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  • Trouble echoing data - data being converted to 0

    - by Haraldo
    Hi, I feel this is something to do with my httpd setup for apache. I'm using mod_rewrite if that helps but I think that only effects the url. It seems when I output some data such as: $sMessage = 'Error'; echo $sMessage; It works fine but when I do this: $sMessage = 'Error'; echo ''+$sMessage+''; It returns 0. Very odd!

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  • Conditionally Delete in Ant

    - by kunjaan
    I want to delete the directory if the property "delete-compiled-dir" is set to true. Right now I have <target name="deleted-after-compilation" depends="compile,jar"> <condition property="${delete-compiled-dir}" value="true"> <delete dir="${compilation-dir}" /> </condition> <echo> Deleting Compiled Directory Classes </echo> </target>

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  • url not found in zend framework though working for index page

    - by Rohan Thakare
    i am trying to develop website using zend framework so i had created one index.php file where all my requests goes and c.reated two controller one is IndexController and other is TestController Class IndexController extends Zend_Controller_Action{ public function indexAction(){ echo "Index Index Jamla"; } public function displayAction(){ echo "Index Display Jamla"; } } now when i access the url http://test/ it correctly calls IndexController and its IndexAction function but when i access the url http://test/index/index it displays the message url /index/index was not found on this server same it does when i access http://test/test/index though http://test/ is equivalent to http://test/index/index

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  • alternative of `die()` in php

    - by Prasoon Saurav
    I have the following script <?php echo "I am alive<br>"; die("I am dying<br>"); echo ("Dead"); ?> The output that I get is I am alive I am dying Is there any way (alternative/substitute of die()) using which the execution of the remaining script be continued?

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  • unhandled errors in php

    - by lexus
    How can I know during runtime that my code threw a Warning? example try { echo (25/0); } catch (exception $exc) { echo "exception catched"; } throws a "Warning: Division by zero" error that i can not handle on my code.

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  • Linking Post Title to Specific Page ID

    - by ThatMacLad
    I've created a form to update my websites homepage with content but I wanted to know how I could set it up so that a posts title links to a specific post ID. I'd also like to add a Read More link that directs anybody reading the blog to the correct post. Here is my PHP code: <html> <head> <title>Blog Name</title> </head> <body> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $password = $row['password']; $id = $row['id']; if ($password == 1) { echo "<p><strong>" . $title . "</strong></p>"; printf("<p>This is a password protected entry. If you have a password, log in below.</p>"); printf("<form method=\"post\" action=\"post.php?id=%s\"><p><strong><label for=\"username\">Username:</label></strong><br /><input type=\"text\" name=\"username\" id=\"username\" /></p><p><strong><label for=\"pass\">Password:</label></strong><br /><input type=\"password\" name=\"pass\" id=\"pass\" /></p><p><input type=\"submit\" name=\"submit\" id=\"submit\" value=\"submit\" /></p></form>",$id); print "<hr />"; } else { ?> <p><strong><?php echo $title; ?></strong><br /><br /> <?php echo $entry; ?><br /><br /> Posted on <?php echo $date; ?> <hr /></p> <?php } } ?> </body> </html> Thanks for any help. I really appreciate any input!

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  • PHP Sockets Errors (connection refused and No such file or directory)

    - by Purefan
    Hello all, I am writing a server app (broadcaster) and a client (relayer). Several relayers can connect to the broadcaster at the same time, send information and the broadcaster will redirect the message to a matching relayer (for example relayer1 sends to broadcaster who sends to relayer43, relayer2 - broadcaster - relayer73...) The server part is working as I have tested it with a telnet client and although its at this point only an echo server it works. Both relayer and broadcaster sit on the same server so I am using AF_UNIX sockets, both files are in different folders though. I have tried two approaches for the relayer and both have failed, the first one is using socket_create: public function __construct() { // where is the socket server? $this->_sHost = 'tcp://127.0.0.1'; $this->_iPort = 11225; // open a client connection $this->_hSocket = socket_create(AF_UNIX, SOCK_STREAM, 0); echo 'Attempting to connect to '.$this->_sHost.' on port '.$this->_iPort .'...'; $result = socket_connect($this->_hSocket, $this->_sHost, $this->_iPort); if ($result === false) { echo "socket_connect() failed.\nReason: ($result) " . socket_strerror(socket_last_error($this->_hSocket)) . "\n"; } else { echo "OK.\n"; } This returns "Warning: socket_connect(): unable to connect [2]: No such file or directory in relayer.class.php on line 27" and (its running from command line) it often also returns a segmentation fault. The second approach is using pfsockopen: public function __construct() { // where is the socket server? $this->_sHost = 'tcp://127.0.0.1'; $this->_iPort = 11225; // open a client connection $fp = pfsockopen ($this->_sHost, $this->_iPort, $errno, $errstr); if (!$fp) { $result = "Error: could not open socket connection"; } else { // get the welcome message fgets ($fp, 1024); // write the user string to the socket fputs ($fp, 'Message ' . __LINE__); // get the result $result .= fgets ($fp, 1024); // close the connection fputs ($fp, "END"); fclose ($fp); // trim the result and remove the starting ? $result = trim($result); $result = substr($result, 2); // now print it to the browser } which only returns the error "Warning: pfsockopen(): unable to connect to tcp://127.0.0.1:11225 (Connection refused) in relayer.class.php on line 33 " In all tests I have tried with different host names, 127.0.0.1, localhost, tcp://127.0.0.1, 192.168.0.199, tcp://192.168.0.199, none of it has worked. Any ideas on this?

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  • Script Bash and History Unix

    - by user1107078
    i just start to use Script bash on UNIX and i didnt find a solution to write the first command in the history which start , for example , with ls. If i write in the shell history !ls it works but when i'm going to create a script it wont work. This is my example code #!/bin/bash set -o | grep history set -o history #echo "HISTFILE is $HISTFILE" #history "!ls"; #history #!ls history #it works Another Question why echo "HISTFILE is $HISTFILE" print me only HISTFILE is ?? Thanks

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  • Replacing div html() by echoing PHP - how to?

    - by Jared
    Hello, I have a multiple product elements that get their class and ID from PHP: $product1["codename"] = "product-1"; $product1["short"] = "Great Product 1"; $product2["codename"] = "product-2"; $product2["short"] = "Great Product 2"; <div class="leftMenuProductButton" id="'. $product1["codename"].'" >'. $product1["short"].'</div> <div class="leftMenuProductButton" id="'. $product2["codename"].'" >'. $product2["short"].'</div> These display as: <div class="leftMenuProductButton" id="product-1" > Great Product 1</div> <div class="leftMenuProductButton" id="product-2" > Great Product 2</div> In the page, I have an element that I want to replace the HTML: <div id="productPopupTop"> //Replace this content </div> Using jquery, I have tried the following: $( '.leftMenuProductButton' ).hover ( function () { var swapNAME = $(this).attr("id"); //gets the ID, #product-1, #product-2 etc. This works. $("#productPopupTop").html(' <? echo $' + swapNAME + '["short"] ?>'); //This is supposed to get something like <? echo $product-1["short"] ?> This doesn't appear to work. }, function () { //this is just here for later }); If I try to do an alert('<? echo $' + swapNAME + '["short"] ?>'); it will literally display something like <? echo $product-1["short"] ?> Please note that both the Javascript and the PHP are externally linked in a PHP file (index.php <<< (js.js, products.php) QUESTION: How do I replace the HTML() of #productPopupTop with the ["short"] of a product? If I should use Ajax, how would I code this?

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  • Classes within classes in PHP

    - by Matt
    Can you do this in PHP? I've heard conflicting opinions: Something like: Class bar { function a_function () { echo "hi!"; } } Class foo { public $bar; function __construct() { $this->bar = new bar(); } } $x = new foo(); $x->bar->a_function(); Will this echo "hi!" or not?

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  • How to use unset() for this Linear Linked List in PHP

    - by Peter
    I'm writing a simple linear linked list implementation in PHP. This is basically just for practice... part of a Project Euler problem. I'm not sure if I should be using unset() to help in garbage collection in order to avoid memory leaks. Should I include an unset() for head and temp in the destructor of LLL? I understand that I'll use unset() to delete nodes when I want, but is unset() necessary for general clean up at any point? Is the memory map freed once the script terminates even if you don't use unset()? I saw this SO question, but I'm still a little unclear. Is the answer that you simply don't have to use unset() to avoid any sort of memory leaks associated with creating references? I'm using PHP 5.. btw. Unsetting references in PHP PHP references tutorial Here is the code - I'm creating references when I create $temp and $this-head at certain points in the LLL class: class Node { public $data; public $next; } class LLL { // The first node private $head; public function __construct() { $this->head = NULL; } public function insertFirst($data) { if (!$this->head) { // Create the head $this->head = new Node; $temp =& $this->head; $temp->data = $data; $temp->next = NULL; } else { // Add a node, and make it the new head. $temp = new Node; $temp->next = $this->head; $temp->data = $data; $this->head =& $temp; } } public function showAll() { echo "The linear linked list:<br/>&nbsp;&nbsp;"; if ($this->head) { $temp =& $this->head; do { echo $temp->data . " "; } while ($temp =& $temp->next); } else { echo "is empty."; } echo "<br/>"; } } Thanks!

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  • How to store the hostname in a variable in a .bat file?

    - by eqbridges
    I would like to convert this /bin/sh syntax into a widely compatible Windows batch script: host=`hostname` echo ${host} How to do this so that it'll work on any Windows Vista, Windows XP, and Windows 2000 machine? To clarify: I would then like to go on in the program and use the hostname as stored in the variable host. In other words, the larger goal of the program is not to simply echo the hostname.

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  • MySQL Database Query - Codeigniter

    - by user2450349
    I am building an application with Codeigniter and need some help with a DB query. I have a table called users with the following fields: user_id, user_name, user_password, user_email, user_role, user_manager_id In my app, I pull all records from the user table using the following: function get_clients() { $this->db->select('*'); $this->db->where('user_role', 'client'); $this->db->order_by("user_name", "Asc"); $query = $this->db->get("users"); return $query->result_array(); } This works as expected, however when I display the results in the view, I also want to display a new column called Manager which will display the managers user_name field. The user_manager_id is the id of the user from the same table. Im guessing you can create an outer join on the same table but not sure. In the view, I am displaying the returned info as follows: <table class="table table-striped" id="zero-configuration"> <thead> <tr> <th>Name</th> <th>Email</th> <th>Manager</th> </tr> </thead> <tbody> <?php foreach($clients as $row) { ?> <tr> <td><?php echo $row['user_name']; ?> (<?php echo $row['user_username']; ?>)</td> <td><?php echo $row['user_email']; ?></td> <td><?php echo $row['???']; ?></td> </tr> <?php } ?> </tbody> </table> Any idea of how I can form the query and display the manager name is the view? Example: user_id user_name user_password user_email user_role user_manager_id 1 Ollie adjjk34jcd [email protected] client null 2 James djklsdfsdjk [email protected] client 1 When i query the database, i want to display results like this: Ollie [email protected] James [email protected] Ollie

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  • my sql insert query not working

    - by Piyush
    I am inserting userId.It is displaying correct but inserting 0 in spite of actual userId. mycode- If(! empty($userIDToCheck) || $userIDToCheck != '' ) { echo $userIDToCheck; $sql = "INSERT INTOpnpdb.ruser(userid) VALUES ('$userIDToCheck');"; mysql_query($sql)or die(mysql_error()); echo "Done"; } Output : pi203713 Done But is database it is inserting "0"???

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  • vim variable declaration

    - by dorelal
    I added following line of code in .vimrc let g:jslint_status = 'enabled' if exists("jslint_status") echo jstlint_status else echo 'not found' endif Error message E121: Undefined variable: jstlint_status E15: Invalid expression: jstlint_status What am I doing wrong?

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  • php web services not getting data from iphone application

    - by user317192
    Hi, I am connecting with a php web service from my iphone application, I am doing a simple thing i.e. 1. Getting user inputs for: username password in a text field from the iphone form and sending the same to the PHP Post request web service. At the web service end I receive nothing other than blank fields that are inserted into the MySQL Database....... The code for sample web service is: ***********SAMPLE CODE FOR WEB SERVICES***** mysql_select_db("eventsfast",$con); $username = $_REQUEST['username']; $password = $_REQUEST['password']; echo $username; echo $password; $data = $_REQUEST; $fp = fopen("log.txt", "w"); fwrite($fp, $data['username']); fwrite($fp, $data['password']); $sql="INSERT INTO users(username,password) VALUES('{$username}','{$password}')"; if(!mysql_query($sql,$con)) { die('Error:'.mysql_error()); } echo json_encode("1 record added to users table"); mysql_close($con); echo "test"; ? ***************PHP******** ****** **************IPHONE EVENT CODE******* import "postdatawithphpViewController.h" @implementation postdatawithphpViewController @synthesize userName,password; -(IBAction) postdataid) sender { NSLog(userName.text); NSLog(password.text); NSString * dataTOB=[userName.text stringByAppendingString:password.text]; NSLog(dataTOB); NSData * postData=[dataTOB dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSLog(postLength); NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://localhost:8888/write.php"]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSURLResponse *response; NSError *error; [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; if(error==nil) NSLog(@"Error is nil"); else NSLog(@"Error is not nil"); NSLog(@"success!"); } Please help.............

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  • How to add a method to an existing class in PHP?

    - by sombe
    I'm using WordPress as a CMS, and I want to extend one of its classes without having to inherit from another class; i.e. I simply want to "add" more methods to that class: class A { function do_a() { echo 'a'; } } then: function insert_this_function_into_class_A() { echo 'b'; } (some way of inserting the latter into A class) and: A::insert_this_function_into_class_A(); # b Is this even possible in tenacious PHP?

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  • test remote file if directory

    - by soField
    HOSTNAME=$1 #missing files will be created by chk_dir for i in `cat filesordirectorieslist_of_remoteserver` do isdir=remsh $HOSTNAME "if [ -d $i ]; then echo dir; else echo file; fi" if [ $isdir -eq "dir" ] then remsh $HOSTNAME "ls -d $i | cpio -o" | cpio -id else remsh $HOSTNAME "ls | cpio -o" | cpio -id fi done i need simple solution for checking remote file is directory or file ? thanks

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  • What is wrong in this simple Makefile

    - by Walidix
    SRC_VAR = test string for variable manipulation. TEST1_VAR = $(subset for,foo,${SRC_VAR}) all: @echo original str: ${SRC_VAR} @echo substitution: ${TEST1_VAR} This is the output: original str: test string for variable manipulation. substitution: The output should be: original str: My test string for variable manipulation. substitution: My test string foo variable manipulation.

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  • Pass PHP variables without being seen when working with a database generated list

    - by Wilcoholic
    Looking for any help regarding the problem. Here's the deal: I have a database that has a teams table and it contains team_id. On one of my pages, I generate a list of links that contain the team_id of the creator in their get URL. I need the team_id on the next page but can't figure out how to pass it through any other way. Using a form and POST isn't an option because this method would only pass through the last links data on the list. Storing in a session isn't an option either because there is no way to discretely pass the the variables I need to a function to set the session variables. I have tried and it can pretty easily be viewed from viewing the source code. So here's some sample code to see exactly what I'm dealing with. <? if(mysql_num_rows($result2)>0){ ?> <a class="fltrt btn btn-danger btn-small" onclick="test()" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=cancel">Cancel Match</a> <?}else{?> <a class="fltrt btn btn-success btn-small" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=accept">Accept Match</a> <?} ?> The code above is generated multiple times on a page via a while loop that was excluded. I want to pass the match_id and team_id variables without being seen anywhere. If I made this a form, it wouldn't pass the correct variables unless there is only one result at the time (not likely). I'm sure there has to be an easy method that is eluding me, so please share thoughts on how to solve this. I feel as though I am not explaining it well enough, but it's not really easy to explain. I basically want something that works like GET but acts like POST and can be hidden from people viewing source code or link locations. Thanks

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