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  • Variable length Blob in hibernate?

    - by Seth
    I have a byte[] member in one of my persistable classes. Normally, I'd just annotate it with @Lob and @Column(name="foo", size=). In this particular case, however, the length of the byte[] can vary a lot (from ~10KB all the way up to ~100MB). If I annotate the column with a size of 128MB, I feel like I'll be wasting a lot of space for the small and mid-sized objects. Is there a variable length blob type I can use? Will hibernate take care of all of this for me behind the scenes without wasting space? What's the best way to go about this? Thanks!

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  • derby + hibernate ConstraintViolationException using manytomany relationships

    - by user364470
    Hi, I'm new to Hibernate+Derby... I've seen this issue mentioned throughout the google, but have not seen a proper resolution. This following code works fine with mysql, but when I try this on derby i get exceptions: ( each Tag has two sets of files and vise-versa - manytomany) Tags.java @Entity @Table(name="TAGS") public class Tags implements Serializable { @Id @GeneratedValue(strategy=GenerationType.AUTO) public long getId() { return id; } @ManyToMany(targetEntity=Files.class ) @ForeignKey(name="USER_TAGS_FILES",inverseName="USER_FILES_TAGS") @JoinTable(name="USERTAGS_FILES", joinColumns=@JoinColumn(name="TAGS_ID"), inverseJoinColumns=@JoinColumn(name="FILES_ID")) public Set<data.Files> getUserFiles() { return userFiles; } @ManyToMany(mappedBy="autoTags", targetEntity=data.Files.class) public Set<data.Files> getAutoFiles() { return autoFiles; } Files.java @Entity @Table(name="FILES") public class Files implements Serializable { @Id @GeneratedValue(strategy=GenerationType.AUTO) public long getId() { return id; } @ManyToMany(mappedBy="userFiles", targetEntity=data.Tags.class) public Set getUserTags() { return userTags; } @ManyToMany(targetEntity=Tags.class ) @ForeignKey(name="AUTO_FILES_TAGS",inverseName="AUTO_TAGS_FILES") @JoinTable(name="AUTOTAGS_FILES", joinColumns=@JoinColumn(name="FILES_ID"), inverseJoinColumns=@JoinColumn(name="TAGS_ID")) public Set getAutoTags() { return autoTags; } I add some data to the DB, but when running over Derby these exception turn up (the don't using mysql) Exceptions SEVERE: DELETE on table 'FILES' caused a violation of foreign key constraint 'USER_FILES_TAGS' for key (3). The statement has been rolled back. Jun 10, 2010 9:49:52 AM org.hibernate.event.def.AbstractFlushingEventListener performExecutions SEVERE: Could not synchronize database state with session org.hibernate.exception.ConstraintViolationException: could not delete: [data.Files#3] at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:96) at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66) at org.hibernate.persister.entity.AbstractEntityPersister.delete(AbstractEntityPersister.java:2712) at org.hibernate.persister.entity.AbstractEntityPersister.delete(AbstractEntityPersister.java:2895) at org.hibernate.action.EntityDeleteAction.execute(EntityDeleteAction.java:97) at org.hibernate.engine.ActionQueue.execute(ActionQueue.java:268) at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:260) at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:184) at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:321) at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:51) at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1206) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:613) at org.hibernate.context.ThreadLocalSessionContext$TransactionProtectionWrapper.invoke(ThreadLocalSessionContext.java:344) at $Proxy13.flush(Unknown Source) at data.HibernateORM.removeFile(HibernateORM.java:285) at data.DataImp.removeFile(DataImp.java:195) at booting.DemoBootForTestUntilTestClassesExist.main(DemoBootForTestUntilTestClassesExist.java:62) I have never used derby before so maybe there is something crutal that i'm missing 1) what am I doing wrong? 2) is there any way of cascading properly when I have 2 many-to-many relationships between two classes? Thanks!

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  • hibernate not picking sessionFactory

    - by Satya
    My application-context.xml is <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd"> <beans> <bean id="myDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName"><value>com.mysql.jdbc.Driver</value></property> <property name="url"><value>jdbc:mysql://localhost:3306/myDB</value></property> <property name="username"><value>myUser</value></property> <property name="password"><value>myUser</value></property> </bean> <bean id="mySessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="mappingResources"> <property name="dataSource"><ref bean="myDataSource"/></property> <list> <value>com/x/model/config/hibernate/user.hbm.xml</value> </list> </property> <property name="hibernateProperties" > <value> hibernate.dialect=org.hibernate.dialect.MySQLDialect </value> </property> </bean> <bean id="userdao" class="com.x.y.z.UserDao"> <property name="sessionFactory"><ref bean="mySessionFactory"/></property> </bean> </beans> user.hbm.xml is <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="com.cpt.model"> <class name="User" table="user"> <id name="userId" column="id"> <generator class="native"/> </id> <property name="firstname" column="firstName" /> <property name="lastName" column="lastName"/> <property name="login" column="login"/> <property name="pass" column="pass"/> <property name="superemail" column="superEmail"/> </class> </hibernate-mapping> and the UserDao is package com.x.y.z; import java.sql.Connection; import java.sql.DriverManager; import java.sql.SQLException; import java.sql.Statement; import org.hibernate.HibernateException; import org.hibernate.Session; import org.hibernate.SessionFactory; import org.hibernate.cfg.Configuration; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.orm.hibernate.support.HibernateDaoSupport; import org.springframework.stereotype.Component; import com.x.model.User; @Component public class UserDao { private SessionFactory sessionFactory; public void addUser(User user) { Session session; try { try { session = getSessionFactory().openSession(); // session = sessionFactory.openSession(); session.save(user); } catch (RuntimeException e) { // TODO Auto-generated catch block e.printStackTrace(); } } catch (HibernateException e) { // TODO Auto-generated catch block System.out.println("printing in the catch"); e.printStackTrace(); } } public SessionFactory getSessionFactory() { System.out.println("returning session factory ::: sessionFactory == null :: "+sessionFactory.openSession()); return sessionFactory; } public void setSessionFactory(SessionFactory sessionFactory) { System.out.println("this is setting session factory" + sessionFactory.getClass()); System.out.println("setting session factory ::: sessionFactory == null :: "+sessionFactory==null); this.sessionFactory = sessionFactory; System.out.println("setting session factory ::: sessionFactory == null :: "+this.sessionFactory.openSession().getClass()); System.out.println(getSessionFactory().openSession().isOpen()); } } However, I keep getting 14:45:09,929 INFO [org.hibernate.impl.SessionFactoryImpl] building session fact ory 14:45:09,933 WARN [net.sf.ehcache.config.Configurator] No configuration found. Configuring ehcache from ehcache-failsafe.xml found in the classpath: vfs:/C:/jb /server/default/deploy/C.war/WEB-INF/lib/ehcache-1.1.jar/ehcache-failsafe.xml 14:45:10,007 INFO [org.hibernate.impl.SessionFactoryObjectFactory] Not binding factory to JNDI, no JNDI name configured 14:45:10,008 INFO [org.hibernate.impl.SessionFactoryImpl] Checking 0 named quer ies 14:45:10,017 INFO [STDOUT] this is setting session factoryclass $Proxy178 14:45:10,017 INFO [STDOUT] false 14:45:10,019 INFO [STDOUT] setting session factory ::: sessionFactory == null : : class org.hibernate.impl.SessionImpl 14:45:10,020 INFO [STDOUT] returning session factory ::: sessionFactory == null :: org.hibernate.impl.SessionImpl(PersistentContext[entitiesByKey={}] ActionQue ue[insertions=[] updates=[] deletions=[] collectionCreations=[] collectionRemova ls=[] collectionUpdates=[]]) It is giving sessionFactory null . Any Idea where am I failing ? Thanks

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  • Getting a CFG form the CFL

    - by Kristian
    Can Any One explain this Language how we converted to CFG Give a CFG for the CFL: {ai bj ck | i ? j or j ? k } //ai mean a^i I have the answer but I need an explaination (Step By Step) The answer : S --> S1|S2 S1 --> A Eab|Eab B|S1 c A --> a|aA B--> b|bB Eab --> Q|a Eab b S2 --> Eac C|A Eac C --> c|cC Eac --> Q|B|a Eac c

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  • JPA hibernate OneToOne mapping

    - by Stupidfrog
    enviroment: hibernate 4.1.6.final spring 3.1.2.release spring jpa 1.1.0.release postgresql 9.1-901-1.jdbc4 there is 2 table public A { private Long id; private Long name; } public B { private Long id; private Long table_a_id; } the A.id and B.id is sequential, unique , but no related.(means they are separately id for their own table). how to do mapping? i have tried some method, however the result is not i wanted, because it bind wrong. for example: public A { .... @OneToOne @JoinColumn(name = "id") private B table_b } public B { ... @JsonIgnore @OneToOne(mappedBy = "table_b") private A table_a; } when i query A the result is { "id":5, "table_b":{ "id":5, "table_a_id":4 } } obviously the data join by using their id but not joining using table_a_id. what i expect is { "id":4, "table_b":{ "id":5, "table_a_id":4 } } so can somebody teach me that, how to map this 2 table by using table b table_a_id(foregin key)

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  • Can we replace XML with JSON entirely?

    - by Saeed Neamati
    I'm sure lots of developers are familiar with XML and JSON, and they've used both of them. Thus no point in explaining what they are, and what is their purpose, even in brief. If we try to map their concepts, we can say (correct me if I'm wrong): XML tags are equivalent to JSON {} XML attributes are equivalent to JSON properties XML tag collection is equivalent to JSON [] The only thing I can think of, which doesn't exist in JSON, is XML Namespaces. The question is, considering this mapping, and considering that JSON is highly lighter in this mapping, can we see a world in future (or at least theoretically think of a world) without XML, but with JSON doing everything XML does? Can we use JSON everywhere XML is used? PS: Please note that I've seen this question. It's something entirely different from what I'm asking here. Thus please don't mention duplicate.

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  • Loading a new instance of a class through XML not working quite right

    - by Thegluestickman
    I'm having trouble with XML and XNA. I want to be able to load weapon settings through XML to make my weapons easier to make and to have less code in the actual project file. So I started out making a basic XML document, something to just assign variables with. But no matter what I changed it gave me a new error every time. The code below gives me a "XML element 'Tag' not found", I added and it started to say the variables weren't found. What I wanted to do in the XML file as well, was load a texture for the file too. So I created a static class to hold my texture values, then in the Texture tag of my XML document I would set it to that instance too. I think that's were the problems are occuring because that's where the "XML element 'Tag' not found" error is pointing me too. My XML document: <XnaContent> <Asset Type="ConversationEngine.Weapon"> <weaponStrength>0</weaponStrength> <damageModifiers>0</damageModifiers> <speed>0</speed> <magicDefense>0</magicDefense> <description>0</description> <identifier>0</identifier> <weaponTexture>LoadWeaponTextures.ironSword</weaponTexture> </Asset> </XnaContent> My Class to load the weapon XML: public static class LoadWeaponXML { static Weapon Weapons; public static Weapon WeaponLoad(ContentManager content, int id) { Weapons = content.Load<Weapon>(@"Weapons/" + id); return Weapons; } } public static class LoadWeaponTextures { public static Texture2D ironSword; public static void TextureLoad(ContentManager content) { ironSword = content.Load<Texture2D>("Sword"); } } I'm not entirely sure if you can load textures through XML, but any help would be greatly appreciated.

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  • Receive the Broadcast program with XML [on hold]

    - by bitmez4
    I have a channel publishing sites and I wanna get into the channel CNN broadcast program.. CNN broadcast the program here: (you can see in source - xml File) http://tvprofil.net/xmltv/data/cnn.info/weekly_cnn.info_tvprofil.net.xml How the data according to the time of withdrawal? For example: Now program: "bitmez's table" next program: "stack's table" in 30 minute Is this possible? UPDATE 1 // -I can take the XML data but to all of XML file- <?php if(!$xml=simplexml_load_file('http://tvprofil.net/xmltv/data/cnn.info/weekly_cnn.info_tvprofil.net.xml')){ trigger_error('XML file -- read error',E_USER_ERROR); } echo 'X-'; foreach($xml as $programme){ echo 'Now: '.$programme->title.' <br/>'; } ?>

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  • Spring-hibernate mapping problem

    - by James
    I have a spring-hibernate application which is failing to map an object properly: basically I have 2 domain objects, a Post and a User. The semantics are that every Post has 1 corresponding User. The Post domain object looks roughly as follows: class Post { private int pId; private String attribute; ... private User user; //getters and setters here } As you can see, Post contains a reference to User. When I load a Post object, I want to corresponding User object to be loaded (lazily - only when its needed). My mapping looks as follows: <class name="com...Post" table="post"> <id name="pId" column="PostId" /> <property name="attribute" column="Attribute" type="java.lang.String" /> <one-to-one name="User" fetch="join" class="com...User"></one-to-one> </class> And of course I have a basic mapping for User set up. As far as my table schema is concerned, I have a table called post with a foreign UserId which links to the user table. I thought this setup should work, BUT when I load a page that forces the lazy loading of the User object, I notice the following Hiberate query being generated: Select ... from post this_ left outer join user user2_ on this.PostId=user2_.UserId ... Obviously this is wrong: it should be joining UserId from post with UserId from user, but instead its incorrectly joining PostId from post (its primary key) with UserId from user. Any ideas? Thanks!

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  • Mapping Hashmap of Coordinates in Hibernate with Annotation

    - by paddydub
    I've just started using hibernate and I'm trying to map walking distance between two coordinates into a hashmap, There can be many connections from one "FromCoordinate" to another "ToCoordinate". I'm not sure if i've implemented this correctly, What annotations do i need to map this MashMap? Thanks HashMap coordWalkingConnections = new HashMap(); @Entity @Table(name = "COORDCONNECTIONS") public class CoordinateConnection implements Serializable{ private static final long serialVersionUID = -1624745319005591573L; /** auto increasing id number */ @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "ID") @id private int id; @Embedded public FromCoordinate fromCoord; @Embedded public ToCoordinate toCoord; HashMap<FromCoordinate, ArrayList<ToCoordinate >> coordWalkingConnections = new HashMap<FromCoordinate, ArrayList<ToCoordinate >>(); } public class FromCoordinate implements ICoordinate { @Column(name = "FROM_LAT") private double latitude; @Column(name = "FROM_LNG") private double longitude; } public class ToCoordinate implements ICoordinate { @Column(name = "TO_LAT") private double latitude; @Column(name = "TO_LNG") private double longitude; @Column(name = "DISTANCE") private double distance; } DATABASE STRUCTURE id FROM_LAT FROM_LNG TO_LAT TO_LNG Dist 1 43.352669 -6.264341 43.350012 -6.260653 0.38 2 43.352669 -6.264341 43.352669 -6.264341 0.00 3 46.352669 -6.264341 43.353373 -6.262013 0.17 4 47.352465 -6.265865 43.351290 -6.261200 0.25 5 45.452578 -6.265768 43.352788 -6.264396 0.01 6 45.452578 -6.265768 45.782788 -6.234523 0.01 ..... ... . Example HashMap for HashMap<Coordinate, ArrayList<Coordinate>> <KEY{43.352669 -6.264341}, Arraylist VALUES{(43.350012,-6.260653,0.383657), (43.352669, -6.264341, 0.000095), (43.353373, -6.262013, 0.173201)}> <KEY{47.352465 -6.265865}, Arraylist VALUES{(43.351290,-6.261200,0.258781)}> <KEY{45.452578 -6.265768}, Arraylist VALUES{(43.352788,-6.264396,0.013726),(45.782788,-6.234523,0.017726)}>

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  • Hibernate Mapping Annotation Question?

    - by paddydub
    I've just started using hibernate and I'm trying to map walking distance between two coordinates into a hashmap, There can be many connections from one "FromCoordinate" to another "ToCoordinate". I'm not sure if i've implemented this correctly, What annotations do i need to map this MashMap? Thanks @Entity @Table(name = "COORDCONNECTIONS") public class CoordinateConnection implements Serializable{ private static final long serialVersionUID = -1624745319005591573L; /** auto increasing id number */ @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "ID") @id private int id; @Embedded public FromCoordinate fromCoord; @Embedded public ToCoordinate toCoord; HashMap<Coordinate, ArrayList<Coordinate>> coordWalkingConnections = new HashMap<Coordinate, ArrayList<Coordinate>>(); } public class FromCoordinate implements ICoordinate { @Column(name = "FROM_LAT") private double latitude; @Column(name = "FROM_LNG") private double longitude; } public class ToCoordinate implements ICoordinate { @Column(name = "TO_LAT") private double latitude; @Column(name = "TO_LNG") private double longitude; @Column(name = "DISTANCE") private double distance; } DATABASE STRUCTURE id FROM_LAT FROM_LNG TO_LAT TO_LNG Dist 1 43.352669 -6.264341 43.350012 -6.260653 0.38 2 43.352669 -6.264341 43.352669 -6.264341 0.00 3 46.352669 -6.264341 43.353373 -6.262013 0.17 4 47.352465 -6.265865 43.351290 -6.261200 0.25 5 45.452578 -6.265768 43.352788 -6.264396 0.01 6 45.452578 -6.265768 45.782788 -6.234523 0.01 ..... ... . Example HashMap for HashMap<Coordinate, ArrayList<Coordinate>> <KEY{43.352669 -6.264341}, Arraylist VALUES{(43.350012,-6.260653,0.383657), (43.352669, -6.264341, 0.000095), (43.353373, -6.262013, 0.173201)}> <KEY{47.352465 -6.265865}, Arraylist VALUES{(43.351290,-6.261200,0.258781)}> <KEY{45.452578 -6.265768}, Arraylist VALUES{(43.352788,-6.264396,0.013726),(45.782788,-6.234523,0.017726)}>

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  • Java Hibernate/C3P0 error: "Could not obtain connection metadata. An attempt by a client to checkout

    - by Allan
    I'm trying to get some code I was passed up and running. It appears to use the Hibernate framework. I've gotten past most of the errors tweaking the configuration, but this one has me dead stumped. It's trying to connect to two databases: gameapp and gamelog. Both exist. It seems to have issues connecting to gamelog, but none connecting to gameapp (later in the init, it connects to and loads other DBs just fine). Below, I've pasted the error and exception stack dump. I imaging there's something else in the configs, so I've also included the configuration file for that db. I know this is very vague, but I'm hoping some pro can see the stupid mistake I'm missing. <?xml version="1.0" encoding="GBK"?> <!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> <hibernate-configuration> <session-factory> <property name="dialect">org.hibernate.dialect.MySQLDialect</property> <property name="connection.driver_class">com.mysql.jdbc.Driver</property> <property name="connection.url">jdbc:mysql://127.0.0.1:3306/gamelog</property> <property name="connection.username">root</property> <property name="connection.password"></property> <property name="connection.useUnicode">true</property> <property name="connection.characterEncoding">UTF-8</property> <property name="hibernate.jdbc.batch_size">100</property> <property name="jdbc.fetch_size">1</property> <property name="hbm2ddl.auto">none</property><!-- update --> <property name="connection.useUnicode">true</property> <property name="show_sql">true</property> <!-- c3p0-configuration --> <property name="hibernate.connection.provider_class">org.hibernate.connection.C3P0ConnectionProvider</property> <property name="hibernate.c3p0.min_size">5</property> <property name="hibernate.c3p0.max_size">10</property> <property name="hibernate.c3p0.timeout">30</property> <property name="hibernate.c3p0.idle_test_period">30</property> <property name="hibernate.c3p0.max_statements">0</property> <property name="hibernate.c3p0.acquire_increment">5</property> </session-factory> </hibernate-configuration> Exception and stack trace: 2010-04-30 17:50:00,411 WARN [org.hibernate.cfg.SettingsFactory] - Could not obtain connection metadata java.sql.SQLException: An attempt by a client to checkout a Connection has timed out. at com.mchange.v2.sql.SqlUtils.toSQLException(SqlUtils.java:106) at com.mchange.v2.sql.SqlUtils.toSQLException(SqlUtils.java:65) at com.mchange.v2.c3p0.impl.C3P0PooledConnectionPool.checkoutPooledConnection(C3P0PooledConnectionPool.java:527) at com.mchange.v2.c3p0.impl.AbstractPoolBackedDataSource.getConnection(AbstractPoolBackedDataSource.java:128) at org.hibernate.connection.C3P0ConnectionProvider.getConnection(C3P0ConnectionProvider.java:35) at org.hibernate.cfg.SettingsFactory.buildSettings(SettingsFactory.java:76) at org.hibernate.cfg.Configuration.buildSettings(Configuration.java:1933) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1216) at com.database.hibernate.util.HibernateFactory.<init>(Unknown Source) at com.database.hibernate.util.HibernateUtil.<clinit>(Unknown Source) at com.server.databaseop.goodOp.GoodOpImpl.initBreedGoods(Unknown Source) at com.server.databaseop.goodOp.GoodOpImpl.access$000(Unknown Source) at com.server.databaseop.goodOp.GoodOpImpl$1.run(Unknown Source) at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:471) at java.util.concurrent.FutureTask$Sync.innerRunAndReset(FutureTask.java:351) at java.util.concurrent.FutureTask.runAndReset(FutureTask.java:178) at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.access$201(ScheduledThreadPoolExecutor.java:165) at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.run(ScheduledThreadPoolExecutor.java:267) at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1110) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:603) at java.lang.Thread.run(Thread.java:636) Caused by: com.mchange.v2.resourcepool.TimeoutException: A client timed out while waiting to acquire a resource from com.mchange.v2.resourcepool.BasicResourcePool@ca470 -- timeout at awaitAvailable() at com.mchange.v2.resourcepool.BasicResourcePool.awaitAvailable(BasicResourcePool.java:1317) at com.mchange.v2.resourcepool.BasicResourcePool.prelimCheckoutResource(BasicResourcePool.java:557) at com.mchange.v2.resourcepool.BasicResourcePool.checkoutResource(BasicResourcePool.java:477) at com.mchange.v2.c3p0.impl.C3P0PooledConnectionPool.checkoutPooledConnection(C3P0PooledConnectionPool.java:525) ... 18 more

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  • Joining tables with composite keys in a legacy system in hibernate

    - by Steve N
    Hi, I'm currently trying to create a pair of Hibernate annotated classes to load (read only) from a pair of tables in a legacy system. The legacy system uses a consistent (if somewhat dated) approach to keying tables. The tables I'm attempting to map are as follows: Customer CustomerAddress -------------------------- ---------------------------- customerNumber:string (pk) customerNumber:string (pk_1) name:string sequenceNumber:int (pk_2) street:string postalCode:string I've approached this by creating a CustomerAddress class like this: @Entity @Table(name="CustomerAddress") @IdClass(CustomerAddressKey.class) public class CustomerAddress { @Id @AttributeOverrides({ @AttributeOverride(name = "customerNumber", column = @Column(name="customerNumber")), @AttributeOverride(name = "sequenceNumber", column = @Column(name="sequenceNumber")) }) private String customerNumber; private int sequenceNumber; private String name; private String postalCode; ... } Where the CustomerAddressKey class is a simple Serializable object with the two key fields. The Customer object is then defined as: @Entity @Table(name = "Customer") public class Customer { private String customerNumber; private List<CustomerAddress> addresses = new ArrayList<CustomerAddress>(); private String name; ... } So, my question is: how do I express the OneToMany relationship on the Customer table?

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  • Unit Testing XML independent of physical XML file

    - by RAbraham
    Hi, My question is: In JUnit, How do I setup xml data for my System Under Test(SUT) without making the SUT read from an XML file physically stored on the file system Background: I am given a XML file which contains rules for creation of an invoice. My job is to convert these rules from XMl to Java Objects e.g. If there is a tag as below in my XML file which indicates that after a period of 30 days, the transaction cannot be invoiced <ExpirationDay>30</ExpirationDay> this converts to a Java class , say ExpirationDateInvoicingRule I have a class InvoiceConfiguration which should take the XML file and create the *InvoicingRule objects. I am thinking of using StAX to parse the XML document within InvoiceConfiguration Problem: I want to unit test InvoiceConfiguration. But I dont want InvoiceConfiguration to read from an xml file physically on the file system . I want my unit test to be independent of any physical stored xml file. I want to create a xml representation in memory. But a StAX parser only takes FileReader( or I can play with the File Object)

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  • Multiple database with Spring+Hibernate+JPA

    - by ziftech
    Hi everybody! I'm trying to configure Spring+Hibernate+JPA for work with two databases (MySQL and MSSQL) my datasource-context.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xsi:schemaLocation="http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-2.5.xsd" xmlns:p="http://www.springframework.org/schema/p" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:util="http://www.springframework.org/schema/util"> <!-- Data Source config --> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${local.jdbc.driver}" p:url="${local.jdbc.url}" p:username="${local.jdbc.username}" p:password="${local.jdbc.password}"> </bean> <bean id="dataSourceRemote" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${remote.jdbc.driver}" p:url="${remote.jdbc.url}" p:username="${remote.jdbc.username}" p:password="${remote.jdbc.password}" /> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" p:entity-manager-factory-ref="entityManagerFactory" /> <!-- JPA config --> <tx:annotation-driven transaction-manager="transactionManager" /> <bean id="persistenceUnitManager" class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager"> <property name="persistenceXmlLocations"> <list value-type="java.lang.String"> <value>classpath*:config/persistence.local.xml</value> <value>classpath*:config/persistence.remote.xml</value> </list> </property> <property name="dataSources"> <map> <entry key="localDataSource" value-ref="dataSource" /> <entry key="remoteDataSource" value-ref="dataSourceRemote" /> </map> </property> <property name="defaultDataSource" ref="dataSource" /> </bean> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" p:showSql="true" p:generateDdl="true"> </bean> </property> <property name="persistenceUnitManager" ref="persistenceUnitManager" /> <property name="persistenceUnitName" value="localjpa"/> </bean> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" /> </beans> each persistence.xml contains one unit, like this: <persistence-unit name="remote" transaction-type="RESOURCE_LOCAL"> <properties> <property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.DefaultNamingStrategy" /> <property name="hibernate.dialect" value="${remote.hibernate.dialect}" /> <property name="hibernate.hbm2ddl.auto" value="${remote.hibernate.hbm2ddl.auto}" /> </properties> </persistence-unit> PersistenceUnitManager cause following exception: Cannot resolve reference to bean 'persistenceUnitManager' while setting bean property 'persistenceUnitManager'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'persistenceUnitManager' defined in class path resource [config/datasource-context.xml]: Initialization of bean failed; nested exception is org.springframework.beans.TypeMismatchException: Failed to convert property value of type [java.util.ArrayList] to required type [java.lang.String] for property 'persistenceXmlLocation'; nested exception is java.lang.IllegalArgumentException: Cannot convert value of type [java.util.ArrayList] to required type [java.lang.String] for property 'persistenceXmlLocation': no matching editors or conversion strategy found If left only one persistence.xml without list, every works fine but I need 2 units... I also try to find alternative solution for work with two databases in Spring+Hibernate context, so I would appreciate any solution new error after changing to persistenceXmlLocations No single default persistence unit defined in {classpath:config/persistence.local.xml, classpath:config/persistence.remote.xml} UPDATE: I add persistenceUnitName, it works, but only with one unit, still need help UPDATE: thanks, ChssPly76 I changed config files: datasource-context.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xsi:schemaLocation="http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-2.5.xsd" xmlns:p="http://www.springframework.org/schema/p" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:util="http://www.springframework.org/schema/util"> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${local.jdbc.driver}" p:url="${local.jdbc.url}" p:username="${local.jdbc.username}" p:password="${local.jdbc.password}"> </bean> <bean id="dataSourceRemote" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${remote.jdbc.driver}" p:url="${remote.jdbc.url}" p:username="${remote.jdbc.username}" p:password="${remote.jdbc.password}"> </bean> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor"> <property name="defaultPersistenceUnitName" value="pu1" /> </bean> <bean id="persistenceUnitManager" class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager"> <property name="persistenceXmlLocation" value="${persistence.xml.location}" /> <property name="defaultDataSource" ref="dataSource" /> <!-- problem --> <property name="dataSources"> <map> <entry key="local" value-ref="dataSource" /> <entry key="remote" value-ref="dataSourceRemote" /> </map> </property> </bean> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" p:showSql="true" p:generateDdl="true"> </bean> </property> <property name="persistenceUnitManager" ref="persistenceUnitManager" /> <property name="persistenceUnitName" value="pu1" /> <property name="dataSource" ref="dataSource" /> </bean> <bean id="entityManagerFactoryRemote" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" p:showSql="true" p:generateDdl="true"> </bean> </property> <property name="persistenceUnitManager" ref="persistenceUnitManager" /> <property name="persistenceUnitName" value="pu2" /> <property name="dataSource" ref="dataSourceRemote" /> </bean> <tx:annotation-driven /> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" p:entity-manager-factory-ref="entityManagerFactory" /> <bean id="transactionManagerRemote" class="org.springframework.orm.jpa.JpaTransactionManager" p:entity-manager-factory-ref="entityManagerFactoryRemote" /> </beans> persistence.xml <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="pu1" transaction-type="RESOURCE_LOCAL"> <properties> <property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.DefaultNamingStrategy" /> <property name="hibernate.dialect" value="${local.hibernate.dialect}" /> <property name="hibernate.hbm2ddl.auto" value="${local.hibernate.hbm2ddl.auto}" /> </properties> </persistence-unit> <persistence-unit name="pu2" transaction-type="RESOURCE_LOCAL"> <properties> <property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.DefaultNamingStrategy" /> <property name="hibernate.dialect" value="${remote.hibernate.dialect}" /> <property name="hibernate.hbm2ddl.auto" value="${remote.hibernate.hbm2ddl.auto}" /> </properties> </persistence-unit> </persistence> Now it builds two entityManagerFactory, but both are for Microsoft SQL Server [main] INFO org.hibernate.ejb.Ejb3Configuration - Processing PersistenceUnitInfo [ name: pu1 ...] [main] INFO org.hibernate.cfg.SettingsFactory - RDBMS: Microsoft SQL Server [main] INFO org.hibernate.ejb.Ejb3Configuration - Processing PersistenceUnitInfo [ name: pu2 ...] [main] INFO org.hibernate.cfg.SettingsFactory - RDBMS: Microsoft SQL Server (but must MySQL) I suggest, that use only dataSource, dataSourceRemote (no substitution) is not worked. That's my last problem

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  • Having an issue with org.hibernate.SessionException: Session is closed! in Hibernate

    - by hal10001
    I've done quite a bit a research on this with no luck, but all the answers have a tendency to point toward the session context settings in the config file. What is odd is that I get a session connection the very first time I hit the page (and therefore, a successful result set), but then when I reload I get the following exception: org.hibernate.SessionException: Session is closed! Here are my config settings that are not DB connection string related: <property name="hibernate.show_sql">false</property> <property name="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</property> <property name="hibernate.current_session_context_class">thread</property> <property name="hibernate.cache.provider_class">org.hibernate.cache.NoCacheProvider</property> <property name="hibernate.cache.use_query_cache">false</property> <property name="hibernate.cache.use_minimal_puts">false</property> Here is an example of a call I make that produces the situation I described above. public T get(int id) { session.beginTransaction(); T type; try { type = getTypeClass().cast(session.get(getTypeClass(), id)); } catch (ClassCastException classCastException) { throw new ClassCastException(classCastException.getMessage()); } session.getTransaction().commit(); return type; } The session variable reference is to a static field that contains the current session. All of the session connection details are textbook reference manual. For example, here is my Hibernate session utility: import org.hibernate.SessionFactory; import org.hibernate.cfg.Configuration; public class HibernateSessionFactoryUtil { private static final SessionFactory sessionFactory = buildSessionFactory(); private static SessionFactory buildSessionFactory() { try { return new Configuration().configure().buildSessionFactory(); } catch (Throwable ex) { System.err.println("Initial SessionFactory creation failed." + ex); throw new ExceptionInInitializerError(ex); } } public static SessionFactory getSessionFactory() { return sessionFactory; } }

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  • hibernate c3p0 broken pipe

    - by raven_arkadon
    Hi, I'm using hibernate 3 with c3p0 for a program which constantly extracts data from some source and writes it to a database. Now the problem is, that the database might become unavailable for some reasons (in the simplest case: i simply shut it down). If anything is about to be written to the database there should not be any exception - the query should wait for all eternity until the database becomes available again. If I'm not mistaken this is one of the things the connection pool could do for me: if there is a problem with the db, just retry to connect - in the worst case for infinity. But instead i get a broken pipe exception, sometimes followed by connection refused and then the exception is passed to my own code, which shouldn't happen. Even if I catch the exception, how could i cleanly reinitialize hibernate again? (So far without c3p0 i simply built the session factory again, but i wouldn't be surprised if that could leak connections (or is it ok to do so?)). The database is Virtuoso open source edition. My hibernate.xml.cfg c3p0 config: <property name="hibernate.connection.provider_class">org.hibernate.connection.C3P0ConnectionProvider</property> <property name="hibernate.c3p0.breakAfterAcquireFailure">false</property> <property name="hibernate.c3p0.acquireRetryAttempts">-1</property> <property name="hibernate.c3p0.acquireRetryDelay">30000</property> <property name="hibernate.c3p0.automaticTestTable">my_test_table</property> <property name="hibernate.c3p0.initialPoolSize">3</property> <property name="hibernate.c3p0.minPoolSize">3</property> <property name="hibernate.c3p0.maxPoolSize">10</property> btw: The test table is created and i get tons of debug output- so it seems it actually reads the config.

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  • What are the advantages of myBatis over Hibernate?

    - by Kshitiz Sharma
    This question originates from a comment I received on one of my questions - I'd rather drop hibernate in favor of mybatis instead of jdbc I've done some research on my own and understand the basic concept. But some insights can only be gained through actual experience. What are the advantages of myBatis that would make it worth learning a new framework? In what case would you avoid using it?

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  • XML deserialization doubling up on entities

    - by Nathan Loding
    I have an XML file that I am attempting to deserialize into it's respective objects. It works great on most of these objects, except for one item that is being doubled up on. Here's the relevant portion of the XML: <Clients> <Client Name="My Company" SiteID="1" GUID="xxx-xxx-xxx-xxx"> <Reports> <Report Name="First Report" Path="/Custom/FirstReport"> <Generate>true</Generate> </Report> </Reports> </Client> </Clients> "Clients" is a List<Client> object. Each Client object has a List<Report> object within it. The issue is that when this XML is deserialized, the List<Report> object has a count of 2 -- the "First Report" Report object is in there twice. Why? Here's the C#: public class Client { [System.Xml.Serialization.XmlArray("Reports"), System.Xml.Serialization.XmlArrayItem(typeof(Report))] public List<Report> Reports; } public class Report { [System.Xml.Serialization.XmlAttribute("Name")] public string Name; public bool Generate; [System.Xml.Serialization.XmlAttribute("Path")] public string Path; } class Program { static void Main(string[] args) { List<Client> _clients = new List<Client>(); string xmlFile = "myxmlfile.xml"; System.Xml.Serialization.XmlSerializer xmlSerializer = new System.Xml.Serialization.XmlSerializer(typeof(List<Client>), new System.Xml.Serialization.XmlRootAttribute("Clients")); using (FileStream stream = new FileStream(xmlFile, FileMode.Open)) { _clients = xmlSerializer.Deserialize(stream) as List<Client>; } foreach(Client _client in _clients) { Console.WriteLine("Count: " + _client.Reports.Count); // This write "2" foreach(Report _report in _client.Reports) { Console.WriteLine("Name: " + _report.Name); // Writes "First Report" twice } } } }

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  • Why were annotations introduced in Spring and Hibernate?

    - by Chandrashekhar
    I would like to know why were annotations introduced in Spring and Hibernate? For earlier versions of both the frameworks book authors were saying that if we keep configuration in xml files then it will be easier to maintain (due to decoupling) and just by changing the xml file we can re-configure the application. If we use annotations in our project and in future we want to re-configure application then again we have to compile and build the project. So why were these annotations introduced in these frameworks? From my point of view annotations make the apps dependent on certain framework. Isn't it true?

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  • How can I map "insert='false' update='false'" on a composite-id key-property which is also used in a one-to-many FK?

    - by Gweebz
    I am working on a legacy code base with an existing DB schema. The existing code uses SQL and PL/SQL to execute queries on the DB. We have been tasked with making a small part of the project database-engine agnostic (at first, change everything eventually). We have chosen to use Hibernate 3.3.2.GA and "*.hbm.xml" mapping files (as opposed to annotations). Unfortunately, it is not feasible to change the existing schema because we cannot regress any legacy features. The problem I am encountering is when I am trying to map a uni-directional, one-to-many relationship where the FK is also part of a composite PK. Here are the classes and mapping file... CompanyEntity.java public class CompanyEntity { private Integer id; private Set<CompanyNameEntity> names; ... } CompanyNameEntity.java public class CompanyNameEntity implements Serializable { private Integer id; private String languageId; private String name; ... } CompanyNameEntity.hbm.xml <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://www.jboss.org/dtd/hibernate/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="com.example"> <class name="com.example.CompanyEntity" table="COMPANY"> <id name="id" column="COMPANY_ID"/> <set name="names" table="COMPANY_NAME" cascade="all-delete-orphan" fetch="join" batch-size="1" lazy="false"> <key column="COMPANY_ID"/> <one-to-many entity-name="vendorName"/> </set> </class> <class entity-name="companyName" name="com.example.CompanyNameEntity" table="COMPANY_NAME"> <composite-id> <key-property name="id" column="COMPANY_ID"/> <key-property name="languageId" column="LANGUAGE_ID"/> </composite-id> <property name="name" column="NAME" length="255"/> </class> </hibernate-mapping> This code works just fine for SELECT and INSERT of a Company with names. I encountered a problem when I tried to update and existing record. I received a BatchUpdateException and after looking through the SQL logs I saw Hibernate was trying to do something stupid... update COMPANY_NAME set COMPANY_ID=null where COMPANY_ID=? Hibernate was trying to dis-associate child records before updating them. The problem is that this field is part of the PK and not-nullable. I found the quick solution to make Hibernate not do this is to add "not-null='true'" to the "key" element in the parent mapping. SO now may mapping looks like this... CompanyNameEntity.hbm.xml <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://www.jboss.org/dtd/hibernate/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="com.example"> <class name="com.example.CompanyEntity" table="COMPANY"> <id name="id" column="COMPANY_ID"/> <set name="names" table="COMPANY_NAME" cascade="all-delete-orphan" fetch="join" batch-size="1" lazy="false"> <key column="COMPANY_ID" not-null="true"/> <one-to-many entity-name="vendorName"/> </set> </class> <class entity-name="companyName" name="com.example.CompanyNameEntity" table="COMPANY_NAME"> <composite-id> <key-property name="id" column="COMPANY_ID"/> <key-property name="languageId" column="LANGUAGE_ID"/> </composite-id> <property name="name" column="NAME" length="255"/> </class> </hibernate-mapping> This mapping gives the exception... org.hibernate.MappingException: Repeated column in mapping for entity: companyName column: COMPANY_ID (should be mapped with insert="false" update="false") My problem now is that I have tryed to add these attributes to the key-property element but that is not supported by the DTD. I have also tryed changing it to a key-many-to-one element but that didn't work either. So... How can I map "insert='false' update='false'" on a composite-id key-property which is also used in a one-to-many FK?

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  • Hibernate without primary keys generated by db?

    - by Michael Jones
    I'm building a data warehouse and want to use InfiniDB as the storage engine. However, it doesn't allow primary keys or foreign key constraints (or any constraints for that matter). Hibernate complains "The database returned no natively generated identity value" when I perform an insert. Each table is relational, and contains a unique integer column that was previously used as the primary key - I want to keep that, but just not have the constraint in the db that the column is the primary key. I'm assuming the problem is that Hibernate expects the db to return a generated key. Is it possible to override this behaviour so I can set the primary key field's value myself and keep Hibernate happy? -- edit -- Two of the mappings are as follows: <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated Jun 1, 2010 2:49:51 PM by Hibernate Tools 3.2.1.GA --> <hibernate-mapping> <class name="com.example.project.Visitor" table="visitor" catalog="orwell"> <id name="id" type="java.lang.Long"> <column name="id" /> <generator class="identity" /> </id> <property name="firstSeen" type="timestamp"> <column name="first_seen" length="19" /> </property> <property name="lastSeen" type="timestamp"> <column name="last_seen" length="19" /> </property> <property name="sessionId" type="string"> <column name="session_id" length="26" unique="true" /> </property> <property name="userId" type="java.lang.Long"> <column name="user_id" /> </property> <set name="visits" inverse="true"> <key> <column name="visitor_id" /> </key> <one-to-many class="com.example.project.Visit" /> </set> </class> </hibernate-mapping> and: <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated Jun 1, 2010 2:49:51 PM by Hibernate Tools 3.2.1.GA --> <hibernate-mapping> <class name="com.example.project.Visit" table="visit" catalog="orwell"> <id name="id" type="java.lang.Long"> <column name="id" /> <generator class="identity" /> </id> <many-to-one name="visitor" class="com.example.project.Visitor" fetch="join" cascade="all"> <column name="visitor_id" /> </many-to-one> <property name="visitId" type="string"> <column name="visit_id" length="20" unique="true" /> </property> <property name="startTime" type="timestamp"> <column name="start_time" length="19" /> </property> <property name="endTime" type="timestamp"> <column name="end_time" length="19" /> </property> <property name="userAgent" type="string"> <column name="user_agent" length="65535" /> </property> <set name="pageViews" inverse="true"> <key> <column name="visit_id" /> </key> <one-to-many class="com.example.project.PageView" /> </set> </class> </hibernate-mapping>

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  • Read XML Files using LINQ to XML and Extension Methods

    - by psheriff
    In previous blog posts I have discussed how to use XML files to store data in your applications. I showed you how to read those XML files from your project and get XML from a WCF service. One of the problems with reading XML files is when elements or attributes are missing. If you try to read that missing data, then a null value is returned. This can cause a problem if you are trying to load that data into an object and a null is read. This blog post will show you how to create extension methods to detect null values and return valid values to load into your object. The XML Data An XML data file called Product.xml is located in the \Xml folder of the Silverlight sample project for this blog post. This XML file contains several rows of product data that will be used in each of the samples for this post. Each row has 4 attributes; namely ProductId, ProductName, IntroductionDate and Price. <Products>  <Product ProductId="1"           ProductName="Haystack Code Generator for .NET"           IntroductionDate="07/01/2010"  Price="799" />  <Product ProductId="2"           ProductName="ASP.Net Jumpstart Samples"           IntroductionDate="05/24/2005"  Price="0" />  ...  ...</Products> The Product Class Just as you create an Entity class to map each column in a table to a property in a class, you should do the same for an XML file too. In this case you will create a Product class with properties for each of the attributes in each element of product data. The following code listing shows the Product class. public class Product : CommonBase{  public const string XmlFile = @"Xml/Product.xml";   private string _ProductName;  private int _ProductId;  private DateTime _IntroductionDate;  private decimal _Price;   public string ProductName  {    get { return _ProductName; }    set {      if (_ProductName != value) {        _ProductName = value;        RaisePropertyChanged("ProductName");      }    }  }   public int ProductId  {    get { return _ProductId; }    set {      if (_ProductId != value) {        _ProductId = value;        RaisePropertyChanged("ProductId");      }    }  }   public DateTime IntroductionDate  {    get { return _IntroductionDate; }    set {      if (_IntroductionDate != value) {        _IntroductionDate = value;        RaisePropertyChanged("IntroductionDate");      }    }  }   public decimal Price  {    get { return _Price; }    set {      if (_Price != value) {        _Price = value;        RaisePropertyChanged("Price");      }    }  }} NOTE: The CommonBase class that the Product class inherits from simply implements the INotifyPropertyChanged event in order to inform your XAML UI of any property changes. You can see this class in the sample you download for this blog post. Reading Data When using LINQ to XML you call the Load method of the XElement class to load the XML file. Once the XML file has been loaded, you write a LINQ query to iterate over the “Product” Descendants in the XML file. The “select” portion of the LINQ query creates a new Product object for each row in the XML file. You retrieve each attribute by passing each attribute name to the Attribute() method and retrieving the data from the “Value” property. The Value property will return a null if there is no data, or will return the string value of the attribute. The Convert class is used to convert the value retrieved into the appropriate data type required by the Product class. private void LoadProducts(){  XElement xElem = null;   try  {    xElem = XElement.Load(Product.XmlFile);     // The following will NOT work if you have missing attributes    var products =         from elem in xElem.Descendants("Product")        orderby elem.Attribute("ProductName").Value        select new Product        {          ProductId = Convert.ToInt32(            elem.Attribute("ProductId").Value),          ProductName = Convert.ToString(            elem.Attribute("ProductName").Value),          IntroductionDate = Convert.ToDateTime(            elem.Attribute("IntroductionDate").Value),          Price = Convert.ToDecimal(elem.Attribute("Price").Value)        };     lstData.DataContext = products;  }  catch (Exception ex)  {    MessageBox.Show(ex.Message);  }} This is where the problem comes in. If you have any missing attributes in any of the rows in the XML file, or if the data in the ProductId or IntroductionDate is not of the appropriate type, then this code will fail! The reason? There is no built-in check to ensure that the correct type of data is contained in the XML file. This is where extension methods can come in real handy. Using Extension Methods Instead of using the Convert class to perform type conversions as you just saw, create a set of extension methods attached to the XAttribute class. These extension methods will perform null-checking and ensure that a valid value is passed back instead of an exception being thrown if there is invalid data in your XML file. private void LoadProducts(){  var xElem = XElement.Load(Product.XmlFile);   var products =       from elem in xElem.Descendants("Product")      orderby elem.Attribute("ProductName").Value      select new Product      {        ProductId = elem.Attribute("ProductId").GetAsInteger(),        ProductName = elem.Attribute("ProductName").GetAsString(),        IntroductionDate =            elem.Attribute("IntroductionDate").GetAsDateTime(),        Price = elem.Attribute("Price").GetAsDecimal()      };   lstData.DataContext = products;} Writing Extension Methods To create an extension method you will create a class with any name you like. In the code listing below is a class named XmlExtensionMethods. This listing just shows a couple of the available methods such as GetAsString and GetAsInteger. These methods are just like any other method you would write except when you pass in the parameter you prefix the type with the keyword “this”. This lets the compiler know that it should add this method to the class specified in the parameter. public static class XmlExtensionMethods{  public static string GetAsString(this XAttribute attr)  {    string ret = string.Empty;     if (attr != null && !string.IsNullOrEmpty(attr.Value))    {      ret = attr.Value;    }     return ret;  }   public static int GetAsInteger(this XAttribute attr)  {    int ret = 0;    int value = 0;     if (attr != null && !string.IsNullOrEmpty(attr.Value))    {      if(int.TryParse(attr.Value, out value))        ret = value;    }     return ret;  }   ...  ...} Each of the methods in the XmlExtensionMethods class should inspect the XAttribute to ensure it is not null and that the value in the attribute is not null. If the value is null, then a default value will be returned such as an empty string or a 0 for a numeric value. Summary Extension methods are a great way to simplify your code and provide protection to ensure problems do not occur when reading data. You will probably want to create more extension methods to handle XElement objects as well for when you use element-based XML. Feel free to extend these extension methods to accept a parameter which would be the default value if a null value is detected, or any other parameters you wish. NOTE: You can download the complete sample code at my website. http://www.pdsa.com/downloads. Choose “Tips & Tricks”, then "Read XML Files using LINQ to XML and Extension Methods" from the drop-down. Good Luck with your Coding,Paul D. Sheriff  

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  • JBoss AS: use .xml files in the properties-service.xml

    - by fgysin
    The properties service (configured in properties-service.xml) in JBoss application server lets you specify external .properties files that are loaded and can then be accessed as system properties from the deployed applications. (See here http://community.jboss.org/wiki/PropertiesService for more info...) Is it also possible to load config files in the .xml format instead of .properties? I know it is possible for certain given configs like for example the mail-service.xml and the jboss-log4j.xml... But they are both loaded directly by JBoss, and not via the properties service.

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