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  • Wordpress Permissions OS X & MAMP

    - by Matt2020
    I have installed several local versions of Wordpress for development purposes. After the install I can create posts, pages and edit admin options. However as soon as try to upload images which would be saved in wp_content/uploads I get an error: Upload Error: Unable to create directory ...../blog/wp-content/uploads/2011/05. Is its parent directory writable by the server? Looks like MAMP server runs as user _www The blog directory is owned by User1 and the group User1 _www is not in the User1 group, should it be? I do not want to chmod 777 or 765 on the directories just to get it going. Googled up a couple of references: http://codex.wordpress.org/Changing_File_Permissions in "Permission Scheme for WordPress" All files should be owned by your user (ftp) account on your web server, and should be writable by that account. On shared hosts, files should never be owned by the webserver process itself (sometimes this is www, or apache, or nobody user). Any file that needs write access from WordPress should be owned or group-owned by the user account used by the WordPress (which may be different than the server account). For example, you may have a user account that lets you FTP files back and forth to your server, but your server itself may run using a separate user, in a separate usergroup, such as dhapache or nobody. If WordPress is running as the FTP account, that account needs to have write access, i.e., be the owner of the files, or belong to a group that has write access. In the latter case, that would mean permissions are set more permissively than default (for example, 775 rather than 755 for folders, and 664 instead of 644). User and group are User1 (which is admin). Running "ps aux | grep httpd" is running as _www So I think this means Wordpress is running as user _www. So the advice seems contradictory: "files should never be owned by the webserver process" i.e. _www but then later it says "Any file that needs write access from WordPress should be owned or group-owned by the user account used by the WordPress" So isn't this _www again? Another search found this url http://dancingengineer.com/computing/2009/07/how-to-install-wordpress-on-mac-os-x-leopard States Which says: My preferred way to do this is to change the group of the wordpress directory and its contents to _www and give write permissions to the group. Keep the owner as your "username". $ cd /Users/"username"/Sites $ sudo chown -R username:_www wordpress_directory $ sudo chmod -R g+w wordpress_directory However, when I tried this, it did not work for automatic upgrades to newer versions of WordPress although it worked for automatically updating the .htaccess file for pretty permalinks. It is not entirely clear to me what should be done. This last suggestion seems to be saying change the group from User1 to _www and give the group write access, but Wordpress upgrades won't work. Is this the right solution? I would have thought there would be a clear way to set this up on OS X 10.6? Be great if there was a plugin that could run a script for each of the main OS's that Wordpress runs on.

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  • Samba with Active Directory - shares are readonly, NT_STATUS_MEDIA_WRITE_PROTECTED

    - by froh42
    I've set a samba server that seems to work, all shares are seemingly exported as readonly, however. The machine is called "lx". When I'm on lx I can run the following command: froh@lx:~$ smbclient //lx/export -UAdministrator Enter Administrator's password: Domain=[CUSTOMER] OS=[Unix] Server=[Samba 3.5.4] smb: \> mkdir wrzlbrmpf NT_STATUS_MEDIA_WRITE_PROTECTED making remote directory \wrzlbrmpf smb: \> ls . D 0 Fri Dec 3 19:04:20 2010 .. D 0 Sun Nov 28 01:32:37 2010 zork D 0 Fri Dec 3 18:53:33 2010 bar D 0 Sun Nov 28 23:52:43 2010 ork 1 Fri Dec 3 18:53:02 2010 foo 1 Sun Nov 28 23:52:41 2010 gaga D 0 Fri Dec 3 19:04:20 2010 How can I troubleshoot this? What I did: First I set up a fresh install of Ubuntu 10.10 x64. Second I got kerberos working with the following krb5.conf file: [libdefaults] ticket_lifetime = 24000 clock_skew = 300 default_realm = CUSTOMER.LOCAL [realms] CUSTOMER.LOCAL = { kdc = SB4.customer.local:88 admin_server = SB4.customer.local:464 default_domain = CUSTOMER.LOCAL } [domain_realm] .customer.local = CUSTOMER.LOCAL customer.local = CUSTOMER.LOCAL #[login] # krb4_convert = true # krb4_get_tickets = false I also added winbind to group, passwd and shadow in nsswitch.conf. Seemingly Kerberos works: root@lx:~# net ads testjoin Join is OK root@lx:~# wbinfo -a 'Administrator%MYSECRETPASSWORD' plaintext password authentication succeeded challenge/response password authentication succeeded wbinfo -u and wbinfo -g also spit out a list of users and a list of groups respectiveley. I noted that domain accounts did NOT include a domain and they are in german (as on the SBS 2003 that is the domain server). So I get a "Domänenbenutzer" in wbinfo -u's output not a "CUSTOMER+Domain User" or something similar. I'm not sure anymore what I did to the PAM configuration, but here is what I currently have: root@lx:/etc/pam.d# cat samba @include common-auth @include common-account @include common-session-noninteractive root@lx:/etc/pam.d# grep -ve '^#' common-auth auth [success=3 default=ignore] pam_krb5.so minimum_uid=1000 auth [success=2 default=ignore] pam_unix.so nullok_secure try_first_pass auth [success=1 default=ignore] pam_winbind.so krb5_auth krb5_ccache_type=FILE cached_login try_first_pass auth requisite pam_deny.so auth required pam_permit.so root@lx:/etc/pam.d# grep -ve '^#' common-account account [success=2 new_authtok_reqd=done default=ignore] pam_unix.so account [success=1 new_authtok_reqd=done default=ignore] pam_winbind.so account requisite pam_deny.so account required pam_permit.so account required pam_krb5.so minimum_uid=1000 root@lx:/etc/pam.d# grep -ve '^#' common-session-noninteractive session [default=1] pam_permit.so session requisite pam_deny.so session required pam_permit.so session optional pam_krb5.so minimum_uid=1000 session required pam_unix.so session optional pam_winbind.so At some point I joined the linux box into the AD domain. After (manually) creating a home directory on the linux box I can log in using the Adminstrator user with the password taken from AD. Now I run samba with the following setup: [global] netbios name = LX realm = CUSTOMER.LOCAL workgroup = CUSTOMER security = ADS encrypt passwords = yes password server = 192.168.20.244 #IP des Domain Controllers os level = 0 socket options = TCP_NODELAY SO_RCVBUF=16384 SO_SNDBUF=16384 idmap uid = 10000-20000 idmap gid = 10000-20000 winbind enum users = Yes winbind enum groups = Yes preferred master = no winbind separator = + dns proxy = no wins proxy = no # client NTLMv2 auth = Yes log level = 2 logfile = /var/log/samba/log.smbd.%U template homedir = /home/%U template shell = /bin/bash [export] path = /mnt/sdc1/export read only = No public = Yes Currently I don't care whether export is exported to everyone or just one user, I want to see somebody WRITING to that directory before I start fiddling with the authentication settings. (Who may access it). As mentioned, accessing the share from smbclient results in this NT_STATUS_MEDIA_WRITE_PROTECTED . Accessing it from windows shows ACLs that look correct (The user may write) - but it does not work, I can only read files not write. The directory to be exported looks like this: root@lx:/etc/pam.d# ls -ld /mnt/ drwxr-xr-x 5 root root 4096 2010-11-28 01:29 /mnt/ root@lx:/etc/pam.d# ls -ld /mnt/sdc1/ drwxr-xr-x 4 froh froh 4096 2010-11-28 01:32 /mnt/sdc1/ root@lx:/etc/pam.d# ls -ld /mnt/sdc1/export/ drwxrwxrwx+ 5 administrator domänen-admins 4096 2010-12-03 19:04 /mnt/sdc1/export/ root@lx:/etc/pam.d# getfacl /mnt/ getfacl: Entferne führende '/' von absoluten Pfadnamen # file: mnt/ # owner: root # group: root user::rwx group::r-x other::r-x root@lx:/etc/pam.d# getfacl /mnt/sdc1/ getfacl: Entferne führende '/' von absoluten Pfadnamen # file: mnt/sdc1/ # owner: froh # group: froh user::rwx group::r-x other::r-x root@lx:/etc/pam.d# getfacl /mnt/sdc1/export/ getfacl: Entferne führende '/' von absoluten Pfadnamen # file: mnt/sdc1/export/ # owner: administrator # group: domänen-admins user::rwx group::rwx group:domänen-admins:rwx mask::rwx other::rwx default:user::rwx default:group::rwx default:group:domänen-admins:rwx default:mask::rwx default:other::rwx My, oh my what am I overlooking? What am I to blind to see?

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  • Samba with Active Directory - shares are readonly, NT_STATUS_MEDIA_WRITE_PROTECTED

    - by froh42
    I've set a samba server that seems to work, all shares are seemingly exported as readonly, however. The machine is called "lx". When I'm on lx I can run the following command: froh@lx:~$ smbclient //lx/export -UAdministrator Enter Administrator's password: Domain=[CUSTOMER] OS=[Unix] Server=[Samba 3.5.4] smb: \> mkdir wrzlbrmpf NT_STATUS_MEDIA_WRITE_PROTECTED making remote directory \wrzlbrmpf smb: \> ls . D 0 Fri Dec 3 19:04:20 2010 .. D 0 Sun Nov 28 01:32:37 2010 zork D 0 Fri Dec 3 18:53:33 2010 bar D 0 Sun Nov 28 23:52:43 2010 ork 1 Fri Dec 3 18:53:02 2010 foo 1 Sun Nov 28 23:52:41 2010 gaga D 0 Fri Dec 3 19:04:20 2010 How can I troubleshoot this? What I did: First I set up a fresh install of Ubuntu 10.10 x64. Second I got kerberos working with the following krb5.conf file: [libdefaults] ticket_lifetime = 24000 clock_skew = 300 default_realm = CUSTOMER.LOCAL [realms] CUSTOMER.LOCAL = { kdc = SB4.customer.local:88 admin_server = SB4.customer.local:464 default_domain = CUSTOMER.LOCAL } [domain_realm] .customer.local = CUSTOMER.LOCAL customer.local = CUSTOMER.LOCAL #[login] # krb4_convert = true # krb4_get_tickets = false I also added winbind to group, passwd and shadow in nsswitch.conf. Seemingly Kerberos works: root@lx:~# net ads testjoin Join is OK root@lx:~# wbinfo -a 'Administrator%MYSECRETPASSWORD' plaintext password authentication succeeded challenge/response password authentication succeeded wbinfo -u and wbinfo -g also spit out a list of users and a list of groups respectiveley. I noted that domain accounts did NOT include a domain and they are in german (as on the SBS 2003 that is the domain server). So I get a "Domänenbenutzer" in wbinfo -u's output not a "CUSTOMER+Domain User" or something similar. I'm not sure anymore what I did to the PAM configuration, but here is what I currently have: root@lx:/etc/pam.d# cat samba @include common-auth @include common-account @include common-session-noninteractive root@lx:/etc/pam.d# grep -ve '^#' common-auth auth [success=3 default=ignore] pam_krb5.so minimum_uid=1000 auth [success=2 default=ignore] pam_unix.so nullok_secure try_first_pass auth [success=1 default=ignore] pam_winbind.so krb5_auth krb5_ccache_type=FILE cached_login try_first_pass auth requisite pam_deny.so auth required pam_permit.so root@lx:/etc/pam.d# grep -ve '^#' common-account account [success=2 new_authtok_reqd=done default=ignore] pam_unix.so account [success=1 new_authtok_reqd=done default=ignore] pam_winbind.so account requisite pam_deny.so account required pam_permit.so account required pam_krb5.so minimum_uid=1000 root@lx:/etc/pam.d# grep -ve '^#' common-session-noninteractive session [default=1] pam_permit.so session requisite pam_deny.so session required pam_permit.so session optional pam_krb5.so minimum_uid=1000 session required pam_unix.so session optional pam_winbind.so At some point I joined the linux box into the AD domain. After (manually) creating a home directory on the linux box I can log in using the Adminstrator user with the password taken from AD. Now I run samba with the following setup: [global] netbios name = LX realm = CUSTOMER.LOCAL workgroup = CUSTOMER security = ADS encrypt passwords = yes password server = 192.168.20.244 #IP des Domain Controllers os level = 0 socket options = TCP_NODELAY SO_RCVBUF=16384 SO_SNDBUF=16384 idmap uid = 10000-20000 idmap gid = 10000-20000 winbind enum users = Yes winbind enum groups = Yes preferred master = no winbind separator = + dns proxy = no wins proxy = no # client NTLMv2 auth = Yes log level = 2 logfile = /var/log/samba/log.smbd.%U template homedir = /home/%U template shell = /bin/bash [export] path = /mnt/sdc1/export read only = No public = Yes Currently I don't care whether export is exported to everyone or just one user, I want to see somebody WRITING to that directory before I start fiddling with the authentication settings. (Who may access it). As mentioned, accessing the share from smbclient results in this NT_STATUS_MEDIA_WRITE_PROTECTED . Accessing it from windows shows ACLs that look correct (The user may write) - but it does not work, I can only read files not write. The directory to be exported looks like this: root@lx:/etc/pam.d# ls -ld /mnt/ drwxr-xr-x 5 root root 4096 2010-11-28 01:29 /mnt/ root@lx:/etc/pam.d# ls -ld /mnt/sdc1/ drwxr-xr-x 4 froh froh 4096 2010-11-28 01:32 /mnt/sdc1/ root@lx:/etc/pam.d# ls -ld /mnt/sdc1/export/ drwxrwxrwx+ 5 administrator domänen-admins 4096 2010-12-03 19:04 /mnt/sdc1/export/ root@lx:/etc/pam.d# getfacl /mnt/ getfacl: Entferne führende '/' von absoluten Pfadnamen # file: mnt/ # owner: root # group: root user::rwx group::r-x other::r-x root@lx:/etc/pam.d# getfacl /mnt/sdc1/ getfacl: Entferne führende '/' von absoluten Pfadnamen # file: mnt/sdc1/ # owner: froh # group: froh user::rwx group::r-x other::r-x root@lx:/etc/pam.d# getfacl /mnt/sdc1/export/ getfacl: Entferne führende '/' von absoluten Pfadnamen # file: mnt/sdc1/export/ # owner: administrator # group: domänen-admins user::rwx group::rwx group:domänen-admins:rwx mask::rwx other::rwx default:user::rwx default:group::rwx default:group:domänen-admins:rwx default:mask::rwx default:other::rwx My, oh my what am I overlooking? What am I to blind to see?

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  • Free SQL Server training? Now you’re talking.

    - by Fatherjack
    SQL Server user groups are everywhere, literally all over the globe there are SQL Server professionals meeting on a regular basis, sharing ideas, solving problems, learning about how to do new stuff and new ways to do old stuff and it’s all for free. I don’t have detailed figures but of all the SQL Server professionals there are only a small number of them attend these user groups. Those people are the people that are taking the time and making then effort to make themselves better at their chosen trade, more employable and having a good time. For free. I don’t know why but there are many people that don’t seem to want to be the best they can be. Some of you enlightened people that do already attend could be doing more though. Have you ever spoken at  your group? Not just in the break while you have a mouthful of pizza and a drink in your hand but had the attention of the whole group listen to you speak. It doesn’t need to be a full hour, it doesn’t need to be some obscure deeply technical demonstration of SQL Server internals, just a few minutes on something that you do that might help other people with their daily work. A neat process that helps you get from Problem A to Solution B. There is no need to get concerned that becoming a speaker means that you suddenly have to know more than anyone else in the room. This is you talking about something that you experienced. What you did, what you would repeat, what you might do differently next time. No one in the audience can pick you up on a technicality. If someone comes out with a great idea that you hadn’t thought of, say “That’s a great idea, I didn’t think of that while we had the problem on our hands. I’ll try to remember that for next time”. If someone is looking to show you up for picking the wrong decision (and this, in my experience, is very uncommon indeed) then you simply give a reply like “Well, at the time we chose that option. Perhaps another time then we would tackle things differently but we were happy with how our solution worked”. It’s sharing things like this that makes user groups have a real value, talking about how you coped with or averted a disaster, a handy little section of code or using a tool in a particular way that you take for granted that might, just might, be something that other people haven’t thought of that solves a problem or saves some time for them. At the next meeting you might get the same benefit from a different person and so it goes on. As individuals benefits so the community benefits. For free. Things I encourage you to do; If you are a chapter or user group leader; encourage someone from your group who has never spoken before to start speaking. If you are a chapter or user group attendee that hasn’t spoken before; speak for at least 5 minutes on something related to SQL Server at any group meeting. If you don’t currently attend a user group; please go along to you nearest one when they are meeting next and invest in yourself and your future. UK user group details are here: http://sqlsouthwest.co.uk/national_ug.htm , PASS chapters outside the UK are found via http://www.sqlpass.org/PASSChapters/LocalChapters.aspx. If you are unsure of how you might achieve any of these things then get in touch with me*, I’ll give you specific advice on getting started on any of the above points and help you prove to yourself what you are capable of. SQL Community – be part of it and make it better. Let me know how you get on in the comments.

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  • Dual Screen will only mirror after 12.04 upgrade

    - by Ne0
    I have been using Ubuntu with a dual screen for years now, after upgrading to 12.04 LTS i cannot get my dual screen working properly Graphics: 01:00.0 VGA compatible controller: Advanced Micro Devices [AMD] nee ATI RV350 AR [Radeon 9600] 01:00.1 Display controller: Advanced Micro Devices [AMD] nee ATI RV350 AR [Radeon 9600] (Secondary) I noticed i was using open source drivers and attempted to install official binaries using the methods in this thread. Output: liam@liam-desktop:~$ sudo apt-get install fglrx fglrx-amdcccle Reading package lists... Done Building dependency tree Reading state information... Done The following packages will be upgraded: fglrx fglrx-amdcccle 2 upgraded, 0 newly installed, 0 to remove and 12 not upgraded. Need to get 45.1 MB of archives. After this operation, 739 kB of additional disk space will be used. Get:1 http://gb.archive.ubuntu.com/ubuntu/ precise/restricted fglrx i386 2:8.960-0ubuntu1 [39.2 MB] Get:2 http://gb.archive.ubuntu.com/ubuntu/ precise/restricted fglrx-amdcccle i386 2:8.960-0ubuntu1 [5,883 kB] Fetched 45.1 MB in 1min 33s (484 kB/s) (Reading database ... 328081 files and directories currently installed.) Preparing to replace fglrx 2:8.951-0ubuntu1 (using .../fglrx_2%3a8.960-0ubuntu1_i386.deb) ... Removing all DKMS Modules Error! There are no instances of module: fglrx 8.951 located in the DKMS tree. Done. Unpacking replacement fglrx ... Preparing to replace fglrx-amdcccle 2:8.951-0ubuntu1 (using .../fglrx-amdcccle_2%3a8.960-0ubuntu1_i386.deb) ... Unpacking replacement fglrx-amdcccle ... Processing triggers for ureadahead ... ureadahead will be reprofiled on next reboot Setting up fglrx (2:8.960-0ubuntu1) ... update-alternatives: warning: forcing reinstallation of alternative /usr/lib/fglrx/ld.so.conf because link group i386-linux-gnu_gl_conf is broken. update-alternatives: warning: skip creation of /etc/OpenCL/vendors/amdocl64.icd because associated file /usr/lib/fglrx/etc/OpenCL/vendors/amdocl64.icd (of link group i386-linux-gnu_gl_conf) doesn't exist. update-alternatives: warning: skip creation of /usr/lib32/libaticalcl.so because associated file /usr/lib32/fglrx/libaticalcl.so (of link group i386-linux-gnu_gl_conf) doesn't exist. update-alternatives: warning: skip creation of /usr/lib32/libaticalrt.so because associated file /usr/lib32/fglrx/libaticalrt.so (of link group i386-linux-gnu_gl_conf) doesn't exist. update-alternatives: warning: forcing reinstallation of alternative /usr/lib/fglrx/ld.so.conf because link group i386-linux-gnu_gl_conf is broken. update-alternatives: warning: skip creation of /etc/OpenCL/vendors/amdocl64.icd because associated file /usr/lib/fglrx/etc/OpenCL/vendors/amdocl64.icd (of link group i386-linux-gnu_gl_conf) doesn't exist. update-alternatives: warning: skip creation of /usr/lib32/libaticalcl.so because associated file /usr/lib32/fglrx/libaticalcl.so (of link group i386-linux-gnu_gl_conf) doesn't exist. update-alternatives: warning: skip creation of /usr/lib32/libaticalrt.so because associated file /usr/lib32/fglrx/libaticalrt.so (of link group i386-linux-gnu_gl_conf) doesn't exist. update-initramfs: deferring update (trigger activated) update-initramfs: Generating /boot/initrd.img-3.2.0-25-generic-pae Loading new fglrx-8.960 DKMS files... Building only for 3.2.0-25-generic-pae Building for architecture i686 Building initial module for 3.2.0-25-generic-pae Done. fglrx: Running module version sanity check. - Original module - No original module exists within this kernel - Installation - Installing to /lib/modules/3.2.0-25-generic-pae/updates/dkms/ depmod....... DKMS: install completed. update-initramfs: deferring update (trigger activated) Processing triggers for bamfdaemon ... Rebuilding /usr/share/applications/bamf.index... Setting up fglrx-amdcccle (2:8.960-0ubuntu1) ... Processing triggers for initramfs-tools ... update-initramfs: Generating /boot/initrd.img-3.2.0-25-generic-pae Processing triggers for libc-bin ... ldconfig deferred processing now taking place liam@liam-desktop:~$ sudo aticonfig --initial -f aticonfig: No supported adapters detected When i attempt to get my settings back to what they were before upgrading i get this message requested position/size for CRTC 81 is outside the allowed limit: position=(1440, 0), size=(1440, 900), maximum=(1680, 1680) and GDBus.Error:org.gtk.GDBus.UnmappedGError.Quark._gnome_2drr_2derror_2dquark.Code3: requested position/size for CRTC 81 is outside the allowed limit: position=(1440, 0), size=(1440, 900), maximum=(1680, 1680) Any idea's on what i need to do to fix this issue?

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  • Squid 2.7.STABLE3-4.1 as a transparent proxy on Ubuntu Server 9.04

    - by E3 Group
    Can't get this to work at all! I'm trying to get this linux box to act as a transparent proxy and, with the help of DHCP, force everyone on the network to gate into the proxy. I have two ethernet connections, both to the same switch. And I'm trying to get 192.168.1.234 to become the default gateway. The actual WAN connection is to a gateway 192.168.1.1. eth0 is 192.168.1.234 eth1 is 192.168.1.2 Effectively I'm trying to make eth0 a LAN only interface and eth1 a WAN interface. I've oi should set the gateway for eth1 to point to 192.168.1.234 my squid.conf file has the following directives added at the bottom: nly set eth0 to have a gateway address in /etc/network/interfaces I'm not sure whether http_port 3128 transparent acl lan src 192.168.1.0/24 acl lh src 127.0.0.1/255.255.255.0 http_access allow lan http_access allow lh i've added the following routing commands: iptables -t nat -A PREROUTING -i eth0 -p tcp -m tcp --dport 80 -j DNAT --to-destination 192.168.1.2:3128 iptables -t nat -A PREROUTING -i eth1 -p tcp -m tcp --dport 80 -j REDIRECT --to-ports 3128 I set a computer with TCP settings 192.168.1.234 as the gateway and opened up google.com, but it comes up with a request error. Any ideas why this isn't working? :( Been searching continuously for a solution to no avail. ----------------------------- EDIT ------------------------------- Managed to get it to route properly to the squid, here's the error I get in the browser: ERROR The requested URL could not be retrieved While trying to process the request: GET / HTTP/1.1 Host: www.google.com User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-GB; rv:1.9.1.2) Gecko/20090729 Firefox/3.5.2 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-gb,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 300 Connection: keep-alive Cache-Control: max-age=0 The following error was encountered: * Invalid Request Some aspect of the HTTP Request is invalid. Possible problems: * Missing or unknown request method * Missing URL * Missing HTTP Identifier (HTTP/1.0) * Request is too large * Content-Length missing for POST or PUT requests * Illegal character in hostname; underscores are not allowed Your cache administrator is webmaster. Generated Mon, 26 Oct 2009 03:41:15 GMT by mjolnir.lloydharrington.local (squid/2.7.STABLE3)

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  • Windows Server 2003 SBS domain in multiple sites

    - by E3 Group
    We have about 25 employees in our current office and are looking to open up another office in another capital city housing about 15 employees. In our current office, we are running a domain hosted by a 2003 SBS server and I've been tasked by the boss to expand our infrastructure to the new office in the cheapest way possible (cheapest way in the short run that is, because my boss doesn't think more than 6 months ahead). So I'm looking to get a second hand server and have it run Server 2003 Std with exchange server 2003. These are the things that it needs to do: Replicate shared folders that are hosted in the parent LAN. Deliver emails hosted in the parent Exchange Server Somehow link up with the parent domain controller and push the AD to the remote site I'm pretty sure 3 is impossible but the DC would be available if a VPN connection is present, right? On that note, would I be looking at hardware VPN connections? I'm not sure how to deploy the new site as this is my first time doing it and i'm making it especially difficult for myself, seeing as the AD and DC is on an SBS server. Would I first start by establishing a VPN connection and then joining the new server to the domain? Will things 'just work' if I install exchange onto the new server and point outlooks to it? and how would I be able to replicate shared folders?

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  • Looking for a new backup solution to replace dying tape drive

    - by E3 Group
    We're running Windows Server 2003 SBS and another machine with Server 2003 Standard on it. The SBS server is about 7 years old running pretty much 24/7 - a HP server of some description. We have an Ultrium 448 cycling LTO2 400GB tapes daily and incrementally backing up approximately 100gb worth of data (20gb C:\ and system state, 40gb exchange, 40gb database for some crap marketing software) on BackupExec 10D. As of 5 months ago, the backups have been consistently failing with IO errors, bad reads and some write errors. When I say consistent, I mean every time and we haven't had a proper backup for the entire 5 months - So if the server explodes tomorrow, 7 years worth of data will just cease to exist. I've only just recently rejoined the company and am looking at rectifying the more concerning problems, so the first thing I did was try a backup to an USB2.0 external drive. It was excruciatingly slow. In fact it was so slow it took 40 hours and it still wasn't finished. I ended up cancelling it and reconfiguring the selections again to reduce file size. This, however, isn't a permanent solution. I concluded that the IO error was either from a faulty tape drive (which has a tape stuck in there right now and not coming out) or from a dying SCSI controller. Neither of them are good news and both are extremely expensive to fix. I'm operating on an extremely low budget so have been looking at outsourcing the backups. A company in Sydney (where I'm located) offer incremental online backups via a NAS. It costs almost double a new tape drive but offers monthly repayments which will let us get through times when cash flow is minimal. It seems like a sweet deal but it is still a little bit pricey. So I'm looking for a cheaper, yet reliable solution. Maybe some in-house NAS or something offsite? The idea is to avoid using tapes. Are there any recommendations for rectifying my current situation? Or are tapes the only way to go? I'm concerned that the server will die one day in the near future and I must be able to restore it to another server with different hardware.

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  • Looking for a tagging media library application for Windows

    - by E3 Group
    I'm looking for a program that can: 1) index specific folders and capture video, music and picture files. 2) allow me to assign tags or categories to these files 3) allow me to search by tags or filenames I have a large collection of movies, music, etc that I want to categorise and tag with multiple tags. Haven't yet been able to find any applications that will do this for me.

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  • Select * from 'many to many' SQL relationship

    - by Rampant Creative Group
    I'm still learning SQL and my brain is having a hard time with this one. Say I have 3 tables: teams players and teams_players as my link table All I want to do is run a query to get each team and the players on them. I tried this: SELECT * FROM teams INNER JOIN teams_players ON teams.id = teams_players.team_id INNER JOIN players ON teams_players.player_id = players.id But it returned a separate row for each player on each team. Is JOIN the right way to do it or should I be doing something else? ----------------------------------------- Edit Ok, so from what I'm hearing, this isn't necessarily a bad way to do it. I'll just have to group the data by team while I'm doing my loop. I have not yet tried the modified SQL statements provided, but I will today and get back to you. To answer the question about structure - I guess I wasn't thinking about the returned row structure which is part of what lead to my confusion. In this particular case, each team is limited to 4 players (or less) so I guess the structure that would be helpful to me is something like the following: teams.id, teams.name, players.id, players.name, players.id, players.name, players.id, players.name, players.id, players.name, 1 Team ABC 1 Jim 2 Bob 3 Ned 4 Roy 2 Team XYZ 2 Bob 3 Ned 5 Ralph 6 Tom

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  • ODI 12c - Aggregating Data

    - by David Allan
    This posting will look at the aggregation component that was introduced in ODI 12c. For many ETL tool users this shouldn't be a big surprise, its a little different than ODI 11g but for good reason. You can use this component for composing data with relational like operations such as sum, average and so forth. Also, Oracle SQL supports special functions called Analytic SQL functions, you can use a specially configured aggregation component or the expression component for these now in ODI 12c. In database systems an aggregate transformation is a transformation where the values of multiple rows are grouped together as input on certain criteria to form a single value of more significant meaning - that's exactly the purpose of the aggregate component. In the image below you can see the aggregate component in action within a mapping, for how this and a few other examples are built look at the ODI 12c Aggregation Viewlet here - the viewlet illustrates a simple aggregation being built and then some Oracle analytic SQL such as AVG(EMP.SAL) OVER (PARTITION BY EMP.DEPTNO) built using both the aggregate component and the expression component. In 11g you used to just write the aggregate expression directly on the target, this made life easy for some cases, but it wan't a very obvious gesture plus had other drawbacks with ordering of transformations (agg before join/lookup. after set and so forth) and supporting analytic SQL for example - there are a lot of postings from creative folks working around this in 11g - anything from customizing KMs, to bypassing aggregation analysis in the ODI code generator. The aggregate component has a few interesting aspects. 1. Firstly and foremost it defines the attributes projected from it - ODI automatically will perform the grouping all you do is define the aggregation expressions for those columns aggregated. In 12c you can control this automatic grouping behavior so that you get the code you desire, so you can indicate that an attribute should not be included in the group by, that's what I did in the analytic SQL example using the aggregate component. 2. The component has a few other properties of interest; it has a HAVING clause and a manual group by clause. The HAVING clause includes a predicate used to filter rows resulting from the GROUP BY clause. Because it acts on the results of the GROUP BY clause, aggregation functions can be used in the HAVING clause predicate, in 11g the filter was overloaded and used for both having clause and filter clause, this is no longer the case. If a filter is after an aggregate, it is after the aggregate (not sometimes after, sometimes having).  3. The manual group by clause let's you use special database grouping grammar if you need to. For example Oracle has a wealth of highly specialized grouping capabilities for data warehousing such as the CUBE function. If you want to use specialized functions like that you can manually define the code here. The example below shows the use of a manual group from an example in the Oracle database data warehousing guide where the SUM aggregate function is used along with the CUBE function in the group by clause. The SQL I am trying to generate looks like the following from the data warehousing guide; SELECT channel_desc, calendar_month_desc, countries.country_iso_code,       TO_CHAR(SUM(amount_sold), '9,999,999,999') SALES$ FROM sales, customers, times, channels, countries WHERE sales.time_id=times.time_id AND sales.cust_id=customers.cust_id AND   sales.channel_id= channels.channel_id  AND customers.country_id = countries.country_id  AND channels.channel_desc IN   ('Direct Sales', 'Internet') AND times.calendar_month_desc IN   ('2000-09', '2000-10') AND countries.country_iso_code IN ('GB', 'US') GROUP BY CUBE(channel_desc, calendar_month_desc, countries.country_iso_code); I can capture the source datastores, the filters and joins using ODI's dataset (or as a traditional flow) which enables us to incrementally design the mapping and the aggregate component for the sum and group by as follows; In the above mapping you can see the joins and filters declared in ODI's dataset, allowing you to capture the relationships of the datastores required in an entity-relationship style just like ODI 11g. The mix of ODI's declarative design and the common flow design provides for a familiar design experience. The example below illustrates flow design (basic arbitrary ordering) - a table load where only the employees who have maximum commission are loaded into a target. The maximum commission is retrieved from the bonus datastore and there is a look using employees as the driving table and only those with maximum commission projected. Hopefully this has given you a taster for some of the new capabilities provided by the aggregate component in ODI 12c. In summary, the actions should be much more consistent in behavior and more easily discoverable for users, the use of the components in a flow graph also supports arbitrary designs and the tool (rather than the interface designer) takes care of the realization using ODI's knowledge modules. Interested to know if a deep dive into each component is interesting for folks. Any thoughts? 

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  • ?Linux 6???UDEV??RAC ASM???????

    - by Liu Maclean(???)
    Maclean?????UDEV??ASMLIB?RAC???????????,???????????????????:Why ASMLIB and why not???UDEV????RAC ASM?????  ?«??UDEV????RAC ASM????? »???????????????,????????udev rule????: for i in b c d e f g h i j k ; do echo "KERNEL==\"sd*\", BUS==\"scsi\", PROGRAM==\"/sbin/scsi_id -g -u -s %p\", RESULT==\"`scsi_id -g -u -s /block/sd$i`\", NAME=\"asm-disk$i\", OWNER=\"grid\", GROUP=\"asmadmin\", MODE=\"0660\"" done ?????Linux 5?????, ????????redhat/Oracle Linux 6???????????? ????: ?OEL6??RHEL6?,????????? ??????:1. scsi_id??????????,scsi_id -g -u -s??????????2. udevtest???????,????udevadm??How to use udev for Oracle ASM in Oracle Linux 6   ???????????,???redhat/Oracle Linux 6??????udev rule ????: 1. #????? Linux 6.0???? [root@vrh6 dev]# cat /etc/issue Oracle Linux Server release 6.2 Kernel \r on an \m 2. #?????/etc/scsi_id.config echo "options=--whitelisted --replace-whitespace" >> /etc/scsi_id.config 3. #?????????udev?? [root@vrh6 dev]# ls -l sd* brw-rw----. 1 root disk 8, 0 Jun 30 09:29 sda brw-rw----. 1 root disk 8, 1 Jun 30 09:29 sda1 brw-rw----. 1 root disk 8, 2 Jun 30 09:29 sda2 brw-rw----. 1 root disk 8, 16 Jun 30 09:29 sdb brw-rw----. 1 root disk 8, 32 Jun 30 09:29 sdc brw-rw----. 1 root disk 8, 48 Jun 30 09:29 sdd brw-rw----. 1 root disk 8, 64 Jun 30 09:29 sde brw-rw----. 1 root disk 8, 80 Jun 30 09:29 sdf ??????? sdb-> sdf???????? 4. ? b->f?????for ???,??: # AUTO UDEV RULE BY Maclean Liu 2012/06/30 for i in b c d e f ; do echo "KERNEL==\"sd*\", BUS==\"scsi\", PROGRAM==\"/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/\$name\", RESULT==\"`/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/sd$i`\", NAME=\"asm-disk$i\", OWNER=\"grid\", GROUP=\"asmadmin\", MODE=\"0660\"" done ????sdb->sdf ?????RULE,????RULE???/etc/udev/rules.d/99-oracle-asmdevices.rules? ??????????? ,??RULE?99-oracle-asmdevices.rules # AUTO UDEV RULE BY Maclean Liu 2012/06/30 for i in b c d e f ; do echo "KERNEL==\"sd*\", BUS==\"scsi\", PROGRAM==\"/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/\$name\", RESULT==\"`/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/sd$i`\", NAME=\"asm-disk$i\", OWNER=\"grid\", GROUP=\"asmadmin\", MODE=\"0660\"" >> /etc/udev/rules.d/99-oracle-asmdevices.rules done 5. ?????root??/sbin/start_udev ?? ??????: [root@vrh6 dev]# echo "options=--whitelisted --replace-whitespace" >> /etc/scsi_id.config [root@vrh6 dev]# for i in b c d e f ; > do > echo "KERNEL==\"sd*\", BUS==\"scsi\", PROGRAM==\"/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/\$name\", RESULT==\"`/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/sd$i`\", NAME=\"asm-disk$i\", OWNER=\"grid\", GROUP=\"asmadmin\", MODE=\"0660\"" >> /etc/udev/rules.d/99-oracle-asmdevices.rules > done [root@vrh6 dev]# [root@vrh6 dev]# cat /etc/udev/rules.d/99-oracle-asmdevices.rules KERNEL=="sd*", BUS=="scsi", PROGRAM=="/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/$name", RESULT=="1ATA_VBOX_HARDDISK_VB09cadb31-cfbea255", NAME="asm-diskb", OWNER="grid", GROUP="asmadmin", MODE="0660" KERNEL=="sd*", BUS=="scsi", PROGRAM=="/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/$name", RESULT=="1ATA_VBOX_HARDDISK_VB5f097069-59efb82f", NAME="asm-diskc", OWNER="grid", GROUP="asmadmin", MODE="0660" KERNEL=="sd*", BUS=="scsi", PROGRAM=="/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/$name", RESULT=="1ATA_VBOX_HARDDISK_VB4e1a81c0-20478bc4", NAME="asm-diskd", OWNER="grid", GROUP="asmadmin", MODE="0660" KERNEL=="sd*", BUS=="scsi", PROGRAM=="/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/$name", RESULT=="1ATA_VBOX_HARDDISK_VBdcce9285-b13c5a27", NAME="asm-diske", OWNER="grid", GROUP="asmadmin", MODE="0660" KERNEL=="sd*", BUS=="scsi", PROGRAM=="/sbin/scsi_id --whitelisted --replace-whitespace --device=/dev/$name", RESULT=="1ATA_VBOX_HARDDISK_VB82effe1a-dbca7dff", NAME="asm-diskf", OWNER="grid", GROUP="asmadmin", MODE="0660" [root@vrh6 dev]# [root@vrh6 dev]# /sbin/start_udev Starting udev: [ OK ] [root@vrh6 dev]# ls -l asm* brw-rw----. 1 grid asmadmin 8, 16 Jun 30 09:34 asm-diskb brw-rw----. 1 grid asmadmin 8, 32 Jun 30 09:34 asm-diskc brw-rw----. 1 grid asmadmin 8, 48 Jun 30 09:34 asm-diskd brw-rw----. 1 grid asmadmin 8, 64 Jun 30 09:34 asm-diske brw-rw----. 1 grid asmadmin 8, 80 Jun 30 09:34 asm-diskf

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  • QoS basics on a Cisco ASA

    - by qbn
    Could someone briefly explain how to use QoS on Cisco ASA 5505? I have the basics of policing down, but what about shaping and priorities? Basically what I'm trying to do is carve out some bandwidth for my VPN subnets (in an object-group called priority-traffic). I've seen this Cisco QoS document, however configuring shaping and priority-queue don't seem to have any effects in my test. A full download of the linux kernel from kernel.org will boost a ping to a server via VPN sky high. Policing has been successful in passing this test, although it doesn't seem as efficient (I cap non-vpn traffic at 3 of my 4.5 megabits of bandwidth). Am I misunderstanding the results of the test? I think there is some simple concept I'm not grasping here. EDIT: Here is my config thus far (I have 4.5 megabits of bandwidth): access-list priority-traffic extended permit ip object-group priority-traffic any access-list priority-traffic extended permit ip any object-group priority-traffic access-list priority-traffic extended permit icmp object-group priority-traffic any access-list priority-traffic extended permit icmp any object-group priority-traffic access-list non-priority-traffic extended deny ip object-group priority-traffic any access-list non-priority-traffic extended deny ip any object-group priority-traffic access-list non-priority-traffic extended permit ip any any priority-queue outside queue-limit 440 class-map non-priority-traffic match access-list non-priority-traffic class-map priority-traffic match access-list priority-traffic class-map inspection_default match default-inspection-traffic policy-map type inspect dns preset_dns_map parameters message-length maximum 512 policy-map global_policy class inspection_default inspect dns preset_dns_map inspect ftp inspect h323 h225 inspect h323 ras inspect rsh inspect rtsp inspect sqlnet inspect skinny inspect sunrpc inspect xdmcp inspect sip inspect netbios inspect tftp policy-map outbound-qos-policy class non-priority-traffic police input 2500000 police output 2500000 class priority-traffic priority service-policy global_policy global service-policy outbound-qos-policy interface outside

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  • Installing CDT on top of JDT: Conflicting Dependency

    - by someguy
    I am trying to install the CDT plugin on top my existing version of Eclipse, which was for Java. The problem is that I got this error message when I tried doing so via "Install New Software...": Cannot complete the install because of a conflicting dependency. Software being installed: Eclipse C/C++ Development Tools 4.0.3.200802251018 (org.eclipse.cdt.feature.group 4.0.3.200802251018) Software currently installed: Eclipse IDE for Java Developers 1.3.1.20100916-1202 (epp.package.java 1.3.1.20100916-1202) Only one of the following can be installed at once: International Components for Unicode for Java (ICU4J) 4.2.1.v20100412 (com.ibm.icu 4.2.1.v20100412) com.ibm.icu 3.6.1.v20070906 Cannot satisfy dependency: From: Eclipse IDE for Java Developers 1.3.1.20100916-1202 (epp.package.java 1.3.1.20100916-1202) To: org.eclipse.epp.package.java.feature.feature.group [1.3.1.20100916-1202] Cannot satisfy dependency: From: Eclipse C/C++ Development Tools 4.0.3.200802251018 (org.eclipse.cdt.feature.group 4.0.3.200802251018) To: com.ibm.icu [3.4.0,4.0.0) Cannot satisfy dependency: From: EPP Java Package 1.3.1.20100916-1202 (org.eclipse.epp.package.java.feature.feature.group 1.3.1.20100916-1202) To: org.eclipse.rcp.feature.group 3.6.0 Cannot satisfy dependency: From: Eclipse RCP 3.6.0.v20100519-9OArFKvFtsd7WLUKh-DcYTS (org.eclipse.rcp.feature.group 3.6.0.v20100519-9OArFKvFtsd7WLUKh-DcYTS) To: com.ibm.icu [4.2.1.v20100412] Cannot satisfy dependency: From: Eclipse RCP 3.6.1.r361_v20100827-9OArFLdFjY-ThSQXmKvKz0_T (org.eclipse.rcp.feature.group 3.6.1.r361_v20100827-9OArFLdFjY-ThSQXmKvKz0_T) To: com.ibm.icu [4.2.1.v20100412] What can I do to solve this?

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  • Matlab computations done over Apple Filing Protocol (AFP) depend on POSIX permissions, ignores ACLs

    - by flumignan
    I'm a system administrator and have never used Matlab, so forgive my general ignorance of the program. My users have encountered problems when executing scripted Matlab actions over AFP to a Mac OS X Server 10.6.7 where the access control list (ACL) should allow actions, but the POSIX-style permissions disallow the activity. It seems as if Matlab, run locally on the Mac workstations on datasets on the remote server, ignores the ACLs entirely. This is the only application I've ever seen behave this way. The server's filesystem is HFS+J and all other activity is performing as expected. These users cannot use CIFS because of our integration with external directory systems. In this example, the directory bxdata, the members of the group cibturner should be able to modify the files. Indeed, they can using any other method except via Matlab scripts. When the Matlab script hits these files, the POSIX permissions of 644 disallow modification. It's as if the ACLs are irrelevant. [root@cib 16:00:24 /14181.2_5sM]# ls -leh@ bxdata/ total 128 -rw-r--r--+ 1 kel32 staff 18K Feb 15 09:31 TS-5sMath030708-21073-1.edat 0: group:cibturner inherited allow read,write,execute,append,readattr,writeattr,readextattr,writeextattr,readsecurity,writesecurity,chown 1: group:cibsrlocaladmins inherited allow read,write,execute,append,readattr,writeattr,readextattr,writeextattr,readsecurity,writesecurity,chown 2: group:crcservergroup inherited allow read,write,execute,append,readattr,writeattr,readextattr,writeextattr,readsecurity,writesecurity,chown -rw-r--r--+ 1 kel32 staff 25K Feb 15 09:31 TS-5sMath030708-21073-1.txt 0: group:cibturner inherited allow read,write,execute,append,readattr,writeattr,readextattr,writeextattr,readsecurity,writesecurity,chown 1: group:cibsrlocaladmins inherited allow read,write,execute,append,readattr,writeattr,readextattr,writeextattr,readsecurity,writesecurity,chown 2: group:crcservergroup inherited allow read,write,execute,append,readattr,writeattr,readextattr,writeextattr,readsecurity,writesecurity,chown Because this server has HIPAA data, security is critical. We are not using networked home directories or SAN technology. The MatLab program is run on the user's hard drive; access is granted via Kerberized AFP.

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  • Advanced Linux file permission question (ownership change during write operation)

    - by Kent
    By default the umask is 0022: usera@cmp$ touch somefile; ls -l total 0 -rw-r--r-- 1 usera usera 0 2009-09-22 22:30 somefile The directory /home/shared/ is meant for shared files and should be owned by root and the shared group. Files created here by usern (any user) are automatically owned by the shared group. There is a cron-job taking care of changing owning user and owning group (of any moved files) once per day: usera@cmp$ cat /etc/cron.daily/sharedscript #!/bin/bash chown -R root:shared /home/shared/ chmod -R 770 /home/shared/ I was writing a really large file to the shared directory. It had me (usera) as owning user and the shared group as group owner. During the write operation the cron job was run, and I still had no problem completing the write process. You see. I thought this would happen: I am writing the file. The file permissions and ownership data for the file looks like this: -rw-r--r-- usera shared The cron job kicks in! The chown line is processed and now the file is owned by the root user and the shared group. As the owning group only has read access to the file I get a file write error! Boom! End of story. Why did the operation succeed? A link to some kind of reference documentation to back up the reason would be very welcome (as I could use it to study more details).

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  • How do I set up a shared directory on Linux?

    - by JR Lawhorne
    I have a linux server I want to use to share files between users in my company. Users will access the machine with sftp or secure shell. Here is what I have: cd /home ls -l drwxrwsr-x 5 userA staff 4096 Jul 22 15:00 shared (other listings omitted) I want all users in the staff group to be able to create, modify, delete any file and/or directory in the shared folder. I don't want anyone else to have access to the folder at all. I have: Added the users to the staff group by modifying /etc/group and running grpconv to update /etc/gshadow Run chown -R userA.staff /home/shared Run chmod -R 2775 /home/shared Now, users in the staff group can create new files but they aren't allowed to open the existing files in the directory for edit. I suspect this is due to the primary group id associated with each user which is still set to be the group created when the user was created. So, the PGID of user 'userA' is 'userA'. I'd rather not change the primary group of the users to 'staff' if I can help it but if it is the easiest option, I would consider it. And, a variation on a theme, I'd like to do this same thing with another directory but also allow the apache user to read files in the directory and serve them. What's the best way to set this up?

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  • Eclipse: Cannot install CDT because of a conflicting dependency

    - by MarkZar
    my eclipse has been configured for Java and pydev, now i want to configure C/C++ development tools with Eclipse. i dont want to download the whole Eclipse IDE for C/C++ Developers, for it is not convenient. so i decided to install CDT in my Eclipse. Help == Install New Software, then input http://download.eclipse.org/tools/cdt/releases/indigo, waited for a while, and chose the following CDT Main Features, CDT Optional Features, and Next, then an error occurred. Cannot complete the install because of a conflicting dependency. Software being installed: C/C++ DSF GDB Debugger Integration 4.0.0.201106081058 (org.eclipse.cdt.gnu.dsf.feature.group 4.0.0.201106081058) Software being installed: C/C++ Development Tools SDK 8.0.2.201202111925 (org.eclipse.cdt.sdk.feature.group 8.0.2.201202111925) Only one of the following can be installed at once: GDB DSF Debugger Integration Core 4.0.0.201106081058 (org.eclipse.cdt.dsf.gdb 4.0.0.201106081058) GDB DSF Debugger Integration Core 4.0.2.201202111925 (org.eclipse.cdt.dsf.gdb 4.0.2.201202111925) GDB DSF Debugger Integration Core 4.0.1.201109151620 (org.eclipse.cdt.dsf.gdb 4.0.1.201109151620) Cannot satisfy dependency: From: C/C++ Development Tools 8.0.2.201202111925 (org.eclipse.cdt.feature.group 8.0.2.201202111925) To: org.eclipse.cdt.gnu.dsf.feature.group [4.0.1.201202111925] Cannot satisfy dependency: From: C/C++ DSF GDB Debugger Integration 4.0.0.201106081058 (org.eclipse.cdt.gnu.dsf.feature.group 4.0.0.201106081058) To: org.eclipse.cdt.dsf.gdb [4.0.0.201106081058] Cannot satisfy dependency: From: C/C++ DSF GDB Debugger Integration 4.0.1.201202111925 (org.eclipse.cdt.gnu.dsf.feature.group 4.0.1.201202111925) To: org.eclipse.cdt.dsf.gdb [4.0.2.201202111925] Cannot satisfy dependency: From: C/C++ Development Tools SDK 8.0.2.201202111925 (org.eclipse.cdt.sdk.feature.group 8.0.2.201202111925) To: org.eclipse.cdt.feature.group [8.0.2.201202111925] i have googled for a lot of time, but still cannot find a valid solution. can anyone give a hand to me? thanks a lot!

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  • jquery creating stacked bar chart with flot?

    - by KittyYoung
    I'm using jquery flot and I'm trying to create a stacked bar chart, but I'm having some syntax issues... I'll post my code at the end of this, but I'm quite certain it's wrong. I do get a stacked bar chart, but there's only three columns... Basically, here is the data that I'm working with and what I want to accomplish... The first group (Focus Group 1) on each line is the bottom bar of the stacked bar, the second group (Focus Group 2) is the second, and the third group (Focus Group 3) is the top group. The "Responses" are what I want to use on the x-axis, the first number in each set is x, and the second number is y. Response1, [0, 0], [0,0], [0,9] Response2, [1, 5], [1,5], [1,11] Response3, [2, 2], [2,0], [2,8] Response4, [3, 1], [3,2], [3,6] Response5, [4, 0], [4,0], [4,7] I should also mention, that I'm not sure if a stacked chart is the best way to go... Admittedly, I'm not a very visual person, and generally find charts annoying... If there's a better way to present this data, then I am so totally open to suggestions... Essentially... I have a series of questions. Each of these questions were presented to three focus groups. Members of the focus groups selected a response. I'm trying to present the count per response, per focus group, for each question. I thought that a stacked chart would be the best way to go, but again, I'm open to other ways of doing this. The only thing is, I definitely need a visual representation of the data....

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  • script to find "deny" ACE in ACLs, and remove it

    - by Tom
    On my 100TB cluster, I need to find dirs and files that have a "deny" ACE within their ACL, then remove that ACE on each instance. I'm using the following: # find . -print0 | xargs -0 ls -led | grep deny -B4 and get this output (partial, for example only) -r--rw---- 1 chris GroupOne 4096 Mar 6 18:12 ./directoryA/fileX.txt OWNER: user:chris GROUP: group:GroupOne 0: user:chris allow file_gen_read,std_write_dac,file_write_attr 1: user:chris deny file_write,append,file_write_ext_attr,execute -- -r--rwxrwx 1 chris GroupOne 14728221 Mar 6 18:12 ./directoryA/subdirA/fileZ.txt OWNER: user:chris GROUP: group:GroupOne 0: user:chris allow file_gen_read,std_write_dac,file_write_attr 1: user:chris deny file_write,append,file_write_ext_attr,execute -- OWNER: user:bob GROUP: group:GroupTwo 0: user:bob allow dir_gen_read,dir_gen_write,dir_gen_execute,std_write_dac,delete_child,object_inherit,container_inherit 1: group:GroupTwo allow std_read_dac,std_write_dac,std_synchronize,dir_read_attr,dir_write_attr,object_inherit,container_inherit 2: group:GroupTwo deny list,add_file,add_subdir,dir_read_ext_attr,dir_write_ext_attr,traverse,delete_child,object_inherit,container_inherit -- As you can see, depending on where the "deny" ACE is, I can see/not-see the path. I could increase the -B value (I've seen up to 8 ACEs on a file) but then I would get more output to distill from... What I need to do next is extract $ACENUMBER and $PATHTOFILE so that I can execute this command: chmod -a# $ACENUMBER $PATHTOFILE Additional issue is that the find command (above) gives a relative path, whereas I need the full path. I guess that would need to be edited somehow. Any guidance on how to accomplish this?

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  • CakePHP's list problem

    - by jun
    Hi there. I have this table in my DB: Group - ID-Name - 1 -abc - 2 -def - 3 -ghi Pages - id-group_id-name - 1 -1 -home - 2 -1 -about us Now I wanted to make a select box that groups them by 'group' using: function add() { $this->set('pages', $this->Page->find('list', array('fields' => array('Page.id', 'Page.name', 'Page.group_id')))); } In my add.ctp: echo $form->input('group_id', array('options' => $pages)); The output: <select name="data[Page][id]" id="PageId"> <optgroup label="1"> <option value="1">Home</option> <option value="2">About Us</option> </optgroup> </select> I wanted the optgroup to display the actual group name not the group id like: <select name="data[Page][id]" id="PageId"> <optgroup label="abc"> <option value="1">Home</option> <option value="2">About Us</option> </optgroup> </select> I have tried this one: $this->Page->find('list', array('conditions' => 'Group.id = Page.id', 'fields' => array('Page.id', 'Page.name', 'Group.name'))); But 'Group.id' and 'Group.name' is unknown. Thanks!

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  • nhibernate error recovery

    - by Berryl
    I downloaded Rhino Security today and started going through some of the tests. Several that run perfectly in isolation start getting errors after one that purposely raises an exception runs though. Here is that test: [Test] public void EntitesGroup_CanCreate() { var group = _authorizationRepository.CreateEntitiesGroup("Accounts"); _session.Flush(); _session.Evict(group); var fromDb = _session.Get<EntitiesGroup>(group.Id); Assert.NotNull(fromDb); Assert.That(fromDb.Name, Is.EqualTo(group.Name)); } And here are the tests and error messages that fail: [Test] public void User_CanSave() { var ayende = new User {Name = "ayende"}; _session.Save(ayende); _session.Flush(); _session.Evict(ayende); var fromDb = _session.Get<User>(ayende.Id); Assert.That(fromDb, Is.Not.Null); Assert.That(ayende.Name, Is.EqualTo(fromDb.Name)); } ----> System.Data.SQLite.SQLiteException : Abort due to constraint violation column Name is not unique [Test] public void UsersGroup_CanCreate() { var group = _authorizationRepository.CreateUsersGroup("Admininstrators"); _session.Flush(); _session.Evict(group); var fromDb = _session.Get<UsersGroup>(group.Id); Assert.NotNull(fromDb); Assert.That(fromDb.Name, Is.EqualTo(group.Name)); } failed: NHibernate.AssertionFailure : null id in Rhino.Security.Tests.User entry (don't flush the Session after an exception occurs) Does anyone see how I can reset the state of the in memory SQLite db after the first test? I changed the code to use nunit instead of xunit so maybe that is part of the problem here as well. Cheers, Berryl

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  • Hibernate ManyToMany and superclass mapping problem

    - by Jesus Benito
    Hi all, I need to create a relation in Hibernate, linking three tables: Survey, User and Group. The Survey can be visible to a User or to a Group, and a Group is form of several Users. My idea was to create a superclass for User and Group, and create a ManyToMany relationship between that superclass and Survey. My problem is that Group, is not map to a table, but to a view, so I can't split the fields of Group among several tables -which would happen if I created a common superclass-. I thought about creating a common interface, but mapping to them is not allowed. I will probably end up going for a two relations solution (Survey-User and Survey-Group), but I don't like too much that approach. I thought as well about creating a table that would look like: Survey Id | ElementId | Type ElementId would be the Group or UserId, and the type... the type of it. Does anyone know how to achieve it using hibernate annotations? Any other ideas? Thanks a lot

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  • "filter" json through ajax (jquery)

    - by Hyung Suh
    I'm trying to filter the json array through ajax and not sure how to do so. { posts: [{"image":"images/bbtv.jpg", "group":"a"}, {"image":"images/grow.jpg", "group":"b"}, {"image":"images/tabs.jpg", "group":"a"}, {"image":"images/bia.jpg", "group":"b"}]} i want it so that i can only show items in group A or group B. how would i have to change my ajax to filter through the content? $.ajax({ type: "GET", url: "category/all.js", dataType: "json", cache: false, contentType: "application/json", success: function(data) { $('#folio').html("<ul/>"); $.each(data.posts, function(i,post){ $('#folio ul').append('<li><div class="boxgrid captionfull"><img src="' + post.image + '" /></div></li>'); }); initBinding(); }, error: function(xhr, status, error) { alert(xhr.status); } }); Also, how can I can I make each link process the filter? <a href="category/all.js">Group A</a> <a href="category/all.js">Group B</a> Sorry for all these questions, can't seem to find a solution.. Any help in the right direction would be appreciated. Thanks!

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  • Deleting objects with FK constraints in Spring/Hibernate

    - by maxdj
    This seems like such a simple scenario to me, yet I cannot for the life of my find a solution online or in print. I have several objects like so (trimmed down): @Entity public class Group extends BaseObject implements Identifiable<Long> { private Long id; private String name; private Set<HiringManager> managers = new HashSet<HiringManager>(); private List<JobOpening> jobs; @ManyToMany(fetch=FetchType.EAGER) @JoinTable( name="group_hiringManager", joinColumns=@JoinColumn(name="group_id"), inverseJoinColumns=@JoinColumn(name="hiringManager_id") ) public Set<HiringManager> getManagers() { return managers; } @OneToMany(mappedBy="group", fetch=FetchType.EAGER) public List<JobOpening> getJobs() { return jobs; } } @Entity public class JobOpening extends BaseObject implements Identifiable<Long> { private Long id; private String name; private Group group; @ManyToOne @JoinColumn(name="group_id", updatable=false, nullable=true) public Group getGroup() { return group; } } @Entity public class HiringManager extends User { @ManyToMany(mappedBy="managers", fetch=FetchType.EAGER) public Set<Group> getGroups() { return groups; } } Say I want to delete a Group object. Now there are dependencies on it in the JobOpening table and in the group_hiringManager table, which cause the delete function to fail. I don't want to cascade the delete, because the managers have other groups, and the jobopenings can be groupless. I have tried overriding the remove() function of my GroupManager to remove the dependencies, but it seems like no matter what I do they persist, and the delete fails! What is the right way to remove this object?

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