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• Vancouver .NET User Group

  While in Vancouver for my Silverlight training in early May, I will give a free Silverlight presentation at the local .NET User Group, .netBC. When: May 5, 2010, 6:30 PM Where: Building SW3 room 1750, BCIT Burnaby Campus, 3700 Willingdon Ave, Burnaby, BC, V5G 3H2 What: Silverlight 4 Business Applications In this session a live demo will be built to show the new features of Silverlight 4 that helps you create business-oriented applications easier than ever. Importing/exporting data, printing,...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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• RDP suggesting a user name when connecting to a server

  - by Neolisk

  Prior to Event X, RDPing to Server 2003 always caused the user name appear blank and Login to be enabled, so you could pick to which domain you would log in. For us it's either local or our domain. Since a recent Event X a domain + user name is being suggested for every server and it's not the most recently used user name. If you remove it manually from RDP dialog, it's still being pre-populated for you, and then at the next available opportunity it returns into General/User name option of RDP dialog. So user name field comes pre-populated and you cannot change to log in locally (only if you manually erase domain specifier - everything before \) - Log in to option is disabled by default. We did not do any changes to our domain or client machines, so I am suspecting some Windows update caused it (and this being Event X). Interesting fact - it does not consistently happen on all machines, and some can login to some servers fine, while other servers keep suggesting a default user name. What could be that Event X and is there a way to fix it? EDIT: I tried this - How to clear remote desktop connections history and specifically this part of it: reg delete "HKEY_CURRENT_USER\Software\Microsoft\Terminal Server Client\UsernameHint" /f The problem still persists.

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• No user/password boxes on login screen after updates today (June 30, 2012)

  - by Tony

  Just installed today's batch of updates, including new kernel 3.2.0-26 and rebooted. Now the screen just has a logo in the middle and "Ubuntu 12.04 LTS" in bottom left corner, but no box to choose which user to log in as, or to enter a password. CTRL-ALT-F1 gets me to a "login:" prompt, and I can log in - but I have no idea what to look at to find out what is wrong, or to fix this. Tried older kernels and recovery mode for current kernel - no joy, still no way to log into the graphics console.

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• User receives group membership error to terminal server even though has rights

  - by BlueToast

  http://www.hlrse.net/Qwerty/TSLoginMembership.png To log on to this remote computer, you must be granted the Allow log on through Terminal Services right. By default, members of the Remote Desktop Users group have this right. If you are not a member of the Remote Desktop Users group or another group that has this right, or if the Remote Desktop User group does not have this right, you must be granted this right manually. Only as of today a particular user began receiving this message for a second terminal server they use; otherwise, they have never had any problems authenticating into this server. We have no restrictions on simultaneous and multiple logins. On each terminal server, we have a group and security group like "_Users" locally in the Builtin\Remote Desktop Users group. For this particular user, on this particular terminal server we have locally given him Administrator, Remote Desktop Users, and Users membership; in AD we have given him DOMAIN\Administrator, Builtin\Remote Desktop Users, DOMAIN\_Users. It still gives us that error message. We gave him membership to another terminal server (random) by simply making him member of another DOMAIN\_Users group -- successfully able to login to that random terminal server. So, from scratch we created an AD account 'dummy' (username) with only Domain Users membership. Tried to login to this particular server, no success. So I added 'dummy' to DOMAIN\_Users group, and then was successfully able to login. Other users from this user's department are able to login to this particular server just fine as well. We checked the Security logs on this particular server, and while it is logging everything, the only thing it appears to not log are these failed login attempts from this particular user who receives this error message. We have tried rebooting the server, and the user is still receiving that error message.

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• MySQL User Group Meeting in Madrid, Spain

  - by Lenka Kasparova

  We are pleased to announce another MySQL User Group meeting scheduled for June 5 in Madrid, Spain. Keith Hollman, the MySQL Principal Sales Consultant will be talking about MySQL & Oracle strategy and MySQL Cluster. A small demo of MySQL Cluster will be part of the presentation.  Details about the event: Date: June 5, 2014 Time: 7:00 pm-8:30 pm Place: Edificio Telefonica, Gran via 28, Madrid, Entrada por C/ Valverde 2 We are looking forward to seeing you in Madrid! See more information & registration.

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• Oracle Event: Database Enterprise User Security

  - by user12603048

  One of the high-value benefits of an integrated Identity and Access Management platform is the ability to leverage a unified corporate directory as the primary authentication source for database access. On July 11, 2012 at 08:00 am PDT, Oracle will host a webcast showing how Enterprise User Security (EUS) can be used to externalize and centrally manage database users in a directory server. The webcast will briefly introduce EUS, followed by a detailed discussion about the various directory options that are supported, including integration with Microsoft Active Directory. We'll conclude how to avoid common pitfalls deploying EUS with directory services. Discussion topics will include Understanding EUS basics Understanding EUS and directory integration options Avoiding common EUS deployment mistakes Make sure to register and mark this date on your calendar! - Click here to register.

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• Ubuntu user expectations from 12.04 and future releases

  - by Rick Green - Turbo

  How much further ahead is 12.10 vs 12.04 in respect to kernel updates and applications? Example: Gimp's newest release is 2.8 which runs equally as well in both 12.04 and 12.10 and probably will in 13.04. What restricts 12.04 from having "the same" look, feel, applications and kernel as 12.10 or the upcoming 13.04? I know that it's more than a name change.....it's whats under the hood that counts. Incrementally upgrading, I feel is safer than radical changes from release to release. Trying to keep a stable desktop and current user experience, how far can I take updating applications before I absolutely have to make a distro upgrade from 12.04LTS

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• Calling Knowledge Workers: Make a Difference in the User Experience

  - by Charles Knapp

  Do you consider yourself a knowledge worker? Do you have ideas of how to make CRM software work smarter so you don't have to work harder? The Oracle Middleware User Experience team will be conducting customer feedback focus groups at Oracle OpenWorld, October 1-3. All it takes is a couple of hours or less for us to learn from you. Customer participation helps Oracle develop outstanding products and solutions. Knowledge workers of all types are invited to participate: Finance, Sales, Human Resources, Marketing, Recruiters, Budget Managers, Project & Product Managers and more. To participate in these sessions you do not have to be registered for Oracle OpenWorld. If you or someone you know is interested in participating, please email muxtesting_us at oracle.com with your name, company, job title, work and mobile phone numbers with country code, and email address.

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• disable password prompt on user switch?

  - by matthewn

  I've got 11.10 on a desktop machine with two users. Both users have "Password" set to "Not asked on login" in Users Settings. At startup, either user can log in without a password. But once both users are logged in, it takes a password to switch between users. In previous Ubuntus, you could override this by setting /desktop/gnome/lockdown/disable_lock_screen to True in gconf-editor. That is ignored in the Gnome 3 / Unity era. Does anyone know a way to disable the password prompt when switching between users in Oneiric?

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• Restrict user to folder (not root) on VSFTPD in Ubuntu

  - by omega1

  I am a new Linux (Ubuntu) user and have a VPS where I am setting up a backup FTP service. I have followed this guide, which I have managed to do correctly and it works. I have two users (user1 and user2) with the same directory /home/users/test. user1 can read/write and user2 can only read. This works OK. When the users log in, they go straight into the correct directory /home/users/test, but they can navigate back down to the home directory, which I do not want to happen. I cannot seem to find out how to not allow this, and have them not be able to navigate back to the /home/ or /home/test/ directories.

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• Twin Cities Connected Systems User Group Meeting - March 11th, 2010

  If you are in are in Minneapolis on Thursday March 11th please join us for the Twin Cities Connected Systems User Group Meeting. The meeting takes place at 6:00 p.m. at the Microsoft offices at 8300 Norman Center Drive, Bloomington, MN 55437.  I will be speaking on How to Create Windows Server AppFabric Applications Here is a write-up of what will be covered: You have heard about Dublin, now called Windows Server AppFabric, but do you know what it is and what it includes?  Do you know...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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• TGT validation fails, but only for one user

  - by wzzrd

  I'm seeing the weirdest thing here. I have a couple of RHEL3, 4 and 5 machines that validate user credentials through Kerberos with an Active Directoy domain controller as their KDC. This works for all of my users, save one. There is one account that is unable to log into RHEL3 Linux machines and generates the following errors there: May 31 13:53:19 mybox sshd(pam_unix)[7186]: authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=10.0.0.1 user=user May 31 13:53:20 mybox sshd[7186]: pam_krb5: TGT verification failed for `user' May 31 13:53:20 mybox sshd[7186]: pam_krb5: authentication fails for `user' Other accounts, like my own, are fine: May 31 17:25:30 mybox sshd(pam_unix)[12913]: authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=10.0.0.1 user=myuser May 31 17:25:31 mybox sshd[12913]: pam_krb5: TGT for myuser successfully verified May 31 17:25:31 mybox sshd[12913]: pam_krb5: authentication succeeds for `myuser' May 31 17:25:31 mybox sshd(pam_unix)[12915]: session opened for user myuser by (uid=0) As you can see, TGT validation fails. This only happens for this specific account, not for any other. The failing useraccount's password has been reset, I inspected both user objects in Active Directory, but I see nothing out of the ordinary. If I have the failing useraccount log into a RHEL4 or 5 box, there is not problem, so it must be RHEL3 specific, but the fact that only one account suffers from this, alludes me. Maybe someone has seen this before?

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• Completing a Basic ASP.NET 3.5 User Input Validation Project

  You learned the basics and configuration steps of the most common types of validation web controls used in ASP.NET 3.5 in the first two parts of this tutorial series. In this last part you will learn how to integrate all of these validation web controls in a working ASP.NET project. You will also learn not only how to validate user input in the client side but also how to validate the page on the server side.... Microsoft SQL Server? Value Calculator Reduce Costs & Increase Value with Microsoft SQL Server? 2008. Download Today!

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• API to UPDATE Oracle FND User

  - by PRajkumar

  API - fnd_user_pkg.updateuser Example -- Consider a FND User having following Details --     Lets Try to Update its Email Id from [email protected] to [email protected]   -- ------------------------------------------------ -- API to UPDATE Oracle FND User -- ------------------------------------------------ DECLARE     lc_user_name                           VARCHAR2(100)   := 'PRAJ_TEST';     lc_user_password                   VARCHAR2(100)   := 'Oracle123';     ld_user_start_date                   DATE                      := TO_DATE('23-JUN-2012');     ld_user_end_date                    VARCHAR2(100)  := NULL;     ld_password_date                   VARCHAR2(100)  := TO_DATE('23-JUN-2012');     ld_password_lifespan_days  NUMBER               := 90;     ln_person_id                            NUMBER                := 32979;     lc_email_address                     VARCHAR2(100)  := '[email protected]'; BEGIN    fnd_user_pkg.updateuser    (  x_user_name                           => lc_user_name,       x_owner                                   => NULL,       x_unencrypted_password    => lc_user_password,       x_start_date                             => ld_user_start_date,       x_end_date                              => ld_user_end_date,       x_password_date                   => ld_password_date,       x_password_lifespan_days  => ld_password_lifespan_days,       x_employee_id                       => ln_person_id,       x_email_address                    => lc_email_address    );  COMMIT; EXCEPTION     WHEN OTHERS THEN                       ROLLBACK;                       DBMS_OUTPUT.PUT_LINE(SQLERRM); END; / SHOW ERR;       

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• User input and automated input separation

  - by tpaksu

  I have a MySQL database and an automation script which modifies the data inside once a day. And these columns may have changed by an user manually. What is the best approach to make the system only update the automated data, not the manually edited ones? I mean yes, flagging the cell which is manually edited is one way to do it, but I want to know if there's another way to accomplish this? Just curiosity. BTW, the question is about cell values, not rows.

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• How can I limit other (administrator) users access to my profile?

  - by kojo

  Hi, We in our club have a computer with Windows 7 Professional that every club member may use. And everyone has their own separate account. Those accounts have to have administrator priveleges since I want everyone to be able to install any software and use any feature they want. However, there is a single thing that they shouldn't be allowed to do - that is, look into another users' profiles. Now when anyone goes to 'c:\Users(Any User Name)' a little prompt appears that this folder is secured and whether you really want to look inside. Simply clickinh 'ok' give you access to any profile. I tried disabling taking ownership for Administrators group in Group Policies but that had no effect. How can I effectively prohibit administrators looking into each others' profiles and documents?

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• User Password I didn't even know of [duplicate]

  - by KiriharaAkaya

  This question already has an answer here: How do I reset a lost administrative password? 13 answers I'm a new user of Ubuntu and I installed it on my computer using Virtual Box. I've been trying to install Java JDK for the past two hours without any success because when I try to do so, Terminal asks for my password, which I don't even remember creating. Can someone please help and tell me how am I suppose to change the password in order to install JDK? It will be very much appreciated, thank you.

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• LINQ-to-SQL: Could not find key member 'x' of key 'x' on type 'y'

  - by Austin Hyde

  I am trying to connect my application to a SQLite database with LINQ-to-SQL, and so far everything has worked fine. The only hitch was that the SQLite provider I am using does not support code generation (unless I was doing something wrong), so I manually coded the 4 tables in the DB. The solution builds properly, but will not run, giving me the error message Could not find key member 'ItemType_Id' of key 'ItemType_Id' on type 'Item'. The key may be wrong or the field or property on 'Item' has changed names. I have checked and double checked spellings and field names on the database and in the attribute mappings, but could not find any problems. The SQL for the table looks like this: CREATE TABLE [Items] ( [Id] integer PRIMARY KEY AUTOINCREMENT NOT NULL, [Name] text NOT NULL, [ItemType_Id] integer NOT NULL ); And my mapping code: [Table(Name="Items")] class Item { // [snip] [Column(Name = "Id", IsPrimaryKey=true, IsDbGenerated=true)] public int Id { get; set; } // [snip] [Column(Name="ItemType_Id")] public int ItemTypeId { get; set; } [Association(Storage = "_itemType", ThisKey = "ItemType_Id")] public ItemType ItemType { get { return _itemType.Entity; } set { _itemType.Entity = value; } } private EntityRef<ItemType> _itemType; // [snip] } This is really my first excursion into LINQ-to-SQL, and am learning as I go, but I cannot seem to get past this seeming simple problem. Why cannot LINQ see my association?

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• Javascript "Member not found" error in IE8

  - by Steven

  I'm trying to debug the following block of Javascript code to see what the issue is. I'm getting an error that says "Member not found" on the line constructor = function() { in the extend:function() method. I'm not very good with Javascript, and I didn't write this, so I'm kind of lost on what the issue is. The error only occurs in IE8, it works fine in IE7 and Firefox. var Class = { create: function() { return function() { if(this.destroy) Class.registerForDestruction(this); if(this.initialize) this.initialize.apply(this, arguments); } }, extend: function(baseClassName) { constructor = function() { var i; this[baseClassName] = {} for(i in window[baseClassName].prototype) { if(!this[i]) this[i] = window[baseClassName].prototype[i]; if(typeof window[baseClassName].prototype[i] == 'function') { this[baseClassName][i] = window[baseClassName].prototype[i].bind(this); } } if(window[baseClassName].getInheritedStuff) { window[baseClassName].getInheritedStuff.apply(this); } if(this.destroy) Class.registerForDestruction(this); if(this.initialize) this.initialize.apply(this, arguments); } constructor.getInheritedStuff = function() { this[baseClassName] = {} for(i in window[baseClassName].prototype) { if(!this[i]) this[i] = window[baseClassName].prototype[i]; if(typeof window[baseClassName].prototype[i] == 'function') { this[baseClassName][i] = window[baseClassName].prototype[i].bind(this); } } if(window[baseClassName].getInheritedStuff) { window[baseClassName].getInheritedStuff.apply(this); } } return constructor; }, objectsToDestroy : [], registerForDestruction: function(obj) { if(!Class.addedDestructionLoader) { Event.observe(window, 'unload', Class.destroyAllObjects); Class.addedDestructionLoader = true; } Class.objectsToDestroy.push(obj); }, destroyAllObjects: function() { var i,item; for(i=0;item=Class.objectsToDestroy[i];i++) { if(item.destroy) item.destroy(); } Class.objectsToDestroy = null; } }

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• Why does setting this member in C fail?

  - by Lee Crabtree

  I'm writing a Python wrapper for a C++ library, and I'm getting a really weird when trying to set a struct's field in C. If I have a struct like this: struct Thing { PyOBJECT_HEAD unsigned int val; }; And have two functions like this: static PyObject* Thing_GetBit(Thing* self, PyObject* args) { unsigned int mask; if(!PyArg_ParseTuple(args, "I", &mask) Py_RETURN_FALSE; if((self->val & mask) != 0) Py_RETURN_TRUE; Py_RETURN_FALSE; } static PyObject* Thing_SetBit(Thing* self, PyObject* args) { unsigned int mask; bool on; if(!PyArg_ParseTuple(args, "Ii", &mask, &on)) Py_RETURN_FALSE; if(on) thing->val |= mask; else thing->val &= ~mask; Py_RETURN_TRUE; } Python code that calls the first method works just fine, giving back the value of the struct member. Calls to the SetBit method give an error about an object at address foo accessing memory at address bar, which couldn't be "written". I've poked around the code, and it's like I can look at the value all I want, both from C and Python, but the instant I try to set it, it blows up in my face. Am I missing something fundamental here?

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• error C3662: override specifier 'new' only allowed on member functions of managed classes

  - by William

  Okay, so I'm trying to override a function in a parent class, and getting some errors. here's a test case #include <iostream> using namespace std; class A{ public: int aba; void printAba(); }; class B: public A{ public: void printAba() new; }; void A::printAba(){ cout << "aba1" << endl; } void B::printAba() new{ cout << "aba2" << endl; } int main(){ A a = B(); a.printAba(); return 0; } And here's the errors I'm getting: Error 1 error C3662: 'B::printAba' : override specifier 'new' only allowed on member functions of managed classes c:\users\test\test\test.cpp 12 test Error 2 error C2723: 'B::printAba' : 'new' storage-class specifier illegal on function definition c:\users\test\test\test.cpp 19 test How the heck do I do this?

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• Embedding Lua functions as member variables in Java

  - by Zarion

  Although the program I'm working on is in Java, answering this from a C perspective is also fine, considering that most of this is either language-agnostic, or happens on the Lua side of things. In the outline I have for the architecture of a game I'm programming, individual types of game objects within a particular class (eg: creatures, items, spells, etc.) are loaded from a data file. Most of their properties are simple data types, but I'd like a few of these members to actually contain simple scripts that define, for example, what an item does when it's used. The scripts will be extremely simple, since all fundamental game actions will be exposed through an API from Java. The Lua is simply responsible for stringing a couple of these basic functions together, and setting arguments. The question is largely about the best way to store a reference to a specific Lua function as a member of a Java class. I understand that if I store the Lua code as a string and call lua_dostring, Lua will compile the code fresh every time it's called. So the function needs to be defined somehow, and a reference to this specific function wrapped in a Java function object. One possibility that I've considered is, during the data loading process, when the loader encounters a script definition in a data file, it extracts this string, decorates the function name using the associated object's unique ID, calls lua_dostring on the string containing a full function definition, and then wraps the generated function name in a Java function object. A function declared in script run with lua_dostring should still be added to the global function table, correct? I'm just wondering if there's a better way of going about this. I admit that my knowledge of Lua at this point is rather superficial and theoretical, so it's possible that I'm overlooking something obvious.

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• convincing C# compiler that execution will stop after a member returns

  - by Sarah Vessels

  I don't think this is currently possible or if it's even a good idea, but it's something I was thinking about just now. I use MSTest for unit testing my C# project. In one of my tests, I do the following: MyClass instance; try { instance = getValue(); } catch (MyException ex) { Assert.Fail("Caught MyException"); } instance.doStuff(); // Use of unassigned local variable 'instance' To make this code compile, I have to assign a value to instance either at its declaration or in the catch block. However, Assert.Fail will never, to the best of my knowledge, allow execution to proceed past it, hence instance will never be used without a value. Why is it then that I must assign a value to it? If I change the Assert.Fail to something like throw ex, the code compiles fine, I assume because it knows that exception will disallow execution to proceed to a point where instance would be used uninitialized. So is it a case of runtime versus compile-time knowledge about where execution will be allowed to proceed? Would it ever be reasonable for C# to have some way of saying that a member, in this case Assert.Fail, will never allow execution after it returns? Maybe that could be in the form of a method attribute. Would this be useful or an unnecessary complexity for the compiler?

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• Call to a member function num_rows() on a non-object

  - by Patrick

  I need to get the number of rows of a query (so I can paginate results). As I'm learning codeigniter (and OO php) I wanted to try and chain a -num_rows() to the query, but it doesn't work: //this works: $data['count'] = count($this->events->findEvents($data['date'], $data['keyword'])); //the following doesn't work and generates // Fatal Error: Call to a member function num_rows() on a non-object $data['count2'] = $this->events->findEvents($data['date'], $data['keyword'])->num_rows(); the model returns an array of objects, and I think this is the reason why I can't use a method on it. function findEvents($date, $keyword, $limit = NULL, $offset = NULL) { $data = array(); $this->db->select('events.*, venues.*, events.venue AS venue_id'); $this->db->join('venues', 'events.venue = venues.id'); if ($date) { $this->db->where('date', $date); } if ($keyword) { $this->db->like('events.description', $keyword); $this->db->or_like('venues.description', $keyword); $this->db->or_like('band', $keyword); $this->db->or_like('venues.venue', $keyword); $this->db->or_like('genre', $keyword); } $this->db->order_by('date', 'DESC'); $this->db->order_by('events.priority', 'DESC'); $this->db->limit($limit, $offset); //for pagination purposes $Q = $this->db->get('events'); if ($Q->num_rows() > 0) { foreach ($Q->result() as $row) { $data[] = $row; } } $Q->free_result(); return $data; } Is there anything that i can do to be able to use it? EG, instead of $data[] = $row; I should use another (OO) syntax?

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• g++ linker can't find const member function

  - by Max

  I have a Point class (with integer members x and y) that has a member function withinBounds that is declared like so: bool withinBounds(const Point&, const Point&) const; and defined like this: bool Point::withinBounds(const Point& TL, const Point& BR) const { if(x < TL.getX()) return false; if(x > BR.getX()) return false; if(y < TL.getY()) return false; if(y > BR.getY()) return false; // Success return true; } and then in another file, I call withinBounds like this: Point pos = currentPlayer->getPosition(); if(pos.withinBounds(topleft, bottomright)) { // code block } This compiles fine, but it fails to link. g++ gives me this error: /home/max/Desktop/Development/YARL/yarl/src/GameData.cpp:61: undefined reference to 'yarl::utility::Point::withinBounds(yarl::utility::Point const&, yarl::utility::Point const&)' When I make the function not const, it links fine. Anyone know the reason why? The linker error looks like it's looking for a non-const version of the function, but I don't know why it would.

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