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  • Best pratice: How do I implement a list similar to Stackoverflow's Users List?

    - by André Pena
    Technologies involved: ASP.NET Web-forms Javascript (jQuery for instance) Case To make it clearer let's give the Stackoverflow Users list as an example. This list can be manipulated at client-side. I can search, page and so forth. So obviously we would need to call jQuery.ajax to retrieve the HTML of each page given a search. Alright. Now this leaves me with the first question: What is the best way to render the response for the jQuery.ajax at server-side? I can't use templates I suppose, so the most obvious solution I think is to create the HTML tags as server-controls and render them as the result of an ASHX request? Is this is best approach? Nice. That solved we have yet another problem: When the user first enters the Authors List the first list page should already come from the server completely rendered alright? Of course we could render the first page as well as an ajax call but I don't think it's better. This time I CAN use templates to render the list but this template couldn't be reused in case 1. What do I do? Now the final question: Now we have 2 rendering strategies: 1) Client and 2) Server. How do I reuse code for the 2 renderings? What are the best pratices for solving these problems?

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  • Sharepoint how to get a list of Sharepoint specific fields/columns

    - by BeraCim
    Hi all: I have a list of fields/columns that comprises of Sharepoint specific fields/columns, my own custom fields/columns, and a bunch of custom fields/columns created by someone else (which I dont know what they are yet). My goal is to get the list of the fields/columnns created by that someone else. My first hurdle lies in how to tell which ones are from Sharepoint. So I was wondering is there any way to programmatically retrieve a list of Sharepoint Specific fields/columns? Thanks.

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  • List View Below Image

    - by sairam333
    Hi I want a list view and below of that list view i want one image.when i use the below code the list view and image view are appeared only in Portrait mode but not landscape mode,Can any one gie me the suggestions for displaying that list view and image view in Landscape also.My xml code is ` <!-- <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical" android:gravity="bottom" android:paddingBottom="100sp" > --> <com.fitzengineering.teslaworldnet.presentationlayer.TransparentPanel android:id="@+id/transparent_panel" android:layout_width="fill_parent" android:paddingTop="5sp" android:paddingLeft="5sp" android:paddingRight="5sp" android:layout_height="wrap_content" android:paddingBottom="5sp"> -- ` Thanks in adnance

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  • Drop Down List in MVC

    - by Zerotoinfinite
    I want to do the following: 1: Add two dropdown list in the register.aspx [Say ddlRole,ddlGender] 2: Fill the dropdown list [ ddlRole should be filled from the database, and ddlRole should have two static field] 3: On submit I want to get the selected value of the two dropdown list. Please help. Thanks in advance.

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  • Inline instantiation of a constant List

    - by Roflcoptr
    I try to do something like this: public const List<String> METRICS = new List<String>() { SourceFile.LOC, SourceFile.MCCABE, SourceFile.NOM, SourceFile.NOA, SourceFile.FANOUT, SourceFile.FANIN, SourceFile.NOPAR, SourceFile.NDC, SourceFile.CALLS }; But unfortunately this doesn't work: FileStorer.METRICS' is of type 'System.Collections.Generic.List<string>'. A const field of a reference type other than string can only be initialized with null. How can I solve this problem?

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  • XSL: List divided into columns.

    - by kalininew
    Hello, help me please. There is a list of nodes. <list> <item>1</item> <item>2</item> <item>3</item> <item>4</item> <item>5</item> <item>6</item> <item>7</item> and so on... </list> Need to divide the list of "n" (arbitrary number) equal parts. If the number of nodes is not divided equally, then let the last set of nodes will contain the remainder of the division. For example, if the input list contains 33 elements and the output should have 4 parts with uniformly distributed elements. At the exit to get 3 parts to 9 of elements and one part with 6 elements in the sum of 33.

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  • Create a flexible, localized, Ruby-on-Rails list-of-values

    - by Craig
    I have a list of values (Beginner, Intermediate, Advanced, Fluent, Native) that I would like to: act as the model for a SELECT list act as a model to convert ids to values in a HTML table use in multiple controllers and views keep in an order that preserves the business rules (ordered by skill level) localize at some point in the future Is there a way of implementing this list to address all or most of my needs?

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  • Binding list of objects to WPF ListView

    - by Dave Colwell
    Hi all, I have a list of objects which i want to bind to a ListView control in my WPF application. The Objects have a DataTemplate already, so no need to define that. The list of objects is a property in the codebehind file in the format list<object> When i add one object programatically, it appears fine. But when i try to bind the ItemSource of the ListBox to the list of objects, nothing shows up. I am using the following binding: ItemsSource="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type Window}}, Path=Portfolios}" where the name of the property i am trying to bind to is Portfolios and exists on the parent window

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  • In python: how to apply itertools.product to elements of a list of lists

    - by Guilherme Rocha
    I have a list of arrays and I would like to get the cartesian product of the elements in the arrays. I will use an example to make this more concrete... itertools.product seems to do the trick but I am stuck in a little detail. arrays = [(-1,+1), (-2,+2), (-3,+3)]; If I do cp = list(itertools.product(arrays)); I get cp = cp0 = [((-1, 1),), ((-2, 2),), ((-3, 3),)] But what I want to get is cp1 = [(-1,-2,-3), (-1,-2,+3), (-1,+2,-3), (-1,+2,+3), ..., (+1,+2,-3), (+1,+2,+3)]. I have tried a few different things: cp = list(itertools.product(itertools.islice(arrays, len(arrays)))); cp = list(itertools.product(iter(arrays, len(arrays)))); They all gave me cp0 instead of cp1. Any ideas? Thanks in advance.

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  • Form values in a list item

    - by Tri
    Here is the site mock-up I'm working on for my job: http://dev.arm.gov/~noensie/dqhands/cgi-bin/explorer. I'm still a novice in web developing and I need help with placing form values in a list item to pass on to another page. I'd rather not go in great detail the purpose of this website, but in terms of its basic use, select the parameters in the middle column for a request and add it to the list on the right column by pressing on "add request" button when it appears. After the list have been populated, a user would submit the selected requests, which will direct them to another page based on the requests selected (or added to the list, same thing). That last sentence is where I'm having a problem. Right now, each of request in the list in the right column are <li> elements and I assign them attribute values that needed to be passed on to the next page. I tried inserting a hidden input with same values, but I'm still not sure how to utilize that; I'm not even sure using the hidden input is the correct way. Also the "submit request" button is located outside the <form> block. I was going to utilize javascript and jQuery to enable the button to serialize the values in the <form> block, but I don't know quite how to do that. Go ahead and take a look at my javascript code (index.js) and slay me, or, I mean, my code. It's still pretty elementary and short (~260 lines, that's short right?). I will take any help for this problem (as the matter of fact, if you see any other problems or a better way of implementation of something, go ahead and mention that too); tips, advice, code samples, or whatever else you can contribute, it will be greatly appreciated. Tri

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  • initializer_list and move semantics

    - by FredOverflow
    Am I allowed to move elements out of a std::initializer_list<T>? #include <initializer_list> #include <utility> template<typename T> void foo(std::initializer_list<T> list) { for (auto it = list.begin(); it != list.end(); ++it) { bar(std::move(*it)); // kosher? } } Since std::intializer_list<T> requires special compiler attention and does not have value semantics like normal containers of the C++ standard library, I'd rather be safe than sorry and ask.

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  • C# - Removing items from lists and all references to them.

    - by LiamV
    Hi there, I'm facing a situation where I have dependent objects and I would like to be able to remove an object and all references to it. Say I have an object structure like the code below, with a Branch type which references two Nodes. public class Node { // Has Some Data! } public class Branch { // Contains references to Nodes public Node NodeA public Node NodeB } public class Graph { public List<Node> Nodes; public List<Branch> Branches; } If I remove a Node from the Nodes list in the Graph class, it is still possible that one or more Branch objects still contains a reference to the removed Node, thus retaining it in memory, whereas really what I would quite like would be to set any references to the removed Node to null and let the garbage collection kick in. Other than enumerating through each Branch and checking each Node reference sequentially, are there any smart ideas on how I remove references to the Node in each Branch instance AND indeed any other class which reference the removed Node? Much appreciated, Liam

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  • Remove Duplicates from List of HashMap Entries

    - by HonorGod
    I have a List<HashMap<String,Object>> which represents a database where each list record is a database row. I have 10 columns in my database. There are several rows where the values of 2 particular columns are equals. I need to remove the duplicates from the list after the list is updated with all the rows from database. What is the efficient way? FYI - I am not able to do distinct while querying the database, because the GroupName is added at a later stage to the Map after the database is loaded. And since Id column is not primary key, once you add GroupName to the Map. You will have duplicates based on Id + GroupName combination! Hope my question makes sense. Let me know if we need more clarification.

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  • Pyton, print delimited list

    - by Mike
    Consider this Python code for printing a list of comma separated values for element in list: print element + ",", What is the preferred method for printing such that a comma does not appear if element is the final element in the list. ex a = [1, 2, 3] for element in a print str(element) +",", output 1,2,3, desired 1,2,3

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  • How to map EnumSet (or List of Enums) in an entity using JPA2

    - by arteq007
    I have entity Person: @Entity @Table(schema="", name="PERSON") public class Person { List<PaymentType> paymentTypesList; //some other fields //getters and setters and other logic } and I have enum PaymentType: public enum PaymentType { FIXED, CO_FINANCED, DETERMINED; } how to persist Person and its list of enums (in this list i have to place variable amount of enums, there may be one of them, or two or all of them) I'm using Spring with Postgres, Entity are created using JPA annotation, and managed using Hibernate

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  • Get a list of mutex?

    - by Patrick
    A program creates a mutex as part of its start-up. I don't know the format of this mutex so I wondered if there is a way to get a list of all non-abandoned mutex, open the program, get a new list and see if I can find the mutex by removing all duplicate entries. Is there a way to get this list?

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  • How can i use generic list with foreach?

    - by Phsika
    if i compiled below codes error return foreach loop how can i solve it? Error:Error 1 foreach statement cannot operate on variables of type 'Sortlist.MyCalisan' because 'Sortlist.MyCalisan' does not contain a public definition for 'GetEnumerator' C:\Users\yusuf.karatoprak\Desktop\ExcelToSql\TestExceltoSql\Sortlist\Program.cs 46 13 Sortlist static void EskiMetodlaListele() { MyCalisan myCalisan = new MyCalisan(); Calisan calisan = new Calisan(); calisan.Ad = "ali"; calisan.SoyAd = "abdullah"; calisan.ID = 1; myCalisan.list.Add(calisan); foreach (Calisan item in myCalisan) { Console.WriteLine(item.Ad.ToString()); } } } public class Calisan { public int ID { get; set; } public string Ad { get; set; } public string SoyAd { get; set; } } public class MyCalisan { public List<Calisan> list { get; set; } public MyCalisan() { list = new List(); } }

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  • Set postion in customized list field in blackberry

    - by arunabha
    I want three list field items to be displayed, from bottom to top. I am able to display three list field items, but they display from top to bottom. I have tried setting the position, but it isn't working. import java.util.Vector; import net.rim.device.api.system.Bitmap; import net.rim.device.api.system.Display; import net.rim.device.api.ui.ContextMenu; import net.rim.device.api.ui.DrawStyle; import net.rim.device.api.ui.Field; import net.rim.device.api.ui.Font; import net.rim.device.api.ui.Graphics; import net.rim.device.api.ui.Manager; import net.rim.device.api.ui.MenuItem; import net.rim.device.api.ui.UiApplication; import net.rim.device.api.ui.component.BitmapField; import net.rim.device.api.ui.component.Dialog; import net.rim.device.api.ui.component.LabelField; import net.rim.device.api.ui.component.ListField; import net.rim.device.api.ui.component.ListFieldCallback; import net.rim.device.api.ui.component.NullField; import net.rim.device.api.ui.container.FullScreen; import net.rim.device.api.ui.container.MainScreen; import net.rim.device.api.util.Arrays; import net.rim.device.api.ui.component.ListField; /** * @author Jason Emerick */ public class TaskListField extends UiApplication { //statics ------------------------------------------------------------------ public static void main(String[] args) { TaskListField theApp = new TaskListField(); theApp.enterEventDispatcher(); } public TaskListField() { pushScreen(new TaskList()); } } /*class List extends FullScreen { TaskList tl; List(){ super(); TaskList tl=new TaskList(); } }*/ class TaskList extends MainScreen implements ListFieldCallback { private Vector rows; private Bitmap p1; private Bitmap p2; private Bitmap p3; String Task; ListField listnew=new ListField(); public TaskList() { super(); listnew.setRowHeight(50); //setEmptyString("Hooray, no tasks here!", DrawStyle.HCENTER); listnew.setCallback(this); p1 = Bitmap.getBitmapResource("1.png"); p2 = Bitmap.getBitmapResource("2.png"); p3 = Bitmap.getBitmapResource("3.png"); rows = new Vector(); for (int x = 0; x < 3; x++) { TableRowManager row = new TableRowManager(); if (x== 0) { Task="On Air Now"; } if (x== 1) { Task="Music Channel"; } if (x==2) { Task="News Channel"; } // SET THE PRIORITY BITMAP FIELD // if high priority, display p1 bitmap if (x % 2 == 0) { row.add(new BitmapField(p1)); } // if priority is 2, set p2 bitmap else if (x % 3 == 0) { row.add(new BitmapField(p2)); } // if priority is 3, set p3 bitmap else { row.add(new BitmapField(p3)); } // SET THE TASK NAME LABELFIELD // if overdue, bold/underline LabelField task = new LabelField(Task, DrawStyle.ELLIPSIS); // if due today, bold if (x % 2 == 0) { task.setFont(Font.getDefault().derive( Font.BOLD)); } else { task.setFont(Font.getDefault().derive(Font.BOLD)); } row.add(task); LabelField task1 = new LabelField("Now Playing" + String.valueOf(x), DrawStyle.ELLIPSIS); // if due today, bold /* if (x % 2 == 0) { task.setFont(Font.getDefault().derive( Font.BOLD)); } else { task.setFont(Font.getDefault().derive(Font.BOLD)); }*/ Font myFont = Font.getDefault().derive(Font.PLAIN, 12); task1.setFont(myFont); row.add(task1); // SET THE DUE DATE/TIME row.add(new LabelField("", DrawStyle.ELLIPSIS | LabelField.USE_ALL_WIDTH | DrawStyle.RIGHT) { protected void paint(Graphics graphics) { graphics.setColor(0x00878787); super.paint(graphics); } }); rows.addElement(row); } listnew.setSize(rows.size()); this.add(listnew); } // ListFieldCallback Implementation public void drawListRow(ListField listField, Graphics g, int index, int y, int width) { //TaskList list =(TaskListField) listnew; TableRowManager rowManager = (TableRowManager)rows .elementAt(index); rowManager.drawRow(g, 0, y, width, listnew.getRowHeight()); } private class TableRowManager extends Manager { public TableRowManager() { super(0); } // Causes the fields within this row manager to be layed out then // painted. public void drawRow(Graphics g, int x, int y, int width, int height) { // Arrange the cell fields within this row manager. layout(0, 1); // Place this row manager within its enclosing list. setPosition(x,y); // Apply a translating/clipping transformation to the graphics // context so that this row paints in the right area. g.pushRegion(getExtent()); // Paint this manager's controlled fields. subpaint(g); g.setColor(0x00CACACA); g.drawLine(0, 0, getPreferredWidth(), 0); // Restore the graphics context. g.popContext(); } // Arrages this manager's controlled fields from left to right within // the enclosing table's columns. protected void sublayout(int width, int height) { // set the size and position of each field. int fontHeight = Font.getDefault().getHeight(); int preferredWidth = getPreferredWidth(); // start with the Bitmap Field of the priority icon /* Field field = getField(0); layoutChild(field, 0, 0); setPositionChild(field, 150, 300);*/ // set the task name label field /* field = getField(1); layoutChild(field, preferredWidth - 16, fontHeight + 1); setPositionChild(field, 34, 3); // set the list name label field field = getField(2); layoutChild(field, 150, fontHeight + 1); setPositionChild(field, 34, fontHeight + 6);*/ // set the due time name label field /* field = getField(3); layoutChild(field, 150, fontHeight + 1); setPositionChild(field,4,340);*/ /* layoutChild(listnew, preferredWidth, fontHeight); setPositionChild(listnew, 3, 396);*/ setExtent(360, 480); } // The preferred width of a row is defined by the list renderer. public int getPreferredWidth() { return getWidth(); } // The preferred height of a row is the "row height" as defined in the // enclosing list. public int getPreferredHeight() { return listnew.getRowHeight(); } } public Object get(ListField listField, int index) { // TODO Auto-generated method stub return null; } public int getPreferredWidth(ListField listField) { // TODO Auto-generated method stub return 0; } public int indexOfList(ListField listField, String prefix, int start) { // TODO Auto-generated method stub return 0; } }

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  • Python, print delimited list

    - by Mike
    Consider this Python code for printing a list of comma separated values for element in list: print element + ",", What is the preferred method for printing such that a comma does not appear if element is the final element in the list. ex a = [1, 2, 3] for element in a print str(element) +",", output 1,2,3, desired 1,2,3

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  • Change the height of a list item when it's in edit mode

    - by toby
    I have custom list item renderers and editors for a List control. I need for the editor to have a greater height then the renderer, i.e., the row should expand(in height) when it goes into edit mode. However, even when the list's variableRowHeight is set to true, it doesn't do what I want: the height seems to be based on the height of the renderer only, not the editor. Is there any way to do what I want?

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  • Linked List Sorting with Strings In C

    - by user308583
    I have a struct, with a Name and a single Node called nextName It's a Singly Linked list, and my task is to create the list, based on alphabetical order of the strings. So iff i enter Joe Zolt and Arthur i should get my list structured as Joe Than Joe Zolt Than Arthur Joe Zolt I'm having trouble implementing the correct Algorithm, which would put the pointers in the right order. This is What I have as of Now. Temp would be the name the user just entered and is trying to put into the list, namebox is just a copy of my root, being the whole list if(temp != NULL) { struct node* namebox = root; while (namebox!=NULL && (strcmp((namebox)->name,temp->name) <= 0)) { namebox = namebox->nextName; printf("here"); } temp->nextName = namebox; namebox = temp; root = namebox; This Works right now, if i enter names like CCC BBB than AAA I Get Back AAA BBB CCC when i print But if i put AAA BBB CCC , When i print i only get CCC, it cuts the previous off.

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