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  • How to create the automatic mass form submitter (javascript-ajax script) to be used on the 3rd part

    - by Daniel
    I need a script that can handle the following tasks. Take user data from my database and fill in and submit / post data to forms located on third part websites.: So I want to know if is it hard to create or do somebody knows if does exists some script for mass form submissions in PHP -Javascript-Ajax ? I run Dancers & Hostess & Model jobs website, I would like to find some script which allows the girls automaticly submit to hundreds websites forms (other 3rd part model agencies) with their similar model application form info on my website previously specified, 1).Firstly the girls will fill out my agency portfolio very detailed form , like this i will get all the model personal info from them , 2) Secondly i would like to allow for example models to submit to 100 and more other model agencies forms (I will find those websites before, and I will get their field names = values and thanks to some script would like to connect them with every girl data already created in my website to submit . I would like to implement it to my wordpress website where the girls has their portfolios instead of my pages . I would like to offer this service especially to models , it should work like some directory submitters , The script knows names - values and fill it out itself, but I want it online - browser side, where the girls should only fill out captcha if there is and click the button "submit".After succesful submit it should offer other form to submit. I would be very happy if you know the answer or if you can redirect me to some article

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  • Can I submit iPhone applications with same Icon.png but differnt bundle name

    - by AJ
    Can some one tell me if it is possible to submit two different iphone applications which has same Icon.png but have a different bundle name? I am working on a travel guide app that is targeted for different cities. I want the users of different cities to download the app as per their cities. So I want to submit different apps for different cities(3 in my case). User can also purchase any of these cities through in-app purchase. In that case the new purchased city would be unlocked in the app. Here is my thing. I want the same icon for all the three apps. I can do away with different names for app store and bundle(home screen icon name). But I am not sure if apple would approve/reject this app. Can someone enhance this blur picture I have?

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  • Time in "Upload Received"

    - by rpeck1682
    I uploaded an app to itunes connect yesterday afternoon. It has been in the "Upload Received" stage ever since then. I uploaded a different app today, it was in that stage for only five minutes. This is the first time I've submitted since the new, more detailed status updates were present. I'm just wondering if the app sitting there in that state for so long seems like something to be concerned about. I'm guessing by staying in that state that it isn't being put on the review queue. Anyways, has anyone else had a similar experience?

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  • Can I save & store a user's submission in a way that proves that the data has not been altered, and that the timestamp is accurate?

    - by jt0dd
    There are many situations where the validity of the timestamp attached to a certain post (submission of information) might be invaluable for the post owner's legal usage. I'm not looking for a service to achieve this, as requested in this great question, but rather a method for the achievement of such a service. For the legal (in most any law system) authentication of text content and its submission time, the owner of the content would need to prove: that the timestamp itself has not been altered and was accurate to begin with. that the text content linked to the timestamp had not been altered I'd like to know how to achieve this via programming (not a language-specific solution, but rather the methodology behind the solution). Can a timestamp be validated to being accurate to the time that the content was really submitted? Can data be stored in a form that it can be read, but not written to, in a proven way? In other words, can I save & store a user's submission in a way that proves that the data has not been altered, and that the timestamp is accurate? I can't think of any programming method that would make this possible, but I am not the most experienced programmer out there. Based on MidnightLightning's answer to the question I cited, this sort of thing is being done. Clarification: I'm looking for a method (hashing, encryption, etc) that would allow an average guy like me to achieve the desired effect through programming. I'm interested in this subject for the purpose of Defensive Publication. I'd like to learn a method that allows an every-day programmer to pick up his computer, write a program, pass information through it, and say: I created this text at this moment in time, and I can prove it. This means the information should be protected from the programmer who writes the code as well. Perhaps a 3rd party API would be required. I'm ok with that.

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  • The Benefits of Being Featured in The DMOZ

    The DMOZ directory submission, or The Open Directory Project, is now so highly regarded that any respectable SEO services company is now presenting its customers with a DMOZ submission service. Another reason why the DMOZ site submission is now featured in the services lists of search engine optimization companies is that performing a DMOZ submission can prove to be extremely difficult, or even impossible in some cases, for anyone other than optimization experts.

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  • Specialized &amp; Recognized by Oracle: Award season - make your submission for the OPN Specializati

    - by Jürgen Kress
      OPN Specialization Award Submit your nomination 2010 As an Oracle Partner in the process to become SOA & Application Grid Specialized and working on SOA and Application Grid opportunities please make sure that you submit your OPN Specialization Award Submit your nomination. Prices include free Oracle Open World tickets, marketing budgets for joint campaigns and joint press release. "These awards will recognize the high-level of innovation, excellence and commitment our partners bring to the table when they become Specialized with Oracle. We’re looking for partners with a proven track record in delivering winning, proven solutions that solve customers' most critical business challenges. Our Award winners will be partners that have demonstrated tangible success, growth in their Oracle business and outstanding Oracle solutions." Stein Surlien, SVP Oracle Alliances and Channels EMEA Nominations are open to partners based in EMEA from 1st March to 2nd July 2010. Be recognized! Submit your nominations today     Oracle Fusion Middleware Innovation Awards 2010 As an Oracle Customer and Partner make sure that you submit your Oracle Fusion Middleware Innovation Awards nomination Does your company use Oracle Fusion Middleware innovatively? Nominate your organization today for a chance to be recognized for your cutting-edge solution using any of the following Oracle Fusion Middleware products: Oracle Application Grid products Oracle SOA Suite Data Integration & Availability Oracle Identity Management Suite Oracle Fusion Middleware with Oracle Applications Enterprise 2.0 Prices include: FREE pass to Oracle OpenWorld 2010 in San Francisco for select winners in each category. Honored by Oracle executives at awards ceremony held during Oracle OpenWorld 2010 in San Francisco. Oracle Middleware Innovation Award Winner Plaque 1-3 meetings with Oracle Executives during Oracle OpenWorld 2010 Feature article placement in Oracle Magazine and placement in Oracle Press Release Customer snapshot and video testimonial opportunity, to be hosted on oracle.com Podcast interview opportunity with Senior Oracle Executive Submit your nomination to [email protected] on or before August 6th 2010 to win Oracle Fusion Middleware Innovation Awards 2010.

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  • Connection to mysql works through php but not through a form submission?

    - by Legend
    I have a download.php file that connects to a remote mysql database. If I run it using php download.php it works fine. But if I create another php file form.php and then submit the form to this download.php, it complains the following: Can't connect to MySQL server on '<IP_ADDRESS>' (13) Does anyone know why this might be happening? I can't see a reason why this works directly but fails to work upon form submission...

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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    How to make the use of hidden variables as array for consecutive submission of data so that they can be used to display the records list. I have a form with 4 text fields and a file upload field.. as i submit he form it should get appended to the list which needs to be displayed below the form, such that these values are NOT stored in the DB.. So in this case how can i use the post array to collect the data and display in the list below?

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  • How to prevent form submission for a form using onchange to submit the form when certain values are

    - by Terrence Brannon
    I have a form I have built: <form class="myform" action="cgi.pl"> <select name="export" onchange='this.form.submit()'> <option value="" selected="selected">Choose an export format</option> <option value="html">HTML</option> <option value="csv">CSV</option> </select> </form> Now, this form works fine if I pull down and select "HTML" or "CSV". But if I hit the back button and select "Choose an export format", the form is submitted, even though I dont want it to be. Is there any way to prevent form submission for that option?

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  • How can I split a PHP form into two sections, before submission to a database?

    - by Daniel Smith
    Hi guys, I have set up a PHP form for a competition, for users to enter and all information to be stored in a database. I used the following NetTut+ tutorial to do so: http://tr.im/SwAd. I've got the form submitting to the database as required, but with so many additional questions being asked, I would like to split the form into two separate sections. Obviously the first page would say continue to the next step before the second step allowing for the form to be submitted to the database. The content that the user sees should be split, but should all be a part of the same form. Step 1 Step 2 before submission. Would anyone know of or recommend any methods to do this? I'm a beginner so please be nice. :) Cheers, Daniel

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  • How can I get jQuery validation plugin Ketchup to stop an Ajax form submission when validation fails?

    - by Marshall Sontag
    I'm using Ruby on Rails, Formtastic gem, jQuery and ketchup to validate my form. I'm submitting the form created by Formtastic inside a modal box using ajax: <% semantic_form_remote_for @contact_form, :url => '/request/contact' do |f| %> I have a validation plugin verifying the fields on the form: $(document).ready(function() { $("#new_contact_form").ketchup(); }); The problem is that semantic_form_remote_for generates an onSubmit ajax request that the jQuery validation plugins won't prevent, since it's not a normal form submission. One question on stackoverflow suggests using :condition on the remote form declaration to fire a javascript function, but I can't do that since I'm not using a function, but rather relying on a jQuery handler. I also tried putting ketchup within a submit event handler: $(document).ready(function() { $("#new_contact_form").submit(function() { $('#new_contact_form').ketchup(); }); }); No luck. Form still submits. I also tried using the beforeSend option of jQuery.ajax: $(document).ready(function() { jQuery.ajax( { beforeSend: function(){ $('#new_contact_form').ketchup(); } }); }); Validation fires off, but form is still submitted. I switched to jQuery Validation plugin just to see if it was due to some limitation in Ketchup. It turns out that Validation has a submitHandler option: $(document).ready(function() { $('#new_contact_form').validate({ submitHandler: function(form) { jQuery.ajax({ data:jQuery.param(jQuery('#new_contact_form').serializeArray()), dataType:'script', type:'post', url:'/request/contact' }); return false; } }); }); This works when I use a regular semantic_form_for instead of semantic_form_remote_for, but alas, I would rather use Ketchup. Is Ketchup just woefully lacking? Am I forced to use jQuery Validation?

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  • Attachment_fu file saving problem

    - by Anand
    Attachment_fu plugin is kind of old, but I have to modify an old app and I can't use another plugin like paperclip etc. So here's the code without further ado Submissions table structure --------------------------- | content_type | varchar(255) | YES | | NULL | filename | varchar(255) | YES | | NULL app/models/submission.rb ------------------------ has_attachment :storage => :file_system, :path_prefix => 'public/submissions', :max_size => 2.megabytes, :content_type => ['application/pdf', 'application/msword', 'text/plain'] app/models/user.rb ------------------ has_one :submission, :dependent => :destroy app/views/user/some_action.html.erb ----------------------------------- <% form_for :user, :url => { :action => "some_action" }, :html => {:multipart => true} do |f| %> .... <%= file_field_tag "submission[uploaded_data]" %> <%end%> app/controllers/user_controller.rb ---------------------------------- @user = User.find_user(session[:user_id]) @submission = @user.submission if request.post? @submission.uploaded_data = params[:submission][:uploaded_data] end When the form is submitted, the database fields "content_type" and "filename" get updated and display the correct values, but the file does not appear in public/submissions/ directory. I have checked the permissions on the submissions directory. What am I missing? Many Thanks

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  • In .NET, how do I prevent, or handle, tampering with form data of disabled fields before submission?

    - by David
    Hi, If a disabled drop-down list is dynamically rendered to the page, it is still possible to use Firebug, or another tool, to tamper with the submitted value, and to remove the "disabled" HTML attribute. This code: protected override void OnLoad(EventArgs e) { var ddlTest = new DropDownList() {ID="ddlTest", Enabled = false}; ddlTest.Items.AddRange(new [] { new ListItem("Please select", ""), new ListItem("test 1", "1"), new ListItem("test 2", "2") }); Controls.Add(ddlTest); } results in this HTML being rendered: <select disabled="disabled" id="Properties_ddlTest" name="Properties$ddlTest"> <option value="" selected="selected">Please select</option> <option value="1">test 1</option> <option value="2">test 2</option> </select> The problem occurs when I use Firebug to remove the "disabled" attribute, and to change the selected option. On submission of the form, and re-creation of the field, the newly generated control has the correct value by the end of OnLoad, but by OnPreRender, it has assumed the identity of the submitted control and has been given the submitted form value. .NET seems to have no way of detecting the fact that the field was originally created in a disabled state and that the submitted value was faked. This is understandable, as there could be legitimate, client-side functionality that would allow the disabled attribute to be removed. Is there some way, other than a brute force approach, of detecting that this field's value should not have been changed? I see the brute force approach as being something crap, like saving the correct value somewhere while still in OnLoad, and restoring the value in the OnPreRender. As some fields have dependencies on others, that would be unacceptable to me.

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  • Browser freezes when try to call a JS function along with submission of a form.

    - by Waseem
    I have form in my view like following 1 <div> 2 <% form_tag facebook_user_path do %> 3 <label>Use my photo and name from facebook?</label><br /> 4 <%= check_box_tag 'use_name_and_photo', 'yes', true %> 5 <img src="<%= @user.pic %>" /><% @user.name %> 6 7 <%= submit_tag "Finish", :id => "use_name_and_photo_submit" %> 8 <% end %> 9 </div> I have attached some JS handlers using Jquery to this form. 1 var fb = { 2 extendedPermissions: function () { 3 $("#use_name_and_photo_submit").click(function (event) { 4 FB.Connect.showPermissionDialog("email,read_stream,publish_stream", function (perms) { 5 if (!perms) { 6 alert("You have to grant facebook extended permissions to further browse the application."); 7 } else { 8 $("form").submit(function () { 9 $.post($(this).attr("action"), $(this).serialize(), null, "script"); 10 }); 11 } 12 }); 13 event.preventDefault(); 14 return false; 15 }); 16 } 17 }; 18 19 $(document).ready(function () { 20 fb.extendedPermissions(); 21 }); What I want is that when the user clicks on the "Finish" button, he is prompted for the facebook permissions dialogue and when he gives the permissions, the form is submitted to FacebookUsersController. Right now when I click the "Finish" button, facebook permissions dialogue is initiated but before I am prompted for the actual permission submission window, the browser freezes. Just like I have pressed Esc during the process. In fact status bar of the browser says "Stopped". Any help is highly appreciated.

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  • Passing params in rails... Breakthrough in understanding params, aka, the "aha" moment

    - by Brian McDonough
    I have a simple has_many belongs_to relationship and I want to include the parent object for the view of the belongs_to model and I have had some success, but I want it to work better. class Submission < ActiveRecord::Base belongs_to :user belongs_to :contest end class Contest < ActiveRecord::Base belongs_to :user has_many :submissions, :dependent => :destroy end In the case that works, I pass contest_id to submissions by placing it in the url: <%= link_to 'Submit Contest Entry', new_submission_path(:contest_id => @contest.id), :class => 'btn btn-primary btn-large mleft10' %> So that, combined with a hidden_field: <%= f.hidden_field :contest_id %> And a find_contest method in the controller (called with a before_filter): def find_contest #the next line is giving the error (line 76) @contest = Contest.find(params[:submission][:contest_id]) end Makes it work for submissions/new, but how do I add a find to the controller that just works across more than that one page, like if I want to access in show and index. Right now, I get an error: Started GET "/submissions?contest_id=5" for 127.0.0.1 at 2012-12-01 16:01:45 -0800 Processing by SubmissionsController#index as HTML Parameters: {"contest_id"=>"5"} User Load (0.3ms) SELECT "users".* FROM "users" WHERE "users"."id" = 2 ORDER BY users.created_at DESC LIMIT 1 Completed 500 Internal Server Error in 37ms NoMethodError (undefined method `[]' for nil:NilClass): app/controllers/submissions_controller.rb:76:in `find_contest' [edited] Adding show action for submissions: before_filter :find_contest, :except => [:index, :show, :edit, :update, :destroy] def find_contest @contest = Contest.find(params[:submission][:contest_id]) end def show contest_id = @submission.contest_id @submission = @commentable = Submission.find(params[:id]) @comments = @commentable.comments.order(:created_at).reverse respond_to do |format| format.html # show.html.erb format.json { render :json => @submission } end end

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  • Using GET Method to Maintain Variables After Logging In

    - by John
    Hello, I am using a login system. When I navigate to comments/index.php without logging in, some variables get passed along using the GET method just fine. Then, if I log in while I am on this page, these variables disappear. The variables that disappear are $submission, $submissionid, and $url. I thought I could use the GET method to keep them live after logging in by appending ?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.' to the URL of the login form action as seen below. But the variables still disappeared after I made this addition. The relevant code I am trying to use is below. Any idea what I can do to make it do what I want? Thanks in advance, John In comments/index.php: require_once "header.php"; include "login.php"; include "comments.php"; In login.php: if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } In comments.php: $url = mysql_real_escape_string($_GET['url']); echo '<div class="subcommenttitle"><a href="http://www.'.$url.'">'.$submission.'</a></div>'; $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); The login function: function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; }

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  • Django: get count of ForeignKey item in template?

    - by AP257
    Straightforward question - apologies if it is a duplicate, but I can't find the answer if so. I have a User model and a Submission model, like this: class Submission(models.Model): uploaded_by = models.ForeignKey('User') class User(models.Model): name = models.CharField(max_length=250 ) How can I show the number of Submissions made by each user in the template? I've tried {{ user.submission.count }}, like this: for user in users: {{ user.name }} ({{ user.submission.count }} submissions) but no luck...

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  • User Getting Logged Out After Making First Comment

    - by John
    Hello, I am using a login system that works well. I am also using a comment system. The comment function does not show up unless the user is logged in (as shown in commentformonoff.php below). When a user makes a comment, the info is passed from the function "show_commentbox" to the file comments2a.php. Then, the info is passed to the file comments2.php. When the site is first pulled up on a browser, after logging in and making a comment, the user is logged out. After logging in a second time during the same browser session, the user is no longer logged out after making a comment. How can I keep the user logged in after making the first comment? Thanks in advance, John Commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } ?> Function "show_commentbox": function show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl) { echo '<form action="http://www...com/.../comments/comments2a.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$_SESSION['username'].'" name="u"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.stripslashes($submission).'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="checkMax" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; } Included in comments2a.php: $uid = mysql_real_escape_string($_POST['uid']); $u = mysql_real_escape_string($_POST['u']); $query = sprintf("INSERT INTO comment VALUES (NULL, %d, %d, '%s', NULL)", $uid, $subid, $comment); mysql_query($query) or die(mysql_error()); $lastcommentid = mysql_insert_id(); header("Location: comments2.php?submission=".$submission."&submissionid=".$submissionid."&url=".$url."&submissiondate=".$submissiondate."&comment=".$comment."&subid=".$subid."&uid=".$uid."&u=".$u."&submittor=".$submittor."&countcomments=".$countcomments."&dispurl=".$dispurl."#comment-$lastcommentid"); exit(); Included in comments2.php: if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../comments/comments2.php?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.'&submissiondate='.$submissiondate.'&submittor='.$submittor.'&countcomments='.$countcomments.'&dispurl='.$dispurl.'');} $uid = mysql_real_escape_string($_GET['uid']); $u = mysql_real_escape_string($_GET['u']);

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