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  • How to check if FORM Realm authentication failed?

    - by Sergio del Amo
    I use FORM Authentication. <login-config> <auth-method>FORM</auth-method> <form-login-config> <form-login-page>/loginPage.jsp</form-login-page> <form-error-page>/loginPage.jsp</form-error-page> </form-login-config> </login-config> I would like to use the same JSP for my form-login-page and form-error-page, for sake of code reuse. I use a Realm ( org.apache.catalina.realm.JDBCRealm ). In my JSP, I would like to display error messages if the authentication failed. Does Realm store anything in the request, which I could check?

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  • Java: JAX-WS passing authentication info to a call to webservice

    - by agnieszka
    I am using JAX-WS. I am connecting to .NET webservice that requires authentication. I first call the Authentication.asmx so that I can be authenticated. The call returns me a LoginResult that contains a cookie name. Then I call another webservice and I need to somehow pass this cookie or a cookie name. and I don't know how. Here is the code: //first service that returns login information Authentication auth = new Authentication(new URL("the_url"), new QName("http://schemas.microsoft.com/sharepoint/soap/", "Authentication")); LoginResult result = auth.getAuthenticationSoap().login(HTTPuserName, HTTPpassword); //i need to pass cookie or cookie name or any other login information to call to this service Copy copyService = new Copy(new URL("service_url"), new QName("http://schemas.microsoft.com/sharepoint/soap/", "Copy")); BindingProvider p = (BindingProvider) copyService.getCopySoap();

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  • After extending the User model in django, how do you create a ModelForm?

    - by mlissner
    I extended the User model in django to include several other variables, such as location, and employer. Now I'm trying to create a form that has the following fields: First name (from User) Last name (from User) Location (from UserProfile, which extends User via a foreign key) Employer (also from UserProfile) I have created a modelform: from django.forms import ModelForm from django.contrib import auth from alert.userHandling.models import UserProfile class ProfileForm(ModelForm): class Meta: # model = auth.models.User # this gives me the User fields model = UserProfile # this gives me the UserProfile fields So, my question is, how can I create a ModelForm that has access to all of the fields, whether they are from the User model or the UserProfile model? Hope this makes sense. I'll be happy to clarify if there are any questions.

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  • creating my own context processor in django

    - by dotty
    Hay, I have come to a point where i need to pass certain variables to all my views (mostly custom authentication type variables). I was told writing my own context processor was the best way to do this, but i am having some issues. My settings file looks like this TEMPLATE_CONTEXT_PROCESSORS = ( "django.contrib.auth.context_processors.auth", "django.core.context_processors.debug", "django.core.context_processors.i18n", "django.core.context_processors.media", "django.contrib.messages.context_processors.messages", "sandbox.context_processors.say_hello", ) As you can see i have a module called 'context_processors' and a function within that called 'say_hello'. This looks like def say_hello(request): return { 'say_hello':"Hello", } Am i right to assume i can now do this within my views {{ say_hello }} because it doesn't return anything.

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  • rubyCAS-client serviceValidation uri questions.

    - by ted-gehling
    php code works with this url but the rubyCAS-Client gem's `validate_service_ticket()' seems to call an SSL Validation on this url which returns an error message. 'OpenSSL::SSL::SSLError in CassersController#index' ||'SSL_connect returned=1 errno=0 state=SSLv3 read server certificate B: certificate verify failed' ---enviroment.rb--- require 'casclient' require 'casclient/frameworks/rails/filter' CASClient::Frameworks::Rails::Filter.configure( :cas_base_url => "https://auth.foo.com", :validate_url => "https://auth.foo.com/serviceValidate" ) ---casser_controller.rb--- class CassersController < ApplicationController require 'casclient' require 'casclient/frameworks/rails/filter' before_filter CASClient::Frameworks::Rails::Filter def index @username = session[:cas_user] end end Possibly just another requirement I need to make or a config file that needs changed, but any help about this error would be appreciated.

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  • [Gdata] GetAuthSubToken returns None

    - by Matt
    Hey guys, I am a little lost on how to get the auth token. Here is the code I am using on the return from authorizing my app: client = gdata.service.GDataService() gdata.alt.appengine.run_on_appengine(client) sessionToken = gdata.auth.extract_auth_sub_token_from_url(self.request.uri) client.UpgradeToSessionToken(sessionToken) logging.info(client.GetAuthSubToken()) what gets logged is "None" so that does seem right :-( if I use this: temp = client.upgrade_to_session_token(sessionToken) logging.info(dump(temp)) I get this: {'scopes': ['http://www.google.com/calendar/feeds/'], 'auth_header': 'AuthSub token=CNKe7drpFRDzp8uVARjD-s-wAg'} so I can see that I am getting a AuthSub Token and I guess I could just parse that and grab the token but that doesn't seem like the way things should work. If I try to use AuthSubTokenInfo I get this: Traceback (most recent call last): File "/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/google/appengine/ext/webapp/__init__.py", line 507, in __call__ handler.get(*groups) File "controllers/indexController.py", line 47, in get logging.info(client.AuthSubTokenInfo()) File "/Users/matthusby/Dropbox/appengine/projects/FBCal/gdata/service.py", line 938, in AuthSubTokenInfo token = self.token_store.find_token(scopes[0]) TypeError: 'NoneType' object is unsubscriptable so it looks like my token_store is not getting filled in correctly, is that something I should be doing? Also I am using gdata 2.0.9 Thanks Matt

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  • What is resource-ref in web.xml used for?

    - by Denise
    Hi everyone, I'm just wondering when/why you would define a resource-ref element in your web.xml file? I would have thought that it would be defined in your web/app server using JNDI and then look up the JNDI reference in your Java code? The resource-ref definition seems a bit redundant to me and I can't think of when it might be useful. Example: <resource-ref> <description>Primary database</description> <res-ref-name>jdbc/primaryDB</res-ref-name> <res-type>javax.sql.DataSource</res-type> <res-auth>CONTAINER</res-auth> </resource-ref> Thanks!

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  • How do I use Zend Cache on this particular problem

    - by davykiash
    I have an action that renders two different view scripts based on whether the user is logged in or not. class IndexController extends Zend_Controller_Action { .... public function indexAction() { $auth = Zend_Auth::getInstance(); if($auth->hasIdentity()) { $this->render('indexregistered'); return; } else { $this->render('indexpublic'); return; } } .... } I have seen quite some useful examples on how to use the Zend Cache and they seem to be based on the fact that the action renders one particular script. What am really looking at is the best approach to cache the the indexpublic script does get quite some hits and I would live to avoid the Zend MVC overhead if possible.

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  • JDBC CommunicationsException with MySQL Database

    - by Dominik Siebel
    I'm having a little trouble with my MySQL- Connection- Pooling. This is the case: Different jobs are scheduled via Quartz. All jobs connect to different databases which works fine the whole day while the nightly scheduled jobs fail with a CommunicationsException... Quartz-Jobs: Job1 runs 0 0 6,10,14,18 * * ? Job2 runs 0 30 10,18 * * ? Job3 runs 0 0 5 * * ? As you can see the last job runs at 18 taking about 1 hour to run. The first job at 5am is the one that fails. I already tried all kinds of parameter-combinations in my resource config this is the one I am running right now: <!-- Database 1 (MySQL) --> <Resource auth="Container" driverClassName="com.mysql.jdbc.Driver" maxActive="100" maxIdle="30" maxWait="10000" removeAbandoned="true" removeAbandonedTimeout="60" logAbandoned="true" type="javax.sql.DataSource" name="jdbc/appDbProd" username="****" password="****" url="jdbc:mysql://127.0.0.1:3306/appDbProd?autoReconnect=true&amp;useUnicode=true&amp;characterEncoding=UTF-8" testWhileIdle="true" testOnBorrow="true" testOnReturn="true" validationQuery="SELECT 1" timeBetweenEvictionRunsMillis="1800000" /> <!-- Database 2 (MySQL) --> <Resource auth="Container" driverClassName="com.mysql.jdbc.Driver" maxActive="100" maxIdle="30" maxWait="10000" removeAbandoned="true" removeAbandonedTimeout="60" logAbandoned="true" type="javax.sql.DataSource" name="jdbc/prodDbCopy" username="****" password="****" url="jdbc:mysql://127.0.0.1:3306/prodDbCopy?autoReconnect=true&amp;useUnicode=true&amp;characterEncoding=UTF-8" testWhileIdle="true" testOnBorrow="true" testOnReturn="true" validationQuery="SELECT 1" timeBetweenEvictionRunsMillis="1800000" /> <!-- Database 3 (MSSQL)--> <Resource auth="Container" driverClassName="net.sourceforge.jtds.jdbc.Driver" maxActive="30" maxIdle="30" maxWait="100" removeAbandoned="true" removeAbandonedTimeout="60" logAbandoned="true" name="jdbc/catalogDb" username="****" password="****" type="javax.sql.DataSource" url="jdbc:jtds:sqlserver://127.0.0.1:1433;databaseName=catalog;useNdTLMv2=false" testWhileIdle="true" testOnBorrow="true" testOnReturn="true" validationQuery="SELECT 1" timeBetweenEvictionRunsMillis="1800000" /> For obvious reasons I changed IPs, Usernames and Passwords but they can be assumed to be correct, seeing that the application runs successfully the whole day. The most annoying thing is: The first job that runs first queries Database2 successfully but fails to query Database1 for some reason (CommunicationsException): Caused by: com.mysql.jdbc.exceptions.jdbc4.CommunicationsException: The last packet successfully received from the server was 39,376,539 milliseconds ago. The last packet sent successfully to the server was 39,376,539 milliseconds ago. is longer than the server configured value of 'wait_timeout'. You should consider either expiring and/or testing connection validity before use in your application, increasing the server configured values for client timeouts, or using the Connector/J connection property 'autoReconnect=true' to avoid this problem. Any ideas? Thanks!

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  • gae error when i login.

    - by zjm1126
    i am using http://code.google.com/p/gaema/source/browse/#hg/demos/webapp, and this is my traceback: Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 510, in __call__ handler.get(*groups) File "D:\gaema\demos\webapp\main.py", line 31, in get google_auth.get_authenticated_user(self._on_auth) File "D:\gaema\demos\webapp\gaema\auth.py", line 641, in get_authenticated_user OpenIdMixin.get_authenticated_user(self, callback) File "D:\gaema\demos\webapp\gaema\auth.py", line 83, in get_authenticated_user url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) File "D:\Python25\lib\urllib.py", line 1250, in urlencode v = quote_plus(str(v)) UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-1: ordinal not in range(128) how to do this thanks ??????????????? ???????? ??????????? ?????????????? ???????

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  • mercurial: less duplication in hgrc file

    - by zaharpopov
    Hi there. I have using Hg for some projects on my google code hosting. For each projects I set in [auth] section of .hgrc the username/password to push without every asking for password. But it is lots of duplication like: [auth] proj1.prefix = ... 111 proj1.username = google code username proj1.password = google code password proj2.prefix = ... 222 proj2.username = google code username proj2.password = google code password Can this somehow be doing with less duplications? Maybe set variable in hgrc and refer to it from all username/password lines? Thanks in advance for your help

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  • Zend_Test: No default module defined for this application

    - by jiewmeng
    UPDATE 23 Dec I had the problem where Zend Framework complains about "No default module defined for this application". I didn't use Modules and the main app works fine. I finally solved the problem with the help from weierophinney.net Your bootstrap needs to minimally set the controller directory -- do a call to $this->frontController->addControllerDirectory(...) in your appBootstrap() method. I didn't in my example, as my Initialization plugin does that sort of thing for me. The problem is solved by adding the below to setUp() $this->getFrontController()->setControllerDirectory(APPLICATION_PATH . '/controllers'); But now, I have afew other questions: 1. Why does that value not get initialized by application.ini? In application.ini, I have [production] resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" [testing : production] // didn't change anything regarding modules nor controllers 2. I tried setting the controllerDirectory in bootstrap.php of my unit test, but it does not work $front = Zend_Controller_Front::getInstance(); $front->setControllerDirectory(APPLICATION_PATH . '/controllers'); The only way that works is using setUp(). Why is that? END UPDATE 23 Dec I am getting the above error when unit testing my controller plugins. I am not using any modules. in my bootstrap.php for unit testing, I even tried adding $front = Zend_Controller_Front::getInstance(); $front->setDefaultModule('default'); But it still does not work. Anyways my bootstrap.php looks like this UPDATE: the error looks something like There were 2 errors: 1) Application_Controller_Plugin_AclTest::testAccessToUnauthorizedPageRedirectsToLogin Zend_Controller_Exception: No default module defined for this application D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:391 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:204 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:244 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Front.php:954 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Test\PHPUnit\ControllerTestCase.php:205 D:\Projects\Tickle\tests\application\controllers\plugins\aclTest.php:6 2) Application_Controller_Plugin_AclTest::testAccessToAllowedPageWorks Zend_Controller_Exception: No default module defined for this application D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:391 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:204 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:244 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Front.php:954 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Test\PHPUnit\ControllerTestCase.php:205 D:\Projects\Tickle\tests\application\controllers\plugins\aclTest.php:16 UPDATE I tried adding public function setUp() { $front = Zend_Controller_Front::getInstance(); $front->setDefaultModule('default'); } then 1 part works. public function testAccessToUnauthorizedPageRedirectsToLogin() { // this fails with exception "Zend_Controller_Exception: No default module defined for this application" $this->dispatch('/projects'); $this->assertController('auth'); $this->assertAction('login'); } public function testAccessToAllowedPageWorks() { // this passes $auth = Zend_Auth::getInstance(); $authAdapter = new Application_Auth_Adapter('jiewmeng', 'password'); $auth->authenticate($authAdapter); $this->dispatch('/projects'); $this->assertController('projects'); $this->assertAction('index'); }

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  • Passing parameters thru Ruby's OAuth

    - by JP
    I'm using Mirven's Twitter OAuth Sinatra example and trying to figure out how I can send a 'next page' parameter with the Oauth request: ie. The user attempts to visit /edit/profile which requires a login so I redirect to /request which deals with login via twitter - I now want to be able to redirect the user to the address they were originally looking for if they log in successfully. I thought I could do this in the .get_request_token line with this code: @request_token = @consumer.get_request_token({:oauth_callback => "http://#{request.host}/auth"},{:next => params['next'] || '/'}) But params has no additional items in the /auth handler. I'm new to OAuth, how would I go about doing this?

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  • Admin section in CakePHP

    - by Nicklas Ansman
    I'm having a hard time understanding how the CakePHP admin system works. Should all controllers who has an action which requires login include AuthComponent or just the one who handles the login/logout? Let's say I want to protect the add action of a controller. First I create admin_add() in the controller and then in the beforeFilter() method I check if $this->Session->check('Auth.User') is set a redirect based on this? Turns out it was better to just controll this with $this->Auth->allow() What is the easiest way to return to the URL the user was trying to access? Is there a better way than setting a session variable? Turns out it does this automagically :) If someone has a good tutorial for this I would happily read it :) I've already read this tutorial but I found it to be a little to basic and the CakePHP-docs are not that great on this topic either.

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  • Problem With View Helpers

    - by Richard Knop
    I wrote few custom view helpers but I have a little trouble using them. If I add the helper path in controller action like this: public function fooAction() { $this->view->addHelperPath('My/View/Helper', 'My_View_Helper'); } Then I can use the views from that path without a problem. But when I add the path in the bootstrap file like this: protected function _initView() { $this->view = new Zend_View(); $this->view->doctype('XHTML1_STRICT'); $this->view->headScript()->appendFile($this->view->baseUrl() . '/js/jquery-ui/jquery.js'); $this->view->headMeta()->appendHttpEquiv('Content-Type', 'text/html; charset=UTF-8'); $this->view->headMeta()->appendHttpEquiv('Content-Style-Type', 'text/css'); $this->view->headMeta()->appendHttpEquiv('Content-Language', 'sk'); $this->view->headLink()->appendStylesheet($this->view->baseUrl() . '/css/reset.css'); $this->view->addHelperPath('My/View/Helper', 'My_View_Helper'); } Then the view helpers don't work. Why is that? It's too troublesome to add the path in every controller action. Here is an example of how my custom view helpers look: class My_View_Helper_FooBar { public function fooBar() { return 'hello world'; } } I use them like this in views: <?php echo $this->fooBar(); ?> Should I post my whole bootstrap file? UPDATE: Added complete bootstrap file just in case: class Bootstrap extends Zend_Application_Bootstrap_Bootstrap { protected function _initFrontController() { $this->frontController = Zend_Controller_Front::getInstance(); $this->frontController->addModuleDirectory(APPLICATION_PATH . '/modules'); Zend_Controller_Action_HelperBroker::addPath( 'My/Controller/Action/Helper', 'My_Controller_Action_Helper' ); $this->frontController->registerPlugin(new My_Controller_Plugin_Auth()); $this->frontController->setBaseUrl('/'); } protected function _initView() { $this->view = new Zend_View(); $this->view->doctype('XHTML1_STRICT'); $this->view->headScript()->appendFile($this->view->baseUrl() . '/js/jquery-ui/jquery.js'); $this->view->headMeta()->appendHttpEquiv('Content-Type', 'text/html; charset=UTF-8'); $this->view->headMeta()->appendHttpEquiv('Content-Style-Type', 'text/css'); $this->view->headMeta()->appendHttpEquiv('Content-Language', 'sk'); $this->view->headLink()->appendStylesheet($this->view->baseUrl() . '/css/reset.css'); $this->view->addHelperPath('My/View/Helper', 'My_View_Helper'); } protected function _initDb() { $this->configuration = new Zend_Config_Ini(APPLICATION_PATH . '/configs/application.ini', APPLICATION_ENVIRONMENT); $this->dbAdapter = Zend_Db::factory($this->configuration->database); Zend_Db_Table_Abstract::setDefaultAdapter($this->dbAdapter); $stmt = new Zend_Db_Statement_Pdo($this->dbAdapter, "SET NAMES 'utf8'"); $stmt->execute(); } protected function _initAuth() { $this->auth = Zend_Auth::getInstance(); } protected function _initCache() { $frontend= array('lifetime' => 7200, 'automatic_serialization' => true); $backend= array('cache_dir' => 'cache'); $this->cache = Zend_Cache::factory('core', 'File', $frontend, $backend); } public function _initTranslate() { $this->translate = new Zend_Translate('Array', BASE_PATH . '/languages/Slovak.php', 'sk_SK'); $this->translate->setLocale('sk_SK'); } protected function _initRegistry() { $this->registry = Zend_Registry::getInstance(); $this->registry->configuration = $this->configuration; $this->registry->dbAdapter = $this->dbAdapter; $this->registry->auth = $this->auth; $this->registry->cache = $this->cache; $this->registry->Zend_Translate = $this->translate; } protected function _initUnset() { unset($this->frontController, $this->view, $this->configuration, $this->dbAdapter, $this->auth, $this->cache, $this->translate, $this->registry); } protected function _initGetRidOfMagicQuotes() { if (get_magic_quotes_gpc()) { function stripslashes_deep($value) { $value = is_array($value) ? array_map('stripslashes_deep', $value) : stripslashes($value); return $value; } $_POST = array_map('stripslashes_deep', $_POST); $_GET = array_map('stripslashes_deep', $_GET); $_COOKIE = array_map('stripslashes_deep', $_COOKIE); $_REQUEST = array_map('stripslashes_deep', $_REQUEST); } } public function run() { $frontController = Zend_Controller_Front::getInstance(); $frontController->dispatch(); } }

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  • Trouble sending html in email with Pony gem

    - by Gearóid
    Hi, I've found this gem to be a great and easy way to send mail but I can't seem to send any html in it. If I write the following: Pony.mail( :to => message[:to], :from => @account[:from], :subject => message[:subject], :content_type => 'text/html', :html_body => "<h1>hey there!</h1>", :via => :smtp, :smtp => { :host => MY_HOST, :port => PORT, :auth => AUTH, :user => MY_USER, :password => MY_PASSWORD, :tls => true } ) The code above send a mail but the message appears to be empty in gmail. Any help would be greatly appreciated on this. Thanks.

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  • Stream post URL security and wall post links

    - by Jeff Lee
    Our app's mobile client can create wall post links to our app's web-facing pages. Since this happens in the context of a mobile app, we do this on behalf of our user using the Graph API's feed/message endpoint. I noticed that the links showing up in the wall posts are being routed through our app's auth dialog, which is NOT what we want. We just want transparent links, without forcing the client to auth our app, similar to what happens when you share to FB in Path. I went ahead and disabled the "Stream post URL option" several hours ago, but we still seem to be getting the re-routed links for wall posts. The target URLs for these links are within the domain we've registered for our Facebook app. Is there anything else I need to do fix this?

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  • NHibernate and SetSessionAuth audit columns

    - by user86431
    We have audit columns set by triggers. For obscure security reasons predating my tenure and out of my control, we log in with a generic user, and do a 'set session authorization' to change the user to the db user of the user who is logged in. When we converted to NHibernate, it creates a whole new session and jacks everything up when we try to do a set session auth, so we turned the set session auth off... Now we are trying to find out a way to get NHibernate to let us do 'set session authorization' without recycling the session on us, so we can use our existing trigger based audit column stuff with both legacy apps, and our new NHibernate apps. It's not a ideal soloution, or the best way to do it even, but is it possible? I was hoping there was a alternate interface that allowed this kind of access. Does anyone know how to do it, or can you point me towards and good hints? Thanks, Eric-

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  • Enable Query Strings in Code Igniter

    - by tarnfeld
    Hey, I am trying to implement Twitter's OAuth into my Code Igniter web application at which the callback URL is /auth/ so once you have authenticated with Twitter you are taken to /auth/?oauth_token=SOME-TOKEN. I want to keep the nice clean URL's the framework provides using the /controller/method/ style of URL but I want to enable query strings as well, there will only ever be one name of the data oauth_token so it's ok if it has to be hard coded. Any ideas? I have tried tons of the things people are saying to do, but none work :( PS: I'm using the .htaccess method of URL rewriting.

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  • DotNetOpenAuth for previously authorized site

    - by Burke Holland
    I've had great luck with DotNetOpenAuth to do 3 legged authorization. Currently, I am connecting and pulling in some Google data. My question is that apparently, if you have already auth'd my web application to your Google account, when I call var accessTokenResponse = google.ProcessUserAuthorization(); It basically does nothing. How do I get the token for an account that has already auth'd my application? I see no callback of any kind. I'm chocking this up to my ignorance about OAuth in general.

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  • Google app engine error when I login.

    - by zjm1126
    i am using http://code.google.com/p/gaema/source/browse/#hg/demos/webapp, and this is my traceback: Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 510, in __call__ handler.get(*groups) File "D:\gaema\demos\webapp\main.py", line 31, in get google_auth.get_authenticated_user(self._on_auth) File "D:\gaema\demos\webapp\gaema\auth.py", line 641, in get_authenticated_user OpenIdMixin.get_authenticated_user(self, callback) File "D:\gaema\demos\webapp\gaema\auth.py", line 83, in get_authenticated_user url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) File "D:\Python25\lib\urllib.py", line 1250, in urlencode v = quote_plus(str(v)) UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-1: ordinal not in range(128) how to do this thanks updated i change the code from args = dict((k, v[-1]) for k, v in self.request.arguments.iteritems()) args["openid.mode"] = u"check_authentication" url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) to args = dict((k, v[-1].encode('utf-8')) for k, v in self.request.arguments.iteritems()) args["openid.mode"] = u"check_authentication" url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) but also error.

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  • How to write a custom (odd) authentication plugins for Wordpress, Joomla and MediaWiki

    - by Bart van Heukelom
    On our network (a group of related websites - not a LAN) we have a common authentication system which works like this: On a network site ("consumer") the user clicks on a login link This redirects the user to a login page on our auth system ("RAS"). Upon successful login the user is directed back to the consumer site. Extra data is passed in the query string. This extra data does not include any information about the user yet. The consumer site's backend contacts RAS to get the information about the logged in user. So as you can see, the consumer site knows nothing about the authentication method. It doesn't know if it's by username/password, fingerprint, smartcard, or winning a game of poker. This is the main problem I'm encountering when trying to find out how I could write custom authentication plugins for these packages, acting as consumer sites: Wordpress Joomla MediaWiki For example Joomla offers a pretty simple auth plugin system, but it depends on a username/password entered on the Joomla site. Any hints on where to start?

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  • Telnet SMTP with expect or shell script

    - by Fendrix
    Want to build up a Auth Smtp Connection with expect script... just to test I wanted to get ehlo parameters but expect is not working like this #!/usr/bin/expect set timeout -1 set smtp [lindex $argv 0] set port [lindex $argv 1] spawn telnet $smtp $port expect "[2]{2,}[0]{1,}" send "ehlo" I expect the code 220 to come from mailserver to continue to send ehlo ... just like ..../...:telnet smtp.mail.yahoo.de 25 Trying 77.238.184.85... Connected to smtp2-de.mail.vip.ukl.yahoo.com. Escape character is '^]'. 220 smtp116.mail.ukl.yahoo.com ESMTP ehlo 250-smtp116.mail.ukl.yahoo.com 250-AUTH LOGIN PLAIN XYMCOOKIE 250-PIPELINING 250-SIZE 41697280 250 8BITMIME

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  • django + xmppy: send a message to two recipients

    - by Agrajag
    I'm trying to use xmpppy for sending jabber-messages from a django-website. This works entirely fine. However, the message only gets sent to the -first- of the recipients in the list. This happens when I run the following function from django, and also if I run it from an interactive python-shell. The weird part though, is that if I extract the -body- of the function and run that interactively, then all the recipients (there's just 2 at the moment) get the message. Also, I do know that the inner for-loop gets run the correct count times (2), because the print-statement does run twice, and return two different message-ids. The function looks like this: def hello_jabber(request, text): jid=xmpp.protocol.JID(settings.JABBER_ID) cl=xmpp.Client(jid.getDomain(),debug=[]) con=cl.connect() auth=cl.auth(jid.getNode(),settings.JABBER_PW,resource=jid.getResource()) for friend in settings.JABBER_FRIENDS: id=cl.send(xmpp.protocol.Message(friend,friend + ' is awesome:' + text)) print 'sent message with id ' + str(id) cl.disconnect() return render_to_response('jabber/sent.htm', locals())

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  • Cannot resolve view when view is in subdirectory

    - by devzero
    We have a MVC 2.0 / c# 4.0 application that we develop visual studio. We have a part of the site (admin) that we have put in it's own sub directory and with its own routing rules: routes.Add("DomainRoute", new DomainRoute( ConfigurationManager.AppSettings["adminDomain"], // Domain with parameters "{controller}/{action}/{id}", // URL with parameters new { controller = "AdminPage", action = "Admin", id = "", isAdmin = true } We have all the views for the admin site inside an admin sub folder so that you get paths like: \views\admin\auth\login.aspx In the \controllers\admin\authController.aspx file I have a function called login: public ActionResult Login() { return View(); } This works just as it should, ie if i go admin.localhost\auth\login I go to the login page. But if I do a right click in visual studio and "go to view" i get an error "unable to go to matching view". Is there anyway to solve this?

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