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• Configure IIS to rewrite IP Address to Site Name

  - by Bath Man

  So i've started my first web site from home, and I'm trying to get it up and running and google crawlable and the like, but I can't seem to figure out how to have my site name returned in the address bar instead of my IP address. I've purchased a domain name for my site on Godaddy and then set it to redirect to my site. When you type in the domain name, you get redirected to http://0.0.0.0/default.aspx (not my real IP obviously), and that stays in the user's address bar. In order to fix that temporarily, I've set up masking on Go Daddy which keeps the URL in the address bar, but just shows my website in a frame. This is fine for users visiting the site, however any kind of automated robot such as GoogleBot cannot discover my content because of the frame. I've looked into ISAPI filters and server-site-rewriting, and the like... but I just can't quite figure out how to do what I need it to do. Any simple suggestions or links would be appreciated.

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• Httpd restart "Address already in use" error

  - by mtndesign

  I have an .rpm, which I created. In its %post part, I do some stuff, and in the end of this script, i call service httpd restart. It gives the following error: + service httpd restart Stopping httpd: [FAILED] Starting httpd: (98)Address already in use: make_sock: could not bind to address [::]:81 (98)Address already in use: make_sock: could not bind to address 0.0.0.0:81 no listening sockets available, shutting down Unable to open logs [FAILED] I got this from the rpm verbose installing (-vv). So I know its about httpd restart itself, nothing else. The according to netstat only one process (httpd) is listening on port 81. $ sudo netstat -nlp | grep 81 tcp 0 0 :::81 :::* LISTEN 29670/httpd I don't understand, why running http FAILS at stop, and FAILS again in start. Any ideas how to solve this?

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• Force an LXC container to use its own IP address

  - by emma sculateur

  Sorry if this question has already been asked. I could not find it, I have this setup : +---------------------------------------------------------------------------------------------+ |HOST | | | | +-------------------------------------------------+ | | | UBUNTU-VM | | | | | | | | +-------------------+ | | | | |UBUNTU-LXC | | +------------------+ | | | | 10.0.0.3/24 | 10.0.0.1/24 | |OTHER VM | | | | | eth0-----lxcbr0----------eth0-----------br0----------eth0 | | | | | | 192.168.100.2/24| 192.168.100.1/24 |192.168.100.3/24 | | | | +-------------------+ | +------------------+ | | +-------------------------------------------------+ | +---------------------------------------------------------------------------------------------+ When I ping 192.168.100.3 from my UBUNTU-LXC, the source IP address is automatically changed to 192.168.100.2 by UBUNTU-VM. It's like having a NAT, whereas I really want my UBUNTU-LXC to talk with it own IP address. Is there any way to do this ? Edit : these info may be relevant : I am using KVM +libvirt to set up my VMs Here is how I create my interface in UBUNTU-VM : <interface type='bridge'> <mac address='52:54:00:cb:aa:74'/> <source bridge='br0'/> <model type='e1000'/> <address type='pci' domain='0x0000' bus='0x00' slot='0x09' function='0x0'/> </interface>

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• How do I implement a Linked List in Java?

  - by Lance Fisher

  What's the best way to make a linked list in Java?

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• Transferring domains when registered owner's email address is incorrect

  - by www.jacob-

  Years ago I registered some domains using a now expired university email address. The other contact details for the registered owner (postal address and phone number) are still correct. In order to change/update the email address, the registrar wants to charge £20 a domain. I would like to transfer the domains away from the current registrar. I can unlock the domains and generate an auth code. However, I cannot authorise the transfer by email as any emails sent to the registered owner's address will bounce. This seems to rule out most registrars I have tried. Are there any ways to transfer these domains without paying the £20 fee to update the registered owner's details?

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• What do you do when you feel you need a variatic list comprehension?

  - by cspyr0

  I would like to make a method where I could give it a list of lengths and it would return all combinations of cartesian coordinates up to those lengths. Easier to explain with an example: cart [2,5] Prelude> [ [0,0],[0,1],[0,2],[0,3],[0,4],[1,0],[1,1],[1,2],[1,3],[1,4] ] cart [2,2,2] Prelude> [ [0,0,0],[0,0,1],[0,1,0],[0,1,1],[1,0,0],[1,0,1],[1,1,0],[1,1,1] ] A simple list comprehension won't work because I don't know how long the lists are going to be. While I love Haskell's simplicity for many problems, this is one that I could write procedurally (in C or something) in 5 minutes whereas Haskell gives me an aneurysm! A solution to this specific problem would help me out a lot; I'd also love to hear about your thought processes when tackling stuff like this.

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• Rewriting to address on postfix local aliases

  - by Wade Williams

  I was running into the common problem that mail for "root" on my system was having $mydomain appended, and because $mydomain is not in $mydestination, the mail was being sent to our central mail server as "root@domain." I cannot add $mydomain to $mydestination, because if I understand it correctly, that would mean all mail addressed to $mydomain would be looked up locally, and if an alias does not exist, delivery would fail. So, I followed these instructions: Delivering some, but not all accounts locally which seems to have resolved the problem. Mail for "root" is now expanded according to /etc/aliases and delivered to the non-local address I desire. The one oddity however is that the "To:" address still reads "root@domain." Is there any way I can get the "To" address to be the one that the alias directed its delivery? So for example, if my alias says that mail for "root" should go to "hostname-admin@domain" is there any way the "To" address can be rewritten as "hostname-admin@domain?" Currently it still shows as "root@domain."

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• How to calculate the occurrences of a list item in Python?

  - by weakish

  Given an item, how to count its occurrences in a list in Python?

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• Assign fixed IP address via DHCP by DNS lookup

  - by Janoszen

  Preface I'm building a virtualization environment with Ubuntu 14.04 and LXC. I don't want to write my own template since the upgrade from 12.04 to 14.04 has shown that backwards compatibility is not guaranteed. Therefore I'm deploying my virtual machines via lxc-create, using the default Ubuntu template. The DNS for the servers is provided by Amazon Route 53, so no local DNS server is needed. I also use Puppet to configure my servers, so I want to keep the manual effort on the deployment minimal. Now, the default Ubuntu template assigns IP addresses via DHCP. Therefore, I need a local DHCP server to assign IP addresses to the nodes, so I can SSH into them and get Puppet running. Since Puppet requires a proper DNS setup, assigning temporary IP addresses is not an option, the client needs to get the right hostname and IP address from the start. Question What DHCP server do I use and how do I get it to assign the IP address based only on the host-name DHCP option by performing a DNS lookup on that very host name? What I've tried I tried to make it work using the ISC DHCP server, however, the manual clearly states: Please be aware that only the dhcp-client-identifier option and the hardware address can be used to match a host declaration, or the host-identifier option parameter for DHCPv6 servers. For example, it is not possible to match a host declaration to a host-name option. This is because the host-name option cannot be guaranteed to be unique for any given client, whereas both the hardware address and dhcp-client-identifier option are at least theoretically guaranteed to be unique to a given client. I also tried to create a class that matches the hostname like this: class "my-client-name" { match if option host-name = "my-client-name"; fixed-address my-client-name.my-domain.com; } Unfortunately the fixed-address option is not allowed in class statements. I can replace it with a 1-size pool, which works as expected: subnet 10.103.0.0 netmask 255.255.0.0 { option routers 10.103.1.1; class "my-client-name" { match if option host-name = "my-client-name"; } pool { allow members of "my-client-name"; range 10.103.1.2 10.103.1.2; } } However, this would require me to administer the IP addresses in two places (Amazon Route53 and the DHCP server), which I would prefer not to do. About security Since this is only used in the bootstrapping phase on an internal network and is then replaced by a static network configuration by Puppet, this shouldn't be an issue from a security standpoint. I am, however, aware that the virtual machine bootstraps with "ubuntu:ubuntu" credentials, which I intend to fix once this is running.

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• Need to set mailx variable to specify the From address

  - by user256817

  Running Oracle Linux 5.8 (which is just re-branded RedHat EL 5.8) I must change the From address. But we have scripts that use mailx which cannot be re-written to use any extra flags, so I'd like to use internal variables instead, which I see on the linux.die.net manpage on mailx is an alternative to the -r flag: -r address Sets the From address. Overrides any from variable specified in environment or startup files. Tilde escapes are disabled. The -r address options are passed to the mail transfer agent unless SMTP is used. This option exists for compatibility only; it is recommended to set the from variable directly instead. (Source: http://linux.die.net/man/1/mailx) How can we use these mailx variables? I tried adding this to /root/.mailrc, no go: set [email protected] I also added that to /etc/mail.rc with no gold. So I am turning to you, SuperUsers...

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• Firefox address bar search like chrome extension? [closed]

  - by Andrew

  Firefox address bar search like chrome extension?

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• ASA firewalls: how does stateful filtering affect my access lists?

  - by Nate

  Ok, so assume that I have an ingress access list that looks like this: access-list outside_in extended ip permit any X.Y.Z.1 eq 25 access-group outside_in in interface outside And I want to do egress filtering. I want to allow inside machines to respond on port 80, and I want to allow ports over 1024. Given that the firewall is statefull, do I need to have the rule access-list inside_in extended ip permit X.Y.Z.1 any eq 25 in my inside_in ACL, or can I get away with just access-list inside_in extended ip permit any any gt 1024 access-group inside_in in interface inside In other words, if I apply an egress access list, do I have to explicitly allow machines to respond to requests allowed by the ingress access list, or does the statefullness of the firewall handle that for me? Thanks!

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• How to remove Excel List Manager?

  - by jdmuys

  I have a spreadsheet with columns set as using the List Manager. I want to remove the list manager. However, the "Remove List Manager" item in the "List" menu of the List toolbar is always disabled. I tried selecting a number of different set of cells in the list, to no avail. "Remove List Manager" stays stubbornly disabled (grayed out). What am I missing? I am using Excel 2008 version 12.1.5.

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• Address already in use - Amazon AWS

  - by Peter

  I've run into a really weird issue. I was debugging a server 500 error script on our EC2 instance and found that we didn't have ioncube loaders installed. So I went to go install them and I created a new file at /etc/php.d/zend.ini and initially I inserted the value of extension=/usr/local/ioncube/ioncube_loader_lin_5.3.so and restarted httpd at which point it told me: The ionCube Loader is a Zend-Engine extension and not a module Please specify the Loader using 'zend_extension' in php.ini PHP Fatal error: Unable to start ionCube Loader module in Unknown on line 0 So I changed the contents of zend.ini to zend_extension=/usr/...etc. Now when I attempt to restart httpd I get this error: Starting httpd: (98)Address already in use: make_sock: could not bind to address [::]:80 (98)Address already in use: make_sock: could not bind to address 0.0.0.0:80 no listening sockets available, shutting down Unable to open logs I can't even run /etc/init.d/httpd stop without it erroring. I've since removed zend.ini to see if that's what caused it and it doesn't seem to be. Any ideas?

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• How to have 2 windows machines on the same network with the same IP address

  - by Stu

  I have a custom made ADC device that is spitting out data by addressed UDP packets. I have that device plugged into a 4 port switch. I have one windows embedded standard 7 machine which is the normal recipient of that data. To be able to receive the data (Using LabVIEW) the windows network adapter IPv4 settings must have a static IP address that corresponds to the UDP packet destination. I would like to add a second windows machine (This one is just regular Win 7 Pro) to simultaneously catch the data, however with all devices connected to the switch, the Win 7 Pro machine recognizes an IP address conflict and will not take the setting for the required static IP address. (The network adaptor settings show that the correct value has been entered but ipconfig shows that it is not actually set.) Neither windows machine needs to transmit network data, they only need to be able to receive the UDP data from the ADC device. Is there any way to disable this IP address conflict detection 'feature' of windows networking?

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• OS X - forwarding external port to local loopback address

  - by Rory Fitzpatrick

  I have an HTTP service bound to port 8000 that I want to access from another computing on the network, but I can't seem to connect using the external IP address of the machine (e.g. 192.168.0.105). I've checked the OS X firewall isn't running, so I'm assuming the issue is the service is only bound to the IP address 127.0.0.1, and not the external IP address. What would be the easiest way to temporarily forward external connections on port 8000 to 127.0.0.1:8000?

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• Why increase pointer by two while finding loop in linked list, why not 3,4,5?

  - by GG

  I had a look at question already which talk about algorithm to find loop in a linked list. I have read Floyd's cycle-finding algorithm solution, mentioned at lot of places that we have to take two pointers. One pointer( slower/tortoise ) is increased by one and other pointer( faster/hare ) is increased by 2. When they are equal we find the loop and if faster pointer reaches null there is no loop in the linked list. Now my question is why we increase faster pointer by 2. Why not something else? Increasing by 2 is necessary or we can increase it by X to get the result. Is it necessary that we will find a loop if we increment faster pointer by 2 or there can be the case where we need to increment by 3 or 5 or x.

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• how to add a color to a line in sharepoint 2007 list that has a specific text ?

  - by gadym

  hello there, I would like to know how to add a color to a line in sharepoint 2007 list if in one field there is a specific text contained ? for example : I have a list that have three fields: list1 1.id 2.name 3.full description now i want to show only the first and the second field to the user. list1 id name 1 abc 2 edv second thing, i want to give a color (let say red) to a row that contains in the hidden field - "full description", a text with the word for example 'color'. I found a javascript code that i can add to the aspx page : (document).ready(function(){ $Text = $("td .ms-vb2:contains('color')"); $Text.parent().css("background-color", "red"); }); but it's only works if the the "full description" is shown. can someone give me an idea ? thanks, gadym

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• What do you do when you feel you need a variadic list comprehension?

  - by cspyr0

  I would like to make a method where I could give it a list of lengths and it would return all combinations of cartesian coordinates up to those lengths. Easier to explain with an example: cart [2,5] Prelude> [ [0,0],[0,1],[0,2],[0,3],[0,4],[1,0],[1,1],[1,2],[1,3],[1,4] ] cart [2,2,2] Prelude> [ [0,0,0],[0,0,1],[0,1,0],[0,1,1],[1,0,0],[1,0,1],[1,1,0],[1,1,1] ] A simple list comprehension won't work because I don't know how long the lists are going to be. While I love Haskell's simplicity for many problems, this is one that I could write procedurally (in C or something) in 5 minutes whereas Haskell gives me an aneurysm! A solution to this specific problem would help me out a lot; I'd also love to hear about your thought processes when tackling stuff like this.

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• question about IP address

  - by baddogai

  i know how IP basically works, and knows that an IP address composed of a network ID portion and a host ID portion, but when I type a IP address ,say "8.8.8.8" into the web browser, i DIDN'T supply any subnet mask information, so how does the browser know where the dividing line is between the network ID and host ID? since 8.8.8.8 may mean 8.8.8.8/8, 8.8.8.8/24 etc. In a nutshell, the IP address I supplied is ambiguous.

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• Routing based on source address in Windows Server 2008 R2

  - by rocku

  I'm implementing a direct routing load balanced solution using Windows Server 2008 R2 as back-end server. I've configured a loopback interface with the external IP address. This works, I am receiving packets with the external IP address and respond to them appropriately. However our infrastructure requires that traffic which is being load-balanced should go through a different gateway then any other traffic originating from the server, ie. updates etc. So basicly I need to route packets based on source address (external IP) to another gateway. The built-in Windows 'route' command allows routing based on destination address only. I've tried setting a default gateway on the loopback interface and mangled with weak/strong host send/receive parameters on the interfaces, however this didn't work. Is there any way around this, possibly using third party tools?

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• Design pattern: polymorphisim for list of objects

  - by ziang

  Suppose I have a class A, and A1, A2 inherits from A. There are 2 functions: List<A1> getListA1(){...} List<A2> getListA2(){...} Now I want to do something similar to both A1 and A2 in another function public void process(List<A>){...} If I want to pass the instance of either ListA1 or ListA2, of course the types doesn't match because the compiler doesn't allow the coercion from List< A1 to List< A. I can't do something like this: List<A1> listA1 = getListA1(); List<A> newList = (List<A>)listA1; //this is not allowed. So what is the best approach to the process()? Is there any way to do it in a universal way rather than write the similar code to both List and List?

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• In C# how can I serialize a List<int> to a byte[] in order to store it in a DB field?

  - by Matt

  In C# how can I serialize a List to a byte[] in order to store it in a DB field? I know how to serialize to a file on the disk, but how do I just serialize to a variable? Here is how I serialized to the disk: List<int> l = IenumerableofInts.ToList(); Stream s = File.OpenWrite("file.bin"); BinaryFormatter bf = new BinaryFormatter(); bf.Serialize(s, lR); s.Close(); I'm sure it's much the same but I just can't wrap my head around it.

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• Add second ip address to an existing SQl 2008 failover clustering

  - by Cédric Boivin

  Hello, I got actually a failover cluster on Windows Server 2008, with sql server 2008. On each server i got two network card, with two different network one are on 10.10.10.x and other are on 192.168.99.x I want my sqlserver cluster listen on the two network. Is it possible and how i add new ip address. When i add a new ip address directly in the cluster, and i do a telnet on the 1433 port with the new cluster ip address it's not working. Thanks

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• make a tree based on the key of each element in list.

  - by cocobear

  >>> s [{'000000': [['apple', 'pear']]}, {'100000': ['good', 'bad']}, {'200000': ['yeah', 'ogg']}, {'300000': [['foo', 'foo']]}, {'310000': [['#'], ['#']]}, {'320000': ['$', ['1']]}, {'321000': [['abc', 'abc']]}, {'322000': [['#'], ['#']]}, {'400000': [['yeah', 'baby']]}] >>> for i in s: ... print i ... {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} i want to make a tree based on the key of each element in list. result in logic will be: {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} perhaps a nested list can implement this or I need a tree type?

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