Search Results

Search found 26438 results on 1058 pages for 'calendar table'.

Page 704/1058 | < Previous Page | 700 701 702 703 704 705 706 707 708 709 710 711  | Next Page >

  • Timeout on Large mySQL Query

    - by Bob Stewart
    I have this query: $theQuery = mysql_query("SELECT phrase, date from wordList WHERE group='nouns'"); while($getWords=mysql_fetch_array($theQuery)) { echo "$getWords[phrase] created on $getWords[date]<br>"; } The data table "wordList" contains 75,000 records in the group "nouns" and every time I load the code I am returned an error. Help!

    Read the article

  • question with its query

    - by user329820
    Hi this is my homework and the question is this: List the average balance of customers by city and short zip code (the first five digits of thezip code). Only include customers residing in Washington State (‘WA’). also the Customer table has 5 columns(Name,Family,CustZip,CustCity,CustAVGBal) I wrote the query like below is this correct? SELECT CustCity,LEFT(CustZip,5) AS NewCustZip,CustAVGBal FROM Customer WHERE CustCity = 'WA' THANKS!!

    Read the article

  • SQL Error with Order By in Subquery

    - by cagin
    Hi all. i m working sql server 2005. My query is: SELECT ( SELECT COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4 GROUP BY refKlinik_id ORDER BY refKlinik_id) as dorduncuay And the error: The ORDER BY clause is invalid in views, inline functions, derived tables, subqueries, and common table expressions, unless TOP or FOR XML is also specified. How can i use order by in a sub query?

    Read the article

  • mysql procedure to update numeric reference in previous rows when one is updated

    - by markcial
    There's a table like this one ______________________ | id | title | order | |----------------------| | 1 | test1 | 1 | |-----|--------|-------| | 2 | test2 | 2 | |-----|--------|-------| | 3 | test3 | 3 | |-----|--------|-------| | 4 | test4 | 4 | '----------------------' when i introduce in my mysql shell a single update to a row $sql UPDATE `table` SET order=1 WHERE id=3; And then procedure or method resamples order column in the before update lower values to get its order renewed like this ______________________ | id | title | order | |----------------------| | 1 | test1 | 2 | |-----|--------|-------| | 2 | test2 | 3 | |-----|--------|-------| | 3 | test3 | 1 | |-----|--------|-------| | 4 | test4 | 4 | '----------------------' Any help would be appreciated, thanks!

    Read the article

  • need help on my query.

    - by Dharmendra
    i have one table : nobel(yr, subject, winner) and i have this query : In which years was the Physics prize awarded but no Chemistry prize. this is what i tried : select distinct yr from nobel where subject='physics' and subject!='chemistry' but is not working where i am going wrong. see, i am not here to make my homework from someone. i am here to learn something. so, please give me suggetion.

    Read the article

  • MySQL: fetching a null or an empty string

    - by Oden
    Hey, I know whats the difference between a NULL value and an empty string ("") value, but if I want to get a value by using the OR keyword, I get no result for a NULL value The table i want to query looks like this: titles_and_tags +----+----------+------+ | id | title | tag | +----+----------+------+ | 1 | title1 | NULL | | 2 | title2 | tag1 | | 3 | title3 | tag2 | +----+----------+------+ The query i use looks like this: select * from `titles_and_tags` WHERE `title` LIKE "title" AND `tag` = "tag1" OR `tag` IS NULL So i want to get here a rows (id: 1,2), BUT this results 0 rows. What have i done wrong?

    Read the article

  • Datable.Select sort expression

    - by xyz
    Hi, I have datatable with column name tag and 100 rows of data.I need to filter this table with tag starting with "UNKNOWN". What should my sortexpression for datatable.select be ? I'm trying the following. Datarow[] abc = null; abc = dtTagList.Select(string.format("tag='{0}'","UNKNOWN")) How can I achieve tag startswith 'UNKNOWN' in the above code ?

    Read the article

  • SQL: Find the max record per group

    - by user319088
    I have one table, which has three fields and data. Name , Top , Total cat , 1 , 10 dog , 2 , 7 cat , 3 , 20 horse , 4 , 4 cat , 5 , 10 dog , 6 , 9 I want to select the record which has highest value of Total for each Name, so my result should be like this: Name , Top , Total cat , 3 , 20 horse , 4 , 4 Dog , 6 , 9 I tried group by name order by total, but it give top most record of group by result. Can anyone guide me, please?

    Read the article

  • grails find first

    - by srinath
    I know this is simple question but taking more time How to find first record from table in grails . I need to get only the first record with out knowing the id number . Is there any method like find :first in grails ? thanks in advance .

    Read the article

  • mysql count rows and grop them by month

    - by user2661296
    I have a table called cc_calls and there I have many call records I want to count them and group them in months I have a timestamp called starttime and I can use that row to extract the month, also limit the count for 12 months the results should be like: Month Count January 768768 February 876786 March 987979 April 765765 May 898797 June 876876 July 786575 August 765765 September 689787 October 765879 November 897989 December 876876 Can anyone guide me or show me the mysql query that I need to get this result.

    Read the article

  • Error in creating alias in formula tag

    - by Senthilnathan
    Hi all I have a sql query in formula tag inside property tag. In that query i am creating alias name but the hibernate appends table name and throwing me error. select sum(e.salary) as sal from employee e but hibernate changes to select sum(e.salary) as employee.sal from employee e how to avoid this .... it should recognise as sal inside of employee.sal !!!

    Read the article

  • sql count conditions

    - by user1311030
    there! I have this question, hope you guys can help me out. So i have this table with two fields: type and authorization in type i have 2 different values: Raid and Hold in authorization i have 2 different values: Accepted or Denied I need to make a view that returns values like this: TYPE:RAID ACCEPTED:5 DENIED:7 Basically i need to know how many of the values in TYPE are Raid, and then how many of them are Accepted and Denied. Thank you in advance!!

    Read the article

  • Ruby/Rails - Add records to an object with each loop iteration / Object vs Arrays

    - by ChrisWesAllen
    I'm trying to figure out how to add records to an existing object for each iteration of a loop. I'm having a hard time discovering the difference between an object and an array. I have this @events = Event.find(1) @loops = Choices.find(:all, :limit => 5) #so loop for 5 instances of choice model for loop in @loops @events = Event.find(:all,:conditions => ["event.id = ?", loop.event_id ]) end I'm trying to add a new events to the existing @events object based on the id of whatever the loop variable is. But the ( = ) operator just creates a new instance of the @events object. I tried ( += ) and ( << ) as operators but got the error "You have a nil object when you didn't expect it! You might have expected an instance of Array. The error occurred while evaluating nil" I tried created an array events = [] events << Event.find(1) @loops = Choices.find(:all, :limit => 5) #so loop for 5 instances of choice model for loop in @loops events << Event.find(:all,:conditions => ["event.id = ?", loop.event_id ]) end But I dont know how to call that arrays attributes within the view With objects I was able do create a loop within the view and call all the attributes of that object as well... <table> <% for event in @events %> <tr> <td><%= link_to event.title, event %></td> <td><%= event.start_date %></td> <td><%= event.price %></td> </tr> <% end %> </table> How could i do this with an array set? So the questions are 1) Whats the difference between arrays and objects? 2) Is there a way to add into the existing object for each iteration? 3) If I use an array, is there a way to call the attributes for each array record within the view?

    Read the article

  • Concatinating Multiple Rows in SQL

    - by Dave C
    Hello, I have a table structure that looks like this: ID String ----------- 1 A 1 Test 1 String 2 Dear 2 Person I need the final output to look like this: ID FullString -------------------- 1 A, Test, String 2 Dear, Person I am really lost on how to approach this... I looked on a couple examples online but they seemed to be VERY complex... this seems like it should be a real easy problem to solve in sql. Thank you for all assistance!

    Read the article

  • Robust Large File Transfer with WCF

    - by Sharov
    I want to transfer big files (1GB) over unreliable transport channels. When connection is interrupted, I don't want start file transfering from the begining. I can partially store it in a temp table and store last readed position, so when connection is reestablished I can request continue uploading of file from this position. Is there any best-practice for such kind of things. I'm currently use chunking channel.

    Read the article

  • Finding contained bordered regions from Excel imports.

    - by dmaruca
    I am importing massive amounts of data from Excel that have various table layouts. I have good enough table detection routines and merge cell handling, but I am running into a problem when it comes to dealing with borders. Namely performance. The bordered regions in some of these files have meaning. Data Setup: I am importing directly from Office Open XML using VB6 and MSXML. The data is parsed from the XML into a dictionary of cell data. This wonks wonderfully and is just as fast as using docmd.transferspreadsheet in Access, but returns much better results. Each cell contains a pointer to a style element which contains a pointer to a border element that defines the visibility and weight of each border (this is how the data is structured inside OpenXML, also). Challenge: What I'm trying to do is find every region that is enclosed inside borders, and create a list of cells that are inside that region. What I have done: I initially created a BFS(breadth first search) fill routine to find these areas. This works wonderfully and fast for "normal" sized spreadsheets, but gets way too slow for imports into the thousands of rows. One problem is that a border in Excel could be stored in the cell you are checking or the opposing border in the adjacent cell. That's ok, I can consolidate that data on import to reduce the number of checks needed. One thing I thought about doing is to create a separate graph that outlines the cells using the borders as my edges and using a graph algorithm to find regions that way, but I'm having trouble figuring out how to implement the algorithm. I've used Dijkstra in the past and thought I could do similar with this. So I can span out using no endpoint to search the entire graph, and if I encounter a closed node I know that I just found an enclosed region, but how can I know if the route I've found is the optimal one? I guess I could flag that to run a separate check for the found closed node to the previous node ignoring that one edge. This could work, but wouldn't be much better performance wise on dense graphs. Can anyone else suggest a better method? Thanks for taking the time to read this.

    Read the article

  • Sql Query to get total rows and total rows matching specific condition

    - by mrNepal
    OK, Here is what my table looks like ------------------------------------------------ id type ----------------------------------------------- 1 a 2 b 3 a 4 c 5 c 7 a 8 a ------------------------------------------------ Now, I need a query that can give me this output... ----------------------------------------------------------------- count(*) | count(type=a) | count(type=b) | count(type=c) ----------------------------------------------------------------- 8 4 1 3 ------------------------------------------------------------------ I only know to get the total set using count(*), but how to do the remaining

    Read the article

< Previous Page | 700 701 702 703 704 705 706 707 708 709 710 711  | Next Page >