => 'start_id' ), 'End' => array( 'className' => 'Place', 'foreignKey' => 'end_id' ), 'Transport' => array( 'className' => 'Transport', 'foreignKey' => 'transport_id' ) ); } ?> <?php class Place extends AppModel { var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id' ), 'Country' => array( 'className' => 'Country', 'foreignKey' => 'country_id' ), 'State' => array( 'className' => 'State', 'foreignKey' => 'state_id' ), 'City' => array( 'className' => 'City', 'foreignKey' => 'city_id' ) ); var $hasMany = array( 'PlaceStart' => array( 'className' => 'trip', 'foreignKey' => 'start_id', 'dependent' => false ), 'PlaceEnd' => array( 'className' => 'trip', 'foreignKey' => 'end_id', 'dependent' => false ) ); } ?> <?php class State extends AppModel { var $belongsTo = array( 'Country' => array( 'className' => 'Country', 'foreignKey' => 'country_id', 'conditions' => '', 'fields' => '', 'order' => '' ) ); var $hasMany = array( 'City' => array( 'className' => 'City', 'foreignKey' => 'city_id', 'dependent' => false ) ); } ?> ... and so forth with User, City, Country, and Transport Models. What I am trying to achieve is to get all the information of the whole tree when I search for a Trip. <?php class TripController extends AppController { function index() { debug($this->Trip->find('first')); } } Outputs Array ( [Trip] => Array ( [id] => 6 [created] => 2010-05-04 00:23:59 [user_id] => 4 [start_id] => 2 [end_id] => 1 [title] => My trip [transport_id] => 1 ) [User] => Array ( [id] => 4 [name] => John Doe [email] => [email protected] ) [Start] => Array ( [id] => 2 [user_id] => 4 [country_id] => 1 [state_id] => 1 [city_id] => 1 [direccion] => Lincoln Street ) [End] => Array ( [id] => 1 [user_id] => 4 [country_id] => 1 [state_id] => 1 [city_id] => 4 [address] => Fifth Avenue ) [Transport] => Array ( [id] => 1 [name] => car ) ) Here is the question: How do I get in one query all the information down the tree? I would like to have something like Array ( [Trip] => Array ( [id] => 6 [created] => 2010-05-04 00:23:59 [User] => Array ( [id] => 4 [name] => John Doe [email] => [email protected] ) [Start] => Array ( [id] => 2 [user_id] => 4 [Country] => Array ( [id] => 1 [name] = Spain ) [State] => Array ( [id] => 1 [name] = Barcelona ) [City] => Array ( [id] => 1 [name] = La Floresta ) [address] => Lincoln Street ) [End] => (same as Start) [title] => My trip [Transport] => Array ( [id] => 1 [name] => car ) ) ) Can CakePHP create this kind of data? Not only for $this->Model->find() but also for $this->paginate() as for example: // filter by start if(isset($this->passedArgs['start'])) { //debug('isset '.$this->passedArgs['start']); $start = $this->passedArgs['start']; $this->paginate['conditions'][] = array( 'OR' => array( 'Start.address LIKE' => "%$start%", 'Start.State.name LIKE' => "%$start%", 'Start.City.name LIKE' => "%$start%", 'Start.Country.name LIKE' => "%$start%" ) ); $this->data['Search']['start'] = $start; } It seems like a rough question but I am sure this is extensively done and documented, I'd really appreciate any help. Thanks Cheers Naoise

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  • MySQL Rating system (calculating average from two tables).

    - by MussuR
    I have two tables, videos and videos_ratings. The videos table has an int videoid field (and many others but those fields are not important I think) and many records. The videos_ratings table has 3 int fields: videoid, rating, rated_by which has many records (multiple records for each fields from the videos table) but not for all records from the videos table. Currently I have the following mysql query: SELECT `videos`.*, avg(`videos_ratings`.`vote`) FROM `videos`, `videos_ratings` WHERE `videos_ratings`.`videoid` = `videos`.`videoid` GROUP BY `videos_ratings`.`videoid` ORDER BY RAND() LIMIT 0, 12 It selects all the records from table videos that have a rating in table video_ratings and calculates the average correctly. But what I need is to select all records from the videos table, no matter if there is a rating for that record or not. And if there aren't any records in the videos_ratings table for that particular videos record, the average function should show 0. Hope someone could understand what I want... :) Thanks!

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  • SQL: joining multiples tables into one.

    - by Graveen
    I have 4 tables. r1, r2, r3 and r4. The table columns are the following: rId | rName I want to have, in fine, an unique table - let's call it R. Obviously, R will have the following structure: rTableName | rId | rName I'm looking for a solution, and the more natural for me is to: add a single column to all rX insert this column the table name i'm processing generate SQLs and concatenate them all Although I see exactly how to perform 1 and 3 with batching, editing, etc... (I have only to perform it once and for all), I don't see how to do the point 2: self-getting the tablename to insert into SQL. Have you an idea / or a different way to do that could solve my problem? Note: In fact, there are 250+ rX tables. That's why i can't do this manually. Note2: Precisely, this is with MySQL.

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  • T-SQL Self Join in combination with aggregate function

    - by Nick
    Hi, i have the following table. CREATE TABLE [dbo].[Tree]( [AutoID] [int] IDENTITY(1,1) NOT NULL, [Category] [varchar](10) NULL, [Condition] [varchar](10) NULL, [Description] [varchar](50) NULL, CONSTRAINT [PK_Tree] PRIMARY KEY CLUSTERED ( [AutoID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] ) ON [PRIMARY] GO the data looks like this: INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('1','Alpha','Type 1') INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('1','Alpha','Type 1') INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('2','Alpha','Type 2') INSERT INTO [Test].[dbo].[Tree] ([Category] ,[Condition] ,[Description]) VALUES ('2','Alpha','Type 2') go I try now to do the following: SELECT Category,COUNT(*) as CategoryCount FROM Tree where Condition = 'Alpha' group by Category but i wish also to get the Description for each Element. I tried several subqueries, self joins etc. i always come to the problem that the subquery cannot return more than one record. The problem is caused by a poor database design which i cannot change and i run out of ideas to get this done in a single query ;-(

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  • MySQL Search (Sort by Relevance)

    - by atif089
    Hi guys, Can any one help me how to sort rows by relevance for the following criterion ? tbluser First Name Last Name tbleduc School College University On the search form the user has following fields Name School College University Where School College and University are Optional.. And Name is split into 2 words (other words in middle are omitted), first word is taken as first anme and last word as last name.. Now I would like to implement search based on relevance. Thanks for the help :)

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  • Select in MySQL based on two tables

    - by Deyan
    Hello everyone, first of all I want to apologize for my bad english. So I have two tables. diseases ----------------------------- | ID | NAME | ----------------------------- | 1 | Disease 1 | | 2 | Disease 2 | | 3 | Disease 3 | diseases_symptoms ----------------------------- | DISEASE_ID | SYMPTOM_ID | ----------------------------- | 1 | 1 | | 1 | 2 | | 1 | 3 | | 1 | 4 | | 2 | 1 | | 2 | 2 | I want to select all diseses which have symptoms 1 or 2 and 3 or 4. I've tried: SELECT * FROM diseases_symtoms WHERE (symptoms = '1' OR symptoms = '2') AND (symptoms = '3' OR symptoms = '4') And: SELECT * FROM diseases_symtoms WHERE symptoms IN ('1','2') AND symptoms IN ('3','4') but it is not working.

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  • When to use CTEs to encapsulate sub-results, and when to let the RDBMS worry about massive joins.

    - by IanC
    This is a SQL theory question. I can provide an example, but I don't think it's needed to make my point. Anyone experienced with SQL will immediately know what I'm talking about. Usually we use joins to minimize the number of records due to matching the left and right rows. However, under certain conditions, joining tables cause a multiplication of results where the result is all permutations of the left and right records. I have a database which has 3 or 4 such joins. This turns what would be a few records into a multitude. My concern is that the tables will be large in production, so the number of these joined rows will be immense. Further, heavy math is performed on each row, and the idea of performing math on duplicate rows is enough to make anyone shudder. I have two questions. The first is, is this something I should care about, or will SQL Server intelligently realize these rows are all duplicates and optimize all processing accordingly? The second is, is there any advantage to grouping each part of the query so as to get only the distinct values going into the next part of the query, using something like: WITH t1 AS ( SELECT DISTINCT... [or GROUP BY] ), t2 AS ( SELECT DISTINCT... ), t3 AS ( SELECT DISTINCT... ) SELECT... I have often seen the use of DISTINCT applied to subqueries. There is obviously a reason for doing this. However, I'm talking about something a little different and perhaps more subtle and tricky.

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  • SQL Query, return value from table with no join

    - by jdenomme19
    I'm hoping for an idea on the best way to approach what I'm trying to do. I have a table with a list of transactions. Each transactions has a PostDate in DateTime format. I have another table holding the fiscal period values. This table has the following columns; FiscalYear, FiscalMonth, StartDate, EndDate. I'm trying to write a query that will return all values from my transactions table, along with the FiscalYear and FiscalMonth of the PostDate. So I guess I'm just trying to return the FiscalYear and FiscalMonth values when the PostDate falls between the StartDate and EndDate. I've tried using a Subbuery, but I have little experience with them and kept returning an error message that the subquery was returning more than 1 value. Help would be appreciated SELECT Transactions.PostDate, Transactions.TranKey, Transactions.CustKey, (SELECT FiscalPeriod.FiscPer FROM FiscalPeriod WHERE (Transactions.PostDate > CONVERT(Datetime, FiscalPeriod.StartDate, 102)) AND (Transactions.PostDate < CONVERT(DATETIME, FiscalPeriod.EndDate, 102))) AS FisPer FROM Transactions

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  • Oracle: how to UPSERT (update or insert into a table?)

    - by Mark Harrison
    The UPSERT operation either updates or inserts a row in a table, depending if the table already has a row that matches the data: if table t has a row exists that has key X: update t set mystuff... where mykey=X else insert into t mystuff... Since Oracle doesn't have a specific UPSERT statement, what's the best way to do this?

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  • how to compare the values inside a table in sql

    - by Ranjana
    how to compare the values of same table(say for eg: Order table) each and every time the record get inserted , if the record with same values get inserted already in same table i should not insert the new record with same values. how to do that exactly in sql server 2008

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  • Graphical patch utility

    - by Demiurg
    I have a kernel patch for a slightly different kernel version then the one I'm trying to patch. Needless to say, the patch partially fails. I can certainly fix it manually, but I was wondering maybe there is a graphical patch utility that can be used to resolve the conflicts.

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