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  • Oracle as a Service in the Cloud

    - by Jason Williamson
    This should really be a Tweet, but I guess I'm writing a bit more. In theme of data migration and legacy modernization, I am seeing more and more of a push to consolidate data sources, especially from non-oracle to oracle in an effort to save dollars. From a modernization perspective, this fits in quite well. We are able to migrate things like Terradata, Sybase and DB2 and put that all into an Oracle database and then provide that as a OaaS (Oracle as a Service) Cloud offering. This seems to be a growing trend, and not unlike the cool RDS Amazon Database cloud being built on Oracle as well. We again find ourselves back in the similar theme of migration, however. The target technology sounds like a winner (COBOL to Java/SOA...DB2/Datacom/Adabas to Oracle) but the age-old problem of how to get there still persists. It it not trivial to migrate large amounts of pre-relational or "devolved" relational data. To do this, we again must revert back to a tight roadmap to migration and leverage the growing tools and services that we have. I'm working on a couple of new sections and chapters for a book that Tom and Prakash and I are writing around Database Migration and Consolidation. I'll share some snipits shortly.

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  • SQL language drawbacks, The Third Manifesto

    - by David Portabella
    Sometime ago I read about SQL language drawbacks (the basic language specification, not vendor specific), and one of the drawbacks was that the language does not allow to create a set of tuples that don't come from a table. For instance, SELECT firstName, lastName from people; this creates a set of tuples coming from the table people. Now, if I don't have this table people, and I want to return a constant, I'd need something like this to return a set of two tuples (this would not require to have a table): SELECT VALUES('james', 'dean'), ('tom', 'cruisse'); Why I would need that? Because of the same reasons that we can define constants (not only basic types, but objects and arrays also) in any advanced programming language. Workarounds, Yes, I could create a temporal table, fill the data, and SELECT from that table. This is a hack, to overcome the drawbacks of the poor SQL language. I think that I read about this somewhere in "The Third Manifesto", but I don't find the paragraph/example talking about this concrete drawback anymore. Do you know a reference about it?

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  • ????????Java????

    - by hamsun
    Breanne Cooley,2014? 2 ? 20 ? ??:Tom McGinn,Java?????? ??? ??(IoT) ?? ???????? ????,??????????? ????????????????????????????????????????????????,?2020?,??????????????????? ??????: ? ???????????. ? ????????? ? ????????? ? ?????????????? Oracle Java?????(Java ME)Embedded  Oracle Java ?????(Java ME)Embedded????????????????,????????????????,????????????????? ???????? ???????????????? Java ME Embedded: Develop Applications for Embedded Devices,??????????????? ????????????,??????????????????LED? ?? ??????????????? ???????????????? ?????????????,??????????(AMS)? ????????????????????????????? ???????????!

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  • Finding a picture in a picture with java?

    - by tarrasch
    what i want to to is analyse input from screen in form of pictures. I want to be able to identify a part of an image in a bigger image and get its coordinates within the bigger picture. Example: would have to be located in And the result would be the upper right corner of the picture in the big picture and the lower left of the part in the big picture. As you can see, the white part of the picture is irrelevant, what i basically need is just the green frame. Is there a library that can do something like this for me? Runtime is not really an issue. What i want to do with this is just generating a few random pixel coordinates and recognize the color in the big picture at that position, to recognize the green box fast later. And how would it decrease performance, if the white box in the middle is transparent? The question has been asked several times on SO as it seems without a single answer. I found i found a solution at http://werner.yellowcouch.org/Papers/subimg/index.html . Unfortunately its in C++ and i do not understand a thing. Would be nice to have a Java implementation on SO.

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  • Force Finder to log in as Guest to a SMB share

    - by slhck
    I have a QNAP NAS that offers a few SMB shares. As I'm in a trusted environment, my shares are accessible as guest rather than with a combination of username and password. Problem Now, when I click the name of the device in Finder's sidebar, I get the black "Connection failed" bar, with the option "Connect as...". When I click that, I receive: I can however press ? + K and enter the server's name manually, which gets me to this window: Here, I have to select "guest". Now, I can select one of the shares to connect to, and I'm finally connected to the server. If I select it in the sidebar, I get a list of all shares available, because I'm connected as "guest", obviously: What I need Well, as soon as I unmount all shares, I have to go through the same procedure of manually logging in as "guest" again, which I find quite annoying. Is there any way I could get Finder (or the underlying SMB client) to know which credentials to use? Or should I look for the solution rather on the server side? (I know that other SMB shares seem to work fine in my network) Diagnostics The only thing I can get out of Console.app is: 5/15/11 7:36:40 PM /System/Library/CoreServices/Finder.app/Contents/MacOS/Finder[200] SharePointBrowser::handleOpenCallBack returned 64 This message occurs when I click the name of the SMB server in the Finder sidebar. Here's the output of `smbclient -L meredith -U guest -d=2 charon:~ werner$ smbclient -L meredith -U guest -d=2 added interface ip=192.168.100.11 bcast=192.168.100.255 nmask=255.255.255.0 tdb(unnamed): tdb_open_ex: could not open file /private/var/samba/gencache.tdb: Permission denied Got a positive name query response from 192.168.100.100 ( 192.168.100.100 ) Password: Domain=[MEREDITH] OS=[Unix] Server=[Samba 3.5.2] Sharename Type Comment --------- ---- ------- music Disk movies Disk photos Disk software Disk archive Disk backups Disk IPC$ IPC IPC Service (NAS Server) Got a positive name query response from 192.168.100.100 ( 192.168.100.100 ) Domain=[MEREDITH] OS=[Unix] Server=[Samba 3.5.2] Server Comment --------- ------- Workgroup Master --------- ------- WORKGROUP MEREDITH Also, things I've tried: There is no relevant entry in the Keychain (but why would it, I'm only connecting as guest) Connecting with user name "Guest" and empty password logs me in but still after ejecting the last share, I get the same "Connection failed" error as before. The appropriate entry is made in the Keychain but obviously has no effect.

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  • Force Finder to log in as Guest to a SMB share

    - by slhck
    I have a QNAP NAS that offers a few SMB shares. As I'm in a trusted environment, my shares are accessible as guest rather than with a combination of username and password. Problem Now, when I click the name of the device in Finder's sidebar, I get the black "Connection failed" bar, with the option "Connect as...". When I click that, I receive: I can however press ? + K and enter the server's name manually, which gets me to this window: Here, I have to select "guest". Now, I can select one of the shares to connect to, and I'm finally connected to the server. If I select it in the sidebar, I get a list of all shares available, because I'm connected as "guest", obviously: What I need Well, as soon as I unmount all shares, I have to go through the same procedure of manually logging in as "guest" again, which I find quite annoying. Is there any way I could get Finder (or the underlying SMB client) to know which credentials to use? Or should I look for the solution rather on the server side? (I know that other SMB shares seem to work fine in my network) Diagnostics The only thing I can get out of Console.app is: 5/15/11 7:36:40 PM /System/Library/CoreServices/Finder.app/Contents/MacOS/Finder[200] SharePointBrowser::handleOpenCallBack returned 64 This message occurs when I click the name of the SMB server in the Finder sidebar. Here's the output of `smbclient -L meredith -U guest -d=2 charon:~ werner$ smbclient -L meredith -U guest -d=2 added interface ip=192.168.100.11 bcast=192.168.100.255 nmask=255.255.255.0 tdb(unnamed): tdb_open_ex: could not open file /private/var/samba/gencache.tdb: Permission denied Got a positive name query response from 192.168.100.100 ( 192.168.100.100 ) Password: Domain=[MEREDITH] OS=[Unix] Server=[Samba 3.5.2] Sharename Type Comment --------- ---- ------- music Disk movies Disk photos Disk software Disk archive Disk backups Disk IPC$ IPC IPC Service (NAS Server) Got a positive name query response from 192.168.100.100 ( 192.168.100.100 ) Domain=[MEREDITH] OS=[Unix] Server=[Samba 3.5.2] Server Comment --------- ------- Workgroup Master --------- ------- WORKGROUP MEREDITH Also, things I've tried: There is no relevant entry in the Keychain (but why would it, I'm only connecting as guest) Connecting with user name "Guest" and empty password logs me in but still after ejecting the last share, I get the same "Connection failed" error as before. The appropriate entry is made in the Keychain but obviously has no effect.

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  • ExtJS: Ext.data.DataReader: #realize was called with invalid remote-data

    - by TomH
    I'm receiving a "Ext.data.DataReader: #realize was called with invalid remote-data" error when I create a new record via a POST request. Although similar to the discussion at this SO conversation, my situation is slightly different: My server returns the pk of the new record and additional information that is to be associated with the new record in the grid. My server returns the following: {'success':true,'message':'Created Quote','data': [{'id':'610'}, {'quoteNumber':'1'}]} Where id is the PK for the record in the mysql database. quoteNumber is a db generated value that needs to be added to the created record. Other relevant bits: var quoteRecord = Ext.data.Record.create([{name:'id', type:'int'},{name:'quoteNumber', type:'int'},{name:'slideID'}, {name:'speaker'},{name:'quote'}, {name:'metadataID'}, {name:'priorityID'}]); var quoteWriter = new Ext.data.JsonWriter({ writeAllFields:false, encode:true }); var quoteReader = new Ext.data.JsonReader({id:'id', root:'data',totalProperty: 'totalitems', successProperty: 'success',messageProperty: 'message',idProperty:'id'}, quoteRecord); I'm stumped. Anyone?? thanks tom

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  • Creating meaningful add URLs in Cakephp

    - by Loftx
    Hi there, For my site I have a number of Orders each of which contains a number of Quotes. A quote is always tied to an individual order, so in the quotes controller I add a quote with reference to it's order: function add($orderId) { // funtion here } And the calling URL looks a bit like http://www.example.com/quotes/add/1 It occurred to me the URLs would make more sense if they looked a bit more like http://www.example.com/orders/1/quotes/add As the quote is being added to order 1. Is this something it's possible to achive in CakePHP? Cheers, Tom

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  • Repeater and add columns to header and itemtemplate on page load

    - by sdmiller
    I haven't used repeaters for much more than showing data from a datatable. I am building a grid that that shows a list of users and columns of roles that the user has been assigned, shown with checkboxes (shown with true/false below but pretent they are checkboxes). ex. |Rep Name|Caller|Closer|Manager|SuperUser| |Bob |True |true | false | false | |Tom |false |false |True | True | Basically using it for roles management. However the roles may change later on so I want to load the roles(headers and items) dynamically into the repeater. I am not sure how to do this or if it is even possible. I figure you grab a list of current role possibilities and load them into the headertemplate but I am not sure how to match those with the itemtemplate and how to create checkboxes and place them in the itemtemplate. Sorry if it is a rudementary question.... I appreciate any advice!

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  • How to get element order number

    - by martin-masiar
    Hello everyone, how can i get order number of some element by javascript/jquery? <ul> <li>Anton</li> <li class="abc">Victor</li> <li class="abc">Simon</li> <li>Adam</li> <li>Peter</li> <li class="abc">Tom</li> </ul> There is 3xli with abc class. Now I need to get order(sequence) number of Simon li. Thanks in advance

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  • JavaOne pictures and Community Commentary on JCP Awards

    - by heathervc
    We posted some pictures from JCP related events at JavaOne 2012 on the JCP Facebook page today.  The 2012 JCP Program Award winners and some of the nominees responded to the community recognition of their achievements during some of the JCP events last week.     “Our job on the EC is to balance the need of innovation – so we don’t standardize too early, or too late. We try to find that sweet spot that makes innovation and standardization work together, and not against each other.”- Ben Evans, CEO of jClarity and Executive Committee (EC) representative of the London Java Community, 2012 JCP Member/Participant of the Year Winner“SouJava has been evangelizing the Java platform, promoting the Java ecosystem in Brazil, and contributing to JSRs for several years. It’s very gratifying to have our work recognized, on behalf of many developers and Java User Groups around the world. This really is the work of a large group of people, represented by the few that can be here tonight.”- Michael Santos, representative of SouJava, 2012 JCP Member/Participant of the Year Winner "In the last years Credit Suisse has contributed to the development of Java EE specifications through participation in many customer advisory boards, through statements of requirements for extensions to the core Java related products in use, and active participation in JSRs. Winning the JCP Outstanding Spec Lead Award 2012 is very encouraging for our engagement and also demonstrates the level of expertise and commitment to drive the evolution of Java. Victor Grazi is happy and honored to receive this award." - Susanne Cech Previtali, Executive Committee (EC) representative of Credit Suisse, accepting award for 2012 JCP Outstanding Spec Lead Winner "Managing a JSR is difficult. There are so many decisions to be made and so many good and varied opinions, you never really know if you have decided correctly. The key to success is transparency and collaboration. I am truly humbled by receiving this award, there are so many other active JSRs.” Victor added that going forward in the JCP EC, they would like to simplify and open the process of participation – being addressed in the JCP.Next initiative of the JCP EC. "We would also like to encourage the engagement of universities, professors and students – as an important part of the Java community. While innovation is the lifeblood of our community and industry, without strong standards and compatibility requirements, we all end up in a maze of technology where everything is slightly different and doesn’t quite work with everything else." Victo Grazi, Executive Committee (EC) representative of Credit Suisse, 2012 JCP Outstanding Spec Lead Winner“I am very pleased, of course, to accept this award, but the credit really should go to all of those who have participated in the work of the JCP, while pushing for changes in the way it operates.  JCP.Next represents three JSRs. The first two are done, but the final step, JSR 358, is the complicated one, and it will bring in the lawyers. Just to give you an idea of what we’re dealing with, it affects licensing, intellectual property, patents, implementations not based on the Reference Implementation (RI), the role of the RI, compatibility policy, possible changes to the Technical Compatibility Kit (TCK), transparency, where do individuals fit in, open source, and more.”- Patrick Curran, JCP Chair, Spec Lead on JCP.Next JSRs (JSR 348, JSR 355 and JSR 358), 2012 JCP Most Significant JSR Winner“I’m especially glad to see the JCP community recognize JCP.Next for its importance. The governance work it represents is KEY to moving the Java platform forward and the success of the technology.”- John Rizzo, Executive Committee (EC) representative of Aplix Corporation, JSR Expert Group Member “I am deeply honored to be nominated. I had the privilege to receive two awards on behalf of Expert Groups and Spec Leads two years ago. But this time, I am nominated personally, which values my own contribution to the JCP, and of course, participation in JSRs and the EC work. I’m a fan of Agile Principles and Values Working. Being an Agile Coach and Consultant, I use it for some of the biggest EC Member companies and projects. It fuels my ability to help the JCP become more agile, lean and transparent as part of the JCP.Next effort.” - Werner Keil, Individual Executive Committee (EC) Member, a 2012 JCP Member/Participant of the Year Nominee, JSR Expert Group Member“The JCP ever has been some kind of institution for me,” Markus said. “If in technical doubt, I go there, look for the specifications of the implementation I work with at the moment and verify what I had observed. Since the beginning of my Java journey more than 12 years back now, I always had a strong relationship with the JCP. Shaping the future of a technology by joining the JCP – giving feedback and contributing to the road ahead through individual JSRs – that brings you to a whole new level.”Calling himself, “the new kid on the block,” he explained that for years he was afraid to join the JCP and contribute. But in reality, “Every single one of the big names I meet from the different Expert Groups is a nice person. People you can actually work with,” he says. “And nobody blames you for things you don't know. As long as you are committed and bring what is worth the most: passion, experiences and the desire to make a difference.” - Markus Eisele, a 2012 JCP Member of the Year Nominee, JSR Expert Group MemberCongratulations again to all of the nominees and winners of the JCP Program Awards.  Next year, we will add another award for the group of JUG members (not an entire JUG) that makes the best contribution to the Adopt-a-JSR program.  Let us know if you have other suggestions or improvements.

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  • Grails checkbox

    - by Tomáš
    Hi gurus I have trouble with binding Boolean property in association classes. Property is set to true if I check checkbox (good), but is null if checbox is not checked. I know the problem with HTML checkbox. I know why is send "_fieldName" in params, but this "_fieldName" dont set my boolean property to false. class Person{ String title List<Group> groups = new ArrayList() static hasMany = [groups: Groups] } class Group{ String title Boolean isHidden static belongTo = Person } class PersonController{ def form = { def person = new Person() person.groups.add( new Group() ) return ["person": person] } def handleForm = { def person = new Person( params ) println person.groups[0] } } If I check checkbox: [isHidden:on, title:a, _isHidden:] println person.groups[0] //true If I don check checkbox: [title:a, _isHidden:] println person.groups[0] //null Thank a lot for help Tom I am sorry, I searched this web, but did not get actual info for my trouble.

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  • Using Solr and Zends Lucene port together...

    - by thebluefox
    Afternoon chaps, After my adventures with Zend-Lucene-Search, and discovering it isn't all its cracked up to be when indexing large datasets, I've turned to Solr (thanks to Bill Karwin for that :) ) I've got Solr indexing the db far far quicker now, taking just over 8 minutes to index a table of just over 1.7million rows - which I'm very pleased with. However, when I come to try and search the index with the Zend port, I run into the following error; Fatal error: Uncaught exception 'Zend_Search_Lucene_Exception' with message 'Unsupported segments file format' in /var/www/Zend/Search/Lucene.php:407 Stack trace: #0 /var/www/Zend/Search/Lucene.php(555): Zend_Search_Lucene-_readSegmentsFile() #1 /var/www/z_search.php(12): Zend_Search_Lucene-__construct('tmp/feeds_index') #2 {main} thrown in /var/www/Zend/Search/Lucene.php on line 407 I've tried to have a search around but can't seem to find anything about this problem, everyone just seems to be able to get them to work? Any help as always much appreciated :) Thanks, Tom

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  • Mysql : Request to select the last 10 send/received messages to/by different users

    - by Yako malin
    Hello, I want to select the 10 last messages you received OR you sent TO different users. For example the results must be shown like that : 1. John1 - last message received 04/17/10 3:12 2. Thomy - last message sent 04/16/10 1:26 3. Pamela - last message received 04/12/10 3:51 4. Freddy - last message received 03/28/10 9:00 5. Jack - last message sent 03/20/10 4:53 6. Tom - last message received 02/01/10 7:41 ..... Table looks like : CREATE TABLE `messages` ( `id` int(11) NOT NULL AUTO_INCREMENT, `time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, `sender` int(11) DEFAULT NULL, `receiver` int(11) DEFAULT NULL, `content` text ) Have someone any solution ? Thanks in advance for your help.

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  • Add comma-separated value of grouped rows to existing query

    - by Peter Lang
    I've got a view for reports, that looks something like this: SELECT a.id, a.value1, a.value2, b.value1, /* (+50 more such columns)*/ FROM a JOIN b ON (b.id = a.b_id) JOIN c ON (c.id = b.c_id) LEFT JOIN d ON (d.id = b.d_id) LEFT JOIN e ON (e.id = d.e_id) /* (+10 more inner/left joins) */ It joins quite a few tables and returns lots of columns, but indexes are in place and performance is fine. Now I want to add another column to the result, showing comma-separated values ordered by value from table y outer joined via intersection table x if a.value3 IS NULL, else take a.value3 To comma-separate the grouped values I use Tom Kyte's stragg, could use COLLECT later. Pseudo-code for the SELECT would look like that: SELECT xx.id, COALESCE( a.value3, stragg( xx.val ) ) value3 FROM ( SELECT x.id, y.val FROM x WHERE x.a_id = a.id JOIN y ON ( y.id = x.y_id ) ORDER BY y.val ASC ) xx GROUP BY xx.id What is the best way to do it? Any tips?

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  • Trying to speed up a SQLITE UNION QUERY

    - by user142683
    I have the below SQLITE code SELECT x.t, CASE WHEN S.Status='A' AND M.Nomorebets=0 THEN S.PriceText ELSE '-' END AS Show_Price FROM sb_Market M LEFT OUTER JOIN (select 2010 t union select 2020 t union select 2030 t union select 2040 t union select 2050 t union select 2060 t union select 2070 t ) as x LEFT OUTER JOIN sb_Selection S ON S.MeetingId=M.MeetingId AND S.EventId=M.EventId AND S.MarketId=M.MarketId AND x.t=S.team WHERE M.meetingid=8051 AND M.eventid=3 AND M.Name='Correct Score' With the current interface restrictions, I have to use the above code to ensure that if one selection is missing, that a '-' appears. Some feed would be something like the following SelectionId Name Team Status PriceText =================================== 1 Barney 2010 A 10 2 Jim 2020 A 5 3 Matt 2030 A 6 4 John 2040 A 8 5 Paul 2050 A 15/2 6 Frank 2060 S 10/11 7 Tom 2070 A 15 Is using the above SQL code the quickest & efficient?? Please advise of anything that could help. Messages with updates would be preferable.

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  • Connecting to SQL Server with Visual Studio Express Editions

    - by tlianza
    I find it odd that in Visual C# 2008 Express edition, when you use the database explorer, your options are: 1) Microsoft Access 2) SQL Server Compact 3.5, and 3) SQL Server Database File. BUT if you use Visual Web Developer 2008 Express, you can connect to a regular SQL Server, Oracle, ODBC, etc. For people developing command-line or other C# apps that need to talk to a SQL Server database, do you really need to build your LINQ/Data Access code with one IDE (Visual Web Developer) and your program in another (Visual C#)? It's not a hard workaround, but it seems weird. If Microsoft wanted to force you to upgrade to Visual Studio to connect to SQL Server, why would they include that feature in one of their free IDEs but not the other? I feel like I might be missing something (like how to do it all in Visual C#). Thanks! Tom

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  • Regex Pattern for ignoring a custom escape character

    - by user1517464
    I am trying to find a suitable regex for matching pair of custom characters in an input string. These custom characters are replaced by their corresponding html tags. For e.g. The input string can have underscores in pairs to indicate words in bold. Hence, _Name_ outputs as <b>Name</b> However if there is a genuine underscore in the string, it cannot be replaced by "bold" tags and has to be ignored. The genuine underscore has to be preceded by / (I couldn't find a better character, it could be one more underscore or hyphen or whatever). Any single or paired occurrance of this genuine underscore has to be ignored by regex. So far I could come up with this regex: var pattern = @"(?!/)_(.*?)(?!/)_"; But it fails in below input string: _Tom_Katy/_Richard/_/_Stephan_and many users It outputs as <b>Tom</b>Katy/<b>Richard/_/</b>Stephan_and many users Many Thanks in Advance, Pr

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  • 301 Redirects, and the correct regex to go with it

    - by Tisch
    Hi Guys, I have several URLs that I want to redirect to the same place, however these are dynamic URLs. The structure is something like this: http://www.mysite.com/declaration/list?[query_string] What I think would be ideal for this situation is to use some regex in my .htaccess file to redirect all these links to the sites home page. I was wondering if someone could help me with the regex for this situation. So far, I have this, but it doesn't work: RewriteCond %{QUERY_STRING} ^(.*)$ RewriteRule ^/declaration/list$ http://www.mysite.com/$ [R=301,L] My regex is weak to say the least, something I want to, and am trying to learn. Thanks in advance. Tom

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  • What are appropriate ways to represent relationships between people in a database table?

    - by Emilio
    I've got a table of people - an ID primary key and a name. In my application, people can have 0 or more real-world relationships with other people, so Jack might "work for" Jane and Tom might "replace" Tony and Bob might "be an employee of" Rob and Bob might also "be married to" Mary. What's the best way to represent this in the database? A many to many intersect table? A series of self joins? A relationship table with one row per relationship pair and type, where I insert records for the relationship in both directions?

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  • problem with if statement used to determine function return

    - by Patrick
    Im using an if statement to determine what to return in a function, but it seems to be not working the way i want it to. function DoThis($dogs, $cats){ // do something with dogs, pet them perhaps. $reg = $dogs[0]; $nate = $dogs[1]; if($cats = "dave"){return $reg;} if($cats = "tom"){return $nate;} } $cats is a string (if that helps), and when entered it doesn't yield any return. If i manually set a return, that works, but the above doesnt for some reason.

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  • iPhone development time...

    - by Tisch
    I have been asked to develop a relatively simple iPhone application. However, it would be my first application. I am a fairly competent programmer and can turn my skills to a new language fairly quickly... what my question is, is... How long has it taken some of you guys to make your first iPhone application and what was your experience like? Also, if you can say this sort of information, how much did you charge for it?! Thanks in advance. Kindest Regards Tom

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  • All possible values of int from the smallest to the largest, using Java.

    - by Totophil
    Write a program to print out all possible values of int data type from the smallest to the largest, using Java. Some notable solutions as of 8th of May 2009, 10:44 GMT: 1) Daniel Lew was the first to post correctly working code. 2) Kris has provided the simplest solution for the given problem. 3) Tom Hawtin - tackline, came up arguably with the most elegant solution. 4) mmyers pointed out that printing is likely to become a bottleneck and can be improved through buffering. 5) Jay's brute force approach is notable since, besides defying the core point of programming, the resulting source code takes about 128 GB and will blow compiler limits. As a side note I believe that the answers do demonstrate that it could be a good interview question, as long as the emphasis is not on the ability to remember trivia about the data type overflow and its implications (that can be easily spotted during unit testing), or the way of obtaining MAX and MIN limits (can easily be looked up in the documentation) but rather on the analysis of various ways of dealing with the problem.

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  • What's the best way to count unique visitors with Hadoop?

    - by beagleguy
    hey all, just getting started on hadoop and curious what the best way in mapreduce would be to count unique visitors if your logfiles looked like this... DATE siteID action username 05-05-2010 siteA pageview jim 05-05-2010 siteB pageview tom 05-05-2010 siteA pageview jim 05-05-2010 siteB pageview bob 05-05-2010 siteA pageview mike and for each site you wanted to find out the unique visitors for each site? I was thinking the mapper would emit siteID \t username and the reducer would keep a set() of the unique usersnames per key and then emit the length of that set. However that would be potentially storing millions of usernames in memory which doesn't seem right. Anyone have a better way? I'm using python streaming by the way thanks

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  • mySQL one-to-many query

    - by Stomped
    I've got 3 tables that are something like this (simplified here ofc): users user_id user_name info info_id user_id rate contacts contact_id user_id contact_data users has a one-to-one relationship with info, although info doesn't always have a related entry. users has a one-to-many relationship with contacts, although contacts doesn't always have related entries. I know I can grab the proper 'users' + 'info' with a left join, is there a way to get all the data I want at once? For example, one returned record might be: user_id: 5 user_name: tom info_id: 1 rate: 25.00 contact_id: 7 contact_data: 555-1212 contact_id: 8 contact_data: 555-1315 contact_id: 9 contact_data: 555-5511 Is this possible with a single query? Or must I use multiple?

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