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  • Array help Index out of range exeption was unhandled

    - by Michael Quiles
    I am trying to populate combo boxes from a text file using comma as a delimiter everything was working fine, but now when I debug I get the "Index out of range exeption was unhandled" warning. I guess I need a fresh pair of eyes to see where I went wrong, I commented on the line that gets the error //Fname = fields[1]; using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Drawing.Printing; using System.Linq; using System.Text; using System.Windows.Forms; using System.IO; namespace Sullivan_Payroll { public partial class xEmpForm : Form { bool complete = false; public xEmpForm() { InitializeComponent(); } private void xEmpForm_Resize(object sender, EventArgs e) { this.xCenterPanel.Left = Convert.ToInt16((this.Width - this.xCenterPanel.Width) / 2); this.xCenterPanel.Top = Convert.ToInt16((this.Height - this.xCenterPanel.Height) / 2); Refresh(); } private void exitToolStripMenuItem_Click(object sender, EventArgs e) { //Exits the application this.Close(); } private void xEmpForm_FormClosing(object sender, FormClosingEventArgs e) //use this on xtrip calculator { DialogResult Response; if (complete == true) { Application.Exit(); } else { Response = MessageBox.Show("Are you sure you want to Exit?", "Exit", MessageBoxButtons.YesNo, MessageBoxIcon.Question, MessageBoxDefaultButton.Button2); if (Response == DialogResult.No) { complete = false; e.Cancel = true; } else { complete = true; Application.Exit(); } } } private void xEmpForm_Load(object sender, EventArgs e) { //file sources string fileDept = "source\\Department.txt"; string fileSex = "source\\Sex.txt"; string fileStatus = "source\\Status.txt"; if (File.Exists(fileDept)) { using (System.IO.StreamReader sr = System.IO.File.OpenText(fileDept)) { string dept = ""; while ((dept = sr.ReadLine()) != null) { this.xDeptComboBox.Items.Add(dept); } } } else { MessageBox.Show("The Department file can not be found.", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error); } if (File.Exists(fileSex)) { using (System.IO.StreamReader sr = System.IO.File.OpenText(fileSex)) { string sex = ""; while ((sex = sr.ReadLine()) != null) { this.xSexComboBox.Items.Add(sex); } } } else { MessageBox.Show("The Sex file can not be found.", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error); } if (File.Exists(fileStatus)) { using (System.IO.StreamReader sr = System.IO.File.OpenText(fileStatus)) { string status = ""; while ((status = sr.ReadLine()) != null) { this.xStatusComboBox.Items.Add(status); } } } else { MessageBox.Show("The Status file can not be found.", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error); } } private void xFileSaveMenuItem_Click(object sender, EventArgs e) { { const string fileNew = "source\\New Staff.txt"; string recordIn; FileStream outFile = new FileStream(fileNew, FileMode.Create, FileAccess.Write); StreamWriter writer = new StreamWriter(outFile); for (int count = 0; count <= this.xEmployeeListBox.Items.Count - 1; count++) { this.xEmployeeListBox.SelectedIndex = count; recordIn = this.xEmployeeListBox.SelectedItem.ToString(); writer.WriteLine(recordIn); } writer.Close(); outFile.Close(); this.xDeptComboBox.SelectedIndex = -1; this.xStatusComboBox.SelectedIndex = -1; this.xSexComboBox.SelectedIndex = -1; MessageBox.Show("your file is saved"); } } private void xViewFacultyMenuItem_Click(object sender, EventArgs e) { const string fileStaff = "source\\Staff.txt"; const char DELIM = ','; string Lname, Fname, Depart, Stat, Sex, Salary, cDept, cStat, cSex; double Gtotal; string recordIn; string[] fields; cDept = this.xDeptComboBox.SelectedItem.ToString(); cStat = this.xStatusComboBox.SelectedItem.ToString(); cSex = this.xSexComboBox.SelectedItem.ToString(); FileStream inFile = new FileStream(fileStaff, FileMode.Open, FileAccess.Read); StreamReader reader = new StreamReader(inFile); recordIn = reader.ReadLine(); while (recordIn != null) { fields = recordIn.Split(DELIM); Lname = fields[0]; Fname = fields[1]; // this is where the error appears Depart = fields[2]; Stat = fields[3]; Sex = fields[4]; Salary = fields[5]; Fname = fields[1].TrimStart(null); Depart = fields[2].TrimStart(null); Stat = fields[3].TrimStart(null); Sex = fields[4].TrimStart(null); Salary = fields[5].TrimStart(null); Gtotal = double.Parse(Salary); if (Depart == cDept && cStat == Stat && cSex == Sex) { this.xEmployeeListBox.Items.Add(recordIn); } recordIn = reader.ReadLine(); } reader.Close(); inFile.Close(); if (this.xEmployeeListBox.Items.Count >= 1) { this.xFileSaveMenuItem.Enabled = true; this.xFilePrintMenuItem.Enabled = true; this.xEditClearMenuItem.Enabled = true; } else { this.xFileSaveMenuItem.Enabled = false; this.xFilePrintMenuItem.Enabled = false; this.xEditClearMenuItem.Enabled = false; MessageBox.Show("Records not found"); } } private void xEditClearMenuItem_Click(object sender, EventArgs e) { this.xEmployeeListBox.Items.Clear(); this.xDeptComboBox.SelectedIndex = -1; this.xStatusComboBox.SelectedIndex = -1; this.xSexComboBox.SelectedIndex = -1; this.xFileSaveMenuItem.Enabled = false; this.xFilePrintMenuItem.Enabled = false; this.xEditClearMenuItem.Enabled = false; } } } Source file -- Anderson, Kristen, Accounting, Assistant, Female, 43155 Ball, Robin, Accounting, Instructor, Female, 42723 Chin, Roger, Accounting, Full, Male,59281 Coats, William, Accounting, Assistant, Male, 45371 Doepke, Cheryl, Accounting, Full, Female, 52105 Downs, Clifton, Accounting, Associate, Male, 46887 Garafano, Karen, Finance, Associate, Female, 49000 Hill, Trevor, Management, Instructor, Male, 38590 Jackson, Carole, Accounting, Instructor, Female, 38781 Jacobson, Andrew, Management, Full, Male, 56281 Lewis, Karl, Management, Associate, Male, 48387 Mack, Kevin, Management, Assistant, Male, 45000 McKaye, Susan, Management, Instructor, Female, 43979 Nelsen, Beth, Finance, Full, Female, 52339 Nelson, Dale, Accounting, Full, Male, 54578 Palermo, Sheryl, Accounting, Associate, Female, 45617 Rais, Mary, Finance, Instructor, Female, 27000 Scheib, Earl, Management, Instructor, Male, 37389 Smith, Tom, Finance, Full, Male, 57167 Smythe, Janice, Management, Associate, Female, 46887 True, David, Accounting, Full, Male, 53181 Young, Jeff, Management, Assistant, Male, 43513

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  • DOM Elements with same id and jQuery

    - by Steve
    Hi I have multiple elements with the same structure in my application. Second div element's id varies as per the comment id in the db which is unique. There are elements with the id 'vote_up' and 'vote_down'. This gets repeated for each comment.What happens is that, as I mentioned, there are multiple comments. I want to perform an Ajax request. First of this structure functions properly using ajax, but the rest does an http request. Btw I am developing a rails application and I am using jQuery. <div id="post_comment"> john<i> says </i> Comment<br/> <div id="comment_10_div"> **<form action="/comments/vote_up" id="vote_up" method="post">** <div style="margin:0;padding:0;display:inline"> <input name="authenticity_token" type="hidden" value="w873BgYHLxQmadUalzMRUC+1ql4AtP3U7f78dT8x9ho=" /> </div> <input id="Comment_place_id" name="Comment[post_id]" type="hidden" value="3" /> <input id="Comment_id" name="Comment[id]" type="hidden" value="10" /> <input id="Comment_user_id" name="Comment[user_id]" type="hidden" value="2" /> <input name="commit" type="submit" value="Vote up" /> </form> <label id="comment_10">10</label> **<form action="/comments/vote_down" id="vote_down" method="post">** <div style="margin:0;padding:0;display:inline"> <input name="authenticity_token" type="hidden" value="w873BgYHLxQmadUalzMRUC+1ql4AtP3U7f78dT8x9ho=" /> </div> <input id="Comment_place_id" name="Comment[place_id]" type="hidden" value="3" /> <input id="Comment_id" name="Comment[id]" type="hidden" value="10" /> <input id="Comment_user_id" name="Comment[user_id]" type="hidden" value="2" /> <input name="commit" type="submit" value="Vote Down" /> </form> </div> Can you please help me to solve this Thanks

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  • Get Value from thick box control

    - by Muhammad Akhtar
    I have hidden field on thick box, when I close thick I need to get the value of my hidden field, when close thick box this method calls function tb_remove(parent_func_callback) { parent.document.getElementById('hdf').value// I need value of hidden field here please tell me how can I get hidden field value that is on thick box? Thanks

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  • Can i store a Queue in viewstate? only will store the first item i add to queue

    - by Mausimo
    Hey, as the question states i am trying to store a Queue in a viewstate (to track postbacks and refreshes to stop a form from resubmitting). Here is just the viewstate code: private Queue<string> p_tempQue { set { ViewState["sTemp"] = value; } get { return (Queue<string>)ViewState["sTemp"]; } } //BasePage constructor public BasePage() { //create a Queue of string //sTemp = new Queue(); this.Load += new EventHandler(this.Page_Load); this.Init += new EventHandler(this.Page_Init); } //In the 'page_Init' event we have created a simple hidden field by name 'hdnGuid' which is attached to the page on the first hit itself. protected void Page_Init(object sender, EventArgs e) { //initializing the hidden field //create a hidden field with a ID HiddenField hdnGuid = new HiddenField(); hdnGuid.ID = "hdnGuid"; //if it is the first time the page is loaded, create a new guid and assign it as the hidden field value if (!Page.IsPostBack) hdnGuid.Value = Guid.NewGuid().ToString(); //add the hidden field to the page Page.Form.Controls.Add(hdnGuid); } //In the 'page_Load' event we check if the hidden field value is same as the old value. In case the value is not same that means it's a 'postback' //and if the value is same then its 'refresh'. As per situation we set the 'httpContent.Items["Refresh"]' value. protected void Page_Load(object sender, EventArgs e) { if(p_tempQue != null) sTemp = p_tempQue; else sTemp = new Queue<string>(); //The hdnGuid will be set the first time page is loaded, else the hdnGuid //will be set after each time the form is submitted using javascript. //assign the hidden field currently on the page for manipulation HiddenField h1 = (HiddenField)(Page.Form.FindControl("hdnGuid")); //create an instance of the GuidClass GuidClass currentGuid = new GuidClass(); //set the GuidClass Guid property to the value of the hidden field currentGuid.Guid = h1.Value; //check to see if the Queue of strings contains the string which is the current Guid property of the GuidClass //if the are equal, then the page was refreshed if (sTemp.Contains<string>(currentGuid.Guid)) { //adds item as key/value pair to share data between an System.Web.IHttpModule interface and an System.Web.IHttpHandler interface during an HTTP request. System.Web.HttpContext.Current.Items.Add("IsRefresh", true); } //if they are not requal, the page is not refreshed else { //if the current Guid property in the GuidClass is not null or not an empty string //add the new Guid to the Queue if (!(currentGuid.Guid.Equals(null) || currentGuid.Guid.Equals(""))) sTemp.Enqueue(currentGuid.Guid); System.Web.HttpContext.Current.Items.Add("IsRefresh", false); } p_tempQue = sTemp; }

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  • Passing Variables Along in a Function

    - by John
    Hello, In the function show_commentbox() below, I would like to pass along the variables $_SESSION['loginid'], $submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl. With the setup below, it's not working. How could I change it to make show_commentbox() pass the variables along? Thanks in advance, John index.php: <?php $submission = $_GET['submission']; require_once "header.php"; include "login.php"; include "comments.php"; include "commentformonoff.php"; ?> In header.php: require_once ("function.inc.php"); In comments.php: $uid = $_SESSION['loginid']; $submissiondate = mysql_real_escape_string($_GET['submissiondate']); $submittor = mysql_real_escape_string($_GET['submittor']); $countcomments = mysql_real_escape_string($_GET['countcomments']); $dispurl = mysql_real_escape_string($_GET['dispurl']); $url = mysql_real_escape_string($_GET['url']); $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox(); } else { echo "Login to comment"; } } else { echo "Login to comment"; } } else { show_commentbox(); } ?> In display.functions.inc.php: function show_commentbox() { echo '<form action="http://www...com/sandbox/comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.$submission.'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="commentsubfield" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; }

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  • Replace all URL unless it is allowed

    - by ratamaster
    I had a regex that replaced all URLs from a given string: my_string = "www.example.com test www.mysite.com" my_string.gsub!(/[a-zA-Z0-9\-\.]+\.(com|net|de|org|uk|biz|info|co.uk|es|de)(\/\S*)?/i,'(site hidden)') As a result of the above I get: "(site hidden) test (site hidden)" How could I change the regex to not replace www.mysite.com ??? It means that the replace should output "(site hidden) test www.mysite.com" Thanks !

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  • How to create Custom ListForm WebPart

    - by DipeshBhanani
    Mostly all who works extensively on SharePoint (including meJ) don’t like to use out-of-box list forms (DispForm.aspx, EditForm.aspx, NewForm.aspx) as interface. Actually these OOB list forms bind hands of developers for the customization. It gives headache to developers to add just one post back event, for a dropdown field and to populate other fields in NewForm.aspx or EditForm.aspx. On top of that clients always ask such stuff. So here I am going to give you guys a flight for SharePoint Customization world. In this blog, I will explain, how to create CustomListForm WebPart. In my next blogs, I am going to explain easy deployment of List Forms through features and last, guidance on using SharePoint web controls. 1.       First thing, create a class library project through Visual Studio and inherit the class with WebPart class.     public class CustomListForm : WebPart   2.       Declare the public variables and properties which we are going to use throughout the class. You will get to know these once you see them in use.         #region "Variable Declaration"           Table spTableCntl;         FormToolBar formToolBar;         Literal ltAlertMessage;         Guid SiteId;         Guid ListId;         int ItemId;         string ListName;           #endregion           #region "Properties"           SPControlMode _ControlMode = SPControlMode.New;         [Personalizable(PersonalizationScope.Shared),          WebBrowsable(true),          WebDisplayName("Control Mode"),          WebDescription("Set Control Mode"),          DefaultValue(""),          Category("Miscellaneous")]         public SPControlMode ControlMode         {             get { return _ControlMode; }             set { _ControlMode = value; }         }           #endregion     The property “ControlMode” is used to identify the mode of the List Form. The property is of type SPControlMode which is an enum type with values (Display, Edit, New and Invalid). When we will add this WebPart to DispForm.aspx, EditForm.aspx and NewForm.aspx, we will set the WebPart property “ControlMode” to Display, Edit and New respectively.     3.       Now, we need to override the CreateChildControl method and write code to manually add SharePoint Web Controls related to each list fields as well as ToolBar controls.         protected override void CreateChildControls()         {             base.CreateChildControls();               try             {                 SiteId = SPContext.Current.Site.ID;                 ListId = SPContext.Current.ListId;                 ListName = SPContext.Current.List.Title;                   if (_ControlMode == SPControlMode.Display || _ControlMode == SPControlMode.Edit)                     ItemId = SPContext.Current.ItemId;                   SPSecurity.RunWithElevatedPrivileges(delegate()                 {                     using (SPSite site = new SPSite(SiteId))                     {                         //creating a new SPSite with credentials of System Account                         using (SPWeb web = site.OpenWeb())                         {                               //<Custom Code for creating form controls>                         }                     }                 });             }             catch (Exception ex)             {                 ShowError(ex, "CreateChildControls");             }         }   Here we are assuming that we are developing this WebPart to plug into List Forms. Hence we will get the List Id and List Name from the current context. We can have Item Id only in case of Display and Edit Mode. We are putting our code into “RunWithElevatedPrivileges” to elevate privileges to System Account. Now, let’s get deep down into the main code and expand “//<Custom Code for creating form controls>”. Before initiating any SharePoint control, we need to set context of SharePoint web controls explicitly so that it will be instantiated with elevated System Account user. Following line does the job.     //To create SharePoint controls with new web object and System Account credentials     SPControl.SetContextWeb(Context, web);   First thing, let’s add main table as container for all controls.     //Table to render webpart     Table spTableMain = new Table();     spTableMain.CellPadding = 0;     spTableMain.CellSpacing = 0;     spTableMain.Width = new Unit(100, UnitType.Percentage);     this.Controls.Add(spTableMain);   Now we need to add Top toolbar with Save and Cancel button at top as you see in the below screen shot.       // Add Row and Cell for Top ToolBar     TableRow spRowTopToolBar = new TableRow();     spTableMain.Rows.Add(spRowTopToolBar);     TableCell spCellTopToolBar = new TableCell();     spRowTopToolBar.Cells.Add(spCellTopToolBar);     spCellTopToolBar.Width = new Unit(100, UnitType.Percentage);         ToolBar toolBarTop = (ToolBar)Page.LoadControl("/_controltemplates/ToolBar.ascx");     toolBarTop.CssClass = "ms-formtoolbar";     toolBarTop.ID = "toolBarTbltop";     toolBarTop.RightButtons.SeparatorHtml = "<td class=ms-separator> </td>";       if (_ControlMode != SPControlMode.Display)     {         SaveButton btnSave = new SaveButton();         btnSave.ControlMode = _ControlMode;         btnSave.ListId = ListId;           if (_ControlMode == SPControlMode.New)             btnSave.RenderContext = SPContext.GetContext(web);         else         {             btnSave.RenderContext = SPContext.GetContext(this.Context, ItemId, ListId, web);             btnSave.ItemContext = SPContext.GetContext(this.Context, ItemId, ListId, web);             btnSave.ItemId = ItemId;         }         toolBarTop.RightButtons.Controls.Add(btnSave);     }       GoBackButton goBackButtonTop = new GoBackButton();     toolBarTop.RightButtons.Controls.Add(goBackButtonTop);     goBackButtonTop.ControlMode = SPControlMode.Display;       spCellTopToolBar.Controls.Add(toolBarTop);   Here we have use “SaveButton” and “GoBackButton” which are internal SharePoint web controls for save and cancel functionality. I have set some of the properties of Save Button with if-else condition because we will not have Item Id in case of New Mode. Item Id property is used to identify which SharePoint List Item need to be saved. Now, add Form Toolbar to the page which contains “Attach File”, “Delete Item” etc buttons.       // Add Row and Cell for FormToolBar     TableRow spRowFormToolBar = new TableRow();     spTableMain.Rows.Add(spRowFormToolBar);     TableCell spCellFormToolBar = new TableCell();     spRowFormToolBar.Cells.Add(spCellFormToolBar);     spCellFormToolBar.Width = new Unit(100, UnitType.Percentage);       FormToolBar formToolBar = new FormToolBar();     formToolBar.ID = "formToolBar";     formToolBar.ListId = ListId;     if (_ControlMode == SPControlMode.New)         formToolBar.RenderContext = SPContext.GetContext(web);     else     {         formToolBar.RenderContext = SPContext.GetContext(this.Context, ItemId, ListId, web);         formToolBar.ItemContext = SPContext.GetContext(this.Context, ItemId, ListId, web);         formToolBar.ItemId = ItemId;     }     formToolBar.ControlMode = _ControlMode;     formToolBar.EnableViewState = true;       spCellFormToolBar.Controls.Add(formToolBar);     The ControlMode property will take care of which button to be displayed on the toolbar. E.g. “Attach files”, “Delete Item” in new/edit forms and “New Item”, “Edit Item”, “Delete Item”, “Manage Permissions” etc in display forms. Now add main section which contains form field controls.     //Create Form Field controls and add them in Table "spCellCntl"     CreateFieldControls(web);     //Add public variable "spCellCntl" containing all form controls to the page     spRowCntl.Cells.Add(spCellCntl);     spCellCntl.Width = new Unit(100, UnitType.Percentage);     spCellCntl.Controls.Add(spTableCntl);       //Add a Blank Row with height of 5px to render space between ToolBar table and Control table     TableRow spRowLine1 = new TableRow();     spTableMain.Rows.Add(spRowLine1);     TableCell spCellLine1 = new TableCell();     spRowLine1.Cells.Add(spCellLine1);     spCellLine1.Height = new Unit(5, UnitType.Pixel);     spCellLine1.Controls.Add(new LiteralControl("<IMG SRC='/_layouts/images/blank.gif' width=1 height=1 alt=''>"));       //Add Row and Cell for Form Controls Section     TableRow spRowCntl = new TableRow();     spTableMain.Rows.Add(spRowCntl);     TableCell spCellCntl = new TableCell();       //Create Form Field controls and add them in Table "spCellCntl"     CreateFieldControls(web);     //Add public variable "spCellCntl" containing all form controls to the page     spRowCntl.Cells.Add(spCellCntl);     spCellCntl.Width = new Unit(100, UnitType.Percentage);     spCellCntl.Controls.Add(spTableCntl);       TableRow spRowLine2 = new TableRow();     spTableMain.Rows.Add(spRowLine2);     TableCell spCellLine2 = new TableCell();     spRowLine2.Cells.Add(spCellLine2);     spCellLine2.CssClass = "ms-formline";     spCellLine2.Controls.Add(new LiteralControl("<IMG SRC='/_layouts/images/blank.gif' width=1 height=1 alt=''>"));       // Add Blank row with height of 5 pixel     TableRow spRowLine3 = new TableRow();     spTableMain.Rows.Add(spRowLine3);     TableCell spCellLine3 = new TableCell();     spRowLine3.Cells.Add(spCellLine3);     spCellLine3.Height = new Unit(5, UnitType.Pixel);     spCellLine3.Controls.Add(new LiteralControl("<IMG SRC='/_layouts/images/blank.gif' width=1 height=1 alt=''>"));   You can add bottom toolbar also to get same look and feel as OOB forms. I am not adding here as the blog will be much lengthy. At last, you need to write following lines to allow unsafe updates for Save and Delete button.     // Allow unsafe update on web for save button and delete button     if (this.Page.IsPostBack && this.Page.Request["__EventTarget"] != null         && (this.Page.Request["__EventTarget"].Contains("IOSaveItem")         || this.Page.Request["__EventTarget"].Contains("IODeleteItem")))     {         SPContext.Current.Web.AllowUnsafeUpdates = true;     }   So that’s all. We have finished writing Custom Code for adding field control. But something most important is skipped. In above code, I have called function “CreateFieldControls(web);” to add SharePoint field controls to the page. Let’s see the implementation of the function:     private void CreateFieldControls(SPWeb pWeb)     {         SPList listMain = pWeb.Lists[ListId];         SPFieldCollection fields = listMain.Fields;           //Main Table to render all fields         spTableCntl = new Table();         spTableCntl.BorderWidth = new Unit(0);         spTableCntl.CellPadding = 0;         spTableCntl.CellSpacing = 0;         spTableCntl.Width = new Unit(100, UnitType.Percentage);         spTableCntl.CssClass = "ms-formtable";           SPContext controlContext = SPContext.GetContext(this.Context, ItemId, ListId, pWeb);           foreach (SPField listField in fields)         {             string fieldDisplayName = listField.Title;             string fieldInternalName = listField.InternalName;               //Skip if the field is system field or hidden             if (listField.Hidden || listField.ShowInVersionHistory == false)                 continue;               //Skip if the control mode is display and field is read-only             if (_ControlMode != SPControlMode.Display && listField.ReadOnlyField == true)                 continue;               FieldLabel fieldLabel = new FieldLabel();             fieldLabel.FieldName = listField.InternalName;             fieldLabel.ListId = ListId;               BaseFieldControl fieldControl = listField.FieldRenderingControl;             fieldControl.ListId = ListId;             //Assign unique id using Field Internal Name             fieldControl.ID = string.Format("Field_{0}", fieldInternalName);             fieldControl.EnableViewState = true;               //Assign control mode             fieldLabel.ControlMode = _ControlMode;             fieldControl.ControlMode = _ControlMode;             switch (_ControlMode)             {                 case SPControlMode.New:                     fieldLabel.RenderContext = SPContext.GetContext(pWeb);                     fieldControl.RenderContext = SPContext.GetContext(pWeb);                     break;                 case SPControlMode.Edit:                 case SPControlMode.Display:                     fieldLabel.RenderContext = controlContext;                     fieldLabel.ItemContext = controlContext;                     fieldLabel.ItemId = ItemId;                       fieldControl.RenderContext = controlContext;                     fieldControl.ItemContext = controlContext;                     fieldControl.ItemId = ItemId;                     break;             }               //Add row to display a field row             TableRow spCntlRow = new TableRow();             spTableCntl.Rows.Add(spCntlRow);               //Add the cells for containing field lable and control             TableCell spCellLabel = new TableCell();             spCellLabel.Width = new Unit(30, UnitType.Percentage);             spCellLabel.CssClass = "ms-formlabel";             spCntlRow.Cells.Add(spCellLabel);             TableCell spCellControl = new TableCell();             spCellControl.Width = new Unit(70, UnitType.Percentage);             spCellControl.CssClass = "ms-formbody";             spCntlRow.Cells.Add(spCellControl);               //Add the control to the table cells             spCellLabel.Controls.Add(fieldLabel);             spCellControl.Controls.Add(fieldControl);               //Add description if there is any in case of New and Edit Mode             if (_ControlMode != SPControlMode.Display && listField.Description != string.Empty)             {                 FieldDescription fieldDesc = new FieldDescription();                 fieldDesc.FieldName = fieldInternalName;                 fieldDesc.ListId = ListId;                 spCellControl.Controls.Add(fieldDesc);             }               //Disable Name(Title) in Edit Mode             if (_ControlMode == SPControlMode.Edit && fieldDisplayName == "Name")             {                 TextBox txtTitlefield = (TextBox)fieldControl.Controls[0].FindControl("TextField");                 txtTitlefield.Enabled = false;             }         }         fields = null;     }   First of all, I have declared List object and got list fields in field collection object called “fields”. Then I have added a table for the container of all controls and assign CSS class as "ms-formtable" so that it gives consistent look and feel of SharePoint. Now it’s time to navigate through all fields and add them if required. Here we don’t need to add hidden or system fields. We also don’t want to display read-only fields in new and edit forms. Following lines does this job.             //Skip if the field is system field or hidden             if (listField.Hidden || listField.ShowInVersionHistory == false)                 continue;               //Skip if the control mode is display and field is read-only             if (_ControlMode != SPControlMode.Display && listField.ReadOnlyField == true)                 continue;   Let’s move to the next line of code.             FieldLabel fieldLabel = new FieldLabel();             fieldLabel.FieldName = listField.InternalName;             fieldLabel.ListId = ListId;               BaseFieldControl fieldControl = listField.FieldRenderingControl;             fieldControl.ListId = ListId;             //Assign unique id using Field Internal Name             fieldControl.ID = string.Format("Field_{0}", fieldInternalName);             fieldControl.EnableViewState = true;               //Assign control mode             fieldLabel.ControlMode = _ControlMode;             fieldControl.ControlMode = _ControlMode;   We have used “FieldLabel” control for displaying field title. The advantage of using Field Label is, SharePoint automatically adds red star besides field label to identify it as mandatory field if there is any. Here is most important part to understand. The “BaseFieldControl”. It will render the respective web controls according to type of the field. For example, if it’s single line of text, then Textbox, if it’s look up then it renders dropdown. Additionally, the “ControlMode” property tells compiler that which mode (display/edit/new) controls need to be rendered with. In display mode, it will render label with field value. In edit mode, it will render respective control with item value and in new mode it will render respective control with empty value. Please note that, it’s not always the case when dropdown field will be rendered for Lookup field or Choice field. You need to understand which controls are rendered for which list fields. I am planning to write a separate blog which I hope to publish it very soon. Moreover, we also need to assign list field specific properties like List Id, Field Name etc to identify which SharePoint List field is attached with the control.             switch (_ControlMode)             {                 case SPControlMode.New:                     fieldLabel.RenderContext = SPContext.GetContext(pWeb);                     fieldControl.RenderContext = SPContext.GetContext(pWeb);                     break;                 case SPControlMode.Edit:                 case SPControlMode.Display:                     fieldLabel.RenderContext = controlContext;                     fieldLabel.ItemContext = controlContext;                     fieldLabel.ItemId = ItemId;                       fieldControl.RenderContext = controlContext;                     fieldControl.ItemContext = controlContext;                     fieldControl.ItemId = ItemId;                     break;             }   Here, I have separate code for new mode and Edit/Display mode because we will not have Item Id to assign in New Mode. We also need to set CSS class for cell containing Label and Controls so that those controls get rendered with SharePoint theme.             spCellLabel.CssClass = "ms-formlabel";             spCellControl.CssClass = "ms-formbody";   “FieldDescription” control is used to add field description if there is any.    Now it’s time to add some more customization,               //Disable Name(Title) in Edit Mode             if (_ControlMode == SPControlMode.Edit && fieldDisplayName == "Name")             {                 TextBox txtTitlefield = (TextBox)fieldControl.Controls[0].FindControl("TextField");                 txtTitlefield.Enabled = false;             }   The above code will disable the title field in edit mode. You can add more code here to achieve more customization according to your requirement. Some of the examples are as follow:             //Adding post back event on UserField to auto populate some other dependent field             //in new mode and disable it in edit mode             if (_ControlMode != SPControlMode.Display && fieldDisplayName == "Manager")             {                 if (fieldControl.Controls[0].FindControl("UserField") != null)                 {                     PeopleEditor pplEditor = (PeopleEditor)fieldControl.Controls[0].FindControl("UserField");                     if (_ControlMode == SPControlMode.New)                         pplEditor.AutoPostBack = true;                     else                         pplEditor.Enabled = false;                 }             }               //Add JavaScript Event on Dropdown field. Don't forget to add the JavaScript function on the page.             if (_ControlMode == SPControlMode.Edit && fieldDisplayName == "Designation")             {                 DropDownList ddlCategory = (DropDownList)fieldControl.Controls[0];                 ddlCategory.Attributes.Add("onchange", string.Format("javascript:DropdownChangeEvent('{0}');return false;", ddlCategory.ClientID));             }    Following are the screenshots of my Custom ListForm WebPart. Let’s play a game, check out your OOB List forms of SharePoint, compare with these screens and find out differences.   DispForm.aspx:   EditForm.aspx:   NewForm.aspx:   Enjoy the SharePoint Soup!!! ­­­­­­­­­­­­­­­­­­­­

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  • IE6 + IE7 CSS problem with overflow: hidden; - position: relative; combo.

    - by googletorp
    So I have created a slider for a homepage, that slides some images with a title and teaser text using jQuery. Everything works fine, and I went to check IE and found that IE 6 and 7 kills my slider css completely. I can't figure out why, but for some reason I can't hide the non active slides with overflow: hidden; I've tried tweaking the css back and forth, but haven't been able to figure out what's causing the problem. I've recreated the problem in a more isolated html page. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="da" lang="da" dir="ltr"> <head> <style> body { width: 900px; } .column-1 { width: 500px; float: left; } .column-2 { width: 200px; float: left; } .column-3 { width: 200px; float: left; } ul { width: 2000px; left: -499px; position: relative; } li { list-style: none; display: block; float: left; } .item-list { overflow: hidden; width: 499px; } </style> </head> <body> <div class="column-1"> <div class="item-list clearfix"> <ul> <li class="first"> <div class="node-slide"> <img src="http://www.hanselman.com/blog/content/binary/lolcats-funny-pictures-leroy-jenkins.jpg" /> <div class="infobox"> <h4>Title 1</h4> <p>Teaser 1</p> </div> </div> </li> <li> <div class="slide"> <img src="http://www.hanselman.com/blog/content/binary/lolcats-funny-pictures-leroy-jenkins.jpg" /> <div class="infobox"> <h4>Title 2</h4> <p>Teaser 2</p> </div> </div> </li> <li class="last"> <div class="slide"> <img src="http://www.hanselman.com/blog/content/binary/lolcats-funny-pictures-leroy-jenkins.jpg" /> <div class="infobox"> <h4>Title 3</h4> <p>Teaser 3</p> </div> </div> </li> </ul> </div> </div> <div class="column-2"> ... </div> <div class="column-3"> ... </div> </body> </html> I've tracked down that it is the ul { position: relative; } on the ul element that is causing the overflow: hidden not to work, but why that is, I don't know. Also this is needed to make the slider javascript work using the left attribute on the ul to slide it. Any ideas as to how you can fix this is most welcome.

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  • Why does my mac have page outs when I have inactive memory?

    - by Chace Fields
    From what I've read, page outs are a sign that you don't have enough RAM. I have also read that if you have inactive memory available, then the machine will use that memory when starting up new programs. I have about 2GB of inactive memory and very little available memory. Once this happens, my page outs go up. Why is this and do I need more memory? I have 8GB of RAM. I'm running VMware Fusion 5 with 2GB allotted to Windows 8.

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  • If USB is not listed in BIOS as a boot option, does that mean the machine can't boot from USB?

    - by Chace Fields
    I just purchased an Asus Zenbook Prime UX31A-DH51 with Windows 8. I want to wipe the drive and do a clean install but USB is not listed as a boot option in the BIOS. Does this mean it is not possible? Here is a photo of my BIOS options. This is the only option I get when I click Add New Boot Option. Not sure if I can add USB here. * Update * Asus tech emailed and said: "Unfortunately with Windows 8 you can not boot from bios."

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  • How to handle Append Only text fields in a Sharepoint DataSheet view?

    - by Telos
    We've created a Sharepoint site to track a process. Eventually we're going to make a workflow out of it, but in the meantime there's a list we all have to look at which lists the various dates each piece is supposed to be finished. So basically My group needs to see and update columns X, Y, Z and Comments while ignoring the other 30 billion or so columns. Which is great in datasheet view because we can easily view our columns, and update them right there without drilling into the item and browsing through all the other crap we don't need. The problem is the Comments field, in which we really need to see the last actual comment made. Unfortunately whenever anyone saves the record the field is updated with a blank value (unless they entered a comment) and the last actual comment is lost unless you drill into the item. Is there some way to get the Datasheet view to show all the entries? I should also note that I know very little about Sharepoint 2007... so detailed answers would be nice!

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  • How to Choose Fields While Using ExportToExcel in jqGrid ?

    - by João Guilherme
    Hi ! I have this jqGrid <trirand:JQGrid runat="server" ID="JQGrid1" OnRowEditing="JQGrid1_RowEditing" RenderingMode="Optimized" oncellbinding="JQGrid1_CellBinding" Height="350" EditUrl="/Ferramenta/Transacoes/TransacoesT.aspx"> <AppearanceSettings HighlightRowsOnHover="true"/> <Columns> <trirand:JQGridColumn DataField="IdLancamento" PrimaryKey="True" Visible="false" /> <trirand:JQGridColumn DataField="IdCategoria" Visible="false" /> <trirand:JQGridColumn DataField="DataLancamento" Editable="true" DataFormatString="{0:dd/MM/yy}" HeaderText="Data" Width="65" TextAlign="Center" CssClass="font_data" /> <trirand:JQGridColumn DataField="Descricao" Editable="true" HeaderText="Descrição" Width="330" /> <trirand:JQGridColumn DataField="NomeCategoria" Editable="true" EditType="DropDown" EditorControlID="ddlCategorias" HeaderText="Categoria"> <Formatter> <trirand:CustomFormatter FormatFunction="DefineUrl" /> </Formatter> </trirand:JQGridColumn> <trirand:JQGridColumn DataField="Valor" Editable="false" DataFormatString="{0:C}" HeaderText="Valor" Width="80" TextAlign="Center" /> </Columns> <ClientSideEvents RowSelect="editRow" /> <PagerSettings PageSize="20" /> <ToolBarSettings ShowEditButton="false" ShowRefreshButton="True" ShowAddButton="false" ShowDeleteButton="false" ShowSearchButton="false" /> <SortSettings InitialSortColumn=""></SortSettings> </trirand:JQGrid> <asp:LinkButton ID="lbExportar" runat="server" onclick="lbExportar_Click">Exportar todas as transações</asp:LinkButton> When I use the method ExportToExcel JQGrid1.ExportToExcel("export.xls"); it includes the first column IdLancamento that is not visible and also includes another column that is used on the query. Is it possible to choose the columns that are going to be exported ?

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  • How to add custom fields in WordPress "Add a New Post" page?

    - by KPL
    Hello awesome people, I want to add a custom field on Add A New Post page. Like - if I am to make a plugin which will post links to Twitter after a new post is made, I would like to give ability to user to select if he wants to tweet that particular post's link to Twitter. I want to display a check box somewhere in the page which says - "Post this on Twitter" and then check for it and make a tweet. I have seen some plugins which do this. But can't remember which they were. Can someone please help me out?

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  • Showing Different fields in EditorForModel vs. DisplayForModel modes in MVC2

    - by CodeGrue
    I have a viewmodel that has an int StateID field and a string StateName field like so: public class DepartmentViewModel : BaseViewModel, IModelWithId { // only show in edit mode public int StateId { get; set; } // only show in display mode public string StateName { get; set; } } I have a read only view that uses DisplayForModel and an update view that uses EditorForModel. I want the DisplayForModel view to show the StateName property, and the EditorForModel view use the StateID property (I am actually rendering a dropdownlist based on this). I have not been able to figure out how to decorate my viewmodel properties to create this behavior.

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  • Possible bug in ASP.NET MVC with form values being replaced.

    - by Dan Atkinson
    I appear to be having a problem with ASP.NET MVC in that, if I have more than one form on a page which uses the same name in each one, but as different types (radio/hidden/etc), then, when the first form posts (I choose the 'Date' radio button for instance), if the form is re-rendered (say as part of the results page), I seem to have the issue that the hidden value of the SearchType on the other forms is changed to the last radio button value (in this case, SearchType.Name). Below is an example form for reduction purposes. <% Html.BeginForm("Search", "Search", FormMethod.Post); %> <%= Html.RadioButton("SearchType", SearchType.Date, true) %> <%= Html.RadioButton("SearchType", SearchType.Name) %> <input type="submit" name="submitForm" value="Submit" /> <% Html.EndForm(); %> <% Html.BeginForm("Search", "Search", FormMethod.Post); %> <%= Html.Hidden("SearchType", SearchType.Colour) %> <input type="submit" name="submitForm" value="Submit" /> <% Html.EndForm(); %> <% Html.BeginForm("Search", "Search", FormMethod.Post); %> <%= Html.Hidden("SearchType", SearchType.Reference) %> <input type="submit" name="submitForm" value="Submit" /> <% Html.EndForm(); %> Resulting page source (this would be part of the results page) <form action="/Search/Search" method="post"> <input type="radio" name="SearchType" value="Date" /> <input type="radio" name="SearchType" value="Name" /> <input type="submit" name="submitForm" value="Submit" /> </form> <form action="/Search/Search" method="post"> <input type="hidden" name="SearchType" value="Name" /> <!-- Should be Colour --> <input type="submit" name="submitForm" value="Submit" /> </form> <form action="/Search/Search" method="post"> <input type="hidden" name="SearchType" value="Name" /> <!-- Should be Reference --> <input type="submit" name="submitForm" value="Submit" /> </form> Please can anyone else with RC1 confirm this? Maybe it's because I'm using an enum. I don't know. I should add that I can circumvent this issue by using 'manual' input () tags for the hidden fields, but if I use MVC tags (<%= Html.Hidden(...) %), .NET MVC replaces them every time. Many thanks. Update: I've seen this bug again today. It seems that this crops its head when you return a posted page and use MVC set hidden form tags with the Html helper. I've contacted Phil Haack about this, because I don't know where else to turn, and I don't believe that this should be expected behaviour as specified by David.

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  • Combine 3 select fields and validate as one in my User model in ruby on rails 3

    - by Psychonetics
    Ok I have 3 select boxes for selecting date of birth. I have constants setup in my User model to provide months, years etc.. Anyway I can successfully validate these select boxes separately. What I want to do is combine the :day, :month and :year and store in :birthday and validate the whole date as one so I can return 1 error rather than 3 separate ones. Also doing this will make it easier to store the validated date in my birthday field in my database. Part of my form <td> <%= f.input :day, :required => false, :label => "Birthday: " , :prompt => "Day", :collection => User::DAYS %></td> <td> <%= f.input :month, :label => false, :prompt => "Month", :collection => User::MONTHS %> </td> <td> <%= f.input :year, :label => false, :prompt => "Year", :collection => User::YEAR_RANGE %> </td> Part of User model MONTHS = ["January", 1], ["February", 2], ["March", 3], ["April", 4], ["May", 5], ["June", 6], ["July", 7], ["August", 8], ["September", 9], ["October", 10], ["November", 11], ["December", 12] # finish this DAYS = 1..31 # finish this START_YEAR = Time.now.year - 106 END_YEAR = Time.now.year YEAR_RANGE = START_YEAR..END_YEAR class User < ActiveRecord::Base attr_accessor :day, :month, :year validates_presence_of :day, :message = 'What day in a month was you born?' validates_presence_of :month, :message = 'What month was you born?' validates_presence_of :year, :message = 'What is your year of birth?' end

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  • How to bulk insert from CSV when some fields have new line character?

    - by z-boss
    I have a CSV dump from another DB that looks like this (id, name, notes): 1001,John Smith,15 Main Street 1002,Jane Smith,"2010 Rockliffe Dr. Pleasantville, IL USA" 1003,Bill Karr,2820 West Ave. The last field may contain carriage returns and commas, in which case it is surrounded by double quotes. I use this code to import CSV into my table: BULK INSERT CSVTest FROM 'c:\csvfile.csv' WITH ( FIELDTERMINATOR = ',', ROWTERMINATOR = '\n' ) SQL Server 2005 bulk insert cannot figure out that carriage returns inside quotes are not row terminators. How to overcome?

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  • Help me with a solution for what could be solutioned by virtual static fields... in FPC

    - by Gregory Smith
    Hi I'm doing an event manager in Freepascal Each event is an object type TEvent (=object), each kind of event must derive from this class. Events are differentiated by an integer identificator, assigned dynamically. The problem is that i want to retrieve the event id of an instance, and i can't do it well. All instances of a class(object) have a unique id = so it should be static field. All classes have a diferent id = so it should be virtual. Event ids are assignated in run time, and can change = so it can't be a simple method In sum, I can't put all this together. I'm looking for an elegant solution, i don't want to write a hardcoded table, actualizing it in every constructor... etc, i'd prefer something taking advantage of the polymorphism Can anyone help me with another technical or design solution? I remark I don't want to use class instead of object construct.(property doesn't work on objects? :(

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  • Is it possible to add custom fields to a Drupal taxonomy term?

    - by user278457
    I'd like to add a date field to a drupal taxonomy term, alongside the default "title" and "description" Is there some technique/php/module that lets me do this? Is it possible to do with CCK?? I need to be able to display the new field in the same view presenting the content nodes referencing the term. At the moment, I've added a date field to the content nodes with CCK, and it's displayed by the view. But that's not exactly what I'm going for, I just want to update one date per term.

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  • Django: How do I add arbitrary html attributes to input fields on a form?

    - by User
    I have an input field that is rendered with a template like so: <div class="field"> {{ form.city }} </div> Which is rendered as: <div class="field"> <input id="id_city" type="text" name="city" maxlength="100" /> </div> Now suppose I want to add an autocomplete="off" attribute to the input element that is rendered, how would I do that? Or onclick="xyz()" or class="my-special-css-class"?

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  • How make this special many2many fields validation using Django ORM?

    - by e-satis
    I have the folowing model: class Step(models.Model): order = models.IntegerField() latitude = models.FloatField() longitude = models.FloatField() date = DateField(blank=True, null=True) class Journey(models.Model): boat = models.ForeignKey(Boat) route = models.ManyToManyField(Step) departure = models.ForeignKey(Step, related_name="departure_of", null=True) arrival = models.ForeignKey(Step, related_name="arrival_of", null=True) I would like to implement the following check: # If a there is less than one step, raises ValidationError. routes = tuple(self.route.order_by("date")) if len(routes) <= 1: raise ValidationError("There must be at least two setps in the route") # save the first and the last step as departure and arrival self.departure = routes[0] self.arrival = routes[-1] # departure and arrival must at least have a date if not (self.departure.date or self.arrival.date): raise ValidationError("There must be an departure and an arrival date. " "Please set the date field for the first and last Step of the Journey") # departure must occurs before arrival if not (self.departure.date > self.arrival.date): raise ValidationError("Departure must take place the same day or any date before arrival. " "Please set accordingly the date field for the first and last Step of the Journey") I tried to do that by overloading save(). Unfortunately, Journey.route is empty in save(). What's more, Journey.id doesn't exists yet. I didn't try django.db.models.signals.post_save but suppose it will fail because Journey.route is empty as well (when does this get filled anyway?). I see a solution in django.db.models.signals.m2m_changed but there are a lot of steps (thousands), and I want to avoid to perform an operation for every single of them.

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  • JasperReports-Ireport: How to make the groupfield don't gets repeated every 3rows of fields?

    - by Aaron
    I have a web app and I need to integrate some JasperReports in this app. So I downloaded iReport and I used the templates. I choose the LeafGreen template, but I have a problem. When I have more than 4 elemets in my list, my headers gets repeated every 4 elements (see the image:) - I don't want this; once is enough. The problem: http://i39.tinypic.com/9kcp6p.jpg This is the template: hxtp://i44.tinypic.com/2ags1w1.jpg What I'm doing wrong?

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