Search Results

Search found 32007 results on 1281 pages for 'php openid'.

Page 759/1281 | < Previous Page | 755 756 757 758 759 760 761 762 763 764 765 766  | Next Page >

  • counting number of new entries in guest book

    - by Lucka
    I want to display the number of new(unseen) guest entries in the guest book of a user. I was thinking to count it so that, total number of entries in guestbook minus entries in guestbook at time of last login. However, I think that is not a good approach, because if the user logs in but does not go to his guestbook, in that case, the entries should be still "new", also if some new entry is posted in the user while he is online, it does not work in that case too. Any suggested please?

    Read the article

  • While loop problems

    - by Luke
    I have put together the following code, the problem is that each while loop is only returning one set of data. $result = mysql_query("SELECT date FROM ".TBL_FIXTURES." WHERE compname = '$comp_name' GROUP BY date"); $i = 1; echo "<table cellspacing=\"10\" style='border: 1px dotted' width=\"300\" bgcolor=\"#eeeeee\">"; while ($row = mysql_fetch_assoc($result)) { $date=date("F j Y", $row['date']); echo $date; echo " <tr> <td>Fixture $i - Deadline on $date</td> </tr> "; $result = mysql_query("SELECT * FROM ".TBL_FIXTURES." WHERE compname = '$comp_name' AND date = '$row[date]' ORDER BY date"); while ($row = mysql_fetch_assoc($result)) { extract ($row); echo " <tr> <td>$home_user - $home_team V $away_user - $away_team</td> </tr> "; } $i++; } echo "</table>"; I should get many dates, and then each set of fixture below. At the moment, the first row from the first while loop is present, along with the data from the second while loop. However, it doesn't continue? Any ideas where I can correct this? Thanks

    Read the article

  • Using a Time Zone Conversion When Dynamically Generating Results

    - by John
    Hello, If I understand correctly, the code below converts $row["datesubmitted"] from one timezone to another. I would like to print the converted $row["datesubmitted"] dynamically in an HTML table. Is there a way that I can apply the conversion below for each row that is pulled from MySQL? I assume that I can't just plug $row["dt"] into the code since there is no field called "dt" in the MySQL that I am using. Thanks in advance, John $dt = new DateTime($row["datesubmitted"], $tzFrom); $dt->setTimezone($tzTo);

    Read the article

  • PHPUnit with Zend Framework

    - by ArneRie
    Hi, i have studied some examples for PHPUnit with Zend Framework, but there is one part iam not understanding. In the most examples, the Application Bootstrap runs from some kind of baseClass inside the setUp() Method. Why not in __construct()? Is there any good reason? Example iam talking about

    Read the article

  • In a web app, is it wise to give log files ".txt" suffix?

    - by Pekka
    I am building a logging mechanism in a web application. Being a Windows man, I tend to give files with textual content the .txt ending. The suffix is automatically registered to be opened in a text editor in any Windows environment, and is just a nice convention. The app is going to be redistributed, and running mostly on Linux, though. The Linux convention for log files is .log. Is there any good reason on the Linux end, besides convention, why I should use .log? Any filters, real-life applications that could become relevant and that will work only with a .log suffix? Or can I merrily call it error_log.txt?

    Read the article

  • Forum achievements on a phpBB3 board?

    - by VIVA LA NWO
    I recently started a new community. The forum software is phpBB3, and so far so good. In an attempt to make my community more unique and interesting, I had to idea of having user achievements. Let me give you a quick run-down. Each user has achievements that they can earn (these will probably be across all users), for example an achievement for when a user hits 1,000 posts, when they upload an avatar, when one of their topics gets 1,000 views and so on. Each achievement has points, for example an achievement like uploading an avatar will be 10 points and reaching 10,000 points will grant 50 achievement points. If anyone here plays World of Warcraft you may be seeing where I'm getting the ideas from. :) What I'm struggling to get my head around though is how exactly to code this... I could keep a record of all users activity and add it to a special database table possibly, and then check via cron every minute or so if any user has met achievement criteria... but then I also want it controllable through the ACP so I can easily add new achievements and change their points etc. My mind is pretty blank when it comes to anything but the most simple things. What I really posted here for was feedback on the idea and how you all think I should go about doing this. The coding part should be pretty simple for me once I get my head around how phpBBB MODs need to be written. Thanks for reading, and I look forward to your replies. :)

    Read the article

  • Help with grasping (INNER?) JOIN

    - by Greenie
    I'm having trouble building a query. I can do what I want in 3 different queries. SELECT id FROM table1 WHERE url LIKE '%/$downloadfile' put that in $url_id SELECT item_id FROM table2 WHERE rel_id = '$url_id'" put that in $item_id SELECT rel_id FROM table2 WHERE rel_id = '$item_id' AND field_id = '42'" put that in $user_id But from reading examples on joins and inner joins I think there's a more elegant way. I cant wrap my brain around writing a better query (but would like to) I can describe how it should go: table1 fields: id, url table2 fields item_id, rel_id, field_id I know the last part of table1.url (LIKE '%/$filename') with that I select table1.id. table1.id is equal to one entry in table2.rel_id. So get that and select the table2.item_id. In table2 there is another entry which has the same table2.item_id and it will have a table2.field_id = '42' And finally the value I need is the table2.rel_id where the table2.field_id was 42. I will fetch that value and put it in $user_id Can this be done with one query using joins/inner joins?

    Read the article

  • How to split value

    - by scopus
    Hi, I want to split value. $value = "code1.code2.code3.code4(code5.code6(arg1.arg2, arg3), code7.code8)"; I want to split like this. Array ( [0] => code1 [1] => code2 [2] => code3 [1] => code4(code5.code6(arg1.arg2, arg3), code7.code8) ) I used explode('.', $value) but explode split in parentheses value. I don't want split in parentheses value. How can i do?

    Read the article

  • What's the best, Escape then store Or store then escape the output?

    - by Axel
    Hi, After doing a long search on stackoverflow i didn't find any one talked about this even if it's a big choice, the Question is what's the best in order to prevent both of XSS and SQL injection, Escaping the data then store it in the DB or Store it as it is and escape when output it? Note: it is better if you give some examples of practics if possible. Thanks

    Read the article

  • Local web apps and W3C standards.

    - by Babiker
    If am writing a local app that will only run using a specific browser, am i setting my self up by slightly ignoring W3C's standards? I ask this question because in this app i am thinking of using custom HTML tags, custom attributes, etc... Thanks in advance guys.

    Read the article

  • Laravel with Homestead

    - by Ahmed el-Gendy
    I new with virtual box and vagrant , Now I using Homestead image and every thing is run well but when i create my project named laravel on virtual machine it supposed that i see this new folder named laravel on my machine but i didn't get any thing on my machine , The synchronization is not working. NOTE: I'm using ubuntu 14.04 This is my homestead.yaml ip: "192.168.10.10" memory: 2048 cpus: 1 authorize: ~/.ssh/id_rsa.pub keys: - ~/.ssh/id_rsa folders: - map: /var/projects/ to: /home/vagrant/projects/ sites: - map: homestead.app to: /home/vagrant/projects/laravel/public variables: - key: APP_ENV value: local thanks advance

    Read the article

  • Display `pretty output` of directory content from array

    - by user275074
    Hi, I'm using the following code to get an array of directories and their sub-directories where each contain file type extension: png. It works great but I need to be able to output the results of the array in a list style format e.g. Test - test2.png - test1.png subfolder - test3.png sub sub folder - test4.png etc Code: $filter=".png"; $directory='../test'; $it=new RecursiveDirectoryIterator("$directory"); foreach(new RecursiveIteratorIterator($it) as $file){ if(!((strpos(strtolower($file),$filter))===false)||empty($filter)){ $items[]=preg_replace("#\\\#", "/", $file); } } Example array of results: array ( 0 => '../test/test2.png', 1 => '../test/subfolder/subsubfolder/test3.png', 2 => '../test/subfolder/test3.png', 3 => '../test/test1.png', ) What would be the best way of achieving the desired result?

    Read the article

  • Sort directory listing using RecursiveDirectoryIterator

    - by Scott Saunders
    I'm using RecursiveDirectoryIterator and RecursiveIteratorIterator to build a file listing tree using code like below. I need to the list to be sorted - either directories then files alphabetically, or just alphabetically. Can anyone tell me how to sort the file list? $dir_iterator = new RecursiveDirectoryIterator($groupDirectory); $iterator = new RecursiveIteratorIterator($dir_iterator, RecursiveIteratorIterator::SELF_FIRST); foreach ($iterator as $file) { // do stuff with $file }

    Read the article

  • Dataflow in Controllers & Layouts in Zend Framework

    - by favo
    I use a basic setup which uses a layout.phtml for the HTML Layout and view scripts for the content part. I want to control some variables in the layout in my controllers, i.e. the title of my site. How can I access my layout to output variables from within the controller? Thanks for your feedback!

    Read the article

  • PHPMailer attachment type and size limit

    - by SomeoneS
    i have one form and i am using PHPMailer to send data from that form to my email. Users can send attachments as well, but i have one rpoblem: how to make PHPMailer to deny attachments larger than 2Mb and to allow only iamge attachments (no other types of documents)? This is code i using for multiply email attachments with PHPMailer: foreach(array_keys($_FILES['fileAttach']['name']) as $key) { $source = $_FILES['fileAttach']['tmp_name'][$key]; $filename = $_FILES['fileAttach']['name'][$key]; $mail->AddAttachment($source, $filename); }

    Read the article

  • Smiley Replace within CDATA of an HTML-String

    - by michaelm
    Hello, i have got a simple problem :( I need to replace text smilies with the according smiley-image. ok.. thats not really complex, but now i have to replace only smilie appereances outside of HTML Tags. short examplae: Text: Thats a good example :/ .. with a <a href="http://www.foobar.com">link</a> inside. i want to replace ":/" with the image of this smiley... ok, how to do that the best way?

    Read the article

  • Ordering Wordpress posts by most recently commented on

    - by Hardseat
    What's the query to list wordpress posts by most recent, with posts most recently commented on going to the top of the order? (Standard "message board" style) This post looked promising: http://stackoverflow.com/questions/698438/ordering-wordpress-posts-by-most-recent-comment But the query is clearly wrong. Can anyone help?

    Read the article

  • importing csv file into pgsql

    - by running4surival
    ok im trying to upload this csv file onto my table in pgsql but im getting this error ERROR: invalid input syntax for integer: "mlname,mfname,slname,sfname,address,postalcode,membershiptype,hphone,email" CONTEXT: COPY members2, line 1, column id: "mlname,mfname,slname,sfname,address,postalcode,membershiptype,hphone,email" i really understand why im getting this error, both my table and my csv file have the same column names

    Read the article

  • how i can retrive files from folder on hard-disk and how to display uplaoded file data into a textar

    - by Deepak Narwal
    I have made a application form in which i am asking for username,password,email id and user's resume.Now after uploading resume i am storing it into hard disk into htdocs/uploadedfiles/..in a format something like this username_filename.In database i am storing file name,file size,file type.Some coading for this i am showing here $filesize=$_FILES['file']['size']; $filename=$_FILES['file']['name']; $filetype=$_FILES['file']['type']; $temp_name=$_FILES['file']['tmp_name']; //temporary name of uploaded file $pwd_hash = hash('sha1',$_POST['password']); $target_path = "uploadedfiles/"; $target_path = $target_path.$_POST['username']."_".basename( $_FILES['file']['name']); move_uploaded_file($_FILES['file']['tmp_name'], $target_path) ; $sql="insert into employee values ('NULL','{$_POST[username]}','{$pwd_hash}','{$filename}','{$filetype}','$filesize',NOW())"; Now i have two questions 1.NOw how i can display this file data into a textarea(something like naukri.com resume section) 2.How one can retrive that resume file from folder on hard-disk.What query should i write to fetch this file from that folder.I know how to retrive data from database but i dont know how to retrive data from a folder in hard-disk like in the case if user want to delete this file or he wnat to download this file.How i can do this

    Read the article

  • help me with function resize , not working with png

    - by user304828
    it not work with png created a thumb png but haven't data , like null data :D with jpg , jpeg still working without error why ? function thumbnail($pathtoFile,$thumWidth,$pathtoThumb) { //infor of image $infor = pathinfo($pathtoFile); // Setting the resize parameters list($width, $height) = getimagesize($pathtoFile); $modwidth = $thumWidth; $modheight = floor( $height * ( $modwidth / $width )); // Resizing the Image $thumb = imagecreatetruecolor($modwidth, $modheight); switch(strtolower($infor['extension'])) { case 'jpeg': case 'jpg': $image = imagecreatefromjpeg($pathtoFile); break; case 'gif': $image = imagecreatefromgif($pathtoFile); break; case 'png': $image = imagecreatefrompng($pathtoFile); break; } imagecopyresampled($thumb, $image, 0, 0, 0, 0, $modwidth, $modheight, $width, $height); switch(strtolower($infor['extension'])) { case 'jpeg': case 'jpg': imagejpeg($thumb,$pathtoThumb, 70); break; case 'gif': imagegif($thumb,$pathtoThumb, 70); break; case 'png': imagepng($thumb,$pathtoThumb, 70); break; } //destroy tmp imagedestroy($thumb); }

    Read the article

  • [Wordpress] How do I return values from custom created meta box?

    - by Steven
    I've just followed this example from Wordpress and I have successfully added an extra Meta Box in Post interface, and the value is stored in DB. Now my question is, how can I retrieve and display the content of this meta box? I'm trying the following code: $intro = get_post_meta($post->ID, 'post_intro', true); echo $intro; But I get nada. What am I doing wrong? And while I'm here, does anybody know if I can place this extra meta box above the default text box in Wordpress post page?

    Read the article

  • Problem in Saving Multi Level Models in YII

    - by Waqar
    My Table structure for user and his adress detail is as follows CREATE TABLE tbl_users ( id bigint(20) unsigned NOT NULL AUTO_INCREMENT, loginname varchar(128) NOT NULL, enabled enum("True","False"), approved enum("True","False"), password varchar(128) NOT NULL, email varchar(128) NOT NULL, role_id int(20) NOT NULL DEFAULT '2', name varchar(70) NOT NULL, co_type enum("S/O","D/O","W/O") DEFAULT "S/O", co_name varchar(70), gender enum("MALE","FEMALE","OTHER") DEFAULT "MALE", dob date DEFAULT NULL, maritalstatus enum("SINGLE","MARRIED","DIVORCED","WIDOWER") DEFAULT "MARRIED", occupation varchar(100) DEFAULT NULL, occupationtype_id int(20) DEFAULT NULL, occupationindustry_id int(20) DEFAULT NULL, contact_id bigint(20) unsigned DEFAULT NULL, signupreason varchar(500), PRIMARY KEY (id), UNIQUE KEY loginname (loginname), UNIQUE KEY email (email), FOREIGN KEY (role_id) REFERENCES tbl_roles (id), FOREIGN KEY (occupationtype_id) REFERENCES tbl_occupationtypes (id), FOREIGN KEY (occupationindustry_id) REFERENCES tbl_occupationindustries (id), FOREIGN KEY (contact_id) REFERENCES tbl_contacts (id) ) ENGINE=InnoDB; CREATE TABLE tbl_contacts ( id bigint(20) unsigned NOT NULL AUTO_INCREMENT, contact_type enum("cres","pres","coff"), address varchar(300) DEFAULT NULL, landmark varchar(100) DEFAULT NULL, district_id int(11) DEFAULT NULL, city_id int(20) DEFAULT NULL, state_id int(20) DEFAULT NULL, pin_id bigint(20) unsigned DEFAULT NULL, area_id bigint(20) unsigned DEFAULT NULL, po_id bigint(20) unsigned DEFAULT NULL, phone1 varchar(20) DEFAULT NULL, phone2 varchar(20) DEFAULT NULL, mobile1 varchar(20) DEFAULT NULL, mobile2 varchar(20) DEFAULT NULL, PRIMARY KEY (id), FOREIGN KEY (district_id) REFERENCES tbl_districts (id), FOREIGN KEY (city_id) REFERENCES tbl_cities (id), FOREIGN KEY (state_id) REFERENCES tbl_states (id) ) ENGINE=InnoDB; CREATE TABLE tbl_states ( id int(20) NOT NULL AUTO_INCREMENT, name varchar(70) DEFAULT NULL, PRIMARY KEY (id) ) ENGINE=InnoDB; CREATE TABLE tbl_districts ( id int(20) NOT NULL AUTO_INCREMENT, name varchar(70) DEFAULT NULL, state_id int(20) DEFAULT NULL, PRIMARY KEY (id), FOREIGN KEY (state_id) REFERENCES tbl_states (id) ) ENGINE=InnoDB; CREATE TABLE tbl_cities ( id int(20) NOT NULL AUTO_INCREMENT, name varchar(70) DEFAULT NULL, district_id int(20) DEFAULT NULL, state_id int(20) DEFAULT NULL, PRIMARY KEY (id), FOREIGN KEY (district_id) REFERENCES tbl_districts (id), FOREIGN KEY (state_id) REFERENCES tbl_states (id) ) ENGINE=InnoDB; The relationship is as follows User has multiple contacts i.e Permanent Address, Current Address, Office Address. Each Contact has state and City. User-Contact-state like this How to save models of this structure in one go. Please provide a reply ASAP

    Read the article

< Previous Page | 755 756 757 758 759 760 761 762 763 764 765 766  | Next Page >