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  • mysql search using for loop from php.

    - by deb
    hi, i am a beginner. but I'm practicing a lot for few days with php mysql, and I am trying to use for loop to search an exploded string, one by one from mysql server. Till now I have no results. I'm giving my codes, <?php // Example 1 $var = @$_GET['s'] ; $limit=500; echo " "; echo "$var"; echo " "; $trimmed_array = explode(" ", $var); echo "$trimmed_array[0]"; // piece1 echo " "; $count= count($trimmed_array); echo $count; for($j=0;$j<$count;$j++) { e cho "$trimmed_array[$j]";; echo " "; } echo " "; for($i=0; $i<$count ; $i++){ $query = "select * from book where name like \"%$trimmed_array[$i]%\" order by name"; $numresults=mysql_query($query); $numrows =mysql_num_rows($numresults); if ($numrows == 0) { echo "<h4>Results</h4>"; echo "<p>Sorry, your search: &quot;" . $trimmed_array[i] . "&quot; returned zero results</p>"; } if (empty($s)) { $s=0; } $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); echo "<p>You searched for: &quot;" . $var . "&quot;</p>"; echo "Results<br /><br />"; $count=1; while ($row= mysql_fetch_array($result)) { $name = $row["name"]; $publisher=$row["publisher"]; $total=$row["total"]; $issued=$row["issued"]; $available=$row["available"]; $category=$row["category"]; echo "<table border='1'><tr><td>$count)</td><td>$name&nbsp;</td><td>$publisher&nbsp;</td><td>$total&nbsp;</td><td>$issued&nbsp;</td><td>$available&nbsp;</td><td>$category&nbsp;</td></tr></table>" ; $count++ ; } } ?>

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  • Print a HTML page in landscape mode?

    - by yoz1k
    Is it possible to print a simple page in landscape mode? (without the need for the user to go to printer settings?) <!DOCTYPE html> <html> <head> <title></title> <meta http-equiv="Content-Type" content="text/html;charset=utf-8" /> <style type="text/css" media="print"/> @page { size: landscape; margin: 2cm; } body { color: red; } </style> <style type="text/css" media="all" > body { font-size: 10pt; font-family: Arial; } table td { padding: 2em; } </style> </head> <body> <table> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> </table> </body> </html> the solution @page size: landscape didn't help. any ideas?

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  • How can I add a column to this union result?

    - by MrXexxed
    I have this query (which I removed some keys from for brevity's sake): SELECT id as in_id, out_id, recipient, sender, read_flag FROM received WHERE recipient=1 UNION ALL SELECT in_id, id AS out_id, recipient, sender, read_flag FROM sent WHERE sender=1 Which combines the results from two tables showing messages sent and received by a given user. What I'd like to do is add a column/flag to the result to distinguish which table the row belongs to so when I display them I can show a relevant icon for sent or received messages. How would I add this?

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  • what does this ADO OPEN Method do?

    - by every_answer_gets_a_point
    in plain english can you explain to me what happens here: rs.Open "batchinfo", oConn, adOpenKeyset, adLockOptimistic, adCmdTable what i need to do is to be able to insert values into a table called batchinfo. would this be the best way to do an OPEN? the only thing i would be doing is inserting values.

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  • MySQL greatest value in row?

    - by noryb009
    Hi! I'm using MySQL with PHP. This is like my table: (I'm using 3 values, but there are more) id | 1 | 2 | 3 1 | 3 |12 |-29 2 | 5 |8 |8 3 | 99|7 |NULL I need to get the greatest value in a certain row. If should get: (id - output) (1 - 2), (2-2), (3-1). Is there any queries for this? I've been trying, but I can't get it to work right.

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  • what math do i need to convert this number

    - by Uberfuzzy
    given an X, what math is needed to find its Y, using this table? x->y 0->1 1->0 2->6 3->5 4->4 5->3 6->2 language agnostic problem and no, i dont/cant just store the array, and do the lookup. yes, the input will always be the finite set of 0 to 6. it wont be scaling later.

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  • Concatenate multi value into one record.

    - by mikehjun
    I joined two tables together and what I like to do is concatenate multi vaule in one records without duplicated value. TAXLOT_ZONE TID ZONE 1 A 1 A 1 B 1 C 2 D 2 D 2 E 3 A 3 B 4 C 5 D Desirable Final table looks like; TID ZONE 1 A, B, C 2 D, E 3 A, B 4 C 5 D

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  • finding if an anniversary is coming up in n days in MySql

    - by user151841
    I have a table with anniversary dates. I want a query that returns me rows of anniversaries coming up in the next 10 days. For instance: birthdate --------- 1965-10-10 1982-05-25 SELECT birthdate FROM Anniversaries WHERE mystical_magical_mumbo_jumbo <= 10 +------------+ | birthdate | +------------+ | 1982-05-25 | +------------+ 1 row in set (0.01 sec) I'd like to keep the query in the form x <= 10, because I'll use that number 10 in other parts of the query, and if I set it to a variable, I can change it once everywhere by changing the variable, and not have to re-write the query.

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  • How to show a UINavigationController with an UIButton on the Iphone?

    - by Claudio
    Hi, in my application the first view is an UIView with a couple of uilabel and an uibutton to do the login. I would to show an uinavigationcontroller with a table after the login, so with the action of the button. I know how to set up a working Navigation Controller starting with the Xcode Template but i dont know how to load this as a "Second View" Any help?

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  • MySQL using function IN with variable

    - by misanov
    I have problem querying table with variable in IN function. SELECT s.date, (SELECT GROUP_CONCAT(value) FROM value WHERE id_value IN(s.ref_values) ) AS vals FROM stats s ORDER BY s.date DESC LIMIT 1 Where s.ref_values is '12,22,54,15'. I get only one return for first number (12). When I insert that value directly in IN(12,22,54,15) it finds all 4. So, there must be problem with using variable in IN. What am I doing wrong?

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  • How to remove duplicate entries from a mysql db?

    - by Yegor
    I have a table with some ids + titles. I want to make the title column unique, but it has over 600k records already, some of which are duplicates (sometimes several dozen times over). How do I remove all duplicates, except one, so I can add a UNIQUE key to the title column after?

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  • Summarize Data with SQL statement

    - by bugbug
    I have CMS table that contain CMS_STARTTIME and CMS_STOPTIME (attachment). I want to create report to summarize exist data by using Date, Time and Year as Parameter (attachment). I don't know how to create sql statement to meet this requirement. I'm using MySQL and MS-SQL. Does one can help? Thank you very much.

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  • Generate Delete Statement From Foreign Key Relationships in SQL 2008 ?

    - by Element
    Is it possible via script/tool to generate a delete statement based on the tables fk relations. i.e. I have the table: DelMe(ID) and there are 30 tables with fk references to its ID that I need to delete first, is there some tool/script that I can run that will generate the 30 delete statements based on the FK relations for me ? (btw I know about cascade delete on the relations, I can't use it in this existing db) I'm using Microsoft SQL Server 2008

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  • least value in count

    - by Nyfer
    i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute. Show all the employee who were hired on the day of the week on which least no of employee were hired. i have done the query, but am not able to get the least. please check if am correct. select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count from test.employee group by days

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  • How to append an integer to a const char value in iphone?

    - by Warrior
    I have sql query statement which used to display the contents in the table.The sql statement consist of a where clause which is to be appended with numeric value as 1 ,2 3 etc depends upon the previously selected content.I am having the numeric value as int and i want it to append to sql statement which is const char.how can i append both the values.Please help me out. My query is == select * from Book where id=1; i have the id value is integer Thanks.

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  • Many to many in linq with vb.net

    - by user512623
    I have 3 tables in a database: image of the database I have been looking online for a long time trying to find out how in linq and vb.net how i can do a query that has access to both the event and individual table for example showing all the events individual 1 is taking part in ect. i was wondering if anyone could point me in the right direction or know of any good tutorial sites with good examples of things similar. Thanks in advance :) Luke.

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