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  • Django inlineformset validation and delete

    - by Andrew Gee
    Hi, Can someone tell me if a form in an inlineformset should go through validation if the DELETE field is checked. I have a form that uses an inlineformset and when I check the DELETE box it fails because the required fields are blank. If I put data in the fields it will pass validation and then be deleted. Is that how it is supposed to work, I would have thought that if it is marked for delete it would bypass the validation for that form. Regards Andrew Follow up - but I would still appreciate some others opinions/help What I have figured out is that for validation to work the a formset form must either be empty or complete(valid) otherwise it will have errors when it is created and will not be deleted. As I have a couple of hidden fields in my formset forms and they are pre-populated when the page loads via javascript the form fails validation on the other required fields which might still be blank. The way I have gotten around this by adding in a check in the add_fields that tests if the DELETE input is True and if it is it makes all fields on the form not required, which means it passes validation and will then delete. def add_fields(self, form, index) #add other fields that are required.... deleteValue = form.fields['DELETE'].widget.value_from datadict(form.data, form.files, form.add_prefix('DELETE')) if bool(deleteValue) or deleteValue == '': for name, field in form.fields.items(): form.fields[name].required= False This seems to be an odd way to do things but I cannot figure out another way. Is there a simpler way that I am missing? I have also noticed that when I add the new form to my page and check the Delete box, there is no value passed back via the request, however an existing form (one loaded from the database) has a value of on when the Delete box is checked. If the box is not checked then the input is not in the request at all. Thanks Andrew

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  • django error:The model Tribe is already registered

    - by zjm1126
    when i python manage.py syncdb,it show this: The following content types are stale and need to be deleted: maps | tribe Any objects related to these content types by a foreign key will also be deleted. Are you sure you want to delete these content types? If you're unsure, answer 'no'. Type 'yes' to continue, or 'no' to cancel: no when i put 'no' ,and then python manage runserver: AlreadyRegistered at / The model Tribe is already registered what should i do ? thanks

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  • onmouseover with django / imagekit

    - by Michael Moreno
    I'm using Imagekit. View.py includes: def pics(request): p = Photo.objects.all() return render_to_response('Shots.html', {'p': p}) The following simple code in the template will generate associated images: {% for p in p %} <img src = "{{ p.display.url }}"> <img src = "{{ p.thumbnail_image.url }}"> {% endfor %} I'm attempting to generate a series of thumbnails {{ p.thumbnail_image.url }} which, when mouseover'd, will generate the slightly larger version of the image, {{ p.display.url }} via Javascript. The following code in the template attempts to do so: <html> <head> <HEAD> <script language="Javascript"> { image1 = new Image image2 = new Image image1.src = {{ p.thumbnail_image.url }} image2.src = {{ p.display.url }} </script> </head> <body> {% for p in p %} <a href="" onMouseOver="document.rollover.src= image2.src onMouseOut="document.rollover.src= image1.src"> <img src="{{ p.thumbnail_image.url }}" border=0 name="rollover"></a> {% endfor %} </body> </html> This will display the series of thumbnails, but the larger image will not display when mouseover'd. I believe it has to do with how I'm specifying the variable {{ p.display.url }}.

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  • django: search forms and redirect

    - by gruszczy
    After processing form from POST I should redirect, to prevent user from hitting back. However, I am using form to determine search query on a database, so I need to either pass params to the redirected site or the result of a search. Or maybe there is some other good practice, how to solve this problem? Maybe in this situation I am allowed not to redirect (nothing happens, if user performs search again).

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  • Timezones and the DateTimeField - Django

    - by RadiantHex
    Hi folks, I'm trying to implement a "time ago" feature, for the displaying of items on a site. As I'm caching the pages I wish to use javascript in order to render the "time ago". Javascript knows local time and problably the Timezone of the local machine so I could play with that, but that would require to hard code the server's timezone. Therefore I'm trying to figure out a simple way to pass a ISO 8601 timestamp, in GMT time. Is there any simple and straight forward way for doing this? Help would be much appreciated! =)

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  • Django: Odd mark_safe behaviour?

    - by Mark
    I wrote this little function for writing out HTML tags: def html_tag(tag, content=None, close=True, attrs={}): lst = ['<',tag] for key, val in attrs.iteritems(): lst.append(' %s="%s"' % (key, escape_html(val))) if close: if content is None: lst.append(' />') else: lst.extend(['>', content, '</', tag, '>']) else: lst.append('>') return mark_safe(''.join(lst)) Which worked great, but then I read this article on efficient string concatenation (I know it doesn't really matter for this, but I wanted consistency) and decided to update my script: def html_tag(tag, body=None, close=True, attrs={}): s = StringIO() s.write('<%s'%tag) for key, val in attrs.iteritems(): s.write(' %s="%s"' % (key, escape_html(val))) if close: if body is None: s.write(' />') else: s.write('>%s</%s>' % (body, tag)) else: s.write('>') return mark_safe(s.getvalue()) But now my HTML get escaped when I try to render it from my template. Everything else is exactly the same. It works properly if I replace the last line with return mark_safe(unicode(s.getvalue())). I checked the return type of s.getvalue(). It should be a str, just like the first function, so why is this failing?? Also fails with SafeString(s.getvalue()) but succeeds with SafeUnicode(s.getvalue()). I'd also like to point out that I used return mark_safe(s.getvalue()) in a different function with no odd behavior. The "call stack" looks like this: class Input(Widget): def render(self): return html_tag('input', attrs={'type':self.itype, 'id':self.id, 'name':self.name, 'value':self.value, 'class':self.itype}) class Field: def __unicode__(self): return mark_safe(self.widget.render()) And then {{myfield}} is in the template. So it does get mark_safed'd twice, which I thought might have been the problem, but I tried removing that too..... I really have no idea what's causing this, but it's not too hard to work around, so I guess I won't fret about it.

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  • Django model: Reference foreign key table in __unicode__ function for admin

    - by pa
    Example models: class Parent(models.Model): name = models.CharField() def __unicode__(self): return self.name class Child(models.Model): parent = models.ForeignKey(Parent) def __unicode__(self): return self.parent.name # Would reference name above I'm wanting the Child.unicode to refer to Parent.name, mostly for the admin section so I don't end up with "Child object" or similar, I'd prefer to display it more like "Child of ". Is this possible? Most of what I've tried hasn't worked unfortunately.

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  • need help figuring out dynamic menu generation in django

    - by photographer
    I need to dynamically generate a code like this in the resulting html: <p>>> gallery one</p> <p><a href="../gallery2">gallery two</a></p> <p><a href="../about">about the author</a></p> <p><a href="../news">our news</a></p> I do have menu_code string variable created in views.py (it is generated depending on an item number of the current page passed — 1 in the case above), which contains that long string with the code shown above. It is (well, supposed to) passed by locals() into the html template (all other variables are passed that way successfully): return render_to_response('gallery_page.html', locals()) I have this: {% include menu_code %} inside the template html. But instead of being interpreted as code it is just shown as text in the browser. What am I doing wrong? How to make it work as a dynamically generated menu?

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  • What's best practice to check if an object is part of a ManyToMany relationship in Django

    - by PhilGo20
    from an instance of Site with a ManyToMany relationship to Kiosk, i'd like to check if a Kiosk object is part of the relationship. I could do self.apps.get(id=app_id).exists() and check if True or self.apps.get(id=app_id) and catch the ObjectDoesNotExist error or self.apps.filter(id=app_id) and check if True If I have to catch a possible ObjectDoesNotExist error, I may as well use the second one I can do the second but doesnt seem super clean can use the third one but using filter on a unique ID seems wrong to me You can tell me to use whatever works and that'll be a valid answer ;-)

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  • GAE Django template and swedish characters

    - by fredrik
    Hi, I'm trying to render templates of an html-page that contains swedish characters "åäö" but when it renders in the web browser it ends up with "?". The page renders in UTF-8. Is there any way to workaround this or do I need to write the chars as html-code? Also any pointers to the best support for multi-lang site? ..fredrik

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  • Decoding not reversing unicode encoding in Django/Python

    - by PhilGo20
    Ok, I have a hardcoded string I declare like this name = u"Par Catégorie" I have a # -- coding: utf-8 -- magic header, so I am guessing it's converted to utf-8 Down the road it's outputted to xml through xml_output.toprettyxml(indent='....', encoding='utf-8') And I get a UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 3: ordinal not in range(128) Most of my data is in French and is ouputted correctly in CDATA nodes, but that one harcoded string keep ... I don't see why an ascii codec is called. what's wrong ?

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  • Django resizing an image pre save using PIL

    - by Ed
    Ugh, I hate having to ask a question on such a common feature, but. . . I'm using an ImageField in a form to upload a photo to S3. I want to resize the image before it is uploaded to S3. I'm trying to use PIL to test the dimensions and resize if necessary. The Image.open() part is throwing me though. It wants a filepath, and the ImageField from the form is only returning the actual file and filename. How can I resize the image before it's saved to S3? Before we get to this point, I'm not using sorl because I believe sorl is compatible with models using ImageFields. But the model associated with the saved S3 images holds just the url of the image on S3 as opposed to using ImageFields.

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  • Django conditional template inheritance

    - by Ed
    I have template that displays object elements with hyperlinks to other parts of my site. I have another function that displays past versions of the same object. In this display, I don't want the hyperlinks. I'm under the assumption that I can't dynamically switch off the hyperlinks, so I've included both versions in the same template. I use an if statement to either display the hyperlinked version or the plain text version. I prefer to keep them in the same template because if I need to change the format of one, it will be easy to apply it to the other right there. The template extends framework.html. Framework has a breadcrumb system and it extends base.html. Base has a simple top menu system. So here's my dilemma. When viewing the standard hyperlink data, I want to see the top menu and the breadcrumbs. But when viewing the past version plain text data, I only want the data, no menu, no breadcrumbs. I'm unsure if this is possible given my current design. I tried having framework inherit the primary template so that I could choose to call either framework (and display the breadcrumbs), or the template itself, thus skipping the breadcrumbs, but I want framework.html available for other templates as well. If framework.html extends a specific template, I lose the ability to display it in other templates. I tried writing an if statement that would display a the top_menu block and the nav_menu block from base.html and framework.html respectively. This would overwrite their blocks and allow me to turn off those elements conditional on the if. Unfortunately, it doesn't appear to be conditional; if the block elements are in the template at all, surrounded by an if or not, I lose the menus. I thought about using {% include %} to pick up the breadcrumbs and a split out top menu. In that case though, I'll have to include it all the time. No more inheritance. Is this the best option given my requirement?

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  • Django | twilio to send SMS

    - by MMRUser
    I'm using twilio as for a mobile verification mechanism, I have no prior experience in using twilio but looking at the sample PHP code I used this one in my code but apparently it's giving me an 400 Bad request HTTP error. Here's the code: d = { 'TO' : '*** *** ****', 'FROM' : '415-555-1212', 'BODY' : 'Hello user, please verify your device using this code %s' % verNumber } try: print account.request('/%s/Accounts/%s/SMS/Messages' % \ (API_VERSION, ACCOUNT_SID), 'POST', d) except Exception, e: return HttpResponse('Error %s' % e) verNumber is randomly generated and the receiver's number is validated in twilio. Thanks.

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  • Django IN query as a string result - invalid literal for int() with base 10

    - by bmelton
    Trying to query a 'Favorites' model to get a list of items a user has favorited, and then querying against a different model to get the objects back from that query to present to the template, but I'm getting an error: "invalid literal for int() with base 10" Looking over all of the other instances of that error, I couldn't find any in which the asker actually wanted to work with a comma separated list of integers, so I'm kind of at a loss. Model class Favorite(models.Model): # key should be the model name, id is the model.id, and user is the User object. key = models.CharField(max_length=255, unique=True) val = models.IntegerField(default=0) user = models.ForeignKey(User) class Admin: list_display = ('key', 'id', 'user') View def index(request): favorites = Favorite.objects.filter(key='blog', user=request.user.pk) values = "" for favorite in favorites: values += "%s," % favorite.val #values = "[%s]" % values blogs = Blog.objects.filter(pk__in=values) return render_to_response('favorite/index.html', { "favorites" : favorites, "blogs" : blogs, "values" : values, }, context_instance=RequestContext(request) ) enter code here

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  • django: caching passwords for custom authentication

    - by gruszczy
    I am authenticating users in ldap, but this happens only once, when user is logging in. Afterwards I need to keep username and password, because before every ldap operation I need to make bind on ldap server before every operation. What is the safe way to cache this password (I can't store in the database or cookies) for as long as session persists.

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  • django: grouping in an order_by query?

    - by AP257
    Hi all, I want to allocate rankings to users, based on a points field. Easy enough you'd think with an order_by query. But how do I deal with the situation where two users have the same number of points and need to share the same ranking? Should I use annotate to find users with the same number of points? My current code, and a pseudocode description of what I'd like to do, are below. top_users = User.objects.filter(problem_user=False).order_by('-points_total') # Wrong - in pseudocode, this should be # Get the highest points_total, find all the users with that points_total, # if there is more than one user, set status to 'Joint first prize', # otherwise set status to 'First prize' top_users[0].status = "First prize" if (top_users[1]): top_users[1].status = "Second prize" if (top_users[2]): top_users[2].status = "Third prize" if (top_users[3]): top_users[3:].status = "Highly commended" The code above doesn't deal with the situation where two users have the same number of points and need to share second prize. I guess I need to create a query that looks for unique values of points_total, and does some kind of nested ranking? It also doesn't cope with the fact that sometimes there are fewer than 4 users - does anyone know how I can do (in pseudocode) 'if top_users[1] is not null...' in Python?

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  • Multi choice form field in Django

    - by Dingo
    Hi! I'am developing application on app-engine-path. I would like to make form with multichoice (acceptably languages for user). Code look like this: Language settings: settings.LANGUAGES = ((u"cs", u"Ceština"), (u"en", u"English")) Form model: class UserForm(forms.ModelForm): first_name = forms.CharField(max_length=100) last_name = forms.CharField(max_length=100) languages = forms.MultipleChoiceField(widget=forms.CheckboxSelectMultiple, choices=settings.LANGUAGES) The form is rendered o.k. (all languages have checkbox. IDs, NAMEs is ok.) But if I save some languages for user, those languages don't check checkboxes. User model look like this class User(User): #... languages = db.StringListProperty() #... and view: def edit_profile(request): user = request.user if request.method == 'POST': form = UserForm(request.POST) if form.is_valid(): # ... else: form = UserForm(instance=user) data = {"user":user, "form": form} return render_to_response(request, 'user_profile/user_profile.html', data)

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  • Django TestCase testing order

    - by ziang
    If there are several methods in the test class, I found that the order to execute is alphabetical. But I want to customize the order of execution. How to define the execution order? For example: testTestA will be loaded first than testTestB. class Test(TestCase): def setUp(self): ... def testTestB(self): #test code def testTestA(self): #test code

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  • Django select max id

    - by pistacchio
    Hi, given a standard model (called Image) with an autoset 'id', how do I get the max id? So far I've tried: max_id = Image.objects.all().aggregate(Max('id')) but I get a 'id__max' Key error. Trying max_id = Image.objects.order_by('id')[0].id gives a 'argument 2 to map() must support iteration' exception Any help?

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