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  • WPF - Only want one expander open at a time

    - by Portsmouth
    I have a UserControl with a templated grouped listbox with expanders and only want one expander open at any time. I have browsed through the site but haven't found anything except binding the IsExpanded to IsSelected which isn't quite what I want. I am trying to put some code in the Expanded event that would loop through Expanders and close all the ones that aren't the expander passed in the Expanded event. I can't seem to figure out how to get at them. I've tried ListBox.Items.Groups but didn't see how to get at them and tried ListBox.ItemContainerGenerator.ContainerFromItem (or Index) but nothing came back. Thanks <ListBox Name="ListBox"> <ListBox.GroupStyle > <GroupStyle> <GroupStyle.ContainerStyle> <Style TargetType="{x:Type GroupItem}"> <Setter Property="Template"> <Setter.Value> <ControlTemplate TargetType="{x:Type GroupItem}"> <Border BorderBrush="CadetBlue" BorderThickness="1"> <Expander BorderThickness="0,0,0,1" Expanded="Expander_Expanded" Focusable="False" IsExpanded="{Binding IsSelected, RelativeSource={RelativeSource FindAncestor, AncestorType= {x:Type ListBoxItem}}}" > <Expander.Header> <Grid> <StackPanel Height="30" Orientation="Horizontal"> <TextBlock Foreground="Navy" FontWeight="Bold" Text="{Binding Path=Name}" Margin="5,0,0,0" MinWidth="200" Padding="3" VerticalAlignment="Center" /> <TextBlock Foreground="Navy" FontWeight="Bold" Text=" Setups: " VerticalAlignment="Center" HorizontalAlignment="Right"/> <TextBlock Foreground="Navy" FontWeight="Bold" Text="{Binding Path=ItemCount}" VerticalAlignment="Center" HorizontalAlignment="Right" /> </StackPanel> </Grid> </Expander.Header> <Expander.Content> <Grid Background="white" > <ItemsPresenter /> </Grid> </Expander.Content> <Expander.Style > <Style TargetType="{x:Type Expander}"> <Style.Triggers> <Trigger Property="IsMouseOver" Value="true"> <Setter Property="Background"> <Setter.Value> <LinearGradientBrush StartPoint="0,0" EndPoint="0,1"> <GradientStop Color="WhiteSmoke" Offset="0.0" /> <GradientStop Color="Orange" Offset="1.0" /> </LinearGradientBrush> </Setter.Value> </Setter> </Trigger> <Trigger Property="IsMouseOver" Value="false" <Setter Property="Background"> <Setter.Value> </code>

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  • WPF: Restyling a window?

    - by mark smith
    Hi there, does anyone know if its possible to restyle a window in wpf. Or even better any tutorials or samples? Basically i would like to change the minimize and maximize buttons - oh and the close button to be slightly bigger.... I have expression blend.... Is this possible? I saw some samples in infragistics sample apps which have some great looking forms and as far as i can tell it doesn't use any custom wpf controls... Any ideas really appreciated

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  • WPF, ShowGridLines equivalent for wrap panel

    - by user275587
    I need to display a 1 pixel wide border around all wrap panel cells, kinda like excel grid. Unfortunately the wrap panel does not implement the grid ShowGridLines property. I can't put a border inside every cell because adjacent cells will have a 2 pixel border instead of 1 pixel. Since the wrap panel arranges it's layout dynamically and does not expose it's properties I can't evaluate the correct value for a border inside a cell. Any workaround possible?

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  • How can I anchor a textbox in wpf ?

    - by csuporj
    I have a window with tabs. On one of the tabs, I have a layout like below. (In fact it is more complicated, I have 4 text boxes in a row, and I have more rows.) How can I make the 3rd textbox have the width of the label + the width of the text box above, that is, to have them properly aligned ? The problem is that WPF widens the 3rd textbox, when I type text into it. Using hardcoded numbers for the sizes defeats the whole purpose of WPF. I could do that way 10 times faster in Windows Forms than in WPF. Is there a better way, than using a grid for each set of consecutive small text boxes, having to skip the large ones from the grid, because putting them in messes up everything. <Window x:Class="WpfApplication1.MainWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="MainWindow" Height="350" Width="525"> <Window.Resources> <Style TargetType="{x:Type Label}"> <Setter Property="VerticalAlignment" Value="Center"/> </Style> <Style TargetType="{x:Type TextBox}"> <Setter Property="VerticalAlignment" Value="Center"/> <Setter Property="Margin" Value="3"/> </Style> <Style x:Key="SmallTextBox" TargetType="{x:Type TextBox}" BasedOn="{StaticResource {x:Type TextBox}}"> <Setter Property="Width" Value="50"/> </Style> </Window.Resources> <StackPanel VerticalAlignment="Top" HorizontalAlignment="Left" Width="{Binding ElementName=grid,Path=ActualWidth}" Grid.IsSharedSizeScope="True"> <Grid Name="grid" HorizontalAlignment="Left"> <Grid.ColumnDefinitions> <ColumnDefinition Width="Auto" SharedSizeGroup="c1"/> <ColumnDefinition Width="Auto" SharedSizeGroup="c2"/> </Grid.ColumnDefinitions> <Grid.RowDefinitions> <RowDefinition Height="Auto"/> <RowDefinition Height="Auto"/> </Grid.RowDefinitions> <Label Content="Foo:"/> <TextBox Grid.Column="1" Style="{StaticResource SmallTextBox}"/> <Label Grid.Row="1" Content="Foobar:"/> <TextBox Grid.Row="1" Grid.Column="1" Style="{StaticResource SmallTextBox}"/> </Grid> <TextBox Grid.Row="1"/> <Grid Name="grid2" HorizontalAlignment="Left"> <Grid.ColumnDefinitions> <ColumnDefinition Width="Auto" SharedSizeGroup="c1"/> <ColumnDefinition Width="Auto" SharedSizeGroup="c2"/> </Grid.ColumnDefinitions> <Label Content="Bar:"/> <TextBox Grid.Column="1" Style="{StaticResource SmallTextBox}"/> </Grid> </StackPanel> </Window>

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  • Why does my TextBox with custom control template not have a visible text cursor?

    - by Philipp Schmid
    I have a custom control template which is set via the style property on a TextBox. The visual poperties are set correctly, even typing to the textbox works, but there is no insertion cursor (the | symbol) visible which makes editing challenging for our users. How does the control template need changing to get the traditional TextBox behavior back? <Style x:Key="DemandEditStyle" TargetType="TextBox"> <EventSetter Event="LostFocus" Handler="DemandLostFocus" /> <Setter Property="HorizontalAlignment" Value="Stretch" /> <Setter Property="VerticalAlignment" Value="Stretch" /> <Setter Property="Template"> <Setter.Value> <ControlTemplate> <Grid HorizontalAlignment="Stretch" VerticalAlignment="Stretch"> <Grid.ColumnDefinitions> <ColumnDefinition Width="*" /> <ColumnDefinition Width="1" /> </Grid.ColumnDefinitions> <Grid.RowDefinitions> <RowDefinition Height="*" /> <RowDefinition Height="1" /> </Grid.RowDefinitions> <Grid.Background> <LinearGradientBrush StartPoint="0,0" EndPoint="0,1"> <GradientStop Color="White" Offset="0" /> <GradientStop Color="White" Offset="0.15" /> <GradientStop Color="#EEE" Offset="1" /> </LinearGradientBrush> </Grid.Background> <Border Grid.Row="1" Grid.Column="0" Grid.ColumnSpan="2" Background="Black" /> <Border Grid.Row="0" Grid.Column="1" Grid.RowSpan="2" Background="Black" /> <Grid Grid.Row="0" Grid.Column="0" Margin="2"> <Grid.ColumnDefinitions> <ColumnDefinition Width="1" /> <ColumnDefinition Width="*" /> <ColumnDefinition Width="1" /> </Grid.ColumnDefinitions> <Grid.RowDefinitions> <RowDefinition Height="1" /> <RowDefinition Height="*" /> <RowDefinition Height="1" /> </Grid.RowDefinitions> <Border Grid.Row="0" Grid.Column="0" Grid.ColumnSpan="3" Background="Black" /> <Border Grid.Row="0" Grid.Column="0" Grid.RowSpan="3" Background="Black" /> <Border Grid.Row="2" Grid.Column="0" Grid.ColumnSpan="3" Background="#CCC" /> <Border Grid.Row="0" Grid.Column="2" Grid.RowSpan="3" Background="#CCC" /> <TextBlock Grid.Row="1" Grid.Column="1" TextAlignment="Right" HorizontalAlignment="Center" VerticalAlignment="Center" Padding="3 0 3 0" Background="Yellow" Text="{Binding RelativeSource={RelativeSource TemplatedParent}, Path=Text}" Width="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type Grid}, AncestorLevel=1}, Path=ActualWidth}" /> </Grid> </Grid> </ControlTemplate> </Setter.Value> </Setter> </Style> Update: Replacing the inner-most TextBox with a ScrollViewer and naming it PART_ContentHost indeed shows the text insertion cursor. Trying to right-align the text in the TextBox by either setting the HorizontalContentAlignment in the Style or as a property on the ScrollViewer were unsuccessful. Suggestions?

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  • Copying Columns from Grid to Clipboard in SQL Developer

    - by thatjeffsmith
    There are several ways to get data from a query or a table|view to the clipboard. You know the tried and true, copy and paste. But what if you only want one or more columns, not every column? There are several ways to do this, let’s see if we can’t identify all of them. Write your query to only include the data you want Obvious? Yes. Needed to be said? Definitely. The best tuning tip is to only ask for the data you need, only when you absolutely need it. But let’s look at a few more practical ways to do this. Hide the unwanted columns Mouse right click on an column header. In the context menu, select ‘Columns.’ Hide the columns you don’t want. Copy and paste. WYSIWYG Grids, Hide Columns and Filter Rows Mouse select the columns Obvious, but a bit painful. For a very large dataset, you’ll be holding down the Shift and PageDown buttons – but it works. Remember to use Ctrl+Shift+C to get the column headers with the data. Use the Export Wizard This used to be called ‘Unload’ – agreed, not a great name. So, we changed it. In a grid, right mouse click on the data, and on the context menu, select ‘Export…’ Select your format – I suggest ‘delimited’ or ‘fixed’ for copying data to the clipboard. You can export to the clipboard, yes you can! Click ‘Next.’ Click in the Columns dialog, and choose the columns you want copied. Trim the columns you don't want copied Click ‘Finish.’ Alt or Ctrl tab to your window or application of choice. And Paste! "FIRST_NAME" "LAST_NAME" "Donald" "OConnell" "Douglas" "Grant" "Jennifer" "Whalen" "Pat" "Fay" "Susan" "Mavris" "William" "Gietz" "Alexander" "Hunold" "Bruce" "Ernst" "David" "Austin" "Valli" "Pataballa" "Diana" "Lorentz" "Daniel" "Faviet" "John" "Chen" "Ismael" "Sciarra" "Jose Manuel" "Urman" "Luis" "Popp" "Alexander" "Khoo" "Shelli" "Baida" "Sigal" "Tobias" "Guy" "Himuro" "Karen" "Colmenares" "Matthew" "Weiss" "Adam" "Fripp" "Payam" "Kaufling" "Shanta" "Vollman" "Kevin" "Mourgos" "Julia" "Nayer" "Irene" "Mikkilineni" ... There’s probably at least 2 or 3 more ways, but… But, try these and let me know how we can improve things. I’ve already gotten a request to be able to include the SQL text used to populate the dataset on the the copy to clipboard, and it’s now on our to-do list

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  • WPF Login Verification Using Active Directory

    - by psheriff
    Back in October of 2009 I created a WPF login screen (Figure 1) that just showed how to create the layout for a login screen. That one sample is probably the most downloaded sample we have. So in this blog post, I thought I would update that screen and also hook it up to show how to authenticate your user against Active Directory. Figure 1: Original WPF Login Screen I have updated not only the code behind for this login screen, but also the look and feel as shown in Figure 2. Figure 2: An Updated WPF Login Screen The UI To create the UI for this login screen you can refer to my October of 2009 blog post to see how to create the borderless window. You can then look at the sample code to see how I created the linear gradient brush for the background. There are just a few differences in this screen compared to the old version. First, I changed the key image and instead of using words for the Cancel and Login buttons, I used some icons. Secondly I added a text box to hold the Domain name that you wish to authenticate against. This text box is automatically filled in if you are connected to a network. In the Window_Loaded event procedure of the winLogin window you can retrieve the user’s domain name from the Environment.UserDomainName property. For example: txtDomain.Text = Environment.UserDomainName The ADHelper Class Instead of coding the call to authenticate the user directly in the login screen I created an ADHelper class. This will make it easier if you want to add additional AD calls in the future. The ADHelper class contains just one method at this time called AuthenticateUser. This method authenticates a user name and password against the specified domain. The login screen will gather the credentials from the user such as their user name and password, and also the domain name to authenticate against. To use this ADHelper class you will need to add a reference to the System.DirectoryServices.dll in .NET. The AuthenticateUser Method In order to authenticate a user against your Active Directory you will need to supply a valid LDAP path string to the constructor of the DirectoryEntry class. The LDAP path string will be in the format LDAP://DomainName. You will also pass in the user name and password to the constructor of the DirectoryEntry class as well. With a DirectoryEntry object populated with this LDAP path string, the user name and password you will now pass this object to the constructor of a DirectorySearcher object. You then perform the FindOne method on the DirectorySearcher object. If the DirectorySearcher object returns a SearchResult then the credentials supplied are valid. If the credentials are not valid on the Active Directory then an exception is thrown. C#public bool AuthenticateUser(string domainName, string userName,  string password){  bool ret = false;   try  {    DirectoryEntry de = new DirectoryEntry("LDAP://" + domainName,                                           userName, password);    DirectorySearcher dsearch = new DirectorySearcher(de);    SearchResult results = null;     results = dsearch.FindOne();     ret = true;  }  catch  {    ret = false;  }   return ret;} Visual Basic Public Function AuthenticateUser(ByVal domainName As String, _ ByVal userName As String, ByVal password As String) As Boolean  Dim ret As Boolean = False   Try    Dim de As New DirectoryEntry("LDAP://" & domainName, _                                 userName, password)    Dim dsearch As New DirectorySearcher(de)    Dim results As SearchResult = Nothing     results = dsearch.FindOne()     ret = True  Catch    ret = False  End Try   Return retEnd Function In the Click event procedure under the Login button you will find the following code that will validate the credentials that the user types into the login window. C#private void btnLogin_Click(object sender, RoutedEventArgs e){  ADHelper ad = new ADHelper();   if(ad.AuthenticateUser(txtDomain.Text,         txtUserName.Text, txtPassword.Password))    DialogResult = true;  else    MessageBox.Show("Unable to Authenticate Using the                      Supplied Credentials");} Visual BasicPrivate Sub btnLogin_Click(ByVal sender As Object, _ ByVal e As RoutedEventArgs)  Dim ad As New ADHelper()   If ad.AuthenticateUser(txtDomain.Text, txtUserName.Text, _                         txtPassword.Password) Then    DialogResult = True  Else    MessageBox.Show("Unable to Authenticate Using the                      Supplied Credentials")  End IfEnd Sub Displaying the Login Screen At some point when your application launches, you will need to display your login screen modally. Below is the code that you would call to display the login form (named winLogin in my sample application). This code is called from the main application form, and thus the owner of the login screen is set to “this”. You then call the ShowDialog method on the login screen to have this form displayed modally. After the user clicks on one of the two buttons you need to check to see what the DialogResult property was set to. The DialogResult property is a nullable type and thus you first need to check to see if the value has been set. C# private void DisplayLoginScreen(){  winLogin win = new winLogin();   win.Owner = this;  win.ShowDialog();  if (win.DialogResult.HasValue && win.DialogResult.Value)    MessageBox.Show("User Logged In");  else    this.Close();} Visual Basic Private Sub DisplayLoginScreen()  Dim win As New winLogin()   win.Owner = Me  win.ShowDialog()  If win.DialogResult.HasValue And win.DialogResult.Value Then    MessageBox.Show("User Logged In")  Else    Me.Close()  End IfEnd Sub Summary Creating a nice looking login screen is fairly simple to do in WPF. Using the Active Directory services from a WPF application should make your desktop programming task easier as you do not need to create your own user authentication system. I hope this article gave you some ideas on how to create a login screen in WPF. NOTE: You can download the complete sample code for this blog entry at my website: http://www.pdsa.com/downloads. Click on Tips & Tricks, then select 'WPF Login Verification Using Active Directory' from the drop down list. Good Luck with your Coding,Paul Sheriff ** SPECIAL OFFER FOR MY BLOG READERS **We frequently offer a FREE gift for readers of my blog. Visit http://www.pdsa.com/Event/Blog for your FREE gift!

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  • Why won't my WPF XAML Grid TranslateTransform.X ?

    - by George
    I'm able to change the width/height of the grid using this, so why won't it work when I use (Grid.RenderTransform).TranslateTransform.X as such: <Window.Triggers> <EventTrigger RoutedEvent="Button.Click" SourceName="button"> <BeginStoryboard> <Storyboard> <DoubleAnimation Storyboard.TargetProperty="(Grid.RenderTransform).(TranslateTransform.X)" From="0" To="200" Storyboard.TargetName="grid" Duration="0:0:2" /> </Storyboard> </BeginStoryboard> </EventTrigger> </Window.Triggers> The application loads etc, but nothing happens when the button is clicked. Here is the XAML for my grid: <Grid x:Name="grid" Height="714" Canvas.Left="240" Canvas.Top="8" Width="360" RenderTransformOrigin="0.5,0.5"> <Grid.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="Black" Offset="0"/> <GradientStop Color="White" Offset="1"/> </LinearGradientBrush> </Grid.Background> <Grid.ColumnDefinitions> <ColumnDefinition Width="0*"/> <ColumnDefinition/> </Grid.ColumnDefinitions> </Grid> Note that I've tried many different Canvas.Left values, to no avail.

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  • WPF opening up exe program within WPF window

    - by SwiftLion
    Not sure if this is possible but is there a way to open up another program like notepad within the container of a WPF window? similiar to that of being able to open a web page using the webbrowser control? Basically I would like to open notepad or other exe but keep it constrained within the WPF window container using xaml/c# code? not sure if possible?

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  • wpf how to get all TextBoxes in wpf application

    - by GC87
    Hi, I'm trying to learn how to do proper wpf application and now I have a big trouble. I know how I would do this if I had to do it with Windows Forms, but I don't know how to modify it to fit with wpf. Would someone know the answer? Here is my code for Windows Forms Form_loaded event: foreach (Control ctrl in this.Controls) { if (ctrl is TextBox) { ctrl.Text = ""; } }

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  • Disabling Minimize and Maximize buttons in a WPF Window

    - by marianor
    In WPF there is no possibility to control when the Minimize and Maximize buttons are disabled when the WindowStyle is SingleBorderWindow or ThreeDBorderWindow . In Windows Forms there are some properties like ControlBox , MinimizeBox and MaximizeBox that allow to do that. Because the WPF window internally has a hWnd we can do this using Windows API ( GetWindowLong and SetWindowLong will do the trick). I did three attached properties applicable to Window that use the internal API, in order to disable...(read more)

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  • WPF Templates error - "Provide value on 'System.Windows.Baml2006.TypeConverterMarkupExtension' threw

    - by jasonk
    I've just started experimenting with WPF templates vs. styles and I'm not sure what I'm doing wrong. The goal below is to alternate the colors of the options in the menu. The code works fine with just the , but when I copy and paste/rename it for the second segment of "MenuChoiceOdd" I get the following error: Provide value on 'System.Windows.Baml2006.TypeConverterMarkupExtension' threw an exception. Sample of the code: <Window x:Class="WpfApplication1.Template_Testing" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="Template_Testing" Height="300" Width="300"> <Grid> <Grid.Resources> <ControlTemplate x:Key="MenuChoiceEven"> <Border BorderThickness="1" BorderBrush="#FF4A5D80"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="0" Width="Auto" FontSize="14" Foreground="SlateGray" TextAlignment="Left" AllowDrop="True" Text="{Binding Path=Content, RelativeSource={RelativeSource TemplatedParent}}"> <TextBlock.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="White" Offset="0" /> <GradientStop Color="#FFC2CCDB" Offset="1" /> </LinearGradientBrush> </TextBlock.Background> </TextBlock> </Border> </ControlTemplate> <ControlTemplate x:Key="MenuChoiceOdd"> <Border BorderThickness="1" BorderBrush="#FF4A5D80"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="0" Width="Auto" FontSize="14" Foreground="SlateGray" TextAlignment="Left" AllowDrop="True" Text="{Binding Path=Content, RelativeSource={RelativeSource TemplatedParent}}"> <TextBlock.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="White" Offset="0" /> <GradientStop Color="##FFCBCBCB" Offset="1" /> </LinearGradientBrush> </TextBlock.Background> </TextBlock> </Border> </ControlTemplate> </Grid.Resources> <Border BorderBrush="SlateGray" BorderThickness="2" Margin="10" CornerRadius="10" Background="LightSteelBlue" Width="200"> <StackPanel Margin="4"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="2,2,2,0" Name="MenuHeaderTextBlock" Text="TextBlock" Width="Auto" FontSize="16" Foreground="PaleGoldenrod" TextAlignment="Left" Padding="10" FontWeight="Bold"><TextBlock.Background><LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"><GradientStop Color="LightSlateGray" Offset="0" /><GradientStop Color="DarkSlateGray" Offset="1" /></LinearGradientBrush></TextBlock.Background></TextBlock> <StackPanel Height="Auto" HorizontalAlignment="Stretch" Margin="2,0,2,0" Name="MenuChoicesStackPanel" VerticalAlignment="Top" Width="Auto"> <Button Template="{StaticResource MenuChoiceEven}" Content="Test Even menu element" /> <Button Template="{StaticResource MenuChoiceOdd}" Content="Test odd menu element" /> </StackPanel> </StackPanel> </Border> </Grid> </Window> What am I doing wrong?

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  • Required Skill Sets Of A Software Architect

    The question has been asked as to what is the required skill sets of a software architect. The answer to this is that it truly depends. When I state that it depend, it depends on the organization, industry, and skill sets available on the open market and internally within a company. With open ended skill sets even Napoleon Dynamite could be an architect. Napoleon Dynamite’s Skills Pedro: Have you asked anybody yet? Napoleon Dynamite: No, but who would? I don't even have any good skills. Pedro: What do you mean? Napoleon Dynamite: You know, like nunchuck skills, bow hunting skills, computer hacking skills... Girls only want boyfriends who have great skills. Pedro: Aren't you pretty good at drawing, like animals and warriors and stuff? This example might be a little off base but it does illustrate a point. What are the real required skills of a software architect? In my opinion, an architect needs to demonstrate the knowledge of the following three main skill set categories so that they are successful. General Skill Sets of an Architect Basic Engineering Skills Organizational  Skills Interpersonal Skills Basic Engineering Skills are a very large part of what a software architect deal with on a daily bases when designing or updating systems. Think about it, how good would a lead mechanic be if they did not know how to fix or repair cars? They would not be, and that is my point that architects need to have at least some basic skills regarding engineering. The skills listed below are generic in nature because they change from job to job, so in this discussion I am trying to focus more on generalities so that anyone can apply this information to their individual situation. Common Basic Engineering Skills Data Modeling Code Creation Configuration Testing Deployment/Publishing System and Environment Knowledge Organizational Skills If an Architect works for or with an origination then they will need strong organization skills to survive. An architect is no use to a project if the project is missed managed. Additionally, budgets and timelines can really affect a company and their products when established deadlines are repeated not meet. By not meeting these timelines a company is forced to cancel the project and waste all the money and time spent or spend more money until it is completed, if it is ever completed. Common Organizational Skills Project Management Estimation (Cost and Time) Creation and Maintenance of Accepted Standards Interpersonal Skills For me personally Interpersonal skill ranks above the other types of skill sets because an architect can quickly pick up the other two skill sets by communicating with other team/project members so that they are quickly up to speed on a project. Additionally, in order for an architect to manage a project or even derive rough estimates they will more than likely have to consult with others actually working on the code (Programmers/Software Engineers) to get there estimates since they will be the ones actually working on the changes to be implemented. Common Interpersonal Skills Good Communicator Focus on projects success over personal Honors roles within a team Reference: Taylor, R. N., Medvidovic, N., & Dashofy, E. M. (2009). Software architecture: Foundations, theory, and practice Hoboken, NJ: John Wiley & Sons

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  • What is the WPF equivilant for the FlowLayoutPanel?

    - by Sargola
    I am working on a WPF application (a one note clone which is called "note your life") where you can dynamically assign Tags to an entry (just as in virtually any web 2.0 app these days). for this I had in my windows forms prototype a FlowLayoutPanel that did the job very well. I want to have the tags float to the next line if there isn't enough space and get a scrollbar if needed. how can this be achieved with WPF? I played around with <StackPanel Orientation="Horizontal" FlowDirection="LeftToRight" ...> but this doesn't move the elements in the next line if needed. Any suggestions?

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  • WPF - simple relative path - FindAncestor

    - by user309392
    In the XAML below the ToolTip correctly binds to RelativeSource Self. However, I can't for the life of me work out how to get the TextBlock in the commented block to refer to SelectedItem.Description <Controls:RadComboBoxWithCommand x:Name="cmbPacking" Grid.Row="2" Grid.Column="5" ItemsSource="{Binding PackingComboSource}" DisplayMemberPath="DisplayMember" SelectedValuePath="SelectedValue" SelectedValue="{Binding ElementName=dataGrid1, Path=SelectedItem.PackingID}" ToolTip="{Binding RelativeSource={RelativeSource Self}, Path=SelectedItem.Description}" IsSynchronizedWithCurrentItem="True" Style="{StaticResource comboBox}"> <!-- <Controls:RadComboBoxWithCommand.ToolTip>--> <!-- <TextBlock Text="{Binding RelativeSource={RelativeSource Self}, Path=SelectedItem.Description}" TextWrapping="Wrap" Width="50"/>--> <!-- </Controls:RadComboBoxWithCommand.ToolTip>--> </Controls:RadComboBoxWithCommand> I would appreciate any suggestions Thanks - Jeremy

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  • forcing Validation; WPF, DataGrid, ObservableCollection

    - by Steve Mills
    I have a WPF DataGrid. I read a csv file and build an ObservableCollection of objects. I set the DataGrid.ItemsSource to the Collection. I would like to then force a RowValidation on every row in the DataGrid. If I, playing user, edit a cell, the RowValidation fires, all is well. But the Validation does not fire on the initial load. Is there some way I can call ??ValidateRow?? on a row? on every row? (C#, WPF, VS2008, etc)

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  • Winform custom control in WPF

    - by Erika
    Hi, I'm inserting a custom winform control in a WPF/ XAML window, however i'm realising that the sizing seems to be very different, what i designed in winform to be 730pixels wide for instance, when placed via a WindowsFormsHost, in a container 730pixels (or at least i think they're pixels..) wide, the control looks much larger and doesnt fit in the host and results in clipping from the right and bottom. Would anyone know how to make these sizes match or something? I'm really at a loss and its very difficult to fix a custom control to make it look as it should off hand on WPF! Please help!

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  • wpf trigger events after a few milli-seconds!!!

    - by Rev
    Hi What was that "wpf trigger events after a few Milli-seconds" ;) Let me explain about that: I have a wpf form with few controls. some of these control over-writing template. for example a textblock with an effect will be trigger on Mouse-Enter event and change color of foreground to something else. But after running program when mouse enter on textBloc, it takes a few Milli-seconds until Mouse-enter event triggers. also all control or better say all control which use mouse-events have this problem. How solve this problem???

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  • WPF Localization Using LocBaml: Handling Special Symbols

    - by Aryeh
    Hello, I’m dealing with localization of a WPF application (Visual Studio 2010 under Windows 7). I’ve just accomplished the whole process of localization using LocBaml tool, as explained in WPF Globalization and Localization Overview and in related posts. The target language is Italian (it-IT culture). When I run my application in Italian, I have a problem with interpretation of the special symbols of © and ™: they both appear there as a white question sign upon a black diamond-shaped background. The symbols © and ™ appear identically in both English and Italian CSV-files. I tried also the special letters (such as È, à etc.) that are present in Italian but absent in English, and they also are interpreted as the above diamond-shaped question. In Region and Language, I changed the system locale to Italian[Italy], restarted the PC and ran the application again – this helped me in the past to cope with a similar problem in localization of C++ applications under Windows XP, but now it didn’t help, either. Has somebody any idea what is the catch here?

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  • HttpWebRequest socket operation during WPF binding in a property getter

    - by wpfwannabe
    In a property getter of a C# class I am doing a HTTP GET using HttpWebRequest to some https address. WPF's property binding seems to choke on this. If I try to access the property in a simple method e.g. Button_Clicked, it works perfectly. If I use WPF binding to access the same property, the app seems to be blocked on a socket's recv() method indefinitely. Is it a no-no to do this sort of thing during binding? Is app in some special state during binding? Is there an easy way for me to overcome this limitation and still maintain the same basic idea?

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  • WPF 4 Datagrid with ComboBox

    - by Doug
    I have a WPF 4 app with a ComboBox embedded in a DataGrid. The ComboBox is in a template column that displays the combobox when in edit mode but just a TextBlock otherwise. If I edit the cell and pick a new value from the combobox, when leaving the cell, the TextBlock in view mode does not reflect the new value. Ultimately, the new value gets saved and is displayed when the window is refreshed but it does not happen while still editing in the grid. Here are the parts that are making this more complicated. The grid and the combobox are bound to different ItemsSource from the EnityFramework which is tied to my database. For this problem, the grid is displaying project members. The project member name can be picked from the combobox which gives a list of all company employees. Any ideas on how to tie the view mode of the DataGridColumnTemplate to the edit value when they are pointing to different DataSources? Relevant XAML <Window.Resources> <ObjectDataProvider x:Key="EmployeeODP" /> </Window.Resources> <StackPanel> <DataGrid Name="teamProjectGrid" AutoGenerateColumns="false" ItemsSource="{Binding Path=ProjectMembers}" <DataGrid.Columns> <DataGridTemplateColumn Header="Name" x:Name="colProjectMember"> <DataGridTemplateColumn.CellTemplate> <DataTemplate> <TextBlock Text="{Binding Path=ProjectMemberFullName}" /> </DataTemplate> </DataGridTemplateColumn.CellTemplate> <DataGridTemplateColumn.CellEditingTemplate> <DataTemplate> <ComboBox x:Name="ProjectMemberCombo" IsReadOnly="True" DisplayMemberPath="FullName" SelectedValue="{Binding Path=Employee}" ItemsSource="{Binding Source={StaticResource EmployeeODP}}" /> </DataTemplate> </DataGridTemplateColumn.CellEditingTemplate> </DataGridTemplateColumn> <DataGridTextColumn x:Name="colProjectRole" Binding="{Binding Path=ProjectRole}" Header="Role" /> </DataGrid.Columns> </DataGrid> </StackPanel> Relevant Code Behind this.DataContext = new MyEntityLibrary.MyProjectEntities(); ObjectDataProvider EmployeeODP= (ObjectDataProvider)FindResource("EmployeeODP"); if (EmployeeODP != null) { EmployeeODP.ObjectInstance = this.DataContext.Employees; }

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