Search Results

Search found 3450 results on 138 pages for 'extract cursors'.

Page 7/138 | < Previous Page | 3 4 5 6 7 8 9 10 11 12 13 14  | Next Page >

  • How to skip one folder with 7zip [closed]

    - by SoMoS
    Hello, I have to extract a file from commandline with 7zip (or other free zip application) with the next structure: MAIN_DIR\ ---a ---b ---SUBDIR\ ---c I need the output structure to be the same but skipping the first folder so I end with: ---a ---b ---SUBDIR\ ---c Can this be done with 7zip or other free commandline zip extractor? Thanks in advance.

    Read the article

  • Sending one record from cursor to another function Postgres

    - by PylonsN00b
    FYI: I am completely new to using cursors... So I have one function that is a cursor: CREATE FUNCTION get_all_product_promos(refcursor, cursor_object_id integer) RETURNS refcursor AS ' BEGIN OPEN $1 FOR SELECT * FROM promos prom1 JOIN promo_objects ON (prom1.promo_id = promo_objects.promotion_id) WHERE prom1.active = true AND now() BETWEEN prom1.start_date AND prom1.end_date AND promo_objects.object_id = cursor_object_id UNION SELECT prom2.promo_id FROM promos prom2 JOIN promo_buy_objects ON (prom2.promo_id = promo_buy_objects.promo_id) LEFT JOIN promo_get_objects ON prom2.promo_id = promo_get_objects.promo_id WHERE (prom2.buy_quantity IS NOT NULL OR prom2.buy_quantity > 0) AND prom2.active = true AND now() BETWEEN prom2.start_date AND prom2.end_date AND promo_buy_objects.object_id = cursor_object_id; RETURN $1; END; ' LANGUAGE plpgsql; SO then in another function I call it and need to process it: ... --Get the promotions from the cursor SELECT get_all_product_promos('promo_cursor', this_object_id) updated := FALSE; IF FOUND THEN --Then loop through your results LOOP FETCH promo_cursor into this_promotion --Preform comparison logic -this is necessary as this logic is used in other contexts from other functions SELECT * INTO best_promo_results FROM get_best_product_promos(this_promotion, this_object_id, get_free_promotion, get_free_promotion_value, current_promotion_value, current_promotion); ... SO the idea here is to select from the cursor, loop using fetch (next is assumed correct?) and put the record fetched into this_promotion. Then send the record in this_promotion to another function. I can't figure out what to declare the type of this_promotion in get_best_product_promos. Here is what I have: CREATE OR REPLACE FUNCTION get_best_product_promos(this_promotion record, this_object_id integer, get_free_promotion integer, get_free_promotion_value numeric(10,2), current_promotion_value numeric(10,2), current_promotion integer) RETURNS... It tells me: ERROR: plpgsql functions cannot take type record OK first I tried: CREATE OR REPLACE FUNCTION get_best_product_promos(this_promotion get_all_product_promos, this_object_id integer, get_free_promotion integer, get_free_promotion_value numeric(10,2), current_promotion_value numeric(10,2), current_promotion integer) RETURNS... Because I saw some syntax in the Postgres docs showed a function being created w/ a input parameter that had a type 'tablename' this works, but it has to be a tablename not a function :( I know I am so close, I was told to use cursors to pass records around. So I studied up. Please help.

    Read the article

  • jquery anchor to html extract

    - by Benjamin Ortuzar
    I would like to implement something similar to the Google quick scroll extension with jquery for the extracts of a search result, so when the full document is opened (within the same website) it gives the user the opportunity to go straight to the extract location. Here is a sample of what I get returned from the search engine when I search for 'food'. <doc> <docid>129305</docid> <title><span class='highlighted'>Food</span></title> <summary> <summarytext>Papers subject to Negative Resolution: 4 <span class='highlighted'>Food</span> <span class='highlighted'>Food</span> Irradiation (England) Regulations 2009 (S.I., 2009, No. 1584), dated 24 June 2009 (by Act), </summarytext> </summary> <paras> <paraitemcount>2</paraitemcount> <para> <paraitem>1</paraitem> <paraid>42</paraid> <pararelevance>100</pararelevance> <paraweights>50</paraweights> <paratext>4 <span class='highlighted'>Food</span></paratext> </para> <para> <paraitem>2</paraitem> <paraid>54</paraid> <pararelevance>100</pararelevance> <paraweights>50</paraweights> <paratext><span class='highlighted'>Food</span> Irradiation (England) Regulations 2009 (S.I., 2009, No. 1584), dated 24 June 2009 (by Act), with an Explanatory Memorandum and an Impact Assessment (</paratext> </para> </paras> </doc> As you see the search engine has returned a document that contains one summary and two extracts. So let's say the user clicks on the second extract in the search resutls page, the browser would open the detailed document in the same website, and would offer the user the possibility to go to the extract as the Google quick scroll extension does. Is there an existing jquery script for this? If not, can you suggest any jquery/javascript code that would simplify my task to implement this. Notes: I can access the extracts from the document details page. I'm aware that the HTML in some cases could be slightly different in the extract than in the details page, finding no match. The search engine does not return where the extract was located. At the moment I'm trying to understand the JS code that the extension uses.

    Read the article

  • Unzip individual files from multiple zip files and extract those individual files to home directory

    - by James P.
    I would like to unzip individual files. These files have a .txt extension. These files also live within multiple zipped files. Here is the command I'm trying to use. unzip -jn /path/to/zipped/files/zipArchiveFile2011\*.zip /path/to/specific/individual/files/myfiles2011*.txt -d /path/to/home/directory/for/extract/ From my understanding, the -j option excludes directories and will extract only the txt files The -n option will not overwrite a file if it has already been extracted. I've also learned that the forward slash in /path/to/zipped/files/zipArchiveFile2011\*.zip is necessary to escape the wildcard (*) character. Here is sample of error messages I'm coming accross: Archive: /path/to/zipped/files/zipArchiveFile20110808.zip caution: filename not matched: /path/to/specific/individual/files/myfiles20110807.txt caution: filename not matched: /path/to/specific/individual/files/myfiles20110808.txt Archive: /path/to/zipped/files/zipArchiveFile20110809.zip caution: filename not matched: /path/to/specific/individual/files/myfiles20110810.txt caution: filename not matched: /path/to/specific/individual/files/myfiles20110809.txt I feel that I'm missing something very simple. I've tried using single quotes (') and double quotes (") around directory paths. But no luck.

    Read the article

  • SQL Server 2008 Prior String Extract

    - by Saidur Rahman
    I have strings like the ones below in a SQL column. I want to extract them as a Gigabyte amount in aggregate. Example: Original Column ---------> Expected Output from a TSQL function ------------------------------------------- $15 / 1GB 24m + Intern 120MB ----------> 1.12 GB $19.95 / 500MB + $49.95 / 9GB Blackberry -----> 9.5GB $174.95 Blackberry 24GB + $10 / 1GB Datapack ----> 25GB $79 / 6GB --> 6GB Null --> Null $20 Plan --> 0GB Note: for our purpose, 1000MB = 1 GB (not 1024). The pattern is numbers followed by GB/MB, usually they are combined like 1GB (without any space but may sometimes may contain a space, it is not particularly important if hard to implement for this exception). Sometimes there are up to three or four instances of GB/MB occurring in the same string which are usually separated by a + sign (see row 2 and 3 of my example above). I have seen how we extract the dollar values in one of the answers where numbers were followed by $ or extract all integers in a string but I don't want to extract the dollar values or all the integers in a string. I just want the sum of GB/MB in the string.

    Read the article

  • Extracting specific files from ZIP in PHP

    - by Michael
    If I have a ZIP file whose structure is: -directory1 DIR -files in here -directory2 DIR -more files in here Using pclzip.lib.php how can I open up this ZIP file and extract directory1 (recursive) into a directory and then extract directory2 (recursive) into another directory.

    Read the article

  • How can I use from ismember

    - by ahmad hosseini
    Assuming A=[32512199.30 5401000.29 347.33 32512199.69 5401000.45 347.39 32512199.67 5401001.32 353.58 32512199.96 5401001.50 346.99 32512196.71 5401001.69 346.62 ] and B=[32512199.30 5401000.29 347.33 32512199.69 5401000.45 347.39 32512199.67 5401001.32 347.00 32512198.85 5401000.91 347.25 32512196.71 5401001.69 346.87 ] I want using ismember extract the rows that have same X and Y and different Z. X is first column, Y is the second and Z is third. in A and B I want extract from A 32512199.67 5401001.32 353.58 and 32512196.71 5401001.69 346.62 OR from B 32512199.67 5401001.32 347.00 and 32512196.71 5401001.69 346.87 How can I do it?

    Read the article

  • Extracting metadata from flac header in linux

    - by Tommy Fisk
    Hello. I recently (and accidentally) wiped a hard-drive which should NOT have been formatted. Thankfully, PhotoRec was able to recover some of the most important files from the disk. Part of those files include a large music collection of flac files. I've placed these in a folder named 'FLAC' that looks like this: [Start of FLAC Folder] f11655088.flac f11698672.flac ... (around 2,000 files total) f291142600.flac [End of FLAC Folder] I'm running a livecd to rescue this data. I have access to a standard terminal in Ubuntu 10.10. I've noticed that the music player in linux will display the song title when I open any of these songs. My goal is to automatically extract the song title from these files and update their names from f12313512.flac to 'Libera - Rebirth.flac' - or whatever the song title happens to be. Thanks in advance for suggestions on how I might accomplish this!

    Read the article

  • Print each bookmark of a PDF separately

    - by Dave
    I have a very large (1000 page) PDF which contains about 100, ten page each documents one after the other. I would like to have them sent to my office printer as individual files so my office printer will print them double sided and staple each one individually. I'm using Adobe Acrobat X and think the first step is to bookmark the start of each of those 100 documents. I don't know the next step though. I also have a batch printing program so if i can extract each of those 100 bookmarks to individual files that would work too. Thanks for all the help.

    Read the article

  • Copy any file with a specific file extension in subfolders into a folder

    - by Onyxius
    I found a script on here that would use 7zip and extract all the files in all the sub-folders of a specific folder and put them in their own folder using the script below. What I need is add to it or maybe use another script if i have to and specify where i want those files to go instead of putting them in their own folder within the folder. I don't know how to do this and hope someone would be able to help. Thanks for the help @echo on FOR /D /r %%F in ("*") DO ( pushd %CD% cd %%F FOR %%X in (*.rar *.zip *.tar) DO ( "C:\Program Files\7-zip\7z.exe" x -o"%%~nX" "%%X" ) popd )

    Read the article

  • Extract string from string using Regex

    - by stacker
    I want to extract MasterPage value directive from a view page. I want the fastest way to do that, taking into account a very big aspx pages, and a very small ones. I think the best way is to do that with two stages: Extract the page directive section from the view (using Regex): <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage" %> Then, extract the value inside MasterPageFile attribute. The result needs to be: ~/Views/Shared/Site.Master. Can I have help from someone to implement this? I badly want to use only regex, but I don't Regex expert. Another thing, Do you think that Regex is the fastest way to do this?

    Read the article

  • Extract part of HTML in C/Objective-C

    - by Dan
    Hi, I need to extract the detail content of a website while preserve all formatting of the division. The section I wish to extract is: ... <div class="detailContent"><p> <P dir=ltr><STRONG>Hinweis</strong>: Auf ... </p> </div> ... My current solution is to use HTMLParser from libxml2 and xpath to find the nodes and walk through all the nodes to reconstruct this piece of HTML. This is a long an complicated code. I' just wondering if there is an easier solution to extract part of HTML? Thanks.

    Read the article

  • Extract multiple values from one column in MySql

    - by Neil
    I've noticed that MySql has an extensive search capacity, allowing both wildcards and regular expressions. However, I'm in somewhat in a bind since I'm trying to extract multiple values from a single string in my select query. For example, if I had the text "<span>Test</span> this <span>query</span>", perhaps using regular expressions I could find and extract values "Test" or "query", but in my case, I have potentially n such strings to extract. And since I can't define n columns in my select statement, that means I'm stuck. Is there anyway I could have a list of values (ideally separated by commas) of any text contained with span tags? In other words, if I ran this query, I would get "Test,query" as the value of spanlist: select <insert logic here> as spanlist from HtmlPages ...

    Read the article

  • Nokogiri extract data from xml

    - by Awea
    Hi guys, i try to extract data from a xml in rails application with the Nokogiri gem, the xml : <item> <description> <img src="something" title="anothething"> <p>text, bla bla...</p> </description> </item> Actually i do something like this to extract data from the xml : def test_content @return = Array.new site = 'http://www.les-encens.com/modules/feeder/rss.php?id_category=0' @doc = Nokogiri::XML(open(site, "UserAgent" => "Ruby-OpenURI")) @doc.xpath("//item").each do |n| @return << [ n.xpath('description') ] end end Could you show me how extract just the src attribute from the img tag ?

    Read the article

  • Are there any Acrobat plugins or standalone programs that allow one to select and extract individual

    - by user30525
    We use BCL Jade currently but are running into problems because it isn't supported or sold anymore, doesn't work on Acrobat 8 or 9, and has some other issues. Other than that though it works great! :) Is there anything like it that allows users to select zones to extract? I see a simaler question on here and and an answer that suggests this http://pdftohtml.sourceforge.net/ but ideally we would want something nonprogrammers could use.

    Read the article

  • how to extract rar format file on Mac?

    - by George2
    I am using a MacBook Pro running Mac OS X 10.5. I am new to this development environment, and previously worked on Windows. I am wondering how to extract rar compressed format file on Mac? Better free or open source software. Thanks in advance.

    Read the article

  • Extract Links and save pages

    - by Veejay
    I have a couple of pages, each has around 20 links on it. Each link leads to a different page. I want to provide the user an option to extract all the links on these Page and then download each of the pages(20) to their desktop. Any tools/addons/plugins that I can suggest users?

    Read the article

  • Extract specific files in a tar archive using a wildcard

    - by AdrieanKhisbe
    I'm tring for a script to extract only jpeg pictures from an archive containing maky kind of files. To do so I tried first to use: tar -xf MyTar.tar *.jpg but it failed (*.jpg not found) and suggest me to use "--wildcard". So I tried tar -xf MyTar.tar --wildcard *.jpg I did that, but then the same error and a different warning saying yo me that the option "--wildcard" is ambigious. I've been over the manuel pages for tar, but didn't find a clue about the problem thanks

    Read the article

  • FFmpeg extract clip - stream frame rate differs from container frame rate (x264, aac)

    - by fideli
    Summary H.264 video seems to have a really high frame rate that requires a scaling factor to the applied to the duration of video that I'm trying to extract (900x lower). Body I'm trying to extract a clip from a movie that I have in MP4 format (created using Handbrake). After trying mencoder and VLC, I decided to give FFmpeg a shot since it was the least troublesome when it came to copying the codecs. That is, compared to mencoder and VLC, the resulting file was still playable in QuickTime (I know about Perian, etc, I'm just trying to learn how all this works). Anyway, my command was as follows: ffmpeg -ss 01:15:51 -t 00:05:59 -i outofsight.mp4 \ -acodec copy -vcodec copy clip.mp4 During the copy, The following comes up: Seems stream 0 codec frame rate differs from container frame rate: 45000.00 (45000/1) -> 25.00 (25/1) Input #0, mov,mp4,m4a,3gp,3g2,mj2, from outofsight.mp4': Duration: 01:57:42.10, start: 0.000000, bitrate: 830 kb/s Stream #0.0(und): Video: h264, yuv420p, 720x384, 25 tbr, 22500 tbn, 45k tbc Stream #0.1(eng): Audio: aac, 48000 Hz, stereo, s16 Output #0, mp4, to 'out.mp4': Stream #0.0(und): Video: libx264, yuv420p, 720x384, q=2-31, 90k tbn, 22500 tbc Stream #0.1(eng): Audio: libfaac, 48000 Hz, stereo, s16 Stream mapping: Stream #0.0 -> #0.0 Stream #0.1 -> #0.1 Press [q] to stop encoding frame= 2591 fps=2349 q=-1.0 size= 8144kB time=101.60 bitrate= 656.7kbits/s … Instead of a 5:59 duration clip, I get the entire rest of the movie. So, to test this, I ran the ffmpeg command with -t 00:00:01. What I got was exactly a 15:00 minute clip. So I did some black box engineering and decided to scale my -t option by calculating what value to enter given that 1 second was interpreted as 900 s. For my desired 359 s clip, I calculated 0.399 s and so my ffmpeg command became: ffmpeg -ss 01:15.51 -t 00:00:00.399 -i outofsight.mp4 \ -acodec copy -vcodec copy clip.mp4 This works, but I have no idea why the duration is scaled by 900. Investigating further, each ffmpeg run has the line: Seems stream 0 codec frame rate differs from container frame rate: 45000.00 (45000/1) -> 25.00 (25/1) 45000/25 = 1800. Must be a relation somewhere. Somehow, the obscenely high frame rate is causing issues with the timing. How is that frame rate so high? The best part about this is that the resulting clip.mp4 has the exact same feature (due to the copied video codec), and taking further clips from this needs the same scaling for the -t duration option. Therefore, I've made it available for anyone willing to check this out. Appendix The preamble for ffmpeg on my system (built using MacPorts ffmpeg port): FFmpeg version 0.5, Copyright (c) 2000-2009 Fabrice Bellard, et al. configuration: --prefix=/opt/local --disable-vhook --enable-gpl --enable-postproc --enable-swscale --enable-avfilter --enable-avfilter-lavf --enable-libmp3lame --enable-libvorbis --enable-libtheora --enable-libdirac --enable-libschroedinger --enable-libfaac --enable-libfaad --enable-libxvid --enable-libx264 --mandir=/opt/local/share/man --enable-shared --enable-pthreads --cc=/usr/bin/gcc-4.2 --arch=x86_64 libavutil 49.15. 0 / 49.15. 0 libavcodec 52.20. 0 / 52.20. 0 libavformat 52.31. 0 / 52.31. 0 libavdevice 52. 1. 0 / 52. 1. 0 libavfilter 1. 4. 0 / 1. 4. 0 libswscale 1. 7. 1 / 1. 7. 1 libpostproc 51. 2. 0 / 51. 2. 0 built on Jan 4 2010 21:51:51, gcc: 4.2.1 (Apple Inc. build 5646) (dot 1)

    Read the article

  • FFmpeg extract clip - stream frame rate differs from container frame rate (x264, aac)

    - by fideli
    Summary H.264 video seems to have a really high frame rate that requires a scaling factor to the applied to the duration of video that I'm trying to extract (900x lower). Body I'm trying to extract a clip from a movie that I have in MP4 format (created using Handbrake). After trying mencoder and VLC, I decided to give FFmpeg a shot since it was the least troublesome when it came to copying the codecs. That is, compared to mencoder and VLC, the resulting file was still playable in QuickTime (I know about Perian, etc, I'm just trying to learn how all this works). Anyway, my command was as follows: ffmpeg -ss 01:15:51 -t 00:05:59 -i outofsight.mp4 \ -acodec copy -vcodec copy clip.mp4 During the copy, The following comes up: Seems stream 0 codec frame rate differs from container frame rate: 45000.00 (45000/1) -> 25.00 (25/1) Input #0, mov,mp4,m4a,3gp,3g2,mj2, from outofsight.mp4': Duration: 01:57:42.10, start: 0.000000, bitrate: 830 kb/s Stream #0.0(und): Video: h264, yuv420p, 720x384, 25 tbr, 22500 tbn, 45k tbc Stream #0.1(eng): Audio: aac, 48000 Hz, stereo, s16 Output #0, mp4, to 'out.mp4': Stream #0.0(und): Video: libx264, yuv420p, 720x384, q=2-31, 90k tbn, 22500 tbc Stream #0.1(eng): Audio: libfaac, 48000 Hz, stereo, s16 Stream mapping: Stream #0.0 -> #0.0 Stream #0.1 -> #0.1 Press [q] to stop encoding frame= 2591 fps=2349 q=-1.0 size= 8144kB time=101.60 bitrate= 656.7kbits/s … Instead of a 5:59 duration clip, I get the entire rest of the movie. So, to test this, I ran the ffmpeg command with -t 00:00:01. What I got was exactly a 15:00 minute clip. So I did some black box engineering and decided to scale my -t option by calculating what value to enter given that 1 second was interpreted as 900 s. For my desired 359 s clip, I calculated 0.399 s and so my ffmpeg command became: ffmpeg -ss 01:15.51 -t 00:00:00.399 -i outofsight.mp4 \ -acodec copy -vcodec copy clip.mp4 This works, but I have no idea why the duration is scaled by 900. Investigating further, each ffmpeg run has the line: Seems stream 0 codec frame rate differs from container frame rate: 45000.00 (45000/1) -> 25.00 (25/1) 45000/25 = 1800. Must be a relation somewhere. Somehow, the obscenely high frame rate is causing issues with the timing. How is that frame rate so high? The best part about this is that the resulting clip.mp4 has the exact same feature (due to the copied video codec), and taking further clips from this needs the same scaling for the -t duration option. Therefore, I've made it available for anyone willing to check this out. Appendix The preamble for ffmpeg on my system (built using MacPorts ffmpeg port): FFmpeg version 0.5, Copyright (c) 2000-2009 Fabrice Bellard, et al. configuration: --prefix=/opt/local --disable-vhook --enable-gpl --enable-postproc --enable-swscale --enable-avfilter --enable-avfilter-lavf --enable-libmp3lame --enable-libvorbis --enable-libtheora --enable-libdirac --enable-libschroedinger --enable-libfaac --enable-libfaad --enable-libxvid --enable-libx264 --mandir=/opt/local/share/man --enable-shared --enable-pthreads --cc=/usr/bin/gcc-4.2 --arch=x86_64 libavutil 49.15. 0 / 49.15. 0 libavcodec 52.20. 0 / 52.20. 0 libavformat 52.31. 0 / 52.31. 0 libavdevice 52. 1. 0 / 52. 1. 0 libavfilter 1. 4. 0 / 1. 4. 0 libswscale 1. 7. 1 / 1. 7. 1 libpostproc 51. 2. 0 / 51. 2. 0 built on Jan 4 2010 21:51:51, gcc: 4.2.1 (Apple Inc. build 5646) (dot 1) EDIT Not sure whether it was a bug or not, but it seems to be fixed now in my current version of ffmpeg, at least for this video (version 0.6.1 from MacPorts).

    Read the article

  • Extract wav file from video file

    - by Nikos Steiakakis
    I am developing an application in which I need to extract the audio from a video. The audio needs to be extracted in .wav format but I do not have a problem with the video format. Any format will do, as long as I can extract the audio in a wav file. Currently I am using Windows Media Player COM control in a windows form to play the videos, but any other embedded player will do as well. Any suggestions on how to do this? Thanks

    Read the article

< Previous Page | 3 4 5 6 7 8 9 10 11 12 13 14  | Next Page >