Search Results

Search found 9557 results on 383 pages for 'x86 64'.

Page 71/383 | < Previous Page | 67 68 69 70 71 72 73 74 75 76 77 78  | Next Page >

• How to add a font to the Cmd window choices in Windows 7 64-bit?

  - by Mark Ransom

  I tried following the procedure outlined in this previous answer and it doesn't work: http://superuser.com/a/5079/2366 Specifically I'm trying to add Lucida Sans Typewriter Regular to the choices of Consolas and Lucida Console that the Cmd window currently allows. Lucida Console is in registry key "0" and Consolas is in registry key "00", so I'm adding key "000" but it's not affecting the available choices in the Font tab under Properties, even after rebooting the system. P.S. I also tried adding Courier New to the choices and it shows up, but appears to select Italic instead.

  Read the article

• How do I get the machine name from an IP via Multicast DNS?

  - by Adam

  I have a list of IP addresses on a network, and most of them support multicast DNS. I'd like to be able to resolve the server name instead of just having the IP address. ping computer.local 64 bytes from 192.168.0.52: icmp_seq=1 ttl=64 time=5.510 ms 64 bytes from 192.168.0.52: icmp_seq=2 ttl=64 time=5.396 ms 64 bytes from 192.168.0.52: icmp_seq=3 ttl=64 time=5.273 ms Works, but I'd like to be able to determine that name from the IP. Also the devices don't necessarily broadcast any services, but definitely do support mDNS broadcast. So looking through services won't work.

  Read the article

• What is the network address (x.x.x.0) used for?

  - by Shtééf

  It appears to be common practice to not use the first address in a subnet, that is the IP 192.168.0.0/24, or a more exotic example would be 172.20.20.64/29. The ipcalc tool I frequently use follows the same practice: $ ipcalc -n -b 172.20.20.64/29 Address: 172.20.20.64 Netmask: 255.255.255.248 = 29 Wildcard: 0.0.0.7 => Network: 172.20.20.64/29 HostMin: 172.20.20.65 HostMax: 172.20.20.70 Broadcast: 172.20.20.71 Hosts/Net: 6 Class B, Private Internet But why is that HostMin is not simply 64 in this case? The 64 address is a valid address, right? And whatever the answer, does the same apply to IPv6? Perhaps slightly related: it also appears possible to use a TCP port 0 and an UDP port 0. Are these valid or used anywhere?

  Read the article

• Is putting swapfile & temp folder in ramdisk a good idea in Windows 7 64 bit with lots of ram?

  - by Tony_Henrich

  I want my Windows to run as fast as possible. If I have 12GB ram in Windows 7 64bit, quad core cpu, and all apps fit in memory, will the swap file ever be used for anything? The question is about if its a good idea to put the swap file in a ram disk. Would a ram disk help in any way or will Windows intelligently use all the available memory for all its work? I am also thinking of putting the temp folder in a ram disk. I know ram disk is volatile memory and I don't care about its content in it if it gets lost.

  Read the article

• How can one create a bootable linux usb key that works on Mac (Intel 64 bit CPU) hardware ?

  - by user3621

  Hi, I'm trying to create a bootable usb key with linux (debian) and that can be booted on Macintel hardware. I have read that MAC's EFI can only boot GPT GUID formatted disks. I'm desperately trying to find a good tutorial which explains how to create such a key. Here what I have done so far: create a GUID partition on te key using linux GNU parted create a HFS+ or ext3 partition on the key, with the boot flag on install a linux .iso with unetbootin While all steps were successfull and in some cases I could even boot on a PC, the step of booting on Macintel software failed (on a macbook). I need to precise that I holded the "alt" key while booting the mac and the only visible bootable disk was the hard disk. Thanks for any advice. PS: I have tried with rEFIt as well. In one case I had a "windows" icon but it then failed to boot with a message like "no system found"

  Read the article

• Difference between "bit-number" in filesystem and that in OS (like 32,64 bit)?

  - by learner

  I encountered 2 terms ,"FAT32", a file system and "Windows Vista 32 bit". I found that the meaning of a 32 bit OS is that that the OS deals with data in chunks of minimum size 32 bits. I don't quite understand the depth of that, but I figure ,every file in that system with that OS should have a minimum size of 32 bits. I also read that these 32 bits are used to hold data of files' location(reference) and details. Which of it is it? I have also read that 4 GB of RAM is all that is needed at the most if you're on a 32 bit OS. But I don't understand why. If there are 32 bits to hold info about files and their locations,there can be 2^32 possible combinations of it. But I have found in many places,2^32 is divided by 1024 thrice to get 4GB. Why? Did that 2^32 become equal to 2^32 bytes? And about filesystems I read a similar explanation for what 32 means in FAT32. It is supposed to mean that 32 bits are used to number file system block. Now how is different from the number before the OS?

  Read the article

• Database platform migration from Windows-32bit to Linux-64bit

  - by [email protected]

  We have a customer which have all they core business database on RAC over Windows OS. Last year they were affected by a virus that destroyed the registry and all their RAC environments were "OUT OF ORDER", the result, thousand people on vacation for a day.They were distrustful about Linux and after came an agreement to migrate their Enterprise Manager from Windows to Linux (OMS and Repository). How we did demonstrate how powerful and easy is RMAN to migrate databases across platforms.Fist of check of target platform is available from sourceSQL> select platform_name from v$db_transportable_platform;PLATFORM_NAME-----------------------------------------------------------Microsoft Windows IA (32-bit)Linux IA (32-bit)HP Tru64 UNIXLinux IA (64-bit)HP Open VMSMicrosoft Windows IA (64-bit)Linux 64-bit for AMDMicrosoft Windows 64-bit for AMDSolaris Operating System (x86)Check database object as directories that can change across platforms, also check external tables.Startup source database in read only modeRun the following RMAN ScriptRMAN> connect target / RMAN> convert database on target platform convert script 'c:/temp/convert_grid.rman'transport script 'c:/TEMP/transporta_grid.sql' new database 'gridbd' format 'c:/temp/gridmydb%U' db_file_name_convert 'C:\oracle\oradata\grid','/oracle/gridbd/data2/data';(Notice tha path change on db_file_name_convert)Move from source to target:PfileNew scriptsexternal table filesbfilesdata filesCheck pfile, and ensure that the paths are OKCreate temporary control file to connect rmanExecute the RMAN scriptRMAN> connect target / RMAN> @/home/oracle/pboixeda/win2lnx.rmanShutdown the instance and remove temporary control filesRecreate controlfile/s, take care about the used paths.Execute the transport script, transporta_grid.sqlDue we were moving from a 32-bit architecture to a 64-bit architecture, there is bug reported in 386990.1 note, we had to recreate OLAP , check the note for more details. Alter or Recreate all necessary objects Launch utlrpAfter this experience with Linux they are on the way to migrate all their RAC from 10gR2 on Windows to 11gR2 Linux 64 bit.Hope it helps

  Read the article

• cannot delete IPv6 default gateway

  - by NulledPointer

  The commands below should be pretty self-explanatory. Please note that the route for which i get failure is obtained by RA and has very less expiry ( e Flag in UDAe). @vm:~$ ip -6 route 2001:4860:4001:800::1002 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:800::1003 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:800::1005 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:803::100e via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 fd00:ffff:ffff:fff1::/64 dev eth1 proto kernel metric 256 expires 2592300sec fe80::/64 dev eth1 proto kernel metric 256 default via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1 default via fe80::20c:29ff:fe87:f9e7 dev eth1 proto kernel metric 1024 expires 1776sec @vm:~$ @vm:~$ @vm:~$ @vm:~$ sudo route -6 delete default gw fe80::20c:29ff:fe87:f9e7 @vm:~$ ip -6 route 2001:4860:4001:800::1002 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:800::1003 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:800::1005 via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 2001:4860:4001:803::100e via fe80::20c:29ff:fe87:f9e7 dev eth1 proto static metric 1024 fd00:ffff:ffff:fff1::/64 dev eth1 proto kernel metric 256 expires 2592279sec fe80::/64 dev eth1 proto kernel metric 256 default via fe80::20c:29ff:fe87:f9e7 dev eth1 proto kernel metric 1024 expires 1755sec @vm:~$ @vm:~$ @vm:~$ sudo route -6 delete ::/0 gw fe80::20c:29ff:fe87:f9e7 dev eth1 SIOCDELRT: No such process @vm:~$ @vm:~$ @vm:~$ route -n6 Kernel IPv6 routing table Destination Next Hop Flag Met Ref Use If 2001:4860:4001:800::1002/128 fe80::20c:29ff:fe87:f9e7 UG 1024 0 0 eth1 2001:4860:4001:800::1003/128 fe80::20c:29ff:fe87:f9e7 UG 1024 0 0 eth1 2001:4860:4001:800::1005/128 fe80::20c:29ff:fe87:f9e7 UG 1024 0 0 eth1 2001:4860:4001:803::100e/128 fe80::20c:29ff:fe87:f9e7 UG 1024 0 0 eth1 fd00:ffff:ffff:fff1::/64 :: UAe 256 0 0 eth1 fe80::/64 :: U 256 0 0 eth1 ::/0 fe80::20c:29ff:fe87:f9e7 UGDAe 1024 0 0 eth1 ::/0 :: !n -1 1 349 lo ::1/128 :: Un 0 1 3 lo fd00:ffff:ffff:fff1:a00:27ff:fe7f:7245/128 :: Un 0 1 0 lo fd00:ffff:ffff:fff1:fce8:ce07:b9ea:389f/128 :: Un 0 1 0 lo fe80::a00:27ff:fe7f:7245/128 :: Un 0 1 0 lo ff00::/8 :: U 256 0 0 eth1 ::/0 :: !n -1 1 349 lo @vm:~$ UPDATE: Another question is whats the use of link local address as the default route?

  Read the article

• can ping, but not SSH

  - by Matt

  So I have NetworkManager, connected to an AP on wlan1. I have wlan0 connected to a AdHoc network. I have Firestarter sharing my inet on the Adhoc. I have my ipod connected to wlan0, IP 10.42.43.101. wlan0 Link encap:Ethernet HWaddr ac:xx:12:81:7f:xx inet addr:10.42.43.1 Bcast:10.255.255.255 Mask:255.0.0.0 wlan1 Link encap:Ethernet HWaddr 00:xx:b3:98:f2:xx inet addr:10.0.1.61 Bcast:10.0.1.255 Mask:255.255.255.0 Now, I can ping my Jailbroken, SSH-enabled and running ipod touch: matt: ~ $ ping 10.42.43.101 PING 10.42.43.101 (10.42.43.101) 56(84) bytes of data. 64 bytes from 10.42.43.101: icmp_req=1 ttl=64 time=168 ms 64 bytes from 10.42.43.101: icmp_req=2 ttl=64 time=256 ms 64 bytes from 10.42.43.101: icmp_req=3 ttl=64 time=151 ms ^C --- 10.42.43.101 ping statistics --- 3 packets transmitted, 3 received, 0% packet loss, time 1999ms rtt min/avg/max/mdev = 151.465/191.979/256.316/46.003 But I cannot SSH it: $ ssh [email protected] -vv OpenSSH_5.8p1 Debian-1ubuntu3, OpenSSL 0.9.8o 01 Jun 2010 debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug2: ssh_connect: needpriv 0 debug1: Connecting to 10.42.43.101 [10.42.43.101] port 22. It just stays there till I ^C it.. Here's my routing: $ ip route show 10.0.1.0/24 dev wlan1 proto kernel scope link src 10.0.1.61 metric 2 10.0.1.0/24 dev wlan1 proto kernel scope link src 10.0.1.61 metric 319 169.254.0.0/16 dev vboxnet0 proto kernel scope link src 169.254.128.223 metric 204 10.0.0.0/8 dev wlan0 proto kernel scope link src 10.42.43.1 default via 10.0.1.1 dev wlan1 proto static default via 10.0.1.1 dev wlan1 metric 319

  Read the article

• dpkg reporting as installed, uninstalled kernels

  - by Tony Martin

  I have run the following command to remove old kernels: dpkg -l 'linux-*' | sed '/^ii/!d;/'"$(uname -r | sed "s/\(.*\)-\([^0-9]\+\)/\1/")"'/d;s/^[^ ]* [^ ]* \([^ ]*\).*/\1/;/[0-9]/!d' | xargs sudo apt-get -y purge and only the current kernel is now installed, which I have confirmed in synaptic and by checking my boot partition. However, when I run: dpkg --list | grep linux-image I get the following response: rc linux-image-3.13.0-30-generic 3.13.0-30.55 amd64 Linux kernel image for version 3.13.0 on 64 bit x86 SMP rc linux-image-3.13.0-32-generic 3.13.0-32.57 amd64 Linux kernel image for version 3.13.0 on 64 bit x86 SMP ii linux-image-3.13.0-34-generic 3.13.0-34.60 amd64 Linux kernel image for version 3.13.0 on 64 bit x86 SMP rc linux-image-extra-3.13.0-30-generic 3.13.0-30.55 amd64 Linux kernel extra modules for version 3.13.0 on 64 bit x86 SMP rc linux-image-extra-3.13.0-32-generic 3.13.0-32.57 amd64 Linux kernel extra modules for version 3.13.0 on 64 bit x86 SMP ii linux-image-extra-3.13.0-34-generic 3.13.0-34.60 amd64 Linux kernel extra modules for version 3.13.0 on 64 bit x86 SMP ii linux-image-generic 3.13.0.34.40 amd64 Generic Linux kernel image Probably not a problem, but just wondering why versions -30 and -32 are reported as present. Can it be rectified? TIA

  Read the article

• Exadata???DiskGroup

  - by Liu Maclean(???)

  Exadata???Asm Diskgroup ???????: 1.??dcli -g /home/oracle/cell_group -l root cellcli -e list griddisk ????active?griddisk [root@dm01db01 ~]# dcli -g /home/oracle/cell_group -l root cellcli -e list griddisk dm01cel01: DATA_DM01_CD_00_dm01cel01 active dm01cel01: DATA_DM01_CD_01_dm01cel01 active dm01cel01: DATA_DM01_CD_02_dm01cel01 active dm01cel01: DATA_DM01_CD_03_dm01cel01 active dm01cel01: DATA_DM01_CD_04_dm01cel01 active dm01cel01: DATA_DM01_CD_05_dm01cel01 active dm01cel01: DATA_DM01_CD_06_dm01cel01 active dm01cel01: DATA_DM01_CD_07_dm01cel01 active dm01cel01: DATA_DM01_CD_08_dm01cel01 active dm01cel01: DATA_DM01_CD_09_dm01cel01 active dm01cel01: DATA_DM01_CD_10_dm01cel01 active dm01cel01: DATA_DM01_CD_11_dm01cel01 active dm01cel01: DBFS_DG_CD_02_dm01cel01 active dm01cel01: DBFS_DG_CD_03_dm01cel01 active dm01cel01: DBFS_DG_CD_04_dm01cel01 active dm01cel01: DBFS_DG_CD_05_dm01cel01 active dm01cel01: DBFS_DG_CD_06_dm01cel01 active dm01cel01: DBFS_DG_CD_07_dm01cel01 active dm01cel01: DBFS_DG_CD_08_dm01cel01 active dm01cel01: DBFS_DG_CD_09_dm01cel01 active dm01cel01: DBFS_DG_CD_10_dm01cel01 active dm01cel01: DBFS_DG_CD_11_dm01cel01 active dm01cel01: RECO_DM01_CD_00_dm01cel01 active dm01cel01: RECO_DM01_CD_01_dm01cel01 active dm01cel01: RECO_DM01_CD_02_dm01cel01 active dm01cel01: RECO_DM01_CD_03_dm01cel01 active dm01cel01: RECO_DM01_CD_04_dm01cel01 active dm01cel01: RECO_DM01_CD_05_dm01cel01 active dm01cel01: RECO_DM01_CD_06_dm01cel01 active dm01cel01: RECO_DM01_CD_07_dm01cel01 active dm01cel01: RECO_DM01_CD_08_dm01cel01 active dm01cel01: RECO_DM01_CD_09_dm01cel01 active dm01cel01: RECO_DM01_CD_10_dm01cel01 active dm01cel01: RECO_DM01_CD_11_dm01cel01 active dm01cel02: DATA_DM01_CD_00_dm01cel02 active dm01cel02: DATA_DM01_CD_01_dm01cel02 active dm01cel02: DATA_DM01_CD_02_dm01cel02 active dm01cel02: DATA_DM01_CD_03_dm01cel02 active dm01cel02: DATA_DM01_CD_04_dm01cel02 active dm01cel02: DATA_DM01_CD_05_dm01cel02 active dm01cel02: DATA_DM01_CD_06_dm01cel02 active dm01cel02: DATA_DM01_CD_07_dm01cel02 active dm01cel02: DATA_DM01_CD_08_dm01cel02 active dm01cel02: DATA_DM01_CD_09_dm01cel02 active dm01cel02: DATA_DM01_CD_10_dm01cel02 active dm01cel02: DATA_DM01_CD_11_dm01cel02 active dm01cel02: DBFS_DG_CD_02_dm01cel02 active dm01cel02: DBFS_DG_CD_03_dm01cel02 active dm01cel02: DBFS_DG_CD_04_dm01cel02 active dm01cel02: DBFS_DG_CD_05_dm01cel02 active dm01cel02: DBFS_DG_CD_06_dm01cel02 active dm01cel02: DBFS_DG_CD_07_dm01cel02 active dm01cel02: DBFS_DG_CD_08_dm01cel02 active dm01cel02: DBFS_DG_CD_09_dm01cel02 active dm01cel02: DBFS_DG_CD_10_dm01cel02 active dm01cel02: DBFS_DG_CD_11_dm01cel02 active dm01cel02: RECO_DM01_CD_00_dm01cel02 active dm01cel02: RECO_DM01_CD_01_dm01cel02 active dm01cel02: RECO_DM01_CD_02_dm01cel02 active dm01cel02: RECO_DM01_CD_03_dm01cel02 active dm01cel02: RECO_DM01_CD_04_dm01cel02 active dm01cel02: RECO_DM01_CD_05_dm01cel02 active dm01cel02: RECO_DM01_CD_06_dm01cel02 active dm01cel02: RECO_DM01_CD_07_dm01cel02 active dm01cel02: RECO_DM01_CD_08_dm01cel02 active dm01cel02: RECO_DM01_CD_09_dm01cel02 active dm01cel02: RECO_DM01_CD_10_dm01cel02 active dm01cel02: RECO_DM01_CD_11_dm01cel02 active dm01cel03: DATA_DM01_CD_00_dm01cel03 active dm01cel03: DATA_DM01_CD_01_dm01cel03 active dm01cel03: DATA_DM01_CD_02_dm01cel03 active dm01cel03: DATA_DM01_CD_03_dm01cel03 active dm01cel03: DATA_DM01_CD_04_dm01cel03 active dm01cel03: DATA_DM01_CD_05_dm01cel03 active dm01cel03: DATA_DM01_CD_06_dm01cel03 active dm01cel03: DATA_DM01_CD_07_dm01cel03 active dm01cel03: DATA_DM01_CD_08_dm01cel03 active dm01cel03: DATA_DM01_CD_09_dm01cel03 active dm01cel03: DATA_DM01_CD_10_dm01cel03 active dm01cel03: DATA_DM01_CD_11_dm01cel03 active dm01cel03: DBFS_DG_CD_02_dm01cel03 active dm01cel03: DBFS_DG_CD_03_dm01cel03 active dm01cel03: DBFS_DG_CD_04_dm01cel03 active dm01cel03: DBFS_DG_CD_05_dm01cel03 active dm01cel03: DBFS_DG_CD_06_dm01cel03 active dm01cel03: DBFS_DG_CD_07_dm01cel03 active dm01cel03: DBFS_DG_CD_08_dm01cel03 active dm01cel03: DBFS_DG_CD_09_dm01cel03 active dm01cel03: DBFS_DG_CD_10_dm01cel03 active dm01cel03: DBFS_DG_CD_11_dm01cel03 active dm01cel03: RECO_DM01_CD_00_dm01cel03 active dm01cel03: RECO_DM01_CD_01_dm01cel03 active dm01cel03: RECO_DM01_CD_02_dm01cel03 active dm01cel03: RECO_DM01_CD_03_dm01cel03 active dm01cel03: RECO_DM01_CD_04_dm01cel03 active dm01cel03: RECO_DM01_CD_05_dm01cel03 active dm01cel03: RECO_DM01_CD_06_dm01cel03 active dm01cel03: RECO_DM01_CD_07_dm01cel03 active dm01cel03: RECO_DM01_CD_08_dm01cel03 active dm01cel03: RECO_DM01_CD_09_dm01cel03 active dm01cel03: RECO_DM01_CD_10_dm01cel03 active dm01cel03: RECO_DM01_CD_11_dm01cel03 active ??????????griddisk, ?????’cellcli -e drop griddisk’ ?’cellcli -e create griddisk’????griddisk ,??????drop DBFS_DG???griddisk 2.??ASM???create disk group ?????CELL?IP,????????????? [root@dm01db02 ~]# cat /etc/oracle/cell/network-config/cellip.ora cell="192.168.64.131" cell="192.168.64.132" cell="192.168.64.133" SQL> create diskgroup DATA_MAC normal redundancy 2 DISK 3 'o/192.168.64.131/RECO_DM01_CD_*_dm01cel01' 4 ,'o/192.168.64.132/RECO_DM01_CD_*_dm01cel02' 5 ,'o/192.168.64.133/RECO_DM01_CD_*_dm01cel03' 6 attribute 7 'AU_SIZE'='4M', 8 'CELL.SMART_SCAN_CAPABLE'='TRUE', 9 'compatible.rdbms'='11.2.0.2', 10 'compatible.asm'='11.2.0.2' 11 / 3. MOUNT ???DISKGROUP ALTER DISKGROUP DATA_MAC mount ; 4.???crsctl start/stop resource ora.DATA_MAC.dg ?????

  Read the article

• IIS 7.5 refuses to load 64-bit assembly - possible CAS problem?

  - by Rune

  Hi, I just downloaded the Orchard CMS, opened it up in VS2008 and hit F5: Everything runs fine. I then created a website in IIS 7.5 and pointed it to the web project's directory and set up permissions correctly (I hope). I downloaded the 64-bit version System.Data.SQLite as suggested here: Orchard Work Item 14798 and here: SO: Could not load file or assembly 'System.Data.SQLite'. The site runs in Full Trust. When I point my browser to the site running through IIS I get Could not load file or assembly 'System.Data.SQLite, Version=1.0.65.0, Culture=neutral, PublicKeyToken=db937bc2d44ff139' or one of its dependencies. Failed to grant minimum permission requests. I don't know much about Code Access Security (if that is even what's at play here), so I am at a loss here. What am I doing wrong / not understanding / not seeing? How do I provide appropriate permissions and to whom / what? Is there any hope of ever deploying this application to a hoster where I am only allowed to run in Medium Trust? Any help, pointers or suggestions would be greatly appreciated. Thanks. NOTE: the question is not why this initially worked when run through Cassini. The answer to that question is contained in the answer to the SO question referenced above.

  Read the article

• How to compile a C DLL for 64 bit with Visual Studio 2010?

  - by Daren Thomas

  I have a DLL written in C in source code. This is the code for the General Polygon Clipper (in case you are interested). I'm using it in a C# project via the C# wrapper provided on the homepage. This comes with a precompiled DLL. Since switching to a 64bit Development machine with Visual Studio 2010 and Windows 7 64 bit, the application won't run anymore. This is the error I get: An attempt was made to load a program with an incorrect format. This is because of DLLImporting the 32bit gpc.dll, as I have gathered from stuff found on the web. I assume this will all go away if I recompile the DLL to 64bit, but can't for the love of me figure out how to do so. My C skills are basic, in that I can write a C program with the GNU tools, but have no experience with various compilers / processors / IDEs etc. I believe I could port this to C#. By that I mean I trust myself to actually pull it off. But I'd prefer not to, since it is a lot of work that I'd prefer a compiler to do for me ;)

  Read the article

• Analyzing Windows crash dumps generated on XP/32 machines with Win7/64 ?

  - by Martin

  We have a problem with analyzing our Windows crash-dumps that were created on customer Windows XP/32 boxes on our development machines. Many of our development machines are now Win7/64 boxes, but it appears that the crash-dumps generated under Windows XP cannot full resolve their binary dependency, thereby leading to warnings when displaying the call stacks in Visual Studio (2005). For example, the msvcr80.dll cannot be resolved when loaded from a Win7 machine when the dump was generated on Windows XP: On XP, the WinSxS path appears to be C:\WINDOWS\WinSxS\x86_Microsoft.VC80.CRT_1fc8b3b9a1e18e3b_8.0.50727.4053_x-ww_e6967989\msvcr80.dll -- on Win7, the WinSxS path to the same DLL version seems to be: x86_microsoft.vc80.crt_1fc8b3b9a1e18e3b_8.0.50727.4053_none_d08d7da0442a985d (I got this info from a forum thread on codeguru that link to an msdn article.) Visual Studio (2005) can now no longer correctly resolve the binaries for the crash-dump. How can I get Visual Studio to resolve all the correct binaries for my dump file? Note: I have already correctly set up the symbol server. The public symbols for most system DLLs (kernel32.dll, etc) and our symbols of our own DLLs are correctly loaded. It is just that the symbols of DLLs that reside in the WinSxS folder are not loaded, because it appears that Vista/7 uses a different path scheme for these DLLs than XP does and therefore Visual Studio cannot find the dll (not the pdb) on the local dev machine and so cannot load the corresponding symbols for the dump file.

  Read the article

• How Can I: Generate 40/64 Bit WEP Key In Python?

  - by Aktariel

  So, I've been beating my head against the wall of this issue for several months now, partly because it's a side interest and partly because I suck at programming. I've searched and researched all across the web, but have not had any luck (except one small bit of success; see below), so I thought I might try asking the experts. What I am trying to do is, as the title suggests, generate a 40/64 bit WEP key from a passphrase, according to the "de facto" standard. (A site such as [http://www.powerdog.com/wepkey.cgi] produces the expected outputs.) I have already written portions of the script that take inputs and write them to a file; one of the inputs would be the passphrase, sanitized to lower case. For the longest time I had no idea what the defacto standard was, much less how to even go about implementing it. I finally stumbled across a paper (http://www.lava.net/~newsham/wlan/WEP_password_cracker.pdf) that sheds as much light as I've had yet on the issue (page 18 has the relevant bits). Apparently, the passphrase is "mapped to a 32-bit value with XOR," the result of which is then used as the seed for a "linear congruential PRNG (which one of the several PRNGs Python has would fit this description, I don't know), and then from that result several bits of the result are taken. I have no idea how to go about implementing this, since the description is rather vague. What I need is help in writing the generator in Python, and also in understanding how exactly the key is generated. I'm not much of a programmer, so explanations are appreciated as well. (Yes, I know that WEP isn't secure.)

  Read the article

• UnauthorizedAccessException in ComRegisterFunction when accessing registry on Win 7 64.

  - by sanbornc

  I have a [ComRegisterFunction] that I am using to register a BHO Internet explorer extension. During registration on 64-bit windows 7 machines, a UnauthorizedAccessException is thrown on the call to subKey.SetValue("NoExplorer", 1). The registry appears to have BHO's located @ \HKLM\SOFTWARE\Wow6432Node\Microsoft\Windows\CurrentVersion\explorer\Browser Helper Objects, however, I get them same exception when trying to register there. Any Help would be appreciated. [ComRegisterFunction] public static void RegisterBho(Type type) { string BhoKeyName= "Software\\Microsoft\\Windows\\CurrentVersion\\Explorer\\Browser Helper Objects"; RegistryKey registryKey = Registry.LocalMachine.OpenSubKey(BhoKeyName, true) ?? Registry.LocalMachine.CreateSubKey(BhoKeyName); if(registryKey == null) throw new ApplicationException("Unable to register Bho"); registryKey.Flush(); string guid = type.GUID.ToString("B"); RegistryKey subKey = registryKey.OpenSubKey(guid) ?? registryKey.CreateSubKey(guid); if (subKey == null) throw new ApplicationException("Unable to register Bho"); subKey.SetValue("NoExplorer", 1); registryKey.Close(); subKey.Close(); }

  Read the article

• What does the ".align" x86 Assembler directive do exactly? [migrated]

  - by Sinister Clock

  I will list exactly what I do not understand, and show you the parts I can not understand as well. First off, The .Align Directive .align integer, pad. The .align directive causes the next data generated to be aligned modulo integer bytes 1.~ ? : What is implied with "causes the next data generated to be aligned modulo integer bytes?" I can surmise that the next data generated is a memory-to-register transfer, no? Modulo would imply the remainder of a division. I do not understand "to be aligned modulo integer bytes"....... What would be a remainder of a simple data declaration, and how would the next data generated being aligned by a remainder be useful? If the next data is aligned modulo, that is saying the next generated data, whatever that means exactly, is the remainder of an integer? That makes absolutely no sense. What specifically would the .align, say, .align 8 directive issued in x86 for a data byte compiled from a C char, i.e., char CHARACTER = 0; be for? Or specifically coded directly with that directive, not preliminary Assembly code after compiling C? I have debugged in Assembly and noticed that any C/C++ data declarations, like chars, ints, floats, etc. will insert the directive .align 8 to each of them, and add other directives like .bss, .zero, .globl, .text, .Letext0, .Ltext0. What are all of these directives for, or at least my main asking? I have learned a lot of the main x86 Assembly instructions, but never was introduced or pointed at all of these strange directives. How do they affect the opcodes, and are all of them necessary?

  Read the article

• Can't make nodejs mingw32: pkg-config can't find gnutils

  - by valya

  I'm trying to compile nodejs using MSYS, mingw32 on Windows 7-64 Valentin Golev@VALYASNOTEBOOK /home/Valentin_Golev/nodejs $ ./configure Checking for program CL : ok C:\Program Files (x86)\Microsoft V isual Studio 10.0\VC\BIN\x86_amd64\CL.exe Checking for program CL : ok C:\Program Files (x86)\Microsoft V isual Studio 10.0\VC\BIN\CL.exe Checking for program CL : ok C:\Program Files (x86)\Microsoft V isual Studio 10.0\VC\BIN\amd64\CL.exe Checking for program CL : ok c:\Program Files (x86)\Microsoft V isual Studio 9.0\VC\BIN\CL.exe Checking for program CL : ok c:\Program Files (x86)\Microsoft V isual Studio 9.0\VC\BIN\CL.exe Checking for program CL : ok c:\Program Files (x86)\Microsoft V isual Studio 9.0\VC\BIN\x86_amd64\CL.exe Checking for program CL : ok c:\Program Files (x86)\Microsoft V isual Studio 9.0\VC\BIN\CL.exe Checking for program CL : ok c:\Program Files (x86)\Microsoft V isual Studio 9.0\VC\BIN\amd64\CL.exe Checking for program CL : ok c:\Program Files (x86)\Microsoft V isual Studio 9.0\VC\BIN\amd64\CL.exe Checking for program LINK : ok c:\Program Files (x86)\Microsoft V isual Studio 9.0\VC\BIN\amd64\LINK.exe Checking for program LIB : ok c:\Program Files (x86)\Microsoft V isual Studio 9.0\VC\BIN\amd64\LIB.exe Checking for program MT : ok C:\Program Files\\Microsoft SDKs\W indows\v6.0A\bin\x64\MT.exe Checking for program RC : ok C:\Program Files\\Microsoft SDKs\W indows\v6.0A\bin\x64\RC.exe Checking for msvc : ok Checking for msvc : ok Checking for library dl : not found Checking for library execinfo : not found Checking for gnutls >= 2.5.0 : fail --- libeio --- Checking for library pthread : not found Checking for function pthread_create : not found error: the configuration failed (see 'C:\\msys\\1.0\\home\\Valentin_Golev\\node js\\build\\config.log') I have gnutils built and installed! I've checked the config.log, and there was a command: pkg-config --errors-to-stdout --print-errors --atleast-version=2.5.0 gnutls I typed it in the console Valentin Golev@VALYASNOTEBOOK /home/Valentin_Golev/nodejs $ pkg-config --errors-to-stdout --print-errors --atleast-version=2.5.0 gnutls Package gnutls was not found in the pkg-config search path. Perhaps you should add the directory containing `gnutls.pc' to the PKG_CONFIG_PATH environment variable No package 'gnutls' found But, Valentin Golev@VALYASNOTEBOOK ~ $ $PKG_CONFIG_PATH sh: c:/msys/1.0/local/lib/pkgconfig: is a directory Valentin Golev@VALYASNOTEBOOK ~ $ cd $PKG_CONFIG_PATH Valentin Golev@VALYASNOTEBOOK /local/lib/pkgconfig $ ls gnutls-extra.pc gnutls.pc What am I doing wrong?

  Read the article

• What's going on here? Repeating rows in random list of lists.

  - by Jesse Aldridge

  I expected to get a grid of unique random numbers. Instead each row is the same sequence of numbers. What's going on here? from pprint import pprint from random import random nrows, ncols = 5, 5 grid = [[0] * ncols] * nrows for r in range(nrows): for c in range(ncols): grid[r][c] = int(random() * 100) pprint(grid) Example output: [[64, 82, 90, 69, 36], [64, 82, 90, 69, 36], [64, 82, 90, 69, 36], [64, 82, 90, 69, 36], [64, 82, 90, 69, 36]]

  Read the article

• MUL instruction help

  - by Tanner Babcock

  I've read a few tutorials and examples, but I cannot wrap my head around how the MUL instruction works. I've used ADD and SUB without problems. So apparently this instruction multiplies its operand by the value in a register. What register (eax, ebp, esp, etc.) is multiplied by the first operand? And what register is the result stored in, so I can move it to the stack? Sorry, I'm just learning x86 assembly. When I try to compile this line... mull $9 I get, "Error: suffix or operands invalid for 'mul'". Can anyone help me out? Thanks. EDIT: OK Madhur, I replaced "mull" with "mul" and I'm still getting the same error. Here's the whole source. .globl _main _main: pushl %ebp movl %esp, %ebp subl $8, %esp movl $7, %eax mul $9 movl %eax, (%esp) call _putchar xorl %eax, %eax leave ret

  Read the article

• BPEL 11.1.1.6 Certified for Prebuilt E-Business Suite 12.1.3 SOA Integrations

  - by Steven Chan (Oracle Development)

  Service Oriented Architecture (SOA) integrations with Oracle E-Business Suite can either be custom integrations that you build yourself or prebuilt integrations from Oracle.  For more information about the differences between the two options for SOA integrations, see this previously-published certification announcement. There are five prebuilt BPEL business processes by Oracle E-Business Suite Release 12 product teams: Oracle Price Protection (DPP) Complex Maintenance, Repair & Overhaul (CMRO/AHL) Oracle Transportation Management (WMS, WSH, PO) Advanced Supply Chain Planning (MSC) Product Information Management (PIM/EGO) Last year we announced the certification of BPEL 11.1.1.5 for Prebuilt E-Business Suite 12.1.3 SOA integrations.  The five prebuilt BPEL processes have now been certified with Oracle BPEL Process Manager 11g version 11.1.1.6 (in Oracle Fusion Middleware SOA Suite 11g).  These prebuilt BPEL processes are certified with Oracle E-Business Suite Release 12.1.3 and higher. Note: The Supply Chain Trading Connector (CLN) product team has opted not to support BPEL 11g with their prebuilt business processes previously certified with BPEL 10.1.3.5.  If you have a requirement for that certification, I would recommend contacting your Oracle account manager to ensure that the Supply Chain team is notified appropriately.  For additional information about prebuilt integrations with Oracle E-Business Suite Release 12.1.3, please refer to the following documentation: Integrating Oracle E-Business Suite Release 12 with Oracle BPEL available in Oracle SOA Suite 11g (Note 1321776.1) Oracle Fusion Middleware 11g (11.1.1.6.0) Documentation Library Installing Oracle SOA Suite and Oracle Business Process Management Suite Release Notes for Oracle Fusion Middleware 11g (11.1.1.6) Certified Platforms Linux x86 (Oracle Linux 4, 5) Linux x86 (RHEL 5) Linux x86 (SLES 10) Linux x86-64 (Oracle Linux 4, 5, 6) Linux x86-64 (RHEL 5) Linux x86-64 (SLES 10)  Oracle Solaris on SPARC (64-bit) (9, 10, 11) HP-UX Itanium (11.23, 11.31) HP-UX PA-RISC (64-bit) (11.23, 11.31) IBM AIX on Power Systems (64-bit) (5.3, 6.1, 7) IBM: Linux on System z (RHEL 5, SLES 10) Microsoft Windows Server (32-bit) (2003, 2008)  Microsoft Windows x64 (64-bit) (2008 R2) Getting SupportIf you need support for the prebuilt EBS 12.1.3 BPEL business processes, you can log Service Requests against the Applications Technology Group product family. Related Articles BPEL 11.1.1.5 Certified for Prebuilt E-Business Suite 12.1.3 SOA Integrations Webcast Replay Available: SOA Integration Options for E-Business Suite Securing E-Business Suite Web Services with Integrated SOA Gateway

  Read the article

• Endianness inside CPU registers

  - by Abhishek Tamhane

  I need help understanding endianness inside CPU registers of x86 processors. I wrote this small assembly program: section .data section .bss section .text global _start _start: nop mov eax, 0x78FF5ABC mov ebx,'WXYZ' nop ; GDB breakpoint here. mov eax, 1 mov ebx, 0 int 0x80 I ran this program in GDB with a breakpoint on line number 10 (commented in the source above). At this breakpoint, info registers shows the value of eax=0x78ff5abc and ebx=0x5a595857. Since the ASCII codes for W, X, Y, Z are 57, 58, 59, 5A respectively; and intel is little endian, 0x5a595857 seems like the correct byte order (least significant byte first). Why isn't then the output for eax register 0xbc5aff78 (least significant byte of the number 0x78ff5abc first) instead of 0x78ff5abc?

  Read the article

• Cannot get Virtualbox to install properly on Ubuntu 12.04

  - by lopac1029

  I cannot get Virtualbox to install properly on my 12.04. I first went with a manual install for the .deb from the old builds section of the Virtualbox page. That .deb opened up the Software Center and installed. Then I got the error coming up of VT-x/AMD-V hardware acceleration is not available on your system. Your 64-bit guest will fail to detect a 64-bit CPU and will not be able to boot. which I can only assume was due to my Ubuntu version being 32-bit (System Details - Overview - OC type: 32-bit, right?) So I followed these instructions to remove the .deb manually, restarted my laptop, and then FOUND the actual Virtualbox install in the Software Center and installed from that (assuming it would give me the correct version I need for my system) So after all that (and then some), I'm still getting the same error when I connect to my new job's project in Virtualbox. Can anyone point me in the right direction of what to do here? This is the first time I've ever worked with Virtualbox, and no one at this company is using Ubuntu, so I'm on my own here. EDIT: Here is the direct info from running the 2 suggested commands Inspiron-1750-brick:~ $lscpu Architecture: i686 CPU op-mode(s): 32-bit, 64-bit Byte Order: Little Endian CPU(s): 2 On-line CPU(s) list: 0,1 Thread(s) per core: 1 Core(s) per socket: 2 Socket(s): 1 Vendor ID: GenuineIntel CPU family: 6 Model: 23 Stepping: 10 CPU MHz: 2100.000 BogoMIPS: 4189.45 L1d cache: 32K L1i cache: 32K L2 cache: 2048K Inspiron-1750-brick:~ $cat /proc/cpuinfo processor : 0 vendor_id : GenuineIntel cpu family : 6 model : 23 model name : Intel(R) Core(TM)2 Duo CPU T6500 @ 2.10GHz stepping : 10 microcode : 0xa07 cpu MHz : 1200.000 cache size : 2048 KB physical id : 0 siblings : 2 core id : 0 cpu cores : 2 apicid : 0 initial apicid : 0 fdiv_bug : no hlt_bug : no f00f_bug : no coma_bug : no fpu : yes fpu_exception : yes cpuid level : 13 wp : yes flags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe nx lm constant_tsc arch_perfmon pebs bts aperfmperf pni dtes64 monitor ds_cpl est tm2 ssse3 cx16 xtpr pdcm sse4_1 xsave lahf_lm dtherm bogomips : 4189.80 clflush size : 64 cache_alignment : 64 address sizes : 36 bits physical, 48 bits virtual power management: processor : 1 vendor_id : GenuineIntel cpu family : 6 model : 23 model name : Intel(R) Core(TM)2 Duo CPU T6500 @ 2.10GHz stepping : 10 microcode : 0xa07 cpu MHz : 1200.000 cache size : 2048 KB physical id : 0 siblings : 2 core id : 1 cpu cores : 2 apicid : 1 initial apicid : 1 fdiv_bug : no hlt_bug : no f00f_bug : no coma_bug : no fpu : yes fpu_exception : yes cpuid level : 13 wp : yes flags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe nx lm constant_tsc arch_perfmon pebs bts aperfmperf pni dtes64 monitor ds_cpl est tm2 ssse3 cx16 xtpr pdcm sse4_1 xsave lahf_lm dtherm bogomips : 4189.45 clflush size : 64 cache_alignment : 64 address sizes : 36 bits physical, 48 bits virtual power management:

  Read the article

• Why don't stacks grow upwards (for security)?

  - by AshleysBrain

  This is related to the question 'Why do stacks typically grow downwards?', but more from a security point of view. I'm generally referring to x86. It strikes me as odd that the stack would grow downwards, when buffers are usually written to upwards in memory. For example a typical C++ string has its end at a higher memory address than the beginning. This means that if there's a buffer overflow you're overwriting further up the call stack, which I understand is a security risk, since it opens the possibility of changing return addresses and local variable contents. If the stack grew upwards in memory, wouldn't buffer overflows simply run in to dead memory? Would this improve security? If so, why hasn't it been done? What about x64, do those stacks grow upwards and if not why not?

  Read the article

• OBIEE 11.1.1.5.0 Bundle Patch 2 is available

  - by mshahi

  Oracle BI EE 11.1.1.5.0 Bundle Patch 2 is available. The Patch number is 13611078 and it can be downloaded from Oracle Support (you can download it without password). This patch currently is available on Microsoft Windows x64 (64 bit), Linux x86 - 64 bit, IBM AIX on Power System (64 bit) and Oracle Solaris Sparc (64 bit). Remaining four platforms Win32, Linux32, HP-Itanium, and Solaris x86-64 are expected 3-4 weeks later. This Patch has thoroughly been tested and signed off by BI QA Team.  Important things to know: 1. All the customers are advised to apply this patch as it contains around 248 bug fixes. Please read the README file for all the bug fixes contained in this patch.   2. This patch can be applied via opatch. Please follow the standard process of applying this patch using opatch, i.e. stop all BI System processes via opmnctl, Stop WLS Managed and Admin Servers, Apply Patch, Start WLS Admin and Managed Servers, Check if all the J2EE applications are running fine, Start all BI System Processes via opmnctl command, and verify your fixes. It is advised to test this patch on Non Productions Instances first, run all the required tests / regressions and then move it to Production.    3. This Bundle Patch is cumulative to 11.1.1.5.0 BP1 (13562882) which was released in January 2012 on Linux x86 - 64 bit which contained around 64 bug fixes. Customers who have applied 11.1.1.5.0 BP1, will get expected OPatch conflict message, they can safely roll back BP1 prior to installing this BP2 or let opatch roll back BP1 during its application process.   4. Customer who have applied some one off patches and these one off patches are also part of 11.1.1.5.0 BP2, they can also roll back their existing one off patches after confirming that their fixes are part of BP2.    5. This Bundle Patch is not cumulative on top of 11.1.1.5.0, meaning this bundle patch does not contain all the one off fixes that were delivered on top of 11.1.1.5.0. All the remaining one off fixes delivered so far, will be available in next scheduled bundle patch i.e. 11.1.1.5.0 BP3. Please check the README file and let support know if your existing fixes are not part of BP2, so that support can open One Off Backport (OOB) request to have them included in next patch i.e. BP3.   6. 11.1.1.5.0 BP3 is in planning stages, and dates for it's availability will be announced in next couple of weeks.

  Read the article

< Previous Page | 67 68 69 70 71 72 73 74 75 76 77 78  | Next Page >