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  • java: can't use constructors in abstract class

    - by ufk
    Hi. I created the following abstract class for job scheduler in red5: package com.demogames.jobs; import com.demogames.demofacebook.MysqlDb; import org.red5.server.api.IClient; import org.red5.server.api.IConnection; import org.red5.server.api.IScope; import org.red5.server.api.scheduling.IScheduledJob; import org.red5.server.api.so.ISharedObject; import org.apache.log4j.Logger; import org.red5.server.api.Red5; /** * * @author ufk */ abstract public class DemoJob implements IScheduledJob { protected IConnection conn; protected IClient client; protected ISharedObject so; protected IScope scope; protected MysqlDb mysqldb; protected static org.apache.log4j.Logger log = Logger .getLogger(DemoJob.class); protected DemoJob (ISharedObject so, MysqlDb mysqldb){ this.conn=Red5.getConnectionLocal(); this.client = conn.getClient(); this.so=so; this.mysqldb=mysqldb; this.scope=conn.getScope(); } protected DemoJob(ISharedObject so) { this.conn=Red5.getConnectionLocal(); this.client=this.conn.getClient(); this.so=so; this.scope=conn.getScope(); } protected DemoJob() { this.conn=Red5.getConnectionLocal(); this.client=this.conn.getClient(); this.scope=conn.getScope(); } } Then i created a simple class that extends the previous one: public class StartChallengeJob extends DemoJob { public void execute(ISchedulingService service) { log.error("test"); } } The problem is that my main application can only see the constructor without any parameters. with means i can do new StartChallengeJob() why doesn't the main application sees all the constructors ? thanks!

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  • Best practice accessing an array set within a class

    - by user350599
    I have created a basic class for a customer. I haven't done this before and want to know the best way to access the data. Should I have a get() method for every field in the customer array or should I simply pass the customer array back and access with the page. i.e. Just return the array class Customer { protected $id; protected $customer; public function __construct($customer_id) { $this->id = $customer_id; $this->set_customer(); } protected function set_customer() { $query = mysql_query("SELECT * FROM customer WHERE id = '$this->id'"); $this->customer = mysql_fetch_row($query); } public function get_customer() { return $this->customer; } } versus create a method for each item in the array class Customer { protected $id; protected $customer; public function __construct($customer_id) { $this->id = $customer_id; $this->set_customer(); } protected function set_customer() { $query = mysql_query("SELECT * FROM customer WHERE id = '$this->id'"); $this->customer = mysql_fetch_row($query); } public function get_customer_name() { return $this->customer->customer_name; } ... ... } versus option 3 based on Tobias' feedback: (not sure if syntax is correct) class Customer { protected $id; protected $customer; public function __construct($customer_id) { $this->id = $customer_id; return $this->set_customer(); } protected function set_customer() { $query = mysql_query("SELECT * FROM customer WHERE id = '$this->id'"); return mysql_fetch_row($query); } }

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  • Forms authentication: how do you store username password in web.config?

    - by Nick G
    I'm used to using Forms Authentication with a database, but I'm writing a little internal utility and the app doesn't have a database so I want to store the username and password in web.config. However for some reason, forms authentication is still trying to access SQL Server and I can't see how to stop it doing this and pick up the credentials from web.config. What am I doing wrong? I just get the error "Failed to generate a user instance of SQL Server due to a failure in impersonating the client. The connection will be closed." Here are the relevant sections of my web.config: <configuration> <system.web> <authentication mode="Forms"> <forms loginUrl="~/Login.aspx" timeout="60" name=".LoginCookie" path="/" > <credentials passwordFormat="Clear"> <user name="user1" password="[pass]" /> <user name="user2" password="[pass]" /> </credentials> </forms> </authentication> <authorization> <deny users="?" /> </authorization> </system.web> </configuration>

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  • Correct usage of "<T extends SuperClass>"

    - by yusaku
    I am not familiar with "Generics". Is it a correct use of "<T extends SuperClass>" ? And do you agree that the codes after using generics are better? Before using Generics ================================================= public abstract class SuperSample { public void getSomething(boolean isProcessA) { doProcessX(); if(isProcessA){ doProcessY(new SubASample()); }else{ doProcessY(new SubBSample()); } } protected abstract void doProcessX(); protected void doProcessY(SubASample subASample) { // Nothing to do } protected void doProcessY(SubBSample subBSample) { // Nothing to do } } public class SubASample extends SuperSample { @Override protected void doProcessX() { System.out.println("doProcessX in SubASample"); } @Override protected void doProcessY(SubASample subASample) { System.out.println("doProcessY in SubASample"); } } public class Sample { public static void main(String[] args) { SubASample subASample = new SubASample(); subASample.getSomething(true); } } After using Generics ================================================= public abstract class SuperSample { public void getSomething(boolean isProcessA) { doProcessX(); if(isProcessA){ doProcessY(new SubASample()); }else{ doProcessY(new SubBSample()); } } protected abstract void doProcessX(); protected abstract <T extends SuperSample> void doProcessY(T subSample); } public class SubASample extends SuperSample { @Override protected void doProcessX() { System.out.println("doProcessX in SubASample"); } @Override protected <T extends SuperSample> void doProcessY(T subSample) { System.out.println("doProcessY in SubASample"); } } public class Sample { public static void main(String[] args) { SubASample subASample = new SubASample(); subASample.getSomething(true); } }

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  • Asynchronously get user data in facebook tab?

    - by Kristoffer Nolgren
    Using the php sdk, I check if a user inside a tab likes the corresponding page. If i put the following code inside index.php and use that page as my page-tab-url, <?php require_once("facebook/facebook.php"); // Create our application instance // (replace this with your appId and secret). $facebook = new Facebook(array( 'appId' => '1399475990283166', 'secret' => 'mysercret', 'cookie' => true )); $signed_request = $facebook->getSignedRequest(); echo $signed_request['page']['liked']; ?> it outputs '1'. I would like to achieve this asynchronously instead, so I put the php in a separate file and try to access it using ajax instead $http.post('/facebook/likes.php'). success(function(data){ console.log(data); }).error(function(data){ console.log(data); } ); This sample is using angular, but what javascript library i'm using probably doesn't matter. When I access the info with javascript Facebook doesn't seem to get the info that I liked the page. Adding a print_r($facebook); on the page I'm retreiving the same values as if i'm not in a facebook-tab: ( [sharedSessionID:protected] => [appId:protected] => 1399475990283166 [appSecret:protected] => 679fb0ab947c2b98e818f9240bc793da [user:protected] => [signedRequest:protected] => [state:protected] => [accessToken:protected] => [fileUploadSupport:protected] => [trustForwarded:protected] => ) Can I access theese values asynchronosly somehow?

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  • Winforms: Attempted to read or write protected memory. This is often an indication that other memory is corrupt

    - by mamcx
    I have a bunch of background events. All of them call a log: private void log(string text, params object[] values) { if (editLog.InvokeRequired) { editLog.BeginInvoke( (MethodInvoker)delegate { this.log(text, values); }); } else { text = string.Format(text, values) + Environment.NewLine; lock (editLog) { editLog.AppendText(text); editLog.SelectionStart = editLog.TextLength; editLog.ScrollToCaret(); } } } Sometimes I get this, but other times not: System.AccessViolationException was unhandled Message=Attempted to read or write protected memory. This is often an indication that other memory is corrupt. Source=System.Windows.Forms StackTrace: at System.Windows.Forms.UnsafeNativeMethods.CallWindowProc(IntPtr wndProc, IntPtr hWnd, Int32 msg, IntPtr wParam, IntPtr lParam) at System.Windows.Forms.NativeWindow.DefWndProc(Message& m) at System.Windows.Forms.Control.WndProc(Message& m) at System.Windows.Forms.RichTextBox.WndProc(Message& m) at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam) at System.Windows.Forms.UnsafeNativeMethods.SendMessage(HandleRef hWnd, Int32 msg, Int32 wParam, Object& editOle) at System.Windows.Forms.TextBoxBase.ScrollToCaret() at Program1.frmMain.log(String text, Object[] values) in ... ... ... P.D: Not always stop at this line, randomly will be one of the three times editLog methods/properties are used. Not always a exception is throw. Sometimes look like the thing freeze. But not the main UI, just the flow of messages (ie: log look like is never called again) The app is a single form, with background process. I can't see what I doing wrong with this...

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  • System.AccessViolationException: Attempted to read or write protected memory.

    - by Ananth
    I get the following exception when I try to "find and replace" in a word 2007 working on Windows Vista , Windows 7. System.AccessViolationException: Attempted to read or write protected memory. This is often an indication that other memory is corrupt. at Microsoft.Office.Interop.Word.Find.Execute(Object& FindText, Object& MatchCase, Object& MatchWholeWord, Object& MatchWildcards, Object& MatchSoundsLike, Object& MatchAllWordForms, Object& Forward, Object& Wrap, Object& Format, Object& ReplaceWith, Object& Replace, Object& MatchKashida, Object& MatchDiacritics, Object& MatchAlefHamza, Object& MatchControl) Is there any solution for this ? Iam using .net3.5 C#.

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  • How do I configure freeSSHd on Windows Server 2008 so I can log in using ssh?

    - by Daryl Spitzer
    I've installed freeSSHd on a Windows Server 2008 box (following the instructions in How to install an SSH Server in Windows Server 2008), including: created a user named "dspitzer" with NTLM authorization opened an exception for port 22 in the Windows Firewall But when I try to connect (from a Mac OS X 10.5.8 command-line), I get permission denied after entering the password: $ ssh 12.34.56.78 [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried: $ ssh [email protected] [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried changing the authorization to "Password stored as SHA1 hash" and entering a simple password, but I get the same problem. And I've tried a different user name ("Administrator") with no luck. I've confirmed that I am connecting to the server I'm configuring—if I stop freeSSHd and try to connect I get: $ ssh 12.34.56.78 ssh: connect to host 12.34.56.78 port 22: Operation timed out I get the exact same results from a Linux command-line. Any advice or troubleshooting tips? Update: I tried disabling the firewall (in response to geeklin's comment) and it made no difference. Update #2: I no longer have this machine (I've changed employers), so I have no way of verifying the answers. I guess all I can do is make this question "community wiki".

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  • How do I configure freeSSHd on Windows Server 2008 so I can log in using ssh?

    - by Daryl Spitzer
    I've installed freeSSHd on a Windows Server 2008 box (following the instructions in How to install an SSH Server in Windows Server 2008), including: created a user named "dspitzer" with NTLM authorization opened an exception for port 22 in the Windows Firewall But when I try to connect (from a Mac OS X 10.5.8 command-line), I get permission denied after entering the password: $ ssh 12.34.56.78 [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried: $ ssh [email protected] [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried changing the authorization to "Password stored as SHA1 hash" and entering a simple password, but I get the same problem. And I've tried a different user name ("Administrator") with no luck. I've confirmed that I am connecting to the server I'm configuring—if I stop freeSSHd and try to connect I get: $ ssh 12.34.56.78 ssh: connect to host 12.34.56.78 port 22: Operation timed out I get the exact same results from a Linux command-line. Any advice or troubleshooting tips? Update: I tried disabling the firewall (in response to geeklin's comment) and it made no difference. Update #2: I no longer have this machine (I've changed employers), so I have no way of verifying the answers. I guess all I can do is make this question "community wiki".

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  • LDAP change user pass on client

    - by Sean
    I am trying to allow ldap users to change their password on client machines. I have tried pam every which way I can think of /etc/ldap.conf & /etc/pam_ldap.conf, as well. At this point I'm stuck. Client: Ubuntu 11.04 Server: Debian 6.0 The current output is this: sobrien4@T-E700F-1:~$ passwd passwd: Authentication service cannot retrieve authentication info passwd: password unchanged /var/log/auth.log gives this during the command: May 9 10:49:06 T-E700F-1 passwd[18515]: pam_unix(passwd:chauthtok): user "sobrien4" does not exist in /etc/passwd May 9 10:49:06 T-E700F-1 passwd[18515]: pam_ldap: ldap_simple_bind Can't contact LDAP server May 9 10:49:06 T-E700F-1 passwd[18515]: pam_ldap: reconnecting to LDAP server... May 9 10:49:06 T-E700F-1 passwd[18515]: pam_ldap: ldap_simple_bind Can't contact LDAP server getent passwd |grep sobrien4 (note keeping short since testing with that account, however it outputs all ldap users): sobrien4:Ffm1oHzwnLz0U:10000:12001:Sean O'Brien:/home/sobrien4:/bin/bash getent group shows all ldap groups. /etc/pam.d/common-password (Note this is just the most current, I have tried a lot of different options): password required pam_cracklib.so retry=3 minlen=8 difok=3 password [success=1 default=ignore] pam_unix.so use_authtok md5 password required pam_ldap.so use_authtok password required pam_permit.so Popped open wireshark as well, the server & client are talking. I have the password changing working on the server. I.E. the server that runs slapd, I can log in with the ldap user and change the passwords. I tried copying the working configs from the server initially and no dice. I also tried cloning it, and just changing ip & host, and no go. My guess is that the client is not authorized by ip or hostname to change a pass. Pertaining to the slapd conf, I saw this in a guide and tried it: access to attrs=loginShell,gecos by dn="cn=admin,dc=cengineering,dc=etb" write by self write by * read access to * by dn="cn=admin,dc=cengineering,dc=etb" write by self write by * read So ldap seems to be working okay, just can't change the password.

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  • How to test code built to save/restore Lifecycle of an Activity?

    - by Pentium10
    How can I test all of the following methods code? I want to play scenarios when all of them are happening to see if my code works for save/restore process of an activity. So what should I do in the Emulator to get all methods tested? public class Activity extends ApplicationContext { protected void onCreate(Bundle savedInstanceState); protected void onStart(); protected void onRestart(); protected void onResume(); protected void onPause(); protected void onStop(); protected void onDestroy(); }

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  • FTP Upload ftpWebRequest Proxy

    - by Rodney Vinyard
    Searchable:   FTP Upload ftpWebRequest Proxy FTP command is not supported when using HTTP proxy     In the article below I will cover 2 topics   1.       C# & Windows Command-Line FTP Upload with No Proxy Server   2.       C# & Windows Command-Line FTP Upload with Proxy Server   Not covered here: Secure FTP / SFTP   Sample Attributes: ·         UploadFilePath = “\\servername\folder\file.name” ·         Proxy Server = “ftp://proxy.server/” ·         FTP Target Server = ftp.target.com ·         FTP User = “User” ·         FTP Password = “Password” with No Proxy Server ·         Windows Command-Line > ftp ftp.target.com > ftp User: User > ftp Password: Password > ftp put \\servername\folder\file.name > ftp dir           (result: file.name listed) > ftp del file.name > ftp dir           (result: file.name deleted) > ftp quit   ·         C#   //----------------- //Start FTP via _TargetFtpProxy //----------------- string relPath = Path.GetFileName(\\servername\folder\file.name);   //result: relPath = “file.name”   FtpWebRequest ftpWebRequest = (FtpWebRequest)WebRequest.Create("ftp.target.com/file.name); ftpWebRequest.Method = WebRequestMethods.Ftp.UploadFile;   //----------------- //user - password //----------------- ftpWebRequest.Credentials = new NetworkCredential("user, "password");   //----------------- // set proxy = null! //----------------- ftpWebRequest.Proxy = null;   //----------------- // Copy the contents of the file to the request stream. //----------------- StreamReader sourceStream = new StreamReader(“\\servername\folder\file.name”);   byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); ftpWebRequest.ContentLength = fileContents.Length;     //----------------- // transer the stream stream. //----------------- Stream requestStream = ftpWebRequest.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close();   //----------------- // Look at the response results //----------------- FtpWebResponse response = (FtpWebResponse)ftpWebRequest.GetResponse();   Console.WriteLine("Upload File Complete, status {0}", response.StatusDescription);   with Proxy Server ·         Windows Command-Line > ftp proxy.server > ftp User: [email protected] > ftp Password: Password > ftp put \\servername\folder\file.name > ftp dir           (result: file.name listed) > ftp del file.name > ftp dir           (result: file.name deleted) > ftp quit   ·         C#   //----------------- //Start FTP via _TargetFtpProxy //----------------- string relPath = Path.GetFileName(\\servername\folder\file.name);   //result: relPath = “file.name”   FtpWebRequest ftpWebRequest = (FtpWebRequest)WebRequest.Create("ftp://proxy.server/" + relPath); ftpWebRequest.Method = WebRequestMethods.Ftp.UploadFile;   //----------------- //user - password //----------------- ftpWebRequest.Credentials = new NetworkCredential("[email protected], "password");   //----------------- // set proxy = null! //----------------- ftpWebRequest.Proxy = null;   //----------------- // Copy the contents of the file to the request stream. //----------------- StreamReader sourceStream = new StreamReader(“\\servername\folder\file.name”);   byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); ftpWebRequest.ContentLength = fileContents.Length;     //----------------- // transer the stream stream. //----------------- Stream requestStream = ftpWebRequest.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close();   //----------------- // Look at the response results //----------------- FtpWebResponse response = (FtpWebResponse)ftpWebRequest.GetResponse();   Console.WriteLine("Upload File Complete, status {0}", response.StatusDescription);

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  • How can I get access to password hashing in postgresql? Tried installing postgresql-contrib in ubun

    - by Tchalvak
    So I'm trying to just hash some passwords in postgresql, and the only hashing solution that I've found for postgresql is part of the pgcrytpo package ( http://www.postgresql.org/docs/8.3/static/pgcrypto.html ) that is supposed to be in postgresql-contrib ( http://www.postgresql.org/docs/8.3/static/contrib.html ). So I installed postgresql-contrib, (sudo apt-get install postgresql-contrib), restarted my server (as a simple way to restart postgresql). However, I still don't have access to any of the functions for hashing that are supposed to be in postgresql-contrib, e.g.: ninjawars=# select crypt('global salt' || 'new password' || 'user created date', gen_salt('sha256')); ERROR: function gen_salt(unknown) does not exist ninjawars=# select digest('test', 'sha256') from players limit 1; ERROR: function digest(unknown, unknown) does not exist ninjawars=# select hmac('test', 'sha256') from players limit 1; ERROR: function hmac(unknown, unknown) does not exist So how can I hash passwords in postgresql, on ubuntu?

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  • How to reduce timeout for bad password on disconnected laptop?

    - by Elroy Flynn
    I use a Windows 7 laptop computer. When not attached to my AD domain, if I enter an incorrect password, I have to wait approximately a full minute before the failure response comes back. When attached to the domain, the response is instant. I think that what's happening is that is that when my entry fails against the cached pw, Windows tries to reach the domain controller and the timeout for that operation is about 60s. Is there a registry entry that controls the timeout? I'd love to reduce it.

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  • How to deal with arrays of data in cookies

    - by peter
    Hi all, I want to store data in a cookie and I am not exactly sure how I will go about it. The data is the UserName, and Password values for the users that are logging into a website, e.g. sometime like this UserName = bob, Password=Passw0rd1 UserName = harry, Password=BLANK UserName = george, Password=R0jjd6s What this means is that bob and george logged into the site and chose to have their password remembered, but harry chose for his password not to be remembered. So on the login dialog a dropdown will be present with all the usernames in it 'bob', 'harry', 'george'. If they select the username bob the password will automatically be filled in, etc. So how does that information need to be stored in the cookie? Like it is above, or does it have to be, UserName1 = bob, Password1=Passw0rd1 UserName2 = harry, Password2=BLANK UserName3 = george, Password3=R0jjd6s Are the username and password values actually stored in the same cookie, or is each piece of data separate? Any information would be good.

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  • How do I set a postgresql password in pgpass.conf for the Administrator account on Windows Server 2008?

    - by brad
    I have a pgpass.conf file that works well for my default user. It is in C:/Users/myuser/AppData/Roaming/postgresql/pgpass.conf. It reads like so; localhost:5432:*:postgres:password1 I have a process that runs under the Administrator account. When I run whoami under this process I get nt authority/system. I want to be able to access the database from this process but it gets stuck because it needs a password. I have tried putting the above pgpass.conf into C:/Users/Administrator/AppData/postgresql/pgpass.conf and C:/Users/Administrator/AppData/Roaming/postgresql/pgpass.conf but it does not work. Is this the correct place for this file? Am I even able to do this as the Administrator. Unfortunately I cannot change the user that this process runs under.

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  • Worksheet.Unprotect - Office Interop - Difference between 2003 and 2007

    - by sdmcnitt
    I have a .NET winforms app that automates Excel and checks for a worksheet password. The requirements are to be able to detect 1) that the protection is turned off 2) that the password is removed (protected but there is no password) 3) that the password matches the correct password from a database To meet the second requirement the program calls the Worksheet.Unprotect command with a null string, capturing the error. If error as expected, the 3rd check is made. If no error, then the Unprotect worked without a password == password was removed. The code sample below has these checks. The application can do this fine with Office 2003. I have since had my dev machine updated to Office 2007 and it no longer works as it did. When I call the Worksheet.Unprotect, Excel prompts for the password! I need to know how this should be accomplished in the new version of Excel or if there is a way to reference the old PIA. No matter what if I set a reference to Excel 11 it is replaced with the PIA for 12 in the GAC. 'return true if unprotect of worksheet does not generate an error 'all other errors will bubble up 'return false if specific error is "Password is invalid..." Try 'detect unprotected or no password If oWorksheet.ProtectContents Then 'try with no passsword and expect an error 'if no error then raise exception Dim blnRaiseException As Boolean = True Try 'oWorksheet.Unprotect(vbNullString) oWorksheet.Unprotect() Catch ex As Exception blnRaiseException = False End Try If blnRaiseException Then Throw New ExcelSheetNoPasswordException End If oWorksheet.Unprotect(strPwd) 'no error so if we get here -- success fnCheckWorksheetPwd = True 'leave as it was -- this may still cause workbook to think it is changed oWorksheet.Protect(strPwd) Else Throw New ExcelSheetNotProtectedException End If Catch COMex As System.Runtime.InteropServices.COMException 'handle error code -2146827284 If COMex.ErrorCode = -2146827284 Then 'this is the error we're looking for Else Throw End If Catch ex As Exception Throw End Try

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  • Enabling publickey authentication for server's sshd

    - by aaron
    I have two servers running RHEL 5. Both have nearly identical configurations. I have set up RSA Publickey authetication on both, and one works but the other does not: [my_user@client] $ ssh my_user@server1 --- server1 MOTD Banner --- [my_user@server1] $ and on the other server: [my_user@client] $ ssh my_user@server2 my_user@server2's password: --- server2 MOTD Banner --- [my_user@server2] $ server2's /etc/ssh/sshd_config file snippet: RSAAuthentication yes PubkeyAuthentication yes AuthorizedKeysFile .ssh/authorized_keys When I run ssh -vvv I get the following snippet: debug3: authmethod_lookup publickey debug3: remaining preferred: keyboard-interactive,password debug3: authmethod_is_enabled publickey debug3: Next authentication method: publickey debug1: Offering public key: /home/my_user/.ssh/id_rsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug1: Authentication that can continue: publickey,gssapi-with-mic,passowrd debug1: Offering public key: /home/my_user/.ssh/id_dsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug1: Authentication that can continue: publickey,gssapi-with-mic,passowrd debug3: authmethod_lookup password debug3: remaining preferred: ,password debug3: authmethod_is_enabled password debug1: Next authentication method: password my_user@server2's password:

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  • additional security measures besides a login with user-password - what can you think of?

    - by Tom Tom
    I'm wondering which additional security measures one could take besides a traditional login with user and password. What do you think of this one: _manually adding a cookie to each client which includes a secret key _this cookie is not served by the webserver, it is actually copied "by hand" to each client computer _if a client connects to the web-app the server graps that cookie and if the containing secret key is ok, the traditional login box is presented where the user has to enter the user-password combination _communication between client and server is encrypted with https Thus a potential intruder would first need to get the cookie from the clients computer, which is only possible with having access to the clients computer. This would work only for a very small user-base and an admin willing to do this manual work.

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  • Trying to send email in Java using gmail always results in username and password not accepted.

    - by Thaeos
    When I call the send method (after setting studentAddress), I get this: javax.mail.AuthenticationFailedException: 535-5.7.1 Username and Password not accepted. Learn more at 535 5.7.1 http://mail.google.com/support/bin/answer.py?answer=14257 y15sm906936wfd.10 I'm pretty sure the code is correct, and 100% positive that the username and password details I'm entering are correct. So is this something wrong with gmail or what? This is my code: import java.util.*; import javax.mail.*; import javax.mail.internet.*; public class SendEmail { private String host = "smtp.gmail.com"; private String emailLogin = "[email protected]"; private String pass = "xxx"; private String studentAddress; private String to; private Properties props = System.getProperties(); public SendEmail() { props.put("mail.smtps.auth", "true"); props.put("mail.smtps.starttls.enable", "true"); props.put("mail.smtp.host", host); props.put("mail.smtp.user", emailLogin); props.put("mail.smtp.password", pass); props.put("mail.smtp.port", "587"); to = "[email protected]"; } public void setStudentAddress(String newAddress) { studentAddress = newAddress; } public void send() { Session session = Session.getDefaultInstance(props, null); MimeMessage message = new MimeMessage(session); try { message.setFrom(new InternetAddress(emailLogin)); InternetAddress[] studentAddressList = {new InternetAddress(studentAddress)}; message.setReplyTo(studentAddressList); message.setRecipient(Message.RecipientType.TO, new InternetAddress(to)); message.setSubject("Test Email"); message.setText("This is a test email!"); Transport transport = session.getTransport("smtps"); transport.connect(host, emailLogin, pass); transport.sendMessage(message, message.getAllRecipients()); transport.close(); } catch (MessagingException me) { System.out.println("There has been an email error!"); me.printStackTrace(); } } } Any ideas...

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  • What's the simplest configuration of SVN on a Windows Server to avoid plain text password storage?

    - by detly
    I have an SVN 1.6 server running on a Windows Server 2003 machine, served via CollabNet's svnserve running as a service (using the svn protocol). I would like to avoid storing passwords in plain text on the server. Unfortunately, the default configuration and SASL with DIGEST-MD5 both require plain text password storage. What is the simplest possible way to avoid storing passwords in plain text? My constraints are: Path-based access control to the SVN repository needs to be possible (currently I can use an authz file). As far as I know, this is more-or-less independent of the authentication method. Active directory is available, but it's not just domain-connected windows machines that need to authenticate: workgroup PCs, Linux PCs and software that uses PySVN to perform SVN operations all need to be able to access the repositories. Upgrading the SVN server is feasible, as is installing additional software.

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  • On iPhone, how do I show a login screen to get username and password before giving access to iPhone

    - by MikeN
    On iPhone, how do I show a login screen to get username and password before giving access to iPhone app? Also, does the iPhone store a cookie to the secure website like a web browser? I was thinking of giving users to my website a long API key to store in the settings of their iPhone instead of asking them to login with a username/password (seems to be the Slicehost iPhone app approach.) Which is the best way to get a user to login securely? I have full control over the design of the iPhone app and website so have a lot of flexibility.

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  • Why does my Mac always crash when I enable `ask for password after screensaver ended`?

    - by Koning Baard XIV
    I have enabled these two things: Placing the mouse-pointer in the bottom-left corner of any display makes the screensaver appear After the screensaver or stand-by has ended, ask for password However, this combination always leads to this (Black Screen of Death) after entering the screensaver with the bottom-left corner: Here are my system specs: Hardware Overview: Model Name: iMac Model Identifier: iMac9,1 Processor Name: Intel Core 2 Duo Processor Speed: 2,66 GHz Number Of Processors: 1 Total Number Of Cores: 2 L2 Cache: 6 MB Memory: 2 GB Bus Speed: 1,07 GHz Boot ROM Version: IM91.008D.B08 SMC Version (system): 1.44f0 Serial Number (system): W89171JF0TF Hardware UUID: 323A90F0-8A2F-5057-B501-2087489E0DFF System Software Overview: System Version: Mac OS X 10.6.3 (10D573) Kernel Version: Darwin 10.3.0 Boot Volume: Macintosh HD Boot Mode: Normal Computer Name: YOU SHOULD NOT KNOW THIS User Name: YOU SHOULD NOT KNOW THIS Secure Virtual Memory: Not Enabled 64-bit Kernel and Extensions: No Time since boot: 11:46 Can anyone help me? Thanks

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  • How to force WinXP to ask for password before software installation/uninstall?

    - by crosenblum
    I really like some of the linux security measures it uses. So what i'd like to do is have WinXP Pro SP3 ask for my user password everytime i try to install/remove software. I know I can't make windows be as secure as linux, but i'd love to adopt some of the great ideas and measures used, as possible, to make windows more secure. Any suggestions? P.S. Are there other people out there, who try to make their windows feel more linux like? Just curious.

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  • Remote desktop logs in with saved credentials when connecting from one computer but asks for username and password from another.

    - by AndrejaKo
    I have two computers on which I recently installed windows 7 64 bit. Using VPN, they connect to remote network on which there is a Windows Server 2000 SP4 computer. User is supposed to connect to server using remote desktop. I set same VPN and remote desktop settings on both computers with Windows 7. I set Remote desktop to save connection credentials on both computers, but when I connect to server form one computer, it uses saved credentials and I don't get log-in prompt on server side. On the other computer with same settings using same username and password, I get log-in prompt once the remote desktop connects to server. I even tried copying the .rdp file from the computer on which everything is working fine to the other computer, but that didn't help. Note that I'm not trying to have both computers connected at the same time. What is causing this and how do I make the other computer skip windows server 2000 log-in prompt.

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