Search Results

Search found 68296 results on 2732 pages for 'utl file'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 76/2732 | < Previous Page | 72 73 74 75 76 77 78 79 80 81 82 83  | Next Page >

  • /etc/hosts file for a multi-homed, multi-domain machine?

    - by threecheeseopera
    I have a server (debian) with two network interfaces that I would like to host multiple services and domains on; it is not entirely clear to me how the hosts file should be set up. Example: eth0, bound to WAN interface 1.2.3.4: mail.example.com www.example.com eth0:1, bound to WAN interface 1.2.3.5: www.other-domain.com eth1, bound to LAN 192.168.1.123: some-clever-hostname What should my hosts file look like? (including localhost,localhost.localdomain, etc.) Should I use DNS for some of these entries? Which ones? Thanks!

    Read the article

  • pscp: how to copy a file from a windows machine to a non-home location on another windows machine?

    - by help
    I want to copy a file from C:\temp on MachineA to C:\final on MachineB. I tried to use the following command, but it gave me an error (permission denied): C:\PROGRA~1\putty\pscp.exe -i C:\PROGRA~1\cwRsync\home\rcadmin\.ssh\id_rsa_private.ppk [email protected]:C:\final\test.txt C:\temp\test.txt It turned out I can only access C:\users\direcpc in my source computer. So if I put the file in C:\users\direcpc\text.txt, then it would work: C:\PROGRA~1\putty\pscp.exe -i C:\PROGRA~1\cwRsync\home\rcadmin\.ssh\id_rsa_private.ppk [email protected]:/test.txt C:\temp\test.txt But I want to access any location on my source computer instead of just my user home directory, is there a way to do this?

    Read the article

  • How can I open a file as read-only from Windows Explorer?

    - by Daniel Daranas
    Is there an easy way to open a file as read-only from Windows Explorer? My inmediate interest is in a Microsoft Access file. I am doing some sanity checks in old MS Access databases and I see that their date is automatically updated when I open them. I don't like this, since it will look like all the old files have been modified today. I am working with Windows XP. Update: As Yoda said, "Do, or do not. There is no try." In my case, it was "do not". I ended up copying the entire (big) folder tree to MyDocuments, and then opening all the databases from there.

    Read the article

  • How to remove file permissions from an external hard drive?

    - by user2540416
    My macbook recently died and I am currently trying to figure out how to copy my data. What I did was, I took out the hard drive, put it in an enclosure and plugged it in to my other laptop that runs linux. The problem is, I cannot copy files from the hard drive due to file permissions. I tried to access the hard drive as root. But I still cannot copy files. How do I remove file permissions from the harddrive?

    Read the article

  • SQL SERVER – FIX: ERROR Msg 5169, Level 16: FILEGROWTH cannot be greater than MAXSIZE for file

    - by pinaldave
    I am writing this blog post right after I resolve this error for one of the system. Recently one of the my friend who is expert in infrastructure as well private cloud was working on SQL Server installation. Please note he is seriously expert in what he does but he has never worked SQL Server before and have absolutely no experience with its installation. He was modifying database file and keep on getting following error. As soon as he saw me he asked me where is the maxfile size setting so he can change. Let us quickly re-create the scenario he was facing. Error Message: Msg 5169, Level 16, State 1, Line 1 FILEGROWTH cannot be greater than MAXSIZE for file ‘NewDB’. Creating Scenario: CREATE DATABASE [NewDB] ON PRIMARY (NAME = N'NewDB', FILENAME = N'D:\NewDB.mdf' , SIZE = 4096KB, FILEGROWTH = 1024KB, MAXSIZE = 4096KB) LOG ON (NAME = N'NewDB_log', FILENAME = N'D:\NewDB_log.ldf', SIZE = 1024KB, FILEGROWTH = 10%) GO Now let us see what exact command was creating error for him. USE [master] GO ALTER DATABASE [NewDB] MODIFY FILE ( NAME = N'NewDB', FILEGROWTH = 1024MB ) GO Workaround / Fix / Solution: The reason for the error is very simple. He was trying to modify the filegrowth to much higher value than the maximum file size specified for the database. There are two way we can fix it. Method 1: Reduces the filegrowth to lower value than maxsize of file USE [master] GO ALTER DATABASE [NewDB] MODIFY FILE ( NAME = N'NewDB', FILEGROWTH = 1024KB ) GO Method 2: Increase maxsize of file so it is greater than new filegrowth USE [master] GO ALTER DATABASE [NewDB] MODIFY FILE ( NAME = N'NewDB', FILEGROWTH = 1024MB, MAXSIZE = 4096MB) GO I think this blog post will help everybody who is facing similar issues. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Error Messages, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • Changing the BizTalk message output file name

    - by Bill Osuch
    By default, BizTalk creates the filename of the message dropped to a send port as %MessageID%, which is the unique identifier (GUID) of the message. What if you want to create your own filename? To start, create a simple schema, and a basic orchestration that will receive the message and send it right back out, like this: If you deploy this and wire up the ports, you can drop an xml file into your receive port and have it come out at your send port named something like {7A63CAF8-317B-49D5-871F-9FD57910C3A0}.xml. Now, we'll create a new message with a custom filename. First, create a new orchestration variable called NewFileName, of the type System.String. Next, create a second message using the same schema as the message you're receiving in the Receive shape. Now, drag a Construct Message shape to the orchestration. In the shape's properties, set Messages Constructed to be the new message you just created. Double click the Message Assignment shape (inside the Construct shape...) and paste in the following code: Message_2 = Message_1;   NewFileName = Message_1(FILE.ReceivedFileName); NewFileName = NewFileName.Replace(".xml","_"); NewFileName = NewFileName + "output_" + System.DateTime.Now.Year.ToString() + "-" + System.DateTime.Now.Month.ToString();   Message_2(FILE.ReceivedFileName) = NewFileName; Here we make a copy of the received message, get it's original file name (ReceivedFileName), replace its extension with an underscore, and date-stamp it. Finally, add a Send shape and a Port to the surface, and configure them to send the message you just created. You should wind up with an orchestration like this: Deploy it, and create a new send port. It should be just about identical to the first send port, except this time the file name will be "%SourceFileName%.xml" (without the quotes of course). Fire up the application, drop in a test file, and you should now get both the xml file named with a GUID, and a second file named something along the lines of "MySchemaTestFile_output_2011-6.xml".

    Read the article

  • FileOpenPicker/FileSavePicker doesn't allow *.* wildcard file associations

    - by mbrit
    On Twitter, Matthias Jauernig commented that the FileOpenPicker and FileSavePicker doesn't allow *.* wildcard file associations. I was relaxed about this and wrote back that it was related to sandboxing implying it was a "good thing", however as Matthias commented back, perhaps it's not.In Metro-style the sandboxing works that if something gives you a file (e.g. the picker, or a share operation), you can access it regardless of where on the system. If you find the file yourself, you have to declare the type.The reason why I think it's related to sandboxing is because if you work with files programmatically you have to be explicit about the file types. This is to stop malware that you think is only interested in - say .PDF files, scanning and uploading any .EML files that it can find on the machine. It follows then on the pickers that restriction would continue. It allow's the retail store team to validate that an app is likely to behave itself. If it's an app that works with images, locking down the picker so that it can only access image file types makes sense.However Matthias mentioned that he has an app that should allow files of any arbitrary file. That fits more into the "if the user selects it, it must be OK" camp than the "programmatic scanning" camp. So now I'm left wondering why the picker doesn't allow any type to be selected.I think then maybe the decision comes down to simplicity. A lot of the decisions in Metro-style design relate to ideas about "zero intimidation". Allow the user to select any file is too much like Old Windows, and not enough like Reimagined Windows. What happens in Matthias's app if the user selects Explorer.exe as the file he or she wants to work with? I guess it's fine if you expect your user to know what they're doing (Old Windows), but not so fine if you're expecting a three year old to work with it (Reimagined Windows).

    Read the article

  • BizTalk 2009 - Error when Testing Map with Flat File Source Schema

    - by StuartBrierley
    I have recently been creating some flat file schemas using the BizTalk Server 2009 Flat File Schema Wizard.  I have then been mapping these flat file schemas to a "normal" xml schema format. I have not previsouly had any cause to map flat files and ran into some trouble when testing the first of these flat file maps; with an instance of the flat file as the source it threw an XSL transform error: Test Map.btm: error btm1050: XSL transform error: Unable to write output instance to the following <file:///C:\Documents and Settings\sbrierley\Local Settings\Temp\_MapData\Test Mapping\Test Map_output.xml>. Data at the root level is invalid. Line 1, position 1. Due to the complexity of the map in question I decided to created a small test map using the same source and destination schemas to see if I could pinpoint the problem.  Although the source message instance vaildated correctly against the flat file schema, when I then tested this simplified map I got the same error. After a time of fruitless head scratching and some serious google time I figured out what the problem was. Looking at the map properties I noticed that I had the test map input set to "XML" - for a flat file instance this should be set to "native".

    Read the article

  • How to obtain position in file (byte-position) from java scanner?

    - by september2010
    How to obtain a position in file (byte-position) from the java scanner? Scanner scanner = new Scanner(new File("file")); scanner.useDelimiter("abc"); scanner.hasNext(); String result = scanner.next(); and now: how to get the position of result in file (in bytes)? Using scanner.match().start() is not the answer, because it gives the position within internal buffer.

    Read the article

  • Python: shutil.rmtree fails on Windows with 'Access is denied'

    - by Sridhar Ratnakumar
    In Python, when running shutil.rmtree over a folder that contains a read-only file, the following exception is printed: File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 221, in rmtree onerror(os.remove, fullname, sys.exc_info()) File "C:\Python26\lib\shutil.py", line 219, in rmtree os.remove(fullname) WindowsError: [Error 5] Access is denied: 'build\\tcl\\tcl8.5\\msgs\\af.msg' Looking in File Properties dialog I noticed that af.msg file is set to be read-only. So the question is: what is the simplest workaround/fix to get around this problem - given that my intention is to do an equivalent of rm -rf build/ but on Windows? (without having to use third-party tools like unxutils or cygwin - as this code is targeted to be run on a bare Windows install with Python 2.6 w/ PyWin32 installed)

    Read the article

  • Extract wav file from video file

    - by Nikos Steiakakis
    I am developing an application in which I need to extract the audio from a video. The audio needs to be extracted in .wav format but I do not have a problem with the video format. Any format will do, as long as I can extract the audio in a wav file. Currently I am using Windows Media Player COM control in a windows form to play the videos, but any other embedded player will do as well. Any suggestions on how to do this? Thanks

    Read the article

  • Locking behaviour is different via network shares

    - by MattH
    I have been trying to lock a file so that other cloned services cannot access the file. I then read the file, and then move the file when finished. The Move is allowed by using FileShare.Delete. However in later testing, we found that this approach does not work if we are looking at a network share. I appreciate my approach may not have been the best, but my specific question is: Why does the below demo work against the local file, but not against the network file? The more specific you can be the better, as I've found very little information in my searches that indicates network shares behave differently to local disks. string sourceFile = @"C:\TestFile.txt"; string localPath = @"C:\MyLocalFolder\TestFile.txt"; string networkPath = @"\\MyMachine\MyNetworkFolder\TestFile.txt"; File.WriteAllText(sourceFile, "Test data"); if (!File.Exists(localPath)) File.Copy(sourceFile, localPath); foreach (string path in new string[] { localPath, networkPath }) { using (FileStream fsLock = File.Open(path, FileMode.Open, FileAccess.ReadWrite, (FileShare.Read | FileShare.Delete))) { string target = path + ".out"; File.Move(path, target); //This is the point of failure, when working with networkPath if (File.Exists(target)) File.Delete(target); } if (!File.Exists(path)) File.Copy(sourceFile, path); }

    Read the article

  • shutil.rmtree fails on Windows with 'Access is denied'

    - by Sridhar Ratnakumar
    In Python, when running shutil.rmtree over a folder that contains a read-only file, the following exception is printed: File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 221, in rmtree onerror(os.remove, fullname, sys.exc_info()) File "C:\ActivePython32Python26\lib\shutil.py", line 219, in rmtree os.remove(fullname) WindowsError: [Error 5] Access is denied: 'build\\pyhg_trunk-win32-x86-hgtip27\\image\\feature-core\\INSTALLDIR\\tcl\\tcl8.5\\msgs\\af.msg' Looking in File Properties dialog I noticed that af.msg file is set to be read-only. So the question is: what is the simplest workaround/fix to get around this problem - given that my intention is to do an equivalent of rm -rf build/ but on Windows? (without having to use unxutils or cygwin)

    Read the article

  • Can't read excel file after creating it using File.WriteAllText() function

    - by Srikanth Mattihalli
    public void ExportDataSetToExcel(DataTable dt) { HttpResponse response = HttpContext.Current.Response; response.Clear(); response.Charset = "utf-8"; response.ContentEncoding = Encoding.GetEncoding("utf-8"); response.ContentType = "application/vnd.ms-excel"; Random Rand = new Random(); int iNum = Rand.Next(10000, 99999); string extension = ".xls"; string filenamepath = AppDomain.CurrentDomain.BaseDirectory + "graphs\\" + iNum + ".xls"; string file_path = "graphs/" + iNum + extension; response.AddHeader("Content-Disposition", "attachment;filename=\"" + iNum + "\""); string query = "insert into graphtable(graphtitle,graphpath,creategraph,year) VALUES('" + iNum.ToString() + "','" + file_path + "','" + true + "','" + DateTime.Now.Year.ToString() + "')"; try { int n = connect.UpdateDb(query); if (n > 0) { resultLabel.Text = "Merge Successfull"; } else { resultLabel.Text = " Merge Failed"; } resultLabel.Visible = true; } catch { } using (StringWriter sw = new StringWriter()) { using (HtmlTextWriter htw = new HtmlTextWriter(sw)) { // instantiate a datagrid DataGrid dg = new DataGrid(); dg.DataSource = dt; //ds.Tables[0]; dg.DataBind(); dg.RenderControl(htw); File.WriteAllText(filenamepath, sw.ToString()); // File.WriteAllText(filenamepath, sw.ToString(), Encoding.UTF8); response.Write(sw.ToString()); response.End(); } } } Hi all, I have created an excel sheet from datatable using above function. I want to read the excel sheet programatically using the below connectionstring. This string works fine for all other excel sheets but not for the one i created using the above function. I guess it is because of excel version problem. OleDbConnection conn= new OleDbConnection("Data Source='" + path +"';provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=Excel 8.0;";); Can anyone suggest a way by which i can create an excel sheet such that it is readable again using above query. I cannot use Microsoft InterOp library as it is not supported by my host.

    Read the article

  • Code to update HyperV Export file

    - by Andy Schneider
    I am using the HyperV Module from Codeplex to do a "config only" export from a 2008R2 Hyper-V server. In order to import the configuration on another HyperV server, I need to edit the value of CopyVMStorage in the EXP file. This file is an XML file. I wrote the following code in PowerShell to do the update for me. The variable $existing is the existing exp file. $xml = [xml](get-content $existing) $xpath = '//PROPERTY[@NAME ="CopyVmStorage"]' foreach ($node in $xml.SelectNodes($xpath)) {$node.Value = 'TRUE'} $xml.Save($existing) This code makes the correct changes to the XML. However, when I go to import the file on the Hyper-V server, I get an error that says the file format is incorrect. I am wondering if the encoding of the file is incorrect or if there is something else going on. If I edit the file manually in wordpad, it imports without an issue. The filename is a GUID with a .exp extension, and it appears that the file name is too long for notepad to open. Notepad throws an error trying to open the file, which is why I went with WordPad. I have noticed that the file that is updated with PowerShell comes out formatted whereas the raw file is xml all bunched together with no whitespace. Any ideas on what "file format" means in this HyperV error message and how I might be able to use my code to automate this change in the XML without changing the file format?

    Read the article

  • How to read from database and write into text file with C#?

    - by user147685
    How to read from database and write into text file? I want to write/copy (not sure what to call) the record inside my database into a text file. One row record in database is equal to one line in the text file. I'm having no problem in database. For creating text file, it mentions FileStream and StreamWriter. Which one should I use?

    Read the article

  • Getting a file pointer from file descriptor

    - by Naga Kiran
    In PHP 5.2.3, "fdopen" was used to read/write to a file descriptor that's opened by another application. fdopen(<fileDescriptorId>,"rw"); //It worked fine with PHP 5.2.3 After upgrading PHP to 5.3.2, it's throwing "undefined reference to 'fdopen' function". Please suggest whats the replacement for this in PHP 5.3.2 or any workaround.

    Read the article

  • How to compare filename of uploaded file and string

    - by user225269
    I use this code to upload image files in xammp server: <?php if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/pjpeg")) && ($_FILES["file"]["size"] < 100000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; } } } else { echo "Invalid file, File must be less than 100Kb in size with .jpg, .jpeg, or .gif file extension"; } ?> What do I do to compare the file name of the uploaded files with the text inputted by the user? My goal is to be able to compare the user input(ID number) and the file name of the image file which should also be an ID number. So that I will be able to display the image that corresponds with the ID Number provided. What do I need to do?Please give me an idea on how can I achieve this. Thanks

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 72 73 74 75 76 77 78 79 80 81 82 83  | Next Page >