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  • How to insert sub root node in xml file

    - by pravakar
    Hi guys hope all are doing good. I want to create one sub root node in my xml file like, <CapitalJobsList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <JobAds> -- element to create <JobAd> <AdvertiserDetails> <AdvertiserId>718508549</AdvertiserId> <AdvertiserName>ABC</AdvertiserName> </AdvertiserDetails> <ConsultantDetails> <ContactName>Naga Divakar</ContactName> <ContactPhone>6239 7755</ContactPhone> <ContactEmail>[email protected]</ContactEmail> <ContactFax>12345678912</ContactFax> </ConsultantDetails> <JobAdDetails> <DateEntered>2009-10-03T21:09:35.500</DateEntered> <AdvertiserJobRef>83754865</AdvertiserJobRef> <Title>IT Operations Manager</Title> <DescriptionShort>Large scale/exciting projects Mentor and manage o...</DescriptionShort> <Description>Large scale/exciting projects Mentor and manage others Management/technical mix This is a fantastic opportunity to join a high profile client who is active across both the commercial and Government domain. As the IT Operations Manager you will be responsible for leading and mentoring a small team of Infrastructure Engineers to ensure the availability and performance of the IT infrastructure. You w</Description> <SalaryMin>0.00</SalaryMin> <SalaryMax>0.00</SalaryMax> <WorkType xsi:nil="true" /> <Location>) as [JobAd/JobAdDetails/Bullets], isnull(Job</Location> <PostCode>2600</PostCode> <ClosingDate>2009-11-01T00:00:00</ClosingDate> <Keywords xsi:nil="true" /> <ApplyEmail xsi:nil="true" /> <ApplyURL>http://jobview.careerone.com.au/GetJob.aspx?JobID=83754865</ApplyURL> </JobAdDetails> <JobAdOptions> <BlindPost xsi:nil="true" /> <AdFormatType xsi:nil="true" /> <AdTemplateName xsi:nil="true" /> <ShowContactDetails xsi:nil="true" /> <ShowSalary xsi:nil="true" /> <HasVideo xsi:nil="true" /> <ResumeRequired>1</ResumeRequired> <ResidentsOnly>0</ResidentsOnly> </JobAdOptions> <CategoryList> <Category xsi:nil="true" /> </CategoryList> <RegionsList> <Region>ACT</Region> </RegionsList> <LevelsList> <Level xsi:nil="true" /> </LevelsList> </JobAd> <JobAd> <AdvertiserDetails> <AdvertiserId>718508549</AdvertiserId> <AdvertiserName>ABC</AdvertiserName> </AdvertiserDetails> <ConsultantDetails> <ContactName>Naga Divakar</ContactName> <ContactPhone>6239 7755</ContactPhone> <ContactEmail>[email protected]</ContactEmail> <ContactFax>12345678912</ContactFax> </ConsultantDetails> <JobAdDetails> <DateEntered>2009-10-03T21:09:35.530</DateEntered> <AdvertiserJobRef>83731488</AdvertiserJobRef> <Title>SAP Developers Required in Canberra - 12 month contract</Title> <DescriptionShort>My client, a large government department in Canbe...</DescriptionShort> <Description>My client, a large government department in Canberra, seeks two SAP Developers for 12 month ongoing contracts. Two SAP Developers Required Expert level ABAP programming skills Large SAP landscape - SAP R/3, SAP Web, SAP BI, SAP ITS My client, a large government department in Canberra, seeks two SAP Developers for 12 month ongoing contracts. My client is a large government department in Canberra, a</Description> <SalaryMin>0.00</SalaryMin> <SalaryMax>0.00</SalaryMax> <WorkType xsi:nil="true" /> <Location>) as [JobAd/JobAdDetails/Bullets], isnull(Job</Location> <PostCode>2600</PostCode> <ClosingDate>2009-11-01T00:00:00</ClosingDate> <Keywords xsi:nil="true" /> <ApplyEmail xsi:nil="true" /> <ApplyURL>http://jobview.careerone.com.au/GetJob.aspx?JobID=83731488</ApplyURL> </JobAdDetails> <JobAdOptions> <BlindPost xsi:nil="true" /> <AdFormatType xsi:nil="true" /> <AdTemplateName xsi:nil="true" /> <ShowContactDetails xsi:nil="true" /> <ShowSalary xsi:nil="true" /> <HasVideo xsi:nil="true" /> <ResumeRequired>1</ResumeRequired> <ResidentsOnly>0</ResidentsOnly> </JobAdOptions> <CategoryList> <Category xsi:nil="true" /> </CategoryList> <RegionsList> <Region>ACT</Region> </RegionsList> <LevelsList> <Level xsi:nil="true" /> </LevelsList> </JobAd> </JobAds> </CapitalJobsList> I have used the sql query for xml path like: select r.advid as [JobAd/AdvertiserDetails/AdvertiserId], CompanyName as [JobAd/AdvertiserDetails/AdvertiserName], firstname +'' ''+ lastname as [JobAd/ConsultantDetails/ContactName], WorkPhone as [JobAd/ConsultantDetails/ContactPhone], AdvEmail as [JobAd/ConsultantDetails/ContactEmail], FaxNo as [JobAd/ConsultantDetails/ContactFax], Job_CreatedDate as [JobAd/JobAdDetails/DateEntered], Job_Id as [JobAd/JobAdDetails/AdvertiserJobRef], Job_Title as [JobAd/JobAdDetails/Title], substring(Job_Description,0,50)+''...'' as [JobAd/JobAdDetails/DescriptionShort], Job_Description as [JobAd/JobAdDetails/Description], CONVERT(DECIMAL(10,2),MinSalary) as [JobAd/JobAdDetails/SalaryMin], CONVERT(DECIMAL(10,2),MaxSalary) as [JobAd/JobAdDetails/SalaryMax], Job_Type as [JobAd/JobAdDetails/WorkType], isnull(Job_Bullets,'') as [JobAd/JobAdDetails/Bullets], isnull(Job_Location,'') as [JobAd/JobAdDetails/Location], Job_PostCode as [JobAd/JobAdDetails/PostCode], Job_ExpireDate as [JobAd/JobAdDetails/ClosingDate], Job_Keywords as [JobAd/JobAdDetails/Keywords], ApplyEmail as [JobAd/JobAdDetails/ApplyEmail], Job_BrandURL+Job_Id as [JobAd/JobAdDetails/ApplyURL], BlindPost as [JobAd/JobAdOptions/BlindPost], AdFormatType as [JobAd/JobAdOptions/AdFormatType], AdTemplateName as [JobAd/JobAdOptions/AdTemplateName], ShowContactDetails as [JobAd/JobAdOptions/ShowContactDetails], ShowSalary as [JobAd/JobAdOptions/ShowSalary], HasVideo as [JobAd/JobAdOptions/HasVideo], ResumeRequired as [JobAd/JobAdOptions/ResumeRequired], ResidentsOnly as [JobAd/JobAdOptions/ResidentsOnly], Job_Category as [JobAd/CategoryList/Category], Job_Location_State as [JobAd/RegionsList/Region], [Level] as [JobAd/LevelsList/Level] from DR_Adv_Registration r, DR_CareerOne_ACTJobs j where r.Advid = j.Advid and job_location_city like(''%'+''+ @City +''+'%'') and job_location_state in('''+ @State +''') and job_status=1 for xml path(''''), Root(''CapitalJobsList''),ELEMENTS XSINIL So, suggest me how to get the sub root node. Thanks in advance

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  • How to decode ASN.1 to XML with erlang

    - by shian
    Hi I use asn1 module in erlang to decode. The output is like {'UL-CCCH-Message',asn1_NOVALUE, {rrcConnectionRequest, {'RRCConnectionRequest', {'tmsi-and-LAI', {'TMSI-and-LAI-GSM-MAP', [1,0,0,0,0,1,1,1,1,1,1,0,1,0,0,0,0,1,1,0,1,1,0,1,0,1,1, 1,1,0,1,0], {'LAI', {'PLMN-Identity',[2,2,6],[0,1]}, [0,1,1,1,1,0,0,1,1,0,0,0,1,1,0,1]}}}, terminatingBackgroundCall,noError, {'MeasuredResultsOnRACH', {'MeasuredResultsOnRACH_currentCell', {fdd, {'MeasuredResultsOnRACH_currentCell_modeSpecificInfo_fdd', {'cpich-Ec-N0',39}}}}, asn1_NOVALUE}, asn1_NOVALUE}}} How can I output XML instead of erlang term?

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  • Sort/Group XML data with PHP?

    - by Volmar
    I'm trying to make a page using data from the discogs.com (XML)-API. i've been parsing it with simpleXML and it's working pretty well but there is some things i'm not sure how to do. Here is part of the XML: <releases> <release id="1468764" status="Accepted" type="Main"> <title>Versions</title> <format>12", EP</format> <label>Not On Label</label> <year>1999</year> </release> <release id="72246" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>LP</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="890064" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>CD</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="1563561" status="Accepted" type="TrackAppearance"> <title>Ännu En Gång Vol. 3</title> <trackinfo>Backtrack</trackinfo> <format>Cass, Comp, Mix</format> <label>Hemmalaget</label> <year>2001</year> </release> </releases> What i want to achieve is something similair to how discogs presents the releases: http://www.discogs.com/artist/Mics+Of+Fury where diferent versions of the same release are sorted together. (see. The M.O.F Blend in my link) This is done on discogs with having a master release that features the other releases. unfortunately this information isn't present in the API data, so i want to do the same thing by grouping the <release>-nodes with the same <title>-tags, or add a flag to the <releases> that don't have a unique <title>? any good ideas on the best way of doing this? i also like to know if it's possible to count the <release>-nodes (child of releases) that have the same type-attribute? like in this example count the releases with the type "Main"? maybe it's better to do this things with XMLReader or XPath?

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  • Python modify an xml file

    - by michele
    I have this xml model. link text So I have to add some node (see the text commented) to this file. How I can do it? I have writed this partial code but it doesn't work: xmldoc=minidom.parse(directory) child = xmldoc.createElement("map") for node in xmldoc.getElementsByTagName("Environment"): node.appendChild(child) Thanks in advance.

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  • Does an XPathDocument load the whole xml document?

    - by Wires
    If I do XPathDocument doc = new XPathDocument("filename.xml"); Does that load the entire document into memory? I'm writing a mobile phone app and the document might store lots of data that doesn't ever need to all be loaded at the same time. Mobile phones don't usually have too much ram!

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  • Convert text to xml

    - by Nave
    I want to convert a tab delimited text file to a XML file. I was able to do it with a single character delimiter. But how do i extend it to tabs? I am coding in C# and using Visual Studio 2010.

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  • Merging XML records into one

    - by BhanuPratap Tarigopula
    I am new to XSLT. I have requirement of merging and adding. XML: <OrderDetails> <OrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <OrderDetail action="add"> <OrderedUnits>12</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <IOrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295762</PONumber> </OrderDetail> <OrderDetails> If the LocationCode, Date, and PONumber fields match, I need to add the OrderedUnits and make it only one entry. Expected output XML: <OrderDetails> <OrderDetail action="add"> <OrderedUnits>30</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <IOrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295762</PONumber> </OrderDetail> <OrderDetails> How can I write this XSLT?

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  • xml appending issue - in ie, chrome browsers

    - by 3gwebtrain
    Hi, i am using this coding for my xml information to append in to html. As well it works fine. but in the ie7,ie8 as well chrome browser it's not propelry. This code work9ing well with firefox,opera, safari.. i unable to find, what is the mistake i made this.. any one help me please? $(function(){ var thisPage; var parentPage; $('ul.left-navi li a').each(function(){ $('ul.left-navi li a').removeClass('current'); var pathname = (window.location.pathname.match(/[^\/]+$/)[0]); var currentPage = $(this).attr('href'); var pathArr = new Array(); pathArr = pathname.split("."); var file = pathArr[pathArr.length - 2]; thisPage = file; if(currentPage==pathname){ $(this).addClass("active"); } }) $.get('career-utility.xml',function(myData){ var receivedData = myData; var myXml = $(myData).find(thisPage); parentPage = thisPage; var overviewTitle = myXml.find('overview').attr('title'); var description = myXml.find('discription').text(); var mainsublinkTitle = myXml.find('mainsublink').attr('title'); var thisTitle = myXml.find("intro").attr('title'); var thisIntro = myXml.find("introinfo").text(); $('<h3>'+overviewTitle+'</h3>').appendTo('.overViewInfo'); $('<p>'+description+'</p>').appendTo('.overViewInfo'); var sublinks = myXml.find('mainsublink').children('sublink'); $('#intro h3').append(thisTitle); $('#intro').append(thisIntro); sublinks.each(function(numsub){ var newSubLink = $(this); var sublinkPage = $(this).attr('pageto'); var linkInfo = $(this).text(); $('ul.career-link').append('<li><a href="'+sublinkPage+'">'+linkInfo+'</a></li>'); }) // alert('thisTitle : '+thisTitle+'thisIntro :'+thisIntro); $(myXml).find('listgroup').each(function(index){ var count = index; var listGroup = $(this); var listGroupTitle = $(this).attr('title'); var shortNote = $(this).attr('shortnote'); var subLink = $(this).find('sublist'); var firstList = $(this).find('list'); $('.grouplist').append('<div class="list-group"><h3>'+listGroupTitle+'</h3><ul class="level-one level' + count + '"></ul></div>'); firstList.each(function(listnum) { $(this).wrapInner('<li>') .find('sublistgroup').wrapInner('<ul>').children().unwrap() .find('sublist').wrapInner('<li>').children().unwrap(); // Append content of 'list' node $('ul.level'+count).append($(this).children()); }); }); }); })

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  • Saving an XML that has invalid characters

    - by BDotA
    there are code snippets that strip the invalid characters inside a string before we save it as an XML ... but I have one more problem: Let's say my user wants to have a column name like "[MyColumnOne] ...so now I do not want to strip these "[","] well because these are the ones that user has defined and wants to see them so if I use some codes that are stripping the invalid characters they are also removing "[" and "[" but in this case I still need them to be saved... what can I do?

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  • Write xml file with lxml

    - by systempuntoout
    Having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

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  • 'How decode my encode xml data?

    - by Alex
    Hi <% 'Stage 1 datas=Server.URLencode("<PaginationData currentPage=""1"" totalPages=""9""/>") response.write "Encode = " datas &"</br></br>" 'Stage 2 response.write "Decode = " 'How i again decode my encode data? %> In the "Stage 1" , i encode my xml data In the "Stage 2", How i decode the "Stage 1" Encode data? hoping your support

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  • TouchCode XML parsing error

    - by itsaboutcode
    Hi, I have a xml document which has only one element in the document, which is <error>error string<error> But when i try to parse it, it says this document has no element at all. In other words when i try to access the rootElement it says "null" CXMLDocument *rssParser = [[[CXMLDocument alloc] initWithContentsOfURL:url options:0 error:nil] autorelease]; NSLog(@"Root: %@",[[rssParser rootElement] name]); Please tell me what is wroing with this. Thanks

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  • Programatically upload XML file to SSRS server

    - by xt_20
    Hi all, How do I programatically upload an XSLT file to an SSRS server database? I would like exactly the same functionality as the 'Upload File', preferably using the 'rs' command. I have tried rs.CreateResource, but it doesn't seem to work for XML/XSLT files (though it works for Excel and image files) I understand that manipulating the SSRS db is not supported. Thanks

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  • Actionscript 3 E4X working with MMS values in XML

    - by user150946
    I am building an application using Action script 3 I am retrieving some XML from the web however the node names are mms:Image mms:Results etc my action script compiler is throwing an error becuase it is not expecting to see the semi colon in the node name. How to I access the nodes? thanks

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  • Replace XML Bullet Points Found in Feed in Classic ASP

    - by StevieB
    Hey I am currently reading in a XML file which contains bullet list in the following container i.e. ? the average pension contribution rate for executive directors . I am having a problem with symbol directly before the text of each bullet point I want to remove it i.e Replace(text,"old","new") but i cant seem to find what value that bullet point actually is to replace of that makes sense. Thanks

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