I have
a dropdown menu that is filled by
a mysql database. I need
to select one and have it send the information for use
on the next page after clicking
submit. It does populate the drop down menu like it is supposed
to it just does not seem
to catch the data
on the next page. Here is what I have:
removeMain.php
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title></title>
</head>
<form action="remove.php" method="post">
<?php
$link = mysql_connect('********', '********', '*********');
if (!$link){
die('Could not connect: ' . mysql_error());
}
mysql_select_db("********", $link);
$res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error());
echo "<select name = CardID>";
while($row=mysql_fetch_assoc($res)) {
echo "<option value=$row[ID]>$row[cardID]</a></option>";
}
echo "</select>";
?>
Amount
to Remove: <input type="text" name="Remove" />
<input type="
submit" />
</form>
<body>
</body>
</html>
remove.php
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title></title>
</head>
<body>
<?php
$link = mysql_connect('*********', '*********', '*********');
if (!$link){
die('Could not connect: ' . mysql_error());
}
mysql_select_db("***********y", $link);
$query = sprintf("UPDATE cardLists SET AmountLeft = AmountLeft - %s WHERE cardID = '%s'", mysql_real_escape_string($_POST["Remove"]), mysql_real_escape_string($_POST["CardID"]));
mysql_query($query);
mysql_close($link);
?>
<br />
<a href="removeMain.php"> <input type="
submit" name="return" id="return" value="Update More" /></a>
<a href="index.php"> <input type="
submit" name="main" id="main" value="Return
To Main" /></a>
</body>
</html>
