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• Example map-reduce oozie program not working on CDH 4.5

  - by user2002748

  I am using Hadoop (CDH 4.5) on my mac since some time now, and do run map reduce jobs regularly. I installed oozie recently (again, CDH4.5) following instructions at: http://archive.cloudera.com/cdh4/cdh/4/oozie-3.3.2-cdh4.5.0/DG_QuickStart.html, and tried to run sample programs provided. However, it always fails with the following error. Looks like the workflow is not getting run at all. The Console URL field in the Job info is also empty. Could someone please help on this? The relevant snippet of the Oozie Job log follows. 2014-06-10 17:27:18,414 INFO ActionStartXCommand:539 - USER[userXXX] GROUP[-] TOKEN[] APP[map-reduce-wf] JOB[0000000-140610172702069-oozie-usrX-W] ACTION[0000000-140610172702069-oozie-usrX-W@:start:] Start action [0000000-140610172702069-oozie-usrX-W@:start:] with user-retry state : userRetryCount [0], userRetryMax [0], userRetryInterval [10] 2014-06-10 17:27:18,417 WARN ActionStartXCommand:542 - USER[userXXX] GROUP[-] TOKEN[] APP[map-reduce-wf] JOB[0000000-140610172702069-oozie-usrX-W] ACTION[0000000-140610172702069-oozie-usrX-W@:start:] [***0000000-140610172702069-oozie-usrX-W@:start:***]Action status=DONE 2014-06-10 17:27:18,417 WARN ActionStartXCommand:542 - USER[userXXX] GROUP[-] TOKEN[] APP[map-reduce-wf] JOB[0000000-140610172702069-oozie-usrX-W] ACTION[0000000-140610172702069-oozie-usrX-W@:start:] [***0000000-140610172702069-oozie-usrX-W@:start:***]Action updated in DB! 2014-06-10 17:27:18,576 INFO ActionStartXCommand:539 - USER[userXXX] GROUP[-] TOKEN[] APP[map-reduce-wf] JOB[0000000-140610172702069-oozie-usrX-W] ACTION[0000000-140610172702069-oozie-usrX-W@mr-node] Start action [0000000-140610172702069-oozie-usrX-W@mr-node] with user-retry state : userRetryCount [0], userRetryMax [0], userRetryInterval [10] 2014-06-10 17:27:19,188 WARN MapReduceActionExecutor:542 - USER[userXXX] GROUP[-] TOKEN[] APP[map-reduce-wf] JOB[0000000-140610172702069-oozie-usrX-W] ACTION[0000000-140610172702069-oozie-usrX-W@mr-node] credentials is null for the action 2014-06-10 17:27:19,423 WARN ActionStartXCommand:542 - USER[userXXX] GROUP[-] TOKEN[] APP[map-reduce-wf] JOB[0000000-140610172702069-oozie-usrX-W] ACTION[0000000-140610172702069-oozie-usrX-W@mr-node] Error starting action [mr-node]. ErrorType [TRANSIENT], ErrorCode [JA009], Message [JA009: Unknown rpc kind RPC_WRITABLE] org.apache.oozie.action.ActionExecutorException: JA009: Unknown rpc kind RPC_WRITABLE at org.apache.oozie.action.ActionExecutor.convertExceptionHelper(ActionExecutor.java:418) at org.apache.oozie.action.ActionExecutor.convertException(ActionExecutor.java:392) at org.apache.oozie.action.hadoop.JavaActionExecutor.submitLauncher(JavaActionExecutor.java:773) at org.apache.oozie.action.hadoop.JavaActionExecutor.start(JavaActionExecutor.java:927) at org.apache.oozie.command.wf.ActionStartXCommand.execute(ActionStartXCommand.java:211) at org.apache.oozie.command.wf.ActionStartXCommand.execute(ActionStartXCommand.java:59) at org.apache.oozie.command.XCommand.call(XCommand.java:277) at org.apache.oozie.service.CallableQueueService$CompositeCallable.call(CallableQueueService.java:326) at org.apache.oozie.service.CallableQueueService$CompositeCallable.call(CallableQueueService.java:255) at org.apache.oozie.service.CallableQueueService$CallableWrapper.run(CallableQueueService.java:175) at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615) at java.lang.Thread.run(Thread.java:744) Caused by: org.apache.hadoop.ipc.RemoteException(java.io.IOException): Unknown rpc kind RPC_WRITABLE at org.apache.hadoop.ipc.Client.call(Client.java:1238) at org.apache.hadoop.ipc.WritableRpcEngine$Invoker.invoke(WritableRpcEngine.java:225) at org.apache.hadoop.mapred.$Proxy30.getDelegationToken(Unknown Source) at org.apache.hadoop.mapred.JobClient.getDelegationToken(JobClient.java:2125) at org.apache.oozie.service.HadoopAccessorService.createJobClient(HadoopAccessorService.java:372) at org.apache.oozie.action.hadoop.JavaActionExecutor.createJobClient(JavaActionExecutor.java:970) at org.apache.oozie.action.hadoop.JavaActionExecutor.submitLauncher(JavaActionExecutor.java:723) ... 10 more 2014-06-10 17:27:19,426 INFO ActionStartXCommand:539 - USER[userXXX] GROUP[-] TOKEN[] APP[map-reduce-wf] JOB[0000000-140610172702069-oozie-usrX-W] ACTION[0000000-140610172702069-oozie-usrX-W@mr-node] Next Retry, Attempt Number [1] in [60,000] milliseconds 2014-06-10 17:28:19,468 INFO ActionStartXCommand:539 - USER[userXXX] GROUP[-] TOKEN[] APP[map-reduce-wf] JOB[0000000-140610172702069-oozie-usrX-W] ACTION[0000000-140610172702069-oozie-usrX-W@mr-node] Start action [0000000-140610172702069-oozie-usrX-W@mr-node] with user-retry state : userRetryCount [0], userRetryMax [0], userRetryInterval [10]

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• International Association for Software Architects (IASA) SE Florida Chapter Inaugural Meeting - 12/6/2010

  - by Sam Abraham

  On Monday 12/6/2010, Florida witnessed the inauguration of the state’s first official chapter of the International Association for Software Architects (IASA). Present were Ms. Damaris Bode, Global IASA Chapter Director and Mr. Uday Batt, President of the Indian Chapter.   Ms. Bode spoke to us about the various benefits IASA offers to its members as well as the various available education courses and certification tracks. Mr. Batt kindly shared with us his experience in establishing and growing the Indian Chapter.   Mr. Rainer Habermann, President of the IASA South East Florida Chapter outlined his vision for the upcoming year and invited all members to take an active role while Mr. Dave Noderer, the chapter’s vice president shared the history and events that took place leading to the final inauguration.   Founding chapter board members are: -Rainer Habermann, President -Dave Noderer, Vice President -Ray Almonte, Treasurer -Quent Hershleman, Director of the Board of Directors. -Sam Abraham (Me), Secretary   Chapter meetings will be taking place at the Microsoft Ft Lauderdale office. For more information on IASA please visit http://www.iasahome.org. For more information about the SE Florida Chapter please visit http://www.iasaglobal.org/iasa/South_East_Florida.asp?SnID=1049126809 Event photos can be found on Facebook: http://www.facebook.com/album.php?aid=19508&id=100001532507436#!/album.php?aid=19508&id=100001532507436   --Sam Abraham

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• Excel Issues macro may be needed

  - by user124643

  I trying to compare lists in excel. There are two lists, one list just has one column and the other has two columns, and what I am trying to do is when column A matches column C than take the value in column D and use that to replace column A. For example: Column A Column B Column C Column D Blue Blue Shirt Blue Red Pants Red Green Shoes Red Green Green Purple So the completed list should look like: Column A Column B Column C Column D Shirt Blue Shirt Shirt Red Pants Pants Green Shoes Pants Shoes Shoes Purple

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• Positioning divs inside a container div without the content of an upper div affecting the position o

  - by silverCORE

  Hi. I'm trying to accomplish the following layout, and I'm almost there, except for the last green div, which is going lower and lower depending on the content of the content (white) div. If I set a value for the TOP property for the green div, and then I add some more text to the content div, the green div goes lower and lower. Since the green div is child to the main container div, and the green div is relatively positioned, isn't it supposed to be placed specifically at the position indicated by the TOP value of it? If I'm incorrect...can someone please tell me how can i make it so that the green div is always displayed at the same spot within the container (gray) div, regardless of the height of the content/white div? I tried to paste the css code here but was having problems with the brower. you can see the test site source/css at http://www.rae-mx.com/test tia for the help.

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• Trying to create a RegEx for the following patterns

  - by Travis

  Here are the patterns: Red,Green (and so on...) Red (+5.00),Green (+6.00) (and so on...) Red (+5.00,+10.00),Green (+6.00,+20.00) (and so on...) Red (+5.00),Green (and so on...) Each attribute ("Red,"Green") can have 0, 1, or 2 modifiers (shown as "+5.00,+10.00", etc.). I need to capture each of the attributes and their modifiers as a single string (i.e. "Red (+5.00,+10.00)", "Green (+6.00,+20.00)". Help?

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• Trying to create a Reg Ex for the following patterns

  - by Travis

  Here are the patterns: Red,Green (and so on...) Red (+5.00),Green (+6.00) (and so on...) Red (+5.00,+10.00),Green (+6.00,+20.00) (and so on...) Red (+5.00),Green (and so on...) Each attribute ("Red,"Green") can have 0, 1, or 2 modifiers (shown as "+5.00,+10.00", etc.). I need to capture each of the attributes and their modifiers as a single string (i.e. "Red (+5.00,+10.00)", "Green (+6.00,+20.00)". Help?

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• Webmaster Tools - URL Parameters Settings Do Not Work

  - by David

  Google Webmaster Tools shows problems with duplicate title tags under Optimization - HTML Improvements, for example: ???????? Mitsubishi Electric Mr. Slim PC Series PC-3KAKLT (220V) 30000 BTU > /????-????/mitsubishi-mr-slim-pc3kaklt-30000-btu.html > /????-????/mitsubishi-mr-slim-pc3kaklt-30000-btu.html?category_id=96 These two pages have exactly the same content, a rel-canonical tag is set, and they are (no longer) linked to internally. Additionally, we used the Configuration - URL Parameters setting, to set this parameter to No: Doesn't affect page content about one month ago. However, Google is still showing these HTML improvements (and rankings dropped dramatically). What else can we do here? Best, David

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• IBM "per core" comparisons for SPECjEnterprise2010

  - by jhenning

  I recently stumbled upon a blog entry from Roman Kharkovski (an IBM employee) comparing some SPECjEnterprise2010 results for IBM vs. Oracle. Mr. Kharkovski's blog claims that SPARC delivers half the transactions per core vs. POWER7. Prior to any argument, I should say that my predisposition is to like Mr. Kharkovski, because he says that his blog is intended to be factual; that the intent is to try to avoid marketing hype and FUD tactic; and mostly because he features a picture of himself wearing a bike helmet (me too). Therefore, in a spirit of technical argument, rather than FUD fight, there are a few areas in his comparison that should be discussed. Scaling is not free For any benchmark, if a small system scores 13k using quantity R1 of some resource, and a big system scores 57k using quantity R2 of that resource, then, sure, it's tempting to divide: is  13k/R1 > 57k/R2 ? It is tempting, but not necessarily educational. The problem is that scaling is not free. Building big systems is harder than building small systems. Scoring  13k/R1  on a little system provides no guarantee whatsoever that one can sustain that ratio when attempting to handle more than 4 times as many users. Choosing the denominator radically changes the picture When ratios are used, one can vastly manipulate appearances by the choice of denominator. In this case, lots of choices are available for the resource to be compared (R1 and R2 above). IBM chooses to put cores in the denominator. Mr. Kharkovski provides some reasons for that choice in his blog entry. And yet, it should be noted that the very concept of a core is: arbitrary: not necessarily comparable across vendors; fluid: modern chips shift chip resources in response to load; and invisible: unless you have a microscope, you can't see it. By contrast, one can actually see processor chips with the naked eye, and they are a bit easier to count. If we put chips in the denominator instead of cores, we get: 13161.07 EjOPS / 4 chips = 3290 EjOPS per chip for IBM vs 57422.17 EjOPS / 16 chips = 3588 EjOPS per chip for Oracle The choice of denominator makes all the difference in the appearance. Speaking for myself, dividing by chips just seems to make more sense, because: I can see chips and count them; and I can accurately compare the number of chips in my system to the count in some other vendor's system; and Tthe probability of being able to continue to accurately count them over the next 10 years of microprocessor development seems higher than the probability of being able to accurately and comparably count "cores". SPEC Fair use requirements Speaking as an individual, not speaking for SPEC and not speaking for my employer, I wonder whether Mr. Kharkovski's blog article, taken as a whole, meets the requirements of the SPEC Fair Use rule www.spec.org/fairuse.html section I.D.2. For example, Mr. Kharkovski's footnote (1) begins Results from http://www.spec.org as of 04/04/2013 Oracle SUN SPARC T5-8 449 EjOPS/core SPECjEnterprise2010 (Oracle's WLS best SPECjEnterprise2010 EjOPS/core result on SPARC). IBM Power730 823 EjOPS/core (World Record SPECjEnterprise2010 EJOPS/core result) The questionable tactic, from a Fair Use point of view, is that there is no such metric at the designated location. At www.spec.org, You can find the SPEC metric 57422.17 SPECjEnterprise2010 EjOPS for Oracle and You can also find the SPEC metric 13161.07 SPECjEnterprise2010 EjOPS for IBM. Despite the implication of the footnote, you will not find any mention of 449 nor anything that says 823. SPEC says that you can, under its fair use rule, derive your own values; but it emphasizes: "The context must not give the appearance that SPEC has created or endorsed the derived value." Substantiation and transparency Although SPEC disclaims responsibility for non-SPEC information (section I.E), it says that non-SPEC data and methods should be accurate, should be explained, should be substantiated. Unfortunately, it is difficult or impossible for the reader to independently verify the pricing: Were like units compared to like (e.g. list price to list price)? Were all components (hw, sw, support) included? Were all fees included? Note that when tpc.org shows IBM pricing, there are often items such as "PROCESSOR ACTIVATION" and "MEMORY ACTIVATION". Without the transparency of a detailed breakdown, the pricing claims are questionable. T5 claim for "Fastest Processor" Mr. Kharkovski several times questions Oracle's claim for fastest processor, writing You see, when you publish industry benchmarks, people may actually compare your results to other vendor's results. Well, as we performance people always say, "it depends". If you believe in performance-per-core as the primary way of looking at the world, then yes, the POWER7+ is impressive, spending its chip resources to support up to 32 threads (8 cores x 4 threads). Or, it just might be useful to consider performance-per-chip. Each SPARC T5 chip allows 128 hardware threads to be simultaneously executing (16 cores x 8 threads). The Industry Standard Benchmark that focuses specifically on processor chip performance is SPEC CPU2006. For this very well known and popular benchmark, SPARC T5: provides better performance than both POWER7 and POWER7+, for 1 chip vs. 1 chip, for 8 chip vs. 8 chip, for integer (SPECint_rate2006) and floating point (SPECfp_rate2006), for Peak tuning and for Base tuning. For example, at the 8-chip level, integer throughput (SPECint_rate2006) is: 3750 for SPARC 2170 for POWER7+. You can find the details at the March 2013 BestPerf CPU2006 page SPEC is a trademark of the Standard Performance Evaluation Corporation, www.spec.org. The two specific results quoted for SPECjEnterprise2010 are posted at the URLs linked from the discussion. Results for SPEC CPU2006 were verified at spec.org 1 July 2013, and can be rechecked here.

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• iPhone Image Processing--matrix convolution

  - by James

  I am implementing a matrix convolution blur on the iPhone. The following code converts the UIImage supplied as an argument of the blur function into a CGImageRef, and then stores the RGBA values in a standard C char array. CGImageRef imageRef = imgRef.CGImage; int width = imgRef.size.width; int height = imgRef.size.height; CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); unsigned char *pixels = malloc((height) * (width) * 4); NSUInteger bytesPerPixel = 4; NSUInteger bytesPerRow = bytesPerPixel * (width); NSUInteger bitsPerComponent = 8; CGContextRef context = CGBitmapContextCreate(pixels, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef); CGContextRelease(context); Then the pixels values stored in the pixels array are convolved, and stored in another array. unsigned char *results = malloc((height) * (width) * 4); Finally, these augmented pixel values are changed back into a CGImageRef, converted to a UIImage, and the returned at the end of the function with the following code. context = CGBitmapContextCreate(results, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGImageRef finalImage = CGBitmapContextCreateImage(context); UIImage *newImage = [UIImage imageWithCGImage:CGBitmapContextCreateImage(context)]; CGImageRelease(finalImage); NSLog(@"edges found"); free(results); free(pixels); CGColorSpaceRelease(colorSpace); return newImage; This works perfectly, once. Then, once the image is put through the filter again, very odd, unprecedented pixel values representing input pixel values that don't exist, are returned. Is there any reason why this should work the first time, but then not afterward? Beneath is the entirety of the function. -(UIImage*) blur:(UIImage*)imgRef { CGImageRef imageRef = imgRef.CGImage; int width = imgRef.size.width; int height = imgRef.size.height; CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); unsigned char *pixels = malloc((height) * (width) * 4); NSUInteger bytesPerPixel = 4; NSUInteger bytesPerRow = bytesPerPixel * (width); NSUInteger bitsPerComponent = 8; CGContextRef context = CGBitmapContextCreate(pixels, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef); CGContextRelease(context); height = imgRef.size.height; width = imgRef.size.width; float matrix[] = {0,0,0,0,1,0,0,0,0}; float divisor = 1; float shift = 0; unsigned char *results = malloc((height) * (width) * 4); for(int y = 1; y < height; y++){ for(int x = 1; x < width; x++){ float red = 0; float green = 0; float blue = 0; int multiplier=1; if(y>0 && x>0){ int index = (y-1)*width + x; red = matrix[0]*multiplier*(float)pixels[4*(index-1)] + matrix[1]*multiplier*(float)pixels[4*(index)] + matrix[2]*multiplier*(float)pixels[4*(index+1)]; green = matrix[0]*multiplier*(float)pixels[4*(index-1)+1] + matrix[1]*multiplier*(float)pixels[4*(index)+1] + matrix[2]*multiplier*(float)pixels[4*(index+1)+1]; blue = matrix[0]*multiplier*(float)pixels[4*(index-1)+2] + matrix[1]*multiplier*(float)pixels[4*(index)+2] + matrix[2]*multiplier*(float)pixels[4*(index+1)+2]; index = (y)*width + x; red = red+ matrix[3]*multiplier*(float)pixels[4*(index-1)] + matrix[4]*multiplier*(float)pixels[4*(index)] + matrix[5]*multiplier*(float)pixels[4*(index+1)]; green = green + matrix[3]*multiplier*(float)pixels[4*(index-1)+1] + matrix[4]*multiplier*(float)pixels[4*(index)+1] + matrix[5]*multiplier*(float)pixels[4*(index+1)+1]; blue = blue + matrix[3]*multiplier*(float)pixels[4*(index-1)+2] + matrix[4]*multiplier*(float)pixels[4*(index)+2] + matrix[5]*multiplier*(float)pixels[4*(index+1)+2]; index = (y+1)*width + x; red = red+ matrix[6]*multiplier*(float)pixels[4*(index-1)] + matrix[7]*multiplier*(float)pixels[4*(index)] + matrix[8]*multiplier*(float)pixels[4*(index+1)]; green = green + matrix[6]*multiplier*(float)pixels[4*(index-1)+1] + matrix[7]*multiplier*(float)pixels[4*(index)+1] + matrix[8]*multiplier*(float)pixels[4*(index+1)+1]; blue = blue + matrix[6]*multiplier*(float)pixels[4*(index-1)+2] + matrix[7]*multiplier*(float)pixels[4*(index)+2] + matrix[8]*multiplier*(float)pixels[4*(index+1)+2]; red = red/divisor+shift; green = green/divisor+shift; blue = blue/divisor+shift; if(red<0){ red=0; } if(green<0){ green=0; } if(blue<0){ blue=0; } if(red>255){ red=255; } if(green>255){ green=255; } if(blue>255){ blue=255; } int realPos = 4*(y*imgRef.size.width + x); results[realPos] = red; results[realPos + 1] = green; results[realPos + 2] = blue; results[realPos + 3] = 1; }else { int realPos = 4*((y)*(imgRef.size.width) + (x)); results[realPos] = 0; results[realPos + 1] = 0; results[realPos + 2] = 0; results[realPos + 3] = 1; } } } context = CGBitmapContextCreate(results, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGImageRef finalImage = CGBitmapContextCreateImage(context); UIImage *newImage = [UIImage imageWithCGImage:CGBitmapContextCreateImage(context)]; CGImageRelease(finalImage); free(results); free(pixels); CGColorSpaceRelease(colorSpace); return newImage;} THANKS!!!

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• Excel 2007 Conditional Formatting is not properly using custom formula provided

  - by Charles

  In Excel 2007, I want to conditionally color a row if it is odd numbered and then vary the coloring depending on if a specific cell (in column E) in that row contains a number (green) or empty(red). E.g. if E15 has a value of 2 and E13 has no entry, I would expect row 15 to be green and row 13 to be red. My two formulas are: To color red: =IF((MOD(ROW(),2) = 1),NOT(ISNUMBER(INDIRECT("$E$"&ROW()))), FALSE) To color green: =IF((MOD(ROW(),2) = 1),ISNUMBER(INDIRECT("E"&ROW())), FALSE) If I paste these formulas into cells on the worksheet I get the expected values. For row 15 the "red" equation is false and the "green" equation is true. For Row 13 the "red" equation is true and the "green equation is false. However if I use these formulas in the conditional formating use formula feature, all of my rows are red, any thoughts?

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• Conky to Monitor WLS Managed Servers

  - by John Graves

  I've been using a little utility on my linux-based machines for years called conky.  It can be used to monitor system resources, but I wanted to modify it to monitor my WebLogic managed servers too. Once installing conky, you'll need to update the .conkyrc file.  Here is a simple example. Basically, the important lines are these: - Admin (7001) ${if_empty ${exec /usr/sbin/lsof -i :7001 | grep LISTEN}}${color red}DOWN${color} ${else}${color green} UP ${color}(${tcp_portmon 7001 7001 count}) ${endif} - OSB (8011) ${if_empty ${exec /usr/sbin/lsof -i :8011 | grep LISTEN}}${color red}DOWN${color} ${else}${color green} UP ${color}(${tcp_portmon 8011 8011 count}) ${endif} - BAM (9001) ${if_empty ${exec /usr/sbin/lsof -i :9001 | grep LISTEN}}${color red}DOWN${color} ${else}${color green} UP ${color}(${tcp_portmon 9001 9001 count}) ${endif} - DB (1521) ${if_empty ${exec /usr/sbin/lsof -i :1521 | grep LISTEN}}${color red}DOWN${color} ${else}${color green} UP ${color}(${tcp_portmon 1521 1521 count}) ${endif} It uses lsof to find out if ports are in use. Here is a video showing it in action.

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• How do I set image position in conky

  - by realitygenerator

  I copied and modified an existing .conkyrc file from the ubuntu forum and I'm trying to place the LinuxMint logo in a specific position Below are my conkyrc file and the screenshot # UBUNTU-CONKY # A comprehensive conky script, configured for use on # Ubuntu / Debian Gnome, without the need for any external scripts. # # Based on conky-jc and the default .conkyrc. # INCLUDES: # - tail of /var/log/messages # - netstat shows number of connections from your computer and application/PID making it. Kill spyware! # # -- Pengo # # Create own window instead of using desktop (required in nautilus) own_window yes own_window_type desktop own_window_transparent yes own_window_hints undecorated,below,sticky,skip_taskbar,skip_pager # Use double buffering (reduces flicker, may not work for everyone) double_buffer yes # fiddle with window use_spacer right # Use Xft? use_xft yes xftfont URW Gothic:size=8 xftalpha 0.8 text_buffer_size 2048 # Update interval in seconds update_interval 3.0 # Minimum size of text area # minimum_size 250 5 # Draw shades? draw_shades no # Text stuff draw_outline no # amplifies text if yes draw_borders no uppercase no # set to yes if you want all text to be in uppercase # Stippled borders? stippled_borders 3 # border margins border_margin 9 # border width border_width 10 # Default colors and also border colors, grey90 == #e5e5e5 default_color grey own_window_colour brown own_window_transparent yes # Text alignment, other possible values are commented #alignment top_left #alignment top_right #alignment bottom_left #alignment bottom_right. alignment top_middle # Gap between borders of screen and text gap_x 10 gap_y 10 #Display temp in fahrenheit temperature_unit fahrenheit #Choose which screen on which to display # stuff after 'TEXT' will be formatted on screen TEXT $color ${color green}SYSTEM ${hr 2}$color $nodename $sysname $kernel on $machine LinuxMint 11 "Katya" (Oneric) ${image ~/Conky/Logo_Linux_Mint.png -s 80x60 -f 86400} ${color green}CPU ${hr 2}$color ${freq}MHz Load: ${loadavg} Temp: ${hwmon temp 1} $cpubar ${cpugraph 000000 ffffff} NAME PID CPU% MEM% ${top name 1} ${top pid 1} ${top cpu 1} ${top mem 1} ${top name 2} ${top pid 2} ${top cpu 2} ${top mem 2} ${top name 3} ${top pid 3} ${top cpu 3} ${top mem 3} ${top name 4} ${top pid 4} ${top cpu 4} ${top mem 4} ${color green}MEMORY / DISK ${hr 2}$color RAM: $memperc% ${membar 6}$color Swap: $swapperc% ${swapbar 6}$color Root: ${fs_free_perc /}% ${fs_bar 6 /}$color hda1: ${fs_free_perc /media/sda1}% ${fs_bar 6 /media/sda1}$color ${color green}NETWORK (${addr eth1}) ${hr 2}$color Down: $color${downspeed eth1} k/s ${alignr}Up: ${upspeed eth1} k/s ${downspeedgraph eth1 25,140 000000 ff0000} ${alignr}${upspeedgraph eth1 25,140 000000 00ff00}$color Total: ${totaldown eth1} ${alignr}Total: ${totalup eth1} ${execi 30 netstat -ept | grep ESTAB | awk '{print $9}' | cut -d: -f1 | sort | uniq -c | sort -nr} ${color green}LOGGING ${hr 2}$color ${execi 30 tail -n3 /var/log/messages | awk '{print " ",$5,$6,$7,$8,$9,$10}' | fold -w50} ${color green}FORTUNE ${hr 2}$color ${execi 120 fortune -s | fold -w50} I want to put the mint logo right after the word (oneric). Any help would be greatly appreciated.

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• Server Virtualization Saves Big Bucks for Feds

  Virtually Speaking: Server virtualization in the U.S. House of Representatives results in green saving green to the tune of more than $700,000 dollars.

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• DPM - Monitoring is green, Protection has error and Latest rec point is old. How do I interpret that?

  - by LosManos

  How do I read the DPM info in this case? Monitoring says Failed but Protection shows Ok while having a Latest recovery point from last year. Under Monitoring tab I have Failed for Source | Computer | Protection group | Start time Computer\System Protection | MyServerName | Recovery point | 2014-06-09 19:00:00 which shows me that something happened last night. But under Protection tab everything is green. Here I have Protection group member | | Protection status Protection group ..name.. Computer: MyServerName Computer\System protection Bare metal recovery OK ... Latest recovery point: 2013-12-12 06:32:54 My guess is that backup failed last night once, but succeeded later. It then found out that there hasn't been any change since sometime last year and leave it be and flags Ok.

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• Boundary fill problem

  - by Taaseen

  hi...Im stuck in this bunch of codes...i cant get the pixel to fill up the circle??...any help #include<iostream> #include<glut.h> struct Color{ float red, green, blue; }; Color getPixel(int x, int y){ // gets the color of the pixel at (x,y) Color c; float color[4]; glReadPixels(x,y,1,1,GL_RGBA, GL_FLOAT, color); c.red = color[0]; c.green = color[1]; c.blue = color[2]; return c; } void setPixel(int x, int y, Color c){ glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glPushAttrib(GL_ALL_ATTRIB_BITS); glColor3f(c.red, c.green, c.blue); glBegin(GL_POINTS); glVertex2i(x,y); glEnd(); glPopAttrib(); glFlush(); } void init() { glClearColor(1.0,1.0,1.0,0.0); gluOrtho2D(0.0,300.0,0.0,300.0); } void drawPixel(int x,int y) { glBegin(GL_POINTS); glVertex2i(x,y); glEnd(); glFlush(); } void Boundary_fill(int x,int y,Color thisColor){ Color boundary_color; boundary_color.red=0.0; boundary_color.green=1.0; boundary_color.blue=0.0; Color nextpixel=getPixel(x,y); if((nextpixel.red!=boundary_color.red)&&(nextpixel.blue!=boundary_color.blue)&&(nextpixel.green!=boundary_color.green) && (nextpixel.red!=thisColor.red)&& (nextpixel.blue!=thisColor.blue)&& (nextpixel.green!=thisColor.green)){ setPixel(x,y,thisColor); Boundary_fill((x+1),y,thisColor); Boundary_fill((x-1),y,thisColor); Boundary_fill(x,(y+1),thisColor); Boundary_fill(x,(y-1),thisColor); } } void draw(int x1,int y1, int x, int y){ drawPixel(x1+x,y1+y);//quadrant1 drawPixel(x1+x,y1-y);//quadrant2 drawPixel(x1-x,y1+y);//quadrant3 drawPixel(x1-x,y1-y);//quadrant4 drawPixel(x1+y,y1+x);//quadrant5 drawPixel(x1+y,y1-x);//quadrant6 drawPixel(x1-y,y1+x);//quadrant7 drawPixel(x1-y,y1-x);//quadrant8 } void circle(int px,int py,int r){ int a,b; float p; a=0; b=r; p=(5/4)-r; while(a<=b){ draw(px,py,a,b); if(p<0){ p=p+(2*a)+1; } else{ b=b-1; p=p+(2*a)+1-(2*b); } a=a+1; } } void Circle(void) { Color thisColor; thisColor.red=1.0; thisColor.blue=0.0; thisColor.green=0.0; glClear(GL_COLOR_BUFFER_BIT); glColor3f(0.0,1.0,0.0); glPointSize(2.0); int x0 = 100; int y0 = 150; circle(x0,y0,50); glColor3f(thisColor.red,thisColor.blue,thisColor.green); Boundary_fill(x0,y0,thisColor); } void main(int argc, char**argv) { glutInit(&argc,argv); glutInitDisplayMode(GLUT_SINGLE | GLUT_RGB); glutInitWindowSize(400,400); glutInitWindowPosition(1,1); glutCreateWindow("Boundary fill in a circle:Taaseen And Abhinav"); init(); glutDisplayFunc(Circle); glutMainLoop(); }

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• rspec testing a controller post changing my params from symbols to strings and breaking my tests

  - by ssmithstone

  In my controller spec I am doing this: it "should create new message" do Client.should_receive(:create).with({:title => 'Mr'}) post 'create' , :client => {:title => "Mr" } end ... and in my controller I am doing ... def create client = Client.create(params[:client]) end However this is failing with the following error message : expected: ({:title=>"Mr"}) got: ({"title"=>"Mr"}) I'm wondering why this is happening and how to get it to work

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• Modify Wordpress SQL Query to pull from within a category

  - by Levi

  Hi I am using a wordpress plugin called "kf most read" which stores a count of how many times a post was read, and lets you output a list of most read posts. This works well. The issue is, I am trying to pull the most read posts, but only the most read posts within the current category you are viewing. I am close to clueless when it comes to sql. Here us what the plugin is currently using to pull the most read posts: $sql = "SELECT count(mr.post_ID) as totHits, p.ID, p.post_title from $wpdb-posts p JOIN {$wpdb-prefix}kf_most_read mr on mr.post_ID = p.ID where mr.hit_ts = '".(time() - ( 86400 * $period))."' GROUP BY mr.post_ID order by totHits desc, ID ASC LIMIT $limit"; How could I incorporate the below query which pulls from a specific category into the above? $sql .= "LEFT JOIN $wpdb-term_taxonomy ON($wpdb-term_relationships.term_taxonomy_id = $wpdb-term_taxonomy.term_taxonomy_id)" ; $sql .= "WHERE $wpdb-term_taxonomy.term_id IN ($currentcat)" ; $sql .= "AND $wpdb-term_taxonomy.taxonomy = 'category'" ; Any Help on this would be much appreciated.

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• How do you parse a paragraph of text into sentences? (perferrably in Ruby)

  - by henry74

  How do you take paragraph or large amount of text and break it into sentences (perferably using Ruby) taking into account cases such as Mr. and Dr. and U.S.A? (Assuming you just put the sentences into an array of arrays) UPDATE: One possible solution I thought of involves using a parts-of-speech tagger (POST) and a classifier to determine the end of a sentence: Getting data from Mr. Jones felt the warm sun on his face as he stepped out onto the balcony of his summer home in Italy. He was happy to be alive. CLASSIFIER Mr./PERSON Jones/PERSON felt/O the/O warm/O sun/O on/O his/O face/O as/O he/O stepped/O out/O onto/O the/O balcony/O of/O his/O summer/O home/O in/O Italy/LOCATION ./O He/O was/O happy/O to/O be/O alive/O ./O POST Mr./NNP Jones/NNP felt/VBD the/DT warm/JJ sun/NN on/IN his/PRP$ face/NN as/IN he/PRP stepped/VBD out/RP onto/IN the/DT balcony/NN of/IN his/PRP$ summer/NN home/NN in/IN Italy./NNP He/PRP was/VBD happy/JJ to/TO be/VB alive./IN Can we assume, since Italy is a location, the period is the valid end of the sentence? Since ending on "Mr." would have no other parts-of-speech, can we assume this is not a valid end-of-sentence period? Is this the best answer to the my question? Thoughts?

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• Java image conversion to RGB565

  - by Vladimir

  I try to convert image to RGB565 format. I read this image: BufferedImage bufImg = ImageIO.read(imagePathFile); sendImg = new BufferedImage(CONTROLLER_LCD_WIDTH/*320*/, CONTROLLER_LCD_HEIGHT/*240*/, BufferedImage.TYPE_USHORT_565_RGB); sendImg .getGraphics().drawImage(bufImg, 0, 0, CONTROLLER_LCD_WIDTH/*320*/, CONTROLLER_LCD_HEIGHT/*240*/, null); Here is it: Then I convert it to RGB565: int numByte=0; byte[] OutputImageArray = new byte[CONTROLLER_LCD_WIDTH*CONTROLLER_LCD_HEIGHT*2]; int i=0; int j=0; int len = OutputImageArray.length; for (i=0;i<CONTROLLER_LCD_WIDTH;i++) { for (j=0;j<CONTROLLER_LCD_HEIGHT;j++) { Color c = new Color(sendImg.getRGB(i, j)); int aRGBpix = sendImg.getRGB(i, j); int alpha; int red = c.getRed(); int green = c.getGreen(); int blue = c.getBlue(); //RGB888 red = (aRGBpix >> 16) & 0x0FF; green = (aRGBpix >> 8) & 0x0FF; blue = (aRGBpix >> 0) & 0x0FF; alpha = (aRGBpix >> 24) & 0x0FF; //RGB565 red = red >> 3; green = green >> 2; blue = blue >> 3; //A pixel is represented by a 4-byte (32 bit) integer, like so: //00000000 00000000 00000000 11111111 //^ Alpha ^Red ^Green ^Blue //Converting to RGB565 short pixel_to_send = 0; int pixel_to_send_int = 0; pixel_to_send_int = (red << 11) | (green << 5) | (blue); pixel_to_send = (short) pixel_to_send_int; //dividing into bytes byte byteH=(byte)((pixel_to_send >> 8) & 0x0FF); byte byteL=(byte)(pixel_to_send & 0x0FF); //Writing it to array - High-byte is second OutputImageArray[numByte]=byteH; OutputImageArray[numByte+1]=byteL; numByte+=2; } } Then I try to restore this from resulting array OutputImageArray: i=0; j=0; numByte=0; BufferedImage NewImg = new BufferedImage(CONTROLLER_LCD_WIDTH, CONTROLLER_LCD_HEIGHT, BufferedImage.TYPE_USHORT_565_RGB); for (i=0;i<CONTROLLER_LCD_WIDTH;i++) { for (j=0;j<CONTROLLER_LCD_HEIGHT;j++) { int curPixel=0; int alpha=0x0FF; int red; int green; int blue; byte byteL=0; byte byteH=0; byteH = OutputImageArray[numByte]; byteL = OutputImageArray[numByte+1]; curPixel= (byteH << 8) | (byteL); //RGB565 red = (curPixel >> (6+5)) & 0x01F; green = (curPixel >> 5) & 0x03F; blue = (curPixel) & 0x01F; //RGB888 red = red << 3; green = green << 2; blue = blue << 3; //aRGB curPixel = 0; curPixel = (alpha << 24) | (red << 16) | (green << 8) | (blue); NewImg.setRGB(i, j, curPixel); numByte+=2; } } I output this restored image. But I see that it looks very poor. I expected the lost of pictures quality. But as I thought, this picture has to have almost the same quality as the previous picture. - Is it right? Is my code right?

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• What do the FireBug DOM colors mean?

  - by André Pena

  I'm confused with these colors. I noticed there are 4 colors showing in the left hand column of FireBug DOM tree: Bold black Black Bold green Green In the right hand column: Blue Red Bold green Green Multiple color elements representing object structures. What do this colors represent? And why, e.g, I can access window.document.URL and I can't access window.document.body in Console even though they are both in the "not-bold black" category in the DOM tree? Thanks a lot

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• Python: For loop problem

  - by Yasmin

  I have a simple for loop problem, when i run the code below it prints out series of 'blue green' sequences then a series of 'green' sequences. I want the output to be; if row[4] is equal to 1 to print blue else print green. for row in rows: for i in `row[4]`: if i ==`1`: print 'blue ' else: print 'green ' Any help would be grateful thanks Yas

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• CISDI Cloud - Industrial Cloud Computing Platform based on Oracle Products

  - by Wenyu Duan

  In today's era, Cloud Computing is becoming integral to the vision and corporate strategy of leading organizations and is often seen as a key business driver to achieve growth and innovation. Headquartered in Chongqing, China, CISDI Engineering Co., Ltd. is a large state-owned engineering company, offering consulting, engineering design, EPC contracting, and equipment integration services to steel producers all over the world. With over 50 years of experience, CISDI offers quality services for every aspect of production for projects in the metal industry and the company has evolved into a leading international engineering service group with 18 subsidiaries providing complete lifecycle for E&C projects. CISDI group delegation led by Mr. Zhaohui Yu, CEO of CISDI Group, Mr. Zhiyou Li, CEO of CISDI Info, Mr. Qing Peng, CTO of CISDI Info and Mr. Xin Xiao, Head of CISDI Info's R&D joined Oracle OpenWorld 2012 and presented a very impressive cloud initiative case in their session titled “E&C Industry Solution in CISDI Cloud - An Industrial Cloud Computing Platform Based on Oracle Products”. CISDI group plans to expand through three phases in the construction of its cloud computing platform: first, it will relocate its existing technologies to Oracle systems, along with establishing private cloud for CISDI; secondly, it will gradually provide mixed cloud services for its subsidiaries and partners; and finally it plans to launch an industrial cloud with a highly mature, secure and scalable environment providing cloud services for customers in the engineering construction and steel industries, among others. “CISDI Cloud” will become the growth engine for the organization to expand its global reach through online services and achieving the strategic objective of being the preferred choice of E&C companies worldwide. The new cloud computing platform is designed to provide access to the shared computing resources pool in a self-service, dynamic, elastic and measurable way. It’s flexible and scalable grid structure can support elastic expansion and sustainable growth, and can bring significant benefits in speed, agility and efficiency. Further, the platform can greatly cut down deployment and maintenance costs. CISDI delegation highlighted these points as the key reasons why the group decided to have a strategic collaboration with Oracle for building this world class industrial cloud - - Oracle’s strategy: Open, Complete and Integrated - Oracle as the only company who can provide engineered system, with complete product chain of hardware and software - Exadata, Exalogic, EM 12c to provide solid foundation for "CISDI Cloud" The cloud blueprint and advanced architecture for industrial cloud computing platform presented in the session shows how Oracle products and technologies together with industrial applications from CISDI can provide end-end portfolio of E&C industry services in cloud. CISDI group was recognized for business leadership and innovative solutions and was presented with Engineering and Construction Industry Excellence Award during Oracle OpenWorld.

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• Use jQuery to find div by background color

  - by maxsilver

  I'm trying to use jQuery to find the number of divs that are both visible, and have a background color of Green. (Normally I'd just add a class to the div, style it green, and check for that class in jQuery but in this instance, I can't actually change the markup of the page itself in any way) I currently have the visible div part working as : if( // if there are more than one visible div $('div.progressContainer:visible').length > 0 ){ I'd like to throw some kind of "and background color is green" selector in there. // not legit javascript if( // if there are more than one visible div, and its color is green $('div.progressContainer:visible[background-color:green]').length > 0 ){ Is it possible to do this?

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• help with boxplot needed

  - by kathy_BJ

  I am new to R, can anyone help me with boxplot for a dataset like: file1 col1 col2 col3 col4 col5 050350005 101 56.625 48.318 RED 051010002 106 50.625 46.990 GREEN 051190007 25 65.875 74.545 BLUE 051191002 246 52.875 57.070 RED 220050004 55 70 80.274 BLUE 220150008 75 67.750 62.749 RED 220170001 77 65.750 54.307 GREEN file2 col1 col2 col3 col4 col5 050350005 101 56.625 57 RED 051010002 106 50.625 77 GREEN 051190007 25 65.875 51.6 BLUE 051191002 246 52.875 55.070 RED 220050004 55 70 32 BLUE 220150008 75 67.750 32.49 RED 220170001 77 65.750 84.07 GREEN for each color (red,green and blue), I need to compare file1 and file2 by making box plot with MB and RMSE for (col4-col3) for file1 and file2 by dividing col2 in different group: if col2<20,20<=col2<50, 50 <= col2 <70, col2 =70. That is, for the boxplot, the x is (<20, 20-50,50-70, 70), while y is MB (and RMSE) of the difference of col4 and col3 I hope I didn't confuse anybody. Thank you so much.

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• How can I turn a bunch of rows into aggregated columns WITHOUT using pivot in SQL Server 2005?

  - by cdeszaq

  Here is the scenario: I have a table that records the user_id, the module_id, and the date/time the module was viewed. eg. Table: Log ------------------------------ User_ID Module_ID Date ------------------------------ 1 red 2001-01-01 1 green 2001-01-02 1 blue 2001-01-03 2 green 2001-01-04 2 blue 2001-01-05 1 red 2001-01-06 1 blue 2001-01-07 3 blue 2001-01-08 3 green 2001-01-09 3 red 2001-01-10 3 green 2001-01-11 4 white 2001-01-12 I need to get a result set that has the user_id as the 1st column, and then a column for each module. The row data is then the user_id and the count of the number of times that user viewed each module. eg. --------------------------------- User_ID red green blue white --------------------------------- 1 2 1 2 0 2 0 1 1 0 3 1 2 1 0 4 0 0 0 1 I was initially thinking that I could do this with PIVOT, but no dice; the database is a converted SQL Server 2000 DB that is running in SQL Server 2005. I'm not able to change the compatibility level, so pivot is out. How can I accomplish this?

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