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• Setting the paper size

  - by rajaneesh

  Please help me how to set paper size in c# code . i am using api printDocument .. my code is ppvw = new PrintPreviewDialog(); ppvw.Document = printDoc; ppvw.PrintPreviewControl.StartPage = 0; ppvw.PrintPreviewControl.Zoom = 1.0; ppvw.PrintPreviewControl.Columns = 10; // Showing the Print Preview Page printDoc.BeginPrint += new System.Drawing.Printing.PrintEventHandler(PrintDoc_BeginPrint); printDoc.PrintPage += new System.Drawing.Printing.PrintPageEventHandler(PrintDoc_PrintPage); if (ppvw.ShowDialog() != DialogResult.OK) { printDoc.BeginPrint -= new System.Drawing.Printing.PrintEventHandler(PrintDoc_BeginPrint); printDoc.PrintPage -= new System.Drawing.Printing.PrintPageEventHandler(PrintDoc_PrintPage); } printDoc.PrinterSettings.DefaultPageSettings.PaperSize = new System.Drawing.Printing.PaperSize("a2", 5.0,5.0); printDoc.Print();

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• Folder browse dialog not showing folders

  - by subash

  I have created an application compiled with .NET 3.5. and used the FolderBrowserDialog object. When a button is pressed i execute this code: FolderBrowserDialog fbd = new FolderBrowserDialog (); fbd.ShowDialog(); A Folder dialog is showed but i can't see any folders. The only thing i see are the buttons OK & Cancel (and create new folder button when the ShowNewFolderButton properyty is set to true). When i try the exact same code on a different form everything is working fine. Any ideas??

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• C# Windows Forms Print Dialog box click OK twice to respond

  - by sbartlett007

  I'm using Visual Studio 2008, .net Framework 3.5 for a Windows forms client-server app that I'm working on. There is a weird bug when I run the program and try to print. The print dialog box opens, but I have to click the OK button twice for it to work. After the second click it works fine, no errors. When I put a breakpoint on: if (result == DialogResult.OK) , the breakpoint doesn't trigger until the second click. Here is the code: private void tbPrint_Click(object sender, EventArgs e) { try { printDialog1.Document = pDoc; DialogResult result = printDialog1.ShowDialog(); if (result == DialogResult.OK) { pDoc.PrinterSettings.PrinterName = printDialog1.PrinterSettings.PrinterName; pDoc.Print(); } ... This is driving me crazy, and I can't see anything else that would interfere with it.

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• question about c# asp.net

  - by daddyCool

  in order to use the FolderBrowserDialog control in asp.net, i had to add a reference to System.Windows.Forms in my project. i wrote this code: FolderBrowserDialog f = new FolderBrowserDialog(); f.ShowDialog(); but this error occured: Current thread must be set to single thread apartment (STA) mode before OLE calls can be made. Ensure that your Main function has STAThreadAttribute marked on it. This exception is only raised if a debugger is attached to the process. any help?

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• FolderDialog Box Crashing Only in Debug Mode VSD2008

  - by Mike

  I have a folderBrowseDialog box in an application. It has been working for a month. Lately when I run the project from VS 2008 and I click on a button that opens the box the command ShowDialog() runs. The browser box shows up for a second and then I get "Windows encountered a problem box". Now here is the interest thing, if I compile the project, whether it be in the Debug or Release profile, and navigate to the exe, everything runs fine. Has anyone have this issue before? I can post the details of the error report if it helps. Mike

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• C# - How can i open a second winform asynchronously but still behave as a child to the parent form?

  - by Gary Willoughby

  I am creating an application and i would like to implement a progress window that appears when a lengthy process is taking place. I've created a standard windows form project to which i've created my app using the default form. I've also created a new form to use as a progress window. The problem arises when i open the progress window (in a function) using: ProgressWindow.ShowDialog(); When this command is encountered, the focus is on the progress window and i assume it's now the window who's mainloop is being processed for events. The downside is it blocks the execution of my lengthy operation in the main form. If i open the progress window using: ProgressWindow.Show(); Then the window opens correctly and now doesn't block the execution of the main form but it doesn't act as a child (modal) window should, i.e. allows the main form to be selected, is not centered on the parent, etc.. Any ideas how i can open a new window but continue processing in the main form?

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• What is best way to remove ProgressDialog

  - by Sunil Kumar Sahoo

  I have created a progress dialog by ProgressDialog progressDialog = null; // create instance variable of ProgressDialog int dialogID = 1; //to create progress dialog protected Dialog onCreateDialog(int id) { progressDialog = new ProgressDialog(context); progressDialog.setMessage(message); progressDialog.setIcon(android.R.id.icon); return progressDialog; } // to show progressdialog showDialog(dialogID); To remove the dialog I am able to use any of the following three approaches approach-1 if(progressDialog != null){ progressDialog.dismiss(); } approach-2 if(progressDialog != null){ progressDialog.cancel(); } approach-3 removeDialog(dialogID); I found second approach is more effective than first approach. and if I have to use with more than one progressdialog it is easier to use approach-3. But what is the best way to destroy a progressdialog and How?

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• Why the current working directory changes when use the Open file dialog in XP?

  - by RRUZ

  I have found an strange behavior when use the open file dialog in c#. If use this code in Windows XP the current working directory changes to the path of the selected file, however if you run this code in windows 7 the current working directory does not change. private void button1_Click(object sender, EventArgs e) { MessageBox.Show(string.Format("Current Directory {0}",Directory.GetCurrentDirectory()), "My Application",MessageBoxButtons.OK, MessageBoxIcon.Asterisk); DialogResult result = openFileDialog1.ShowDialog(); // Show the dialog and get result. if (result == DialogResult.OK) { } MessageBox.Show(string.Format("Current Directory {0}", Directory.GetCurrentDirectory()), "My Application", MessageBoxButtons.OK, MessageBoxIcon.Asterisk); } Anybody know the reason for this behavior? Why the current directoiry changes in XP and not in windows 7?

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• C# threading a FolderBrowserDialog

  - by Marthin

  Hi, Im trying to use the FolderBrowserDialog to select a folder in C#. At first I got a Thread exception, so I googled what was wrong and fixed that but now im stuck at a nother problem. I whant to know when a folder has been selected. This is what i'v got right now. private void btnWorkingFolder_Click(object sender, EventArgs e) { var t = new Thread(SelectFolder); t.IsBackground = true; t.SetApartmentState(ApartmentState.STA); t.Start(); } private void SelectFolder() { FolderBrowserDialog dialog = new FolderBrowserDialog(); if (dialog.ShowDialog() == DialogResult.OK) { txtWorkFolder.Text = dialog.SelectedPath; } } } The problem here is that i cant Set the Text for txtWorkingFolder since im not in the same thread. I dont want to change the thread for txtWorkingFolder, so my question is this, how do I change it's value from the new thread once the DialogResult.OK has been set? Thx for any help! /Marthin

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• ListAdapters and WrapperListAdapter algorithm

  - by Matty F

  This logic is written in a function with signature private void showDialog(final AdapterView<? extends Adapter> parent, String title, String message, final Tag subject) Is there a better way of doing this? // refresh adapter SimpleCursorAdapter adapter; if (parent.getAdapter() instanceof WrapperListAdapter) { adapter = (SimpleCursorAdapter) ((WrapperListAdapter) parent.getAdapter()).getWrappedAdapter(); } else { adapter = (SimpleCursorAdapter) parent.getAdapter(); } adapter.getCursor().requery(); adapter.notifyDataSetChanged(); Also, is there any point in having AdapterView<? extends Adapter> in the signature and not just AdapterView<?>?

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• How do I work with WIndows Forms in WPF?

  - by xarzu

  How do I work with WIndows Forms in WPF? In my WPF program I created a Windows Form class. In this Form, I placed an OK button and I went into the properties of the button and set the DialogResult to OK. Now, I am calling this Dialog (Window Form) from the MainWindow.xaml.cs: dres = form.ShowDialog(); if (dres != DialogResult.OK) return; The compiler is complaining: Error 3 'System.Nullable<bool>' does not contain a definition for 'OK' and no extension method 'OK' accepting a first argument of type 'System.Nullable<bool>' could be found (are you missing a using directive or an assembly reference?)

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• In registration form adding date dialogbox how can apply validation in system date in dialog ends

  - by narasimha

  hi i am implementing registration form adding date field then click icon to display date dialog window then limit date validation in system date below date only how can implement the validation protected Dialog onCreateDialog(int id) { Calendar c = Calendar.getInstance(); int cyear = c.get(Calendar.YEAR); int cmonth = c.get(Calendar.MONTH); int cday = c.get(Calendar.DAY_OF_MONTH); switch (id) { case DATE_DIALOG_ID: return new DatePickerDialog(this, mDateSetListener, cyear, cmonth, cday); } return null; } private DatePickerDialog.OnDateSetListener mDateSetListener = new DatePickerDialog.OnDateSetListener() { public void onDateSet(DatePicker view, int year, int monthOfYear, int dayOfMonth) { String date_selected = String.valueOf(monthOfYear+1)+" /"+String.valueOf(dayOfMonth)+" /"+String.valueOf(year); EditText birthday=(EditText) findViewById(R.id.EditTextBirthday); birthday.setText(date_selected); } }; public void onClick(View v) { if(v == b1) showDialog(DATE_DIALOG_ID); } } ** showing in system date in below dates only how can implemented some solution in running year to below years are display not incrementing above years this condition are appliying validations how can implemented ?

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• Fileopen trough the FolderBrowserDialog.. How?? HELP!

  - by thunderbass

  This is what i got now... FolderBrowserDialog1.ShowDialog() TextBox1.Text = FolderBrowserDialog1.SelectedPath If FolderBrowserDialog1.SelectedPath = Nothing = True Then MsgBox("Select your folder..") If FolderBrowserDialog1.SelectedPath = Nothing = True Then Button1.Enabled = False If FolderBrowserDialog1.SelectedPath = Nothing = False Then Button1.Enabled = True End Sub FileOpen(1, ,,,,,, & "File" & ".dll", OpenMode.Output) PrintLine(1, TextBox2.Text) FileClose() End Sub But i want the Output folder (The place were File.dll is saved) to be the FolderBrowserDialog1.SelectedPath... how? Anyone? Tryed FileOpen(1, FolderBrowserDialog1.SelectedPath & File & .dll, OpenMode.Output) but nop :( Help plzzz

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• C#: how to check and display the content of a folder?

  - by user147685

  I'm not sure whether this topics has been disscussed before or not, but I'm not sure the exact word to search for it. What method/class should I use? The program has 3 buttons: 1) for folder browsing, 2) scan for the selected folder content, and 3) open the file. When user browse the selected folder*(1), user click scan button to scan from the first file until the last available files and listed it text box(2)* and from that user can decide whether to open the files or not*(3)*. Here are what have I done so far (no 1 and 3): //For browse. private void browse2() { if (folderBrowserDialog1.ShowDialog() == DialogResult.OK) { this.txtDest.Text = folderBrowserDialog1.SelectedPath; } } //For opening folder. private void btnOpen_Click(object sender, EventArgs e) { try { Process.Start(txtDest.Text); } catch { MessageBox.Show("Please select one file/folder"); } }

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• What option in Visual Studio let catching exception where it occurred?

  - by macias

  VS 2010. The same WPF project, debug mode, two computers: A -- when exception occurrs the caret is placed at the point of exception B -- when the exception occurrs, correct exception is placed but always caret is placed at "win.ShowDialog()" in App.xaml.cs -- this is main entry for showing & running my application, in such case it is very tiresome to track down where the exception occurred What kind of settings control such behaviour? Of course I would like to switch B, so when exception hits I would be place at the point of exception, not at the main entry.

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• Printdialog in multithreaded wpf window thrown TargetInvocationException

  - by Nils

  I have designed a multithreaded app, which is starting most windows in an dedicated thread like this: Thread newWindowThread = new Thread(new ThreadStart(ThreadStartingPoint)); newWindowThread.SetApartmentState(ApartmentState.STA); newWindowThread.IsBackground = true; newWindowThread.Start(); However, if in one of those window-in-own-thread I try to print something by simply calling PrintDialog pDialog = new PrintDialog(); bool? doPrint = pDialog.ShowDialog(); I get a TargetInvocationException - it does look like the PrintDialog does not reside in the same thread as my window. Is there any way to create a thread-agnostic (or "thread-save") PrinterDialog ?

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• Running NUnit Tests from Code

  - by Dror Helper

  I'm trying to write a simple method that receives a file an runs it using NUnit. The code I managed to build using NUnit's source does not work: if(openFileDialog1.ShowDialog() != DialogResult.OK) { return; } var builder = new TestSuiteBuilder(); var testPackage = new TestPackage(openFileDialog1.FileName); var directoryName = Path.GetDirectoryName(openFileDialog1.FileName); testPackage.BasePath = directoryName; var suite = builder.Build(testPackage); TestResult result = suite.Run(new NullListener(), TestFilter.Empty); The problem is that I keep getting an exception thrown by builder.Build stating that the assembly was not found. What am I missing?

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• How to Run NUnit Tests from C# Code

  - by Dror Helper

  I'm trying to write a simple method that receives a file and runs it using NUnit. The code I managed to build using NUnit's source does not work: if(openFileDialog1.ShowDialog() != DialogResult.OK) { return; } var builder = new TestSuiteBuilder(); var testPackage = new TestPackage(openFileDialog1.FileName); var directoryName = Path.GetDirectoryName(openFileDialog1.FileName); testPackage.BasePath = directoryName; var suite = builder.Build(testPackage); TestResult result = suite.Run(new NullListener(), TestFilter.Empty); The problem is that I keep getting an exception thrown by builder.Build stating that the assembly was not found. What am I missing? Is there some other way to run the test from the code (without using Process.Start)?

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• Closing a dialog form closes the application

  - by user361633

  bool CheckAnswer() { DialogForm dialogForm = new DialogForm(); if (dialogForm.showDialog() == System.Windows.Forms.DialogResult.OK) return true; } The dialog form is invoked by a form created in the main form. When i close the dialog form the application is closed, not just the dialog form! If i invoke the dialog form in other form it works normally. The form from which i invoke the dialog form is top level, but even if i change that i'm getting the same result. Does anyone know what's wrong?

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• How to communicate between C# and Wpf projects ?

  - by Wazzz

  Hey folks , i'm working with 3 projects , one C# (let's called it A ) the other two are Wpf projects(let's call them B,C). The project B has a main window which contains a button ,when i press the button it shows the project "A" main's window .(i've done that by adding the right references and doing the code below in button click event handler : CsharpForm.Form1 d = new CsharpForm.Form1(); d.ShowDialog(); , but The Problem i have now is how do to the opposite ?? i have a button in project "C"(wpf one ) and want it to open a window of project "a" (C# ) Do u know any idea about this ?

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• How to op-en file and view in a rich text box using vb.net?

  - by Aaron Warnke

  Hi I am trying to open and view a files text in a rich text box. Here is what I have please let me know what I am doing wrong? Private Sub loadButton_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles loadButton.Click ' Displays an OpenFileDialog so the user can select a Cursor. Dim openFileDialog1 As New OpenFileDialog() openFileDialog1.Filter = "Cursor Files|*.txt" openFileDialog1.Title = "Select a Cursor File" If openFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then ' Assign the cursor in the Stream to the Form's Cursor property. Me.mainRTBox = New Text(openFileDialog1.OpenFile()) End If End Sub

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• Creating Visual Studio Templates

  - by vanja.

  I'm looking to create a Visual Studio 2008 template that will create a basic project and based on remove certain files/folders based on options the user enters. Right now, I have followed some tutorials online which have let me create the form to query the user and pass the data into an IWizard class, but I don't know what to do from there. The tutorials provide a sample to do some simple substitution: code: Form1 form = new Form1(); DialogResult dlg = form.ShowDialog(); if (dlg == DialogResult.OK) { foreach (KeyValuePair<string, string> pair in form.Parameters) { if (!replacementsDictionary.ContainsKey(pair.Key)) replacementsDictionary.Add(pair.Key, pair.Value); else replacementsDictionary[pair.Key] = pair.Value; } } form.Close(); but I'm looking to selectively include files based on the user settings, and if possible, selectively include code sections in a file based on settings. Is there a clever way to do this, or will I manually have to delete project files in the IWizard:ProjectFinishedGenerating()?

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• Would I really want to return the minimum date?

  - by Clay Shannon

  An old work colleague used to quote his father about tools, "You have to be smarter than it." In the code below, Resharper is telling me, "Value assigned is not used in any execution path" (pointing to the first line). If I accept its offer of help, dt is not assigned a value ("today"). Is this a case where "I have to be smarter than it" and ignore their warning, or is this a case where the tool is smarter than me, and I'm just not understanding it? My take on the situation is that if the if statement fails, the current date is returned (the default value I want), but if I acquiesce to Resharper's "demands" it would return the default value for Datetime, which is the minimum date, which I assume is something like 7/4/1776 or 1/1/0000 or so. DateTime dt = DateTime.Now; if (!(DateTime.TryParse(substr, out dt))) { using (var dtpDlgForm = new ReturnDate("Please select the Date that the file was created:")) { if (dtpDlgForm.ShowDialog() == DialogResult.OK) { dt = dtpDlgForm.ReturnVal; } } } return dt;

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• Make Directory.GetFiles() ignore protected folders

  - by Kryptic

  Hello Everyone, I'm using the Directory.GetFiles() method to get a list of files to operate on. This method throws an UnauthorizedAccessException for example when trying to access a protected folder. I would like it to simply skip over such folders and continue. How can I accomplish this with either Directory.GetFiles (preferably) or another method? Update: Here is the code that throws the exception. I am asking the user to select a directory and then retrieving the list of files. I commented out the code (so this is now whole method) that iterates through the files and the problem still occurs. The exception is thrown on the Directory.GetFiles() line. FolderBrowserDialog fbd = new FolderBrowserDialog(); DialogResult dr = fbd.ShowDialog(); if (dr == System.Windows.Forms.DialogResult.Cancel) return; string directory = fbd.SelectedPath; string[] files = Directory.GetFiles(directory, "*.html", SearchOption.AllDirectories);

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• strange wpf errors on xp machine

  - by Yoav

  I created an application that has two windows. the second one is opened by .showDialog() command from the first window. on Windows 7 everything works fine but when running on XP the first window works fine but when trying to open the second window the application crash. exception message: Provide value on 'System.Windows.Baml2006.TypeConverterMarkupExtension' threw an exception. and now for the weird part: when changing the application and making the second window run first it opens without a problem. when removing the icon from the second window (it's the same file for both windows) it also runs fine. any ideas on how to solve this?

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