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  • Limiting the maximum number of concurrent requests django/apache

    - by Johan
    Hi, I have a django site that demonstrates the usage of a tool. One of my views takes a file as input and runs some fairly heavy computation trough an external python script and returns some output to the user. The tool runs fast enough to return the output in the same request though. I would however want to limit how many concurrent requests to this URL/view to keep the server from getting congested. Any tips on how i would go about doing this? The page in itself is very simple and the usage will be low.

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  • Python / Django : emulating a multidimensional layer on a MySQL database

    - by Sébastien Piquemal
    Hi, I'm working on a Django project where I need to provide a lot of different visualizations on the same data (for example average of a value for each month, for each year / for a location, etc...). I have been using an OLAP database once in college, and I thought that it would fit my needs, but it appears that it is much too heavy for what I need. Actually the volume of data is not very big, so I don't need any optimization, just a way to present different visualizations of the same data without having to write 1000 times the same code. So, to recap, I need a python library: to emulate a multidimensional database (OLAP style would be nice because I think it is quite convenient : star structure, and everything) non-intrusive, because I can't modify anything on the existing MySQL database easy-to-use, because otherwise there's no point in replacing some overhead by another.

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  • Local sites not displaying in VirtualBox when using Django's local development server?

    - by littlejim84
    Hello. I develop web applications using Django on Mac OSX 10.6. I use Django's built in local development server which I run on my computer's IP (such as: http://192.168.0.11:8001/). I test my applications in Firefox, Safari and Chrome and all display fine. I use Sun's VirtualBox with 3 different instances of Windows XP that have IE6, IE7 and IE8 on them. For whatever reason, these sometimes just don't display the Django sites. They come up with 'The page cannot be displayed'. Eight times out of ten, they display fine and function normally but for no reason at all they won't display. Sometimes restarting Django's local development server from the Terminal will fix the problem, sometimes it won't. Is there some sort of VirtualBox settings or Django settings that I need to set to ensure smooth operation of this? Am I overlooking something? Has anyone else had these problems?

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  • Django filter with two constraints on related model

    - by BJ Homer
    I have a django app with models as follows: A Question model An Answer model, with a ForeignKey back to the Question. (A question can have multiple answers.) A Flag model, with a ForeignKey to the Answer. (An answer can be flagged as inappropriate.) All of the above also have a user field, defining the user that created that object. I'm trying to get a list of all Questions with answers from the current user which have been flagged. I tried this: Question.objects.filter(answer__user=user).\ filter(answer__flag__isnull=True).distinct() … but I believe that will return a list of Questions with answers from the current user and with answers which have been flagged, but will not necessarily guarantee that it is the user's answer that has been flagged. Is there an easy way to do this? Basically, I want to make the answer part of the filter refer to the same answer on both of them. Please let me know if something is unclear.

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  • Django - Tips to avoid repeating code in views

    - by D Roddis
    I'm moving from a PHP background into Django development via python, mostly for the sake of tackling a MVC (or MVT) that I feel makes the most sense, although in this pattern I've started to notice a lot of repeated code in my views. For example, when logged in I have information regarding the user that I would like to appear on every page, although when using render_to_response and in every view this is required I have to grab the information and pass it to the render_to_response function. I'm wondering what would be the most efficient way to cut down on the duplicate code which would in essence be required in all views in a particular app. Thanks in advance.

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  • Django json serialization problem

    - by codingJoe
    I am having difficulty serializing a django object. The problem is that there are foreign keys. I want the serialization to have data from the referenced object, not just the index. For example, I would like the sponsor data field to say "sponsor.last_name, sponsor.first_name" rather than "13". How can I fix my serialization? json data: {"totalCount":"2","activities":[{"pk": 1, "model": "app.activity", "fields": {"activity_date": "2010-12-20", "description": "my activity", "sponsor": 13, "location": 1, .... model code: class Activity(models.Model): activity_date = models.DateField() description = models.CharField(max_length=200) sponsor = models.ForeignKey(Sponsor) location = models.ForeignKey(Location) class Sponsor(models.Model): last_name = models.CharField(max_length=20) first_name= models.CharField(max_length=20) specialty = models.CharField(max_length=100) class Location(models.Model): location_num = models.IntegerField(primary_key=True) location_name = models.CharField(max_length=100) def activityJSON(request): activities = Activity.objects.all() total = activities.count() activities_json = serializers.serialize("json", activities) data = "{\"totalCount\":\"%s\",\"activities\":%s}" % (total, activities_json) return HttpResponse(data, mimetype="application/json")

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  • Inlines in Django Admin

    - by Oli
    I have two models, Order and UserProfile. Each Order has a ForeignKey to UserProfile, to associate it with that user. On the django admin page for each Order, I'd like to display the UserProfile associated with it, for easy processing of information. I have tried inlines: class UserInline(admin.TabularInline): model = UserProfile class ValuationRequestAdmin(admin.ModelAdmin): list_display = ('address1', 'address2', 'town', 'date_added') list_filter = ('town', 'date_added') ordering = ('-date_updated',) inlines = [ UserInline, ] But it complains that UserProfile "has no ForeignKey to" Order - which it doesn't, it's the other way around. Is there a way to do what I want?

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  • How to set up Django app to make cookies work on subdomain

    - by Dzida
    Hi, I have deployed my application on subdomain.domain.com (it works only on that one subdomain). Everything works fine except the fact that from time to time users cannot log in to application (the message "Looks like your browser isn't configured to accept cookies. Please enable cookies, reload this page, and try again" is shown when trying to log into admin panel). I've noticed that restarting the web server eliminates this problem for some time. Does anyone have experience with setting up django project on subdomain and can guide me how to configure my application to make it work correctly without need to ocasionally make reset?

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  • Django Admin: Many-to-Many listbox doesn't show up with a through parameter

    - by NP
    Hi All, I have the following models: class Message(models.Model): date = models.DateTimeField() user = models.ForeignKey(User) thread = models.ForeignKey('self', blank=True, null=True) ... class Forum(models.Model): name = models.CharField(max_length=24) messages = models.ManyToManyField(Message, through="Message_forum", blank=True, null=True) ... class Message_forum(models.Model): message = models.ForeignKey(Message) forum = models.ForeignKey(Forum) status = models.IntegerField() position = models.IntegerField(blank=True, null=True) tags = models.ManyToManyField(Tag, blank=True, null=True) In the admin site, when I go to add/change a forum, I don't see the messages listbox as you'd expect. However, it shows up if I remove the 'through' parameter in the ManyToManyField declaration. What's up with that? I've registered all three models (plus Tag) to the admin site in admin.py. TIA

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  • Python / Django : emulating a multidimensionnal layer on a mySql database

    - by Sébastien Piquemal
    Hi, I'm working on a Django project where I need to provide a lot of different visualizations on the same data (for example average of a value for each month, for each year / for a location, etc ...). I have been using OLAP database once in college, and I thought that it would fit my needs, but it appears that it is much to heavy for what I need. Actually the volume of data is not very big, so I don't need any optimization, just a way to present different visualizations of the same data without having to write 1000 times the same code. So let's recap : I need a python library : to emulate a multidimensional database (OLAP style would be nice because I think it is quite convenient : stat structure, and everything) non-intrusive, because I can't modify anything on the existing mysql database easy-to-use, because otherwise there's no point in replacing some overhead by another.

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  • How can I selectively override a django .count() method

    - by Tom Viner
    I'm using postGresSQL and my main table has about 20,000 rows. Sometimes count() methods can take ages or even timeout. Mod.manager.filter(...).count() I need to selectively override the count() method depending on what filter has been applied. Just having a cache of results would be a great gain but I'd like to be able to say: if filter query is just {'enabled'=True} then return 20,000 without touching the db. Note: I can't prevent the call to .count() as it's inside django's pagination, which always does a count.

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  • Getting users latest tweet with Django

    - by Hanpan
    I want to create a function which grabs every users latest tweet from a specific group. So, if a user is in the 'authors' group, I want to grab their latest tweet and then finally cache the result for the day so we only do the crazy leg work once. def latest_tweets(self): g = Group.objects.get(name='author') users = [] for u in g.user_set.all(): acc = u.get_profile().twitter_account users.append('http://twitter.com/statuses/user_timeline/'+acc+'.rss') return users Is where I am at so far, but I'm at a complete loose end as to how I parse the RSS to get there latest tweet. Can anyone help me out here? If there is a better way to do this, any suggestions are welcome! I'm sure someone will suggest using django-twitter or other such libraries, but I'd like to do this manually if possible. Cheers

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  • django url tag performance

    - by zxygentoo
    I was trying to integrate django-voting into my project following the RedditStyleVoting instruction. In my urls.py, i did something like this: url(r'^sections/(?P<object_id>\d+)/(?P<direction>up|down|clear)vote/?$', vote_on_object, dict( model=Section, template_object_name='section', template_name='script/section_confirm_vote.html', allow_xmlhttprequest=True ), name="section_vote", then, in my template: {% vote_by_user user on section as vote %} {% score_for_object section as score %} {% vote_by_user user on section as vote %} {% score_for_object section as score %} {{ score.score|default:0 }} It takes over 1.3s to load the page, but by hard coding it like this: {% vote_by_user user on section as vote %} {% score_for_object section as score %} {{ score.score|default:0 }} I got 50ms. Just avoid the url tag resolving stuff I got a 20+ times performance improvement. Is there something I did wrong? If not, then what's the best practice here, should we do things the right way or the fast way?

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  • Django dictionary in templates: Grab key from another objects attribute

    - by Jordan Messina
    I have a dictionary called number_devices I'm passing to a template, the dictionary keys are the ids of a list of objects I'm also passing to the template (called implementations). I'm iterating over the list of objects and then trying to use the object.id to get a value out of the dict like so: {% for implementation in implementations %} {{ number_devices.implementation.id }} {% endfor %} Unfortunately number_devices.implementation is evaluated first, then the result.id is evaluated obviously returning and displaying nothing. I can't use parentheses like: {{ number_devices.(implementation.id) }} because I get a parse error. How do I get around this annoyance in Django templates? Thanks for any help!

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  • Django complex queries

    - by Josh K
    I need to craft a filter for an object that checks date ranges. Right now I'm performing a very inefficient loop which checks all the objects. I would like to simplify this to a database call. The logic is you have a start and an end date objects. I need to check if the start OR the end is within the range of an appointment. if (start >= appointment.start && start < appointment.end) || (end > appointment.start && end <= appointment.end) I could do this in SQL, but I'm not as familiar with the Django model structure for more complex queries.

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  • Django. default=datetime.now() problem

    - by Shamanu4
    Hello. I've such db model: from datetime import datetime class TermPayment(models.Model): dev_session = models.ForeignKey(DeviceSession, related_name='payments') user_session = models.ForeignKey(UserSession, related_name='payment') date = models.DateTimeField(default=datetime.now(),blank=True) sum = models.FloatField(default=0) cnt = models.IntegerField(default=0) class Meta: db_table = 'term_payments' ordering = ['-date'] and here new instance is added: # ... tp = TermPayment() tp.dev_session = self.conn.session # device session hash tp.user_session = self.session # user session hash tp.sum = sum tp.cnt = cnt tp.save() But i've a problem: all records in database have the same value in date field - the date of the first payment. After server restart - one record have new date and others have the same as first after restart. It's look like some data cache is using but I can't found where. database: mysql 5.1.25 django v1.1.1

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  • Django colon syntax in template tags: only in newer versions?

    - by Alan
    I just deployed an application to a new server, and although I'm using virtualenv, I had to install a new environment on the production server, which has a different architecture. Anyway, I received no TemplateSytaxErrors in development, but on the production server, I get: Exception Type: TemplateSyntaxError Exception Value: Caught SyntaxError while rendering: invalid syntax (views.py, line 25) The offending line is: {% url admin:password_change as password_change_url %} Upon removing that line, the TemplateSyntaxError hops to the next line that has a colon in it (and lets other template tags work fine). So my question is this: is there some discrepancy in versions of Python/Django that would allow or disallow the namespacing syntax? The template tags are in django-grappelli (http://code.google.com/p/django-grappelli/), so I'd rather not go through their code and rewrite all the template tags. Development server: 32-bit Debian Python 2.5.5 Django 1.2.1 Production server: 64-bit CentOS Python 2.4.3 Django 1.2.1 Any ideas?

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  • Django: Localization Issue

    - by Eric
    In my application, I have a dictionary of phrases that are used throughout of the application. This same dictionary is used to create PDFs and Excel Spreadsheets. The dictionary looks like so: GLOBAL_MRD_VOCAB = { 'fiscal_year': _('Fiscal Year'), 'region': _('Region / Focal Area'), 'prepared_by': _('Preparer Name'), 'review_cycle':_('Review Period'), ... snip ... } In the code to produce the PDF, I have: fy = dashboard_v.fiscal_year fy_label = GLOBAL_MRD_VOCAB['fiscal_year'] rg = dashboard_v.dashboard.region rg_label = GLOBAL_MRD_VOCAB['region'] rc = dashboard_v.review_cycle rc_label = GLOBAL_MRD_VOCAB['review_cycle'] pb = dashboard_v.prepared_by pb_label = GLOBAL_MRD_VOCAB['prepared_by'] Now, when the PDF is produced, in the PDF, I don't see these labels but rather, I see: <django.utils.functional.__proxy__ object at 0x10106fdd0> Can somebody help me with this? How do I get the properly translated labels? Thanks Eric

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  • Django admin page dropdowns

    - by zen
    I am building a high school team application using Django. Here is my working models file: class Directory(models.Model): school = models.CharField(max_length=60) website = models.URLField() district = models.SmallIntegerField() conference = models.ForeignKey(Conference) class Conference(models.Model): conference_name = models.CharField(max_length=50) url = models.URLField() class Meta: ordering = ['conference_name'] When I open my admin pages and go to edit a school's conference the drop down looks like this: <select> <option value="1">Conference Object</option> <option value="2">Conference Object</option> <select> How do I replace "Conference Object" with the conference_name?

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  • Firefox - Stashing Requests for Deliberate Resubmission to Django App

    - by Koobz
    I've got an object creation form that's somewhat complicated, it contains a few dynamic formsets etc. I'm trying to ensure that these dynamic formsets are intact if the form runs into an error and returns you to the given page. In cases like this, the refresh button actually works well in re-submitting the request, but I can't rely on it. I'm doing some ad-hoc testing in the browser that I'd like to make a bit more repeatable, and eventually move to a unit test using Django's mock client. Is there an extension, or some convenient method to stash requests for later re-submission. The goal: I resubmit the request, tweak the code, eyeball the results, rinse and repeat. Three days later I can come back to it an try it again to make sure it's still working. The closest thing I can think of in this case is simply recording my activity with Selenium ide and replaying it.

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  • Django - Empty session data in ajax requests

    - by ninja123
    Hi guys, I have an ajax view where I want to set a session variable like such: def upload(request, *args, **kwargs): request.session['test'] = 'test' request.session.modified = True print request.session.items() I have another normal view something like this: def advertise(request): print request.session.items() I get these two strings printed to shell: [('test', 'test')] [('_auth_user_backend', 'django.contrib.auth.backends.ModelBackend'), ('_auth_user_id', 26L)] Why is the session data that I set in the ajax view not passing to my regular views? If I set session data in regular view, everything works as fine, but it seems that ajax requests contain empty session data? Anybody dealt with something like this before? Any suggestions are greatly appreciated. Thanks.

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  • Django i18n: makemessages only on site level possible?

    - by AndiDog
    I have several strings in my site that don't belong to any app, for example {% block title %}{% trans "Login" %}{% endblock %} or a modified authentication form used to set the locale cookie class AuthenticationFormWithLocaleOption(AuthenticationForm): locale = forms.ChoiceField(choices = settings.LANGUAGES, required = False, initial = preselectedLocale, label = _("Locale/language")) Now when I execute django-admin.py makemessages --all -e .html,.template in the site directory, it extracts the strings from all Python, .html and .template files, including those in my apps. That is because I develop my apps inside that directory: Directory structure: sitename myapp1 myapp2 Is there any way to extract all strings that are not in my apps? The only solution I found is to move the app directories outside the site directory structure, but I'm using bzr-externals (similar to git submodules or svn externals) so that doesn't make sense in my case. Moving stuff that needs translation into a new app is also possible but I don't know if that is the only reasonable solution.

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  • Can you iterate over chunks() with request.POST in Django?

    - by Sebastian
    I'm trying to optimize a site I'm building with Django/Flash and am having a problem using Django's iterate over chunks() feature. I'm sending an image from Flash to Django using request.POST data rather than through a form (using request.FILES). The problem I foresee is that if there is large user volume, I could potentially kill memory. But it seems that Django only allows iterating over chunks with request.FILES. Is there a way to: 1) wrap my request.POST data into a request.FILES (thus spoofing Django) or 2) use chunks() with request.POST data

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  • Django admin return to page after save

    - by Thordin9
    Hi all, I have 3 pages of items listed in my django application admin. After i edit one of them (lets say it is in page 2) and save my changes, i return to page 1 of my listing. How can i make it so i return to the page the item is in? I looked into some similar questions here at stackoverflow and i believe that i need to use javascript to send a httpresponse with the location header. But how i can determine the page the item is in? any help is appreciated

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  • How to stream an HttpResponse with Django

    - by muudscope
    I'm trying to get the 'hello world' of streaming responses working for Django (1.2). I figured out how to use a generator and the yield function. But the response still not streaming. I suspect there's a middleware that's mucking with it -- maybe ETAG calculator? But I'm not sure how to disable it. Can somebody please help? Here's the "hello world" of streaming that I have so far: def stream_response(request): resp = HttpResponse( stream_response_generator()) return resp def stream_response_generator(): for x in range(1,11): yield "%s\n" % x # Returns a chunk of the response to the browser time.sleep(1)

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