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  • Is it possible to write a database view that encompasses one-to-many relationships?

    - by Brandon Linton
    So I'm not necessarily saying this is even a good idea if it were possible, since the schema of the view would be extremely volatile, but is there any way to represent a has-many relationship in a single view? For example, let's say I have a customer that can have any number of addresses in the database. Is there any way to list out each column of each address with perhaps a number as a part of the alias (e.g., columns like Customer Id, Name, Address_Street_1, Address_Street_2, etc)? Thanks!

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  • WCF Cool Applications

    - by Lijo
    Hi Team, What all are the cool applications that we can create by utilizing WCF. Games, Chat …. Please list what all you feel cool. It would be great if you can mention the transport protocol needed for it. If you can mention a sample article for the application also, there is nothing like that. Please share your opinion Thanks Lijo

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  • suggestion box in ruby on rails

    - by ohana
    hi, anyone know how to create a suggestion box in ruby on rails? all the materials i found so far are about observe some text field and update some list in other , not related to suggestion box... Thanks!

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  • Fluid images - portrait/landscape

    - by Richard
    I have a simple slideshow (list items) but a combination of portrait and landscape images. I'm working on a fluid grid so everything is, essentially, 100% of itself. I'm wondering if there's a way for all the images to remain the same height, but the widths stay true to their proportions. All the images have the same height - 2000px - when uploaded. See the site here: http://goo.gl/BdFUj See here for the desired output: http://d.pr/i/HJUH Thanks, R

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  • When calling twitter api favorites, get favourite_count

    - by mickyjtwin
    Using the Twitter REST API Method: favorites for a user, this returns a list of statuses of each favourite. Is there a way to get the favourite count other than calling users/show, and accessing the property this way? Seems an ineffecient way of determining if there are more than 20 favourites for paging purposes.

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  • hi this is my css horizontal menu i need the submeus for this?

    - by kalaivani
    /* CSS Document */ . rhm1{ width:780px; height:64px; margin:0 auto; background:url(images/rhm1_bg.g if) repeat-x; } .rhm1-left{ background:url(images/rhm1_l.gi f) no-repeat; width:15px; height:64px; float:left; } .rhm1-right{ background:url(images/rhm1_r.gi f) no-repeat; width:15px; height:64px; float:right; } .rhm1-bg{ background:url(images/rhm1_bg.g if) repeat-x; height:64px; } .rhm1-bg ul{ list-style:none; margin:0 auto; } .rhm1-bg li{ float:left; list-style:none; } .rhm1-bg li a{ float:left; display:block; color:#ffe8cc; text-decoration:none; font:12px 'Lucida Sans', sans-serif; font-weight:bold; padding:0 0 0 18px; height:64px; line-height:40px; text-align:center; cursor:pointer; } .rhm1-bg li a span{ float:left; display:block; padding:0 32px 0 18px; } .rhm1-bg li.current a{ color:#fff; background:url(images/rhm1_hove r_l.gif) no-repeat left 5px; } .rhm1-bg li.current a span{ color:#fff; background:url(images/rhm1_hove r_r.gif) no-repeat right 5px; } .rhm1-bg li a:hover{ color:#fff; background:url(images/rhm1_hove r_l.gif) no-repeat left 5px; } .rhm1-bg li a:hover span{ color:#fff; background:url(images/rhm1_hove r_r.gif) no-repeat right 5px; }

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  • Linking to a section of a site that is hidden by a hide/show JavaScript function

    - by hollyb
    I am using a bit of JavaScript to show/hide sections of a site when a tab is clicked. I'm trying to figure out if there is a way I can link back to the page and have a certain tab open based on that link. Here is the JS: var ids=new Array('section1','section2','section3','section4'); function switchid(id, el){ hideallids(); showdiv(id); var li = el.parentNode.parentNode.childNodes[0]; while (li) { if (!li.tagName || li.tagName.toLowerCase() != "li") li = li.nextSibling; // skip the text node if (li) { li.className = ""; li = li.nextSibling; } } el.parentNode.className = "active"; } function hideallids(){ //loop through the array and hide each element by id for (var i=0;i<ids.length;i++){ hidediv(ids[i]); } } function hidediv(id) { //safe function to hide an element with a specified id document.getElementById(id).style.display = 'none'; } function showdiv(id) { //safe function to show an element with a specified id document.getElementById(id).style.display = 'block'; } And the HTML <ul> <li class="active"><a onclick="switchid('section1', this);return false;">One</a></li> <li><a onclick="switchid('section2', this);return false;">Two</a></li> <li><a onclick="switchid('section3', this);return false;">Three</a></li> <li><a onclick="switchid('section4', this);return false;">Four</a></li> </ul> <div id="section1" style="display:block;"> <div id="section2" style="display:none;"> <div id="section3" style="display:none;"> <div id="section4" style="display:none;"> I haven't been able to come up with a way to link back to a specific section. Is it even possible with this method? Thanks!

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  • Listview dsplaying Issue

    - by raj
    I am using LinearLayout to display ListView Adding Button at the Top. Then adding Listview bellow the button. Problem is that Listview take the entire screen at the time of scroll. At the time of scroll the first cell of the ListView went in the Background of the button. Is there any solution to strict the List below the button?

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  • BroadcastReciever doesn't show SMS not Send or Not delivered

    - by user1657111
    While using broadcastreciver for checking sms status, it shows the toast when sms is sent but shows nothing when sms is not sent or delivered (im testing it by putting an abrupt number). the code im using is the one ive seen the most on every site of checking sms delivery status. But my code is only showing the status when sms is sent successfully. Can any one get a hint of what am i doing wrong ? I hav this method in doInBackground() and so obviously im using AsyncTask. Thanks guys public void send_SMS(String list, String msg, AtaskClass task) { String SENT = "SMS_SENT"; String DELIVERED = "SMS_DELIVERED"; SmsManager sms = SmsManager.getDefault(); PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(SENT), 0); PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0, new Intent(DELIVERED), 0); //---when the SMS has been sent--- registerReceiver(new BroadcastReceiver(){ @Override public void onReceive(Context context, Intent arg1) { switch (getResultCode()) { case Activity.RESULT_OK: Toast.makeText(context, "SMS sent", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_GENERIC_FAILURE: Toast.makeText(context, "Generic failure", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_NO_SERVICE: Toast.makeText(context, "No service", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_NULL_PDU: Toast.makeText(context, "Null PDU", Toast.LENGTH_SHORT).show(); break; case SmsManager.RESULT_ERROR_RADIO_OFF: Toast.makeText(context, "Radio off", Toast.LENGTH_SHORT).show(); break; } } }, new IntentFilter(SENT)); //---when the SMS has been delivered--- registerReceiver(new BroadcastReceiver(){ @Override public void onReceive(Context context, Intent arg1) { switch (getResultCode()) { case Activity.RESULT_OK: Toast.makeText(context, "SMS delivered", Toast.LENGTH_SHORT).show(); break; case Activity.RESULT_CANCELED: Toast.makeText(context, "SMS not delivered", Toast.LENGTH_SHORT).show(); break; } } }, new IntentFilter(DELIVERED)); StringTokenizer st = new StringTokenizer(list,","); int count= st.countTokens(); int i =1; count = 1; while(st.hasMoreElements()) { // PendingIntent pi = PendingIntent.getActivity(this,0,new Intent(this, SMS.class),0); String tempMobileNumber = (String)st.nextElement(); //SmsManager sms = SmsManager.getDefault(); sms.sendTextMessage(tempMobileNumber, null, msg , sentPI, deliveredPI); Double cCom = ((double)i/count) * 100; int j = cCom.intValue(); task.doProgress(j); i++; count ++; } // class ends }

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  • Model Binding with Parent/Child Relationship

    - by user296297
    I'm sure this has been answered before, but I've spent the last three hours looking for an acceptable solution and have been unable to find anything, so I apologize for what I'm sure is a repeat. I have two domain objects, Player and Position. Player's have a Position. My domain objects are POCOs tied to my database with NHibernate. I have an Add action that takes a Player, so I'm using the built in model binding. On my view I have a drop down list that lets a user select the Position for the Player. The value of the drop down list is the Id of the position. Everything gets populated correctly except that my Position object fails validation (ModelState.IsValid) because at the point of model binding it only has an Id and none of it's other required attributes. What is the preferred solution for solving this with ASP.NET MVC 2? Solutions I've tried... Fetch the Position from the database based on the Id before ModelState.IsValid is called in the Add action of my controller. I can't get the model to run the validation again, so ModelState.IsValid always returns false. Create a custom ModelBinder that inherits from the default binder and fetch the Position from the database after the base binder is called. The ModelBinder seems to be doing the validation so if I use anything from the default binder I'm hosed. Which means I have to completely roll my own binder and grab every value from the form...this seems really wrong and inefficient for such a common use-case. Solutions I think might work, I just can't figure out how to do... Turn off the validation for the Position class when used in Player. Write a custom ModelBinder leverages the default binder for most of the property binding, but lets me get the Position from the database BEFORE the default binder runs validation. So, how do the rest of you solve this? Thanks, Dan P.S. In my opinion having a PositionId on Player just for this case is not a good solution. There has to be solvable in a more elegant fashion.

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  • MS Access 07 - Q re lookup column vs many-to-many; Q re checkboxes in many-to-many forms

    - by TBinLondon
    Hello, I'm creating a database with Access. This is just a test database, similar to my requirements, so I can get my skills up before creating one for work. I've created a database for a fictional school as this is a good playground and rich data (many students have many subjects have many teachers, etc). Question 1 What is the difference, if any, between using a Lookup column and a many-to-many associate table? Example: I have Tables 'Teacher' and 'Subject'. Many teachers have many subjects. I can, and have, created a table 'Teacher_Subject' and run queries with this. I have then created a lookup column in teachers table with data from subjects. The lookup column seems to take the place of the teacher_subject table. (though the data on relationships is obviously duplicated between lookup table and teacher_subject and may vary). Which one is the 'better' option? Is there a snag with using lookup tables? (I realize that this is a very 'general' question. Links to other resources and answers saying 'that depends...' are appreciated) Question 2 What attracts me to lookup tables is the following: When creating a form for entering subjects for teachers, with lookup I can simply create checkboxes and click a subject for a teacher 'on' or 'off'. Each click on/off creates/removes a record in the lookup column (which replaces teacher_subject). If I use a form from a query from teacher subject with teacher as main form and subject as subform I run into this problem: In the subform I can either select each subject that teacher has in a bombo box, i.e. click, scroll down, select, go to next row, click, scroll down, etc. (takes too long) OR I can create a list box listing all available subjects in each row but allowing me to select only one. (takes up too much space). Is it possible to have a click on/off list box for teacher_subject, creating/removing a record there with each click? Note - I know zero SQL or VB. If the correct answer is "you need to know SQL for this" then that's cool. I just need to know. Thanks!

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  • An O(1) Sort ~~~

    - by FlySwat
    Before you stone me for being a heretic, There is a sort that proclaims to be O(1), called "Bead Sort" (http://en.wikipedia.org/wiki/Bead_sort) , however that is pure theory, when actually applied I found that it was actually O(N * M), which is pretty pathetic. That said, Lets list out some of the fastest sorts, and their best case and worst case speed in Big O notation. ~~ FlySwat ~~

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  • findcontrol problems

    - by saadan
    why can not I do this I have a data list which retrieves some data out. if the label1 is we say 123 then a second label must be invisible Label Label = (Label)DataList2.FindControl("LabelName"); Label Label2 = (Label)DataList2.FindControl("LabelName2"); if (Label.Text == "123") { Label2.Visible = false; }

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  • WPF DataGrid Get All SelectedRows

    - by anvarbek raupov
    Have to use free WPF DataGrid (I thought Infragistics libraries are bad, I take it back after this) for this project of mine. Looks like DataGrid doesnt have clean MVVM Friendly way of getting the list of selectedRows ? I can data bind to SelectedItem="{Binding SelectedSourceFile}" but this only shows the 1st selected row. Need to be able to get all selected rows. Any hints to do it cleanly via MVVM ?

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  • Worst Case number of rotations for BST to AVL algorithm?

    - by spacker_lechuck
    I have a basic algorithm below and I know that the worst case input BST is one that has degenerated to a linked list from inserts to only one side. How would I compute the worst case complexity in terms of number of rotations for this BST to AVL conversion algorithm? IF tree is right heavy { IF tree's right subtree is left heavy { Perform Double Left rotation } ELSE { Perform Single Left rotation } } ELSE IF tree is left heavy { IF tree's left subtree is right heavy { Perform Double Right rotation } ELSE { Perform Single Right rotation } }

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  • JPA CascadeType.ALL does not delete orphans.

    - by Paul Whelan
    I am having trouble deleting orphan nodes using JPA with the following mapping @OneToMany (cascade = CascadeType.ALL, fetch = FetchType.EAGER, mappedBy = "owner") private List<Bikes> bikes; I am having the issue of the orphaned roles hanging around the database. I can use the @org.hibernate.annotations.Cascade Hibernate specific tag but obviously I don't want to tie my solution into a hibernate implementation. Any pointers greatly appreciated.

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  • Close socket handle utility

    - by Boris
    Hi I need a utility to close server socket handles open by the process, on windows. I cannot use tcpview as it does not close the server socket (ESTABLISHED state). Process explorer comes close with its handle list and "close handle" option, but it only gives the handle path (like \Device\Afd) and if application has open many such sockets I cannot tell which handle I would like to close. Any idea?

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  • How to test unescaped &nbsps; as a whitespace

    - by gleery
    I use apache common lang to unescape a block of html text which contains &nbsp;, I want to filter out blocks that contains only whitespaces. But I can't test the   as a whitespace. It's not in the normal whitespace list(http://en.wikipedia.org/wiki/Whitespace_character), and I try to print its Hex form by calling Character.getNumericValue which return -1. &nbsp should be a whitespace,isn't? But How can I test it?

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