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  • Django: test failing on a view with @login_required

    - by Esteban Feldman
    Hi all, I'm trying to build a test for a view that's decorated with @login_required, since I failed to make it work, I did a simple test and still can't make it pass. Here is the code for the simple test and the view: def test_login(self): user = self._create_new_user() self.assertTrue(user.is_active) login = self.client.login(username=user.username, password=self.data['password1']) self.failUnless(login, 'Could not log in') response = self.client.get('/accounts/testlogin/') self.assertEqual(response.status_code, 200) @login_required def testlogin(request): print 'testlogin !! ' return HttpResponse('OK') _create_new_user() is saving the user and there is a test inside that method to see that is working. The test fails in the response.status_code, returning 302 and the response instance is of a HttpResponseRedirect, is redirecting it as if not logged in. Any clue? I'm missing something? Regards Esteban

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  • Django blog reply system

    - by dana
    hello, i'm trying to build a mini reply system, based on the user's posts on a mini blog. Every post has a link named reply. if one presses reply, the reply form appears, and one edits the reply, and submits the form.The problem is that i don't know how to take the id of the post i want to reply to. In the view, if i use as a parameter one number (as an id of the blog post),it inserts the reply to the database. But how can i do it by not hardcoding? The view is: def save_reply(request): if request.method == 'POST': form = ReplyForm(request.POST) if form.is_valid(): new_obj = form.save(commit=False) new_obj.creator = request.user new_post = New(1) #it works only hardcoded new_obj.reply_to = new_post new_obj.save() return HttpResponseRedirect('.') else: form = ReplyForm() return render_to_response('replies/replies.html', { 'form': form, }, context_instance=RequestContext(request)) i have in forms.py: class ReplyForm(ModelForm): class Meta: model = Reply fields = ['reply'] and in models: class Reply(models.Model): reply_to = models.ForeignKey(New) creator = models.ForeignKey(User) reply = models.CharField(max_length=140,blank=False) objects = NewManager() mentioning that New is the micro blog class thanks

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  • Django/Python best practice template_dict

    - by fredrik
    Hi, After just been coding for about 6-9 months. I probably changed my coding style a number of times after reading some code or read best practices. But one thing I haven't yet come a cross is a good why to populate the template_dict. As of now I pass the template_dict across a number of methods (that changes/modifies it) and returns is. The result is that every methods takes template_dict as first argument and the returns it and this in my eyes doesn't seems to be the best solution. An idea is to have a method that handles all the changes. But I'm curios if there's a best practice for this? Or is it "do what you feel like"-type of thing? The 2 things I think is pretty ugly is to send as an argument and return it in all methods. And the just the var name is written xxx number of times in the code :) ..fredrik

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  • Django: Named URLs / Same Template, Different Named URL

    - by TheLizardKing
    I have a webapp that lists all of my artists, albums and songs when the appropriate link is clicked. I make extensive use of generic views (object_list/detail) and named urls but I am coming across an annoyance. I have three templates that pretty much output the exact same html that look just like this: {% extends "base.html" %} {% block content %} <div id="content"> <ul id="starts-with"> {% for starts_with in starts_with_list %} <li><a href="{% url song_list_x starts_with %}">{{ starts_with|upper }}</a></li> {% endfor %} </ul> <ul> {% for song in songs_list %} <li>{{ song.title }}</li> {% endfor %} </ul> </div> {% endblock content %} My artist and album template look pretty much the same and I'd like to combine the three template's into one. The fact that my variables start with song can easily be changed to the default obj. It's my <ul id="starts-with"> named url I don't know how to correct. Obviously I want it to link to a specific album/artist/song using the named urls in my urls.py but I don't know how to make it context aware. Any suggestions? urlpatterns = patterns('tlkmusic.apps.tlkmusic_base.views', # (r'^$', index), url(r'^artists/$', artist_list, name='artist_list'), url(r'^artists/(?P<starts_with>\w)/$', artist_list, name='artist_list_x'), url(r'^artist/(?P<artist_id>\d+)/$', artist_detail, name='artist_detail'), url(r'^albums/$', album_list, name='album_list'), url(r'^albums/(?P<starts_with>\w)/$', album_list, name='album_list_x'), url(r'^songs/$', song_list, name='song_list'), url(r'^songs/(?P<starts_with>\w)/$', song_list, name='song_list_x'), )

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  • Django openid authentication with google

    - by Zayatzz
    Hello I am looking into authenticating via google. I dont understand how it works:http://code.google.com/apis/accounts/docs/OpenID.html#Samples If i do that 2nd request by entering the data as one url with params into browser i get back XML file. Should i not get back sample response nr3? Can somebody explain this to me? The problem is, that im trying to sort through some third party app that uses google openid authentication and its not recieving authenticated users e-mail back, like in sample response 3. Alan PS i have read through similar questions and their responses and gone through pages like: http://stackoverflow.com/questions/353880/how-does-openid-authentication-works http://www.windley.com/archives/2006/04/how_does_openid.shtml http://tinisles.blogspot.com/2008/02/how-does-openid-work.html http://openid.net/pres/protocolflow-1.1.png etc..

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  • Django LFS - custom views

    - by owca
    For all those ligthning fast shop users. I'm trying to implement my own first page view that will list all products from shop ( under '/' address). So I have a template : {% extends "lfs/shop/shop_base.html" %} {% block content %} <div id="najnowsze_produkty"> <ul> {% for obj in objects %} <li> {{ obj.name }} </li> {% endfor %} </ul> </div> {% endblock %} and then I've edited main shop view : from lfs.catalog.models import Category from lfs.catalog.models import Product def shop_view(request, template_name="lfs/shop/shop.html"): products = Product.objects.all() shop = lfs_get_object_or_404(Shop, pk=1) return render_to_response(template_name, RequestContext(request, { "shop" : shop, "products" : products })) but it just shows nothing. When I do Product.objects.all() query in shell I get results. Any ideas what could cause the problem ? Maybe I should filter products with 'active' status only ? But I'm not sure if it can influence all objects in any way.

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  • Django template not loading properly

    - by fmsf
    Hey, When this one runs everything goes fine: (r"^newobject$", "views.myobjects.newobject"), All the CSS + JS files are properly fetched from: static/css/... static/js/... When this one runs: (r"^mybjects/(([a-z]|[A-Z]|[0-9])+)$","views.myobjects.loadobject"), All the css and JS files that are being fetched, are run trough the urlpatterns and are returning my defailt page: (r"", 'views.main.index'), This makes all my CSS and JS code to actualy be HTML. My guess is that i'm giving some noob mistake. Is there any common reason why this should happen? And how to fix it?

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  • ForeignKey django 1.1.1 model

    - by Spikie
    i have class staff_name(models.Model): firstname = models.CharField(max_length=150) surname = models.CharField(max_length=150) class inventory_transaction(models.Model): staffs = models.ForeignKey(staff_name) i want to get or create staff surname and first name through inventory_transaction i used these code below inventory_transaction.objects.get_or_create(staffs_surname_contains=sname,staffs_firstname_contains=fname) i got this error "staffs_surname_contains can not be defined" what have i done wrong ? thanks

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  • add text to the choice_label of ChoiceField in Django

    - by pablo
    The ChoiceField creates a select html element and the options show the choice_label which is the _unicode_ of each model object. How can I change the text of the choice_label without modifying _unicode_ ? I have a Product model and I want to show in the options text the product name + price + link to edit. I've searched in fields.py and widgets.py but couldn't find what needed to be changed. Thanks

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  • Django microblog showing a logged in user only his posts

    - by dana
    i have a miniblog application, with a class named New(refering to a new post), having a foreign key to an user(who has posted the entry). above i have a method that displays all the posts from all the users. I'd like to show to the logged in user, only his posts How can i do it? Thanks in advance! def paginate(request): paginator = New.objects.all() return render_to_response('news/newform.html', { 'object_list': paginator, }, context_instance=RequestContext(request))

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  • django url user id versus userprofile id problem

    - by dana
    hello there, i have a mini comunity where each user can search and find another user profile. Userprofile is a class model, indexed differently compared to user model class (user id is not equal to userprofile id) But i cannot see a user profile by typing in the url the corresponding id. I only see the profile of the currently logged in user. Why is that? I'd also want to have in my url the username (a primary key of the user table also) and NOT the id (a number). The guilty part of the code is: what can i replace that request.user with so that it wil actually display the user i searched for, and not the currently logged in? def profile_view(request, id): u = UserProfile.objects.get(pk=id) cv = UserProfile.objects.filter(created_by = request.user) blog = New.objects.filter(created_by = request.user) return render_to_response('profile/publicProfile.html', { 'u':u, 'cv':cv, 'blog':blog, }, context_instance=RequestContext(request)) in urls (of the accounts app): url(r'^profile_view/(?P<id>\d+)/$', profile_view, name='profile_view'), and in template: <h3>Recent Entries:</h3> {% load pagination_tags %} {% autopaginate list 10 %} {% paginate %} {% for object in list %} <li>{{ object.post }} <br /> Voted: {{ vote.count }} times.<br /> {% for reply in object.reply_set.all %} {{ reply.reply }} <br /> {% endfor %} <a href=''> {{ object.created_by }}</a> <br /> {{object.date}} <br /> <a href = "/vote/save_vote/{{object.id}}/">Vote this</a> <a href="/replies/save_reply/{{object.id}}/">Comment</a> </li> {% endfor %} thanks in advance!

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  • Django stupid mark_safe?

    - by Mark
    I wrote this little function for writing out HTML tags: def html_tag(tag, content=None, close=True, attrs={}): lst = ['<',tag] for key, val in attrs.iteritems(): lst.append(' %s="%s"' % (key, escape_html(val))) if close: if content is None: lst.append(' />') else: lst.extend(['>', content, '</', tag, '>']) else: lst.append('>') return mark_safe(''.join(lst)) Which worked great, but then I read this article on efficient string concatenation (I know it doesn't really matter for this, but I wanted consistency) and decided to update my script: def html_tag(tag, body=None, close=True, attrs={}): s = StringIO() s.write('<%s'%tag) for key, val in attrs.iteritems(): s.write(' %s="%s"' % (key, escape_html(val))) if close: if body is None: s.write(' />') else: s.write('>%s</%s>' % (body, tag)) else: s.write('>') return mark_safe(s.getvalue()) But now my HTML get escaped when I try to render it from my template. Everything else is exactly the same. It works properly if I replace the last line with return mark_safe(unicode(s.getvalue())). I checked the return type of s.getvalue(). It should be a str, just like the first function, so why is this failing?? Also fails with SafeString(s.getvalue()) but succeeds with SafeUnicode(s.getvalue()). I'd also like to point out that I used return mark_safe(s.getvalue()) in a different function with no odd behavior.

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  • django accepting GET parameters

    - by tipu
    I want the index page to accept parameters, whether it be mysite.com/search/param_here or mysite.com/?search=param_here I have this in my URL patterns but I can't get it to work.. any suggestions? urlpatterns = patterns('', (r'^$/(?P<tag>\w+)', 'twingle.search.views.index'), )

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  • django link to any user profile in social comunity

    - by dana
    i am trying to build a virtual comunity, and i have a profile page, and a personal page. In the profile page, one can see only the posts of one user(the user whos profile is checked), in the personal page one can see his posts, plus all the posts he has subscribed to (just like in Facebook) it's a little confusing for me how i can link to the profile of one user, i mean when anybody clicks on a username, it should link to his personal profile page. for example, if someone searches name "abc", the rsult would be "abc",and link to his profile. How can i pass to one function the username or id of a linked user? i mean, showing the profile of the logged in user who is checking his profile is quite easy.But how about another user profile, if one wants to access it? thanks a lot!

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  • Django template not loading javascript and css properly due to urlpatterns

    - by fmsf
    Hey, When this one runs everything goes fine: (r"^newobject$", "views.myobjects.newobject"), All the CSS + JS files are properly fetched from: static/css/... static/js/... When this one runs: (r"^mybjects/(([a-z]|[A-Z]|[0-9])+)$","views.myobjects.loadobject"), All the css and JS files that are being fetched, are run trough the urlpatterns and are returning my defailt page: (r"", 'views.main.index'), This makes all my CSS and JS code to actualy be HTML. My guess is that i'm giving some noob mistake. Is there any common reason why this should happen? And how to fix it?

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  • Cannot use "image.save" on django

    - by zjm1126
    My error is: IOError at /mytest/photo/upload/ [Errno 2] No such file or directory: u'/mytest/photo/upload/2.png' And my view is: UPLOAD_URL = '/mytest/photo/upload/' def upload(request): buf = request.FILES.get('photo', None) print buf if buf: #data = buf.read() #f = StringIO.StringIO(data) image = Image.open(buf) #image = image.convert('RGB') name = '%s%s' % (UPLOAD_URL, buf.name) image.save(file(name, 'wb'), 'PNG') return HttpResponse('ok') return HttpResponse('no') And my urls.py is: urlpatterns = patterns('mytest.views', url(r'^photo/upload/$','upload',name="") ) How can I fix this?

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  • arbitrary typed data in django model

    - by Dmitry Shevchenko
    I have a model, say, Item. I want to store arbitrary amount of attributes on it, like title, description, release_date. And i want them to be not just strings but have python type, so string, boolean, datetime etc. What are my options here? EAV pattern with separate name-value table won't work because of the same DB type across all values. JSONField can probably help, but it doesn't know about datetime, for example. Also i was looking at PickeField, it fits perfectly, but i'm a bit concerned about performance.

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  • Django m2m form appearing fields

    - by dana
    I have a classroom application,and a follow relation. Users can follow each other and can create classrooms.When a user creates a classroom, he can invite only the people that are following him. The Classroom model is a m2m to User table. i have in models. py: class Classroom(models.Model): creator = models.ForeignKey(User) classname = models.CharField(max_length=140, unique = True) date = models.DateTimeField(auto_now=True) open_class = models.BooleanField(default=True) members = models.ManyToManyField(User,related_name="list of invited members") and in models.py of the follow application: class Relations(models.Model): initiated_by = models.ForeignKey(User, editable=False) date_initiated = models.DateTimeField(auto_now=True, editable = False) follow = models.ForeignKey(User, editable = False, related_name = "follow") date_follow = models.DateTimeField(auto_now=True, editable = False) and in views.py of the classroom app: def save_classroom(request, username): if request.method == 'POST': u = User.objects.get(username=username) form = ClassroomForm(request.POST, request.FILES) if form.is_valid(): new_obj = form.save(commit=False) new_obj.creator = request.user r = Relations.objects.filter(initiated_by = request.user) # new_obj.members = new_obj.save() return HttpResponseRedirect('.') else: form = ClassroomForm() return render_to_response('classroom/classroom_form.html', { 'form': form, }, context_instance=RequestContext(request)) i'm using a ModelForm for the classroom form, and the default view, taking in consideration my many to many relation with User table, in the field Members, is a list of all Users in my database. But i only want in that list the users that are in a follow relationship with the logged in user - the one who creates the classroom. How can i do that? Thanks!

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  • Dynamic choices for Django SelectMultiple Widget

    - by PhilGo20
    I'm building a form (not modelForm) where i'd like to use the SelectMultiple Widget to display choices based on a query done during the init of the form. I can think of a few way to do this but I am not exactly clear on the right way to do it. I see different options. I get the "choices" I should pass to the widget in the form init but I am not sure how I should pass them. class NavigatorExportForm(forms.Form): def __init__(self,user, app_id, *args,**kwargs): super (NavigatorExportForm,self ).__init__(*args,**kwargs) # populates the form language_choices = Navigator.admin_objects.get(id=app_id).languages.all().values_list('language', flat=True) languages = forms.CharField(max_length=2, widget=forms.SelectMultiple(choices=???language_choices))

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  • Django dislaying upload file content

    - by dana
    hello, i have an application that loads different documents to the server, and allows users to read documents' content. i am uploading the documents to the server, and then i try to read the courses by id, like: def view_course(request,id): u = Courses.objects.get(pk=id) etc But i don't find anywhere : how can i actually read the content of a /.doc/.pdf/.txt and display it on a web page? thanks in advance!

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  • Django save, column specified twice

    - by realshadow
    Hey, I would like to save a modified model, but I get Programming error - that a field is specified twice. class ProductInfo(models.Model): product_info_id = models.AutoField(primary_key=True) language_id = models.IntegerField() product_id = models.IntegerField() description = models.TextField(blank=True) status = models.IntegerField() model = models.CharField(max_length=255, blank=True) label = models.ForeignKey(Category_info, verbose_name = 'Category_info', db_column = 'language_id', to_field = 'node_id', null = True) I get this error because the foreign key uses as db_column language_id. If I will delete it, my object will be saved properly. I dont quite understand whats going on and since I have defined almost all of my models this way, I fear its totally wrong or maybe I just missunderstood it... Any ideas? Regards

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  • Django: tinyMCE and cross site javascript

    - by pistacchio
    Hi, follow this question, I was able to set some textareas in my admin page as richtext inputs. The most voted answer suggests to follow an example and is what i did. Also, it talks about a problem concerning "blank pages". I'm having the same problem and I'm not able to solve it. I have my media files served by a different server, so MEDIA_URL points to a different host with a different port. To simulate this in my dev environment, I also serve media files from a different port. Debugging the failing javascript, Chrome yelds: Unsafe JavaScript attempt to access frame with URL http://localhost:8000/admin/blog/post/add/ from frame with URL http://localhost:88/s3mangerie/js/tiny_mce/themes/advanced/image.htm. Domains, protocols and ports must match. How to solve this problem? Thanks

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  • django file upload in 2 steps

    - by alexarsh
    Hi, I want to upload a file in 2 steps. First I want to upload it and show the errors and on the second step I want actually to save the file data in the database. So I made a simple form and my problem is how to pass the same file to the form on the second step? I mean how to insert request.FILES data in the same form again. Or maybe there is a better way? Thanks, Arshavski Alexander.

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