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• Search the internet for a term selected in a text editor/viewer

  - by cipricus

  It seems possible (as I learned from a comment to this question made by user55822) to use Artha in order to search a term on the Internet by using "keybinding". What the aforementioned user says is that "you could search mouse selection anywhere by using an app like Artha, or by keybinding sh -c 'firefox "http://translate.google.com/#en/fr/$(xclip -o)"' (example given translate english into french)" A lot of things are obscure for me here. I could use Artha or keybinding (as alternative), or both? How to do that in each case? and "The command I gave you will open google translate in Firefox with your mouse selection (text highlighted) as a query. Use sh -c 'firefox "https://www.google.com/search?q=$(xclip -o)"' if you want regular Google over Google translate. And obviously, that would work everywhere" I do not know what to do with that formula. What should I do exactly? How to use it? In what application?

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• How can I permute pairs across a set?

  - by sila

  I am writing a bet settling app in C# and WinForms. I have 6 selections, 4 of them have won. I know that using the following formula from Excel: =FACT(selections)/(FACT(selections-doubles))/FACT(doubles) This is coded into my app and working well: I can work out how many possible doubles (e.g., AB, AC, AD, AE, BC, BD, BE, etc.) need to be resolved. But what I can't figure out is how to do the actual calculation. How can I efficiently code it so that every combination of A, B, C, and D has been calculated? All my efforts thus far on paper have proved to be ugly and verbose: is there an elegant solution to this problem?

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• Confusion about Rotation matrices from Euler Angles

  - by xEnOn

  I am trying to learn more about Euler Angles so as to help myself in understanding how I can control my camera better in the game. I came across the following formula that converts Euler Angles to rotation matrices: In the equation, I could see that the first matrix from the left is the rotation matrix about x-axis, the second is about y-axis and the third is about z-axis. From my understanding about ordinary matrix transformations, the later transformation is always applied to the right hand side. And if I'm right about this, then the above equation should have a rotation order starting from rotating about z-axis, y-axis, then finally x-axis. But, from the symbols it seems that the rotation order start rotating about x-axis, then y-axis, then finally z-axis. What should the actual order of the rotation be? Also, I am confuse about if the input vector, in this case, would be a row vector on the left, or a column vector on the right?

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• Subtext 2.5 is released!

  After more then one year since last release, we are happy to announce that the new version of Subtext, number 2.5, has just been released. The main features are the new dashboard, featuring the Ayendes formula for blog post popularity, and a improved site-wide search based on Lucene.net. More about that will be published shortly, in the meantime you can read how the search engine has been implemented using Lucene.net. Lots of improvements have been made to the codebase of Subtext for this release: ...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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• Scan-Line Z-Buffering Dilemma

  - by Belgin

  I have a set of vertices in 3D space, and for each I retain the following information: Its 3D coordinates (x, y, z). A list of pointers to some of the other vertices with which it's connected by edges. Right now, I'm doing perspective projection with the projecting plane being XY and the eye placed somewhere at (0, 0, d), with d < 0. By doing Z-Buffering, I need to find the depth of the point of a polygon (they're all planar) which corresponds to a certain pixel on the screen so I can hide the surfaces that are not visible. My questions are the following: How do I determine to which polygon does a pixel belong to so I could use the formula of the plane which contains the polygon to find the Z-coordinate? Are my data structures correct? Do I need to store something else entirely in order for this to work? I'm just projecting the vertices onto the projection plane and joining them with lines based on the pointer lists.

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• Nice function for "rolling score up"?

  - by bobobobo

  I'm adding to the player's score, and I'm using a per-frame formula like: int score, displayedScore ;// score is ACTUAL score player has, // displayedScore is what is shown this frame to the player // (the creeping/"rolling" number) float disparity = score - displayedScore ; int d = disparity * .1f ; // add 1/10 of the difference, if( !d ) d = signum( disparity ) ; // last 10 go by 1's score += d ; Where inline int signum( float val ){ if( val > 0 ) return 1 ; else if( val < 0 ) return -1 ; else return 0 ; } So, it kind of works where it makes big changes rapidly, then it creeps in the last few one at a time. But I'm looking for better (or possibly well known?) score-creeping functions. Any one?

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• Translate along local axis

  - by Aaron

  I have an object with a position matrix and a rotation matrix (derived from a quaternion, but I digress). I'm able to translate this object along world-relative vectors, but I'm trying to figure out how to translate it along local-relative vectors. So if the object is tilted 45 degrees around its Z-axis the vector (1, 0, 0) would make it move to the upper right. For world-space translations I simply turn the movement vector into a matrix and multiply it by the position matrix: position_mat = translation_mat * position_mat. For local-space translations I'd think I'd have to use the rotation matrix into that formula, but I see the object spin around instead when I apply a translation over time no matter where I multiply the rotation matrix.

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• Isometric tile range aquisition

  - by Steve

  I'm putting together an isometric engine and need to cull the tiles that aren't in the camera's current view. My tile coordinates go from left to right on the X and top to bottom on the Y with (0,0) being the top left corner. If I have access to say the top left, top right, bot left and bot right corner coordinates, is there a formula or something I could use to determine which tiles fall in range? I've linked a picture of the layout of the tiles for reference. If there isn't one, or there's a better way to determine which tiles are on screen and which to cull, I'm all ears and am grateful for any ideas. I've got a few other methods I may be able to try such as checking the position of the tile against a rectangle. I pretty much just need something quick. Thanks for giving this a read =)

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• Nearest color algorithm using Hex Triplet

  - by Lijo

  Following page list colors with names http://en.wikipedia.org/wiki/List_of_colors. For example #5D8AA8 Hex Triplet is "Air Force Blue". This information will be stored in a databse table (tbl_Color (HexTriplet,ColorName)) in my system Suppose I created a color with #5D8AA7 Hex Triplet. I need to get the nearest color available in the tbl_Color table. The expected anaser is "#5D8AA8 - Air Force Blue". This is because #5D8AA8 is the nearest color for #5D8AA7. Do we have any algorithm for finding the nearest color? How to write it using C# / Java? REFERENCE http://stackoverflow.com/questions/5440051/algorithm-for-parsing-hex-into-color-family http://stackoverflow.com/questions/6130621/algorithm-for-finding-the-color-between-two-others-in-the-colorspace-of-painte Suggested Formula: Suggested by @user281377. Choose the color where the sum of those squared differences is minimal (Square(Red(source)-Red(target))) + (Square(Green(source)-Green(target))) +(Square(Blue(source)-Blue(target)))

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• Calculating angle between 2 vectors

  - by Error 454

  I am working on some movement AI where there are no obstacles and movement is restricted to the XY plane. I am calculating 2 vectors: v - the direction of ship 1 w - the vector pointing from the position of ship 1 to ship 2 I am then calculating the angle between these two vectors using the standard formula: arccos( v . w / ( |v| |w| ) ) The problem I'm having is the nature of arccos only returning values between 0 and 180. This makes it impossible to determine whether I should turn left or right to face the other ship. Is there a better way to do this?

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• How to syncronize two animations without delays

  - by GeKi

  I have one character idle animation running inside a game in a loop, over and over again. A a certain time I trigger another animation to be played, for the same character. The second animation won't play immediately, as will be a discontinuity in my character animation. First I wait for the idle animation to finish and then I play my second animation. Now I have a smooth, continuous animation, BUT I have introduced a delay between my action and character animation. If I play the second animation right away as it is triggered, the character animation won't be continuous and smooth. I was thinking on breaking the idle animation in small pieces and also to have the same number of second action animations to match the last frame of the idle pieces. This won't solve the delay completely, only will minimize it a bit. So it's a magic formula of how can I get rid of this delay? Thanks.

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• In 3D camera math, calculate what Z depth is pixel unity for a given FOV

  - by badweasel

  I am working in iOS and OpenGL ES 2.0. Through trial and error I've figured out a frustum to where at a specific z depth pixels drawn are 1 to 1 with my source textures. So 1 pixel in my texture is 1 pixel on the screen. For 2d games this is good. Of course it means that I also factor in things like the size of the quad and the size of the texture. For example if my sprite is a quad 32x32 pixels. The quad size is 3.2 units wide and tall. And the texcoords are 32 / the size of the texture wide and tall. Then the frustum is: matrixFrustum(-(float)backingWidth/frustumScale,(float)backingWidth/frustumScale, -(float)backingHeight/frustumScale, (float)backingHeight/frustumScale, 40, 1000, mProjection); Where frustumScale is 800 for a retina screen. Then at a distance of 800 from camera the sprite is pixel for pixel the same as photoshop. For 3d games sometimes I still want to be able to do this. But depending on the scene I sometimes need the FOV to be different things. I'm looking for a way to figure out what Z depth will achieve this same pixel unity for a given FOV. For this my mProjection is set using: matrixPerspective(cameraFOV, near, far, (float)backingWidth / (float)backingHeight, mProjection); With testing I found that at an FOV of 45.0 a Z of 38.5 is very close to pixel unity. And at an FOV of 30.0 a Z of 59.5 is about right. But how can I calculate a value that is spot on? Here's my matrixPerspecitve code: void matrixPerspective(float angle, float near, float far, float aspect, mat4 m) { //float size = near * tanf(angle / 360.0 * M_PI); float size = near * tanf(degreesToRadians(angle) / 2.0); float left = -size, right = size, bottom = -size / aspect, top = size / aspect; // Unused values in perspective formula. m[1] = m[2] = m[3] = m[4] = 0; m[6] = m[7] = m[12] = m[13] = m[15] = 0; // Perspective formula. m[0] = 2 * near / (right - left); m[5] = 2 * near / (top - bottom); m[8] = (right + left) / (right - left); m[9] = (top + bottom) / (top - bottom); m[10] = -(far + near) / (far - near); m[11] = -1; m[14] = -(2 * far * near) / (far - near); } And my mView is set using: lookAtMatrix(cameraPos, camLookAt, camUpVector, mView); * UPDATE * I'm going to leave this here in case anyone has a different solution, can explain how they do it, or why this works. This is what I figured out. In my system I use a 10th scale unit to pixels on non-retina displays and a 20th scale on retina displays. The iPhone is 640 pixels wide on retina and 320 pixels wide on non-retina (obsolete). So if I want something to be the full screen width I divide by 20 to get the OpenGL unit width. Then divide that by 2 to get the left and right unit position. Something 32 units wide centered on the screen goes from -16 to +16. Believe it or not I have an excel spreadsheet do all this math for me and output all the vertex data for my sprite sheet. It's an arbitrary thing I made up to do .1 units = 1 non-retina pixel or 2 retina pixels. I could have made it .01 units = 2 pixels and someday I might switch to that. But for now it's the other. So the width of the screen in units is 32.0, and that means the left most pixel is at -16.0 and the right most is at 16.0. After messing a bit I figured out that if I take the [0] value of an identity modelViewProjection matrix and multiply it by 16 I get the depth required to get 1:1 pixels. I don't know why. I don't know if the 16 is related to the screen size or just a lucky guess. But I did a test where I placed a sprite at that calculated depth and varied the FOV through all the valid values and the object stays steady on screen with 1:1 pixels. So now I'm just calculating the unityDepth that way. If someone gives me a better answer I'll checkmark it.

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• Does Google counts backlinks from homepage to inside pages?

  - by SharkTheDark

  I have a site with good PR and my inside pages are getting increase of PR, but they don't have links pointing to them, only from my homepage. Does that means that Google counts ALL links on my homepage, including links to inside pages? Does it calculate inside pages PR with one coming from my domain, my homepage, too? Also, if inside pages that got high PR from homepage have link back to homepage, will that increase homepage PR additionally, since those links should count too? By Google PR algorithm formula, by calculations on Wikipedia and Stanford PR algorithm explanation ( which is originally developed by ) it counts those links, and also it counts after-increase backlink again, making few times circle ( it stops because of d ( 0.85 ) factor. ), but it counts them. Does anyone know is this correct?

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• Using VBA to model data in Autodesk Inventor?

  - by user108478

  I have a close friend who is using a specific device that records the dimensions of an object as it is eroded and outputs the dimensional data to an excel sheet. The object is spherical in nature but is eroded from the top and bottom, so the shape is constantly changing and a single formula for surface area and volume would not work. This is where Inventor comes in. My friend can plug the dimensional data to Inventor and it immediately returns the surface area and volume. The erosion process takes several minutes to complete and records data at very short intervals, so it would be very arduous to plug in the data thousand of time. Since Inventor supports macros and VBA, is there a way to plug the data into Inventor and output it into another spreadsheet? Any suggestions would be appreciated.

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• How can I compute the Big-O notation for a given piece of code?

  - by TheNew Rob Mullins

  So I just took a data structure midterm today and I was asked to determine the run time, in Big O notation, of the following nested loop: for (int i = 0; i < n-1; i++) { for(int j = 0; j < i; j++2) { //1 Statement } } I'm having trouble understanding the formula behind determining the run time. I thought that since the inner loop has 1 statement, and using the series equation of: (n * (n - 1)) / 2, I figured it to be: 1n * (n-1) / 2. Thus equaling (n^2 - 1) / 2. And so I generalized the runtime to be O(n^2 / 2). I'm not sure this is right though haha, was I supposed to divide my answer again by 2 since j is being upped in intervals of 2? Or is my answer completely off?

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• Find the new coordinates using a starting point, a distance, and an angle

  - by dqhendricks

  Okay, say I have a point coordinate. var coordinate = { x: 10, y: 20 }; Now I also have a distance and an angle. var distance = 20; var angle = 72; The problem I am trying to solve is, if I want to travel 20 points in the direction of angle from the starting coordinate, how can I find what my new coordinates will be? I know the answer involves things like sin/cosin, because I used to know how to do this, but I have since forgotten the formula. Can anyone help?

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• Size of an image imported with FreeImage

  - by KaiserJohaan

  I'm having abit of a brainfart and I can't quite grasp what I'm doing wrong. It's quite simple, I am importing an image with FreeImage (http://freeimage.sourceforge.net/) which has a method FreeImage_GetBits that returns a pointer to the first byte of the image data. I then try to load all the data into memory using (bitsperpixel / 8) * pixelsWidth ' pixelHeight, like this: uint32_t bitsPerPixel = FreeImage_GetBPP(bitmap); // resolves to 24 uint32_t widthInPixels = FreeImage_GetWidth(bitmap); // resolves to 1024 uint32_t heightInPixels = FreeImage_GetHeight(bitmap); // resolves to 1024 // container is a std::vector<uint8_t> pkgMaterial.mTextureData.insert(pkgMaterial.mTextureData.begin(), FreeImage_GetBits(bitmap), FreeImage_GetBits(bitmap) + ((bitsPerPixel/8) * widthInPixels * heightInPixels)); I have a jpg which is 31 kilobytes in size on disc. Yet when I load it using the above formula, I see the vector is then filled with 3145728 bytes, which is approx 3145 kilobytes. What am I doing wrong?

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• algoritm and structure pseucode [closed]

  - by user72759

  Create entries, which administers the test, which is 20 questions, the responses and fixed the 5 correct answer for each question. Write this test, if the execution of the algorithm to each recipe realisations change the order of questions and answers and responses are notified by user enters the correct answer. 2. Writin' example, where the line 2 is used stack. Create a stack of 20 items that the first element is 1, and the next is calculated by the formula an=an-1+1/an-1. Found this stack items that are whole numbers.

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• How can I calculate the angle between two 2D vectors?

  - by Error 454

  I am working on some movement AI where there are no obstacles and movement is restricted to the XY plane. I am calculating two vectors, v, the facing direction of ship 1, and w, the vector pointing from the position of ship 1 to ship 2. I am then calculating the angle between these two vectors using the formula arccos((v · w) / (|v| · |w|)) The problem I'm having is that arccos only returns values between 0° and 180°. This makes it impossible to determine whether I should turn left or right to face the other ship. Is there a better way to do this?

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• How do I find a unit vector of another in Java?

  - by Shijima

  I'm writing a Java formula based on this tutorial: 2-D elastic collisions without Trigonometry. I am in the section "Elastic Collisions in 2 Dimensions". Part of step 1 says: Next, find the unit vector of n, which we will call un. This is done by dividing by the magnitude of n. My below code represents the normal vector of 2 objects (I'm using a simple array to represent the normal vector). int[] normal = new int[2]; normal[0] = ball2.x - ball1.x; normal[1] = ball2.y - ball1.y; I am unsure what the tutorial means by dividing the magnitude of n to get the un. What is un? How can I calculate it with my Java array?

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• F1 Pit Pragmatics

  Occasionally, you just have to man up and deal with complex systems. In fact, sometimes you just need to sacrifice everything else in the name of performance. In Formula 1 Racing, each car has up to 100 sensors, transmitting around 30Gb of data over the course of a race (70% in real-time). This data is then processed by no less than 3 servers (per car) so that the engineers in the pit have access to telemetry, strategy information, timing feeds, while the servers are exposed to carbon dust, oil,...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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• Problem with currency formats and big numbers [on hold]

  - by user132750

  I am working on a dollars to euros/euros to dollars converter in C#. I got the formula, $ times 0.73361 = euro, and I have checked Google with the answers. They were right, (1 dollar equals 0.73 euros). However, it stops working properly when the dollar input value is higher than $1363. This is what I get with $1364: $1364 = 1 000,64 €. I don't know what to do, will someone please help me? Thanks. decimal toEuro; Val.doy = "$" + decimal.Parse(richTextBox1.Text); //Ignore this, it's for the output form CultureInfo eu = new CultureInfo("fr-FR"); toEuro = decimal.Parse(richTextBox1.Text.Trim()); toEuro = toEuro * 0.73361m; richTextBox1.Clear(); Val.duh = toEuro.ToString("C2", eu);

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• Can't join OS X Mavericks to AD Domain

  - by watkipet

  I'm attempting to join an OS X Mavericks (10.9) client to a Windows Server 2008 Active Directory domain, however the bind fails with this error in the OS X client's system.log: Oct 24 15:03:15 host.domain.com com.apple.preferences.users.remoteservice[5547]: -[ODCAddServerSheetController handleOtherActionError: gotError: Error Domain=com.apple.OpenDirectory Code=5202 "Authentication server encountered an error while attempting the requested operation." UserInfo=0x7f9e6cb3e180 {NSLocalizedDescription=Authentication server encountered an error while attempting the requested operation., NSLocalizedFailureReason=Authentication server encountered an error while attempting the requested operation.}, Authentication server encountered an error while attempting the requested operation. I've joined (bound) Ubuntu Linux clients to the same domain with net ads join in the past with no problems (using the same administrative user). I don't have access to any server logs. Here's the GUI error (from Directory Utility) on the OS X client: Here's the GUI error (from User's and Groups) in System Preferences on the OS X client: Update After some Wiresharking I've got some more info: OS X Client - KDC (over UDP): AS_REQ (no padata) OS X Client <- KDC (over UDP): KRB5KDC_ERR_PREAUTH_REQUIRED OS X Client - KDC (over UDP): AS_REQ (this time with PA-ENC-TIMESTAMP in padata) OS X Client <- KDC (over UDP): KRB5KDC_ERR_RESPONSE_TOO_BIG OS X Client - KDC (over TCP): AS_REQ (also with PA-ENC-TIMESTAMP in padata) OS X Client <- KDC (over TCP): KDC_ERR_ETYPE_NOSUPP ...and that's it. This is what I think is going on: The OS X client sends a kerberos request. The KDC says, "You need to pre-authenticate. Try again" The OS X client tries to pre-authenticate (all this so far is over UDP) Something gets lost on our network and the KDC says, "Oops something went wrong" The OS X client switches to TCP and tries again. Over TCP, the KDC says, "You're using an encryption type I don't support" Note that in its padata records, the OS X client is always using "aes256-cts-hmac-sha1-96" as its encryption type. However, in its KDC_REQ_BODY record it lists the aes256-cts-hmac-sha1-96, aes128-cts-hmac-sha1-96, des3-cbc-sha1, and rc4-hmac encryption types. When the KDC comes back with KDC_ERR_ETYPE_NOSUPP, it uses rc4-hmac as its encryption type in its padata record. I know next to nothing about Kerberos, but it seems to me that the OS X client should go ahead and try the rc4-hmac encryption type. However, it does nothing after this. Update 2 Here's the debug log from Directory Services on the OS X client. Sorry--it's long. 2013-10-25 14:19:13.219128 PDT - 10544.20463 - ODNodeCustomCall request, NodeID: 52A65FAE-4B24-455D-86EC-2199A780D234, Code: 80 2013-10-25 14:19:13.220409 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - client requested OU - 'CN=Computers,DC=domain,DC=com' 2013-10-25 14:19:13.220427 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - Binding using '[email protected]' for kerberos ID 2013-10-25 14:19:13.220571 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - new kerberos credential cache 'MEMORY:0x7fa713635470' for '[email protected]' 2013-10-25 14:19:13.220623 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: loop 1 2013-10-25 14:19:13.220639 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - KDC send 0 patypes 2013-10-25 14:19:13.220653 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - fast disabled, not doing any fast wrapping 2013-10-25 14:19:13.220699 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - Trying to find service kdc for realm DOMAIN.COM flags 0 2013-10-25 14:19:13.221275 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - submissing new requests to new host 2013-10-25 14:19:13.221326 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - connecting to host: udp 192.168.0.1:kerberos (192.168.0.1) tid: 00000001 2013-10-25 14:19:13.221373 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - writing packet: udp 192.168.0.1:kerberos (192.168.0.1) tid: 00000001 2013-10-25 14:19:13.222588 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - reading packet: udp 192.168.0.1:kerberos (192.168.0.1) tid: 00000001 2013-10-25 14:19:13.222617 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - host completed: udp 192.168.0.1:kerberos (192.168.0.1) tid: 00000001 2013-10-25 14:19:13.222665 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_sendto_context DOMAIN.COM done: 0 hosts 1 packets 1 wc: 0.001960 nr: 0.000000 kh: 0.000560 tid: 00000001 2013-10-25 14:19:13.222705 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: loop 2 2013-10-25 14:19:13.222737 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: processing input 2013-10-25 14:19:13.222752 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: got an KRB-ERROR from KDC 2013-10-25 14:19:13.222775 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: KRB-ERROR -1765328359/Additional pre-authentication required 2013-10-25 14:19:13.222791 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - KDC send 4 patypes 2013-10-25 14:19:13.222800 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - KDC send PA-DATA type: 19 2013-10-25 14:19:13.222808 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - KDC send PA-DATA type: 2 2013-10-25 14:19:13.222816 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - KDC send PA-DATA type: 16 2013-10-25 14:19:13.222825 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - KDC send PA-DATA type: 15 2013-10-25 14:19:13.222840 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: using ENC-TS with enctype 18 2013-10-25 14:19:13.222850 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: using default_s2k_func 2013-10-25 14:19:13.227443 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - fast disabled, not doing any fast wrapping 2013-10-25 14:19:13.227502 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - Trying to find service kdc for realm DOMAIN.COM flags 0 2013-10-25 14:19:13.228233 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - submissing new requests to new host 2013-10-25 14:19:13.228320 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - connecting to host: udp 192.168.0.1:kerberos (192.168.0.1) tid: 00010001 2013-10-25 14:19:13.228374 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - writing packet: udp 192.168.0.1:kerberos (192.168.0.1) tid: 00010001 2013-10-25 14:19:13.229930 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - reading packet: udp 192.168.0.1:kerberos (192.168.0.1) tid: 00010001 2013-10-25 14:19:13.229957 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - host completed: udp 192.168.0.1:kerberos (192.168.0.1) tid: 00010001 2013-10-25 14:19:13.229975 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_sendto trying over again (reset): 0 2013-10-25 14:19:13.230023 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - Trying to find service kdc for realm DOMAIN.COM flags 2 2013-10-25 14:19:13.230664 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - submissing new requests to new host 2013-10-25 14:19:13.230726 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - connecting to host: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00010002 2013-10-25 14:19:13.230818 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - connecting to 11: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00010002 2013-10-25 14:19:13.231101 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - writing packet: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00010002 2013-10-25 14:19:13.232743 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - reading packet: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00010002 2013-10-25 14:19:13.232777 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - host completed: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00010002 2013-10-25 14:19:13.232798 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_sendto_context DOMAIN.COM done: 0 hosts 2 packets 2 wc: 0.005316 nr: 0.000000 kh: 0.001339 tid: 00010002 2013-10-25 14:19:13.232856 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: loop 3 2013-10-25 14:19:13.232868 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: processing input 2013-10-25 14:19:13.232900 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: using keyproc 2013-10-25 14:19:13.232910 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: using default_s2k_func 2013-10-25 14:19:13.236487 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: extracting ticket 2013-10-25 14:19:13.236557 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_init_creds: wc: 0.015944 2013-10-25 14:19:13.237022 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - Trying to find service kdc for realm DOMAIN.COM flags 2 2013-10-25 14:19:13.237444 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - submissing new requests to new host 2013-10-25 14:19:13.237482 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - connecting to host: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00020001 2013-10-25 14:19:13.237551 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - connecting to 11: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00020001 2013-10-25 14:19:13.237900 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - writing packet: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00020001 2013-10-25 14:19:13.238616 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - reading packet: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00020001 2013-10-25 14:19:13.238645 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - host completed: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00020001 2013-10-25 14:19:13.238674 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_sendto_context DOMAIN.COM done: 0 hosts 1 packets 1 wc: 0.001656 nr: 0.000000 kh: 0.000409 tid: 00020001 2013-10-25 14:19:13.238839 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - Trying to find service kdc for realm DOMAIN.COM flags 2 2013-10-25 14:19:13.239302 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - submissing new requests to new host 2013-10-25 14:19:13.239360 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - connecting to host: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00030001 2013-10-25 14:19:13.239429 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - connecting to 11: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00030001 2013-10-25 14:19:13.239683 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - writing packet: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00030001 2013-10-25 14:19:13.240350 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - reading packet: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00030001 2013-10-25 14:19:13.240387 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - host completed: tcp 192.168.0.1:kerberos (192.168.0.1) tid: 00030001 2013-10-25 14:19:13.240415 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_sendto_context DOMAIN.COM done: 0 hosts 1 packets 1 wc: 0.001578 nr: 0.000000 kh: 0.000445 tid: 00030001 2013-10-25 14:19:13.240514 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - krb5_credential - krb5_get_credentials_with_flags: DOMAIN.COM wc: 0.003615 2013-10-25 14:19:13.240537 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - valid credentials for [email protected] 2013-10-25 14:19:13.240541 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - switching to cache 'MEMORY:0x7fa713635470' 2013-10-25 14:19:13.240545 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - switching GSS to cache 'MEMORY:0x7fa713635470 2013-10-25 14:19:13.240555 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - Bind Step 5 - Bind/Join computer to domain - 'domain.com' 2013-10-25 14:19:13.241345 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - resolving 'server.domain.com' 2013-10-25 14:19:13.241646 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - added socket 12 for host 'server.domain.com:389' address '192.168.0.2' to kqueue list 2013-10-25 14:19:13.241930 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - Setting kerberos server for 'Kerberos:DOMAIN.COM' to 'server.domain.com' 2013-10-25 14:19:13.241962 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - switching to cache 'MEMORY:0x7fa713635470' 2013-10-25 14:19:13.241969 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - switching GSS to cache 'MEMORY:0x7fa713635470 2013-10-25 14:19:13.242231 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - GSSAPI allow Confidentiality 2013-10-25 14:19:13.242234 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - setting realm 'DOMAIN.COM' for node '/Active Directory/domain.com' 2013-10-25 14:19:13.242239 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - GSSAPI allow Integrity (signing) 2013-10-25 14:19:13.242274 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - GSSAPI using hostname 'server.domain.com' 2013-10-25 14:19:13.242282 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - GSSAPI using initiator credential '[email protected]' 2013-10-25 14:19:13.250771 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - Authenticate to LDAP using Kerberos credential - 0 2013-10-25 14:19:13.250784 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - verified connectivity to '192.168.0.2' with socket 12 2013-10-25 14:19:13.251513 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - locating site using domain domain.com using CLDAP 2013-10-25 14:19:13.252145 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - using site of 'DOMAINGROUP' from CLDAP 2013-10-25 14:19:13.253626 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - resolving 'server2.domain.com' 2013-10-25 14:19:13.253933 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - added socket 13 for host 'server2.domain.com:389' address '192.168.0.1' to kqueue list 2013-10-25 14:19:13.254428 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - Setting kerberos server for 'Kerberos:DOMAIN.COM' to 'server2.domain.com' 2013-10-25 14:19:13.254462 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - switching to cache 'MEMORY:0x7fa713635470' 2013-10-25 14:19:13.254468 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - switching GSS to cache 'MEMORY:0x7fa713635470 2013-10-25 14:19:13.254617 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - setting realm 'DOMAIN.COM' for node '/Active Directory/domain.com' 2013-10-25 14:19:13.254661 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - GSSAPI allow Confidentiality 2013-10-25 14:19:13.254670 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - GSSAPI allow Integrity (signing) 2013-10-25 14:19:13.254689 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - GSSAPI using hostname 'server2.domain.com' 2013-10-25 14:19:13.254695 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - GSSAPI using initiator credential '[email protected]' 2013-10-25 14:19:13.262092 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - Authenticate to LDAP using Kerberos credential - 0 2013-10-25 14:19:13.262108 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - verified connectivity to '192.168.0.1' with socket 13 2013-10-25 14:19:13.262982 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - Computer account either already exists or DC is already Read/Write 2013-10-25 14:19:13.264968 PDT - 10544.20463, Node: /Active Directory, Module: ActiveDirectory - Adding record 'cn=spike,CN=Computers,DC=domain,DC=com' in 'domain.com' The failure point seems to be Computer account either already exists or DC is already Read/Write, however, I can search for 'spike' on the Active Directory server using Active Directory Explorer and it's not there. If I do the same search for the Linux and Windows PCs I added previously, I can find them.

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• Why is my mouse randomly deselecting and unclicking?

  - by Coldblackice

  (Windows 7 x64, Logitech MX1100 mouse) If I click/hold/ the mouse, like on the title bar of a folder to move it, or to select text, the mouse will randomly "unselect" it and then randomly reselect at another point in the movement. For example, if I were to start mouse-selecting the above paragraph, starting with "movement." and then moving backwards, it might select as far as "reselect", but then the selection would disappear, only to start selecting again from "will randomly". I realize this would sound like a clear-cut case for a hardware issue in the mouse button, but I've narrowed out that that's not the case. The problem doesn't happen if I drag-move/drag-select slowly. But I can make the problem very apparent if I click and drag something fast. For example, if I click and hold the title bar of a window, and then start quickly dragging it around in circles across my monitor, the window will get "dropped", and a new window will get picked up in the process. Additionally, if I right-click anywhere to get a context menu (in Windows, programs, anywhere/everywhere), and then relatively quickly press the left mouse button to select something on the context menu, the context menu will disappear as if I had clicked "through" it. I haven't had any driver changes, system updates, or significant software changes/updates/installations recently, that might be a precursor to this issue. Again, the oddity seems to be the "speed" of action. Another note -- it seems that "lag" has a bit to do with it. If I click and drag a window around quickly, it might start to "lag" a tad bit, like it's perhaps moving too fast for Windows to keep up with the refresh/redraw rate, and that's usually synonymous with this odd deselect bug happening. (Batteries fully charged, no damage or recent changes to mouse, no changes that might affect/block wireless communication)

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• Windows 2008 RemoteAPP client disconnects within a matter of minutes

  - by Jeroen Wilke

  I'm having an odd problem with Windows 2008 TS, and remote applications specifically. The situation is as follows: TS idle timeout is disabled via GPO TS terminating disconnected sessions after 1hr (via GPO) My users can log on to the Terminal server, and get a full desktop, OR via rdp files that give access to a few remote applications. When a user connects to a full desktop, everything is fine and dandy, they will remain logged on indefinately, and when they disconnect the session is terminated after an hour. however, when a user connects using a remote application link, the client seems to disconnect after only a few minutes of inactivity, when you click the window, the session reconnects. EventID's on TS server: 4779: This event is generated when a user disconnects from an existing Terminal Services session, or when a user switches away from an existing destop using Fast User Switching. 4778 : This event is generated when a user reconnects to an existing Terminal Services session, or when a user switches to an existing desktop using Fast User Switching users are connecting directly to 3389, not using a TS-gateway at the moment. This behavior is consistent on different clients that we have, Full desktop is fine, RemoteAPP constantly disconnects. The .rdp file used doesn't list any interesting parameters, aside from what application to launch, and where to find it. Can someone explain to me how there can be a difference in behaviour between full desktop, and remoteapp ? since essentially they use the exact same client ? Regards Jeroen

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