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  • ProtectedData.Unprotect() after Impersonate()

    - by Andrey
    The following code doesn't work: IntPtr token = Win32Dll.LogonUser(“user1”, “mydomain”, “password1”); WindowsIdentity id = new WindowsIdentity(token); WindowsImpersonationContext ic = id.Impersonate(); byte[] unprotectedBytes = ProtectedData.Unprotect(passwordBytes, null, DataProtectionScope.CurrentUser); password = Encoding.Unicode.GetString(unprotectedBytes); ic.Undo(); The password is not decrypted. MSDN said "If you use this method during impersonation, you may receive the following error: "Key not valid for use in specified state." This error can be prevented by loading the profile of the user you want to impersonate, before calling the method." I would be very grateful for the help!

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  • java.lang.NoClassDefFoundError: org/springframework/transaction/interceptor/TransactionInterceptor

    - by user1137146
    I am trying to integrate spring 3.1.1 with hibernate 4.0. This is my dispatcher-servlet.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:jee="http://www.springframework.org/schema/jee" xmlns:lang="http://www.springframework.org/schema/lang" xmlns:p="http://www.springframework.org/schema/p" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:util="http://www.springframework.org/schema/util" xmlns:mvc="http://www.springframework.org/schema/mvc" xsi:schemaLocation="http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd"> <context:component-scan base-package="com.future.controllers" /> <context:annotation-config /> <context:component-scan base-package="com.future.services.menu" /> <context:component-scan base-package="com.future.dao" /> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="com.mysql.jdbc.Driver" p:url="jdbc:mysql://localhost:3306/bar_visitor2" p:username="root" p:password=""/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/views/" /> <property name="suffix" value=".jsp" /> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="configLocation"> <value>classpath:hibernate.cfg.xml</value> </property> </bean> <tx:annotation-driven /> <bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory" /> </bean> When I try to use @Transactional annotation I am getting an error java.lang.NoClassDefFoundError: org/springframework/transaction/interceptor/TransactionInterceptor. I checked my classpath and there is TransactionInterceptor.class. What am I doing wrong? Should I add something? Edit This is my lib folder:

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  • Request for the permission of type 'System.Data.SqlClient.SqlClientPermission, System.Data

    - by joebeazelman
    I created an assembly containing WCF service code and dropped into another web project. When I try to invoke a service method, I get the following inner exception: Request for the permission of type 'System.Data.SqlClient.SqlClientPermission, System.Data, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' failed. Why this is happening? My newly created assembly lives inside the ASP.NET /bin folder along with other assemblies. At this level, should the database not know or care whether it is being called from a web service or from a normal call? How would it know that my assembly is foreign? How do I resolve this issue?

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  • Best way for a remote web app to authenticate users in my current web app?

    - by jklp
    So a bit of background, I'm working on an existing web application which has a set of users, who are able to log in via a traditional login screen with a user name and password, etc. Recently we've managed to score a client (who have their own Intranet site), who are wanting to be able to have their users log into their Intranet site, and then have their users click a link on their Intranet which redirects to our application and logs them into it automatically. I've had two suggestions on how to implement this so far: Create a URL which takes 2 parameters (which are "username" and "password") and have the Intranet site pass those parameters to us (our connection is via TLS so it's all encrypted). This would work fine, but it seems a little "hacky", and also means that the logins and passwords have to be the same on both systems (and having to write some kind of web service which can update the passwords for users - which also seems a bit insecure) Provide a token to the Intranet, so when the client clicks on a link on the Intranet, it sends the token to us, along with the user name (and no password) which means they're authenticated. Again, this sounds a bit hacky as isn't that essentially the same as providing everyone with the same password to log in? So to summarise, I'm after the following things: A way for the users who are already authenticated on the Intranet to log into our system without too much messing around, and without using an external system to authenticate, i.e. LDAP / Kerberos Something which isn't too specific to this client, and can easily be implemented by other Intranets to log in

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  • How do you override the WCF AuthenticationService IsLoggedIn() method?

    - by Ryan Riley
    I have three current thoughts on how to do this: re-implement AuthenticationService, which uses lots of internal constructors and internal helpers, implement custom IIdentity and IPrincipal types and somehow hook these into FormsAuthentication. give up and roll my own. The problem is that we've got web apps and fat client apps using authentication and storing cookies. However, logging out of a web app does not log out of a fat client app, and we have now way of forcing a refreshed cookie, atm.

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  • How to authenticate WCF calls using forms authentication and secutity

    - by Fixer
    I'm planning a set up for a distributed application that spans serveral machines and will use WCF to send data in between. Machine A Front end website http://www.site.com Password protected site using Forms Authentication Machine B WCF Application Service http://service1.site.com/DoSomething.svc Machine C WCF Application Service http://service2.site.com/DoSomething.svc The WCF services on Machine B and Machine C should check that the request from Machine A has been authenticated. How can i check that the request is authenticated across the different machines? I only care that the request is authenticated and not concerned about securing the message body (because we are not sending any sensitive data across the wire), so SSL is not required. What authentication methods can i use for the above scenario?

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  • How can I throttle user login attempts in PHP

    - by jasondavis
    I was just reading this post http://stackoverflow.com/questions/549/the-definitive-guide-to-website-authentication-beta#477585 on Preventing Rapid-Fire Login Attempts. Best practice #1: A short time delay that increases with the number of failed attempts, like: 1 failed attempt = no delay 2 failed attempts = 2 sec delay 3 failed attempts = 4 sec delay 4 failed attempts = 8 sec delay 5 failed attempts = 16 sec delay etc. DoS attacking this scheme would be very impractical, but on the other hand, potentially devastating, since the delay increases exponentially. I am curious how I could implement something like this for my login system in PHP?

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  • Using JavaScript eval to parse JSON

    - by Quandary
    Question: I'm using eval to parse a JSON return value from one of my WebMethods. I prefer not to add jquery-json because the transfer volume is already quite large. So I parse the JSON return value with eval. Now rumors go that this is insecure. Why ? Nobody can modify the JSOn return value unless they hack my server, in which case I would have a much larger problem anyway. And if they do it locally, JavaScript only executes in their browser. So I fail to see where the problem is. Can anybody shed some light on this, using this concrete example? function OnWebMethodSucceeded(JSONstrWebMethodReturnValue) { var result=eval('(' + JSONstrWebMethodReturnValue + ')') ... // Adding result.xy to a table }

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  • What are best practices for securing the admin section of a website?

    - by UpTheCreek
    I'd like to know what people consider best practice for securing the Admin sections of websites, specifically from an authentication/access point of view. Of course there are obvious things, such as using SSL and logging all access, but I'm wondering just where above these basic steps people consider the bar to be set. For example: Are you just relying on the same authentication mechanism that you use for normal users? If not, what? Are you running the Admin section in the same 'application domain'? What steps do you take to make the admin section undiscovered? (or do you reject the while 'obscurity' thing)

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  • How secure is a PostgreSQL database if my server is stolen?

    - by orokusaki
    If I have a server with a database if top secret data in PostgreSQL and my password is practically impossible to crack (128 character string of all sorts of weird chars, generated by hand). The server password is also uncrackable in theory (basically, ignore the possibility of a password crack on the DB). Aside from a password crack, how easy is it to get the data out of this database? Assumptions: Only the DB exists on the server. There is no password in a PHP script or anything like that The person who has the server is a computer / DB / hard-drive recovery expert I'm not using any hard-drive encryption or anything out of the norm for protection I'm trying to understand the risks involved with somebody gaining physical access to my server's hard-drives.

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  • Web Application Scanner

    - by rajesh
    I want to develop a Web applications to collect or exchange sensitive or personal data, this system would give user a detailed automated report on : • How secure user's website is? • How easily it can be hacked? • Where exactly is the problem and • What are the remedies? Any suggestions????

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  • Issue in configuring JPA with Spring 3 in Jboss 4.2.2 server.

    - by KVMKReddy
    Hi, I am facing issues in configuring JPA with Spring 3 in JBoss 4.2.2 server. Please find the below file of persistence.xml. <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="TestPU"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <jta-data-source>java:/TestDS</jta-data-source> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/> <property name="hibernate.show_sql" value="true"/> </properties> </persistence-unit> </persistence> My spring-beans.xml is as below <bean id="MyAdvise" class=".......Aspect"> <property name="persister"> <bean id="dbPersister" class="..............DataBasePersister"> </bean> </property> </bean> <bean id="localContainerEntityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="showSql" value="true"/> <property name="database" value="ORACLE"/> </bean> </property> <property name="jpaProperties"> <props> <prop key="hibernate.transaction.manager_lookup_class">org.hibernate.transaction.JBossTransactionManagerLookup</prop> </props> </property> </bean> <bean id="myTxManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="localContainerEntityManagerFactory"/> </bean> <tx:annotation-driven transaction-manager="myTxManager" /> My persister bean is as follows. public class DataBasePersister implements IPersister { private static Logger log = Logger.getLogger(DataBasePersister.class); // The Entity Manager @PersistenceContext protected EntityManager entityManager; @Transactional(readOnly = false) public void persist(Object data) { log.info("IN persist() call. Is the data can castable to MethodStats -->:"+(data instanceof MethodStats)); log.info("Entity Manager instance -->:"+(entityManager)); ---------------------- ---------------------- ---------------------- } } I am getting the following exception when the spring container creating my persister bean org.springframework.transaction.CannotCreateTransactionException: Could not open JPA EntityManager for transaction; nested exception is java.lang.IllegalStateException: JTA EntityManager cannot access a transactions at org.springframework.orm.jpa.JpaTransactionManager.doBegin(JpaTransactionManager.java:382) at org.springframework.transaction.support.AbstractPlatformTransactionManager.getTransaction(AbstractPlatformTransactionManager.java:371) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:585) at org.springframework.aop.support.AopUtils.invokeJoinpointUsingReflection(AopUtils.java:309) at org.springframework.aop.framework.ReflectiveMethodInvocation.invokeJoinpoint(ReflectiveMethodInvocation.java:183) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:150) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:166) at org.springframework.aop.interceptor.ExposeInvocationInterceptor.invoke(ExposeInvocationInterceptor.java:89) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:172) at org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:202) at $Proxy147.getTransaction(Unknown Source) at org.springframework.transaction.interceptor.TransactionAspectSupport.createTransactionIfNecessary(TransactionAspectSupport.java:335) at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:105) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:172) at org.springframework.aop.interceptor.ExposeInvocationInterceptor.invoke(ExposeInvocationInterceptor.java:89) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:172) at org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:202) at $Proxy141.persist(Unknown Source) at com.adp.sbs.aop.aspectj.SBSMethodStatsCollectorAspect.doAround(SBSMethodStatsCollectorAspect.java:63) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:585) at org.springframework.aop.aspectj.AbstractAspectJAdvice.invokeAdviceMethodWithGivenArgs(AbstractAspectJAdvice.java:621) at org.springframework.aop.aspectj.AbstractAspectJAdvice.invokeAdviceMethod(AbstractAspectJAdvice.java:610) at org.springframework.aop.aspectj.AspectJAroundAdvice.invoke(AspectJAroundAdvice.java:65) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:161) at org.springframework.aop.interceptor.ExposeInvocationInterceptor.invoke(ExposeInvocationInterceptor.java:89) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:172) at org.springframework.aop.framework.Cglib2AopProxy$DynamicAdvisedInterceptor.intercept(Cglib2AopProxy.java:621) at com.adp.sbs.aop.test.TestMethodLevelAnnotationStats$$EnhancerByCGLIB$$efbc78a8.MethodWithOneParamsAndReturnTypeAsString(<generated>) at com.adp.sbs.aop.test.SimpleTestServlet.testMethodAnnotations(SimpleTestServlet.java:46) at com.adp.sbs.aop.test.SimpleTestServlet.doPost(SimpleTestServlet.java:40) at com.adp.sbs.aop.test.SimpleTestServlet.doGet(SimpleTestServlet.java:33) at javax.servlet.http.HttpServlet.service(HttpServlet.java:690) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.jboss.web.tomcat.filters.ReplyHeaderFilter.doFilter(ReplyHeaderFilter.java:96) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:230) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:175) at org.jboss.web.tomcat.security.SecurityAssociationValve.invoke(SecurityAssociationValve.java:179) at org.jboss.web.tomcat.security.JaccContextValve.invoke(JaccContextValve.java:84) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.jboss.web.tomcat.service.jca.CachedConnectionValve.invoke(CachedConnectionValve.java:157) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:262) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:844) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:583) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:446) at java.lang.Thread.run(Thread.java:595) Caused by: java.lang.IllegalStateException: JTA EntityManager cannot access a transactions at org.hibernate.ejb.AbstractEntityManagerImpl.getTransaction(AbstractEntityManagerImpl.java:316) at org.springframework.orm.jpa.DefaultJpaDialect.beginTransaction(DefaultJpaDialect.java:70) at org.springframework.orm.jpa.vendor.HibernateJpaDialect.beginTransaction(HibernateJpaDialect.java:57) at org.springframework.orm.jpa.JpaTransactionManager.doBegin(JpaTransactionManager.java:332) Can you somebody please suggest me how to resolve this.

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  • HMAC URLs instead of login?

    - by Tres
    In implementing my site (a Rails site if it makes any difference), one of my design priorities is to relieve the user of the need to create yet another username and password while still providing useful per-user functionality. The way I am planning to do this is: User enters information on the site. Information is associated with the user via server-side session. User completes entering information, server sends an access URL via e-mail to the user roughly in the form of: http://siteurl/<user identifier>/<signature: HMAC(secret + salt + user identifier)> User clicks URL, site looks up user ID and salt and computes the HMAC with the server-stored secret and authenticates if the computed HMAC and signature match. My question is: is this a reasonably secure way to accomplish what I'm looking to do? Are there common attacks that would render it useless? Is there a compelling reason to abandon my desire to avoid a username/password? Is there a must-read book or article on the subject? Note that I'm not dealing with credit card numbers or anything exceedingly private, but I would still like to keep the information reasonably secure.

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  • Which are the best techniques to protect a 'homemade' framework from unlogged visitors?

    - by Hermet
    First of all, I would like to say that I have used the search box looking for a similar question unsuccessfully, maybe because of my poor english skills. The way I currently do this is checking in every single page that a session has been opened. If not, the user gets redirected to a 404 page, to seem like the file which has been requested doesn't exist. I really don't know if this is sure or there's a better and more safety way and I'm currently working with kind of confidential data that should never become public. Could you give me some tips? Or leave a link where I could find some? Thank you very much, and again excuse me for kicking the dictionary.

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