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  • PHP shell_exec() - Run directly, or perform a cron (bash/php) and include MySQL layer?

    - by Jimbo
    Sorry if the title is vague - I wasn't quite sure how to word it! What I'm Doing I'm running a Linux command to output data into a variable, parse the data, and output it as an array. Array values will be displayed on a page using PHP, and this PHP page output is requested via AJAX every 10 seconds so, in effect, the data will be retrieved and displayed/updated every 10 seconds. There could be as many as 10,000 characters being parsed on every request, although this is usually much lower. Alternative Idea I want to know if there is a better* alternative method of retrieving this data every 10 seconds, as multiple users (<10) will be having this command executed automatically for them. A cronjob running on the server could execute either bash or php (which is faster?) to grab the data and store it in a MySQL database. Then, any AJAX calls to the PHP output would return values in the MySQL database rather than making a direct call to execute server code every 10 seconds. Why? I know there are security concerns with running execs directly from PHP, and (I hope this isn't micro-optimisation) I'm worried about CPU usage on the server. The server is running a sempron processor. Yes, they do still exist. Having this only execute when the user is on the page (idea #1) means that the server isn't running code that doesn't need to be run. However, is this slow and insecure? Just in case the type of linux command may be of assistance in determining it's efficiency: shell_exec("transmission-remote $host:$port --auth $username:$password -l"); I'm hoping that there are differences in efficiency and level of security with the two methods I have outlined above, and that this isn't just micro-micro-optimisation. If there are alternative methods that are better*, I'd love to learn about these! :)

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  • strip version from package name using Bash

    - by cd1
    hi, I'm trying to strip the version out of a package name using only Bash. I have one solution but I don't think that's the best one available, so I'd like to know if there's a better way to do it. by better I mean cleaner, easier to understand. suppose I have the string "my-program-1.0" and I want only "my-program". my current solution is: #!/bin/bash PROGRAM_FULL="my-program-1.0" INDEX_OF_LAST_CHARACTER=`awk '{print match($0, "[A-Za-z0-9]-[0-9]")} <<< $PROGRAM_FULL` PROGRAM_NAME=`cut -c -$INDEX_OF_LAST_CHARACTER <<< $PROGRAM_FULL` actually, the "package name" syntax is an RPM file name, if it matters. thanks!

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  • How to delete "-" file from svn?

    - by ~brzeti
    Accidentally I have created file "-" (just a minus) in a directory and commited it. I have to delete it because its causing error on other machines: svn: Can't convert string from 'UTF-8' to native encoding: svn: ?\226?\128?\147 I can remove it from local directory using "rm -i *" or with python "os.remove('\xe2\x80\x93')" but those methods do not work with "svn rm". How to delete such file from svn repository?

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  • grep from a log file to get count

    - by subodh1989
    I have to get certain count from files. The grep statement i am using is like this : counter_pstn=0 completed_count_pstn=0 rec=0 for rec in `(grep "merged" update_completed*.log | awk '{print $1}' | sed 's/ //g' | cut -d':' -f2)` do if [ $counter_pstn -eq 0 ] then completed_count_pstn=$rec else completed_count_pstn=$(($completed_count_pstn+$rec)) fi counter_pstn=$(($counter_pstn+1)) done echo "Completed Orders PSTN Primary " $completed_count_pstn But the log file contains data in this format : 2500 rows merged. 2500 rows merged. 2500 rows merged. 2500 rows merged.2500 rows merged. 2500 rows merged. 2500 rows merged. As a result , it is missing out the count of one merge(eg on line 4 of output).How do i modify the grep or use another function to get the count. NOTE that the 2500 number maybe for different logs. So we have to use "rows merged" pattern to get the count. i have tried -o ,-w grep options,but it is not working. Expected output from above data: 17500 Actual output showing : 15000

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  • Bash Scripting: I want to open a set of .html files, and add line before html tag

    - by Bashn00b
    Hi guys, I have a set of .php files in a folder, I want to add text just before these lines: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en" > What i want is to insert just before these lines in the html file. So just want to prepend that file before each docType declaration. However the DOCTYPE declaration is never on line 1, as there is loads of php lines before. I have this current script (where FE is the folder containing all the scripts i want to edit): for file in ${fe}*; do echo "$file" done Thanks,

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  • grep value inside a variable pointing to other variable

    - by Joice
    using : ksh *abc = 1 efg = 2 hgd = 3 not known to me * say if i have Value="abc efg hgd" abc efg hgd all contains some value which i dnt know. Now I want to grep the value contained inside abc. like for i in $Value do grep "echo $(($((echo $i | cut -d'|' -f2))))" done this grep should look for the value inside abc efg hgd grep 1 grep 2 grep 3

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  • Linux How to print all the files with the same prefix after searching for them?

    - by Alyx
    I need to search through a directory which contains many sub directories, each which contain files. The files read as follows question1234_01, where 1234 are random digits and the suffix _01 is the number of messages that contain the prefix, meaning they are apart of the same continuing thread. find . -name 'quest*' | cut -d_ -f1 | awk '{print $1}' | uniq -c | sort -n example output: 1 quest1234 10 quest1523 This searches for all the files then sorts them in order. What I want to do is print all the files which end up having the most occurrences, in my example the one with 10 matches. So it should only output quest1523_01 - 11

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  • Creating a Custom Ubuntu Daemon

    - by Chris S
    What's the "correct" way to create a custom daemon in Ubuntu, that will start at boot time and be controllable by Ubuntu's standard daemon start/stop commands? Can I just copy and paste one of the scripts in /etc/init.d or do I need to "register" the daemon somewhere else?

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  • How to get line count from variable (from MYSQL query)?

    - by Mint
    My problematic code: testMYSQL=`mysql -u $mysqlUser -p$mysqlPass -h $mysqlHost --skip-column-names --batch -D $mysqlDB -e "SELECT $select FROM $mysqlTable WHERE nameTXT='test';"` $testMYSQL now contains: test test test Then I do: TEST=$(echo $testMYSQL | wc -l) echo "$TEST" I would of thought that would work, but it doesn't, it returns 1 But if I put this into $testMYSQL: "test\ntest\ntest" it will say 3… Whats going on here? does MYSQL not use new lines? PS, I know I can use a for loop to loop though the lines then count up the lines that way, but I was hoping for a simpler solution like wc

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  • Ignoring specific differences in diff

    - by naumcho
    When doing recursive diffs I want to ignore expected differences/translations - is there a way to do that with standard unix tools? E.g. file1: 1 ... 2 /path/to/something/ver1/blah/blah 3 /path/to/something/ver1/blah/blah 4 ... file2: 1 ... 2 /path/to/something/ver2/blah/blah 3 /path/to/something/ver3/blah/blah 4 ... I want to be able to do something like: diff file1 file2 --ignore-transltion "ver1>ver2" This should show only show me that line 3 is different Does anyone know of a good way to do that? I can easily write a perl script to do it but i will end up re-implementing most of the rest of the functionality of 'diff'. Update: My goal is to run this on directories with different versions of the same files with "diff -r" so I can spot unexpected differences in versions.

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  • How to check an exectuable's path is correct in PHP?

    - by nickf
    I'm writing a setup/installer script for my application, basically just a nice front end to the configuration file. One of the configuration variables is the executable path for mysql. After the user has typed it in (for example: /path/to/mysql-5.0/bin/mysql or just mysql if it is in their system PATH), I want to verify that it is correct. My initial reaction would be to try running it with "--version" to see what comes back. However, I quickly realised this would lead to me writing this line of code: shell_exec($somethingAUserHasEntered . " --version"); ...which is obviously a Very Bad Thing. Now, this is a setup script which is designed for trusted users only, and ones which probably already have relatively high level access to the system, but still I don't think the above solution is something I want to write. Is there a better way to verify the executable path? Perhaps one which doesn't expose a massive security hole?

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  • Prompt message box Linux or any system from removable device

    - by Zloy Smiertniy
    Hi all, I have some files that in windows enable me to prompt messages when a device is plugged. In case it is lost it pops up a message that says the user to please return it to he owner. Does anybody know how can I do this in Linux? I doesnt need to be a complex thing, it can be an option in a right clic menu, or a splashcreen, or anything, just to make sure that the owner of the device may be looking for it.

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  • how to search for a term only in non test files

    - by dorelal
    I use ack and I like it. However from time to time I need to search for something in my code base and I want to ignore all the files residing in test directory. Basically all the files which have test in their absolute path should be not included in the search. How do I achieve that? I am willing to have a custom bash script. Something like ack_no_test "application" - search for "application" in all files but ignore files residing in test directory

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  • Extract IDs from CSS

    - by nosuchip
    I've the CSS file with many entry like id1, #id2, #id3, #id4 { ... } id3, #id2 { ... } id2, #id4 { ... } I want to extract list of unique IDs using command line tools (msys). Unique means any entry in list presented only once. How? PS: I know how doing it using python, but what about awk/sed/cat?

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  • Python 3.1: Syntax Error for Everything! (Mac OS X)

    - by Nathan G.
    I updated to Python 3.1.3 (I've got OS X 10.6). If I type python in Terminal, I get a working 2.6.1 environment. If I type python3 in Terminal, I get a 3.1.3 environment. Everything looks fine until I do something. If I try to run print "hello", I get a syntax error. This problem is the same in IDLE. I tried deleting everything for 3.1 and then reinstalling, but it hasn't worked. Ideas? Thanks in advance!

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  • piping to variables

    - by lego69
    cut -d" " -f2 ${2} | $callsTo hello, can somebody please explain can I pipe the result of cut to variable callsTo, and how will it be stored, as the string or list?

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  • Several ways to call a windows batch file from another one or from prompt. Which one in which case?

    - by dim
    A windows batch file (called.bat or called.cmd) can be called from another batch file (caller.bat or caller.cmd) or interactive cmd.exe prompt in several ways: direct call: called.bat using call command: call called.bat using cmd command: cmd /c called.bat using start command: start called.bat I'm quite in trouble to differentiate their intended usage based on their help text: when to use which one? e.g. why I might use 'call' command instead of direct call. What's different? I'm interested on some summary report that analyze all 4 possibilities (and others if any missing) from various point of views: recommended use cases for which they are designed to fit, process spawning, execution context, environment, return code processing. Note: I'm using Windows XP SP3.

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  • How does the #! work?

    - by mocybin
    In a script you must include a #! on the first line followed by the path to the program that will execute the script (e.g.: sh, perl). As far as I know though, the # character denotes the start of a comment and that line is supposed to be ignored by the program executing the script. It would seem though, that this first line is at some point read by something in order for the script to be executed by the proper program. Could somebody please shed more light on the workings of the #! ? Edit: I'm really curious about this, so the more in-depth the answer the better.

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  • How to pass in password to pg_dump?

    - by Mark
    I'm trying to create a cronjob to back up my database every night before something catastrophic happens. It looks like this command should meet my needs: pg_dump dbname | gzip > $(date +%Y-%m-%d).psql.gz Except after running that, it expects me to type in a password. I can't do that if I run it from cron. How can I pass one in automatically?

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