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Search found 503 results on 21 pages for 'xsi'.

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  • Spring @PostConstruct function in a @Repository called multiple times

    - by Seth
    I have a DAO that I'm trying to inject into a couple different places: @Repository public class FooDAO { @Autowired private HibernateManager sessionFactory; @PostConstruct public void doSomeDatabaseStuff() throws DataAccessException { ... } } And my application-context.xml is a fairly simple context:component-scan: <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd" default-init-method="init" default-destroy-method="destroy"> <context:component-scan base-package="top.level"/> </beans> The DAO is accessed from a couple servlets in my application server through @Autowired properties. As far as I understand, anything annotated with @Repository should default to being a singleton and thus doSomeDatabaseStuff() should only be called once (as is my intention). The problem is that I'm seeing doSomeDatabaseStuff() called multiple times. What's going on here? Have I set something up incorrectly? I'm using spring 3.0.0. Thanks for the help.

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  • Parsing SOAP XML in Oracle

    - by user258587
    Hi I am new to Oracle and I am working on something that needs to parse a SOAP request and save the address to DB Tables. I am using the XML parser in Oracle (XMLType) with XPath but am struggling since I can't figure out the way to parse the SOAP request because it has multiple namespaces. Could anyone give me an example? Thanks in advance!!! edit It would be a typical SOAP request similar to the one below. <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soap="http://soap.service.****.com"> <soapenv:Header /> <soapenv:Body> <soap:UpdateElem> <soap:request> <soap:att1>123456789</soap:att1> <soap:att2 xsi:nil="true" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" /> <soap:att3>L</soap:att3> ..... </soap:request> </soap:UpdateElem> </soapenv:Body> </soapenv:Envelope> I need to retrieve parameters att1, att2... and save them in to a DB table.

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  • XML Schema and element with type string

    - by svick
    I'm trying to create an XML Schema and I'm stuck. It seems I can't define an element with string content. What am I doing wrong? Schema: <?xml version="1.0"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://ponderka.wz.cz/MusicLibrary0" targetNamespace="http://ponderka.wz.cz/MusicLibrary0"> <xs:element name="music-library"> <xs:complexType> <xs:sequence> <xs:element name="artist" type="xs:string"/> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> Document: <?xml version="1.0"?> <music-library xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://ponderka.wz.cz/MusicLibrary0 data0.xsd" xmlns="http://ponderka.wz.cz/MusicLibrary0"> <artist>a</artist> </music-library> The validator says: Element <artist> is not allowed under element <music-library>. Reason: The following elements are expected at this location (see below) <artist> Error location: music-library / artist Details cvc-model-group: Element <artist> unexpected by type '{anonymous}' of element <music-library>. cvc-elt.5.2.1: The element <music-library> is not valid with respect to the actual type definition '{anonymous}'.

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  • application-context.xml problem for Spring ActionScript

    - by jiri
    content of The application-content.xml is <?xml version="1.0" encoding="utf-8"?> <objects xmlns="http://www.springactionscript.org/schema/objects" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springactionscript.org/schema/objects http://www.springactionscript.org/schema/objects/spring-actionscript-objects-1.0.xsd"> <property file="strings.properties" /> <object id="string1" class="String"/> <object id="string2" class="String"/> <object id="nlslzf" class="com.sgb.model.MyClass"/> </objects> content of strings.properties is: s1=Firststring s2=Secondstring but error: Main Thread (Suspended: Error: An object definition for 'string1' was not found.) org.springextensions.actionscript.ioc.factory.support::AbstractObjectFactory/getObject SpringActionScript/test SpringActionScript/onCreationComplete SpringActionScript/___SpringActionScript_Application1_creationComplete flash.events::EventDispatcher/dispatchEventFunction [no source] mx.core::UIComponent/dispatchEvent mx.core::UIComponent/set initialized mx.managers::LayoutManager/doPhasedInstantiation Function/http://adobe.com/AS3/2006/builtin::apply [no source] mx.core::UIComponent/callLaterDispatcher2 mx.core::UIComponent/callLaterDispatcher2 mx.core::UIComponent/callLaterDispatcher i can run normal if removed the '' why it is? springactionscript bug?

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  • DDMS plugin not loading GPX files

    - by Craig
    I am unable to load a GPX file in the DDMS eclipse plugin. When specifying a GPX file, no points are added to the emulator control list. I have tried adding KML files as well, generated in Google earth. Is there a way to get these files to work? The content of the file is listed below: <?xml version="1.0" encoding="UTF-8"?> <gpx version="1.0" creator="RunKeeper - http://www.runkeeper.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.topografix.com/GPX/1/0" xsi:schemaLocation="http://www.topografix.com/GPX/1/0 http://www.topografix.com/GPX/1/0/gpx.xsd"> <trk> <name>Running 11/30/09 3:37 pm11/30/09 3:37 pm</name> <time>2009-11-30T15:37:08Z</time> <trkseg> <trkpt lat="41.811406000" lon="-72.521427000"> <ele>37.000000</ele> <time>2009-11-30T15:37:08Z</time> </trkpt> <trkpt lat="41.811030000" lon="-72.522882000"> <ele>38.000000</ele> <time>2009-11-30T15:37:10Z</time> </trkpt>

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  • How to use a Spring config file in a Maven dependency

    - by javamonkey79
    In dependency A I have the following: <beans> <bean id="simplePersonBase" class="com.paml.test.SimplePerson" abstract="true"> <property name="firstName" value="Joe" /> <property name="lastName" value="Smith" /> </bean> </beans> And then in project B, I add A as a dependency and have the following config: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd"> <bean id="simplePersonAddress01" parent="simplePersonBase"> <property name="firstName" value="BillyBob" /> <property name="address" value="1060 W. Addison St" /> <property name="city" value="Chicago" /> <property name="state" value="IL" /> <property name="zip" value="60613" /> </bean> </beans> When I use ClassPathXmlApplicationContext like so: BeanFactory beanFactory = new ClassPathXmlApplicationContext( new String[] { "./*.xml" } ); SimplePerson person = (SimplePerson)beanFactory.getBean( "simplePersonAddress01" ); System.out.println( person.getFirstName() ); Spring complains as it can not resolve the parent xml. Caused by: org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'simplePersonBase' is defined I am sure there is a way to do this, however, I have not found it. Does anyone know how?

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  • Basic Tomcat Servlet error.

    - by ajay
    package mypackage; import java.io.*; import javax.servlet.http.*; import javax.servlet.*; public class Hello extends HttpServlet { public void doGet (HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException { PrintWriter out = res.getWriter(); out.println("Hello, world!"); out.close(); } } web.xml file is as follows: <?xml version="1.0" encoding="ISO-8859-1"?> <web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4"> <display-name>Hello, World Application</display-name> <description> This is a simple web application with a source code organization based on the recommendations of the Application Developer's Guide. </description> <servlet> <servlet-name>HelloServlet</servlet-name> <servlet-class>mypackage.Hello</servlet-class> </servlet> <servlet-mapping> <servlet-name>HelloServlet</servlet-name> <url-pattern>/hello</url-pattern> </servlet-mapping> </web-app> I am then doing ant all , ant reload and also /etc/init.d/tomcat restart But I get this error on browser: HTTP Status 404 - /hello/ type Status report message /hello/ description The requested resource (/hello/) is not available. Apache Tomcat/6.0.26 What could be wrong?

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  • How to run an app in Tomcat?

    - by artaxerxe
    Hi! I have put my project in tomcat_home/webapps/ directory. The structure is : project_name/WEB-INF/classes. in WEB-INF i have put my web.xml descriptor. The problem is that when i try to run the application, it doesn't find the files. The error is: The requested resource () is not available. My web.xml content is: <?xml version="1.0" encoding="ISO-8859-1"?> <web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4"> <servlet> <servlet-name>Chapter1 Servlet</servlet-name> <servlet-class>Ch1Servlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Chapter1 Servlet</servlet-name> <servlet-url>/Serv1</servlet-url> </servlet-mapping> </web-app> I have also restarted the server, but it doesn't want to work. Any suggestions?

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  • JAX-WS client with AXIS server; namespace problem?

    - by Jarno
    I'm having a problem related to JAX-WS and AXIS. JAX-WS (2.1.7) as a client, Axis (1.4.x) as server. Everything works OK, but the response can't be read to Java. Response: <?xml version="1.0" encoding="UTF-8"?> <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <soapenv:Body> <ns1:myserviceResponse soapenv:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns1="http://my/service"> <ns1:myserviceReturn xsi:type="xsd:string">responsestring</ns1:myserviceReturn> </ns1:myserviceResponse> </soapenv:Body> </soapenv:Envelope> The problem is that if "ns1:"-namespace declaration is removed from myserviceReturn, JAX-WS is able to return else than null. Does anyone have a clue how to force JAX-WS to ignore namespaces, how to modify SOAP response manually to exclude "ns1", or other ideas for this kind of problem? Any help is appreciated!!!

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  • How to Deserialize Missing Fields To Nulls

    - by Nathan
    I am working on a .NET project where several versions of the same type of object have been created over the life of the project - most new versions add a field or two. However, now I am looking to mitigate problems for users with an old version. My goal is that when a user tries to open an old version of the serialized object with the new program, the program will automatically assign default values to the fields that are missing from the depreciated version of the file. For example, say I had a class with two boolean fields - RepeatSound and RepeatForever. The first version of the program doesn't know how to repeat forever, so it only saved RepeatSound: <anyType xsi:type="Sound"> <RepeatSound>true</RepeatSound> </anyType> but the new files look like this: <anyType xsi:type="Sound"> <RepeatSound>true</RepeatSound> <RepeatForever>true</RepeatForever> </anyType> My goal is that when I deserialize the first file in the new program that it will create the Sound object but simply default the value of RepeatForever to false. Right now trying to deserialize the first object would throw an exception. Thank you in advance for any responses

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  • Spring Security 3.0 - Intercept-URL - All pages require authentication but one

    - by gav
    Hi All, I want any user to be able to submit their name to a volunteer form but only administrators to be able to view any other URL. Unfortunately I don't seem to be able to get this correct. My resources.xml are as follows; <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <http realm = "BumBumTrain Personnel list requires you to login" auto-config="true" use-expressions="true"> <http-basic/> <intercept-url pattern="/person/volunteer*" access=""/> <intercept-url pattern="/**" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_ADMIN"/> </user-service> </authentication-provider> </authentication-manager> </beans:beans> Specifically I am trying to achieve the access settings I described via; <intercept-url pattern="/person/volunteer*" access=""/> <intercept-url pattern="/**" access="isAuthenticated()" /> Could someone please describe how to use intercept-url to achieve the outcome I've described? Thanks Gav

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  • How do I process multipart http responses in Ruby Net:HTTP?

    - by seal-7
    There is so much information out there on how to generate multipart responses or do multipart file uploads. I can't seem to find any information on how to process a multipart http response. Here is some IRB output from a multipart http response I am working with. >> response.http.content_type => "multipart/related" >> response.http.body[0..2048] => "\r\n------=_Part_3_806633756.1271797659309\r\nContent-Type: text/xml; charset=UTF-8\r\nContent-Transfer-Encoding: binary\r\nContent-Id: <A0FCC4333C6D0FCA346B97FAB6B61818>\r\n\r\n<?xml version="1.0" encoding="UTF-8"?><soapenv:Envelope xmlns:soapenv="http://www.w3.org/2003/05/soap-envelope" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><soapenv:Body><ns1:runReportResponse soapenv:encodingStyle="http://www.w3.org/2003/05/soap-encoding" xmlns:ns1="http://192.168.1.200:8080/jasperserver/services/repository"><ns2:result xmlns:ns2="http://www.w3.org/2003/05/soap-rpc">runReportReturn</ns2:result><runReportReturn xsi:type="xsd:string">&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;\n&lt;operationResult version=&quot;2.0.1&quot;&gt;\n\t&lt;returnCode&gt;&lt;![CDATA[0]]&gt;&lt;/returnCode&gt;\n&lt;/operationResult&gt;\n</runReportReturn></ns1:runReportResponse></soapenv:Body></soapenv:Envelope>\r\n------=_Part_3_806633756.1271797659309\r\nContent-Type: application/pdf\r\nContent-Transfer-Encoding: binary\r\nContent-Id: <report>\r\n\r\n%PDF-1.4\n%\342\343\317\323\n3 0 obj

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  • How to wrtie a XML License Line(ended with a forward slash '/') in C#?

    - by Nano HE
    I want to write a XML file as below: <?xml version="1.0" encoding="UTF-8"?> <books xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <License licenseId="" licensePath="" /> Some piece of my code attached here // Create a new file in D:\\ and set the encoding to UTF-8 XmlTextWriter textWriter = new XmlTextWriter("D:\\books.xml", System.Text.Encoding.UTF8); // Format automatically textWriter.Formatting = Formatting.Indented; // Opens the document textWriter.WriteStartDocument(); // Write the namespace declaration. textWriter.WriteStartElement("books", null); // Write the genre attribute. textWriter.WriteAttributeString("xmlns", "xsd", null, "http://www.w3.org/2001/XMLSchema"); textWriter.WriteAttributeString("xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance"); And now I need to write the License Line below in C# <License licenseId="" licensePath="" /> But I don't know how to move on for I found the Line ended with the forward slash / .Thank you.

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  • Axis webservice calls fail sometimes, access.log shows content!

    - by epischel
    Hi, our app is a webservice client (axis 1) to a third party webservice (also axis 1). We use it for some years now. Since a few weeks, we (as a client) get sometimes HTTP status 400 (bad request) or read timeouts when calling the webservice. Strangely, the access.log of the service shows part of the request or the response instead of the URL. It looks like this (looks like the end of the request string) x.x.x.x -> y.y.y.y:8080 - - [timestamp] "POST /webservice HTTP/1.0" 200 16127 0 x.x.x.x -> y.y.y.y:8080 - - [timestamp] "POST /webservice HTTP/1.0" 200 22511 1 x.x.x.x -> y.y.y.y:8080 - - [timestamp] "il=\"true\"/><nsl:text xsi:type=\"xsd:string\" xsi:nil=\"true\"/></SOAPSomeOperation></soapenv:Body></soapenv:Envelope> Axis/1.4" 400 299 0 or (some string out of the what looks like the request) x.x.x.x -> y.y.y.y:8080 - - [timestamp] ":string\">some text</sometag><othertag>moretext" 400 299 0 or in some other cases it looks like two requests thrown together (... means xml string left out): x.x.x.x -> y.y.y.y:8080 - - [timestamp] "...</someop></soapenv:Body></soapenv:Envelope>:xsd=\"http://www.w3.org/2001/XMLSchema\"...</soapenv:Body></soapenv:Envelope>" 400 299 0 Application log does not give any hints. Frequency of such call is 1% of all calls to that service. The only discriminator I know of so far is that it happens since operations informed us that the service url changed because of "server migration". Has anyone experienced such phenomenon yet? Has somebody got an idea whats wrong and how to fix? Thanks,

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  • XmlSerialize a custom collection with an Attribute

    - by roomaroo
    I've got a simple class that inherits from Collection and adds a couple of properties. I need to serialize this class to XML, but the XMLSerializer ignores my additional properties. I assume this is because of the special treatment that XMLSerializer gives ICollection and IEnumerable objects. What's the best way around this? Here's some sample code: using System.Collections.ObjectModel; using System.IO; using System.Xml.Serialization; namespace SerialiseCollection { class Program { static void Main(string[] args) { var c = new MyCollection(); c.Add("Hello"); c.Add("Goodbye"); var serializer = new XmlSerializer(typeof(MyCollection)); using (var writer = new StreamWriter("test.xml")) serializer.Serialize(writer, c); } } [XmlRoot("MyCollection")] public class MyCollection : Collection<string> { [XmlAttribute()] public string MyAttribute { get; set; } public MyCollection() { this.MyAttribute = "SerializeThis"; } } } This outputs the following XML (note MyAttribute is missing in the MyCollection element): <?xml version="1.0" encoding="utf-8"?> <MyCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> What I want is <MyCollection MyAttribute="SerializeThis" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> Any ideas? The simpler the better. Thanks.

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  • Class 'org.springframework.http.converter.ResourceHttpMessageConverter' not found - how to correct?

    - by Ash Kim
    Eclipse STS is reporting I have problem with my spring project. It's a fresh project generated from the Spring Web MVC Project Template (File-New-Spring Template Project-Spring Web MVC ). When I create the project it has no problems - it's only once I modify the pom (by adding the hibernate dependencies) that STS then picks up the spring problem. Strangely if I revert the pom the problem remains. Also I can run the project on a spring tc server and all works correctly. Any ideas how I can satisfy this problem report? "Class 'org.springframework.http.converter.ResourceHttpMessageConverter' not found" mvc-config.xml /src/main/webapp/WEB-INF/spring line 9 Spring Beans Problem mvc-config.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd"> <mvc:annotation-driven /> <!-- <= PROBLEMATIC LINE REPORTED BY STS --> <!-- Resolves view names to protected .jsp resources within the /WEB-INF/views directory --> <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/views/"/> <property name="suffix" value=".jsp"/> </bean> </beans>

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  • java.lang.ClassNotFoundException: org.springframework.ui.ModelMap

    - by aelshereay
    I create a simple webapp using tomcat 6, spring 2.5.6 and maven. The problem is when I boot up tomcat, I am getting the following errors: SEVERE: StandardWrapper.Throwable java.lang.NoClassDefFoundError: org/springframework/ui/ModelMap ... Caused by: java.lang.ClassNotFoundException: org.springframework.ui.ModelMap The ModelMap class does exist in spring-2.5.6.jar and spring-context-2.5.6.jar, I also have some other spring jars. All of them are being deployed to tomcat correctly, when I check the application WEB-INF (deployed to tomcat) I found all those jars there! I have only one @Controller that has a @RequestMapping("/home.htm") showForm(ModelMap model) method. My applicationContext is quite simple: <?xml version="1.0" encoding="utf-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:dwr="http://www.directwebremoting.org/schema/spring-dwr" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd http://www.directwebremoting.org/schema/spring-dwr http://www.directwebremoting.org/schema/spring-dwr-3.0.xsd" default-autowire="byName"> <context:component-scan base-package="org.myapp"/> <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/view/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans>

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  • XML Catalog in Eclipse is not working

    - by svaret
    Where I work we do not have any internet connection. We still want to have validation and code completion when editing xml files. I have tried the instructions here http://www.helmers.nu/?p=276 However, I try the instructions, restarts eclipse, do reload dependencies. I still cannot get any code completion nor validation. Can anyone point me in the right direction? I have tried both with Eclipse Galileo and Helios. My catalog.xml <?xml version="1.0" encoding="UTF-8" standalone="no"?> <catalog xmlns="urn:oasis:names:tc:entity:xmlns:xml:catalog"> <uri name="http://www.liquibase.org/xml/ns/dbchangelog/1.9" uri="file:///C:/dev/XMLSchemaDefinition/dbchangelog-1.9.xsd"/> </catalog> My xml-file: <?xml version="1.0" encoding="UTF-8" standalone="no"?> <databaseChangeLog xmlns="http://www.liquibase.org/xml/ns/dbchangelog/1.9" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.liquibase.org/xml/ns/dbchangelog/1.9 http://www.liquibase.org/xml/ns/dbchangelog/dbchangelog-1.9.xsd"> </databaseChangeLog>

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  • Parsing XML in C# from stream

    - by Phillip
    I've tried several methods, from Linq to loading the data to an XML document, but i can't seem to be able to return the result that i need. here's the example XML: <serv:message xmlns:serv="http://www.webex.com/schemas/2002/06/service" xmlns:com="http://www.webex.com/schemas/2002/06/common" xmlns:event="http://www.webex.com/schemas/2002/06/service/event"><serv:header><serv:response><serv:result>SUCCESS</serv:result><serv:gsbStatus>PRIMARY</serv:gsbStatus></serv:response></serv:header><serv:body><serv:bodyContent xsi:type="event:createEventResponse" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><event:sessionKey>11111111</event:sessionKey><event:guestToken>111111111111111111111</event:guestToken></serv:bodyContent></serv:body></serv:message> And, here's what i've tried to do: StreamReader reader = new StreamReader(dataStream); XmlDocument doc = new XmlDocument(); doc.LoadXml(reader.ReadToEnd()); XmlNamespaceManager ns = new XmlNamespaceManager(doc.NameTable); XmlNamespaceManager ns2 = new XmlNamespaceManager(doc.NameTable); XmlNamespaceManager ns3 = new XmlNamespaceManager(doc.NameTable); ns.AddNamespace("serv", "http://www.webex.com/schemas/2002/06/service"); ns2.AddNamespace("com", "http://www.webex.com/schemas/2002/06/common"); ns3.AddNamespace("event", "http://www.webex.com/schemas/2002/06/service/event"); XmlNode node = doc.SelectSingleNode("result",ns); Yet, for some reason i cannot ever seem to return the actual result, which should be either 'SUCCESS' or 'FAILURE' based on the actual xml above. How can i do this?

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  • Deploy GWT Application to Google App Engine using NetBeans

    - by Yan Cheng CHEOK
    Hello, I try to deploy a GWT application, to Google App Engine using NetBeans. I had successful run GWT sample http://code.google.com/webtoolkit/doc/latest/tutorial/create.html using Personal GlassFish v3 Prelude Domain, by 1) Copy generated source code from StockWatcher to C:\Projects\StockWatcherNetbeans\src\java\com\google\ 2) Modify C:\Projects\StockWatcherNetbeans\nbproject\gwt.properties gwt.module=com.google.gwt.stockwatcher.StockWatcher 3) Select Personal GlassFish v3 Prelude Domain, and run. All works fine! Now, I try to select Google App Engine server, and run. However, I get the error "There is no appengine web project opened!" I check... There is file called C:\Projects\StockWatcherNetbeans\war\WEB-INF\appengine-web.xml with content <?xml version="1.0" encoding="UTF-8"?> <appengine-web-app xmlns="http://appengine.google.com/ns/1.0" xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:schemaLocation='http://kenai.com/projects/nbappengine/downloads/download/schema/appengine-web.xsd appengine-web.xsd'> <application>StockWatcherNetbeans</application> <version>1</version> </appengine-web-app> I am using NetBeans 6.7.1 GWT4NB (GWT Plugin for NetBeans) 2.6.12 Google App Engine plugin for NetBeans from http://kenai.com/downloads/nbappengine/1.0_NetBeans671/updates.xml Anything I had missed out? Even when I right click to the project, the Deploy to Google App Engine options is disabled. And yes, please do not ask me why not use Eclipse.

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  • java.lang.ExceptionInInitializerError Exception when creating Application Context in Spring

    - by cyotee
    I am practicing with Spring, and am getting a java.lang.ExceptionInInitializerError exception when I try to instantiate the context. The Exception appears below, with my code following it. I have simplified my experiment from before. The Exception Oct 17, 2012 5:54:22 PM org.springframework.context.support.AbstractApplicationContext prepareRefresh INFO: Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@570c16b7: startup date [Wed Oct 17 17:54:22 CDT 2012]; root of context hierarchy Exception in thread "main" java.lang.ExceptionInInitializerError at org.springframework.context.support.AbstractRefreshableApplicationContext.createBeanFactory(AbstractRefreshableApplicationContext.java:195) at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:128) at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:535) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:449) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:139) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:83) at helloworld.HelloWorldTest.main(HelloWorldTest.java:13) Caused by: java.lang.NullPointerException at org.springframework.beans.factory.support.DefaultListableBeanFactory.<clinit>(DefaultListableBeanFactory.java:105) ... 7 more My configuration XML <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:c="http://www.springframework.org/schema/c" xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <bean id="messageContainer" class="helloworld.MessageContainer"> <property name="message" value="Hello World"> </property> </bean> <bean id="messageOutputService" class="helloworld.MessageOutputService"> </bean> My test class. package helloworld; import org.springframework.context.ApplicationContext; import org.springframework.context.support.ClassPathXmlApplicationContext; public class HelloWorldTest { /** * @param args */ public static void main(String[] args) { ApplicationContext context = new ClassPathXmlApplicationContext("HelloWorldTest-context.xml"); MessageContainer message = context.getBean(MessageContainer.class); MessageOutputService service = context.getBean(MessageOutputService.class); service.outputMessageToConsole(message); } }

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  • XAttribute Generating strange namespaces

    - by Adam Driscoll
    I'm constructing an XElement with a couple attributes that have different namespaces. The code looks like this: var element = new XElement("SynchronousCommand", new XAttribute("{wcm}action", "add"), new XAttribute("{ns}id", Guid.NewGuid()), new XElement... ); The XML that is generated looks like this: <unattend xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="urn:schemas-microsoft-com:unattend"> <SynchronousCommand d5p1:action="add" d5p2:id="c0f5fc6d-d407-4d3d-8a05-d84236cca2fb" xmlns:d5p2="ns" xmlns:d5p1="wcm"> ... </SynchronousCommand> </unattend> I'm just wondering if the auto-generated d5p2 is valid and why it is doing this. According to the XML standards here it seems like it would be valid. But why is it not: <unattend xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="urn:schemas-microsoft-com:unattend"> <SynchronousCommand wcm:action="add" ns:id="c0f5fc6d-d407-4d3d-8a05-d84236cca2fb" > To generate the XML I'm doing this: public class unattend { public List<XElement> Any {get;} } var unattend = new unattend(); unattend.Add(element); serializer.Serialize(xmlWriter, unattend);

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  • Add namespace to XmlTextWriter using C#

    - by xml
    Hi, I have an serializeable class that his root is serizlized to XmlRootAttribute with namespace. I want to add additional namespace to this root elemt, how can i do it? adding XmlAttribute failed to compile. The code: [System.Xml.Serialization.XmlRootAttribute("Root", Namespace = "http://www.w3.org/2003/05/soap-envelope", IsNullable = false)] public class MyClass { [System.Xml.Serialization.XmlElement("...")] public ClassA A; [System.Xml.Serialization.XmlElement("..")] public ClassB b; } After the serialization i'm getting something like that: <Root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://www.w3.org/2003/05/soap-envelope"> <ClassA/> <ClassB/> </Envelope> I want to add to the rood additioanl namespace, e.g. i want the xml to be: <Root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" **xmlns:tns="anotherXml"** xmlns="http://www.w3.org/2003/05/soap-envelope"> <ClassA/> <ClassB/> </Envelope> Any idea?

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  • How to Declare Complex Nested C# Type for Web Service

    - by TheArtTrooper
    I would like to create a service that accepts a complex nested type. In a sample asmx file I created: [WebService(Namespace = "http://tempuri.org/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] // To allow this Web Service to be called from script, using ASP.NET AJAX, uncomment the following line. // [System.Web.Script.Services.ScriptService] public class ServiceNest : System.Web.Services.WebService { public class Block { [XmlElement(IsNullable = false)] public int number; } public class Cell { [XmlElement(IsNullable = false)] public Block block; } public class Head { [XmlElement(IsNullable = false)] public Cell cell; } public class Nest { public Head head; } [WebMethod] public void TakeNest(Nest nest) { } } When I view the asmx file in IE the test page shows the example SOAP post request as: <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Body> <TakeNest xmlns="http://schemas.intellicorp.com/livecompare/"> <nest> <head> <cell> <block xsi:nil="true" /> </cell> </head> </nest> </TakeNest> </soap:Body> </soap:Envelope> It hasn't expanded the <block> into its number member. Looking at the WSDL, the types all look good. So is this just a limitation of the post demo page creator? Thanks.

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  • Java Mvc And Hibernate

    - by GigaPr
    Hi i am trying to learn Java, Hibernate and the MVC pattern. Following various tutorial online i managed to map my database, i have created few Main methods to test it and it works. Furthermore i have created few pages using the MVC patter and i am able to display some mock data as well in a view. the problem is i can not connect the two. this is what i have My view Looks like this <%@ include file="/WEB-INF/jsp/include.jsp" %> <html> <head> <title>Users</title> <%@ include file="/WEB-INF/jsp/head.jsp" %> </head> <body> <%@ include file="/WEB-INF/jsp/header.jsp" %> <img src="images/rss.png" alt="Rss Feed"/> <%@ include file="/WEB-INF/jsp/menu.jsp" %> <div class="ContainerIntroText"> <img src="images/usersList.png" class="marginL150px" alt="Add New User"/> <br/> <br/> <div class="usersList"> <div class="listHeaders"> <div class="headerBox"> <strong>FirstName</strong> </div> <div class="headerBox"> <strong>LastName</strong> </div> <div class="headerBox"> <strong>Username</strong> </div> <div class="headerAction"> <strong>Edit</strong> </div> <div class="headerAction"> <strong>Delete</strong> </div> </div> <br><br> <c:forEach items="${users}" var="user"> <div class="listElement"> <c:out value="${user.firstName}"/> </div> <div class="listElement"> <c:out value="${user.lastName}"/> </div> <div class="listElement"> <c:out value="${user.username}"/> </div> <div class="listElementAction"> <input type="button" name="Edit" title="Edit" value="Edit"/> </div> <div class="listElementAction"> <input type="image" src="images/delete.png" name="image" alt="Delete" > </div> <br /> </c:forEach> </div> </div> <a id="addUser" href="addUser.htm" title="Click to add a new user">&nbsp;</a> </body> </html> My controller public class UsersController implements Controller { private UserServiceImplementation userServiceImplementation; public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ModelAndView modelAndView = new ModelAndView("users"); List<User> users = this.userServiceImplementation.get(); modelAndView.addObject("users", users); return modelAndView; } public UserServiceImplementation getUserServiceImplementation() { return userServiceImplementation; } public void setUserServiceImplementation(UserServiceImplementation userServiceImplementation) { this.userServiceImplementation = userServiceImplementation; } } My servelet definitions <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <!-- the application context definition for the springapp DispatcherServlet --> <bean name="/home.htm" class="com.rssFeed.mvc.HomeController"/> <bean name="/rssFeeds.htm" class="com.rssFeed.mvc.RssFeedsController"/> <bean name="/addUser.htm" class="com.rssFeed.mvc.AddUserController"/> <bean name="/users.htm" class="com.rssFeed.mvc.UsersController"> <property name="userServiceImplementation" ref="userServiceImplementation"/> </bean> <bean id="userServiceImplementation" class="com.rssFeed.ServiceImplementation.UserServiceImplementation"> <property name="users"> <list> <ref bean="user1"/> <ref bean="user2"/> </list> </property> </bean> <bean id="user1" class="com.rssFeed.domain.User"> <property name="firstName" value="firstName1"/> <property name="lastName" value="lastName1"/> <property name="username" value="username1"/> <property name="password" value="password1"/> </bean> <bean id="user2" class="com.rssFeed.domain.User"> <property name="firstName" value="firstName2"/> <property name="lastName" value="lastName2"/> <property name="username" value="username2"/> <property name="password" value="password2"/> </bean> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans> and finally this class to access the database public class HibernateUserDao extends HibernateDaoSupport implements UserDao { public void addUser(User user) { getHibernateTemplate().saveOrUpdate(user); } public List<User> get() { User user1 = new User(); user1.setFirstName("FirstName"); user1.setLastName("LastName"); user1.setUsername("Username"); user1.setPassword("Password"); List<User> users = new LinkedList<User>(); users.add(user1); return users; } public User get(int id) { throw new UnsupportedOperationException("Not supported yet."); } public User get(String username) { return null; } } the database connection occurs in this file <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd"> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="org.hsqldb.jdbcDriver"/> <property name="url" value="jdbc:hsqldb:hsql://localhost/rss"/> <property name="username" value="sa"/> <property name="password" value=""/> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean" > <property name="dataSource" ref="dataSource" /> <property name="mappingResources"> <list> <value>com/rssFeed/domain/User.hbm.xml</value> </list> </property> <property name="hibernateProperties" > <props> <prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop> </props> </property> </bean> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory"/> </bean> <bean id="userDao" class="com.rssFeed.dao.hibernate.HibernateUserDao"> <property name="sessionFactory" ref="sessionFactory"/> </bean> </beans> Could you help me to solve this problem i spent the last 4 days and nights on this issue without any success Thanks

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