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  • Understanding CABasicAnimation when spinning an object from a random angle....

    - by user157733
    I have spent ages trying to figure this out and I am still having problems. I want to rotate an image a random number of time - say 5 and a bit - then have it stop. I then want to rotate it again FROM ITS STOPPED POSITION. I am having difficulty with this so maybe someone can advise me on the right way to do it. Ok so I am using a CABasicAnimation for the spin like this... CABasicAnimation* rotationAnimation; rotationAnimation = [NSNumber numberWithFloat: 0.0]; rotationAnimation.toValue = [NSNumber numberWithFloat: M_PI * 1.0]; rotationAnimation.duration = 100; rotationAnimation.cumulative = YES; rotationAnimation.repeatCount = 5.2; rotationAnimation.removedOnCompletion = NO; rotationAnimation.fillMode = kCAFillModeForwards; [myView.layer addAnimation:rotationAnimation forKey:@"rotationAnimation"]; This works fine. I use a animationDidStop function to transform the image to the new angle so that it actually in the new position (not just appearing that way). This is where my problems start. I have tried the following... removing the toValue line which means the animation starts from where it currently is but when the animation block is repeated it jumps back to this start position every time the block is run storing the value of the end rotation and using this in the toValue so the 2 lines of code become... rotationAnimation = [NSNumber numberWithFloat: previousVal]; rotationAnimation.toValue = [NSNumber numberWithFloat: (M_PI * 1.0)+previousVal]; when I do this the animation still jumps because it is flicking back to the previousVal everytime the block is repeated Therefore my final thought is to check to see if the image is at zero, if not then rotate it to zero, then impliment the block of code to spin multiple times. This seems complicated but is this the ONLY way to achieve this? I am concerned about getting the timings smooth with this method. Any suggestions would be amazing! Thanks

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  • How can I test a form that requires the entry of two random characters from a security phrase?

    - by lawm
    I need to test a two-stage login system which first asks for your email address and password and then presents the user with two select lists containing [a-zA-Z0-9]. The labels beside the drop down's are of the form 'Select character X from your security phrase', where X is a random character index from a known security phrase. I'd rather not stub the code for an acceptance test, so is it possible to write a matcher in cucumber which will, given that we know the whole phrase, select the required character in each of the two lists? Here is the scenario I have so far and the steps involved: Scenario: valid login email, password and secret phrase takes me to the dashboard Given I am not logged in When I log in as "[email protected]" Then I should be on the dashboard page And I should see "Your Dashboard" When /^I log in as "([^\"]*)"$/ do |login| visit path_to('Login page') fill_in "Email", :with => login fill_in "Password", :with => "Password123" click_button "Log in" response.should contain("Please verify some characters from your security phrase") select "a", :from => "Select character X of your security phrase" select "b", :from => "Select character Y of your security phrase" click_button "Submit" end For example, if the security phrase is 'Secret123', X = 3 and Y = 8, the above would have to produce the equivalent of: select "c", :from => "Select character 3 of your security phrase" select "2", :from => "Select character 8 of your security phrase" The numbers X and Y in the actual page are inside span#svc_1 and span#svc_2 respectively. Thanks,

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  • What is the best way to limit text input entry to numbers, lowercase letters, and certain symbols?

    - by Adam Maras
    Without using jQuery, what is the best way to limit text entry of a textbox to numbers, lowercase letters and a given set of symbols (for example - and _)? If the user enters an uppercase letter, I would like it to be automatically converted to a lowercase letter, and if the user enters a symbol not within the given set, I would like to be able to instantly show a validation error (show some element adjacent to or below the text box). What's the cleanest cross-browser way of doing this without the aid of jQuery?

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  • C# Read a String then extract the numbers in that string.

    - by microsumol
    How can we get the numbers 7 and 4 and 5 from the following string: MODULE potmtpMAIN main <info: "Enterprise Optimizer 7.4 for COR Technology 5.5 -- Advanced Solver Edition", url:"http://EO.riverlogic.com", url_menu:"EO Online...", app_id:"EOAS",app_name:"Enterprise Optimizer AS", **app_major:7**, **app_minor:4**,**app_micro:5**,app_copyright:"\251 1996-2010 River Logic Inc.\r\nAll Rights Reserved."> Thank You in advance

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  • What is the best way to format Int32 numbers?

    - by Mendy
    What is the best way to get formatted Int32 numbers? Let say I have this o function: string o(int x); This is the value that o need to return according to x x = 0 => o = 00 x = 1 => o = 01 x = 5 => o = 05 x = 10 => o = 10 x = 31 => o = 31 x = 106 => o = 106

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  • Idiomatic scheme and generic programming, why only on numbers ?

    - by Skeptic
    Hi, In Scheme, procedures like +, -, *, / works on different types of numbers, but we don't much see any other generic procedures. For example, length works only on list so that vector-length and string-length are needed. I guess it comes from the fact that the language doesn't really offer any mechanism for defining generic procedure (except cond of course) like "type classes" in Haskell or a standardized object system. Is there an idiomatic scheme way to handle generic procedures that I'm not aware of ?

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  • Long numbers. Division.

    - by user577395
    Hello, world! I have a problem. Today I tried to create a code, which finds Catalan number. But in my program can be long numbers. I found numerator and denominator. But i can't div long numbers! Also, only standard libraries was must use in this program. Help me please. This is my code #include <vector> #include <iostream> using namespace std; int main(int argc, char *argv[]) { const int base = 1000*1000*1000; vector <int> a, b; int n, carry = 0; cin>>n; a.push_back(n); for (int ii=n+2; ii!=(2*n)+1;++ii) { carry = 0; for (size_t i=0; i<a.size() || carry; ++i) { if (i == a.size()) a.push_back (0); long long cur = carry + a[i] * 1ll * ii; a[i] = int (cur % base); carry = int (cur / base); } } while (a.size() > 1 && a.back() == 0) a.pop_back(); b.push_back(n); for (int ii=1; ii!=n+1;++ii) { carry = 0; for (size_t i=0; i<b.size() || carry; ++i) { if (i == b.size()) b.push_back (0); long long cur = carry + b[i] * 1ll * ii; b[i] = int (cur % base); carry = int (cur / base); } } while (b.size() > 1 && b.back() == 0) b.pop_back(); cout<<(a.empty() ? 0 : a.back()); for (int i=(int)a.size()-2; i>=0; --i) cout<<(a[i]); cout<<" "; cout<<(b.empty() ? 0 : b.back()); for (int i=(int)b.size()-2; i>=0; --i) cout<<(b[i]); //system("PAUSE"); cout<<endl; return 0; } P.S. Sorry for my bad english =)

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