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  • form submits in FireFox when any button on page is clicked

    - by RememberME
    First time using Asp.net-mvc and originally followed the NerdDinner tutorial. My form submit button looks like this: <p> <input type="submit" value="Save" /> </p> I've now added another button to the page with jQuery code attached. It works in IE, but when I test in FireFox the form submits. I tried adding another button, this time with no attached jQuery code and the same thing happens. When the button is clicked, the form submits. <button id="random-button">Do Nothing</button> ??

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  • jquery form validation, and submit-on-change

    - by Bee
    I want to make all my settings forms across my site confirm that changes are saved, kinda like facebook does if you make changes in a form and then try to navigate away without saving. So I'm disabling the submit button on the forms only enabling if the values change. I then prompt the user to hit save before they leave the page in the case that they do have changes pending. var form = $('form.edit'); if(form.length > 0) { var orig_str = form.serialize(); $(':submit',form).attr('disabled','disabled'); form.on('change keyup', function(){ if(form.serialize() == orig_str) { setConfirmUnload(false); $(':submit',form).attr('disabled','disabled'); } else { setConfirmUnload(true); $(':submit',form).removeAttr('disabled') } }); $('input[type=submit]').click(function(){ setConfirmUnload(false); }); } function setConfirmUnload(on) { window.onbeforeunload = (on) ? unloadMessage : null; } function unloadMessage() { return 'If you navigate away from this page without saving your changes, they will be lost.'; } One of these forms needs some additional validation which I do using jQuery.validate library. e.g. if i wanted to ensure the user can't double submit the form on accident by double clicking on submit or somesuch (the actual validation in question is for a credit-card form and not this simple): $('form').validate({ submitHandler: function(form) { $(':submit', form).attr('disabled','disabled'); form.submit(); } }); Unfortunately both bits are trying to bind to submit button and they're interfering with each other such that the submit button remains disabled no matter what I do and it is impossible to submit the form at all. Is there some way to chain the validations together or something? Or some other way to avoid re-writing the validation code to repeat the "did you change anything in the form" business?

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  • Security Issues with Single Page Apps

    - by Stephen.Walther
    Last week, I was asked to do a code review of a Single Page App built using the ASP.NET Web API, Durandal, and Knockout (good stuff!). In particular, I was asked to investigate whether there any special security issues associated with building a Single Page App which are not present in the case of a traditional server-side ASP.NET application. In this blog entry, I discuss two areas in which you need to exercise extra caution when building a Single Page App. I discuss how Single Page Apps are extra vulnerable to both Cross-Site Scripting (XSS) attacks and Cross-Site Request Forgery (CSRF) attacks. This goal of this blog post is NOT to persuade you to avoid writing Single Page Apps. I’m a big fan of Single Page Apps. Instead, the goal is to ensure that you are fully aware of some of the security issues related to Single Page Apps and ensure that you know how to guard against them. Cross-Site Scripting (XSS) Attacks According to WhiteHat Security, over 65% of public websites are open to XSS attacks. That’s bad. By taking advantage of XSS holes in a website, a hacker can steal your credit cards, passwords, or bank account information. Any website that redisplays untrusted information is open to XSS attacks. Let me give you a simple example. Imagine that you want to display the name of the current user on a page. To do this, you create the following server-side ASP.NET page located at http://MajorBank.com/SomePage.aspx: <%@Page Language="C#" %> <html> <head> <title>Some Page</title> </head> <body> Welcome <%= Request["username"] %> </body> </html> Nothing fancy here. Notice that the page displays the current username by using Request[“username”]. Using Request[“username”] displays the username regardless of whether the username is present in a cookie, a form field, or a query string variable. Unfortunately, by using Request[“username”] to redisplay untrusted information, you have now opened your website to XSS attacks. Here’s how. Imagine that an evil hacker creates the following link on another website (hackers.com): <a href="/SomePage.aspx?username=<script src=Evil.js></script>">Visit MajorBank</a> Notice that the link includes a query string variable named username and the value of the username variable is an HTML <SCRIPT> tag which points to a JavaScript file named Evil.js. When anyone clicks on the link, the <SCRIPT> tag will be injected into SomePage.aspx and the Evil.js script will be loaded and executed. What can a hacker do in the Evil.js script? Anything the hacker wants. For example, the hacker could display a popup dialog on the MajorBank.com site which asks the user to enter their password. The script could then post the password back to hackers.com and now the evil hacker has your secret password. ASP.NET Web Forms and ASP.NET MVC have two automatic safeguards against this type of attack: Request Validation and Automatic HTML Encoding. Protecting Coming In (Request Validation) In a server-side ASP.NET app, you are protected against the XSS attack described above by a feature named Request Validation. If you attempt to submit “potentially dangerous” content — such as a JavaScript <SCRIPT> tag — in a form field or query string variable then you get an exception. Unfortunately, Request Validation only applies to server-side apps. Request Validation does not help in the case of a Single Page App. In particular, the ASP.NET Web API does not pay attention to Request Validation. You can post any content you want – including <SCRIPT> tags – to an ASP.NET Web API action. For example, the following HTML page contains a form. When you submit the form, the form data is submitted to an ASP.NET Web API controller on the server using an Ajax request: <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title></title> </head> <body> <form data-bind="submit:submit"> <div> <label> User Name: <input data-bind="value:user.userName" /> </label> </div> <div> <label> Email: <input data-bind="value:user.email" /> </label> </div> <div> <input type="submit" value="Submit" /> </div> </form> <script src="Scripts/jquery-1.7.1.js"></script> <script src="Scripts/knockout-2.1.0.js"></script> <script> var viewModel = { user: { userName: ko.observable(), email: ko.observable() }, submit: function () { $.post("/api/users", ko.toJS(this.user)); } }; ko.applyBindings(viewModel); </script> </body> </html> The form above is using Knockout to bind the form fields to a view model. When you submit the form, the view model is submitted to an ASP.NET Web API action on the server. Here’s the server-side ASP.NET Web API controller and model class: public class UsersController : ApiController { public HttpResponseMessage Post(UserViewModel user) { var userName = user.UserName; return Request.CreateResponse(HttpStatusCode.OK); } } public class UserViewModel { public string UserName { get; set; } public string Email { get; set; } } If you submit the HTML form, you don’t get an error. The “potentially dangerous” content is passed to the server without any exception being thrown. In the screenshot below, you can see that I was able to post a username form field with the value “<script>alert(‘boo’)</script”. So what this means is that you do not get automatic Request Validation in the case of a Single Page App. You need to be extra careful in a Single Page App about ensuring that you do not display untrusted content because you don’t have the Request Validation safety net which you have in a traditional server-side ASP.NET app. Protecting Going Out (Automatic HTML Encoding) Server-side ASP.NET also protects you from XSS attacks when you render content. By default, all content rendered by the razor view engine is HTML encoded. For example, the following razor view displays the text “<b>Hello!</b>” instead of the text “Hello!” in bold: @{ var message = "<b>Hello!</b>"; } @message   If you don’t want to render content as HTML encoded in razor then you need to take the extra step of using the @Html.Raw() helper. In a Web Form page, if you use <%: %> instead of <%= %> then you get automatic HTML Encoding: <%@ Page Language="C#" %> <% var message = "<b>Hello!</b>"; %> <%: message %> This automatic HTML Encoding will prevent many types of XSS attacks. It prevents <script> tags from being rendered and only allows &lt;script&gt; tags to be rendered which are useless for executing JavaScript. (This automatic HTML encoding does not protect you from all forms of XSS attacks. For example, you can assign the value “javascript:alert(‘evil’)” to the Hyperlink control’s NavigateUrl property and execute the JavaScript). The situation with Knockout is more complicated. If you use the Knockout TEXT binding then you get HTML encoded content. On the other hand, if you use the HTML binding then you do not: <!-- This JavaScript DOES NOT execute --> <div data-bind="text:someProp"></div> <!-- This Javacript DOES execute --> <div data-bind="html:someProp"></div> <script src="Scripts/jquery-1.7.1.js"></script> <script src="Scripts/knockout-2.1.0.js"></script> <script> var viewModel = { someProp : "<script>alert('Evil!')<" + "/script>" }; ko.applyBindings(viewModel); </script>   So, in the page above, the DIV element which uses the TEXT binding is safe from XSS attacks. According to the Knockout documentation: “Since this binding sets your text value using a text node, it’s safe to set any string value without risking HTML or script injection.” Just like server-side HTML encoding, Knockout does not protect you from all types of XSS attacks. For example, there is nothing in Knockout which prevents you from binding JavaScript to a hyperlink like this: <a data-bind="attr:{href:homePageUrl}">Go</a> <script src="Scripts/jquery-1.7.1.min.js"></script> <script src="Scripts/knockout-2.1.0.js"></script> <script> var viewModel = { homePageUrl: "javascript:alert('evil!')" }; ko.applyBindings(viewModel); </script> In the page above, the value “javascript:alert(‘evil’)” is bound to the HREF attribute using Knockout. When you click the link, the JavaScript executes. Cross-Site Request Forgery (CSRF) Attacks Cross-Site Request Forgery (CSRF) attacks rely on the fact that a session cookie does not expire until you close your browser. In particular, if you visit and login to MajorBank.com and then you navigate to Hackers.com then you will still be authenticated against MajorBank.com even after you navigate to Hackers.com. Because MajorBank.com cannot tell whether a request is coming from MajorBank.com or Hackers.com, Hackers.com can submit requests to MajorBank.com pretending to be you. For example, Hackers.com can post an HTML form from Hackers.com to MajorBank.com and change your email address at MajorBank.com. Hackers.com can post a form to MajorBank.com using your authentication cookie. After your email address has been changed, by using a password reset page at MajorBank.com, a hacker can access your bank account. To prevent CSRF attacks, you need some mechanism for detecting whether a request is coming from a page loaded from your website or whether the request is coming from some other website. The recommended way of preventing Cross-Site Request Forgery attacks is to use the “Synchronizer Token Pattern” as described here: https://www.owasp.org/index.php/Cross-Site_Request_Forgery_%28CSRF%29_Prevention_Cheat_Sheet When using the Synchronizer Token Pattern, you include a hidden input field which contains a random token whenever you display an HTML form. When the user opens the form, you add a cookie to the user’s browser with the same random token. When the user posts the form, you verify that the hidden form token and the cookie token match. Preventing Cross-Site Request Forgery Attacks with ASP.NET MVC ASP.NET gives you a helper and an action filter which you can use to thwart Cross-Site Request Forgery attacks. For example, the following razor form for creating a product shows how you use the @Html.AntiForgeryToken() helper: @model MvcApplication2.Models.Product <h2>Create Product</h2> @using (Html.BeginForm()) { @Html.AntiForgeryToken(); <div> @Html.LabelFor( p => p.Name, "Product Name:") @Html.TextBoxFor( p => p.Name) </div> <div> @Html.LabelFor( p => p.Price, "Product Price:") @Html.TextBoxFor( p => p.Price) </div> <input type="submit" /> } The @Html.AntiForgeryToken() helper generates a random token and assigns a serialized version of the same random token to both a cookie and a hidden form field. (Actually, if you dive into the source code, the AntiForgeryToken() does something a little more complex because it takes advantage of a user’s identity when generating the token). Here’s what the hidden form field looks like: <input name=”__RequestVerificationToken” type=”hidden” value=”NqqZGAmlDHh6fPTNR_mti3nYGUDgpIkCiJHnEEL59S7FNToyyeSo7v4AfzF2i67Cv0qTB1TgmZcqiVtgdkW2NnXgEcBc-iBts0x6WAIShtM1″ /> And here’s what the cookie looks like using the Google Chrome developer toolbar: You use the [ValidateAntiForgeryToken] action filter on the controller action which is the recipient of the form post to validate that the token in the hidden form field matches the token in the cookie. If the tokens don’t match then validation fails and you can’t post the form: public ActionResult Create() { return View(); } [ValidateAntiForgeryToken] [HttpPost] public ActionResult Create(Product productToCreate) { if (ModelState.IsValid) { // save product to db return RedirectToAction("Index"); } return View(); } How does this all work? Let’s imagine that a hacker has copied the Create Product page from MajorBank.com to Hackers.com – the hacker grabs the HTML source and places it at Hackers.com. Now, imagine that the hacker trick you into submitting the Create Product form from Hackers.com to MajorBank.com. You’ll get the following exception: The Cross-Site Request Forgery attack is blocked because the anti-forgery token included in the Create Product form at Hackers.com won’t match the anti-forgery token stored in the cookie in your browser. The tokens were generated at different times for different users so the attack fails. Preventing Cross-Site Request Forgery Attacks with a Single Page App In a Single Page App, you can’t prevent Cross-Site Request Forgery attacks using the same method as a server-side ASP.NET MVC app. In a Single Page App, HTML forms are not generated on the server. Instead, in a Single Page App, forms are loaded dynamically in the browser. Phil Haack has a blog post on this topic where he discusses passing the anti-forgery token in an Ajax header instead of a hidden form field. He also describes how you can create a custom anti-forgery token attribute to compare the token in the Ajax header and the token in the cookie. See: http://haacked.com/archive/2011/10/10/preventing-csrf-with-ajax.aspx Also, take a look at Johan’s update to Phil Haack’s original post: http://johan.driessen.se/posts/Updated-Anti-XSRF-Validation-for-ASP.NET-MVC-4-RC (Other server frameworks such as Rails and Django do something similar. For example, Rails uses an X-CSRF-Token to prevent CSRF attacks which you generate on the server – see http://excid3.com/blog/rails-tip-2-include-csrf-token-with-every-ajax-request/#.UTFtgDDkvL8 ). For example, if you are creating a Durandal app, then you can use the following razor view for your one and only server-side page: @{ Layout = null; } <!DOCTYPE html> <html> <head> <title>Index</title> </head> <body> @Html.AntiForgeryToken() <div id="applicationHost"> Loading app.... </div> @Scripts.Render("~/scripts/vendor") <script type="text/javascript" src="~/App/durandal/amd/require.js" data-main="/App/main"></script> </body> </html> Notice that this page includes a call to @Html.AntiForgeryToken() to generate the anti-forgery token. Then, whenever you make an Ajax request in the Durandal app, you can retrieve the anti-forgery token from the razor view and pass the token as a header: var csrfToken = $("input[name='__RequestVerificationToken']").val(); $.ajax({ headers: { __RequestVerificationToken: csrfToken }, type: "POST", dataType: "json", contentType: 'application/json; charset=utf-8', url: "/api/products", data: JSON.stringify({ name: "Milk", price: 2.33 }), statusCode: { 200: function () { alert("Success!"); } } }); Use the following code to create an action filter which you can use to match the header and cookie tokens: using System.Linq; using System.Net.Http; using System.Web.Helpers; using System.Web.Http.Controllers; namespace MvcApplication2.Infrastructure { public class ValidateAjaxAntiForgeryToken : System.Web.Http.AuthorizeAttribute { protected override bool IsAuthorized(HttpActionContext actionContext) { var headerToken = actionContext .Request .Headers .GetValues("__RequestVerificationToken") .FirstOrDefault(); ; var cookieToken = actionContext .Request .Headers .GetCookies() .Select(c => c[AntiForgeryConfig.CookieName]) .FirstOrDefault(); // check for missing cookie or header if (cookieToken == null || headerToken == null) { return false; } // ensure that the cookie matches the header try { AntiForgery.Validate(cookieToken.Value, headerToken); } catch { return false; } return base.IsAuthorized(actionContext); } } } Notice that the action filter derives from the base AuthorizeAttribute. The ValidateAjaxAntiForgeryToken only works when the user is authenticated and it will not work for anonymous requests. Add the action filter to your ASP.NET Web API controller actions like this: [ValidateAjaxAntiForgeryToken] public HttpResponseMessage PostProduct(Product productToCreate) { // add product to db return Request.CreateResponse(HttpStatusCode.OK); } After you complete these steps, it won’t be possible for a hacker to pretend to be you at Hackers.com and submit a form to MajorBank.com. The header token used in the Ajax request won’t travel to Hackers.com. This approach works, but I am not entirely happy with it. The one thing that I don’t like about this approach is that it creates a hard dependency on using razor. Your single page in your Single Page App must be generated from a server-side razor view. A better solution would be to generate the anti-forgery token in JavaScript. Unfortunately, until all browsers support a way to generate cryptographically strong random numbers – for example, by supporting the window.crypto.getRandomValues() method — there is no good way to generate anti-forgery tokens in JavaScript. So, at least right now, the best solution for generating the tokens is the server-side solution with the (regrettable) dependency on razor. Conclusion The goal of this blog entry was to explore some ways in which you need to handle security differently in the case of a Single Page App than in the case of a traditional server app. In particular, I focused on how to prevent Cross-Site Scripting and Cross-Site Request Forgery attacks in the case of a Single Page App. I want to emphasize that I am not suggesting that Single Page Apps are inherently less secure than server-side apps. Whatever type of web application you build – regardless of whether it is a Single Page App, an ASP.NET MVC app, an ASP.NET Web Forms app, or a Rails app – you must constantly guard against security vulnerabilities.

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  • Does Google submit HTML forms?

    - by Saeed Neamati
    I have a web page, say http://domain/purchase and in this page, I have a web form. User, on submitting this form (which has validation, both client-side and server side and won't be validated until fields are filled appropriately), would be redirected to another page, where (s)he can choose other things, and specify other settings and then purchase our product. Say the second page is http://domain/options. So, user comes to our site and visits http://domain/purchase, fills the form, submits it, and then would be redirected to the second page, http://doamin/options?parameter1=value1&parameter2=value2, which contains parameters from the first page. This is very common in passing parameters between web pages (or technically, between URLs). Now I was reviewing my website, and saw that Google had indexed some of my redirected web pages and URLs, like: http://domain/options?parameter1=value1&parameter2=value2 http://domain/options?parameter1=value3&parameter2=value4 http://domain/options?parameter1=value5&parameter2=value6 http://domain/options?parameter1=value7&parameter2=value8 http://domain/options?parameter1=value9&parameter2=value10 This means that Google Bot has visited our http://domain/purchase page, and has filled our form, and has submitted it, and was being redirected to the other URL, with corresponding parameters. This is the only way that makes sense to me. Does Google really fills forms? PS: All parameters are meaningful, meaning that they are not filled arbitrarily. For example, the phone parameter in indexed pages has correct phone numbers. How is it possible?

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  • Using hash to check if page with $_POST values was refreshed

    - by Dieseltime
    When posting a form to the same PHP page, what is the correct method to find if the page was accidentally refreshed instead of submitted again? Here's what I'm using right now: $tmp = implode('',$_POST); $myHash = md5($tmp); if(isset($_SESSION["myHash"]) && $_SESSION["myHash"] == $myHash) { header("Location: index.php"); // page refreshed, send user somewhere else die(); } else { $_SESSION["myHash"] = $myHash; } // continue processing... Is there anything wrong with this solution?

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  • How to redirect page

    - by sharun
    Hi i created one java application in which i tried to open my company's standard login page and i planned to redirect the link to open my own design page. Standard login page is displayed, instead of going to my own design page as usual its going to mail page. After sign out the mail page i'm gettting my own design page. But my need is, when i sign in the standard login page it should diplay my own design page. Is it possible? Please Help me. And this is code that i followed import java.io.IOException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.google.appengine.api.users.UserService; import com.google.appengine.api.users.UserServiceFactory; import com.google.appengine.api.users.User; public class New extends HttpServlet { /** * */ private static final long serialVersionUID = 1L; public void doPost(HttpServletRequest req, HttpServletResponse resp) throws IOException { resp.setHeader("Cache-Control", "no-store, no-cache, must-revalidate"); resp.setContentType("text/html"); UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); if (user != null) { if(user.getEmail().equals("[email protected]")) { resp.getWriter().println("done"); resp.sendRedirect("/login.jsp"); } else { resp.getWriter().println("Hello, " + user.getNickname()+"<br>"); resp.getWriter().println("Thanks for your interest. But this application is still not available to everybody."); resp.getWriter().println("<a href="+UserServiceFactory.getUserService().createLogoutURL(userService.createLoginURL(req.getRequestURI()))+">Log out</a>"); } } else { resp.sendRedirect(userService.createLoginURL("http://mail.yyy.edu.in")); } } } Thanks in advance Regards Sharun.

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  • Web page from the terminal

    - by juanpablo
    Hi, I use snow leopard. how I can send a html page to web browser from the terminal? example: if I am in $HOME dir, where exist myPage.html, I can send this page for see in web browser with a command ? Many thanks.

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  • Good places to submit a business profile?

    - by Rob
    We have a new graphic/web design site that we've created and we'd like to give it a boost in terms of back links. What are the obvious places to submit a website to achieve some good back links? And what would be the recurring work load (if any) that those back links would need? Are there any good industry specific websites we could submit a profile to? E.g Twitter, would need constant interaction and new content with back links to the website. UPDATE: I've always felt it's worth it but after several years trying to submit different websites, I've never successfully managed to get a site into DMOZ!!

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  • access dropdown control from the master page to the content page using asp.net

    - by Isha Jain
    i have a master page and the content pages in the master page i have the textbox and dropdown the value in the dropdown may vary according to the content pages e.g for one content page the dropdown may contain branchname, city, address and let for other content page under same master page the dropdown may have values like Contactnumber, EmailID, ........... ......... etc..... so please help me to how can i bind that dropdown from my content page thanks.

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  • android webview returns blank page when load dynamic html page

    - by user2962555
    I am trying to click one button to load a page into a div block dynamically. To test it, I try to append a list item with text "abc" into the loaded page. However, I always get a blank page. load function works fine because if I try to load a static page, it works. Following is my main html page code. <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <title>LoadPageTest</title> <link rel="stylesheet" href="http://fonts.googleapis.com/css?family=Open+Sans:300,400,700"> <link rel="stylesheet" href="./css/customizedstyle.css"> <link rel="stylesheet" href="./css/themes/default/jquery.mobile-1.4.3.min.css"> <link rel="stylesheet" href="./css/jqm-demos.css"> <script src="./js/jquery.js"></script> <script scr="./js/customizedjs.js"></script> <script src="./js/jquery.mobile-1.4.3.min.js"></script> <script> $( document ).on( "pagecreate", "#demo-page", function() { $( document ).on( "swipeleft swiperight", "#demo-page", function( e ) { if ( $( ".ui-page-active" ).jqmData( "panel" ) !== "open" ) { if ( e.type === "swipeleft" ) { $( "#right-panel" ).panel( "open" ); } } }); }); </script> <style type="text/css"> body { overflow:hidden; } </style> </head> <body style= "overflow:hidden" scrolling="no"> <style type="text/css"> body { overflow:hidden; } </style> <div data-role="page" id="main-page" style= "overflow:hidden" scrolling="no"> <div role="main" class="ui-content" id ="maindiv" style= "overflow: auto"> Will load diff pages here. </div><!-- /content --> <div data-role="panel" id="left-panel" data-theme="b"> <ul data-role="listview" data-icon="false" id="menu"> <li> <a href="#" id = "btnA" data-rel="close">Go Page A <img src="./images/icona.png" class="ui-li-thumb"/> </li> <li> <a href="#" id = "btnB" data-rel="close">Go Page B <img src="./images/iconb.png" class="ui-li-thumb"/> </li> </ul> </div><!-- /panel --> <script type="text/javascript"> $("#btnA").on("click", function(){ $("#maindiv").empty(); $("#maindiv").load("pageA.html"); }); $("#btnB").on("click", function(){ $("#maindiv").empty(); $("#maindiv").load("pageB.html"); }); </script> </div><!-- /page --> </body> </html> Next is code for the page I try to load dynamically. <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <title>Page should be loaded</title> <link rel="stylesheet" href="http://fonts.googleapis.com/css?family=Open+Sans:300,400,700"> <link rel="stylesheet" href="./css/customizedstyle.css"> <link rel="stylesheet" href="./css/themes/default/jquery.mobile-1.4.3.min.css"> <link rel="stylesheet" href="./css/jqm-demos.css"> <script src="./js/jquery.js"></script> <script scr="./js/customizedjs.js"></script> <script src="./js/jquery.mobile-1.4.3.min.js"></script> <script> $(document).on('pagebeforeshow', function () { $('#postlist').append('<li> abc </li>'); $('#postlist').listview('refresh'); }); </script> </head> <body > <div data-role="page" id="posthome"> <div data-role = "content"> <ul data-role='listview' id = "postlist"> </ul> </div> </div> </body> </html> I doubt if it is because my javascript in the page doesn't work, cause the swipe js code in the main page seems not work either. Is that possible? I have enabled javascript in the onCreate() function of the activity file as below. protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_message); new LongRunningGetIO().execute(); mWebView = (WebView) findViewById(R.id.webview); mWebView.setWebViewClient(new AppClient()); mWebView.setVerticalScrollBarEnabled(false); mWebView.getSettings().setJavaScriptEnabled(true); mWebView.getSettings().setDomStorageEnabled(true); mWebView.loadUrl("file:///android_asset/index.html"); } I noticed there is a warning for statement to enable javascript "Using setJavaScriptEnabled can introduce XSS vulnerabilities into you application, review carefully". Will that maybe the reason? Then, I added @SuppressLint("SetJavaScriptEnabled") on top of the activity. The warning is gone, but the js code in pages seem still not work.

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  • Why make the login page to a single page application a separate page?

    - by ryanzec
    I am wondering why it seems to be popular to have the login page of a SPA be a separate page that is not page of the SPA (as in loaded and send data through ajax requests)? I only thing I can think of is security but I can't think a specific security reason. I mean the only thing that come to mind is that if your login page in part of the SPA, it sends the username/password through ajax which can be seen by such tools like firebug or web inspector however even if you send it as a normal POST request, there are other tools that can easily capture this data (like fiddler, httpscoop, etc...). Is there something I am missing?

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  • how to open HTML page stored on client machine from aspx page.

    - by shania
    Hi, I m developing asp.net application in which I m opening HTML page that is stored on client machine on that page I have a link which will open aspx page on server, On that aspx page I have a button that will open another html page stored on client machine. Since I m new to web development Plz help me and suggest me some solutions for this ASAP. Thanks....

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  • Rails, Edit page update in a window

    - by Mike
    I have my code working so that I have a table of businesses. There's a pencil icon you can click on the edit the business information. The edit information comes up in a partial inside of a modal pop up box. The only problem is that once they make the changes they want and click update, it sends them to the 'show' page for that business. What I want to happen is have the pop up box close and have it update the information. This is my update function in my controller. def update @business = Business.find(params[:id]) respond_to do |format| if @business.update_attributes(params[:business]) flash[:notice] = 'Business was successfully updated.' format.html { redirect_to(business_url(@business)) } format.js else format.html { render :action => "edit" } format.xml { render :xml => @business.errors, :status => :unprocessable_entity } end end end I tried following railscast 43 and i created an .rjs file but I couldn't get that to work at all. My update was still taking me to the show page. Any help would be appreciated. EDIT: Added some more code. <% form_for(@business) do |f| %> <%= f.error_messages %> <p> <%= f.label :name %><br /> <%= f.text_field :name %> </p> ... <%= f.label :business_category %><br /> <%= f.select :business_category_id, @business_categories_map, :selected => @business.business_category_id %> </p> <p> <%= f.label :description %><br /> <%= f.text_area :description %> </p> <p> <%= f.submit 'Update' %> </p> <% end %> This is my form inside of my edit page which is being called through the index in a pop up by: <div id="popupEdit<%=h business.id %>" class="popupContact"> <a class="popupClose<%=h business.id %>" id="popupClose">x</a> <% if business.business_category_id %> <% @business = business %> <%= render "business/edit" %> <% end %> </div>

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  • Page submission problem with safari

    - by jestges
    Hi I'm working with a simple application in asp.net (c#). In my page1 I've a load button in that load button click event I try to open another window. In my second window I've a button If I click on that button my intension is to reload parent page (i.e page1). So I try to use this script scriptString = " window.opener.location.href = myparentpage; window.opener.document.getElementById('ValidationSummary1').style.display='none';"; Page.ClientScript.RegisterClientScriptBlock(this.GetType(), "script", scriptString); But it is not working in Safari. Is there any solution?

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  • why resubmit after refresh php page

    - by user2719452
    why resubmit after refresh php page? try it, go to: http://qass.im/message-envelope/ and upload any image now try click F5, after refresh page "resubmit" Why? I don't want resubmit after refresh page What is the solution? See this is my form code: <form id="uploadedfile" name="uploadedfile" enctype="multipart/form-data" action="upload.php" method="POST"> <input name="uploadedfile" type="file" /> <input type="submit" value="upload" /> </form> See this is php code upload.php file: <?php $allowedExts = array("gif", "jpeg", "jpg", "png", "zip", "pdf", "docx", "rar", "txt", "doc"); $temp = explode(".", $_FILES["uploadedfile"]["name"]); $extension = end($temp); $newname = $extension.'_'.substr(str_shuffle(str_repeat("0123456789abcdefghijklmnopqrstuvwxyz", 7)), 4, 7); $imglink = 'attachment/attachment_file_'; $uploaded = $imglink .$newname.'.'.$extension; if ((($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpg") || ($_FILES["uploadedfile"]["type"] == "image/pjpeg") || ($_FILES["uploadedfile"]["type"] == "image/x-png") || ($_FILES["uploadedfile"]["type"] == "image/gif") || ($_FILES["uploadedfile"]["type"] == "image/png") || ($_FILES["uploadedfile"]["type"] == "application/msword") || ($_FILES["uploadedfile"]["type"] == "text/plain") || ($_FILES["uploadedfile"]["type"] == "application/vnd.openxmlformats-officedocument.wordprocessingml.document") || ($_FILES["uploadedfile"]["type"] == "application/pdf") || ($_FILES["uploadedfile"]["type"] == "application/x-rar-compressed") || ($_FILES["uploadedfile"]["type"] == "application/x-zip-compressed") || ($_FILES["uploadedfile"]["type"] == "application/zip") || ($_FILES["uploadedfile"]["type"] == "multipart/x-zip") || ($_FILES["uploadedfile"]["type"] == "application/x-compressed") || ($_FILES["uploadedfile"]["type"] == "application/octet-stream")) && ($_FILES["uploadedfile"]["size"] < 5242880) // Max size is 5MB && in_array($extension, $allowedExts)) { move_uploaded_file($_FILES["uploadedfile"]["tmp_name"], $uploaded ); echo '<a target="_blank" href="'.$uploaded.'">click</a>'; // If has been uploaded file echo '<h3>'.$uploaded.'</h3>'; } if($_FILES["uploadedfile"]["error"] > 0){ echo '<h3>Please choose file to upload it!</h3>'; // If you don't choose file } elseif(!in_array($extension, $allowedExts)){ echo '<h3>This extension is not allowed!</h3>'; // If you choose file not allowed } elseif($_FILES["uploadedfile"]["size"] > 5242880){ echo "Big size!"; // If you choose big file } ?> if you have solution, please edit my php code and paste your solution code! Thanks.

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  • Should you disable page file with SSD?

    - by Pyrolistical
    I've been reading http://serverfault.com/questions/23621/any-benefit-or-detriment-from-removing-a-pagefile-on-an-8gb-ram-machine, and it has a lot of great information. But assuming you have more than enough ram, I think page file should be disabled on SSD to extend the life time. I know you would lose the core dump on crash, but not many people need that information. From my understand without a page file as you reach the limit of your ram that might trigger thrashing on disk. But for SSDs there is no concept of thrashing, reads are fast. What do you guys think?

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  • Dynamically created controls and the ASP.NET page lifecycle

    - by Dirk
    I'm working on an ASP.NET project in which the vast majority of the forms are generated dynamically at run time (form definitions are stored in a DB for customizability). Therefore, I have to dynamically create and add my controls to the Page every time OnLoad fires, regardless of IsPostBack. This has been working just fine and .NET takes care of managing ViewState for these controls. protected override void OnLoad(EventArgs e) { base.OnLoad(e); RenderDynamicControls() } private void RenderDynamicControls(){ //1. call service layer to retrieve form definition //2. create and add controls to page container } I have a new requirement in which if a user clicks on a given button (this button is created at design time) the page should be re-rendered in a slightly different way. So in addition to the code that executes in OnLoad (i.e. RenderDynamicControls()), I have this code: protected void MyButton_Click(object sender, EventArgs e) { RenderDynamicControlsALittleDifferently() } private void RenderDynamicControlsALittleDifferently() (){ //1. clear all controls from the page container added in RenderDynamicControls() //2. call service layer to retrieve form definition //3. create and add controls to page container } My question is, is this really the only way to accomplish what I'm after? It seems beyond hacky to effectively render the form twice simply to respond to a button click. I gather from my research that this is simply how the page-lifecycle works in ASP.NET: Namely, that OnLoad must fire on every Postback before child events are invoked. Still, it's worthwhile to check with the SO community before having to drink the kool-aid. On a related note, once I get this feature completed, I'm planning on throwing an UpdatePanel on the page to perform the page updates via Ajax. Any code/advice that make that transition easier would be much appreciated. Thanks

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  • one page filter results in new page in javascript

    - by Jake
    I have links set up on one page and the relationship between the links is a parent child relationship. (For example: Parent: All, Children: Software; Hardware) These links of course lead the user to a new page that shows the results from a table that is populated. Currently these links are all Similar destinations, but just a filter in the url. But the problem is that there is a javascript filter on the page that gives the user to choose between All, Software, or Hardware. Understand basically that if the url is still reading that there on the software page but they just filtered on the page to be Hardware that doesn't look good IMO. So what I was trying to do was make the links on the inital page all go the the exact same destination and somehow still know on the new page which link was clicked and run the javascript filter from knowing which link was clicked on that page. Is there a way to found that out from javascript? I guess a way to pass that value to the new page and retrieving it in javascript without showing it in the url so I can filter the table for the user based on that value?

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  • Rails paginate array items one-by-one instead of page-by-page

    - by hnovick
    Hi Guys, I have a group of assets, let's call them "practitioners". I'm displaying these practitioners in the header of a calendar interface. There are 7 columns to the calendar. 7 columns = 7 practitioners per view/page. Right now: if the first page shows you practitioners 1-7, when you go the next page you will see practitioners 8-15, next page 16-23, etc. etc. i am wondering how to page the practitioners so that if the first page shows you practitioners 1-7, the next page will show you practitioners 2-8, then 3-9, etc. etc. i would greatly appreciate any help you can offer. here is the rails code i am working with. best regards, harris novick # get the default sort order sort_order = RESOURCE_SORT_ORDER # if we've been given asset ids, start our list with them unless params[:asset_ids].blank? params[:asset_ids] = params[:asset_ids].values unless params[:asset_ids].is_a?(Array) sort_order = "#{params[:asset_ids].collect{|id| "service_provider_resources.id = #{id} DESC"}.join(",")}, #{sort_order}" end @asset_set = @provider.active_resources(:include => {:active_services => :latest_approved_version}).paginate( :per_page => RESOURCES_IN_DAY_VIEW, :page => params[:page], :order => sort_order )

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  • [php] Firefox refreshes page 1, even after redirection to page 2

    - by Znarkus
    Hi! This is a quite weird and annoying problem, which is reproduced with the script below. Say we have two pages: script.php and script.php?second. Page 1 creates some database entries and redirects to page 2. On page 2, the user is presented with an editor for said entries. If page 1 for some reason crashes on the first try, and prints some error message, a strange thing will happend. If we refresh page 1 (and this time it redirects fine), every consecutive refresh (of page 2) will actually refresh page 1 and again redirect to page 2. In the above example this would create new database entries for every refresh, which is the problem I want to circumvent by redirecting to page 2. <?php header('Content-type: text/plain'); session_start(); if (!isset($_GET['second'])) { $_SESSION['counter'] = isset($_SESSION['counter']) ? $_SESSION['counter'] + 1 : 1; /*$_SESSION['counter'] = 0; exit('asd');*/ header("Location: {$_SERVER['PHP_SELF']}?second", true, 303); exit; } echo "Counter: {$_SESSION['counter']}"; To try the above complete script, first run it with the commented code intact, then by enabling the commented code. I've tried 301, 302 and 303 redirections. Does someone know why this is happening?

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