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• Is this XML file correct for RSS feeding?

  - by Hermet

  Hi guys I am generating a XML-RSS type file from PHP. The output for example is like this <?xml version="1.0" encoding="iso-8859-1"?> <rss version="2.0"> <channel> <title>Mi web mola</title> <link>http://www.dominio.com/blog.php</link> <language>es-ES</language> <description>Mallas y eso</description> <generator>Autor</generator> <item> <title>Articulo de prueba</title> <link>http://www.midominio.com/2342</link> <pubDate>14/06/2010</pubDate> <description><![CDATA[Descripcion de prueba bla bla bla]]></description> <content:encoded><![CDATA[Contenido prueba]]></content:encoded> </item> </channel> </rss> ... and all I can see in the Firefox preview is the title and the description of the blog, not the items, but in the source it appears correctly, so I've thought it must be a parse error or something like that.. What could be wrong? Again, excuse me for my bad english, and thank you very much.

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• linq to xml enumerating over descendants

  - by gh9

  Hi trying to write a simple linq query from a tutorial I read. But i cannot seem to get it to work. I am trying to display both the address in the attached xml document, but can only display the first one. Can someone help me figure out why both aren't being printed. Thank you very much <?xml version="1.0" encoding="utf-8" ?> <Emails> <Email group="FooBar"> <Subject>Test subject</Subject> <Content>Test Content</Content> <EmailTo> <Address>[email protected]</Address> <Address>[email protected]</Address> </EmailTo> </Email> </Emails> Dim steve = (From email In emailList.Descendants("Email") _ Where (email.Attribute("group").Value.Equals("FooBar")) _ Select content = email.Element("EmailTo").Descendants("Address")).ToList() If Not steve Is Nothing Then For Each addr In steve Console.WriteLine(addr.Value) Next Console.ReadLine() End If

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• C# xml read, show error

  - by gloris

  Whats wrong with my code? XmlTextReader textReader = new XmlTextReader(@"D:\xml_file.xml"); textReader.Read(); // If the node has value while (textReader.Read()) { // Move to fist element textReader.MoveToElement(); Console.WriteLine("XmlTextReader Properties Test"); Console.WriteLine("==================="); // Read this element's properties and display them on console Console.WriteLine("id:" + textReader.id.ToString()); Console.WriteLine("name:" + textReader.name.ToString()); Console.WriteLine("time:" + textReader.time.ToString()); } Console.ReadLine() show erron on: id, name, time My XML file: <students> <student> <id>1</id> <name>Rikko Nora</name> <time>2010-03-12</time> </student> <student> <id>2</id> <name>Rikko Nora2</name> <time>2010-05-15</time> </student> </students>

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• Uploading an xml direct to ftp

  - by Joshua Maerten

  i put this direct below a button: XmlDocument doc = new XmlDocument(); XmlElement root = doc.CreateElement("Login"); XmlElement id = doc.CreateElement("id"); id.SetAttribute("userName", usernameTxb.Text); id.SetAttribute("passWord", passwordTxb.Text); XmlElement name = doc.CreateElement("Name"); name.InnerText = nameTxb.Text; XmlElement age = doc.CreateElement("Age"); age.InnerText = ageTxb.Text; XmlElement Country = doc.CreateElement("Country"); Country.InnerText = countryTxb.Text; id.AppendChild(name); id.AppendChild(age); id.AppendChild(Country); root.AppendChild(id); doc.AppendChild(root); // Get the object used to communicate with the server. FtpWebRequest request = (FtpWebRequest)WebRequest.Create("ftp://users.skynet.be"); request.Method = WebRequestMethods.Ftp.UploadFile; request.UsePassive = false; // This example assumes the FTP site uses anonymous logon. request.Credentials = new NetworkCredential("fa490002", "password"); // Copy the contents of the file to the request stream. StreamReader sourceStream = new StreamReader(); byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); request.ContentLength = fileContents.Length; Stream requestStream = request.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close(); FtpWebResponse response = (FtpWebResponse)request.GetResponse(); response.Close(); MessageBox.Show("Created SuccesFully!"); this.Close(); but i always get an error of the streamreader path, what do i need to place there ? the meening is, creating an account and when i press the button, an xml file is saved to, ftp://users.skynet.be/testxml/ the filename is from usernameTxb.Text + ".xml".

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• How to search within an xml data set?

  - by user187580

  Hi, I have some xml data and I am trying to keyword search data. For example, if I search "some" for the following data it returns me the <id> and <title>. <resource> <id>101</id> <title>Test Environment</title> <description><b>Some</b> description. </description> <type>classroom</type> </resource> <resource> <id>102</id> <title>ABC Test Environment</title> <description><b>Some</b> another description. </description> <type>classroom</type> </resource> ... I had a look on on xpath e.g. $xml->xpath('//title') but looks for elements only. Basically what I need to do is to create a functionality where users can keyword search within the above data set which I receive from third party api in the above format. Any ideas how I can achieve this? using PHP/ Javascript etc. Thanks.

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• parse a special xml in python

  - by zhaojing

  I have s special xml file like below: <alarm-dictionary source="DDD" type="ProxyComponent"> <alarm code="402" severity="Alarm" name="DDM_Alarm_402"> <message>Database memory usage low threshold crossed</message> <description>dnKinds = database type = quality_of_service perceived_severity = minor probable_cause = thresholdCrossed additional_text = Database memory usage low threshold crossed </description> </alarm> ... </alarm-dictionary> I know in python, I can get the "alarm code", "severity" in tag alarm by: for alarm_tag in dom.getElementsByTagName('alarm'): if alarm_tag.hasAttribute('code'): alarmcode = str(alarm_tag.getAttribute('code')) And I can get the text in tag message like below: for messages_tag in dom.getElementsByTagName('message'): messages = "" for message_tag in messages_tag.childNodes: if message_tag.nodeType in (message_tag.TEXT_NODE, message_tag.CDATA_SECTION_NODE): messages += message_tag.data But I also want to get the value like dnkind(database), type(quality_of_service), perceived_severity(thresholdCrossed) and probable_cause(Database memory usage low threshold crossed ) in tag description. That is, I also want to parse the content in the tag in xml. Could anyone help me with this? Thanks a lot!

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• XML with iPhone app !

  - by totato

  hi .. I just work on web-based application for iPhone, And I try to retrieve data from my website to my app. can I edit XML code for my website as I want to be in my iPhone app? for example, XML for my website is: <item> <title>Announcement title</title> <link>iphone feed</link> <description>Announcement type</description> <category>Students</category> <pubDate>April 5, 2010, 12:50 pm</pubDate> <guid>iphone feed</guid> </item> but I can't retrieve all of this to the tableview in my app. So, I will edit the code to be like this: <item> <category name="staff"> <Announcement title="welcome back"> <description> hope all of you enjoy in the vacation, and welcome back to university </description> </Announcement> </category> </item> Is this the right way?

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• Populate on demand a TreeView with datas in an XML

  - by m6a-uds

  Hi I have a large XML file (3000+ nodes) that I want to represent in a TreeView on ASP.NET. I cannot databind it to a XMLDataSource because loading the TreeView will then be way too slow (I never even waited long enough to see it finish...) So the solution for this would be to use the PopulateOnDemand property of the TreeNodes to load data only when needed. Problem is, I can't think of a way to acheive this... How can-I, based on the ID of a node, search a XMLDocument to get all the childnodes of the node having this ID? XML would look like that: <document ID=1> <document ID=2> <document ID=3> </document> </document> <document ID=4> </document> </document> There are nor rules on how much levels it can go down or anything...

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• SQL Server Querying An XML Field

  - by Gavin Draper

  I have a table that contains some meta data in an XML field. For example <Meta> <From>[email protected]</From> <To> <Address>[email protected]</Address> <Address>[email protected]</Address> </To> <Subject>ESubject Goes Here</Subject> </Meta> I want to then be able to query this field to return the following results From To Subject [email protected] [email protected] Subject Goes Here [email protected] [email protected] Subject Goes Here I've written the following query SELECT MetaData.query('data(/Meta/From)') AS [From], MetaData.query('data(/Meta/To/Address)') AS [To], MetaData.query('data(/Meta/Subject)') AS [Subject] FROM Documents However this only returns one record for that XML field. It combines both the 2 addresses into one result. Is it possible for split these on to separate records? The result I'm getting is From To Subject [email protected] [email protected] [email protected] Subject Goes Here Thanks Gav

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• How to send XML data through socket InputStream

  - by THeK3nger

  Hi, I'm trying to write a client-server application in Java with an XML-based protocol. But I have a great problem! See this part of client code: InputStream incoming = skt.getInputStream(); //I get Stream from Socket. OutputStream out = skt.getOutputStream(); [...] XMLSerializer serializer = new XMLSerializer(); //This create an XML document. tosend = WUTPClientWriter.createMessage100(projectid, cpuclock, cpunumber); serializer.setOutputByteStream(out); serializer.serialize(tosend); At this point server fall in deadlock. It wait for EOF but I can't send it because if I use out.close(); or skt.shutdownOutput(); I close Socket and I must keep alive this connection. I can't send '\0' becouse I get Parse Error in the server. How can I do? Can I "close" output stream without close socket? RESOLVED I've created new class XMLStreamOutput and XMLStreamInput with advanced Stream gesture.

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• Switch XML value for another in google maps

  - by JeffP

  all thanks for taking a look. Problem: Using Google maps I need to switch catid value to another value. How would I approach this and display it in a the window. E.G var catid = { 2: { newcatid: 'london' }, 4: { newcatid: 'newyork' } }; function load() { var map = new google.maps.Map(document.getElementById("map"), { center: new google.maps.LatLng(47.6145, -122.3418), zoom: 5, mapTypeId: 'roadmap' }); var infoWindow = new google.maps.InfoWindow; // Change this depending on the name of your PHP file downloadUrl("index_xml.php", function(data) { var xml = data.responseXML; var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("title"); var address = markers[i].getAttribute("address"); var catid = markers[i].getAttribute("catid"); var point = new google.maps.LatLng( parseFloat(markers[i].getAttribute("latitude")), parseFloat(markers[i].getAttribute("langtitude"))); var html = "<b>" + name + "</b> <br/>" + address + "<br/>" + **catid** + "<br/> <a href='@'>Info</a>" ;

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• C# XML Documentation Compiler Warning

  - by ImperialLion

  I am curious as to why I get a compiler warning in the following situation. /// <summary>This is class A /// </summary> public class A { /// <summary>This is the documentation for Method A /// </summary> public void MethodA() { //Do something } } /// <summary>This is class B /// </summary> public class B : A { /// <summary>This does something that I want to /// reference <see cref="MethodA"/> /// </summary> public void MethodB() { //Do something } } The warning states that "XML comment on 'B.MethodB()' has cref attribute 'MethodA' that could not be resolved." If B inherits from A shouldn't the compiler be able to see that method when generating the documentation without me specifying the parent class in the cref? If I change the cref to be cref="A.MethodA()" it works fine, but it seems like that's unnecessary and is a pain to do, especially if I have to go up more than one level. As a note to anyone testing this you have to be sure to "XML documentation file" checked in the Properties - Build in order to see the warning.

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• Query decendants in XML to Linq

  - by Gordon

  I have the following xml data: <portfolio> <item> <title>Site</title> <description>Site.com is a </description> <url>http://www.site.com</url> <photos> <photo url="http://www.site.com/site/thumbnail.png" thumbnail="true" description="Main" /> <photo url="http://www.site.com/site/1.png" thumbnail="false" description="Main" /> </photos> </item> </portfolio> In c# I am using the following link query: List list = new List(); XDocument xmlDoc = XDocument.Load(HttpContext.Current.Server.MapPath("~/app_data/portfolio.xml")); list = (from portfolio in xmlDoc.Descendants("item") select new PortfolioItem() { Title = portfolio.Element("title").Value, Description = portfolio.Element("description").Value, Url = portfolio.Element("url").Value }).ToList(); How do I go about querying the photos node? In the PortfolioItem class I have a property: List Photos {get;set;} Any ideas would be greatly appreciated!

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• Linq Return node level of hierarchical xml

  - by Ryan

  In a treeview you can retrieve the level of an item. I am trying to accomplish the same thing with the given input being an object. The XML data I will use for this example would be something like the following <?xml version="1.0" encoding="utf-8" ?> <Testing> <Numbers> <Number val="1"> <Number val="1.1"> <Number val="1.1.1"> <Number val="1.1.2" /> <Number val="1.1.3" /> <Number val="1.1.4" /> </Number> </Number> <Number val="1.2" /> <Number val="1.3" /> <Number val="1.4" /> </Number> <Number val="2" /> <Number val="3" /> <Number val="4" /> </Numbers> <Numbers> <Number val="5" /> <Number val="6" /> <Number val="7" /> <Number val="8" /> </Numbers> </Testing> This one is kicking my butt!

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• Is it possible to create the following XML using Xdocument(C#3.0)

  - by Newbie

  <?xml version='1.0' encoding='UTF-8'?> <StockMarket> <StockDate Day = "02" Month="06" Year="2010"> <Stock> <Symbol>ABC</Symbol> <Amount>110.45</Amount> </Stock> <Stock> <Symbol>XYZ</Symbol> <Amount>366.25</Amount> </Stock> </StockDate> <StockDate Day = "03" Month="06" Year="2010"> <Stock> <Symbol>ABC</Symbol> <Amount>110.35</Amount> </Stock> <Stock> <Symbol>XYZ</Symbol> <Amount>369.70</Amount> </Stock> </StockDate> </StockMarket> My approach so far is XDocument doc = new XDocument( new XElement("StockMarket", new XElement("StockDate", new XAttribute("Day", "02"),new XAttribute("Month","06"),new XAttribute("Year","2010")), new XElement("Stock") ) ); Since I am new to Linq to XML, I am presently struggling a lot and henceforth seeking for help. Using C#3.0 . Thanks

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• Deleting items from datagrid (xml)

  - by Tonz

  Hello, I have a datagrid buttoncolumn which acts as delete buttons for my xml nodes. The elements are simply displayed in a boundcolumn, so there names get displayed. Each item generated gets a unique id (each time one is made id+++). My question his how can i remove a item (the entire element node with that certain id) when i click on one of the buttons in the bound column? <root> <element id="0"> <name>One</name> </element> <element id="1"> <name>Two</name> </element> </root> protected void dg_DeleteCommand(object sender, DataGridCommandEventArgs e) { XmlFunctions.Remove(index); }/*dg_DeleteCommand*/ (function on other class, where all my xml methods are written) public static void Remove(string index) { XmlDocument XMLDoc = new XmlDocument(); XMLDoc.Load(XMLFile); XPathNavigator nav = XMLDoc.CreateNavigator(); var node = nav.SelectSingleNode("/test/one[@id='" +???+ "']"); node.DeleteSelf(); XMLDoc.Save(XMLFile); } Edit: added datagrid <asp:View ID="viewDelete" runat="server"> <asp:DataGrid ID="dgDelete runat="server" AutoGenerateColumns="False" OnDeleteCommand="dg_DeleteCommand"> <Columns> <asp:BoundColumn DataField="name" HeaderText="names" /> <asp:ButtonColumn ButtonType="PushButton" Text="Delete" CommandName="Delete" ></asp:ButtonColumn> </Columns> </asp:DataGrid> </asp:View>

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• Copy existing XML, duplicate element and modify

  - by Robert

  Hi, I have a tricky XSL problem at the moment. I need to copy the existing XML, copy a certain element (plus its child elements) and modify the value of two child-elements. The modifications are: divide value of the 'value' element by 110 and edit the value of the 'type' element from 'normal' to 'discount'. This is currently what I have: Current XML: <dataset> <data> <prices> <price> <value>50.00</value> <type>normal</type> </price> </prices> </data> </dataset> Expected result <dataset> <data> <prices> <price> <value>50.00</value> <type>normal</type> </price> <price> <value>45.00</value> <type>discount</type> </price> </prices> </data> </dataset> Any takers? I've gotten as far as copying the desired 'price' element using copy-of, but I'm stuck as to how to modify it next.

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• Properly obsoleting old members in an XML Serializable class in C# VB .NET

  - by George

  Hi! Some time ago I defined a class that was serialized using XML. That class contained a serializable propertyA of integer type. Now I have extended and updated this class, whereby a new propertyB was added, whose type is another class that also has several serializable properties. The new propertyB is now supposed to play the role of propertyA, that is since type of propertyB is another class, one of its members would contain the value that previously propertyA contained, thus making peroptyA obsolete. What I am trying to figure out is how do I make sure that when I desireliaze the OLD version of this class (without propertyB in it), I make sure that the desreializer would take the value of propertyA from the old calss and set it as a value of one of the members of propertyB in a new class? Private WithEvents _Position As Position = New Position(Alignment.MiddleMiddle, 0, True, 0, True) Public Property Position() As Position 'NEW composite property that holds the value of the obsolted property, i.e. Alignment Get Return _Position End Get Set(ByVal value As Position) _Position = value End Set End Property Private _Alignment As Alignment = Alignment.MiddleMiddle <Xml.Serialization.XmlIgnore(), Obsolete("Use Position property instead.")> _ Public Property Alignment() As Alignment'The old, obsoleted property that I guess must be left for compliance with deserializing the old version of this class Get Return _Alignment End Get Set(ByVal value As Alignment) _Alignment = value End Set End Property Can you help me, please?

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• creating xml from database

  - by Prady

  hi, I am creating an xml from salesforce database, Everything works fine except when there is a & in the data which is been fetched. <apex:page contenttype="text/xml" > controller="Test2ab" > <data > wiki-section="Timeline"> <apex:repeat > value="{!lsttask}" var="e" > <event > start="{!e.ActivityDate}" title= > "{!e.Subject}"> <apex:outputText > value="{!e.Subject}" /> </event> > </apex:repeat> </data></apex:page> and in the controller i am just querying > lsttask =[Select OwnerId,WhoId,Status,Subject,ActivityDate from Task where Status = 'Completed' Order By ActivityDate Desc]; How can i use an escape for the value retrieved from the database Thanks Prady

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• Admob in xml not showing in Linear

  - by NoobMe

  i am implementing admob on my app it appears when the parent is in relative layout but i must not use the alignparentbottom so i am changing it to linear but it doesnt show when i change it to linear.. any tips? help? thanks in advance here it is in xml: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="vertical" > <RelativeLayout android:id="@+id/banner_holder" android:layout_width="match_parent" android:layout_height="wrap_content" > <ImageView android:id="@+id/offline_banner" android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_centerInParent="true" android:background="@color/black" android:src="@drawable/offline_banner" /> <com.google.ads.AdView xmlns:ads="http://schemas.android.com/apk/lib/com.google.ads" android:id="@+id/adView" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_centerInParent="true" ads:adSize="SMART_BANNER" ads:adUnitId="@string/unit_id" ads:loadAdOnCreate="true" /> </RelativeLayout> <FrameLayout android:id="@+id/fragmentContainer" android:layout_width="match_parent" android:layout_height="wrap_content" /> </LinearLayout> i want the admob to be at the bottom part of the screen without using the alignparentbottom of relative layout thanks~

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• Cannot get list of elements using Linq to XML

  - by Blackator

  Sample XML: <CONFIGURATION> <Files> <File>D:\Test\TestFolder\TestFolder1\TestFile.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile01.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile02.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile03.txt</File> <File>D:\Test\TestFolder\TestFolder1\TestFile04.txt</File> </Files> <SizeMB>3</SizeMB> <BackupLocation>D:\Log backups\File backups</BackupLocation> </CONFIGURATION> I've been doing some tutorials but I am unable to get all the list of file inside the files element. It only shows the first element and doesn't display the rest. This is my code: var fileFolders = from file in XDocument.Load(@"D:\Hello\backupconfig1.xml").Descendants("Files") select new { File = file.Element("File").Value }; foreach (var fileFolder in fileFolders) { Console.WriteLine("File = " + fileFolder.File); } How do I display all the File in the Files element, the SizeMB and BackupLocation? Thanks

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• placing the matched 2 different child elements xml values in a single line from xslt2.0

  - by Girikumar Mathivanan

  I have the below input xml, <GSKProductHierarchy> <GlobalBusinessIdentifier>ZGB001</GlobalBusinessIdentifier> <Hierarchy> <Material>335165140779</Material> <Level1>02</Level1> <Level2>02AQ</Level2> <Level3>02AQ006</Level3> <Level4>02AQ006309</Level4> <Level5>02AQ006309</Level5> <Level6>02AQ006309</Level6> <Level7>02AQ006309</Level7> <Level8>02AQ006309</Level8> </Hierarchy> <Hierarchy> <Material>335165140780</Material> <Level1>02</Level1> <Level2>02AQ</Level2> <Level3>02AQ006</Level3> <Level4>02AQ006309</Level4> <Level5>02AQ006309</Level5> <Level6>02AQ006309</Level6> <Level7>02AQ006309</Level7> <Level8>02AQ006310</Level8> </Hierarchy> <Texts> <ProductHierarchy>02AQ006310</ProductHierarchy> <Language>A</Language> <Description>CREAM</Description> </Texts> <Texts> <ProductHierarchy>02AQ006309</ProductHierarchy> <Language>B</Language> <Description>CREAM</Description> </Texts> as per the requirement, xsl should check the matched value of GSKProductHierarchy/Hierarchy/Level8 in the GSKProductHierarchy/Texts/ProductHierarchy elements...and its should result as below flat file. 335165140779|02|02AQ|02AQ006|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006309|A|CREAM| 335165140780|02|02AQ|02AQ006|02AQ006309|02AQ006309|02AQ006309|02AQ006309|02AQ006310|02AQ006310|B|CREAM| Right now I have the below xslt, <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exsl="http://exslt.org/common" xmlns:set="http://exslt.org/sets" xmlns:str="http://exslt.org/strings" xmlns:java="http://xml.apache.org/xslt/java" xmlns:saxon="http://saxon.sf.net/" exclude-result-prefixes="exsl set str java saxon"> <xsl:output method="text" indent="yes"/> <xsl:variable name="VarPipe" select="'|'"/> <xsl:variable name="VarBreak" select="'&#xa;'"/> <xsl:template match="/"> <xsl:for-each select="GSKProductHierarchy/Hierarchy"> <xsl:variable name="currentIndex" select="position()"/> <xsl:variable name="Level8" select="Level8"/> <xsl:variable name="ProductHierarchy" select="../Texts[$currentIndex]/ProductHierarchy"/> <xsl:if test="$Level8=$ProductHierarchy"> <xsl:value-of select="Material"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level1"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level2"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level3"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level4"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level5"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level6"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level7"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="Level8"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/ProductHierarchy"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/Language"/> <xsl:value-of select="$VarPipe"/> <xsl:value-of select="../Texts[$currentIndex]/Description"/> <xsl:value-of select="$VarPipe"/> <xsl:if test="not(position() = last())"> <xsl:value-of select="$VarBreak"/> </xsl:if> </xsl:if> </xsl:for-each> </xsl:template> can anyone please suggest what function should i need to use to get the desired result. Regards, Giri

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• Can I make Windows to open Excel XML files with Excel without opening Explorer?

  - by Sorin Sbarnea

  I want to be able to open Excel XML files in Excel but without assigning XML directly to Excel. There are lots of XML files that are not Excel files and I don't want to open all of them in Excel. The file has proper header for opening in Excel but currently it does open Internet Explorer that asks me if I want to open the file with Excel, save or cancel. I just want to open it without two another annoying windows.

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• What is a good XML Editor for Mac OS X?

  - by g.

  I am looking for a good lightweight XML viewer/editor for Mac OS X. It would only be for occasional use, so free options are preferable though paid options aren't out of the question. It would be used primarily for reviewing and making small changes to XML files and would require the following basic features. easily create a new file from clipboard (copy/paste) re-format (pretty print) xml syntax highlighting validation find

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• XML Serialization is not including milliseconds in datetime field from Rails model

  - by revgum

  By default, the datetime field from the database is being converted and stripping off the milliseconds: some_datetime = "2009-11-11T02:19:36Z" attribute_before_type_cast('some_datetime') = "2009-11-11 02:19:36.145" If I try to overrride the accessor for this attribute like; def some_datetime attribute_before_type_cast('some_datetime') end when I try "to_xml" for that model, I get the following error: NoMethodError (undefined method `xmlschema' for "2009-11-11 02:19:36.145":String): I have tried to parse the String to a Time object but can't get one to include the milliseconds; def some_datetime Time.parse(attribute_before_type_cast('some_datetime').sub(/\s/,"T").sub(/$/,"Z")) end Can anyone help get get a datetime with milliseconds rendered by to_xml?

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