Search Results

Search found 19501 results on 781 pages for 'form spam'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 73/781 | < Previous Page | 69 70 71 72 73 74 75 76 77 78 79 80  | Next Page >

  • user registeration form without captcha?

    - by terrani
    Hi, I was trying to sign-up Twitter today and I noticed that their registration form does not have a captcha. The form URL is https://twitter.com/signup. I also noticed that they used an input like below. <input name="authenticity_token" type="hidden" value="ce803cee65a96aaa97bdf75da166599c3adc9ec8" /> what kind of method is this? Do they create a temp value in their database when a user access the registration form? and check it when a user submit the form?

    Read the article

  • MS Access raise form events programmatically

    - by Eric G
    Is it possible to raise built-in MS Access form events programmatically? I have a feeling it isn't but thought I would check. (I am using Access 2003). For instance, I want to do something like this within a private sub on the form: RaiseEvent Delete(Cancel) and have it trigger the Access.Form delete event -- i.e. without actually deleting a bound record. Note my delete event is not handled by the form itself but by an external class, so I can't simply call Form_Delete(Cancel).

    Read the article

  • Symfony: Pass an object from another module to a form

    - by djcloud23
    I have a symfony project and I have one model, which for this example I will name Boat. From the Boat's showSuccess page, I would like to make a link to another model's form page. For this example we will call it Ticket. When they click on the link, I would like for the Boat object to be passed to the Ticket form because I have to display some of that specific Boat's fields (title, price, etc) on the Ticket form page (newSuccess.php). I guess my question is, how do I pass an object (as a variable) to another model's "new" form page. I have looked everywhere and I can't seem to find an answer that works for me. Thank you!

    Read the article

  • How to make checkboxes have the same submit behavior as other inputs?

    - by Tim Santeford
    I have a search form where several checkboxes are checked by default. When the form submits, as a GET, the url will only contain the list of checkboxes that were left checked. http://www.example.com/page/?checkbox1=yes&checkbox2=yes It is difficult with this scenario to determine the difference between when a user first arrives at this search page and when they submit the form with all checkboxes unchecked because the querystrings look the same. To combat this problem I have started injecting a hidden field before the checkbox with the same name and a 'no' value. When the checkbox is unchecked the browser will send the hidden field's no value and when the checkbox is set then the browser is overriding the hidden field with the checkbox's 'yes' value. <input type="hidden" name="checkbox1" value="no" /> <input type="checkbox" name="checkbox1" value="yes" /> when the user submits the form with all checkboxes unchecked I get this querystring: http://www.example.com/page/?checkbox1=no&checkbox2=no This seems to work on ff, chrome, ie5.5+ so I'am I safe in using this method or is there a better way to make checkboxes submit like inputs and selects?

    Read the article

  • Instantiate a form, then find it later, without showing it initially

    - by awilson53
    I am having a problem that is strange to me but hopefully is not so strange to someone else. : ) Some background: I am working on a simple IM client that allows the user to broadcast messages to multiple recipients. The goal is to create a chat form for each of the recipients containing the text of the broadcast message, then show that form only if the recipient responds to the broadcast-er. However, when the application receives a response then attempts to locate the form for that particular chat session (using Application.OpenForms) it cannot find it UNLESS I .Show at the time it is created. I would like to avoid having to show this form when it is created because this means that the user will see a flash on the screen. The form doesn't seem to really be created until I show it, but it would seem there has to be a way to do this without showing first. Can anyone assist? I can provide code snippets if needed, I didn't in this post because this feels more like a conceptual misunderstanding on my part than a bug in the code. Thanks in advance!

    Read the article

  • PHP Multiple form tokens

    - by Juddling
    I understand the idea of generating a form token and storing it in a session, and also putting it as a hidden input in my forms. But how could I make this work if I have pages with multiple forms, is it still safe to use the same token for each form? And I still feel weary about bots and stuff on my website, can these form tokens really safely replace CAPTCHAs?

    Read the article

  • How to set a predefined value in a form in Rails

    - by marco
    So I just got started in Rails, and I'm trying to create an Object (a book_loan in my case) with a Form. The thing is that I get to this form by clicking on a book, so I pass the book_id as a parameter, like localhost:3000/loans/new?id=1. Now I don't want the user to be able to set the book id field in the form, since I already know the id. So my question is how to set the value in the form. I have been trying things like: <% form_for(@loan) do |f| %> <%= f.error_messages %> ... <%= @loan.book_id = params[:id] %> <%= f.submit 'Create' %> <% end %> without any success. Does anybody have a hint for me?

    Read the article

  • stop form during submission if it validates incorrectly

    - by muqman
    I am trying to use JavaScript to validate forms but if the form doesn't validate, I don't want the form to be sent to the "action" page. The validator: <script> function formSubmit() { document.getElementById("signup_form").submit(); var x=document.forms["signup_form"]["tname"].value; if (x==null || x=="") { alert("First name must be filled out"); return false; } } </script> The form itself: <form action="some_file.php" method="post" id="signup_form" name="signup_form" onsubmit="return formSubmit()"> But all this does is if the tname field empty, it will return an alert but as soon as the user hits ok, the form then redirects to some_file.php. What have I missed here? The submit button: <a href="" onclick="return formSubmit(); return false" class="purplebutton">Signup</a> So what have I missed? How do I avoid this in the future?

    Read the article

  • Jquery Form Validation Plugin Not Working

    - by nayanjyoti hazarika
    I try to validate a simple Form but the Jquery Validation Plugin not working when I use only Button not The Submit Button. I can not use the Submit button there Because If I use submit Button After Submitting the form It take the Action and goes to Default page while my current form is comes from Ajax. I am very new to Jquery. Please Help its Urgent... I am giving the files here. index.html <html> <head> <script src="jquery.js"> <script="jquery-validate-min.js"> <script="validation.js> </head> <body> <form id="contact_form"> <table> <tr><th>Name</th><td><input name="name" /></td></tr> <tr><th>E Mail</th><td><input name="email" /></td></tr> <tr><th><input type="button" name ="submit" id="form_sub" onclick="save"></th><td><input name="email" /></td></tr> </table> </form> </body> </html> Now the validation.js file function save(){ $("#form_sub").click(function(){ $("#contact_form").validate({ 'rules':{ 'name':{ 'required':true, 'minlength':5 }, 'email':{ 'required':true, 'email':true } } }) } Everything works fine when we use input type="submit"... But it not working when we use input type="button" Any Idea how can Fix this? I am new to Jquery ... Please Help

    Read the article

  • Form Search Onkeyup event

    - by Aryan
    I Have a Form In which the form should automatically search when i complete entering the 10th character in the text field but the below code is searching for each n every character i enter in the text field . . . I just want the result after completing the 10th character not for each n every character . . i have used onkeyup event and i set that value to 10 but still it is searching for each n every character... please do help me <body OnKeyPress="return disableKeyPress(event)"> <section id="content" class="container_12 clearfix" data-sort=true> <center><table class='dynamic styled with-prev-next' data-table-tools='{'display':true}' align=center> <script> function disableEnterKey(e) { var key; if(window.event) key = window.event.keyCode; //IE else key = e.which; //firefox return (key != 13); } function showUser(str) { if (str=="") { document.getElementById("txtHint").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("txtHint").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","resdb.php?id="+str,true); xmlhttp.send(); } </script> <script type='text/javascript'> //<![CDATA[ $(window).load(function(){ $('#id').keyup(function(){ if(this.value.length ==10) }); });//]]> </script> <form id="form" method="post" name="form" > <tr><td><p align="center"><font size="3"><b>JNTUH - B.Tech IV Year II Semester (R07) Advance Supplementary Results - July 2012</b></font></p></td></tr> <td><p align="center"><b>Last Date for RC/RV : 8th August 2012</b></p></td> <tr><td><p align="center"></b> <input type="text" onkeyup="showUser(this.value)" onKeyPress="return disableEnterKey(event)" data-type="autocomplete" data-source="extras/autocomplete1.php" name="id" id="id" maxlength="10" placeholder=" Hall-Ticket Number">&emsp;</p></td></tr> </table> </center> </form> <center> <div id="txtHint"><b>Results will be displayed here</b></div> </center> </body>

    Read the article

  • JQuery Autocomplete Form Submission

    - by user1658370
    I have managed to implement the jQuery autocomplete plugin on my website but was wondering if it is possible to make the form auto-submit once the user selects an item from the search. I have the following set-up: HTML Form: <form class="quick_search" action="../include/search.php" method="post"> <input type="text" name="search" id="search" value="Search..."> </form> JavaScript: $().ready(function() { $("#search").autocomplete("../include/search.php", { width: 350, selectFirst: false }); }); I have also included the jQuery and Autoplugin scripts. The search.php file contains a list of the search options. At the moment, the search works correctly and I just need it to submit the form once an item is selected from the list that appears. I tried to use the onClick and onSelect options within the search field but neither of these worked correctly. Any help would be much appreciated (I don't really understand js)! Thanks.

    Read the article

  • How to write submit form in another manner?

    - by user281180
    I have the follwing: <% using (Ajax.BeginForm("ChangePassword", new AjaxOptions { OnComplete = "ChangePasswordComplete" })) {% <%Html.RenderPartial("ChangePassword"); % <input type="submit" value="test" /> <%} % I want to write it in the following manner: <form> <%Html.RenderPartial("ChangePassword"); %> <input type="submit" value="test" /> </form> How can I do that? What to write in the form tag

    Read the article

  • Showing a hidden form

    - by Arcadian
    Newb question: how do i show a from that have been hidden using this.Hide(); I have tried MainMenuForm.Show(); and this just says i need an object ref have tried: MainMenuForm frmMainMenu = new MainMenuForm(); frmMainMenu.Show(); which seems to show the appropriate form. but when you exit the app, it is still held in memory because it hasn't shown the form that was hidden, instead it has shown a new version of the form. in effect having 2 instances of the form (one hidden, one visible). whats the correct procedure here Thanks in advance

    Read the article

  • Form:has selector does not work on IE

    - by Joel
    Hey, I am trying to use "form:has" selector which works on Chrome but not on IE. http://jsbin.com/uvumu/2 Does anyone have any idea why it is not working on IE? (when pushing the Post button there should be an alert box) Edited: Here is the code: JS: $(document).ready(function() { $(".comment-link").live('click',function() { return false; }); $("#morefeeds-link").click(function () { return false; }); // Form submittion - doesnt work $("form:has(.commentBtn)").live('submit',function () { alert("a"); return false; }); return false; });? HTML <form> <a href="#" class="comment-link" style="font-size:12px;">Comment</a> <table border="0" cellpadding="0" cellspacing="0"> <tr> <td valign="middle"> <input type="hidden" name="commentkey" value="1"> <input type="text" name="commenttext" class="commentfocus" value="Express your opinion"> </td> <td valign="middle"><input type="submit" class="commentBtn" value="Post"></td> </tr> </table> </form>

    Read the article

  • PHP-How to Pass Multiple Value In Form Field

    - by Tall boY
    hi i have a php based sorting method with drop down menu to sort no of rows, it is working fine. i have another sorting links to sort id & title, it is also working fine. but together they are not working fine. what happens is that when i sort(say by title) using links, result gets sorted by title, then if i sort rows using drop down menu rows get sorted but result gets back to default of id sort. sorting codes for id & tite is if ($orderby == 'title' && $sortby == 'asc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=title&sort=asc'>title-asc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=title&sort=asc'>title-asc:</a></li> ";} if ($orderby == 'title' && $sortby == 'desc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=title&sort=desc'>title-desc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=title&sort=desc'>title-desc:</a></li> ";} if ($orderby == 'id' && $sortby == 'asc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=id&sort=asc'>id-asc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=id&sort=asc'>id-asc:</a></li> ";} if ($orderby == 'id' && $sortby == 'desc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=id&sort=desc'>id-desc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=id&sort=desc'>id-desc:</a></li> ";} ?> sorting codes for rows is <form action="is-test.php" method="get"> <select name="rpp" onchange="this.form.submit()"> <option value="10" <?php if ($rowsperpage == 10) echo 'selected="selected"' ?>>10</option> <option value="20" <?php if ($rowsperpage == 20) echo 'selected="selected"' ?>>20</option> <option value="30" <?php if ($rowsperpage == 30) echo 'selected="selected"' ?>>30</option> </select> </form> this method passes only rows per page(rpp) into url. i want it to pass order, sort& rpp. is there a way around to pass multiple values in form fields like this. <form action="is-test.php" method="get"> <select name="rpp, order, sort" onchange="this.form.submit()"> <option value="10, $orderby, $sortby" <?php if ($rowsperpage == 10) echo 'selected="selected"' ?>>10</option> <option value="20, $orderby, $sortby" <?php if ($rowsperpage == 20) echo 'selected="selected"' ?>>20</option> <option value="30, $orderby, $sortby" <?php if ($rowsperpage == 30) echo 'selected="selected"' ?>>30</option> </select> </form> this may seem silly but it just to give you an idea of what i am trying to implement,(i am very new to php) please suggest any way to make this work. thanks

    Read the article

  • C# - Printing the Form

    - by Jon
    I am using the code from MS to print a form however it looks like the form needs to be visible with a Show/ShowDialog() to work. I am trying to use the code for a form that I don't want to show. Any ideas?

    Read the article

  • After mysql_query, no result output

    - by Jerry
    I have a simple mysql_query() update command to update mysql. When a user submits my form, it will jump to an update page to update the data. The problem is that there's supposed to be some data shown after the update, but it comes out blank. My form <form id="form1" method="POST" action="scheduleUpdate.php" > <select name=std1> <option>AA</option> <option>BB</option> <option>CC</option> </select> <select name=std2> <option>DD</option> <option>EE</option> <option>FF</option> </select> .......//more drop down menu but the name is std3..std4..etc... ....... </form> scheduleUpdate.php //$i is the value posted from my main app to tell me how many std we have for($k=0;$k<$i;$k++){ $std=$_POST['std'.$k]; //if i remove the updateQuery, the html will output.I know the query is the problem but i //couldn't fix it.. $updateQuery=mysql_query("UPDATE board SET student='$std' WHERE badStudent='$std' or goodStudent='$std'",$connection); //no output below this line at all if($updateQuery){ DIE('mysql Error:'+mysql_error()); } } // I have bunch of HTML here....but no output at all!!!! MySQL will be updated after I hit submit, but it doesn't shown any HTML.

    Read the article

  • submitting a form inside a modalbox with jquery

    - by birdy
    submitting form with jQuery works $('#testform').submit(); doesn't work $('#testform').submit(function () { alert('test1'); return true; }); This is just an exmaple but at times i'd like to do stuff before submission of the form. Like for example submit the form using $.POST Update: If I keep both then the $.POST has no value because the form still gets submitted the traditional way, without ajax... $("#testform").submit(function() { $.post('/myajaxcontroller', function(data) { $('#result').html(data); }); }); $("#testform").submit();

    Read the article

  • form element not showing up after adding in through jquery

    - by ooo
    inside a jquery method (on a click event of a button) i have the following code: $(selector).html("<form action='/Tracker/CopyFood' method='post'><input type='hidden' name='Id' value=" + id + "><input class='very-small-input' type='text' name='Quantity' value='1' /> for <select name='Date'><option value='Today'>Today</option><option value='Yesterday'>Yesterday</option></select><select name='Meal'><option value='Breakfast'>Breakfast</option><option value='Lunch'>Lunch</option><option value='Dinner'>Dinner</option><option value='Evening Snack'>Evening Snack</option></select><input type='button' class='submitCopyFood' value='Add'> or <div style='display:inline' class='CancelCopy'>Cancel</div></form> "); it seems to work on the screen, but the button click "submitCopyFood" wasn't firing. When i click "View Selection Source" in firefox, i see the issue. All i see is this: <input name="Id" value="128" type="hidden"><input class="very-small-input" name="Quantity" value="1" type="text"> for <select name="Date"><option value="Today">Today</option><option value="Yesterday">Yesterday</option></select><select name="Meal"><option value="Breakfast">Breakfast</option><option value="Lunch">Lunch</option><option value="Dinner">Dinner</option><option value="Evening Snack">Evening Snack</option></select><input class="submitCopyFood" value="Add" type="button"> or <div style="display: inline;" class="CancelCopy">Cancel</div> Its like i never added the form anywhere. Is there any reason why i dont see the: <form action='/Tracker/CopyFood' method='post'> or the </form> in the source code inside the selected source. Is there something special that i need to do here?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 69 70 71 72 73 74 75 76 77 78 79 80  | Next Page >