Search Results

Search found 5330 results on 214 pages for 'django auth'.

Page 71/214 | < Previous Page | 67 68 69 70 71 72 73 74 75 76 77 78  | Next Page >

• Project design / FS layout for large django projects

  - by rcreswick

  What is the best way to layout a large django project? The tutuorials provide simple instructions for setting up apps, models, and views, but there is less information about how apps and projects should be broken down, how much sharing is allowable/necessary between apps in a typical project (obviously that is largely dependent on the project) and how/where general templates should be kept. Does anyone have examples, suggestions, and explanations as to why a certain project layout is better than another? I am particularly interested in the incorporation of large numbers of unit tests (2-5x the size of the actual code base) and string externalization / templates.

  Read the article

• Limiting the maximum number of concurrent requests django/apache

  - by Johan

  Hi, I have a django site that demonstrates the usage of a tool. One of my views takes a file as input and runs some fairly heavy computation trough an external python script and returns some output to the user. The tool runs fast enough to return the output in the same request though. I would however want to limit how many concurrent requests to this URL/view to keep the server from getting congested. Any tips on how i would go about doing this? The page in itself is very simple and the usage will be low.

  Read the article

• Resizing uploaded files in django using PIL

  - by Nikunj

  I am using PIL to resize an uploaded file using this method: def resize_uploaded_image(buf): imagefile = StringIO.StringIO(buf.read()) imageImage = Image.open(imagefile) (width, height) = imageImage.size (width, height) = scale_dimensions(width, height, longest_side=240) resizedImage = imageImage.resize((width, height)) return resizedImage I then use this method to get the resizedImage in my main view method: image = request.FILES['avatar'] resizedImage = resize_uploaded_image(image) content = django.core.files.File(resizedImage) acc = Account.objects.get(account=request.user) acc.avatar.save(image.name, content) However, this gives me the 'read' error. Trace: Exception Type: AttributeError at /myapp/editAvatar Exception Value: read Any idea how to fix this? I have been at it for hours! Thanks! Nikunj

  Read the article

• Django "Page not found" error page shows only one of two expected urls

  - by Frank V

  I'm working with Django, admittedly for the first time doing anything real. The URL config looks like the following: urlpatterns = patterns('my_site.core_prototype.views', (r'^newpost/$', 'newPost'), (r'^$', 'NewPostAndDisplayList'), # capture nothing... #more here... - perhaps the perma-links? ) This is in an app's url.py which is loaded from the project's url.py via: urlpatterns = patterns('', # only app for now. (r'^$', include('my_site.core_prototype.urls')), ) The problem is, when I receive a 404 attempting to utilize newpost, the error page only shows the ^$ -- it seems to ignore the newpost pattern... I'm sure the solution is probably stupid-simple but right now I'm missing it. Can someone help get me on the right track...

  Read the article

• Python / Django : emulating a multidimensional layer on a MySQL database

  - by Sébastien Piquemal

  Hi, I'm working on a Django project where I need to provide a lot of different visualizations on the same data (for example average of a value for each month, for each year / for a location, etc...). I have been using an OLAP database once in college, and I thought that it would fit my needs, but it appears that it is much too heavy for what I need. Actually the volume of data is not very big, so I don't need any optimization, just a way to present different visualizations of the same data without having to write 1000 times the same code. So, to recap, I need a python library: to emulate a multidimensional database (OLAP style would be nice because I think it is quite convenient : star structure, and everything) non-intrusive, because I can't modify anything on the existing MySQL database easy-to-use, because otherwise there's no point in replacing some overhead by another.

  Read the article

• Django filter with two constraints on related model

  - by BJ Homer

  I have a django app with models as follows: A Question model An Answer model, with a ForeignKey back to the Question. (A question can have multiple answers.) A Flag model, with a ForeignKey to the Answer. (An answer can be flagged as inappropriate.) All of the above also have a user field, defining the user that created that object. I'm trying to get a list of all Questions with answers from the current user which have been flagged. I tried this: Question.objects.filter(answer__user=user).\ filter(answer__flag__isnull=True).distinct() … but I believe that will return a list of Questions with answers from the current user and with answers which have been flagged, but will not necessarily guarantee that it is the user's answer that has been flagged. Is there an easy way to do this? Basically, I want to make the answer part of the filter refer to the same answer on both of them. Please let me know if something is unclear.

  Read the article

• Django - Tips to avoid repeating code in views

  - by D Roddis

  I'm moving from a PHP background into Django development via python, mostly for the sake of tackling a MVC (or MVT) that I feel makes the most sense, although in this pattern I've started to notice a lot of repeated code in my views. For example, when logged in I have information regarding the user that I would like to appear on every page, although when using render_to_response and in every view this is required I have to grab the information and pass it to the render_to_response function. I'm wondering what would be the most efficient way to cut down on the duplicate code which would in essence be required in all views in a particular app. Thanks in advance.

  Read the article

• Local sites not displaying in VirtualBox when using Django's local development server?

  - by littlejim84

  Hello. I develop web applications using Django on Mac OSX 10.6. I use Django's built in local development server which I run on my computer's IP (such as: http://192.168.0.11:8001/). I test my applications in Firefox, Safari and Chrome and all display fine. I use Sun's VirtualBox with 3 different instances of Windows XP that have IE6, IE7 and IE8 on them. For whatever reason, these sometimes just don't display the Django sites. They come up with 'The page cannot be displayed'. Eight times out of ten, they display fine and function normally but for no reason at all they won't display. Sometimes restarting Django's local development server from the Terminal will fix the problem, sometimes it won't. Is there some sort of VirtualBox settings or Django settings that I need to set to ensure smooth operation of this? Am I overlooking something? Has anyone else had these problems?

  Read the article

• Django "Error: cannot import name escape" on windows

  - by Sam

  I cannot run the dev server because of this error ("Error: cannot import name escape"). I assume its because of modifications I've done to the project, but i have no idea how to find where the error is originating from to fix it. I don't import anything called escape anywhere. Update Using django-admin.py rather than the projects manage.py, don't know why... Update 2 Now manage.py is working. This may be because I had a file called email.py which was trying to import email.mime.text (ie trying to import itself) renaming to sendemail.py solved this problem.

  Read the article

• Inlines in Django Admin

  - by Oli

  I have two models, Order and UserProfile. Each Order has a ForeignKey to UserProfile, to associate it with that user. On the django admin page for each Order, I'd like to display the UserProfile associated with it, for easy processing of information. I have tried inlines: class UserInline(admin.TabularInline): model = UserProfile class ValuationRequestAdmin(admin.ModelAdmin): list_display = ('address1', 'address2', 'town', 'date_added') list_filter = ('town', 'date_added') ordering = ('-date_updated',) inlines = [ UserInline, ] But it complains that UserProfile "has no ForeignKey to" Order - which it doesn't, it's the other way around. Is there a way to do what I want?

  Read the article

• importing CELERY* environment variables in django settings.py causes celeryd not to start

  - by Taras

  I just spent 2 hours trying to figure out why django celery stopped working. Celery would being to start, but would stop short of printing out the configuration items, implying that it wasn't starting correct. The log would only contain The celery.decorators module along with the magic keyword arguments, are deprecated, and will be removed in version 3.0. Please use the celery.task module instead of celery.decorators, and the task.request should be used instead of the magic keyword arguments: from celery.task import task See http://bit.ly/celery22major for more information. """)) It turns out that some celery env variables that I was importing to try and fix a different problem were causing celery not to start correctly: from celery.tests.config import CELERY_QUEUES, CELERY_DEFAULT_QUEUE, CELERY_DEFAULT_ROUTING_KEY Even though I wasn't using them anywhere. Does anyone know what was happening?

  Read the article

• Django json serialization problem

  - by codingJoe

  I am having difficulty serializing a django object. The problem is that there are foreign keys. I want the serialization to have data from the referenced object, not just the index. For example, I would like the sponsor data field to say "sponsor.last_name, sponsor.first_name" rather than "13". How can I fix my serialization? json data: {"totalCount":"2","activities":[{"pk": 1, "model": "app.activity", "fields": {"activity_date": "2010-12-20", "description": "my activity", "sponsor": 13, "location": 1, .... model code: class Activity(models.Model): activity_date = models.DateField() description = models.CharField(max_length=200) sponsor = models.ForeignKey(Sponsor) location = models.ForeignKey(Location) class Sponsor(models.Model): last_name = models.CharField(max_length=20) first_name= models.CharField(max_length=20) specialty = models.CharField(max_length=100) class Location(models.Model): location_num = models.IntegerField(primary_key=True) location_name = models.CharField(max_length=100) def activityJSON(request): activities = Activity.objects.all() total = activities.count() activities_json = serializers.serialize("json", activities) data = "{\"totalCount\":\"%s\",\"activities\":%s}" % (total, activities_json) return HttpResponse(data, mimetype="application/json")

  Read the article

• How to set up Django app to make cookies work on subdomain

  - by Dzida

  Hi, I have deployed my application on subdomain.domain.com (it works only on that one subdomain). Everything works fine except the fact that from time to time users cannot log in to application (the message "Looks like your browser isn't configured to accept cookies. Please enable cookies, reload this page, and try again" is shown when trying to log into admin panel). I've noticed that restarting the web server eliminates this problem for some time. Does anyone have experience with setting up django project on subdomain and can guide me how to configure my application to make it work correctly without need to ocasionally make reset?

  Read the article

• Python / Django : emulating a multidimensionnal layer on a mySql database

  - by Sébastien Piquemal

  Hi, I'm working on a Django project where I need to provide a lot of different visualizations on the same data (for example average of a value for each month, for each year / for a location, etc ...). I have been using OLAP database once in college, and I thought that it would fit my needs, but it appears that it is much to heavy for what I need. Actually the volume of data is not very big, so I don't need any optimization, just a way to present different visualizations of the same data without having to write 1000 times the same code. So let's recap : I need a python library : to emulate a multidimensional database (OLAP style would be nice because I think it is quite convenient : stat structure, and everything) non-intrusive, because I can't modify anything on the existing mysql database easy-to-use, because otherwise there's no point in replacing some overhead by another.

  Read the article

• Getting users latest tweet with Django

  - by Hanpan

  I want to create a function which grabs every users latest tweet from a specific group. So, if a user is in the 'authors' group, I want to grab their latest tweet and then finally cache the result for the day so we only do the crazy leg work once. def latest_tweets(self): g = Group.objects.get(name='author') users = [] for u in g.user_set.all(): acc = u.get_profile().twitter_account users.append('http://twitter.com/statuses/user_timeline/'+acc+'.rss') return users Is where I am at so far, but I'm at a complete loose end as to how I parse the RSS to get there latest tweet. Can anyone help me out here? If there is a better way to do this, any suggestions are welcome! I'm sure someone will suggest using django-twitter or other such libraries, but I'd like to do this manually if possible. Cheers

  Read the article

• How can I selectively override a django .count() method

  - by Tom Viner

  I'm using postGresSQL and my main table has about 20,000 rows. Sometimes count() methods can take ages or even timeout. Mod.manager.filter(...).count() I need to selectively override the count() method depending on what filter has been applied. Just having a cache of results would be a great gain but I'd like to be able to say: if filter query is just {'enabled'=True} then return 20,000 without touching the db. Note: I can't prevent the call to .count() as it's inside django's pagination, which always does a count.

  Read the article

• Django: How do I get logging working?

  - by swisstony

  I've added the following to my settings.py file: import logging ... logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(levelname)s %(message)s', filename=os.path.join(rootdir, 'django.log'), filemode='a+') And in views.py, I've added: import logging log = logging.getLogger(__name__) ... log.info("testing 123!") Unfortunately, no log file is being created. Any ideas what I am doing wrong? And also is their a better method I should be using for logging? I am doing this on Webfaction.

  Read the article

• Django dictionary in templates: Grab key from another objects attribute

  - by Jordan Messina

  I have a dictionary called number_devices I'm passing to a template, the dictionary keys are the ids of a list of objects I'm also passing to the template (called implementations). I'm iterating over the list of objects and then trying to use the object.id to get a value out of the dict like so: {% for implementation in implementations %} {{ number_devices.implementation.id }} {% endfor %} Unfortunately number_devices.implementation is evaluated first, then the result.id is evaluated obviously returning and displaying nothing. I can't use parentheses like: {{ number_devices.(implementation.id) }} because I get a parse error. How do I get around this annoyance in Django templates? Thanks for any help!

  Read the article

• django url tag performance

  - by zxygentoo

  I was trying to integrate django-voting into my project following the RedditStyleVoting instruction. In my urls.py, i did something like this: url(r'^sections/(?P<object_id>\d+)/(?P<direction>up|down|clear)vote/?$', vote_on_object, dict( model=Section, template_object_name='section', template_name='script/section_confirm_vote.html', allow_xmlhttprequest=True ), name="section_vote", then, in my template: {% vote_by_user user on section as vote %} {% score_for_object section as score %} {% vote_by_user user on section as vote %} {% score_for_object section as score %} {{ score.score|default:0 }} It takes over 1.3s to load the page, but by hard coding it like this: {% vote_by_user user on section as vote %} {% score_for_object section as score %} {{ score.score|default:0 }} I got 50ms. Just avoid the url tag resolving stuff I got a 20+ times performance improvement. Is there something I did wrong? If not, then what's the best practice here, should we do things the right way or the fast way?

  Read the article

• Django. default=datetime.now() problem

  - by Shamanu4

  Hello. I've such db model: from datetime import datetime class TermPayment(models.Model): dev_session = models.ForeignKey(DeviceSession, related_name='payments') user_session = models.ForeignKey(UserSession, related_name='payment') date = models.DateTimeField(default=datetime.now(),blank=True) sum = models.FloatField(default=0) cnt = models.IntegerField(default=0) class Meta: db_table = 'term_payments' ordering = ['-date'] and here new instance is added: # ... tp = TermPayment() tp.dev_session = self.conn.session # device session hash tp.user_session = self.session # user session hash tp.sum = sum tp.cnt = cnt tp.save() But i've a problem: all records in database have the same value in date field - the date of the first payment. After server restart - one record have new date and others have the same as first after restart. It's look like some data cache is using but I can't found where. database: mysql 5.1.25 django v1.1.1

  Read the article

• Django: Localization Issue

  - by Eric

  In my application, I have a dictionary of phrases that are used throughout of the application. This same dictionary is used to create PDFs and Excel Spreadsheets. The dictionary looks like so: GLOBAL_MRD_VOCAB = { 'fiscal_year': _('Fiscal Year'), 'region': _('Region / Focal Area'), 'prepared_by': _('Preparer Name'), 'review_cycle':_('Review Period'), ... snip ... } In the code to produce the PDF, I have: fy = dashboard_v.fiscal_year fy_label = GLOBAL_MRD_VOCAB['fiscal_year'] rg = dashboard_v.dashboard.region rg_label = GLOBAL_MRD_VOCAB['region'] rc = dashboard_v.review_cycle rc_label = GLOBAL_MRD_VOCAB['review_cycle'] pb = dashboard_v.prepared_by pb_label = GLOBAL_MRD_VOCAB['prepared_by'] Now, when the PDF is produced, in the PDF, I don't see these labels but rather, I see: <django.utils.functional.__proxy__ object at 0x10106fdd0> Can somebody help me with this? How do I get the properly translated labels? Thanks Eric

  Read the article

• Django complex queries

  - by Josh K

  I need to craft a filter for an object that checks date ranges. Right now I'm performing a very inefficient loop which checks all the objects. I would like to simplify this to a database call. The logic is you have a start and an end date objects. I need to check if the start OR the end is within the range of an appointment. if (start >= appointment.start && start < appointment.end) || (end > appointment.start && end <= appointment.end) I could do this in SQL, but I'm not as familiar with the Django model structure for more complex queries.

  Read the article

• Django colon syntax in template tags: only in newer versions?

  - by Alan

  I just deployed an application to a new server, and although I'm using virtualenv, I had to install a new environment on the production server, which has a different architecture. Anyway, I received no TemplateSytaxErrors in development, but on the production server, I get: Exception Type: TemplateSyntaxError Exception Value: Caught SyntaxError while rendering: invalid syntax (views.py, line 25) The offending line is: {% url admin:password_change as password_change_url %} Upon removing that line, the TemplateSyntaxError hops to the next line that has a colon in it (and lets other template tags work fine). So my question is this: is there some discrepancy in versions of Python/Django that would allow or disallow the namespacing syntax? The template tags are in django-grappelli (http://code.google.com/p/django-grappelli/), so I'd rather not go through their code and rewrite all the template tags. Development server: 32-bit Debian Python 2.5.5 Django 1.2.1 Production server: 64-bit CentOS Python 2.4.3 Django 1.2.1 Any ideas?

  Read the article

• Django admin page dropdowns

  - by zen

  I am building a high school team application using Django. Here is my working models file: class Directory(models.Model): school = models.CharField(max_length=60) website = models.URLField() district = models.SmallIntegerField() conference = models.ForeignKey(Conference) class Conference(models.Model): conference_name = models.CharField(max_length=50) url = models.URLField() class Meta: ordering = ['conference_name'] When I open my admin pages and go to edit a school's conference the drop down looks like this: <select> <option value="1">Conference Object</option> <option value="2">Conference Object</option> <select> How do I replace "Conference Object" with the conference_name?

  Read the article

• Firefox - Stashing Requests for Deliberate Resubmission to Django App

  - by Koobz

  I've got an object creation form that's somewhat complicated, it contains a few dynamic formsets etc. I'm trying to ensure that these dynamic formsets are intact if the form runs into an error and returns you to the given page. In cases like this, the refresh button actually works well in re-submitting the request, but I can't rely on it. I'm doing some ad-hoc testing in the browser that I'd like to make a bit more repeatable, and eventually move to a unit test using Django's mock client. Is there an extension, or some convenient method to stash requests for later re-submission. The goal: I resubmit the request, tweak the code, eyeball the results, rinse and repeat. Three days later I can come back to it an try it again to make sure it's still working. The closest thing I can think of in this case is simply recording my activity with Selenium ide and replaying it.

  Read the article

< Previous Page | 67 68 69 70 71 72 73 74 75 76 77 78  | Next Page >