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  • Mysql Date formats and url query

    - by jasmine
    I want to make a url query with date. I have confused a little : There is a mysql table: calDate : varchar The query : $sql="select * from calTbl"; $result = mysql_query($sql); while ($row = mysql_fetch_array($result)) { $n = str_replace("/", "",$row['calDate']); echo '<a href="index.php?p='.$n.'">'.$n.'</a>'; } I want to see related event from query. Can I set apart month, day and year from this? Or what is the correct table design here? Thanks in advance

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  • Optimising (My)SQL Query

    - by Simon
    I usually use ORM instead of SQL and I am slightly out of touch on the different JOINs... SELECT `order_invoice`.*, `client`.*, `order_product`.*, SUM(product.cost) as net FROM `order_invoice` LEFT JOIN `client` ON order_invoice.client_id = client.client_id LEFT JOIN `order_product` ON order_invoice.invoice_id = order_product.invoice_id LEFT JOIN `product` ON order_product.product_id = product.product_id WHERE (order_invoice.date_created >= '2009-01-01') AND (order_invoice.date_created <= '2009-02-01') GROUP BY `order_invoice`.`invoice_id` The tables/ columns are logically names... it's an shop type application... the query works... it's just very very slow... I use the Zend Framework and would usually use Zend_Db_Table_Row::find(Parent|Dependent)Row(set)('TableClass') but I have to make lots of joins and I thought it'll improve performance by doing it all in one query instead of hundreds... Can I improve the above query by using more appropriate JOINs or a different implementation? Many thanks.

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  • modx revo snippet variable in query

    - by Meddie
    I noticed something weird when using a query in a snippet. When I have a query like this: $sql = 'SELECT * FROM table WHERE colomn = ' . $variable; And I echo $sql, the query reads: SELECT * FROM table WHERE colomn = <code class="php plain">2</code> .. wich will result in an error because the sql is no longer valid. So for now I use strip_tags to remove the code tag, but I find it not a very clean method. I couldnt find anything about this, so maybe someone can shed some light on this for me?

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  • Getting the final value to this MySQL query...

    - by Jack W-H
    I've got my database set up with three tables - code, tags, and code_tags for tagging posts. This will be the SQL query processed when a post is submitted. Each tag is sliced up by PHP and individually inserted using these queries. INSERT IGNORE INTO tags (tag) VALUES ('$tags[1]'); SELECT tags.id FROM tags WHERE tag = '$tags[1]' ORDER BY id DESC LIMIT 1; INSERT INTO code_tags (code_id, tag_id) VALUES ($codeid, WHAT_GOES_HERE?) The WHAT_GOES_HERE? value at the end is what I need to know. It needs to be the ID of the tag that the second query fetched. How can I put that ID into the third query? I hope I explained that correctly. I'll rephrase if necessary.

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  • how to simplify this database update query (php)

    - by krike
    How could I simplify this update instruction? Whenever a client buys an item it will update the sales with 1. $this->db->query('SELECT amount FROM shop_items WHERE itemid='.$itemid.''); $new_amount = $item->amount+1; if(!$this->db->query('UPDATE shop_items SET amount='.$new_amount.' WHERE itemid='.$itemid.'')): return false; endif; Can't I make it more simple so there are less lines, for example: if(!$this->db->query('UPDATE shop_items SET amount=_current_value_+1 WHERE itemid='.$itemid.'')): return false; endif; is this possible? if not thanks anyway

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  • Date range/query problem..

    - by Simon
    Am hoping someone can help me out a bit with date ranges... I have a table with 3 fields id, datestart, dateend I need to query this to find out if a pair of dates from a form are conflicting i.e table entry 1, 2010-12-01, 2010-12-09 from the form 2010-12-08, 20-12-15 select id from date_table where '2010-12-02' between datestart and dateend; That returns me the id that I want, but what I would like to do is to take the date range from the form and do a query similar to what I have got that will take both form dates 2010-12-08, 20-12-15 and query the db to ensure that there is no conflicting date ranges in the table. Am sat scratching my head with the problem... TIA

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  • Help needed with simple mysql group by query

    - by Jack
    This query fails when I add the line shown... :BEGIN FAIL: I have this so far Select Companyid, count(*) as cnt from mytable where State is not null and cnt = 1 <------------------------- FAIL group by CompanyID :END FAIL: Any way to do this? Here's a long winded background if it'll help.... I have a single table query. here's a sample of the table: CompanyID, State 1,OH 1,IL 1,NY 2,IL 3,NY 3,OH 4,NY 5,CA 5,WA I want a query that'll return something like this: 2,IL 4,NY I have this so far Select Companyid, count(*) as cnt from mytable where State is not null group by CompanyID This gives me a count of the number of records for each company. IE: 1,3 2,1 3,2 4,1 5,2 Now I want to filter the above list to just the two records with one result. I tried adding another where clause, but it failed: BEGIN FAIL: I have this so far Select Companyid, count(*) as cnt from mytable where State is not null and cnt = 1 <-------------------- FAIL group by CompanyID END FAIL:

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  • C# Dynamic Query Without A Database Model

    - by hitopp
    I have been searching the web for a solution to dynamic queries. I have found many different solutions (e.g. Linq to Sql, Dynamic Linq Expressions, Dynamic Query), but all of these solutions involve some sort of previous knowledge of the database (like a model in code). Maybe what I am asking is way off the deep end, but is there any possible way to dynamically query a database without a model? For example, a database has a Customers table with the following columns: CustomerID Name FavoriteColor I want to create a query as SELECT Name FROM Customers WHERE @0 = @1, where the two placeholders are populated dynamically. The resulting data does not tie to a model class and I would prefer to use some sort of framework to build the queries, not simple string concatenation. The System.Linq.Dynamic namespace came really close to fulfilling this request, but it uses a database model. I realize this is crazy, but I was just curious.

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  • Need help building SQL Query (simple JOIN)

    - by Newbie
    Hello! In my database, I have a "users", a "quests" and a "questings" table. A user can solve a quest. Solving a quest will save the "user_id" and the "quest_id" in my "questings" table. Now, I want to select all quests, a user has NOT solved (meaning there is no entry for this user and quest in "questings" table)! Let's say the user has the id 14. How to write this query? After solving this query, I want to filter the results, too. A quest and a user has a city, too. What to do for writing a query which returns all quests, a user has NOT solved yet, in the users city (user city == quest city)?

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  • MySQL query optimization.

    - by PiKey
    I'm so bad in making good MySQL queries. I've created this one: http://pastebin.com/GtDfgky8 products Table have about 17k rows, allegro Table have about 3k of rows. The query Idea is select all products, where stock_quanity 3, where is photo, and where is no product id in allegro table. Now query takes about 10 seconds... I have no idea how I can optimize this query. Please help my, I'll be thankfully! :) & Sorry for my bad English also

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  • Get count matches in query on large table very slow

    - by Roy Roes
    I have a mysql table "items" with 2 integer fields: seid and tiid The table has about 35000000 records, so it's very large. seid tiid ----------- 1 1 2 2 2 3 2 4 3 4 4 1 4 2 The table has a primary key on both fields, an index on seid and an index on tiid. Someone types in 1 or more tiid values and now I would like to get the seid with most results. For example when someone types 1,2,3, I would like to get seid 2 and 4 as result. They both have 2 matches on the tiid values. My query so far: SELECT COUNT(*) as c, seid FROM items WHERE tiid IN (1,2,3) GROUP BY seid HAVING c = (SELECT COUNT(*) as c, seid FROM items WHERE tiid IN (1,2,3) GROUP BY seid ORDER BY c DESC LIMIT 1) But this query is extremly slow, because of the large table. Does anyone know how to construct a better query for this purpose?

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  • MySQL Query, Date Range From "Blacklist"

    - by erbaker
    I have 2 databases. One is properties and the other is dates. In dates I have associated the land_id and a date (In YYYYMMDD format) which means that the date is not available. I need to formulate a query that a user can specify a start and end date, and then choose a property for which dates are available (not in the date database). How do airline and hotel websites do this kind of logic? I was thinking about taking the date range and picking all days in between and doing a query where the dates do not match and ordering it by number of results, but I can see how that could easily turn into an intense query. CREATE TABLE IF NOT EXISTS `dates` ( `id` int(11) NOT NULL AUTO_INCREMENT, `land_id` int(11) NOT NULL, `date` varchar(255) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=44 ; -- -- Dumping data for table `dates` -- INSERT INTO `dates` (`id`, `land_id`, `date`) VALUES (43, 1, '20100526'), (39, 1, '20100522'), (40, 1, '20100523'), (41, 1, '20100521'), (42, 1, '20100525');

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  • Query with multiple IN-statements but without the cartesian product

    - by Janne
    How could I make this kind of query e.g. in MySQL SELECT * FROM Table t WHERE t.a IN (1,2,3) AND t.b IN (4,5,6) AND t.c IN (7,8,9) ... so that the result would contain only the three rows: t.a|t.b|t.c ---+---+--- 1 | 4 | 7 2 | 5 | 8 3 | 6 | 9 The above query of course returns all the combinations of the values in the IN clauses but I would like to get just the ones where the first elements of each tuple match, second elements of each tuple match and so on. Is there any efficient way to do this? By the way is there some common term for this kind of query or concept? I'm having hard time coming up with the question's title because I can't put this into words..

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  • Simple PHP query question: LIKE

    - by pg
    When I replace $ordering = "apples, bananas, cranberries, grapes"; with $ordering = "apples, bananas, grapes"; I no longer want cranberries to be returned by my query, which I've written out like this: $query = "SELECT * from dbname where FruitName LIKE '$ordering'"; Of Course this doesn't work, because I used LIKE wrong. I've read through various manuals that describe how to use LIKE and it doesn't quite make sense to me. If I change the end of the db to "LIKE "apples"" that works for limiting it to just apples. Do I have to explode the ordering on the ", " or is there a way to do this in the query?

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  • MySQL Multiple "AND" Query

    - by Mark J
    I have a table with 2 columns (see below). A member can have multiple responses to a question RESPONSES --------- member_id INT response_id INT SAMPLE DATA member_id -- response_id 1 -- 3 1 -- 5 2 -- 1 2 -- 5 2 -- 9 3 -- 1 3 -- 5 3 -- 6 What I need to do is query the table for member that meet ALL response criteria. For example I need to select all members that have a response_id of 1 AND 5. I am using the following query: SELECT DISTINCT member_id FROM responses WHERE response_id = 1 AND response_id = 5. I would expect to get back member_id's 2,3. However I am getting nothing returned. I used EXPLAIN and it shows there is an error in my where query. What am I doing wrong? Also, is there a function similar to IN where all the criteria must be met in order to return true? Thanks for your help.

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  • how to import csv data into django models

    - by little_fish
    i have some csv data and i want to export into django models the example of csv data 1;"02-01-101101";"Worm Gear HRF 50";"Ratio 1 : 10";"input shaft, output shaft, direction A, color dark green"; 2;"02-01-101102";"Worm Gear HRF 50";"Ratio 1 : 20";"input shaft, output shaft, direction A, color dark green"; 3;"02-01-101103";"Worm Gear HRF 50";"Ratio 1 : 30";"input shaft, output shaft, direction A, color dark green"; 4;"02-01-101104";"Worm Gear HRF 50";"Ratio 1 : 40";"input shaft, output shaft, direction A, color dark green"; 5;"02-01-101105";"Worm Gear HRF 50";"Ratio 1 : 50";"input shaft, output shaft, direction A, color dark green"; and i have some django models name Product in Product there is some fields like name, description and price and i want to something like this product=Product() product.name = "Worm Gear HRF 70(02-01-101116)" product.description = "input shaft, output shaft, direction A, color dark green" product.price = 100

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  • nginx serving Django static media | 502 bad gateway

    - by MMRUser
    I'm trying to serve Django static media through nginx, Here's my nginx.conf server { listen 7777; listen localhost:7777; server_name example.com; location / { proxy_pass http://localhost:7777; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffer_size 4k; proxy_buffers 4 32k; proxy_busy_buffers_size 64k; proxy_temp_file_write_size 64k; } location /test-app-media/ { root /sites/mysite/staticmedia/; expires max; } } but give a 502 bad gateway error, the path to /sites/mysite/staticmedia/ is in the nginx root/ is that the problem.. Django running on Apache 2.2 + mod_wsgi nginx 0.7.65 Thanks..

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  • File Uploading In Google Application Engine Using Django

    - by Ayush
    I am using gae with django. I have an project named MusicSite with following url mapping- urls.py from django.conf.urls.defaults import * from MusicSite.views import MainHandler from MusicSite.views import UploadHandler from MusicSite.views import ServeHandler urlpatterns = patterns('',(r'^start/', MainHandler), (r'^upload/', UploadHandler), (r'^/serve/([^/]+)?', ServeHandler), ) There is an application MusicSite inside MusicFun with the following codes- views.py import os import urllib from google.appengine.ext import blobstore from google.appengine.ext import webapp from google.appengine.ext.webapp import blobstore_handlers from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app def MainHandler(request): response=HttpResponse() upload_url = blobstore.create_upload_url('http://localhost: 8000/upload/') response.write('') response.write('' % upload_url) response.write("""Upload File: """) return HttpResponse(response) def UploadHandler(request): upload_files=request.FILES['file'] blob_info = upload_files[0] response.redirect('http://localhost:8000/serve/%s' % blob_info.key()) class ServeHandler(blobstore_handlers.BlobstoreDownloadHandler): def get(self, resource): resource = str(urllib.unquote(resource)) blob_info = blobstore.BlobInfo.get(resource) self.send_blob(blob_info) now whenever a upload a file using /start and click Submit i am taken to a blank page with the following url- localhost:8000/_ah/upload/ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgHDA These random alphabets keep varying but the result is same. A blank page after every upload. Somebody please help. The server responses are as below- INFO:root:"GET /start/ HTTP/1.1" 200 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 - INFO:root:Internal redirection to http://localhost:8000/upload/ INFO:root:Upload handler returned 500 ERROR:root:Invalid upload handler response. Only 301, 302 and 303 statuses are permitted and it may not have a content body. INFO:root:"POST /_ah/upload/ ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgCDA HTTP/1.1" 500 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 -

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  • Reversing Django URLs With Extra Options

    - by Justin Voss
    Suppose I have a URLconf like below, and 'foo' and 'bar' are valid values for page_slug. urlpatterns = patterns('', (r'^page/(?P<page_slug>.*)/', 'myapp.views.someview'), ) Then, I could reconstruct the URLs using the below, right? >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/page/foo/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/page/bar/' But what if I change my URLconf to this? urlpatterns = patterns('', (r'^foo-direct/', 'myapp.views.someview', {'page_slug': 'foo'}), (r'^my-bar-page/', 'myapp.views.someview', {'page_slug': 'bar'}), ) I expected this result: >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/foo-direct/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/my-bar-page/' However, this throws a NoReverseMatch exception. I suspect I'm trying to do something impossible. Any suggestions on a saner way to accomplish what I want? Named URLs aren't an option, since I don't want other apps that link to these to need to know about the specifics of the URL structure (encapsulation and all that).

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  • Treebeard admin in Django

    - by Sharath
    I've setup Treebeard in Django and everything seems to have gone well. I tried to setup the admin system and I can see my models being presented in the admin interface. However, when I try to add new data using the admin interface, I get the following error in my template. The code still works fine, and I did a check in my DB and the data seems to be inserted properly. However, the view doesn't seem to load properly. Any idea about what is causing this?? The exception am getting is.. Caught an exception while rendering: Failed lookup for key [request] in u'[{\'action_index\': 0, \'block\': , , , , , , ]}, {\'block\': , , , ], , , , , \n \', ], , ], , , , ], , , \n \', , , , , , , , , ], , ], \n \']}, {\'cl\': , \'root_path\': None, \'actions_on_bottom\': False, \'title\': u\'Select album to change\', \'has_add_permission\': True, \'media\': , \'is_popup\': False, \'action_form\': , \'actions_on_top\': True, \'app_label\': \'gallery\'}, {\'MEDIA_URL\': \'\'}, {\'LANGUAGES\': ((\'ar\', \'Arabic\'), (\'bn\', \'Bengali\'), (\'bg\', \'Bulgarian\'), (\'ca\', \'Catalan\'), (\'cs\', \'Czech\'), (\'cy\', \'Welsh\'), (\'da\', \'Danish\'), (\'de\', \'German\'), (\'el\', \'Greek\'), (\'en\', \'English\'), (\'es\', \'Spanish\'), (\'et\', \'Estonian\'), (\'es-ar\', \'Argentinean Spanish\'), (\'eu\', \'Basque\'), (\'fa\', \'Persian\'), (\'fi\', \'Finnish\'), (\'fr\', \'French\'), (\'ga\', \'Irish\'), (\'gl\', \'Galician\'), (\'hu\', \'Hungarian\'), (\'he\', \'Hebrew\'), (\'hi\', \'Hindi\'), (\'hr\', \'Croatian\'), (\'is\', \'Icelandic\'), (\'it\', \'Italian\'), (\'ja\', \'Japanese\'), (\'ka\', \'Georgian\'), (\'ko\', \'Korean\'), (\'km\', \'Khmer\'), (\'kn\', \'Kannada\'), (\'lv\', \'Latvian\'), (\'lt\', \'Lithuanian\'), (\'mk\', \'Macedonian\'), (\'nl\', \'Dutch\'), (\'no\', \'Norwegian\'), (\'pl\', \'Polish\'), (\'pt\', \'Portuguese\'), (\'pt-br\', \'Brazilian Portuguese\'), (\'ro\', \'Romanian\'), (\'ru\', \'Russian\'), (\'sk\', \'Slovak\'), (\'sl\', \'Slovenian\'), (\'sr\', \'Serbian\'), (\'sv\', \'Swedish\'), (\'ta\', \'Tamil\'), (\'te\', \'Telugu\'), (\'th\', \'Thai\'), (\'tr\', \'Turkish\'), (\'uk\', \'Ukrainian\'), (\'zh-cn\', \'Simplified Chinese\'), (\'zh-tw\', \'Traditional Chinese\')), \'LANGUAGE_BIDI\': False, \'LANGUAGE_CODE\': \'en-us\'}, {}, {\'perms\': , \'messages\': [], \'user\': }, {}]' This happens after I hit the save button in Django admin. This is my admin.py implementation.. class MP_Album_Admin(TreeAdmin): pass admin.site.register(Album,MP_Album_Admin)

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  • Django 404 page not showing up

    - by Matthew Doyle
    Hey all, I'm in the middle of putting up my first django application on shared hosting. This should be an easy thing, but I am just not seeing it. I tried to follow the directions of the django documentation, and created a 404.html page within my template folder. I just wrote "This is a 404 page." in the .html file. I also did the same thing for a 500.html page and wrote in it "This is a 500 page." However when I hit a 'bad page' I get a standard 404 page from the browser (Oops! This link appears to be broken. in Chrome) when I would expect "This is a 404 page." What's even more interesting is out of frustration I wrote {% asdfjasdf %} in the 404.html, and instead of getting the "Oops!..." error I get "This is a 500 page," so it definitely sees the 404.html template. Here's what I can confirm: Debug = False I am running apache on a shared hosting I have not done anything special with .htaccess and 404 errors. If I run with Debug = True, it says it's a 404 error. I am using FastCGI Anything else anyone think I could try? Thank you very much!

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  • Mimic remote API or extend existing django model

    - by drozzy
    I am in a process of designing a client for a REST-ful web-service. What is the best way to go about representing the remote resource locally in my django application? For example if the API exposes resources such as: List of Cars Car Detail Car Search Dealership summary So far I have thought of two different approaches to take: Try to wrangle the django's models.Model to mimic the native feel of it. So I could try to get some class called Car to have methods like Car.objects.all() and such. This kind of breaks down on Car Search resources. Implement a Data Access Layer class, with custom methods like: Car.get_all() Car.get(id) CarSearch.search("blah") So I will be creating some custom looking classes. Has anyone encoutered a similar problem? Perhaps working with some external API's (i.e. twitter?) Any advice is welcome. PS: Please let me know if some part of question is confusing, as I had trouble putting it in precise terms.

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  • Django server side AJAX validation

    - by MMRUser
    Hi, Recently I'm trying to implement a simple Django application that include one server side AJAX validation, it's a simple form input field (username). I have used a pre-built in line AJAX validation library which uses jQuery. So the code goes like this HTML snippet <form id="simpleform" method="post" action="/done/"> Username:<input value="" class="validate[required,custom[noSpecialCaracters],length[0,20],ajax[ajaxUser]]" type="text" name="user" id="user" /> <input class="submit" type="submit" value="Validate"/> </form> The server side code snippet (embedded in to a php script) /* RECEIVE VALUE */ $validateValue=$_POST['validateValue']; $validateId=$_POST['validateId']; $validateError=$_POST['validateError']; /* RETURN VALUE */ $arrayToJs = array(); $arrayToJs[0] = $validateId; $arrayToJs[1] = $validateError; if($validateValue =="testname"){ // validate?? $arrayToJs[2] = "true"; // RETURN TRUE echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; // RETURN ARRAY WITH success }else{ for($x=0;$x<1000000;$x++){ if($x == 990000){ $arrayToJs[2] = "false"; echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; // RETURN ARRAY WITH ERROR } } } So my question is that how do I get this in to Python code (in order to use in Django environment) how do I get the user name from the input field in to the back end,I think the server side script snippet already does it but I want to know how to use this in my Pyhon code,and this is my first time using jQuery and I do need to use this same exact validation library. Your valuable corporation is needed. Thanks.

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  • Is it approproate it use django signals withing the same app

    - by Alex Lebedev
    Trying to add email notification to my app in the cleanest way possible. When certain fields of a model change, app should send a notification to a user. Here's my old solution: from django.contrib.auth import User class MyModel(models.Model): user = models.ForeignKey(User) field_a = models.CharField() field_b = models.CharField() def save(self, *args, **kwargs): old = self.__class__.objects.get(pk=self.pk) if self.pk else None super(MyModel, self).save(*args, **kwargs) if old and old.field_b != self.field_b: self.notify("b-changed") # Sevelar more events here # ... def notify(self, event) subj, text = self._prepare_notification(event) send_mail(subj, body, settings.DEFAULT_FROM_EMAIL, [self.user.email], fail_silently=True) This worked fine while I had one or two notification types, but after that just felt wrong to have so much code in my save() method. So, I changed code to signal-based: from django.db.models import signals def remember_old(sender, instance, **kwargs): """pre_save hanlder to save clean copy of original record into `old` attribute """ instance.old = None if instance.pk: try: instance.old = sender.objects.get(pk=instance.pk) except ObjectDoesNotExist: pass def on_mymodel_save(sender, instance, created, **kwargs): old = instance.old if old and old.field_b != instance.field_b: self.notify("b-changed") # Sevelar more events here # ... signals.pre_save.connect(remember_old, sender=MyModel, dispatch_uid="mymodel-remember-old") signals.post_save.connect(on_mymodel_save, sender=MyModel, dispatch_uid="mymodel-on-save") The benefit is that I can separate event handlers into different module, reducing size of models.py and I can enable/disable them individually. The downside is that this solution is more code and signal handlers are separated from model itself and unknowing reader can miss them altogether. So, colleagues, do you think it's worth it?

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  • Web-based game in Python + Django and client browser polling

    - by ty
    I am creating a text-based game that implements a basic model in which multiple (10+) players interact with data and one moderator watches them and sets certain environmental statistics that affect gameplay. Recently I have begun to familiarize myself with Django. It seems to me that it would be an excellent tool for creating a game quickly, particularly because the nature of my game depends largely on sets of data (which lends itself quite well to a database). I am wondering how to "push" changes made by the game moderator to the players (for example, the moderator can decide to display an image to all players). The game is turn-based, not real-time, but certain messages need to be pushed out in roughly real-time. My thoughts: I could have each player's browser poll a status periodically (say, every 30 seconds) to see if there is a message from a moderator. But this forces a lag and means different players might receive it at different times. And reducing this interval to <10 seems like a bad idea for the server. Is there a better way to inform clients of changes? Would you suggest something other than using a web framework like Django? Thanks!

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