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  • Password-protected sharing allows access to users who have no account?

    - by romkyns
    Running Win7 on two computers in my LAN. Computer A has password-protected sharing enabled, and shares a folder. It has a single user account "Bob", and the Guest account is turned off. The network is workgroup-based. According to the descriptions of the "password-protected sharing" I could find, the only people who can access the shared folder via the LAN are those who know the username+password for the "Bob" account. However a second computer on the LAN is able to view this shared folder by simply browsing to Computer A. They don't need to enter any passwords or anything. The only user account registered on that PC is called "Jim", and has a different password from "Bob". How on earth is computer B able to view this shared folder? Is the popular description of the "password-protected sharing" feature inaccurate / did I misunderstand it big time? P.S. There is a possibility that the password for "Bob" has been entered on that PC once, and possibly the "remember password" box was checked. I've looked in the "Credential Manager" on both computers and there is nothing saved anywhere.

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  • Google 2-step verification: Should my phone know my password? [closed]

    - by Sir Code-A-Lot
    Hi, Just enabled 2-step verification for my Google account. I have installed Google Authenticator on my Android phone, and I set up an application specific password for the Google account associated on my phone. This works great when just using installed apps like Gmail, Calendar and Google Reader. But if I want to access Google Docs, Google Tasks or any other website that requires a Google login, I don't seem to be able to use a application specific password. I have to use my real password and then use Google Authenticator to make a code for the next step. This means if my phone is stolen, revoking the password to my phone is pointless. The phone have already been verified, and all that is needed is my password, which the phones browser will have remembered. I realize that I can take measures to ensure the phones browser doesn't remember my password, but that's just not convenient at all. Am I missing something, or is there no elegant solution to this? Should I just let my phone know my real password? As I see it, being able to login with application specific passwords on websites (which apparently isn't possible) is the only way I can revoke my phones access in a meaningful way.

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  • Trying to use Digest Authentication for Folder Protection

    - by Jon Hazlett
    StackOverflow users suggested I try my question here. I'm using Server 2008 EE and IIS 7. I've got a site that I've migrated over from XP Pro using IIS 5. On the old system, I was using IIS Password to use simple .htaccess files to control a couple of folders that I didn't want to be publicly viewable. Now that I'm running a full-blown DC with a more powerful version of IIS, I decided it'd be a good idea to start using something slightly more sophisticated. After doing my research and trying to keep things as cheap as possible with a touch of extra security, I decided that Digest Authentication would be the best way to go. My issue is this: With Anon access disabled and Digest enabled, I am never prompted for credentials. when on the server, viewing domain[dot]com/example will simply show my 401.htm page without prompting me for credentials. when on a different network/computer, viewing domain[dot]com/example again shows my 401.htm without prompting for credentials. At the site level I only have Anon enabled. Every subfolder, unless I want it protected, has just Anon enabled. Only the folders I want protected have Anon disabled and Digest enabled. I have tried editing the bindings to see if that would spark any kind of change... www.domain.com, domain.com, and localhost have all been tried. There was never a change in behavior at any permutation (aside from the page not being found when I un-bound localhost to the site). I might have screwed up when I deleted the default site from IIS. I didn't think I'd actually need it for anything, but some of what I have read online is telling me otherwise now. As for Digest settings, I have it pointed to local.domain.com, which is the name assigned to my AD Domain. I'm guessing that's right, but honestly have no clue about what a realm actually is. Would it matter that I have an A record for local.domain.com pointing to my IP address? I had problems initially with an absolute link for 401.htm pages, but have since resolved that. Instead of D:\HTTP\401.htm I've used /401.htm and all is well. I used to get error 500's because it couldn't find the custom 401.htm file, but now it loads just fine. As for some data, I was getting entries like this from access logs: 2009-07-10 17:34:12 10.0.0.10 GET /example/ - 80 - [workip] Mozilla/4.0+(compatible;+MSIE+7.0;+Windows+NT+5.1;+.NET+CLR+1.1.4322;+.NET+CLR+2.0.50727;+InfoPath.2) 401 2 5 132 But after correcting my 401.htm links now get logs like this: 2009-07-10 18:56:25 10.0.0.10 GET /example - 80 - [workip] Mozilla/5.0+(Windows;+U;+Windows+NT+5.1;+en-US;+rv:1.9.0.11)+Gecko/2009060215+Firefox/3.0.11 200 0 0 146 I don't know if that means anything or not. I still don't get any credential challenges, regardless of where I try to sign in from ( my workstation, my server, my cellphone even ). The only thing that's seemed to work is viewing localhost and I donno what could be preventing authentication from finding it's way out of the server. Thanks for any help! Jon

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  • Hibernate - strange order of native SQL parameters

    - by Xorty
    Hello, I am trying to use native MySQL's MD5 crypto func, so I defined custom insert in my mapping file. <hibernate-mapping package="tutorial"> <class name="com.xorty.mailclient.client.domain.User" table="user"> <id name="login" type="string" column="login"></id> <property name="password"> <column name="password" /> </property> <sql-insert>INSERT INTO user (login,password) VALUES ( ?, MD5(?) )</sql-insert> </class> </hibernate-mapping> Then I create User (pretty simple POJO with just 2 Strings - login and password) and try to persist it. session.beginTransaction(); // we have no such user in here yet User junitUser = (User) session.load(User.class, "junit_user"); assert (null == junitUser); // insert new user junitUser = new User(); junitUser.setLogin("junit_user"); junitUser.setPassword("junitpass"); session.save(junitUser); session.getTransaction().commit(); What actually happens? User is created, but with reversed parameters order. He has login "junitpass" and "junit_user" is MD5 encrypted and stored as password. What did I wrong? Thanks EDIT: ADDING POJO class package com.xorty.mailclient.client.domain; import java.io.Serializable; /** * POJO class representing user. * @author MisoV * @version 0.1 */ public class User implements Serializable { /** * Generated UID */ private static final long serialVersionUID = -969127095912324468L; private String login; private String password; /** * @return login */ public String getLogin() { return login; } /** * @return password */ public String getPassword() { return password; } /** * @param login the login to set */ public void setLogin(String login) { this.login = login; } /** * @param password the password to set */ public void setPassword(String password) { this.password = password; } /** * @see java.lang.Object#toString() * @return login */ @Override public String toString() { return login; } /** * Creates new User. * @param login User's login. * @param password User's password. */ public User(String login, String password) { setLogin(login); setPassword(password); } /** * Default constructor */ public User() { } /** * @return hashCode * @see java.lang.Object#hashCode() */ @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + ((null == login) ? 0 : login.hashCode()); result = prime * result + ((null == password) ? 0 : password.hashCode()); return result; } /** * @param obj Compared object * @return True, if objects are same. Else false. * @see java.lang.Object#equals(java.lang.Object) */ @Override public boolean equals(Object obj) { if (this == obj) { return true; } if (obj == null) { return false; } if (!(obj instanceof User)) { return false; } User other = (User) obj; if (login == null) { if (other.login != null) { return false; } } else if (!login.equals(other.login)) { return false; } if (password == null) { if (other.password != null) { return false; } } else if (!password.equals(other.password)) { return false; } return true; } }

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  • C++ file input/output search

    - by Brian J
    Hi I took the following code from a program I'm writing to check a user generated string against a dictionary as well as other validation. My problem is that although my dictionary file is referenced correctly,the program gives the default "no dictionary found".I can't see clearly what I'm doing in error here,if anyone has any tips or pointers it would be appreciated, Thanks. //variables for checkWordInFile #define gC_FOUND 99 #define gC_NOT_FOUND -99 // static bool certifyThat(bool condition, const char* error) { if(!condition) printf("%s", error); return !condition; } //method to validate a user generated password following password guidelines. void validatePass() { FILE *fptr; char password[MAX+1]; int iChar,iUpper,iLower,iSymbol,iNumber,iTotal,iResult,iCount; //shows user password guidelines printf("\n\n\t\tPassword rules: "); printf("\n\n\t\t 1. Passwords must be at least 9 characters long and less than 15 characters. "); printf("\n\n\t\t 2. Passwords must have at least 2 numbers in them."); printf("\n\n\t\t 3. Passwords must have at least 2 uppercase letters and 2 lowercase letters in them."); printf("\n\n\t\t 4. Passwords must have at least 1 symbol in them (eg ?, $, £, %)."); printf("\n\n\t\t 5. Passwords may not have small, common words in them eg hat, pow or ate."); //gets user password input get_user_password: printf("\n\n\t\tEnter your password following password rules: "); scanf("%s", &password); iChar = countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); iUpper = countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); iLower =countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); iSymbol =countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); iNumber = countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); iTotal = countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); if(certifyThat(iUpper >= 2, "Not enough uppercase letters!!!\n") || certifyThat(iLower >= 2, "Not enough lowercase letters!!!\n") || certifyThat(iSymbol >= 1, "Not enough symbols!!!\n") || certifyThat(iNumber >= 2, "Not enough numbers!!!\n") || certifyThat(iTotal >= 9, "Not enough characters!!!\n") || certifyThat(iTotal <= 15, "Too many characters!!!\n")) goto get_user_password; iResult = checkWordInFile("dictionary.txt", password); if(certifyThat(iResult != gC_FOUND, "Password contains small common 3 letter word/s.")) goto get_user_password; iResult = checkWordInFile("passHistory.txt",password); if(certifyThat(iResult != gC_FOUND, "Password contains previously used password.")) goto get_user_password; printf("\n\n\n Your new password is verified "); printf(password); //writing password to passHistroy file. fptr = fopen("passHistory.txt", "w"); // create or open the file for( iCount = 0; iCount < 8; iCount++) { fprintf(fptr, "%s\n", password[iCount]); } fclose(fptr); printf("\n\n\n"); system("pause"); }//end validatePass method int checkWordInFile(char * fileName,char * theWord){ FILE * fptr; char fileString[MAX + 1]; int iFound = -99; //open the file fptr = fopen(fileName, "r"); if (fptr == NULL) { printf("\nNo dictionary file\n"); printf("\n\n\n"); system("pause"); return (0); // just exit the program } /* read the contents of the file */ while( fgets(fileString, MAX, fptr) ) { if( 0 == strcmp(theWord, fileString) ) { iFound = -99; } } fclose(fptr); return(0); }//end of checkwORDiNFile

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  • Generate random number histogram using java

    - by Chewart
    Histogram -------------------------------------------------------- 1 ****(4) 2 ******(6) 3 ***********(11) 4 *****************(17) 5 **************************(26) 6 *************************(25) 7 *******(7) 8 ***(3) 9 (0) 10 *(1) -------------------------------------------------------- basically above is what my prgram needs to do.. im missing something somewhere any help would be great :) import java.util.Random; public class Histogram { /*This is a program to generate random number histogram between 1 and 100 and generate a table */ public static void main(String args[]) { int [] randarray = new int [80]; Random random = new Random(); System.out.println("Histogram"); System.out.println("---------"); int i ; for ( i = 0; i<randarray.length;i++) { int temp = random.nextInt(100); //random numbers up to number value 100 randarray[i] = temp; } int [] histo = new int [10]; for ( i = 0; i<10; i++) { /* %03d\t, this generates the random numbers to three decimal places so the numbers are generated with a full number or number with 00's or one 0*/ if (randarray[i] <= 10) { histo[i] = histo[i] + 1; //System.out.println("*"); } else if ( randarray[i] <= 20){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 30){ histo[i] = histo[i] + 1; } else if ( randarray[i] <= 40){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 50){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=60){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=70){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=80){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=90){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=100){ histo[i] = histo[i] + 1; } switch (randarray[i]) { case 1: System.out.print("0-10 | "); break; case 2: System.out.print("11-20 | "); break; case 3: System.out.print("21-30 | "); break; case 4: System.out.print("31-40 | "); break; case 5: System.out.print("41-50 | "); break; case 6: System.out.print("51-60 | "); break; case 7: System.out.print("61-70 | "); break; case 8: System.out.print("71-80 | "); break; case 9: System.out.print("81-90 | "); break; case 10: System.out.print("91-100 | "); } for (int i = 0; i < 80; i++) { randomNumber = random.nextInt(100) index = (randomNumber - 1) / 2; histo[index]++; } } } }

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  • Proper way to let user enter password for a bash script using only the GUI (with the terminal hidden)

    - by MountainX
    I have made a bash script that uses kdialog exclusively for interacting with the user. It is launched from a ".desktop" file so the user never sees the terminal. It looks 100% like a GUI app (even though it is just a bash script). It runs in KDE only (Kubuntu 12.04). My only problem is handling password input securely and conveniently. I can't find a satisfactory solution. The script was designed to be run as a normal user and to prompt for the password when a sudo command is first needed. In this way, most commands, those not requiring sudo rights, are run as the normal user. What happens (when the script is run from the terminal) is that the user is prompted for their password once and the default sudo timeout allows the script to finish, including any additional sudo commands, without prompting the user again. This is how I want it to work when run behind the GUI too. The main problem is that using kdesudo to launch my script, which is the standard GUI way, means that the entire script is executed by the root user. So file ownerships get assigned to the root user, I can't rely upon ~/ in paths, and many other things are less than ideal. Running the entire script as the root user is just a very unsatisfactory solution and I think it is a bad practice. I appreciate any ideas for letting a user enter the sudo password just once via GUI while not running the whole script as root. Thanks.

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  • Facebook - Isn't this a big vulnerability risk for users? (After Password Change)

    - by Trufa
    I would like to know you opinions as programmers / developers. When I changed my Facebook password yesterday, by mistake I entered the old one and got this: Am I missing something here or this is a big potencial risk for users. In my opinion this is a problem BECAUSE it is FaceBook and is used by, well, everyone and the latest statistics show that 76.3% of the users are idiots [source:me], that is more that 3/4!! All kidding aside: Isn't this useful information for an attacker? It reveals private information about the user! It could help the attacker gain access to another site in which the user used the same password Granted, you should't use use the same password twice (but remember: 76.3%!!!) Doesn't this simply increase the surface area for attackers? It increases the chances of getting useful information at least. In a site like Facebook 1st choice for hackers and (bad) people interested in valued personal information shouldn't anything increasing the chance of a vulnerability be removed? Am I missing something? Am I being paranoid? Will 76.3% of the accounts will be hacked after this post? Thanks in advance!! BTW if you want to try it out, a dummy account: user: [email protected] (old) password: hunter2

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  • Algorithm to generate all possible letter combinations of given string down to 2 letters

    - by Alan
    Algorithm to generate all possible letter combinations of given string down to 2 letters Trying to create an Anagram solver in AS3, such as this one found here: http://homepage.ntlworld.com/adam.bozon/anagramsolver.htm I'm having a problem wrapping my brain around generating all possible letter combinations for the various lengths of strings. If I was only generating permutations for a fixed length, it wouldn't be such a problem for me... but I'm looking to reduce the length of the string and obtain all the possible permutations from the original set of letters for a string with a max length smaller than the original string. For example, say I want a string length of 2, yet I have a 3 letter string of “abc”, the output would be: ab ac ba bc ca cb. Ideally the algorithm would produce a complete list of possible combinations starting with the original string length, down to the smallest string length of 2. I have a feeling there is probably a small recursive algorithm to do this, but can't wrap my brain around it. I'm working in AS3. Thanks!

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  • Disable browser 'Save Password' functionality

    - by mattsmith321
    One of the joys of working for a government healthcare agency is having to deal with all of the paranoia around dealing with PHI (Protected Health Information). Don't get me wrong, I'm all for doing everything possible to protect people's personal information (health, financial, surfing habits, etc.), but sometimes people get a little too jumpy. Case in point: One of our state customers recently found out that the browser provides the handy feature to save your password. We all know that it has been there for a while and is completely optional and is up to the end user to decide whether or not it is a smart decision to use or not. However, there is a bit of an uproar at the moment and we are being demanded to find a way to disable that functionality for our site. Question: Is there a way for a site to tell the browser not to offer to remember passwords? I've been around web development a long time but don't know that I have come across that before. Any help is appreciated. Thanks, Matt

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  • Generate POCO classes in different project to the project with Entity Framework model

    - by Max
    I'm trying to use the Repository Pattern with EF4 using VS2010. To this end I am using POCO code generation by right clicking on the entity model designer and clicking Add code generation item. I then select the POCO template and get my classes. What I would like to be able to do is have my solution structured into separate projects for Entity (POCO) classes and another project for the entity model and repository code. This means that my MVC project could use the POCO classes for strongly typed views etc and not have to know about the repository or have to have a reference to it. To plug it all together I will have another separate project with interfaces and use IoC. Sounds good in my head I just don't know how to generate the classes into their own project! I can copy them and then change the namespaces on them but I wanted to avoid manual work whenever I change the schema in the db and want to update my model. Thanks

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  • Algorithm to generate numerical concept hierarchy

    - by Christophe Herreman
    I have a couple of numerical datasets that I need to create a concept hierarchy for. For now, I have been doing this manually by observing the data (and a corresponding linechart). Based on my intuition, I created some acceptable hierarchies. This seems like a task that can be automated. Does anyone know if there is an algorithm to generate a concept hierarchy for numerical data? To give an example, I have the following dataset: Bangladesh 521 Brazil 8295 Burma 446 China 3259 Congo 2952 Egypt 2162 Ethiopia 333 France 46037 Germany 44729 India 1017 Indonesia 2239 Iran 4600 Italy 38996 Japan 38457 Mexico 10200 Nigeria 1401 Pakistan 1022 Philippines 1845 Russia 11807 South Africa 5685 Thailand 4116 Turkey 10479 UK 43734 US 47440 Vietnam 1042 for which I created the following hierarchy: LOWEST ( < 1000) LOW (1000 - 2500) MEDIUM (2501 - 7500) HIGH (7501 - 30000) HIGHEST ( 30000)

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  • generate only objectLayer of Entity Framework Model by edmgen tool

    - by loviji
    How to generate only objectLayer by edmgen tool, without generating csdl, ssdl and views ? *"%windir%\Microsoft.NET\Framework\v4.0.30319\edmgen.exe" /mode:fullgeneration /c:"Data Source=.\sqlexpress; Initial Catalog=uqs; Integrated Security=SSPI" /project:generateEntityModel /entitycontainer:uqsEntities /namespace:uqsModel /language:CSharp /outobjectlayer:"D:/uqsObjectLayer.cs" * in this script I don't write location to write csdl, ssdl and views , but they are generated in C:\Users\adminUser in windows Vista and objectLayer generated to D:/uqsObjectLayer.cs. If I use /mode:EntityClassGeneration, this option requires the /incsdl argument and either the /project argument or the /outobjectlayer argument. The /language argument is optional. But I don't want use csdl file. As I understand, edmgen.tool can not create objectlayer without csdl file. Now is there alternate way or tool for generating objectlayer from db?

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  • BIC generator - Generate BIC from IBAN bank account number

    - by Tim
    Is there any existing library or script I can use to generate the BIC code from an IBAN bank account number (and other necessary information)? I've searched the web, but found only IBAN generators. Thanks in advance! Edit: Solution for Belgian IBAN's There exists a webservice for Belgian iban numbers, it's very easy to get the bic from the iban bank account number. $client = new SoapClient('http://www.ibanbic.be/IBANBIC.asmx?WSDL'); $bban = $client->getBelgianBBAN(array('Value' => $iban))->getBelgianBBANResult; $bic = $client->BBANtoBIC(array('Value' => $bban))->BBANtoBICResult; I've searched for a dutch webservice aswell, but I couldn't find one. But you can always make one yourself with the data from http://www.betaalvereniging.nl/europees-betalen/sepa-documentatie/bic-afleiden-uit-iban/

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  • Dynamic SQL to generate column names?

    - by Ben McCormack
    I have a query where I'm trying pivot row values into column names and currently I'm using SUM(Case...) As 'ColumnName' statements, like so: SELECT SKU1, SUM(Case When Sku2=157 Then Quantity Else 0 End) As '157', SUM(Case When Sku2=158 Then Quantity Else 0 End) As '158', SUM(Case When Sku2=167 Then Quantity Else 0 End) As '167' FROM OrderDetailDeliveryReview Group By OrderShipToID, DeliveryDate, SKU1 The above query works great and gives me exactly what I need. However, I'm writing out the SUM(Case... statements by hand based on the results of the following query: Select Distinct Sku2 From OrderDetailDeliveryReview Is there a way, using T-SQL inside a stored procedure, that I can dynamically generate the SUM(Case... statements from the Select Distinct Sku2 From OrderDetailDeliveryReview query and then execute the resulting SQL code?

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  • Passing Certificate to Svcutil to generate proxy for OSB Service

    - by webwires
    We are wanting to implement Two-Way SSL security from WCF to OSB Services. We have successfully deployed the certificates so that when you browse to the service with IE you get the appropriate prompt for certificate and then it takes you immediately to the WSDL. But, when you attempt to generate a proxy using svcutil as defined in steps 8 and 9 in this MSDN article. http://msdn.microsoft.com/en-us/library/cc949005.aspx I get the error: A reply message was received for operation 'Get' with action 'http://schemas.xmlsoap.org/ws/2004/09/transfer/Get'. However, your client code requires action 'http://schemas.xmlsoap.org/ws/2004/09/transfer/GetResponse'. The OSB services are set to use Soap 1.2 and the svcutil.exe.config we use is identicle to the article except for the findValue and x509FindType. Instead we used the FindByThumbprint pointing to the "My" store name and "CurrentUser" store location. The cert is there and is the same cert we select from the IE prompt.

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  • Using Dynamics AX's Business Conectors to Generate Sales Orders

    - by FelipeFiali
    So, just like the title says, I need to create an application that gets data from another Database, and shoves it through Dynamics AX's throat. This data comes from a portal, not Enterprise Portal, but a PHP one. It stores some data from the order in a separate database. So as said, I need to 'import' that to AX, creating the sales orders with the data I have from the other database. Also I'd like some references on Business Conector too, does it handle all those RECIDS and references that AX uses for me? Thanks in advance. EDIT: OK, I'm able to insert records in AX's database, theres just one problem. I can't generate the internal ID. Like, the 'AccountNum' field for the CustTable. Is there a way to capture it from business connector?

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  • Using ptrace to generate a stack dump

    - by Gomez
    Hello. I am compiling C++ on *nix and I would like to generate a stack dump a) at an arbitrary point in the program, b) during any signal, particularly during SIGSEGV. Google tells me that ptrace is probably the tool for the job, but I can't find any comprehensible examples of walking the stack. Getting the return address, yeah, but what about the NEXT return address? And what about extracting the symbolic name of the function at that point? Something to do with DWARF? Many thanks if you can tell me where to go from here.

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  • Entitiy Framework: "Update Database from Model" instead of "Generate Database from Model"

    - by David
    Hey everyone, I have created a Entity Framework 4 model with Visual Studio 2010 and generated a database from it. Now I found myself adding new properties (with default values), changing documentation of columns, changing names of columns, changing types of columns several times. All tasks that do not require much "extra work" in order not to be possible to be achieved automatically (in my humble opinion). Everytime I did "Generate Database from Model" and lost of course the table data. Is there a way just to update the database's architecture so to say - leaving the table data untouched? Maybe with some user interaction especially when changing types etc.? Or would this functionality be simply too difficult to be realized to work in a reliable way? Thanks in advance! Cheers, David

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  • Stress Test tool for Password Protected Website

    - by Jason
    We need to run a stress test on a password protection section of a website we host. What tool (paid or free) would be best for us to use for this? We'd like to be able to create several 'scripts' and then have the stress test simulate X number of users. Each script will have us login as a specific user and then click on some links and submit forms to simulate an actual user. Ideally the software would also create some nice data exports/charts. Server is a linux web server, but we could run this on linux or Windows so software that will run on either is fine.

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  • Easier way to generate paths

    - by Horace Loeb
    Songs on Rap Genius have paths like /lyrics/The-notorious-b-i-g-ft-mase-and-puff-daddy/Mo-money-mo-problems which are defined in routes.rb as: map.song '/lyrics/:artist_slug/:title_slug', :controller => 'songs', :action => 'show' When I want to generate such a path, I use song_url(:title_slug => song.title_slug, :artist_slug => song.artist_slug). However, I'd much prefer to be able to type song_url(some_song). Is there a way I can make this happen besides defining a helper like: def x_song_path(song) song_path(:title_slug => song.title_slug, :artist_slug => song.artist_slug) end

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  • generate EF model by System.Diagnostics.Process

    - by loviji
    Hello, after read this article i tried generate EF model by System.Diagnostics.Process: Process myProcess = new Process(); var cs = "Data Source=.\\SQLEXPRESS; Initial Catalog=uqs; Integrated Security=SSPI"; myProcess.StartInfo.FileName = @"C:\Windows\Microsoft.NET\Framework\v3.5\EdmGen.exe"; myProcess.StartInfo.Arguments = "/mode:fullgeneration /c:"+cs+" project:School /entitycontainer:SchoolEntities /namespace:SchoolModel /language:CSharp "; myProcess.Start(); 1.but i haven't get a result, because i can't do well formed arguments string. As I tried, there have many quotes. how to organize argument string? 2.how can i catch if generation completed or have occurred errors?

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  • .net generate proxy classes problem (wsdl/svchost) by soapHeader

    - by Oguzhan
    I'm using a web service from .Net C# client application. My web service has a method which return generic list and in my client application I use Configuration Service Reference to change array to generic list.Its working correctly. But when I add a soapHeader to my web service Configuration Service Reference to change array to generic list its not working and return Array instead of generic list. public class Service1 : System.Web.Services.WebService { public Authentication authentication = new Authentication(); [SoapHeader("authentication")] [WebMethod] public List<string> HelloWorld() { List<string> result = new List<string>(); result.Add("oguzhan"); return result; } } public class Authentication : SoapHeader { public string username; public string password; }

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  • gcc does not generate debugger info when using -g, -ggdb, -g3, or -ggdb3

    - by CJJ
    I'm using GCC 4.4.1 and GDB 7.0-ubuntu on Ubuntu 9.10. However, GCC won't generate debugger info when using any of the following switches: -g, -g3, -ggdb, or -ggdb3. So when I run the program with GDB, its as if there was no debugger information generated. I have created very simple test source files in a new, empty folder. Here is one example: #include <stdlib.h> #include <stdio.h> int main (int argc, char **argv) { char msg[4]; // allocate 4 bytes on the stack strcpy (msg, "hello world"); // overflow printf ("%s\n", msg); return 0; }

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