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  • what does this ADO OPEN Method do?

    - by every_answer_gets_a_point
    in plain english can you explain to me what happens here: rs.Open "batchinfo", oConn, adOpenKeyset, adLockOptimistic, adCmdTable what i need to do is to be able to insert values into a table called batchinfo. would this be the best way to do an OPEN? the only thing i would be doing is inserting values.

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  • How to show a UINavigationController with an UIButton on the Iphone?

    - by Claudio
    Hi, in my application the first view is an UIView with a couple of uilabel and an uibutton to do the login. I would to show an uinavigationcontroller with a table after the login, so with the action of the button. I know how to set up a working Navigation Controller starting with the Xcode Template but i dont know how to load this as a "Second View" Any help?

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  • How can I add a column to this union result?

    - by MrXexxed
    I have this query (which I removed some keys from for brevity's sake): SELECT id as in_id, out_id, recipient, sender, read_flag FROM received WHERE recipient=1 UNION ALL SELECT in_id, id AS out_id, recipient, sender, read_flag FROM sent WHERE sender=1 Which combines the results from two tables showing messages sent and received by a given user. What I'd like to do is add a column/flag to the result to distinguish which table the row belongs to so when I display them I can show a relevant icon for sent or received messages. How would I add this?

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  • MySQL using function IN with variable

    - by misanov
    I have problem querying table with variable in IN function. SELECT s.date, (SELECT GROUP_CONCAT(value) FROM value WHERE id_value IN(s.ref_values) ) AS vals FROM stats s ORDER BY s.date DESC LIMIT 1 Where s.ref_values is '12,22,54,15'. I get only one return for first number (12). When I insert that value directly in IN(12,22,54,15) it finds all 4. So, there must be problem with using variable in IN. What am I doing wrong?

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  • Print a HTML page in landscape mode?

    - by yoz1k
    Is it possible to print a simple page in landscape mode? (without the need for the user to go to printer settings?) <!DOCTYPE html> <html> <head> <title></title> <meta http-equiv="Content-Type" content="text/html;charset=utf-8" /> <style type="text/css" media="print"/> @page { size: landscape; margin: 2cm; } body { color: red; } </style> <style type="text/css" media="all" > body { font-size: 10pt; font-family: Arial; } table td { padding: 2em; } </style> </head> <body> <table> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> <tr> <td>a</td><td>b</td><td>c</td><td>d</td><td>e</td><td>f</td><td>g</td><td>h</td><td>i</td><td>j</td><td>k</td><td>l</td><td>m</td><td>n</td><td>o</td><td>p</td><td>q</td><td>r</td><td>s</td><td>t</td><td>u</td><td>v</td><td>w</td><td>x</td><td>y</td><td>z</td> </tr> </table> </body> </html> the solution @page size: landscape didn't help. any ideas?

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  • Concatenate multi value into one record.

    - by mikehjun
    I joined two tables together and what I like to do is concatenate multi vaule in one records without duplicated value. TAXLOT_ZONE TID ZONE 1 A 1 A 1 B 1 C 2 D 2 D 2 E 3 A 3 B 4 C 5 D Desirable Final table looks like; TID ZONE 1 A, B, C 2 D, E 3 A, B 4 C 5 D

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  • How to remove duplicate entries from a mysql db?

    - by Yegor
    I have a table with some ids + titles. I want to make the title column unique, but it has over 600k records already, some of which are duplicates (sometimes several dozen times over). How do I remove all duplicates, except one, so I can add a UNIQUE key to the title column after?

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  • finding if an anniversary is coming up in n days in MySql

    - by user151841
    I have a table with anniversary dates. I want a query that returns me rows of anniversaries coming up in the next 10 days. For instance: birthdate --------- 1965-10-10 1982-05-25 SELECT birthdate FROM Anniversaries WHERE mystical_magical_mumbo_jumbo <= 10 +------------+ | birthdate | +------------+ | 1982-05-25 | +------------+ 1 row in set (0.01 sec) I'd like to keep the query in the form x <= 10, because I'll use that number 10 in other parts of the query, and if I set it to a variable, I can change it once everywhere by changing the variable, and not have to re-write the query.

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  • what math do i need to convert this number

    - by Uberfuzzy
    given an X, what math is needed to find its Y, using this table? x->y 0->1 1->0 2->6 3->5 4->4 5->3 6->2 language agnostic problem and no, i dont/cant just store the array, and do the lookup. yes, the input will always be the finite set of 0 to 6. it wont be scaling later.

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  • least value in count

    - by Nyfer
    i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute. Show all the employee who were hired on the day of the week on which least no of employee were hired. i have done the query, but am not able to get the least. please check if am correct. select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count from test.employee group by days

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  • Summarize Data with SQL statement

    - by bugbug
    I have CMS table that contain CMS_STARTTIME and CMS_STOPTIME (attachment). I want to create report to summarize exist data by using Date, Time and Year as Parameter (attachment). I don't know how to create sql statement to meet this requirement. I'm using MySQL and MS-SQL. Does one can help? Thank you very much.

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  • Generate Delete Statement From Foreign Key Relationships in SQL 2008 ?

    - by Element
    Is it possible via script/tool to generate a delete statement based on the tables fk relations. i.e. I have the table: DelMe(ID) and there are 30 tables with fk references to its ID that I need to delete first, is there some tool/script that I can run that will generate the 30 delete statements based on the FK relations for me ? (btw I know about cascade delete on the relations, I can't use it in this existing db) I'm using Microsoft SQL Server 2008

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  • How to append an integer to a const char value in iphone?

    - by Warrior
    I have sql query statement which used to display the contents in the table.The sql statement consist of a where clause which is to be appended with numeric value as 1 ,2 3 etc depends upon the previously selected content.I am having the numeric value as int and i want it to append to sql statement which is const char.how can i append both the values.Please help me out. My query is == select * from Book where id=1; i have the id value is integer Thanks.

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  • Complex SELECT statement; one-to-many all details in one row

    - by RubyWedge
    There are two tables: Products ID (Primary Key), ProductName PlannedByMonths ProductID (Primary Key) (Link to the Products table many-to-one), MonthNumber (Primary Key), QtytoProduce, How to write SELECT statement to retrieve results in the following format? ProductName, QtytoProduceMonth1, QtytoProduceMonth2, QtytoProduceMonth3, QtytoProduceMonth4, QtytoProduceMonth5, QtytoProduceMonth6, QtytoProduceMonth7, QtytoProduceMonth8, QtytoProduceMonth9, QtytoProduceMonth10, QtytoProduceMonth11, QtytoProduceMonth12 Thank you.

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