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  • build an API service in Django

    - by Peter
    Hi all, I want to build an API service using Django. A basic workflow goes like this: First, an http request goes to http://mycompany.com/create.py?id=001&callback=http://callback.com. It will create a folder on the server with name 001. Second, if the folder does not exist, it will be created. You get response immediately in XML format. It will look like: <?xml version="1.0" encoding="UTF-8"?> <response> <status> <statusCode>0</statusCode> <message>Success</message> </status> <group id="001"/> </response> Finally, the server will do its job (i.e. creating the folder). After it is done, the server does a callback to the URL provided. Currently, I use return render_to_response('create.xml', {'statusCode': statusCode, 'statusMessage': statusMessage, 'groupId': groupId, }, mimetype = 'text/xml') to send the XML response back. I have an XML template which has statusCode, statusMessage, groupId placeholders. <?xml version="1.0" encoding="UTF-8"?> <response> <status> <statusCode>{{ statusCode }}</statusCode> <message>{{ statusMessage }}</message> </status> {% if not statusCode %} <group id="{{ groupId }}"/> {% endif %} </response> But in this way I have to put step 3 before step 2, because otherwise step 3 will not be executed if it is after return statement. Can somebody give me some suggestions how to do this? Thanks.

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  • django simple approach to multi-field search

    - by Scott Willman
    I have a simple address book app that I want to make searchable. The model would look something like: class Address(models.Model): address1 = models.CharField("Address Line 1", max_length=128) address2 = models.CharField("Address Line 2", max_length=128) city = models.CharField("City", max_length=128) state = models.CharField("State", max_length=24) zipCode = models.CharField("Zip Code", max_length=24) def __unicode__(self): return "%s %s, %s, %s, %s" % (self.address1, self.address2, self.city, self.state, self.zipCode) class Entry(models.Model): name = models.CharField("Official School Name", max_length=128) createdBy = models.ForeignKey(User) address = models.ForeignKey(Address, unique=True) def __unicode__(self): return "%s - %s, %s" % (self.name, self.address.city, self.address.state) I want the searching to be fairly loose, like: Bank of America Los Angeles 91345. It seems like I want a field that contains all of those elements into one that I can search, but that also seems redundant. I was hoping I could add a method to the Entry model like this: def _getSearchText(self): return "%s %s %s" % (self.name, self.address, self.mascot) searchText = property(_getSearchText) ...and search that as a field, but I suppose that's wishful thinking... How should I approach this using basic Django and SqLite (this is a learning exercise). Thank you!!

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  • Django + jquery : getting 301

    - by llazzaro
    Hello, I have tabs that calls via javascript urls of django to complete the "container" But i am getting 301, any idea why this is happening? Server misconfiguration? urls.py urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), (r'^list/', 'carsproj.cars.views.list'), ) view def list(request): if request.is_ajax(): return render_to_response('templates/generic_list.html', { 'items' : Cars.objects.all(), 'name' : 'List - Cars' }, context_instance = RequestContext(request)) javascript the_tabs.click(function(e){ var element = $(this); if(element.find('#overLine').length) return false; var bg = element.attr('class').replace('tab ',''); $('#overLine').remove(); $('<div>',{ id:'overLine', css:{ display:'none', width:element.outerWidth()-2, background:topLineColor[bg] || 'white' }}).appendTo(element).fadeIn('slow'); if(!element.data('cache')) { $('#contentHolder').html('<img src="/media/img/ajax_preloader.gif" width="64" height="64" class="preloader" />'); $.get(element.data('page'),function(msg){ $('#contentHolder').html(msg); element.data('cache',msg); }); } else $('#contentHolder').html(element.data('cache')); e.preventDefault(); }) Please tell me what more information you need, js code? template? url.py? I WILL EDIT THIS POST FOR ADD MORE DATA

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  • Need a workaround to filter on related model and aggregated fields in Django

    - by parxier
    I opened a ticket for this problem. In a nutshell here is my model: class Plan(models.Model): cap = models.IntegerField() class Phone(models.Model): plan = models.ForeignKey(Plan, related_name='phones') class Call(models.Model): phone = models.ForeignKey(Phone, related_name='calls') cost = models.IntegerField() I want to run a query like this one: Phone.objects.annotate(total_cost=Sum('calls__cost')).filter(total_cost__gte=0.5*F('plan__cap')) Unfortunately Django generates bad SQL: SELECT "app_phone"."id", "app_phone"."plan_id", SUM("app_call"."cost") AS "total_cost" FROM "app_phone" INNER JOIN "app_plan" ON ("app_phone"."plan_id" = "app_plan"."id") LEFT OUTER JOIN "app_call" ON ("app_phone"."id" = "app_call"."phone_id") GROUP BY "app_phone"."id", "app_phone"."plan_id" HAVING SUM("app_call"."cost") >= 0.5 * "app_plan"."cap" and errors with: ProgrammingError: column "app_plan.cap" must appear in the GROUP BY clause or be used in an aggregate function LINE 1: ...."plan_id" HAVING SUM("app_call"."cost") >= 0.5 * "app_plan".... Is there any workaround apart from running raw SQL?

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  • strange Django problem

    - by Pounds
    Sorrt to bother you everyone, but I really suffer a strange problem. I am working on a Django project for a company. This project worked very well before today. Today I found a page can not show images (and their corrsponding links). I checked source code of THAT PAGE, I found there are images and links, I just can not find them on the page. I checked the auth of the server and I am sure I can write things to the database. In fact, I think it is not database mistake because I can find what I want in the page source code, I just can not find them on the page. Oh my Gosh, I am going to be crazy... Has anyone suffered similar problem? What kind of problem could it be? Please help me! Thank you very much! PS: I can not provide any source code of the project because some business limit...I am really sorry...

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  • I can't login to my Django app when debug is set to False

    - by Eric
    I have a very strange problem, and I don't know how to fix or debug it. Short Story: I get locked out of my Django app when Debug is set to False. Long story: Case 1 (the first time it happened): 1. I enter my login info, but It just redirects to the login page. 2. I restart the server, try to login, and it works fine, I get in. 3. a few hours later I come back, log out, try to log back in and I can't. It just redirects to the login page. Case 2 (I figure out how to provoke the login failure): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a server error. 4. I log out and try to log back in, and I can't, just get redirected back to the login page. Case 3 (I can't provoke the login failure with Debug set to True): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a traceback. 4. I log out and log back in, everything works. 5. I wait and play around with it and can't get the login to fail while in Debug mode. Please help!

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  • Django Interrupted system call when sending email

    - by mhost
    Hi, Sometimes, when submitting a form (pretty much any form on my site that sends me an email), I get the following error: File "/usr/lib/python2.5/smtplib.py", line 603, in starttls (resp, reply) = self.docmd("STARTTLS") File "/usr/lib/python2.5/smtplib.py", line 378, in docmd return self.getreply() File "/usr/lib/python2.5/smtplib.py", line 352, in getreply line = self.file.readline() File "/usr/lib/python2.5/socket.py", line 381, in readline data = self._sock.recv(self._rbufsize) error: (4, 'Interrupted system call') My code is sending email via gmail. I am also using django contact-form which does the same thing. The problem doesn't always happen. It seems very random. At one point today it got so bad that it displayed the error every time I submitted a form. Restarting apache fixes the problem for one submission and then it does it again. I have checked the RAM and there is plenty available (about 350MB available). Can someone lead me in the right direction? What does this error mean? What can I do to prevent this. Thanks.

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  • use of ajax in django problem with the code

    - by tazim
    I am new to ajax and using Django for web development. Now My Template contains : sample.html <html> <body> <script language="javascript" type="text/javascript"> //Browser Support Code function ajaxFunction(){ var ajaxRequest; // The variable that makes Ajax possible! try{ // Opera 8.0+, Firefox, Safari ajaxRequest = new XMLHttpRequest(); } catch (e){ // Internet Explorer Browsers try{ ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try{ ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e){ // Something went wrong alert("Your browser broke!"); return false; } } } // Create a function that will receive data sent from the server ajaxRequest.onreadystatechange = function(){ if(ajaxRequest.readyState == 4){ document.myForm.time.value = ajaxRequest.responseText; } } ajaxRequest.open("GET", "/showtime/", true); ajaxRequest.send(null); } </script> <form name='myForm'> Name: <input type='text' onBlur="ajaxFunction();" name='username' /> <br /> Time: <input type='text' name='time' /> </form> </body> </html> In views.py my function is : def showtime(request): string = "Ajax Application" data = {"string" : string} pprint (data) return render_to_response("sample.html",data) Now, The output is not as expected . The template does not receives the response sent by the server What is wrong with the code ?

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  • Django - partially validating form

    - by aeter
    I'm new to Django, trying to process some forms. I have this form for entering information (creating a new ad) in one template: class Ad(models.Model): ... category = models.CharField("Category",max_length=30, choices=CATEGORIES) sub_category = models.CharField("Subcategory",max_length=4, choices=SUBCATEGORIES) location = models.CharField("Location",max_length=30, blank=True) title = models.CharField("Title",max_length=50) ... I validate it with "is_valid()" just fine. Basically for the second validation (another template) I want to validate only against "category" and "sub_category": In another template, I want to use 2 fields from the same form ("category" and "sub_category") for filtering information - and now the "is_valid()" method would not work correctly, cause it validates the entire form, and I need to validate only 2 fields. I have tried with the following: ... if request.method == 'POST': # If a filter for data has been submitted: form = AdForm(request.POST) try: form = form.clean() category = form.category sub_category = form.sub_category latest_ads_list = Ad.objects.filter(category=category) except ValidationError: latest_ads_list = Ad.objects.all().order_by('pub_date') else: latest_ads_list = Ad.objects.all().order_by('pub_date') form = AdForm() ... but it doesn't work. How can I validate only the 2 fields category and sub_category?

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  • Django Datetime field question

    - by Shehzad009
    Hello I have been having a problem with django while trying to work with datetime. In my webapp I have a table like so when I run server. ID Owing 1 -100 (All the same value) 2 -100 3 -100 . . . . . . It has in one column Invoice id and the other owing. One-one relationship as well. sow for example owing value for 1 is 100. Unfortunately, this is where it all goes wrong because throughout column (Owing), it is giving me the owing value for ID=1. I want each ID to give me their owing value. Here is my view. I also wonder if I may need a for loop somewhere as well. def homepage(request): invoices_list = Invoice.objects.all() invoice_name = invoices_list[0].client_contract_number.client_number.name invoice_gross = invoices_list[0].invoice_gross payment_date = invoices_list[0].payment_date if payment_date <= datetime.now(): owing = invoice_gross if payment_date > datetime.now(): owing = 0 else: owing= 0 return render_to_response(('index.html', locals()), {'invoices_list': invoices_list ,'invoice_number':invoice_number, 'invoice_name':invoice_name, 'invoice_gross':invoice_gross, 'payment_date':payment_date, 'owing': owing}, context_instance=RequestContext(request)) EDIT: Here is my template. The thing is the function owing is not in my models so saying {{invoices.owing}} wont work. {% for invoices in invoices_list %} <tr> <td>{{invoices.invoice_number}}</td> <td>{{invoices.invoice_contact}}</td> <td>{{invoices.client_contract_number}}</td> <td>{{invoices.payment_date|date:"d M Y"}}</td> <td>{{invoices.invoice_gross}}</td> <td>{{owing}}</td> {% endfor %}

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  • Python logging in Django

    - by Jeff
    I'm developing a Django app, and I'm trying to use Python's logging module for error/trace logging. Ideally I'd like to have different loggers configured for different areas of the site. So far I've got all of this working, but one thing has me scratching my head. I have the root logger going to sys.stderr, and I have configured another logger to write to a file. This is in my settings.py file: sviewlog = logging.getLogger('MyApp.views.scans') view_log_handler = logging.FileHandler('C:\\MyApp\\logs\\scan_log.log') view_log_handler.setLevel(logging.INFO) view_log_handler.setFormatter(logging.Formatter('%(asctime)s %(name)-12s %(levelname)-8s %(message)s')) sviewlog.addHandler(view_log_handler) Seems pretty simple. Here's the problem, though: whatever I write to the sviewlog gets written to the log file twice. The root logger only prints it once. It's like addHandler() is being called twice. And when I put my code through a debugger, this is exactly what I see. The code in settings.py is getting executed twice, so two FileHandlers are created and added to the same logger instance. But why? And how do I get around this? Can anyone tell me what's going on here? I've tried moving the sviewlog logger/handler instantiation code to the file where it's used (since that actually seems like the appropriate place to me), but I have the same problem there. Most of the examples I've seen online use only the root logger, and I'd prefer to have multiple loggers.

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  • Global name not defined error in Django/Python trying to set foreignkey

    - by Mark
    Summary: I define a method createPage within a file called PageTree.py that takes a Source model object and a string. The method tries to generate a Page model object. It tries to set the Page model object's foreignkey to refer to the Source model object which was passed in. This throws a NameError exception! I'm trying to represent a website which is structured like a tree. I define the Django models Page and Source, Page representing a node on the tree and Source representing the contents of the page. (You can probably skip over these, this is a basic tree implementation using doubly linked nodes). class Page(models.Model): name = models.CharField(max_length=50) parent = models.ForeignKey("self", related_name="children", null=True); firstChild = models.ForeignKey("self", related_name="origin", null=True); nextSibling = models.ForeignKey("self", related_name="prevSibling", null=True); previousSibling = models.ForeignKey("self", related_name="nxtSibling", null=True); source = models.ForeignKey("Source"); class Source(models.Model): #A source that is non dynamic will be refered to as a static source #Dynamic sources contain locations that are names of functions #Static sources contain locations that are places on disk name = models.CharField(primary_key=True, max_length=50) isDynamic = models.BooleanField() location = models.CharField(max_length=100); I've coded a python program called PageTree.py which allows me to request nodes from the database and manipulate the structure of the tree. Here is the trouble making method: def createPage(pageSource, pageName): page = Page() page.source = pageSource page.name = pageName page.save() return page I'm running this program in a shell through manage.py in Windows 7 manage.py shell from mysite.PageManager.models import Page, Source from mysite.PageManager.PageTree import * ... create someSource = Source(), populate the fields, and save it ... createPage(someSource, "test") ... NameError: global name 'source' is not defined When I type in the function definition for createPage into the shell by hand, the call works without error. This is driving me bonkers and help is appreciated.

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  • django multiprocess problem

    - by iKiR
    I have django application, running under lighttpd via fastcgi. FCGI running script looks like: python manage.py runfcgi socket=<path>/main.socket method=prefork \ pidfile=<path>/server.pid \ minspare=5 maxspare=10 maxchildren=10 maxrequests=500 \ I use SQLite. So I have 10 proccess, which all work with the same DB. Next I have 2 views: def view1(request) ... obj = MyModel.objects.get_or_create(id=1) obj.param1 = <some value> obj.save () def view2(request) ... obj = MyModel.objects.get_or_create(id=1) obj.param2 = <some value> obj.save () And If this views are executed in two different threads sometimes I get MyModel instance in DB with id=1 and updated either param1 or param2 (BUT not both) - it depends on which process was the first. (of course in real life id changes, but sometimes 2 processes execute these two views with same id) The question is: What should I do to get instance with updated param1 and param2? I need something for merging changes in different processes. One decision is create interprocess lock object but in this case I will get sequence executing views and they will not be able to be executed simultaneously, so I ask help

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  • Looking for: nosql (redis/mongodb) based event logging for Django

    - by Parand
    I'm looking for a flexible event logging platform to store both pre-defined (username, ip address) and non-pre-defined (can be generated as needed by any piece of code) events for Django. I'm currently doing some of this with log files, but it ends up requiring various analysis scripts and ends up in a DB anyway, so I'm considering throwing it immediately into a nosql store such as MongoDB or Redis. The idea is to be easily able to query, for example, which ip address the user most commonly comes from, whether the user has ever performed some action, lookup the outcome for a specific event, etc. Is there something that already does this? If not, I'm thinking of this: The "event" is a dictionary attached to the request object. Middleware fills in various pieces (username, ip, sql timing), code fills in the rest as needed. After the request is served a post-request hook drops the event into mongodb/redis, normalizing various fields (eg. incrementing the username:ip address counter) and dropping the rest in as is. Words of wisdom / pointers to code that does some/all of this would be appreciated.

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  • Best practice- How to team-split a django project while still allowing code reusal

    - by Infinity
    I know this sounds kind of vague, but please let me explain- I'm starting work on a brand new project, it will have two main components: "ACME PRODUCT" (think Gmail, Meebo, etc), and "THE SITE" (help, information, marketing stuff, promotional landing pages, etc lots of marketing-induced cruft). So basically the url /acme/* will load stuff in the uber cool ajaxy application, and every other URI will load stuff in the other site. Problem: "THE SITE" component is out of my hands, and will be handled by a consultants team that will work closely with marketing, And I and my team will work solely on the ACME PRODUCT. Question: How to set up the django project in such a way that we can have: Seperate releases. (They can push new marketing pages and functionality without having to worry about the state of our code. Maybe even separate Subversion "projects") Minimize impact (on our product) of whatever flying-unicorns-hocus-pocus the other team codes into the site. Still allow some code reusal. My main concern is that the ACME product needs to be rock solid, and therefore needs to be somewhat isolated of whatever mistakes/code bloopers the consultants make in their marketing side of the site. How have you handled this? Any ideas? Thanks!

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  • using replace to produce javascript code, django

    - by durdenk
    I want to use highcharts with my django site but it requires a comlex javascript code such as below. So I wanted to get this script in my python code and replace apropriate portions then write it in my template, first question is, is this a dump way to do that for a person not knowing javascript. I can read it tough. Second question is, Why I cant replace this string. Lets say this string is a variable like this. lineChartsTemplate = """ ... ... """ if I try and do lineChartsTemplate .replace('dataCategory', dataCategory) it basically suppossed to change dataCategory text with my dataCategory variable, but no such luck. I need guidance here. thx. $(function () { var chart = new Highcharts.Chart({ chart: { renderTo: 'container', type: 'bar' }, xAxis: { categories: dataCategory }, yAxis: { }, legend: { layout: 'vertical', floating: true, backgroundColor: '#FFFFFF', align: 'right', verticalAlign: 'top', y: 60, x: -60 }, tooltip: { formatter: function() { return '<b>'+ this.series.name +'</b><br/>'+ this.x +': '+ this.y; } }, plotOptions: { }, series: [{ data: dataList , name : 'Satislar'}] }); });

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  • Celery / Django Single Tasks being run multiple times

    - by felix001
    I'm facing an issue where I'm placing a task into the queue and it is being run multiple times. From the celery logs I can see that the same worker is running the task ... [2014-06-06 15:12:20,731: INFO/MainProcess] Received task: input.tasks.add_queue [2014-06-06 15:12:20,750: INFO/Worker-2] starting runner.. [2014-06-06 15:12:20,759: INFO/Worker-2] collection started [2014-06-06 15:13:32,828: INFO/Worker-2] collection complete [2014-06-06 15:13:32,836: INFO/Worker-2] generation of steps complete [2014-06-06 15:13:32,836: INFO/Worker-2] update created [2014-06-06 15:13:33,655: INFO/Worker-2] email sent [2014-06-06 15:13:33,656: INFO/Worker-2] update created [2014-06-06 15:13:34,420: INFO/Worker-2] email sent [2014-06-06 15:13:34,421: INFO/Worker-2] FINISH - Success However when I view the actual logs of the application it is showing 5-6 log lines for each step (??). Im using Django 1.6 with RabbitMQ. The method for placing into the queue is via placing a delay on a function. This function (task decorator is added( then calls a class which is run. Has anyone any idea on the best way to troubleshoot this ? Edit : As requested heres the code, views.py In my view im sending my data to the queue via ... from input.tasks import add_queue_project add_queue_project.delay(data) tasks.py from celery.decorators import task @task() def add_queue_project(data): """ run project """ logger = logging_setup(app="project") logger.info("starting project runner..") f = project_runner(data) f.main() class project_runner(): """ main project runner """ def __init__(self,data): self.data = data self.logger = logging_setup(app="project") def self.main(self): .... Code settings.py THIRD_PARTY_APPS = ( 'south', # Database migration helpers: 'crispy_forms', # Form layouts 'rest_framework', 'djcelery', ) import djcelery djcelery.setup_loader() BROKER_HOST = "127.0.0.1" BROKER_PORT = 5672 # default RabbitMQ listening port BROKER_USER = "test" BROKER_PASSWORD = "test" BROKER_VHOST = "test" CELERY_BACKEND = "amqp" # telling Celery to report the results back to RabbitMQ CELERY_RESULT_DBURI = "" CELERY_IMPORTS = ("input.tasks", ) celeryd The line im running is to start celery, python2.7 manage.py celeryd -l info Thanks,

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  • Django ModelForm Imagefield Upload

    - by Wei Xu
    I am pretty new to Django and I met a problem in handling image upload using ModelForm. My model is as following: class Project(models.Model): name = models.CharField(max_length=100) description = models.CharField(max_length=2000) startDate = models.DateField(auto_now_add=True) photo = models.ImageField(upload_to="projectimg/", null=True, blank=True) And the modelform is as following: class AddProjectForm(ModelForm): class Meta: model = Project widgets = { 'description': Textarea(attrs={'cols': 80, 'rows': 50}), } fields = ['name', 'description', 'photo'] And the View function is: def addProject(request, template_name): if request.method == 'POST': addprojectform = AddProjectForm(request.POST,request.FILES) print addprojectform if addprojectform.is_valid(): newproject = addprojectform.save(commit=False) print newproject print request.FILES newproject.photo = request.FILES['photo'] newproject.save() print newproject.photo else: addprojectform = AddProjectForm() newProposalNum = projectProposal.objects.filter(solved=False).count() return render(request, template_name, {'addprojectform':addprojectform, 'newProposalNum':newProposalNum}) the template is: <form class="bs-example form-horizontal" method="post" action="">{% csrf_token %} <h2>Project Name</h2><br> {{ addprojectform.name }}<br> <h2>Project Description</h2> {{ addprojectform.description }}<br> <h2>Image Upload</h2><br> {{ addprojectform.photo }}<br> <input type="submit" class="btn btn-success" value="Add Project"> </form> Can anyone help me or could you give an example of image uploading? Thank you!

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  • Caching queries in Django

    - by dolma33
    In a django project I only need to cache a few queries, using, because of server limitations, a cache table instead of memcached. One of those queries looks like this: Let's say I have a Parent object, which has a lot of Child objects. I need to store the result of the simple query parent.childs.all(). I have no problem with that, and everything works as expected with some code like key = "%s_children" %(parent.name) value = cache.get(key) if value is None: cache.set(key, parent.children.all(), CACHE_TIMEOUT) value = cache.get(key) But sometimes, just sometimes, the cache.set does nothing, and, after executing cache.set, cache.get(key) keeps returning None. After some test, I've noticed that cache.set is not working when parent.children.all().count() has higher values. That means that if I'm storing inside of key (for example) 600 children objects, it works fine, but it wont work with 1200 children. So my question is: is there a limit to the data that a key could store? How can I override it? Second question: which way is "better", the above code, or the following one? key = "%s_children" %(parent.name) value = cache.get(key) if value is None: value = parent.children.all() cache.set(key, value, CACHE_TIMEOUT) The second version won't cause errors if cache.set doesn't work, so it could be a workaround to my issue, but obviously not a solution. In general, let's forget about my issue, which version would you consider "better"?

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  • Heroku DJango app development on Windows

    - by Cliff
    I'm trying to start a Django app on Heroku using Windows and I'm getting stuck on the following error when I try to pip install psycopg2: Downloading/unpacking psycopg2 Downloading psycopg2-2.4.5.tar.gz (719Kb): 719Kb downloaded Running setup.py egg_info for package psycopg2 Error: pg_config executable not found. Please add the directory containing pg_config to the PATH or specify the full executable path with the option: python setup.py build_ext --pg-config /path/to/pg_config build ... or with the pg_config option in 'setup.cfg'. Complete output from command python setup.py egg_info: running egg_info creating pip-egg-info\psycopg2.egg-info writing pip-egg-info\psycopg2.egg-info\PKG-INFO writing top-level names to pip-egg-info\psycopg2.egg-info\top_level.txt writing dependency_links to pip-egg-info\psycopg2.egg-info\dependency_links.txt writing manifest file 'pip-egg-info\psycopg2.egg-info\SOURCES.txt' warning: manifest_maker: standard file '-c' not found I've googled the error and it seems you need libpq-dev python-dev as dependencies for postgres under Python. I also turned up a link that says you gt into trouble if you don't have the postgres bin folder in your Path so I installed Postgres manually and tried again. This time I get: error: Unable to find vcvarsall.bat I am still a python N00b so I am lost. Could someone point me in a general direction?

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  • Django: Storing ordered, arbitrary references

    - by Sarah
    I'm new to Django, and I'm not sure what I want is possible: I have a number of items that I want each AppUser (extended User model) to be able to reference. That is, given an AppUser, I want to be able to extract its list of items in the way that AppUser has chosen to order them. In general, these items would actually be references to something else in the database, and this led me to one possible solution: Store the keys for the given objects in a CommaSeparatedIntegerField in AppUser. This way, a user could have stored {7, 3, 232, 42, 1} in their items field and both the references and their preferred order would be stored. However, this feels hacky. Since most db backends store CommaSeparatedIntegerField as a VARCHAR internally, the user is not only limited by a number of objects, but also the number of digits in their chosen items. Eg. "you may store 10 items if you choose items with itemID < 10, but only 5 items if 10 < itemID < 100". Is there a better way to do this?

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  • Creating dynamic icons based on data entered into database from django forms

    - by John Hoke
    So I'm using Django to create a projects page with multiple forms for each project. Let's call them form 1, 2, 3, and 4. Once you create a project you can fill out any of these forms. I want to create "buttons" or links for each one of the forms that would show up on the main page. Now this is the part I need help with: Step 1. I want it so that if you click on a button for a form (say form 1) and none exists for that project yet a pop up would come up saying "This form does not exist yet, are you sure you want to create one?". And if you'd answer yes you would be directed to the form page. Step 2. But if that form does exist, I don't want any pop up to open and I want the link to take the user directly to that page. Step 3. My next problem is this. These forms are in order, so if you didn't create form 1 but created form 2, I don't want to give the user access to form 1. So in this scenario, if you click on form 1 I want a pop up to open and say "This form can no longer be created", and the link wouldn't function anymore. Basically the button will have 3 function. First it should look at the database and if data for that specific form exists it should do "Step 2", if data for that form and the proceeding forms don't exist it should do "Step 1", and if data for that form doesn't exist but data for proceeding form's does exist is should do "Step 3". Is this possible? Please help as I need to find a solution to this soon. Any help would be highly appreciated. Thank you

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  • Django - Weird behaviour of sessions variables with Apache

    - by Étienne Loks
    In a Menu class with Section children, each Section has an available attribute. This attribute is initialized during the instance creation. The process of getting the availability is not trivial, so I stock a Menu instance for each user in a session variable. With the Django embedded webserver this works well. But when I deploy the application on an Apache webserver I can observe a very weird behavior. Once authentified, a click on a link or a refreshment of the page and the availability of each Section seems to be forgotten (empty menu but in the log file I can see that all Sections are here) then a new refresh on the page the availability is back, a new refresh the menu disappears once again, etc. There is no cache activated on the web server. The menu is initialized in a context processor. def get_base_context(request): if 'MENU' not in request.session or \ not request.session['MENU'].childs or\ request.session['MENU'].user != request.user: _menu = Menu(request.user) _menu.init() request.session['MENU'] = _menu (...) I have no idea what could cause such a behavior. Any clue?

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  • Adjacency List Tree Using Recursive WITH (Postgres 8.4) instead of Nested Set

    - by Koobz
    I'm looking for a Django tree library and doing my best to avoid Nested Sets (they're a nightmare to maintain). The cons of the adjacency list model have always been an inability to fetch descendants without resorting to multiple queries. The WITH clause in Postgres seems like a solid solution to this problem. Has anyone seen any performance reports regarding WITH vs. Nested Set? I assume the Nested set will still be faster but as long as they're in the same complexity class, I could swallow a 2x performance discrepancy. Django-Treebeard interests me. Does anyone know if they've implemented the WITH clause when running under Postgres? Has anyone here made the switch away from Nested Sets in light of the WITH clause?

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  • How Can I Populate Default Form Data with a ManyToMany Field?

    - by b14ck
    Ok, I've been crawling google and Django documentation for over 2 hours now (as well as the IRC channel on freenode), and haven't been able to figure this one out. Basically, I have a model called Room, which is displayed below: class Room(models.Model): """ A `Partyline` room. Rooms on the `Partyline`s are like mini-chatrooms. Each room has a variable amount of `Caller`s, and usually a moderator of some sort. Each `Partyline` has many rooms, and it is common for `Caller`s to join multiple rooms over the duration of their call. """ LIVE = 0 PRIVATE = 1 ONE_ON_ONE = 2 UNCENSORED = 3 BULLETIN_BOARD = 4 CHILL = 5 PHONE_BOOTH = 6 TYPE_CHOICES = ( ('LR', 'Live Room'), ('PR', 'Private Room'), ('UR', 'Uncensored Room'), ) type = models.CharField('Room Type', max_length=2, choices=TYPE_CHOICES) number = models.IntegerField('Room Number') partyline = models.ForeignKey(Partyline) owner = models.ForeignKey(User, blank=True, null=True) bans = models.ManyToManyField(Caller, blank=True, null=True) def __unicode__(self): return "%s - %s %d" % (self.partyline.name, self.type, self.number) I've also got a forms.py which has the following ModelForm to represent my Room model: from django.forms import ModelForm from partyline_portal.rooms.models import Room class RoomForm(ModelForm): class Meta: model = Room I'm creating a view which allows administrators to edit a given Room object. Here's my view (so far): def edit_room(request, id=None): """ Edit various attributes of a specific `Room`. Room owners do not have access to this page. They cannot edit the attributes of the `Room`(s) that they control. """ room = get_object_or_404(Room, id=id) if not room.is_owner(request.user): return HttpResponseForbidden('Forbidden.') if is_user_type(request.user, ['admin']): form_type = RoomForm elif is_user_type(request.user, ['lm']): form_type = LineManagerEditRoomForm elif is_user_type(request.user, ['lo']): form_type = LineOwnerEditRoomForm if request.method == 'POST': form = form_type(request.POST, instance=room) if form.is_valid(): if 'owner' in form.cleaned_data: room.owner = form.cleaned_data['owner'] room.save() else: defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id} if room.owner: defaults['owner'] = room.owner.id if room.bans: defaults['bans'] = room.bans.all() ### this does not work properly! form = form_type(defaults, instance=room) variables = RequestContext(request, {'form': form, 'room': room}) return render_to_response('portal/rooms/edit.html', variables) Now, this view works fine when I view the page. It shows all of the form attributes, and all of the default values are filled in (when users do a GET)... EXCEPT for the default values for the ManyToMany field 'bans'. Basically, if an admins clicks on a Room object to edit, the page they go to will show all of the Rooms default values except for the 'bans'. No matter what I do, I can't find a way to get Django to display the currently 'banned users' for the Room object. Here is the line of code that needs to be changed (from the view): defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id} if room.owner: defaults['owner'] = room.owner.id if room.bans: defaults['bans'] = room.bans.all() ### this does not work properly! There must be some other syntax I have to use to specify the default value for the 'bans' field. I've really been pulling my hair out on this one, and would definitely appreciate some help. Thanks!

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