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  • Cakephp Localization, Cannot Change language when DEFAULT_LANGUAGE is set

    - by ion
    I am confused :) I'm using the p18n component in cakephp found here: http://www.palivoda.eu/2008/04/i18n-in-cakephp-12-database-content-translation-part-2/ This component requires me to set in core.php the following constant: define("DEFAULT_LANGUAGE", 'eng') However when this is set I cannot change the language using: Configure::write('Config.language', 'eng'); At the moment, into my knowledge, the only way to change the locale of my static content is the use of the Configure::write. But for the dynamic content to change through the use of the p28n component I must have the DEFINE_LANGUAGE constant set to a value. This is all very confusing. Any help will be much appreciated.

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  • CakePHP call to member function on non-object

    - by joec
    I have the following Model and Controller files, and when i visit this url, http://....../pois/index i get this error: Notice (8): Undefined property: PoisController::$Poi [APP/controllers/pois_controller.php, line 5] Fatal error: Call to a member function find() on a non-object in /home/joecoyle/public_html/app/controllers/pois_controller.php on line 5 The Model is this, called poi.php: <?php class Poi extends AppModel { } ?> And the controller is this, named pois_controller.php <?php class PoisController extends AppController { function index(){ $this->set('pois',$this->Poi->find('all')); } } ?> As i am new to CakePHP i am not sure what is causing this error, as everything seems to be named, right, and i am following the tutorial on the CakePHP site... Thanks

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  • using ajax to post comments in cakephp results in 404 error, but no errors locally?

    - by Paul
    Using an ajax helper created for use with Jquery I've created a form that posts comments to "/comments/add", and this works as expected on my local wamp server but not on my production server. On my production server I get a '404 error, cannot find /comments/add'. I've spent quite a bit of time searching for a resolution with no luck so far. I've focused on trying to identify a gap but nothing jumps out at me. Here are some observations: works as expected on local wamp server requestHandler is listed as component files on both local and production server are the same controllers folder has write access autoLayout and autoRender are both set to false Here is the form in my view: <div class="comments form"> <?php echo $ajax->form('/comments/add', 'tournament', array('url' => '/comments/add', 'update' => 'Comments', 'indicator' => 'commentSaved'));?> <fieldset> <legend><?php __('Add Comment');?></legend> <div id="commentSaved" style="display: none; float: right;"> <h2>Loading...</h2> </div> <?php echo $form->hidden('Comment.foreign_id', array('value' => $tournament['Tournament']['id'])); echo $form->hidden('Comment.belongs_to', array('value' => 'Tournament')); echo $form->input('Comment.name'); echo $form->input('Comment.email'); echo $form->input('Comment.web', array('value' => 'http://')); echo $form->input('Comment.content'); ?> </fieldset> <?php echo $form->end('Submit');?> </div> And here is my 'comment's controller add action: function add() { if($this->RequestHandler->isAjax()) { $this->autoLayout = false; $this->autoRender=false; $this->Comment->recursive =-1; $commentInfos = $this->Comment->findAllByIp($_SERVER['REMOTE_ADDR']); $spam = FALSE; foreach($commentInfos as $commentInfo) { if ( time() - strtotime($commentInfo['Comment']['created']) < 180) { $spam = TRUE; } } if ($spam === FALSE) { if (!empty($this->data)) { $this->data['Comment']['ip'] = $_SERVER['REMOTE_ADDR']; $this->Comment->create(); if ($this->Comment->save($this->data)) { $this->Comment->recursive =-1; $comments = $this->Comment->findAll(array('Comment.foreign_id' => $this->data['Comment']['foreign_id'], 'Comment.belongs_to' => $this->data['Comment']['belongs_to'], 'Comment.status' =>'approved')); $this->set(compact('comments')); $this->viewPath = 'elements'.DS.'posts'; $this->render('comments'); } } } else { $this->Comment->recursive =-1; $comments = $this->Comment->findAll(array('Comment.foreign_id' => $this->data['Comment']['foreign_id'], 'Comment.belongs_to' => $this->data['Comment']['belongs_to'], 'Comment.status' =>'approved')); $this->set(compact('comments')); $this->viewPath = 'elements'.DS.'posts'; $this->render('spam'); } } else { $this->Session->setFlash(__('Invalid Action. Please view a post to add a comment.', true)); $this->redirect(array('controller' => 'pages', 'action'=>'display', 'home')); } } As you can see I've made sure that 'autoLayout' and 'autoRender' are set to false, but in Firebug I still get a 404 error stating /comments/add cannot be found on the production server. I should also point out that I'm using jquery, jquery.form and jquery.editable as well as a ajax helper created to be used with jquery. Any help or even suggestions about how to trouble shoot this is really appreciated. Cheers, Paul

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  • Include models in Cakephp without going through index.php

    - by Nicklas Ansman
    Hey! I'm using CakePHP to build a site which has a crawler that mines data from different sites. The problem is that I would like to be able to call the crawler from command line (since it can take hours for it to finnish) and I would like to the use models in CakePHP when saving the data. Is there a file I could just include that includes the rest for me? If I just include the index.php it dispatches the call which I don't want. Regards Nicklas

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  • CakePHP: Using two tables for a single model

    - by mwaterous
    I'm just picking up development in CakePHP right now so forgive me if this seems obvious; it did to me when I first read about has, belongsTo, hasMany, etc. The problem is I would like to associate two tables with a single model, and was wondering if there was a way to configure this so that when CakePHP did it's queries it automatically performed a join on the two tables. I don't want to create a separate model for the second table as it is merely a meta information table - the master table will contain the primary information required, the meta table will be populated with secondary information that is not required and therefore may or may not be set for every row of the master table.

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  • CakePHP model useTable with SQL Views

    - by Chris
    I'm in the process converting our CakePHP-built website from Pervasive to SQL Server 2005. After a lot of hassle the setup I've gotten to work is using the ADODB driver with 'connect' as odbc_mssql. This connects to our database and builds the SQL queries just fine. However, here's the rub: one of our Models was associated with an SQL view in Pervasive. I ported over the view, but it appears using the set up that I have that CakePHP can't find the View in SQL Server. Couldn't find much after some Google searches - has anyone else run into a problem like this? Is there a solution/workaround, or is there some redesign in my future?

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  • CakePHP: What to use for MySQL users & permissions?

    - by Steve
    I'm getting ready to deploy a CakePHP site for the first time. I'm using the site with a MySQL database, and I'm still a little unclear about the proper use of users & permissions for MySQL -- I'm talking about the "login" and "password" fields that appear in app/config/database.php. During development, I've been using 'root' and 'root' -- but I'm pretty sure that can't be a good idea. So my question is: what are the best practices for assigning a MySQL user to a CakePHP app, and what MySQL privileges should be assigned to it?

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  • One table for uploads for multiple resources in CakePHP

    - by Mef
    Hi, I have CakePHP app in which I'd like to attach gallery to multiple resources. Let's say I've got artists, each one has own gallery. I've got articles, every article has some images attached to it and so on. Now I set up tables like this: Artists hasMany Artistimages, fields in artistimages table are: id, artist_id, filename, filetype, filesize etc. Articles hasMany Articleimages, fields in articleimages table are: id, article_id, filename, filetype, filesize etc. ...but this is not how it should be, I think. Is there possibility to have one table called for example uploads which will contain all images with foreign key pointing to resource its reffering to? How to tell CakePHP which image is coming from which resource?

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  • Slow server response time - CakePHP

    - by Hasan
    I am using CakePHP 1.2 for building a website. The problem i am facing is when ever a page loads it takes a lot of time in "waiting for www.example.com". The server response time is very slow. First i thot it was my database queries, but they were executing in less than seconds time. Next i also contacted the server people. They told it was not the server. Now i am stuck very badly with "waiting for www.example.com". Is the problem is in coding or the cakePHP is mis configured. Need help badly and fast. Thanks

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  • Manually Building a Tree in CakePHP

    - by mabwi
    I'm currently working on building an application in CakePHP. There's a quite extensive existing data set that's conceptually a tree, but wasn't previously stored as one. What I mean by that, is there's no real relationship defined in the data. The problem I'm having is getting it to work correctly with the CakePHP tree behaviour. Because I have to set all the values on existing data - as opposed to Cake setting up the structure as elements are inserted - I need to understand how the lft/rght values work. So, I guess the question is: How does the structure data work, specifically the lft/rght values? How do I set it up so that the data comes out rationally, without inserting them one at a time? It's a 2 level tree, with Sections and sub-sections. Thanks for the help

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  • How do I completely disable caching in Cakephp?

    - by James Lamiell
    So I opened the cache floodgates in my Cakephp app and now I want to close them... I've done pretty everything I can: delete all files in the tmp folder (but not the folders), turned 'Cache.disable' on in the core.php file in my app, have tried clearing the cache from within some controllers with clearCache() and Cache::clear() (but I suspect this doesn't work because it's not loading the controller -- due to caching). I've pretty much effectively halted my development process just because caching won't turn off. Anyone have some ideas that I could try? I'm starting to think it may be within the browser or maybe my hosting service, but it's probably just Cakephp messing with me.

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  • created modified function (default) is not working in Cakephp 1.2 version

    - by Jpsworld
    I created an application and all the db tables have 'created,modified' fields that filled automatically by Cakephp's Default Functionality. And i put the Field Type is created datetime NULL, modified datetime NULL, like. But it doesn't work. The data where shows 0000-00-00 00:00:00 Format. The cakephp version is 1.2 , so i put the datetime NULL option ,also i removed the temp,cache files in Model. I need to save the correct date & time format for those 2 fields. If there is any problem with XAMPP version (I use the latest version of XAMPP,1.7.7 PHP: 5.3.8 & mysql v 5.5.16 ) I hope that all are identifies my Issue. Please help me with correct solution. Thanks & Regards, Jpsworld.

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  • Specify fields in a recursive find with cakephp

    - by Razor Storm
    Suppose I have a table Recipe that hasmany ingredients. I do a recursive find to grab recipes with their associated ingredients: $this->Recipe->find('all', array('fields' => array('id','title','description'))); Here I can use the 'fields' attribute to specify that I only want it to return id, title, and description. However, despite this, cakephp still returns ALL columns from the ingredients table. How do I tell cakephp that I only want ingredient table's id and name fields? btw ingredient model is "Ingredient" and the table is ingredients, and the aggregation table is recipes_ingredients.

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  • Setting baseurl in cakephp

    - by Aruna
    Hi, I am working on an appliication which is running in cakephp and i am using ajax query inbetween. In all the cases for all the ajax post i have used the url as var ht = $.ajax({ type: "GET", url: "http://172.20.52.99/FormBuilder/index.php/forms/viewChoices/"+attribute_id, async: false }).responseText; var myObject = eval('(' + ht + ')'); is there any way in cakephp where i can give my base url as http://172.20.52.99/FormBuilder/index.php/ and to call the baseurl in all the places i want. Please give some suggestions . Thank you..

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  • Set up CakePHP in a subdirectory; Wordpress is installed in the root

    - by Derek Chiang
    I have been searching for a solution for 2 hours but nothing seems to work... here is my problem: I have WordPress installed in the root (var/www). So by going to http://www.geekderek.com, I see my wordpress site. I put CakePHP in a subdirectory var/www/cakephp. I want to be able to see my CakePHP app by going to: www.geekderek.com/cakephp. However, currently this url just returns a Wordpress page saying "Content not found." I believe this problem can be solved by modifying .htaccess in my root directory. So here is my .htaccess: http://pastebin.com/sXJTRstB As you can see, I added this line to the default WP .htaccess file: RewriteRule ^cakephp(/(.*))?$ cakephp/app/webroot/$1 [QSA,L] However, for some reason this doesn't seem to work. Could anyone please tell me what is wrong?? Thank you so much!

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  • How to use default.ctp in cakephp

    - by Louis Stephens
    I just finished the "15 min Blog Post tutorial" included in the documentation for cakephp. I was asked for another tutorial to change the layout for first tutorial. However, I am fairly new to MVC programming/Cakephp and I have no real clue how to do so. Well, I know I need "default.ctp" placed in app/views/layouts/ and I presume I need to include to include my data? . . . I am really at a loss of what to do. I set up my default.ctp as I mentioned above, but when I go to localhost:9999/posts the layout is still the same. I guess I need to include a stylesheet (and if so, where?) I guess if someone can point me in the right direction to a beginner's guide to layout styling or how to use it I would greatly appreciate any help.

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  • cakephp links not relative

    - by Dan
    In my layout, I have a menu that I've included as an element, and it contains a link like so.. <? $html->link('New Part Number','/part_numbers/add'); ?> The problem that I have is that cake isn't redirecting correctly and it ends up sending me to "http://localhost/part_numbers/add" instead of "http://localhost/my_client_folder/client_app/part_numbers/add" (I'm building this locally). My cakephp app is stored a few directories below my webroot folder, but I thought cakephp would autodetect how to build the linking no matter where the application was located, right? So do i need to configure the application root folder, or create a route or something? Thanks!

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  • Java 6 Certified with Forms and Reports 10g for EBS 12

    - by John Abraham
    Java 6 is now certified with Oracle Application Server 10g Forms and Reports with Oracle E-Business Suite Release 12 (12.0.6, 12.1.1 and higher). What? Wasn't this already certified? No, but a little background might be useful in understanding why this is a new announcement. We previously certified the use of Java 6 with E-Business Suite Release 12 -- with the sole exception of Oracle Application Server 10g components in the E-Business Suite technology stack. Oracle Application Server 10g originally included Java 1.4.2 as part of its distribution.  E-Business Suite 12 uses, amongst other things, the Oracle Forms and Reports 10g components running on Java 1.4. Java 1.4 in the Oracle Application Server 10g ORACLE_HOME is used exclusively by AS 10g Forms and Reports' for Java functionality.  This version of Java is separate from the Java distribution used by other parts of EBS such as Oracle Containers for Java (OC4J). What's new about this certification? You can now upgrade the older Java 1.4 libraries used by Oracle Forms & Reports 10g to Java 6. This allows you to upgrade the Java releases within the Oracle Application Server 10g ORACLE_HOME to the the same level as the rest of your E-Business Suite technology stack components. Why upgrade? This becomes particularly important for customers as individual vendors' support lifecycle for Java 1.4 reaches End of Life: Oracle's Sun JDK Release 1.4.2's End of Extended Support: February 2013 (Sustaining Support indefinitely after) IBM SDK and JRE 1.4.2's End of Service: September 2013 HP-UX Java 1.4.2's End-of-Life : May 2012 Along with Oracle Forms, Java lies at the heart of the Oracle E-Business Suite.  Small improvements in Java can have significant effects on the performance and stability of the E-Business Suite.  As a notable side-benefit, later versions of Java have improved built-in and third-party tools for JVM performance monitoring and tuning.Our standing recommendation is that you always stay current with the latest available Java update provided by your operating system vendor.  Don't forget to upgrade Forms & Reports to 10.1.2.3 E-Business Suite 12 originally shipped with Oracle Application Server 10g Forms & Reports 10.1.2.0.2.  That version is no longer eligible for Error Correction Support. New Forms and Reports 10g patches are now being released with Forms and Reports 10.1.2.3 as the prerequisite. Forms and Reports 10.1.2.3 was certified for EBS 12 environments in November 2008. If you haven't upgraded your EBS 12 environment to Forms & Reports 10.1.2.3, this is a good opportunity to do so. References Using Latest Update of Java 6.0 with Oracle E-Business Suite Release 12 (My Oracle Support Document 455492.1) Overview of Using Java with Oracle E-Business Suite Release 12 (My Oracle Support Document 418664.1) Oracle Lifetime Support Policy (Oracle Fusion Middleware) IBM Developer Kit Lifecycle Dates HP-UX Java - End of Life Policy & Release Naming Terminology Related Articles OracleAS 10g Forms and Reports 10.1.2.3 Certified With EBS R12 Java 6 Certified with E-Business Suite Release 12

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  • Which Presentation Would You Like to See at the OUG Ireland?

    - by Grant Ronald
    A novel idea, and one I think one worth trialling, is the OUG Ireland are allowing the public to vote on which presentation I will give at the conference in March.  So, rather than the a paper selection committee choosing,  the OUG community can choose.I know that Oracle tried this at Oracle World over the last couple of year and I think its good to get some community input.If you are a member of the OUG you can vote here.

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  • Django forms: how to dynamically create ModelChoiceField labels

    - by Henri
    I would like to create dynamic labels for a forms.ModelChoiceField and I'm wondering how to do that. I have the following form class: class ProfileForm(forms.ModelForm): def __init__(self, data=None, ..., language_code='en', family_name_label='Family name', horoscope_label='Horoscope type', *args, **kwargs): super(ProfileForm, self).__init__(data, *args, **kwargs) self.fields['family_name'].label = family_name_label . . self.fields['horoscope'].label = horoscope_label self.fields['horoscope'].queryset = Horoscope.objects.all() class Meta: model = Profile family_name = forms.CharField(widget=forms.TextInput(attrs={'size':'80', 'class': 'contact_form'})) . . horoscope = forms.ModelChoiceField(queryset = Horoscope.objects.none(), widget=forms.RadioSelect(), empty_label=None) The default labels are defined by the unicode function specified in the Profile definition. However the labels for the radio buttons created by the ModelChoiceField need to be created dynamically. First I thought I could simply override ModelChoiceField as described in the Django documentation. But that creates static labels. It allows you to define any label but once the choice is made, that choice is fixed. So I think I need to adapt add something to init like: class ProfileForm(forms.ModelForm): def __init__(self, data=None, ..., language_code='en', family_name_label='Family name', horoscope_label='Horoscope type', *args, **kwargs): super(ProfileForm, self).__init__(data, *args, **kwargs) self.fields['family_name'].label = family_name_label . . self.fields['horoscope'].label = horoscope_label self.fields['horoscope'].queryset = Horoscope.objects.all() self.fields['horoscope'].<WHAT>??? = ??? Anyone having any idea how to handle this? Any help would be appreciated very much.

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  • Multipage forms for joomla (looking outside the box)

    - by John Snow
    I have created a number of forms using various Joomla components which have more or less worked successfully. Recently I have attempted to create mult-page forms - the forms work...but they are slow as molasses. Having spent a couple of weeks trying to resolve this and not seeing any signs of improvement ...... I wonder if anyone has experience of using hosted forms services in Joomla either using a wrapper or as a static page within a Joomla site. Any pointers or recommendations would be appreciated.

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  • Django Passing Custom Form Parameters to Formset

    - by Paolo Bergantino
    I have a Django Form that looks like this: class ServiceForm(forms.Form): option = forms.ModelChoiceField(queryset=ServiceOption.objects.none()) rate = forms.DecimalField(widget=custom_widgets.SmallField()) units = forms.IntegerField(min_value=1, widget=custom_widgets.SmallField()) def __init__(self, *args, **kwargs): affiliate = kwargs.pop('affiliate') super(ServiceForm, self).__init__(*args, **kwargs) self.fields["option"].queryset = ServiceOption.objects.filter(affiliate=affiliate) I call this form with something like this: form = ServiceForm(affiliate=request.affiliate) Where request.affiliate is the logged in user. This works as intended. My problem is that I now want to turn this single form into a formset. What I can't figure out is how I can pass the affiliate information to the individual forms when creating the formset. According to the docs to make a formset out of this I need to do something like this: ServiceFormSet = forms.formsets.formset_factory(ServiceForm, extra=3) And then I need to create it like this: formset = ServiceFormSet() Now how can I pass affiliate=request.affiliate to the individual forms this way?

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  • how to insert multiple rows using cakephp

    - by Paul
    In the cakePHP project I'm building, I want to insert a defined number of identical records. These will serve as placeholders records that will have additional data added later. Each record will insert the IDs taken from two belongs_to relationships as well as two other string values. What I want to do is be able to enter a value for the number of records I want created, which would equate to how many times the data is looped during save. What I don't know is: 1) how to setup a loop to handle a set number of inserts 2) how to define a form field in cakePHP that only sets the number of records to create. What I've tried is the following: function massAdd() { $inserts_required = 1; while ($inserts_required <= 10) { $this->Match->create(); $this->Match->save($this->data); echo $inserts_required++; } $brackets = $this->Match->Bracket->find('list'); $this->set(compact('brackets')); } What happens is: 1) at the top of the screen, above the doc type, the string 12345678910 is displayed, this is displayed on screen 2) a total of 11 records are created, and only the last record has the values passed in the form. I don't know why 11 records as opposed to 10 are created, and why only the last records has the entered form data? As always, your help and direction is appreciated. -Paul

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