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  • $this->url() to another subdomain

    - by Supertino7
    Hello, I created subdomain for my application. host_www.type = "Zend_Controller_Router_Route_Hostname" host_www.route = "www.mywebsite.com" host_www.defaults.module = "produits" host_www.defaults.controller = "produits" host_www.defaults.action = "index" fiche_boutique.route = "ficheboutique/:boutique" fiche_boutique.defaults.controller = "boutique" fiche_boutique.defaults.action = "fiche-boutique" fiche_boutique.defaults.module = "default" fiche_boutique.chain = "host_www" host_produits.type = "Zend_Controller_Router_Route_Hostname" host_produits.route = "produits.mywebsite.com" host_produits.defaults.module = "produits" host_produits.defaults.controller = "produits" host_produits.defaults.action = "index" fiche_produit.type = "Zend_Controller_Router_Route_Regex" fiche_produit.route = "([-\w]+).htm" fiche_produit.reverse = "%s.htm" fiche_produit.map.1 = "q" fiche_produit.defaults.module = "produits" fiche_produit.defaults.controller = "produits" fiche_produit.defaults.action = "voir-produit" fiche_produit.chain = "host" I don't know if the syntax in this zend config ini file is correct, in particular for routes chaining. Once I'm on this subdomain, urls constructed with $this-url() like this : <a href="<?= $this->url(array('boutique' => 1234), 'fiche_boutique', true) ?>"> Visit this store </a> still point to the subdomain produits.mywebsite.com, where I want it to point to www.mywebsite.com For the moment, I do this : <a href="http://www.mywebsite.com<?= $this->url(array('boutique' => 1234), 'fiche_boutique', true) ?>"> Visit this store </a> But it's not flexible at all. Is there a solution, a parameter to add, or my config file is wrong ? thanks in advance for your help.

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  • MODx not display correct image path

    - by Austin
    In the MODx WYSIWYG whenever I click the Image icon to insert an image, followed by browse image it generates the wrong path: /data/12/1/111/99/1111262/user/1169144/htdocs/images/image.jpg instead of assets/images/image.jpg I have checked my Resource URL and Resource Path and they both look correct. Has anyone ever experienced MODx rewriting your paths to the server vs what it should be?

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  • spaces or %20 in links turn into + signs when page is sent as an email

    - by Obay
    I am creating a web app that accepts input of news items (title, article, url). It has a page news.php which creates a summary of all news items inputted for specified dates, like so: News 4/25/2010 Title 1 [URL 1] Article 1 Title 2 [URL 2] Article 2 and so on... I have two other pages, namely preview.php and send.php , both of which call news.php through a file_get_contents() call. Everything works fine except when the URL contains spaces. During Preview, the urls get opened (FF: spaces are spaces, Chrome: spaces are %20). However, during Send, when received as emails, the urls don't get opened, because the spaces are converted into + signs. For example: 1. Preview in FF: http://www.example.com/this is the link.html 2. Preview in Chrome: http://www.example.com/this%20is%20the%20link.html 3. Viewed as email in both browsers: http://www.example.com/this+is+the+link.html Only #3 doesn't work (link doesn't get opened). Why are the spaces in the urls correct (spaces or %20) when previewed, but incorrect (+) when received in the emails, when in fact, the same page is generated by the same news.php? Any help appreciated :)

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  • How to read URDU from url and show it to your mobile using java Me

    - by Basit
    HI, Hope you all will be fine. Actually I m facing a problem. Actually i am using Google translation API. What my application does it connect to CGI-script, i pass value to it using GET then the CGI script connect to Google API, Translate the mesage from english to Urdu and then i retreive it.Here is the code [Java] import java.io.*; import javax.microedition.io.*; import javax.microedition.lcdui.*; import javax.microedition.midlet.*; /** * An example MIDlet to invoke a CGI script (GET method). */ public class InvokeCgiMidlet1 extends MIDlet { private Display display; String url = "http://xxx.xxx.xx.xxx/cgi-bin/api/GT/GT_Send_Msg.cgi?message=my%20name%20is%20basit"; public InvokeCgiMidlet1() { display = Display.getDisplay(this); } /** * Initialization. Invoked when we activate the MIDlet. */ public void startApp() { try { getGrade(url); } catch (IOException e) { System.out.println("IOException " + e); e.printStackTrace(); } } /** * Pause, discontinue .... */ public void pauseApp() { } /** * Destroy must cleanup everything. */ public void destroyApp(boolean unconditional) { } /** * Retrieve a grade.... */ void getGrade(String url) throws IOException { HttpConnection c = null; InputStream is = null; OutputStream os = null; StringBuffer b = new StringBuffer(); TextBox t = null; String response; try { c = (HttpConnection)Connector.open(url, Connector.READ_WRITE); c.setRequestMethod(HttpConnection.GET); c.setRequestProperty("User-Agent","Profile/MIDP-1.0 Confirguration/CLDC-1.0"); c.setRequestProperty("Content-Type","application/x-www-form-urlencoded"); c.setRequestProperty("User-Agent","Profile/MIDP-2.0 Configuration/CLDC-1.1"); c.setRequestProperty("Accept-Charset","UTF-8;q=0.7,*;q=0.7"); c.setRequestProperty("Accept-Encoding","gzip, deflate"); c.setRequestProperty("Accept","text/xml,application/xml,application/xhtml+xml,text/html;q=0.9,text/plain;q=0.8,image/png,*/*;q=0.5"); c.setRequestProperty("Content-Language", "en-EN"); os = c.openOutputStream(); Reader r = new InputStreamReader(c.openDataInputStream(), "UTF-8"); int ch; while ((ch = r.read()) != -1) { b.append((char) ch ); //System.out.println((char)ch + "->" + ch + "->" + ch); } t = new TextBox("Final Grades", b.reverse().toString(), 1024, 0); } finally { if(is!= null) { is.close(); } if(os != null) { os.close(); } if(c != null) { c.close(); } } display.setCurrent(t); } } [/Java] The problem is as i told you that the translated text is in Urdu. So when it appear on screen each character is separate like this. ? ?? ? ? ?? . Because i read character by character I want it to appear in proper form like this ??????? So how can i do this. Is there font rendering required. If yes then how can i do it or any other method please hep me. Thanks

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  • Android fill ImageView from URL

    - by Luke Batley
    Hi i'm trying to add an image to an ImageView from a URL i have tried loading it as a bitmap but nothing is showing. so does anyone know what the best method to do this is or what i'm doing wrong? heres my code @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); //Check Preferences which sets UI setContentView(R.layout.singlenews); TextView headerText = (TextView) findViewById(R.id.header_text); headerText.setText("Latest News"); PostTask posttask; posttask = new PostTask(); posttask.execute(); } public void loadNews(){ newsStr = getIntent().getStringExtra("singleNews"); try { JSONObject obj = new JSONObject(newsStr); content = obj.getString("content"); title = obj.getString("title"); fullName = obj.getString("fullname"); created = obj.getString("created"); NewsImageURL = obj.getString("image_primary"); tagline = obj.getString("tagline"); meta = "posted by: " + fullName + " " + created; URL aURL = new URL("NewsImageURL"); URLConnection conn = aURL.openConnection(); conn.connect(); InputStream is = conn.getInputStream(); /* Buffered is always good for a performance plus. */ BufferedInputStream bis = new BufferedInputStream(is); /* Decode url-data to a bitmap. */ bm = BitmapFactory.decodeStream(bis); bis.close(); is.close(); /* Apply the Bitmap to the ImageView that will be returned. */ Log.v("lc", "content=" + content); Log.v("lc", "title=" + title); Log.v("lc", "fullname=" + fullName); Log.v("lc", "created=" + created); Log.v("lc", "NewsImage=" + NewsImageURL); Log.v("lc", "Meta=" + meta); Log.v("lc", "tagline=" + tagline); } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } public class PostTask extends AsyncTask<Void, String, Boolean> { @Override protected Boolean doInBackground(Void... params) { boolean result = false; loadNews(); publishProgress("progress"); return result; } protected void onProgressUpdate(String... progress) { StringBuilder str = new StringBuilder(); for (int i = 1; i < progress.length; i++) { str.append(progress[i] + " "); } } @Override protected void onPostExecute(Boolean result) { super.onPostExecute(result); Log.v("BGThread", "begin fillin data"); fillData(); } } public void fillData(){ NewsView = LayoutInflater.from(getBaseContext()).inflate(R.layout.newsdetailact, null); TextView Title = (TextView) NewsView.findViewById(R.id.NewsTitle); Title.setText(title); TextView Tagline = (TextView) NewsView.findViewById(R.id.subtitle); Tagline.setText(tagline); TextView MetaData = (TextView) NewsView.findViewById(R.id.meta); MetaData.setText(meta); ImageView NewsImage = (ImageView)NewsView.findViewById(R.id.imageView2); NewsImage.setImageBitmap(bm); TextView MainContent = (TextView) NewsView.findViewById(R.id.maintext); MainContent.setText(content); Log.v("BGThread", "Filled results"); adapter = new MergeAdapter(); adapter.addView(NewsView); setListAdapter(adapter); } }

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  • OAuth Callback procedure for mobile devices

    - by behrk2
    Hello, I am designing a Netflix Application for BlackBerry mobile devices. I am currently working on the OAuth. I am at the point where I can generate a Netflix login page in an embedded browser field in my application. After the user signs in, Netflix will send the user from the login page to a specified callback url. The callback url will also contain an authorized token, which is then needed to send back to Netflix. My question is: How am I supposed to do this on a mobile device? Is there a procedure set in place? I am unsure how I can extract the authorized token from the callback URL and send it back to my application. From my research, it does not appear that Netflix will provide a PIN/verifier for the user to then type into the application... Does anyone have any ideas? Thanks...

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  • What does using RESTful URLs buy me?

    - by Spike Williams
    I've been reading up on REST, and I'm trying to figure out what the advantages to using it are. Specifically, what is the advantage to REST-style URLs that make them worth implementing over a more typical GET request with a query string? Why is this URL: http://www.parts-depot.com/parts/getPart?id=00345 Considered inferior to this? http://www.parts-depot.com/parts/00345 In the above examples (taken from here) the second URL is indeed more elegant looking and concise. But it comes at a cost... the first URL is pretty easy to implement in any web language, out of the box. The second requires additional code and/or server configuration to parse out values, as well as additional documentation and time spent explaining the system to junior programmers and justifying it to peers. So, my question is, aside from the pleasure of having URLs that look cool, what advantages do RESTful URLs gain for me that would make using them worth the cost of implementation?

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  • Mapping Absolute / Relative (Local) Paths to Absolute URLs

    - by Alix Axel
    I need a fast and reliable way to map an absolute or relative local path (say ./images/Mafalda.jpg) to it's corresponding absolute URL, so far I've managed to come up with this: function Path($path) { if (file_exists($path) === true) { return rtrim(str_replace('\\', '/', realpath($path)), '/') . (is_dir($path) ? '/' : ''); } return false; } function URL($path) { $path = Path($path); if ($path !== false) { return str_replace($_SERVER['DOCUMENT_ROOT'], getservbyport($_SERVER['SERVER_PORT'], 'tcp') . '://' . $_SERVER['HTTP_HOST'], $path); } return false; } URL('./images/Mafalda.jpg'); // http://domain.com/images/Mafalda.jpg Seems to be working as expected, but since this is a critical feature to my app I want to ask if anyone can spot any problem that I might have missed and optimizations are also welcome since I'm going to use this function several times per each request.

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  • Regexing it up with IIS re-write module

    - by Michael Jasper
    I am developing a profile-based web application where each user is assigned there own url through their username & iis rewrite mod's magic. A typical user's profile url would be http://www.mymark.com/mike Each user is also created a blog in a multi-user wordpress installation. The wordpress url would look like this: http://www.mymark.com/blog/mike I am trying to use the rewrite module to create more canonical urls for the user (http://www.mymark.com/mike/blog), and have tried several regex variations that I have created through RegExr(a regex generation tool) and come up with this as the pattern to match (www.|)mymark.com/([^/]+)/blog but haven't had any success so far. What am I doing wrong here? Here is a screen shot of my re-write rule:

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  • Stop default hashtag behavior with jquery

    - by scatteredbomb
    I'm using the following code to append a hashtag to the end of a url. That way someone can copy that url and take them back to that page, with certain divs visable. $("a.live").click(function() { window.location.hash = 'live'; $("#live).slideDown(); }); In this example I have a div called 'live', that would slideDown when a link is clicked, and '#live' added to the url. Then I have code that checks the hash tags when the page is loaded to show the proper divs. My problem is, how do I prevent the browser from jumping to the 'live' div once it's called? I don't want the page to scroll down to the div, just want it opened and the hashtag appended so a person could copy it and come back to that page with that div showing. Any tips? Thank you!

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  • spring 3 mvc requestmapping dynamic param problem

    - by Faisal khan
    I have the following code which works fine with http://localhost:8080/HelloWorldSpring3/forms/helloworld but i want to have url have some thing like this http://localhost:8080/HelloWorldSpring3/forms/helloworld/locname_here/locid_here I found that adding this @RequestMapping("/helloworld/**") will work but when i try to access http://localhost:8080/HelloWorldSpring3/forms/helloworld/locname_here/locid_here it is not found. Web.xml entry as follows <servlet-mapping> <servlet-name>dispatcher</servlet-name> <url-pattern>/forms/*</url-pattern> </servlet-mapping> Mapping bean entry @RequestMapping("/helloworld/**") public ModelAndView helloWord(){ String message = "Hello World, Spring 3.0!"; return new ModelAndView("helloworld", "message",message); }

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  • Sending the variable's content to my mailbox in Python?

    - by brilliant
    I have asked this question here about a Python command that fetches a URL of a web page and stores it in a variable. The first thing that I wanted to know then was whether or not the variable in this code contains the HTML code of a web-page: from google.appengine.api import urlfetch url = "http://www.google.com/" result = urlfetch.fetch(url) if result.status_code == 200: doSomethingWithResult(result.content) The answer that I received was "yes", i.e. the variable "result" in the code did contain the HTML code of a web page, and the programmer who was answering said that I needed to "check the Content-Type header and verify that it's either text/html or application/xhtml+xml". I've looked through several Python tutorials, but couldn't find anything about headers. So my question is where is this Content-Type header located and how can I check it? Could I send the content of that variable directly to my mailbox? Here is where I got this code. It's on Google App Engines.

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  • jQuery rewrite href

    - by user317188
    I have an onclick function that I want to add an anchor to the href value. I do not want to change the URL's, because I need the site to still function for people without javascript / for SEO purposes. so here is what I have tried using (amoung other things): jQuery('a[rel=ajax]').click(function () { jQuery(this).attr('href', '/#' + jQuery('a')); }); An orginal link looks like this: http://www.mysite.com/PopularTags/ URL re-write should look like this, so that AJAX will work: http://www.mysite.com/#PopularTags I was able to get some URL's to work by setting a links name value to the same as the href, but it did not work for links with sub-sections: http://www.mysite.com/Artist/BandName/ So not really sure. Thanks for the help.

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  • HTTP status 405 - HTTP method POST is not supported by this URL

    - by Wont Say
    I am getting this "HTTP method POST is not supported by this URL" error when I run my project. The funny thing is, it was running perfectly fine two days ago. After I made a few changes to my code but then restored my original code and its giving me this error. Could you please help me? Here is my index.html: <form method="post" action="login.do"> <div> <table> <tr><td>Username: </td><td><input type="text" name="e_name"/> </td> </tr> <tr><td> Password: </td><td><input type="password" name="e_pass"/> </td> </tr> <tr><td></td><td><input type="submit" name ="e_submit" value="Submit"/> Here is my Login servlet: public class Login extends HttpServlet { /** * Processes requests for both HTTP * <code>GET</code> and * <code>POST</code> methods. * * @param request servlet request * @param response servlet response * @throws ServletException if a servlet-specific error occurs * @throws IOException if an I/O error occurs */ protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException, SQLException { response.setContentType("text/html;charset=UTF-8"); PrintWriter out = response.getWriter(); try { /* * TODO output your page here. You may use following sample code. */ int status; String submit = request.getParameter("e_submit"); String submit2 = request.getParameter("a_submit"); out.println("Here1"); String e_name = request.getParameter("e_name"); String e_password = request.getParameter("e_pass"); String a_name = request.getParameter("a_name"); String a_password = request.getParameter("a_pass"); out.println(e_name+e_password+a_name+a_password); Author author = new Author(a_name,a_password); Editor editor = new Editor(e_name,e_password); // If it is an AUTHOR login: if(submit==null){ status = author.login(author); out.println("Author Login"); //Incorrect login details if(status==0) { out.println("Incorrect"); RequestDispatcher view = request.getRequestDispatcher("index_F.html"); view.forward(request, response); } //Correct login details --- AUTHOR else { out.println("Correct login details"); HttpSession session = request.getSession(); session.setAttribute(a_name, "a_name"); RequestDispatcher view = request.getRequestDispatcher("index_S.jsp"); view.forward(request, response); } } //If it is an EDITOR login else if (submit2==null){ status = editor.login(editor); //Incorrect login details if(status==0) { RequestDispatcher view = request.getRequestDispatcher("index_F.html"); view.forward(request, response); } //Correct login details --- EDITOR else { out.println("correct"); HttpSession session = request.getSession(); session.setAttribute(e_name, "e_name"); session.setAttribute(e_password, "e_pass"); RequestDispatcher view = request.getRequestDispatcher("index_S_1.html"); view.forward(request, response); } } out.println("</body>"); out.println("</html>"); } finally { out.close(); } } @Override protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { super.doPost(req, resp); } @Override protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { super.doGet(req, resp); }} And my web.xml looks like this: <?xml version="1.0" encoding="UTF-8"?> <servlet> <servlet-name>action</servlet-name> <servlet-class>org.apache.struts.action.ActionServlet</servlet-class> <init-param> <param-name>config</param-name> <param-value>/WEB-INF/struts-config.xml</param-value> </init-param> <init-param> <param-name>debug</param-name> <param-value>2</param-value> </init-param> <init-param> <param-name>detail</param-name> <param-value>2</param-value> </init-param> <load-on-startup>2</load-on-startup> </servlet> <servlet> <servlet-name>Login</servlet-name> <servlet-class>controller.Login</servlet-class> </servlet> <servlet-mapping> <servlet-name>action</servlet-name> <url-pattern>*.do</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>Login</servlet-name> <url-pattern>/login.do</url-pattern> </servlet-mapping> <session-config> <session-timeout> 30 </session-timeout> </session-config> <welcome-file-list> <welcome-file>index.html</welcome-file> </welcome-file-list> I use Glassfish v3 server - let me know anything else you need to know

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  • How to add a local image in my firefox entension?

    - by jin
    I am developing a firefox extension and create a table and in it add a image , and I create a image with : var _img = document.createElementNS("http://www.mozilla.org/keymaster/gatekeeper/there.is.only.xul", "xul:image"); and then I found I couldn't set its attribute "src" with a local image just like use its Url: chrome:\...., so I have to locate it in a web url:http:\ , but a problem will arise, when the http:\ couldn't be visted, How to do? if can I set the attribute of a image with a local url? Thank you very much!

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  • JSP 2.0 SEO friendly links encoding

    - by victor hugo
    Currently I have something like this in my JSP <c:url value="/teams/${contact.id}/${contact.name}" /> The important part of my URL is the ID, I just put the name on it for SEO purposes (just like stackoverflow.com does). I was just wondering if there is a quick and clean way to encode the name (change spaces per +, latin chars removal, etc). I'd like it to be like this: <c:url value="/teams/${contact.id}/${supercool(contact.name)}" /> Is there a function like that out there or should I make my own?

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  • UIWebView doesn't load some link

    - by elos
    hello I'm trying to write an rss feed viewer for my iPhone. In my DetailView I have a UIWebView where I want to display specific link retrieved with the rss item.: NSString* url = [data objectForKey:@"link"]; NSString *encodedUrl = [url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding ]; NSLog(@"Selected link:%@",url); NSURLRequest *request = [[NSURLRequest alloc] initWithURL:[NSURL URLWithString:encodedUrl]]; [itemWebpage loadRequest:request]; [request release]; now,if the retrieved link is something like www.shazaam.com it works. But as soon as the link is something like: http://www.shazam.com/music/web/track?id=41970148" it doesn't. I suppose it's because of the parameter...but how can I fix the problem???? thanks a lot! elos

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  • Storing millions of URLs in a database for fast pattern matching

    - by Paras Chopra
    I am developing a web analytics kind of system which needs to log referring URL, landing page URL and search keywords for every visitor on the website. What I want to do with this collected data is to allow end-user to query the data such as "Show me all visitors who came from Bing.com searching for phrase that contains 'red shoes'" or "Show me all visitors who landed on URL that contained 'campaign=twitter_ad'", etc. Because this system will be used on many big websites, the amount of data that needs to log will grow really, really fast. So, my question: a) what would be the best strategy for logging so that scaling the system doesn't become a pain; b) how to use that architecture for rapid querying of arbitrary requests? Is there a special method of storing URLs so that querying them gets faster? In addition to MySQL database that I use, I am exploring (and open to) other alternatives better suited for this task.

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  • Is there a faster way to download a page from the net to a string?

    - by cphil5
    I have tried other methods to download info from a URL, but needed a faster one. I need to download and parse about 250 separate pages, and would like the app to not appear ridiculously slow. This is the code I am currently using to retrieve a single page, any insight would be great. try { URL myURL = new URL("http://www.google.com"); URLConnection ucon = myURL.openConnection(); InputStream inputStream = ucon.getInputStream(); BufferedInputStream bufferedInputStream = new BufferedInputStream(inputStream); ByteArrayBuffer byteArrayBuffer = new ByteArrayBuffer(50); int current = 0; while ((current = bufferedInputStream.read()) != -1) { byteArrayBuffer.append((byte) current); } tempString = new String(byteArrayBuffer.toByteArray()); } catch (Exception e) { Log.i("Error",e.toString()); }

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  • Automatically create valid links

    - by Marcos Placona
    Hi, I'm new to python, so please bare with me :) I was wondering if there's any built-in way in python to append variables to URL's regardless of it's structure. I would like to have a URL variable (test=1) added to an URL which could have any of the following structures http://www.aaa.com (would simply add "/?test=1") to the end http://www.aaa.com/home (like the one above, would simply add "/?test=1") to the end http://www.aaa.com/?location=home (would figure out there's already a ? being used, and would add &test=1 to the end) http://www.aaa.com/?location=home&page=1 (like the one above, would figure out there's already a ? being used, and would add &test=1 to the end) I'd be happy to write domething to do it myself, but if python can already do it somehow, I'd me more than happy to use any built-in functionality that would save me some time ;-) Thanks in advance

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  • How do I identify where the POST data sent to a PHP script came from?

    - by Mike Turley
    I have a ton of data collection forms on my website, and I wrote a PHP script to handle all the data. All the forms have that one script as their action, and POST as the method. The handler emails a copy of the data to me, and I'd like for the emails I get to contain the URL of the form where they originated. Is there any way in PHP to get the url of the form which was submitted to the script? Or do I have to add an extra hidden field in every form with its URL?

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  • Squid site redirection

    - by AndyM
    I have an internal website that cannot be accessed from some machines on my network, due to the physical location, VPN ,network ranges etc. I would like to install Squid on "in between" network to forward request from the clients that cannot reach the website. The issue is the clients have no ability to connect to www.example.com , but they can reach a network with a squid proxy , which in turn can reach www.example.com What is the correct term I need to research in squid , is it just caching www.example.com or do I need to set the clients to use a URL that gets rewritten ? i.e www.squid-example.com -- www.example.com

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  • .htaccess RewriteRule Problem

    - by Kunal Gautam
    Before asking question let me tell you some assumptions here there are 5 files on my webserver index.php config.php read.php write.php .htaccess I've wrote following URL rewriting rule in .htaccess RewriteEngine on RewriteRule ^(\w+)$ read.php?id=$1 Now when I type domain.com/xyz it fetch data from read.php?id=xyz thats nice :) But when I type domain.com/index it fetch data from index.php or when i type domain.com/write or domain.com/config or domain.com/read it fetch data from write.php , config.php and read.php respectively I want data to be fectched from read.php?id=index or read.php?id=config or read.php?id=read or read.php?id=write Any one can help me regarding this ? Sorry for my poor english

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  • Configure IIS to rewrite IP Address to Site Name

    - by Bath Man
    So i've started my first web site from home, and I'm trying to get it up and running and google crawlable and the like, but I can't seem to figure out how to have my site name returned in the address bar instead of my IP address. I've purchased a domain name for my site on Godaddy and then set it to redirect to my site. When you type in the domain name, you get redirected to http://0.0.0.0/default.aspx (not my real IP obviously), and that stays in the user's address bar. In order to fix that temporarily, I've set up masking on Go Daddy which keeps the URL in the address bar, but just shows my website in a frame. This is fine for users visiting the site, however any kind of automated robot such as GoogleBot cannot discover my content because of the frame. I've looked into ISAPI filters and server-site-rewriting, and the like... but I just can't quite figure out how to do what I need it to do. Any simple suggestions or links would be appreciated.

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  • Configure IIS 7 Reverse Proxy to connect to TeamCity Tomcat

    - by Cynicszm
    We have an IIS 7 webserver configured and would like to create a reverse proxy for a TeamCity installation using Tomcat on the same machine. The IIS server site is https://somesite and I would like the TeamCity to appear as https://somesite/teamcity redirecting to http://localhost:portnumber I have installed the IIS URL Rewrite extension from http://www.iis.net/download/URLRewrite and the Application Request Routing from http://www.iis.net/download/ApplicationRequestRouting to try and setup a reverse proxy but can't get it working. The closest answer I found is an old StackOverflow question http://stackoverflow.com/questions/331755/how-do-i-setup-teamcity-for-public-access-over-https which unfortunately doesn't have a working example. I've searched a quite a bit but can't seem to find a relevant example. Any help appreciated (apologies for the bold but the spam prevention won't let me post more than 1 hyperlink)

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