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  • Filtering foreign keys with AJAX in Django admin

    - by cnobile
    I have most of this figured out already. I have AJAX returning the region/state/province when a country is selected. The correct foreign key is saved to the database, however, when the record is viewed afterwards the selected state is not shown in the select nor are any states for the selected country. I understand why this is happening as, the admin view is not aware of the relation between the state and the country. So here is the question. Is there a hook in the admin view that will allow me to load the correct states for the country and set the selected attribute on the option in the select tag? Or how can I override the admin view for any forms that require the country and region/state/province set? I am using jQuery and Djando-1.1. Thanks

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  • Strategies for generating Zend Cache Keys

    - by emeraldjava
    ATM i'm manually generating a cache key based on the method name and parameters, then follow to the normal cache pattern. This is all done in the Controller and i'm calling a model class that 'extends Zend_Db_Table_Abstract'. public function indexAction() { $cache = Zend_Registry::get('cache'); $individualleaguekey = sprintf("getIndividualLeague_%d_%s",$leagueid,$division->code); if(!$leaguetable = $cache->load($individualleaguekey)) { $table = new Model_DbTable_Raceresult(); $leaguetable = $table->getIndividualLeague($leagueid,$division,$races); $cache->save($leaguetable, $individualleaguekey); } $this->view->leaguetable = $leaguetable; .... I want to avoid the duplication of parameters to the cache creation method and also to the model method, so i'm thinking of moving the caching logic away from my controller class and into model class packaged in './model/DbTable', but this seems incorrect since the DB model should only handle SQL operations. Any suggestions on how i can implement a clean patterned solution?

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  • How to get Media Picker Field via proxy record of many-to-many in orchard

    - by Sergey Schipanov
    I need to access mediapickerfield in Widget view. This field is relative to 'ActionPart'. I have a problem, when I create many-to-many relationships to display my 'ActionPart' in the widget. When I mapped many-to-many I take an 'ActionPart' and but cannot access the mediapickerfield. Records classes public class ActionPartRecord : ContentPartRecord { public virtual string Text { get; set; } public virtual double Price { get; set; } public virtual int TextPosX { get; set; } public virtual int TextPosY { get; set; } public virtual String TextSale { get; set; } public virtual int Color { get; set; } } public class ActionListRecord { public virtual int Id { get; set; } public virtual ActionPartRecord ActionPartRecord { get; set; } public virtual ActionWidgetPartRecord ActionWidgetPartRecord { get; set; } } public class ActionWidgetPartRecord : ContentPartRecord { public ActionWidgetPartRecord() { ActionList = new List<ActionListRecord>(); } public virtual IList<ActionListRecord> ActionList { get; set; } } public class ActionWidgetPart : ContentPart<ActionWidgetPartRecord> { public IEnumerable<ActionPartRecord> ActionList { get { return Record.ActionList.Select(x => x.ActionPartRecord); } } } ActionPart class public class ActionPart : ContentPart<ActionPartRecord> { public String Text { get { return Record.Text; } set { Record.Text = value; } } /*other field*/ } Migrations public int Create() { SchemaBuilder.CreateTable("ActionPartRecord", table => table .ContentPartRecord() .Column<string>("Text") .Column<double>("Price") .Column<int>("TextPosX") .Column<int>("TextPosY") .Column<string>("TextSale") .Column<int>("Color") ); ContentDefinitionManager.AlterPartDefinition("ActionPart", builder => builder .WithField("BaseImage", fieldBuilder => fieldBuilder.OfType("MediaPickerField").WithDisplayName("Action Image")) .WithField("PatternImage", fieldBuilder => fieldBuilder.OfType("MediaPickerField").WithDisplayName("Pattern Image")) .WithField("TimeExp", fieldBuilder => fieldBuilder.OfType("DateTimeField").WithDisplayName("Expecting date")) .Attachable()); ContentDefinitionManager.AlterTypeDefinition("Action", cfg => cfg .WithPart("CommonPart") .WithPart("TitlePart") .WithPart("RoutePart") .WithPart("BodyPart") .WithPart("ActionPart") .Creatable() .Indexed()); SchemaBuilder.CreateTable("ActionListRecord", table => table .Column<int>("Id", column => column.PrimaryKey().Identity()) .Column<int>("ActionPartRecord_Id") .Column<int>("ActionWidgetPartRecord_Id") ); SchemaBuilder.CreateTable("ActionWidgetPartRecord", table => table .ContentPartRecord() ); ContentDefinitionManager.AlterPartDefinition( "ActionWidgetPart", builder => builder.Attachable()); ContentDefinitionManager.AlterTypeDefinition("ActionWidget", cfg => cfg .WithPart("ActionWidgetPart") .WithPart("WidgetPart") .WithPart("CommonPart") .WithSetting("Stereotype", "Widget")); return 1; } Driver Display method protected override DriverResult Display( ActionWidgetPart part, string displayType, dynamic shapeHelper) { return ContentShape("Parts_ActionWidget", () => shapeHelper.Parts_ActionWidget( ContentPart: part, ActionList: part.ActionList)); } Widget View @foreach (var action in Model.ActionList) { <div class="item"> *How to access BaseImage Field in this row* <div class="sale-pattern"></div> <div class="container"> <div class="carousel-caption"> <h1>@action.Text</h1> <h1 class="price">@action.Price</h1> </div> </div> </div> }

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  • Model-binding an object from the repository by several keys

    - by Anton
    Suppose the following route: {region}/{storehouse}/{controller}/{action} These two parameters region and storehouse altogether identify a single entity - a Storehouse. Thus, a bunch of controllers are being called in the context of some storehouse. And I'd like to write actions like this: public ActionResult SomeAction(Storehouse storehouse, ...) Here I can read your thoughts: "Write custom model binder, man". I do. However, the question is How to avoid magic strings within custom model binder? Here is my current code: public class StorehouseModelBinder : IModelBinder { readonly IStorehouseRepository repository; public StorehouseModelBinder(IStorehouseRepository repository) { this.repository = repository; } public object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext) { var region = bindingContext.ValueProvider.GetValue("region").AttemptedValue; var storehouse = bindingContext.ValueProvider.GetValue("storehouse").AttemptedValue; return repository.GetByKey(region, storehouse); } } If there was a single key, bindingContext.ModelName could be used... Probably, there is another way to supply all the actions with a Storehouse object, i.e. declaring it as a property of the controller and populating it in the Controller.Initialize.

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  • reversing keys/values - create new instance of HashMap

    - by stck777
    I’ve got an existing instance of HashMap simply called sale (it is Map) I use it to log customers and items history. Is there a way to create a new instance of HashMap, that effectively reverses this usage? i.e will show each item purchased as a unique key and the corresponding value as a String set of the customers that have purchased that product. I suspect there is a simple process using keySet() in some way to iterate over the sales map but I just can’t see how to do this. Any help would be much appreciated.

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  • Composite keys as Foreign Key?

    - by paulio
    I have the following table... TABLE: Accounts ID (int, PK, Identity) AccountType (int, PK) Username (varchar) Password (varchar) I have created a composite key out of ID and AccountType columns so that people can have the same username/password but different AccountTypes. Does this mean that for each foreign table that I try and link to I'll have to create two columns? I’m using SQL Server 2008

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  • Unable to relate two MySQL tables (foreign keys)

    - by KPL
    Hello people, Here's my USER table CREATE TABLE IF NOT EXISTS `users` ( `id` int(11) NOT NULL AUTO_INCREMENT, `username` varchar(100) NOT NULL, `expiry` varchar(6) NOT NULL, `contact_id` int(11) NOT NULL, `email` varchar(255) NOT NULL, `password` varchar(100) NOT NULL, `level` int(3) NOT NULL, `active` tinyint(4) NOT NULL DEFAULT '1', PRIMARY KEY (`id`,`email`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; And here's my contact_info table CREATE TABLE IF NOT EXISTS `contact_info` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `email_address` varchar(255) NOT NULL, `company_name` varchar(255) NOT NULL, `license_number` varchar(255) NOT NULL, `phone` varchar(30) NOT NULL, `fax` varchar(30) NOT NULL, `mobile` varchar(30) NOT NULL, `category` varchar(100) NOT NULL, `country` varchar(20) NOT NULL, `state` varchar(20) NOT NULL, `city` varchar(100) NOT NULL, `postcode` varchar(50) NOT NULL, PRIMARY KEY (`id`,`email_address`), ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; The system uses username to login users.I want to modify it in such a way that it uses email for login. But there's no email_address in users table. I have added foreign key - email in user table(which is email_address in contact_info). How should I query database?

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  • How to save to Django Model that Have Mulitple Foreign Keys Fields

    - by Spikie
    I have Models for business Apps class staff_name(models.Model): TITLE_CHOICES = ( ('Mr', 'Mr'), ('Miss', 'Miss'), ( 'Mrs', 'Mrs'), ( 'chief', 'chief'), ) titlename = models.CharField(max_length=10,choices=TITLE_CHOICES) firstname = models.CharField(max_length=150) surname = models.CharField(max_length=150) date = models.DateTimeField(auto_now=True) class meta: ordering = ["date"] get_latest_by = "date" class inventory_transaction(models.Model): stock_in = models.DecimalField(blank=True, null=True,max_digits=8, decimal_places=2) stock_out = models.DecimalField(blank=True,null=True,max_digits=8, decimal_places=2) Number_container = models.ForeignKey(container_identity) staffs = models.ForeignKey(staff_name) goods_details = models.ForeignKey(departments) balance = models.DecimalField(max_digits=8, decimal_places=2) date = models.DateTimeField(auto_now=True) What i want to accomplish is check if the staff have made entry to the table before if yes add the value for the stock in plus (last) balance field and assign to balance if no just assign stock in value to balance field and save these are my codes These are my codes: try: s = staffname.staffs_set.all().order_by("-date").latest() # staffname is the instant of the class model staff_name e = s.staffs_set.create(stockin=vdataz,balance=s.balance + vdataz ) # e is the instant of the class model inventory_transaction e.save e.staffs.add(s) e.from_container.add(containersno) e.goods_details.add(department) except ObjectDoesNotExist: e = staff_name.objects.create(stockin=vdataz,balance=vdataz ) e.save e.staffs.add(staffname) e.from_container.add(containersno) e.goods_details.add(department) I will really appreciate a solution Thanks I hope it make more sense now. iam on online if you need more explanation just ask in the comment.Thank you for your help

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  • Special chars in Amazon S3 keys?

    - by Martin
    Is it possible to have special characters like åäö in the key? If i urlencode the key before storing it works, but i cant really find a way to access the object. If i write åäö in the url i get access denied (like i get if the object is not found). If i urlencode the url i paste in the browser i get "InvalidURICouldn't parse the specified URI". Is there some way to do this?

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  • Custom keys for Google App Engine models (Python)

    - by Cameron
    First off, I'm relatively new to Google App Engine, so I'm probably doing something silly. Say I've got a model Foo: class Foo(db.Model): name = db.StringProperty() I want to use name as a unique key for every Foo object. How is this done? When I want to get a specific Foo object, I currently query the datastore for all Foo objects with the target unique name, but queries are slow (plus it's a pain to ensure that name is unique when each new Foo is created). There's got to be a better way to do this! Thanks.

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  • Need sorted dictionary designed to find values with keys less or greater than search value

    - by Captain Comic
    Hi I need to have objects sorted by price (decimal) value for fast access. I need to be able to find all objects with price more then A or less than B. I was thinkg about SortedList, but it does not provide a way to find ascending or descending enumerator starting from given key value (say give me all objects with price less than $120). Think of a system that accepts items for sell from users and stores them into that collection. Another users want to find items cheaper than $120. Basically what i need is tree-based collection and functionality to find node that is smaller\greater\equal to provided key. Please advice.

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  • C++ find multiple keys from a std::multimap

    - by sch0ck9
    I have a STL::multimap and I search to populate a std::list with value which key is duplicated. Can I find/insert to a std::list the value of elements for all key where count 1 without counting them one by one? std::multimap<int, std::string> mm ; mm[0] = "a" ; mm[1] = "b" ; mm[0] = "c" ; mm[2] = "j" ; mm[2] = "k" ; std::list<std::string> lst ; lst might contains "a" ,"c","j","k" ; I try this template <class K, class V> class extract_value { private: K last_key_ ; std::list<V> m_list_value ; std::pair<K, V> first_elem ; public: extract_value(const K& k_): last_key_(k_) { } void operator() (std::pair<const K, V> elem) { if (last_key_ == elem.first) { m_list_value.push_back(elem.second) ; } else { // First entry last_key_ = elem.first; first_elem= elem ; } } std::list<V> get_value() { return m_list_value ; } }; ex_ = for_each(mm.begin(),mm.end(), extract_value<int, std::string>(0)) ; std::list<std::string> lst = ex_.get_value() ; I'm not sure that this code compile.

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  • NHibernate - get List<long> representing primary keys?

    - by Nathan
    I have a situation where I definitely don't want to get the whole domain object. Basically, the entity has a primary key of long (.NET)/bigint(sql server 2005). I simply need to pass the primary key to an external system which will access the database directly - and since the list of ids could be large, I don't want to rehydrate the entire domain object just to get the Id. In linq2sql, I could accomplish this with a projection, but I am restricted to NHibernate 1.2.1.4000, which doesn't support Linq. Is there a way to accomplish this using NHibernate 1.2.1.4000? (I am open to using a named-query if that will work)

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  • Sonata Media Bundle sortBy created_at

    - by tony908
    I use SonataMediaBundle and i would like sort Gallery by created_at field. In repository class i have (without orderBy working good!): $qb = $this->createQueryBuilder('m') ->orderBy('j.expires_at', 'DESC'); $query = $qb->getQuery(); return $query->getResult(); and this throw error: An exception has been thrown during the rendering of a template ("[Semantical Error] line 0, col 80 near 'created_at D': Error: Class Application\Sonata\MediaBundle\Entity\Gallery has no field or association named created_at") so i add this field to Gallery class: /** * @var \DateTime */ private $created_at; /** * Set created_at * * @param \DateTime $createdAt * @return Slider */ public function setCreatedAt($createdAt) { $this->created_at = $createdAt; return $this; } /** * Get created_at * * @return \DateTime */ public function getCreatedAt() { return $this->created_at; } but now i have error: FatalErrorException: Compile Error: Declaration of Application\Sonata\MediaBundle\Entity\Gallery::setCreatedAt() must be compatible with Sonata\MediaBundle\Model\GalleryInterface::setCreatedAt(DateTime $createdAt = NULL) in /home/tony/www/test/Application/Sonata/MediaBundle/Entity/Gallery.php line 32 GalleryInterface: https://github.com/sonata-project/SonataMediaBundle/blob/master/Model/GalleryInterface.php So... how can i use sortBy in my example?

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  • assign keys for combo box in java

    - by adesh kumar
    I want to add a JComboBox in Swing that is simple but I want to assign the values for each items in combo. I have the following code JComboBox jc1= new JComboBox(); jc1.addItem("a"); jc1.addItem("b"); jc1.addItem("c"); Now what I want is that when click on combo box it should return 1, 2 and 3 correspondingly instead of a ,b, c. Is there any way to assign the key values for each items in combo box?

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  • Sort array with multiple keys

    - by Vincent
    All, I have the following array in array format. The JSON format is shown just for user-friendliness. How can I sort the array ascending with the key "name" in php? "food": [ { "id": 1, "name": "dessert" }, { "id": 2, "name": "maincourse" }, { "id": 3, "name": "entrees" }, { "id": 4, "name": "appetizers" } ]

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  • Append or modify keys in conf files using sed/bash one-liner

    - by Jeff
    I often have to modify files such as sysctl.conf, and I'm familiar with using sed to replace existing values. Is there a way to append the new key/value pair to the file if sed wasn't able to replace it? For instance, using this example: modify config file using bash script sed -c -i "s/\($TARGET_KEY *= *\).*/\1$REPLACEMENT_VALUE/" $CONFIG_FILE How could I add the $TARGET_KEY = $REPLACEMENT_VALUE new line to $CONFIG_FILE using the same sed expression with slight changes? And on a related topic, how can I force creation of $CONFIG_FILE if it didn't exist?

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  • FieldError when annotating over foreign keys

    - by X_9
    I have a models file that looks similar to the following: class WithDate(models.Model): adddedDate = models.DateTimeField(auto_now_add=True) modifiedDate = models.DateTimeField(auto_now=True) class Meta: abstract = True class Match(WithDate): ... class Notify(WithDate): matchId = models.ForeignKey(Match) headline = models.CharField(null=True, blank=True, max_length=10) For each Match I'm trying to get a count of notify records that have a headline. So my call looks like matchObjs = Match.objects.annotate(notifies_made=Count('notify__headline__isnull')) This keeps throwing a FieldError. I've simplified the query down to matchObjs = Match.objects.annotate(notifies_made=Count('notify')) And I still get the same FieldError... I've seen this work in other cases (other documentation, other SO questions like this one) but I can't figure out why I'm getting an error. The specific error that is returned is as follows: Cannot resolve keyword 'notify' into field. Choices are: (all fields from Match model) Does anyone have a clue as to why I can't get this annotation to work across tables? I'm baffled after looking at the other SO question and various Django docs where I've seen this done. Edit: I am using Django 1.1.1

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  • How do I restrict foreign keys choices to related objects only in django

    - by Jeff Mc
    I have a two way foreign relation similar to the following class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True) class Child(models.Model): name = models.CharField(max_length=255) myparent = models.ForeignKey(Parent) How do I restrict the choices for Parent.favoritechild to only children whose parent is itself? I tried class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True, limit_choices_to = {"myparent": "self"}) but that causes the admin interface to not list any children.

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  • MySQL Many to Many with Unique keys and Update/Select if Exists otherwise Insert

    - by Jayrox
    In my goal to have a Many-to-Many relationship in my MySQL database I have arrived at another bridge to build. Current Tables: Users (id, name) Tags (id, name) User_Tags (user_id, tag_id) Here is the goal: I would like to have the ability to take a tag i.e: #fb and insert it into my Tags database which has a unique constraint on name and if the tag exists I would like to return it's id I would like to insert the tag.id and the current user's user.id into User_Tags. I do not have any unique constraints on the User_Tags table because I would like to be able to track the user's most commonly used tags and present them in a list ordered by frequency of use. I am currently developing this project in PHP using prepared statements. Additionally, performance is not currently an issue as my user count is still fairly small, but it is steadily growing and may be an issue in the future.

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